© 2001 McGraw-Hill Companies
767
and the Circle
10.2
OBJECTIVES
1. Given a center and radius, find the equation of a circle
2. Given an equation for a circle, find the center and radius
3. Given an equation, sketch the graph of a circle
In Section 10.1, we examined the parabola. In this section, we turn our attention to another conic section, the circle.
The distance formula is central to any discussion of conic sections.
Equation (1) can be used in two ways. Given the center and radius of the circle, we can write its equation; or given its equation, we can find the center and radius of a circle.
We can use the distance formula to derive the algebraic equation of a circle, given its center and its radius.
Suppose a circle has its center at a point with coordinates (h, k) and radius r. If (x, y) rep- resents any point on the circle, then, by its definition, the distance from (h, k) to (x, y) is r.
Applying the distance formula, we have
Squaring both sides of the equation gives the equation of the circle r
2(x h)
2(y k)
2In general, we can write the following equation of a circle.
r 2(x h)
2(y k)
2A circle is the set of all points in the plane equidistant from a fixed point, called the center of the circle. The distance between the center of the circle and any point on the circle is called the radius of the circle.
Definitions: Circle
The distance, d, between two points (x1, y1) and (x2, y2) is given by d 2(x2 x1)2 (y2 y1)2
Definitions: The Distance Formula
The equation of a circle with center (h, k) and radius r is
(x h)2 (y k)2 r2 (1)
Definitions: Equation of a Circle
NOTEA special case is the circlecentered at the origin with radius r. Then (h, k) (0, 0), and its equation is
x2 y2 r2
(x2, y2)
(x2, y1) (x1, y1)
d y
x
(x, y)
(h, k) y
x r
768 CHAPTER10 GRAPHS OFCONICSECTIONS
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Finding the Center and Radius of a Circle
Find the center and radius of the circle with equation (x 1)
2(y 2)
29
Remember, the general form is (x h)
2(y k)
2r
2Our equation “fits” this form when it is written as
Note: y 2 y (2)
(x 1)
2[y (2)]
23
2So the center is at (1, 2), and the radius is 3. The graph is shown.
y
x 3
(1, 2)
(x 1)2 (y 2)2 9
Example 2
Finding the Equation of a Circle
Find the equation of a circle with center at (2, 1) and radius 3. Sketch the circle.
Let (h, k) (2, 1) and r 3. Applying equation (1) yields (x 2)
2[y (1)]
23
2(x 2)
2(y 1)
29
To sketch the circle, we locate the center of the circle. Then we determine four points 3 units to the right and left and up and down from the center of the circle. Drawing a smooth curve through those four points completes the graph.
Example 1
Now, given an equation for a circle, we can also find the radius and center and then sketch the circle. We start with an equation in the special form of equation (1).
C H E C K Y O U R S E L F 1
Find the equation of the circle with center at (2, 1) and radius 5. Sketch the circle.
y
x 3
(2, 1)
(x 2)2 (y 1)2 9
NOTEThe circle can be graphed on the calculator by solving for y, then graphing both the upper half and lower half of the circle. In this case, (x 1)2 (y 2)2 9 ( y 2)2 9 (x 1)2
Now graph the two functions
and
on your calculator. (The display screen may need to be squared to obtain the shape of a circle.) y 2 29 (x 1)2 y 2 29 (x 1)2 y 2 29 (x 1)2 ( y 2) 29 (x 1)2
© 2001 McGraw-Hill Companies
Finding the Center and Radius of a Circle
Find the center and radius of the circle with equation x
22x y
26y 1
Then sketch the circle.
We could, of course, simply substitute values of x and try to find the corresponding values for y. A much better approach is to rewrite the original equation so that it matches the standard form.
First, add 1 to both sides to complete the square in x.
x
22x 1 y
26y 1 1
Then add 9 to both sides to complete the square in y.
x
22x 1 y
26y 9 1 1 9
We can factor the two trinomials on the left (they are both perfect squares) and simplify on the right.
(x 1)
2(y 3)
29
The equation is now in standard form, and we can see that the center is at ( 1, 3) and the radius is 3. The sketch of the circle is shown. Note the “translation” of the center to ( 1, 3).
Example 3
NOTETo recognize theequation as having the form of a circle, note that the
coefficients of x2and y2are equal.
NOTEThe linear terms in x and y show a translation of the center away from the origin.
To graph the equation of a circle that is not in standard form, we complete the square.
Let’s see how completing the square can be used in graphing the equation of a circle.
C H E C K Y O U R S E L F 2
Find the center and radius of the circle with equation
(x 3)
2(y 2)
216
Sketch the circle.C H E C K Y O U R S E L F 3
Find the center and radius of the circle with equation
x
24x y
22y 1
Sketch the circle.3
(x 1)2 (y 3)2 9 y
x (1, 3)
770 CHAPTER10 GRAPHS OFCONICSECTIONS
© 2001 McGraw-Hill Companies
C H E C K Y O U R S E L F A N S W E R S
1. (x 2)
2(y 1)
225 2. center: ( 3, 2); radius 4
3. (x 2)
2(y 1)
24; center: (2, 1); radius 2
y
(2, 1) x 2
y
(3, 2)
x 4
y
(2, 1)
x 5
© 2001 McGraw-Hill Companies
Exercises
In exercises 1 to 12, decide whether each equation has as its graph a line, a parabola, a circle, or none of these.
1.
y x
22x 5
2.y
2x
264
3.
y 3x 2
4.2y 3x 12
5.
(x 3)
2(y 2)
210
6.y 2(x 3)
25
7.
x
24x y
26y 3
8.4x 3
9.
y
24x
236
10.x
2(y 3)
29
11.
y 2x
28x 3
12.2x
23y
26y 13
In exercises 13 to 20, find the center and the radius for each circle.
13.
x
2y
225
14.x
2y
272
15.
(x 3)
2(y 1)
216
16.(x 3)
2y
281
17.
x
22x y
215
18.x
2y
26y 72
19.
x
26x y
28y 16
20.x
25x y
23y 8
In exercises 21 to 32, graph each circle by finding the center and the radius.
21.
x
2y
24
22.x
2y
225
y
x y
x
10.2
Section DateANSWERS
1.2.
3.
4.
5.
6.
7.
8.
9.
10.
11.
12.
13.
14.
15.
16.
17.
18.
19.
20.
21.
22.
771
© 2001 McGraw-Hill Companies
23.
4x
24y
236
24.9x
29y
2144
25.
(x 1)
2y
29
26.x
2(y 2)
216
27.
(x 4)
2(y 1)
216
28.
(x 3)
2(y 2)
225
y
x y
x
y
x y
x
y
x y
x
ANSWERS
23.24.
25.
26.
27.
28.
772
29.
x
2y
24y 12
30.x
26x y
20
31.
x
24x y
22y 1
32.
x
22x y
26y 6
33.
Describe the graph of x
2y
22x 4y 5 0.
34.
Describe how completing the square is used in graphing circles.
35.
A solar oven is constructed in the shape of a hemisphere. If the equation x
2y
2500 1000
describes the outer edge of the oven in centimeters, what is its radius?
36.
A solar oven in the shape of a hemisphere is to have a diameter of 80 cm. Write the equation that describes the outer edge of this oven.
37.
A solar water heater is constructed in the shape of a half cylinder, with the water supply pipe at its center. If the water heater has a diameter of m, what is the equation that describes its outer edge?
4 3
y
x y
x
y
x y
x
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29.
30.
31.
32.
33.
34.
35.
36.
37.
773
© 2001 McGraw-Hill Companies 38.
A solar water heater is constructed in the shape of a half cylinder with circumference
described by the equation 9x
29y
216 0
What is its diameter if the units for the equation are meters?
A circle can be graphed on a calculator by plotting the upper and lower semicircles on the same axes. For example, to graph x
2y
216, we solve for y:
This is then graphed as two separate functions, and
In exercises 39 to 42, use that technique to graph each circle.
39.
x
2y
236
40.
(x 3)
2y
29
41.
(x 5)
2y
236
Y
2216 x
2Y
1216 x
2y 216 x
2ANSWERS
38.
39.
40.
41.
774
42.
(x 2)
2(y 1)
225
Each of the following equations defines a relation. Write the domain and the range of each relation.
43.
(x 3)
2(y 2)
216
44.(x 1)
2(y 5)
29
45.
x
2(y 3)
225
46.(x 2)
2y
236
Answers
1.
Parabola
3.Line
5.Circle
7.Circle
9.None of these
11.Parabola
13.Center: (0, 0); radius: 5
15.Center: (3, 1); radius: 4
17.Center: ( 1, 0); radius: 4
19.Center: (3, 4); radius:
21.
x
2y
24
23.4x
24y
236
x
2y
29
Center: (0, 0); radius: 2 Center: (0, 0); radius: 3
25.
(x 1)
2y
29
27.(x 4)
2(y 1)
216 Center: (1, 0); radius: 3 Center: (4, 1); radius: 4
(x 4)2 (y 1)2 16 Center: (4, 1);
radius: 4 y
x (x 1)2 y2 9
Center: (1, 0);
radius: 3 y
x
4x2 4y2 36 x2 y2 9 Center: (0, 0);
radius: 3 y
x x2 y2 4
Center: (0, 0);
radius: 2 y
x
141
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42.
43.
44.
45.
46.
775
© 2001 McGraw-Hill Companies 29.
x
2y
24y 12
31.x
24x y
22y 1
Center: (0, 2); radius: 4 Center: (2, 1); radius: 2
33.
Circle with radius 0; center at (1, 2)
35.24.4 cm
37.x
2y
239.
x
2y
236
41.
(x 5)
2y
236
43.
Domain: x7 x 1
45.Domain: x5 x 5
Range: y2 y 6 Range: y2 y 8
y y
36 (x 5)2 36 (x 5)2 y y
36 x2 36 x2
4 9
1500 1015 cm
x2 4x y2 2y 1 (x 2)2 (y 1)2 4 Center: (2, 1);
radius: 2 y
x x2 y2 4y 12
x2 (y 2)2 16 Center: (0, 2);
radius: 4 y
x
776