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R E S E A R C H

Open Access

Composition and multiplication operators

between Orlicz function spaces

Tadeusz Chawziuk

1

, Yunan Cui

2*

, Yousef Estaremi

3

, Henryk Hudzik

1

and Radosław Kaczmarek

1

*Correspondence:

[email protected]

2Department of Mathematics,

Harbin University of Science and Technology, Harbin, 150080, P.R. China

Full list of author information is available at the end of the article

Abstract

Composition operators and multiplication operators between two Orlicz function spaces are investigated. First, necessary and sufficient conditions for their continuity are presented in several forms. It is shown that, in general, the Radon-Nikodým derivatived(μdμτ–1)(s) need not belong toL∞() to guarantee the continuity of the composition operatorcτx(t) =x(τ(t)) fromL() intoL(). Next, the problem of

compactness of these operators is considered. We apply a compactness criterion in Orlicz spaces which involves compactness with respect to the topology of local convergence in measure and equi-absolute continuity in norm of all the elements of the set under consideration. In connection with this, we state some sufficient conditions for equi-absolute continuity of the composition operatorand the

multiplication operatorMwfrom one Orlicz space into another. Also the problem of necessary conditions is discussed.

MSC: Primary 47B33; secondary 46E30

Keywords: composition operator; multiplication operator; Orlicz spaces

1 Introduction

Since the early s composition operators have been a subject of study of many mathe-maticians or physicists. At the beginning they were used to solve problems in mathemat-ical physics and classmathemat-ical mechanics [, ], or to study ergodic transformations [, ]. Up until now many Ph.D. theses have been defended (for instance: Boyd [], Gupta [], Ridge [], Schwartz [], Singh [], Swanton [], Veluchamy []), numerous books published [, ], and innumerable papers printed on the composition operator or the weighted composition operator in various function spaces,e.g.,Lpspaces ([–], and others),

Or-licz spaces ([–], and others), Musielak-OrOr-licz spaces [, ], Musielak-OrOr-licz spaces of Bochner type ([] or []), Orlicz-Lorentz spaces [–], Hilbert spaces [–] and many other types of spaces (for instance: [–]). The multiplication operator has also been a subject of research of many mathematicians (see for instance: [–]). For more details as regards the historical background we refer the reader to [].

Let (,,μ) be a non-atomic,σ-finite and complete measure space and letτ:

be a measurable function,i.e., a mapping such thatτ–(A)if and only ifAfor any

A, whereτ–(A) is the counterimage ofA. In the whole paper we will assume thatτ

is non-singular, that is,μ(τ–(A)) =  providedμ(A) = . The last assumption guarantees

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that the measureμτ–defined for anyAby the formula

μτ–(A) =μτ–(A)

is absolutely continuous with respect to the measure μ (what is usually denoted by

μτ–μ). Then the Radon-Nikodým theorem implies the existence of a non-negative

locally integrable functiononsuch thatμτ–(A) =

Ahτ(s)(s) for anyA. The

function(s) =d(μ◦τ

–)

(s) is called the Radon-Nikodým derivative of the measureμτ

–

with respect to the measureμ. Let us remark that even if the Radon-Nikodým derivative is unbounded, the corresponding composition operator acting from an Orlicz space onto itself can still be continuous (see []).

LetL() =L(,,μ) be the space of all (abstract classes of )-measurable functions

fromintoRwith respect to the equivalence relation:xyif and only ifx(t) =y(t) for

μ-a.e.t.

With the help of a non-singular and measurable mappingτ:one defines onL

the composition operator

(cτx)(t) :=x

τ(t)

for anytand anyxL().

LetwL(,,μ) be a strictly positive function. We define the multiplication operator

Mw:L→Lby the formula

(Mwx)(t) :=w(t)x(t)

for anytand anyxL().

It is obvious thatcτxL() andMwxL() ifxL().

Remark . We do not assume, if not specifically stated otherwise, that the mappingτis a surjection,i.e.,τ() =.

A function:R→R+= [,∞) is said to be an Orlicz function ifis convex, even,

continuous, vanishing only at .

The complementary function in the sense of Young to an Orlicz functionis defined to be the function∗: [,∞)→[,∞] such that∗(u) =supv>{uv(v)}.

A functionϕfrom×RintoR+ such thatϕ(t,·) is an Orlicz function forμ-a.e.t

andϕ(·,u) is a-measurable function for everyu∈Ris called a generalized Orlicz function or a Musielak-Orlicz function. The Musielak-Orlicz space=Lϕ(,,μ) is the

space of all (equivalence classes of )-measurable functionsx:→Rsuch that

(λx) =

ϕt,λx(t)<∞

for someλ>  depending onx. The Musielak-Orlicz space equipped with the Luxemburg norm

xϕ=inf

λ>  :

x

λ

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is a Banach space (cf.[, ], and in the case of Orlicz spaces also [–]). It is obvious that Orlicz functions are Musielak-Orlicz functions, and consequently, Orlicz spaces are Musielak-Orlicz spaces. For instance, an Orlicz weighted spaceL

h() is the

Musielak-Orlicz space() generated byϕ(t,u) =(u)h(t) for anytand anyuR.

Throughout the paper, we will make use of Ishii’s theorem from [].

Theorem . For Musielak-Orlicz spaces Lϕ()and Lψ()over a non-atomic measure space= (,,μ),the inclusion Lϕ()Lψ()holds if and only if there exist k,K>  and c(·)∈L()such that

ψ(t,)≤(t,ξ) +c(t)

for allξ≥and a.e.t.

For anyA, byI(x,A) we mean the value of the modularIatxin the Orlicz space L(A) generated by the Orlicz functionover the measure space (A,A,μ|

A). In the

case whenA=, we will writeI(x) instead ofI(x,).

2 Continuity of the composition operatorcτfromLintoLand fromL ontoL

We are interested in finding necessary and sufficient conditions for the continuity of the composition operator from the Orlicz spaceL() =L(,,μ) equipped with the

Luxemburg norm into the Orlicz space L() =L(,,μ) endowed with the

corre-sponding Luxemburg norm. The following fact will be very helpful.

Fact . For an arbitrary function xL(), we have c

τxL() if and only if xL

h(τ()), whereLh(τ()) =Lh(τ(),τ(),μ|∩τ()) is a weighted Orlicz space with

the weight functionh(s) =dμ◦τdμ–(s).

Proof For anyxL(), we have

I(cτx,) =

cτx(t)

(t)

=

(t)(t)

=

τ()

x(s)τ–(s)

=

τ()

x(s)h(s)(s) =I,h

x,τ().

Theorem . If the quadruple,,h,τsatisfies the condition

K>A∈∩τ∃ ()

μ(A)=

gL+(τ())s∈τ(∀)\Au∀≥(u)h(s)≤(Ku) +g(s), ()

or,equivalently,L(τ())L

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Moreover,ifμ(\τ()) = ,then condition()is necessary for the continuity of the com-position operator cτ from L()into L().

Proof We will show that if condition () is satisfied thencτxL() wheneverxL(), i.e.,xL

h(τ()) wheneverxL

() (see Fact .).

Assume thatxL(). Applying condition () and Fact ., we obtain

I

cτx

K( +gL(τ()))x

,

≤ 

 +gL(τ())

I

cτx Kx,

= 

 +gL(τ())I,h

x

Kx,τ()

I(

x

x,τ()) +gL(τ())  +gL(τ())

≤ 

 +gL(τ())

 +gL(τ())= ,

which shows that acts fromL() intoL() and cτxK

 +gL(τ())x,

which finishes the proof of the first part of the theorem.

Now assume thatμ(\τ()) = . If the inclusion in the assumption of the theorem fails to hold, then there exists a functionxbelonging toL(τ()) =L() but not belonging

toL

h(τ()). In virtue of Fact ., we obtainxL

() and, simultaneously,c

τx∈/L(),

hence does not even act fromL() intoL().

The preceding theorem can be formulated in a different language, which in some situa-tions might be more useful.

Theorem . The composition operator cτ :L()→L()is continuous if the following simple condition is satisfied:

τ()

χh(s)(s) <∞, ()

where h=dμτ– andχis the function complementary in the sense of Young to the function

K–,with K being the constant from condition()of Theorem..Ifμ(\τ()) = ,

then condition()is necessary for the continuity of cτ.

Proof It is not too difficult to see that,, andhsatisfy condition () if and only if

sup

u≥

(u)h(s) –(Ku)∈L+τ().

But

sup

u≥

(u)h(s) –(Ku)=sup

v≥

vh(s) –K–(v)

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Remark . Notice that ifb(χ) :=sup{u≥ :χ(u) <∞}<∞then condition () implies thathL∞(τ())≤b(χ) <∞, that is, the Radon-Nikodým derivativeh=dμ◦τ

–

is es-sentially bounded. Moreover, it is easy to see that the integral () can be finite for some

h∈/L∞(τ()) if and only if the functionχhas only finite values (for the case when=

see []; the proof in the case when=is similar).

The next theorem states a necessary and sufficient condition in order thatχis such a function.

Theorem . The functionχ= (K–),with K> ,assumes only finite values(i.e.,

b(χ) =∞)if and only iflim inft→∞(Kt)(t) =∞.

Proof Sufficiency. Let lim inft→∞(Kt)(t) = ∞. Then limt→∞

(Kt)

(t) = ∞ and so

limt→∞(K–(t))

t =∞. Take an arbitraryv> . In virtue of the last equality, there exists

uv>  such that for alluuvthe inequality

(K–(u))

uv

holds. Hence

χ(v) :=sup

u≥

uvK–(u)=sup

u≥

u

v(K

–(u))

u

= sup

u∈[,uv]

uvK–(u)<∞

as a supremum of a continuous function on a compact interval.

Necessity. Assume thatlim inft→∞(Kt)(t) <∞forK> . Thenlim inft→∞

(K–(t))

t <∞

forK> , and so there existc>  and a sequence of positive numbers (un)∞n= such that

un→ ∞asn→ ∞andlimn→∞(K

–(u n))

un =c. Consequently,c

(c,) can be found

such that forn∈Nlarge enough we have

K–(un)

cun.

Therefore, takingv>c, we get

unv

K–(un)

unvcun=un

vc

forn∈Nlarge enough, whence

sup

u≥

uvK–(u)≥sup

n∈N

unv

K–(un)

vcsup

n∈Nun=∞,

which finishes the proof of the theorem.

Now we show that if the functionχfrom Theorem . assumes only finite values,i.e.,

b(χ) =∞, then it may happen that the composition operator fromL() intoL() is

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Example . Let= (, ], (,,μ) be the Lebesgue measure space andAn= (n+ ,n] for

everyn∈N. Then∞n=An=. Letχbe the function from Theorem ., letb(χ) =∞

andun>  be such thatχ(un) =

nfor everyn∈N. Sinceun ∞asn→ ∞, there exists

m∈Nsuch thatun≥ for anyn>m. Defineτ: (, ]→(, ] by the formula

τ(t) =

⎧ ⎨ ⎩

t, fortAnwithnm, t

un, fortAn, wheren>m.

Let us denotevn=  ifnmandvn=unifn>m. Thenτ–:τ()→is defined by the

formulaτ–(s) =v

nsfor anysτ(An). Consequently, for anyAτ(), we have

μτ–(A) :=μτ–(A)=μ

n=

τ–Aτ(An)

=

n=

μτ–Aτ(An)

= ∞ n= μ vn A∩ 

vn

(An)

=

n=

μ(vnAAn). ()

Let us define

h(s) =

n=

vn1

unAn(s). ()

Then, for anyAτ(),

A

h(s)(s) =

n=A∩τ(An)

h(s)(s) =

n=

A∩ vn(An)

vndμ(s)

=

n=

vnμ

A∩ 

vn An = ∞ n=

μ(vnAAn). ()

By inequalities () and (), we get

μτ–(A) =

A

h(s)(s), ∀Aτ(),

which means thath=d(μ◦τdμ–). By formula () and the definition ofvn, we have

τ()

χh(s)=

n=

χ(vn)μ

vn An = m n=

μ(An) +

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≤ +

n=m+

(An)

≤ +

n=m+

n n(n+ )

<  +

n=

n/ <∞.

In virtue of Theorem ., we conclude that the composition operator fromL() into L() is continuous. However, sinceu

n→ ∞asn→ ∞, we havehL∞(τ())=∞.

Theorem . The composition operator cτ acts continuously from L(,,μ) onto L(,,μ)if and only ifμ(\τ()) = and the following two conditions are jointly sat-isfied:

(i) ∃K>A∈∩

μ(A)= ∃gL

+()∀s∈\Au≥(u)h(s)≤(Ku) +g(s); (ii) ∃K>A

μ(A)= ∃pL

+()∀s\Au≥(u)≤(Ku)h(s) +p(s),

where h(s) = dμ◦τdμ–(s)forμ-a.e.s.

Proof Obviously, the conditionμ(\τ()) =  is necessary for(L()) =L(), so in

the further part of the proof we assume this condition holds. Therefore, by Fact ., we know that acts fromL() ontoL() if and only ifL() =Lh(). Equivalently, this

holds if and only if we have two inclusions:L()L

h() andL

h()⊂L

(). The first

inclusion holds if and only if condition (i) is satisfied and the reverse inclusion holds if and only if condition (ii) is satisfied (see [] and []), and this finishes the proof.

It is interesting and profitable to observe that the preceding theorem can be written in the following form.

Theorem . The composition operator cτ acts continuously from L()onto L()if and only ifμ(\τ()) = and for some K> the following two conditions are jointly sat-isfied:

() χ(h(s))(s) <∞; () h(s)q(h(s) )(s) <∞,

whereχis the function complementary in the sense of Young to the functionK–,q is

the function complementary in the sense of Young to the functionK–,and h(s) = dμ◦τ–

(s)forμ-a.e.s.

Proof In the proof of Theorem . we already showed that condition (i) from Theorem . is equivalent to condition (). So, the proof will be finished if we show that condition () is equivalent to condition (ii) from Theorem ..

It is easy to see that condition (ii) is equivalent to the fact thatqL

+(), where

q(s) =sup

u≥

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for alls. Sinceh(s)=  forμ-a.e.s, we have

q(s) =h(s)sup

u≥

(u)

h(s) –(Ku)

=h(s)sup

v≥

v h(s)–

K–(v)

=h(s)K–∗

h(s)

forμ-a.e.s, where (K–)∗ is the complementary function to the function

K–, which finishes the proof.

3 Continuity of the multiplication operatorMwfromLintoLand fromL ontoL

We will state criteria in order thatMw mapL(,,μ) intoL(,,μ), whereand

are distinct Orlicz functions. Note thatMwxL(,,μ) means that there isλ> 

such thatI(λw(t)x(t)) =

(λw(t)x(t))(t) <∞. This is equivalent to the fact thatxLw(,,μ), whereLw(,,μ) is a Orlicz space generated by the Musielak-Orlicz functionw(t,u) :=(w(t)u). Let us begin with the following.

Theorem . The multiplication operator Mwmaps L(,,μ)into L(,,μ)if and

only ifχK(t, )(t) <∞for some K> ,whereχK(t,u)is,for fixed t,the function

complementary in the sense of Young to the functionw(t)K –with respect to u.

Proof The fact thatMw:L(,,μ)→L(,,μ) means thatL(,,μ)⊂Lw(,

,μ), which, by Theorem ., holds if and only if there areAwithμ(A) = , a constant

K> , and a functionhL

+(,,μ) such that the inequality

w(t)u(Ku) +h(t) () holds for allt\Aand allu∈R. It is easy to see that this is equivalent to the fact that

for someK>  the functionh˜Kdefined by the formula

˜

hK(t) =sup u∈R

w(t)u(Ku)=sup

u≥

w(t)u(Ku) ()

is integrable over. In fact,h˜Kis the smallest function such that condition () holds with

˜

hKin place ofh. Setting in ()u= –(v)

w(t) , we get

˜

hK(t) =sup v>

v

K w(t)

–(v)

=χK(t, ),

whereχK(t,u) is the function complementary in the sense of Young tow(t)K –.

There-fore, the fact thatMwmaps continuouslyL(,,μ) intoL(,,μ) is equivalent to the

fact thatχK(t, )(t) <∞.

Theorem . The multiplication operator Mw maps L(,,μ) onto the whole of

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(i) χK(t, )(t) <∞for someK> ,whereχK(t,u)is the function defined in Theorem.;

(ii) UK(t, )(t) <∞for someK> ,whereUK(t,u)is,for fixedt,the function complementary in the sense of Young,with respect tou,to the function

(Kw(·)–)(t,u) =(Kw(t)–(u)).

Proof It is obvious thatMwmapsL(,,μ) ontoL(,,μ) if and only ifμ(\suppw) =

 and {w(t)x(t) : xL} =L(,,μ). The space on the left-hand side of the last

equality is the Musielak-Orlicz space Lw(), where

w(t,u) =(w(t)u ). Observe that

Lw(,,μ) =L(,,μ) is equivalent toL(,,μ) =Lw(,,μ), where w(t,u) =

(w(t)u). Therefore, the assumption thatMwmapsL(,,μ) ontoL(,,μ) means

that L(,,μ) =Lw(,,μ), that is, the inclusions L()Lw() and Lw()

L() hold. The preceding theorem established that the first inclusion is equivalent to

condition (i). We need only to prove that the reverse inclusion is equivalent to (ii). How-ever, by Ishii’s theorem, the inclusionLw()L() holds if and only if there is a con-stantK> , a setAwithμ(A) = , andgL

+(,,μ), such that

(u)≤Kw(t)u+g(t)

for allt\Aandu≥. The last condition is equivalent to the condition

sup

u≥

(u) –Kw(t)uL+(,,μ).

But note that

sup

u≥

(u) –Kw(t)u=sup

v≥

vKw(t)–(v) =UK(t, ),

whereUK(t,u) is, for fixedt, the function complementary in the sense of Young, with

respect tou, to the functionM(t,u) =(Kw(t)–(u)). This finishes the proof.

4 Compactness of the composition operatorcτfrom one Orlicz space into another

We begin with some notions that will be useful in the following. Let (,,μ) be a non-atomic, complete andσ-finite measure space. We say that functions in a setAcontained in the Musielak-Orlicz spaceL() have equi-absolutely continuous norms if for any real

numberε>  there exist a setwithμ() <∞and a real numberδ=δ(ε) >  such

that for any functionxAwe have\<εandxχB<εwheneverB

andμ(B) <δ.

LetL() =L(,,μ) andL() =L(,,μ) be distinct Orlicz spaces. We say that

the operatorT:L()L() is equi-absolutely continuous if for any bounded setA L() all functions of the setT(A)L() have equi-absolutely continuous norms.

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Theorem .(Theorem . in []) Let(,,μ)be a non-atomicσ-finite measure space and letϕbe a Musielak-Orlicz function.If the functions in a set A()all have equi-absolutely continuous norms and A is relatively compact with respect to local convergence in measure,then A is relatively compact in Eϕ(),the subspace of absolutely continuous functions in Lϕ().

Conversely,if a set A()is relatively compact,then all the functions in A have equi-absolutely continuous norms and A is relatively compact with respect to local convergence in measure.

In the proof of the forthcoming theorem we will need the following.

Lemma .(Lemma . in []) Let the measureμbe atomless and let a sequence{αi}of

positive numbers and a sequence{ai}of measurable,finite,non-negative functions inbe

given,satisfying the inequalities

ai(t)≥iαi for i= , , . . . .

Then there exist an increasing sequence {ik} of positive integers and a sequence{Ak} of

pairwise disjoint sets fromsuch that

Ak

aik(t)=αik for k= ,  . . . .

The following theorem will be of great importance in proving necessary and sufficient conditions for the compactness of the composition operator :L()→L(). Theorem . Let(,,μ)be a finite or infinite butσ-finite non-atomic and complete measure space andτbe such thatμ(τ–(A)) <∞wheneverμ(A) <∞for any Aτ().

Then the composition operator cτ:L()→L()is equi-absolutely continuous whenever the following condition is satisfied:

σ>A∈∩τ∃ ()

μ(A)=

L+(τ())

s∈τ()\Au∀≥(u)h(s)≤(σu) +(s). ()

Condition()is necessary for the equi-absolute continuity of cτ ifμ() <∞.

Proof Sufficiency. First we prove that for anyε>  there exists a setDwithμ(\D) <

∞such that all the functions in the set{cτx:xS(L)}, whereS(L) is the unit sphere

ofL, satisfy the condition(c

τx)χD<ε.

Letσ>  be a number such that ( +σ)σ<εand let be a function from condition

() corresponding toσ. SinceL+(τ()), there exists a setCτ() such that

gσχC<σandμ(τ()\C) <∞. DefiningD=τ–(C), we have for any functionxS(L)

I

cτx

σ χD

=

cτx(t)

σ χD(t)

(t)

=

D

x(τ(t))

σ

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=

τ(D)

x(s)

σ

τ–(s)

=

C

x(s)

σ

h(s)(s)

C

x(s)(s) +

C

(s)(s)

≤ +σ. ()

By () we get

I

(cτx)χD

( +σ)σ

≤ 

 +σI

cτx

σ χD

≤ 

 +σ( +σ) = 

for anyxS(L). Consequently,(c

τx)χD≤( +σ)σ<εfor anyxS(L), which

fin-ishes the first part of the proof.

Now we show the following implication:

σ>δ=∃δ(ε)B⊂τ∀()\DxS(L)μ(B) <δ

(cτx)χB<ε,

whereDis the set from the first part of this proof. Take anyxS(L). Sinceg

σL+(τ()), it is obvious that there isδ=δ(σ) >  such that,

ifC∩(τ()\D) andμ(C) <δ, thenC(s)(s) <σ. LetB=τ–(C). Then applying

condition (), we get

I

cτx

σ χB

= cτx(t)

σ χB(t)

(t)

=

B

x(τ(t))

σ

(t)

=

τ(B)

x(s)

σ

τ–(s)

=

C

x(s)

σ

h(s)(s)

C

x(s)(s) +

C

(s)(s)

≤ +σ. ()

Now, by convexity of the modularIand the fact thatIvanishes at zero we haveI(λx)≤

λI(x) for anyxL() andλ∈[, ]. From this fact and from (), we get

I

(cτx)χB

( +σ)σ

≤ 

 +σI

cτx

σ χB

≤ 

 +σ( +σ) = .

Hence(cτx)χB≤( +σ)σ<ε. Sinceσdepends only onε,δ=δ(σ) depends only onε,

and so the proof of sufficiency is finished.

Necessity. Assume thatμ() <∞and for anyσ>  define the function

(s) =sup

u≥

(12)

(s) is a non-negative (since foru= , we have()h(s) –(σ) = ) measurable

func-tion.

Suppose condition () is not satisfied. Then there isσ>  such that

τ()

(s)(s) = +∞.

Let{ri}∞i=be a sequence of all non-negative rational numbers withr= . By the continuity

of the Orlicz functionsand, we have

(s) = sup i=,,...

(ri)h(s) –(σri)

.

Let us write

,n(s) = max ≤in

(ri)h(s) –(σri)

.

It is obvious that,n≥ and,nare measurable functions such that ,n as

n→+∞μ-a.e. inτ(). By Beppo Levi’s theorem, we have

τ()

,n(s)(s)

τ()

(s)(s).

Hence there exists a subsequence{,nk} ⊂ {,n}satisfying

τ()

,nk(s)(s)≥ k.

Without loss of generality we may assume thatτ(),n(s)(s)≥nfor eachn∈N∪

{}. It is clear that for eachsτ() and eachn∈N∪{}there existsrn(s)∈ {r,r,r, . . . ,rn}

such that

,n(s) =

rn(s)

h(s) –σrn(s)

.

Hence

τ()

rn(s)

h(s)(s) =

τ()

hσo,n(s)(s) +

τ()

σrn(s)

(s)≥n.

Applying Lemma ., we conclude that there is a sequence of sets{k} ⊂τ() withi

j=∅fori=jsuch that

n

rn(s)

h(s)(s) = .

(13)

Since, by assumption, μ() <∞, we have ∞n=μ(n) =μ(

n=n)≤μ() <∞,

whencelimn→∞μ(n) = . This means that{¯rn}+n=∞does not have equi-absolutely

contin-uous norms inE

h(). Yet, using the fact that,n≥ (n∈N∪ {}), we get the following:

r¯n(s)

h(s)≥σ¯rn(s)

, n∈N∪ {}.

SoI(σ¯rn)≤, that is,¯rnσ, which means that the operator :L()→L() is

not equi-absolutely continuous. Hence we proved that condition () is necessary for the

equi-absolutely continuity of.

From Theorem ., applying Theorem . and the definition of a compact operator, we directly get the following.

Theorem . If(,,μ)is a non-atomic complete finite or infinite butσ-finite measure space andτ satisfies the assumption from Theorem.,then the composition operator cτ from L()into L()is compact whenever the set c

τ(S(L))is relatively compact with respect to local convergence in measure and condition()from Theorem.is satisfied.

Under the assumption thatμ() <∞,if the composition operator cτ from L()into E()is compact then the set c

τ(S(L))is relatively compact with respect to convergence in measure and condition()is satisfied.

In the case whenhas infinite measure, we were unable to show that () is a necessary condition for the equi-absolute continuity of the composition operator. Instead, we can

deduce a slightly different (and weaker) condition, as the following theorem states.

Theorem . Assume thatμ() =∞andμ(\τ()) = . If the composition operator :L()→L()is equi-absolutely continuous,then the condition

λ> A∃∈

μ(A)=

>L∃+()

s\Au∀≥(λu)h(s)≤(u) +(s) ()

is satisfied.

Proof We can assume without loss of generality thatτ() =. First, notice that if,, andhsatisfy condition () thenL()E

h(), where

Eh() =

xL() : ∀

λ>I,h(λx) =

λx(t)h(t)(t) <∞

is the subspace of absolutely continuous elements ofL

h(). The inclusion results from the

assumption thatis an equi-absolutely continuous operator,i.e., for any bounded setAL(), the functions of the setc

τ(A)⊂L() all have equi-absolutely continuous norms,

and the observation that, for anyxL(), the singleton set{x}is bounded, and thusx

has an equi-absolutely continuous norm, which means thatxis an absolutely continuous element ofL

h(),i.e.,xE

h().

Further, observe that

L() =

λ>

,∗(), E

h() =

λ>

,∗

(14)

where for any λ>  we define λ(u) =(u) and L,∗() ={xL() :I(x) <∞} is a

Musielak-Orlicz class (λ and Lh,∗() are defined analogously). Hence the inclusion L()E

h() can be expressed as

λ>

,∗()

λ>

,∗

h ().

This means that, for anyλ> , the Musielak-Orlicz class,∗() is contained in all of

,∗

h () (λ> ). In particular, takingλ = , we see thatL,∗() is contained in all the

Musielak-Orlicz classes,∗

h () (λ> ). By Theorem . in [], this is equivalent to

λ> A∃∈

μ(A)=

>L∃+()

s∈\Au∀≥(λu)h(s)≤(u) +(s),

which finishes the proof.

From the preceding theorem, applying Theorem ., we can deduce the following nec-essary condition for the compactness of the composition operator:

Theorem . Assume thatμ() =∞ andμ(\τ()) = .If the composition operator :L()→E()is compact then the following conditions are jointly satisfied:

() the setcτ(S(L))is relatively compact with respect to local convergence in measure;

() the functionsandsatisfy condition().

Remark . If there existsε>  such that the set

:=

tτ() : ∀

u≥(u)h(t) >(εu)

has positive measure, then no composition operator :L()→L() over a

non-atomic measure space (,,μ) is compact.

Proof of Remark. Assume that there existsε>  such that the measure of the setis

positive. Then in the setwe can find a sequence of measurable and pairwise disjoint

sets{Bn}inτ() having positive and finite measure. Define

xn=

χBn

χBn =–

μ(Bn)

χBn.

Obviously,I(xn) = , soxn=  for alln∈N. We have

I

εxn

xnτ

,

=

τ()

εxn(t)

xnτ

(t)

<

τ()

xn(t)

xnτ

h(t)(t)

=

(xnτ)(t)

xnτ

(t) =I

cτxn

cτxn

,

(15)

Therefore,

εxn

xnτ

≤,

i.e.,cτxnεxn=εbecausexn= . Since the supports ofxnare pairwise

dis-joint, for alln,m∈N,m=nwe get

cτxncτxm=(xnxm)≥max

cτxn,cτxm

ε.

Hence the sequence{cτxn}∞n=has no Cauchy subsequence, that is,(S(L())) is not

rel-atively compact. Consequently, no composition operator fromL() intoL() over

a non-atomic measure space (,,μ) is compact.

5 Compactness of the multiplication operatorMwfrom one Orlicz space into another

We state a sufficient condition for the compactness of the multiplication operatorMw:

L()L().

Theorem . Let(,,μ)be a non-atomic complete,finite or infinite butσ-finite measure space and let,be two Orlicz functions and wL

+(,,μ).If the triple,,w satisfies

the condition

σ> ∃∈

μ(Aσ)=

L+()

t\Au∀≥

w(t)u(σu) +(t) ()

then the multiplication operator Mwfrom L()into L()is equi-absolutely continuous.

Proof First we show that givenε>  there exists a set B withμ(B) <∞such that

xχ\B<εfor any functionxS(L()).

Takeε>  and letσ >  be such thatσ( +σ) <ε. Let be a function from condition

() corresponding toσ. SinceL+(), there existsB withμ(B) <∞such that gσχ\BL()<σ. Then

I

Mwx

σ χ\B

I(\B) +

\B

(t)(t)≤ +σ,

whence

I

Mwx

σ( +σ)χ\B

≤ 

 +σI

Mwxχ\B

σ

≤ 

 +σ( +σ) = ,

that is,Mwxχ\Bσ( +σ) <ε.

Next, we show that forε>  there existsδ=δ(ε) >  such that for anyDBand any functionxS(L), ifμ(D) <δthenM

wxχD<ε.

Letε>  and letσ >  be such thatσ( +σ) <ε. By the absolute continuity of in L(B), there existsδ=δ(σ) such thatgσχCL()<σ wheneverCBandμ(C) <δ.

Then, by condition (),

I

Mwx

σ χC

(16)

whence

I

Mwx

σ( +σ)χC

≤ 

 +σI

MwxχC

σ

≤,

and soMwxσ( +σ) <ε, which finishes the proof.

Remark . Let us note that in the case when=, Theorem . can only hold when

(∞).

Indeed, if Theorem . holds, then the operatorMwacts, in fact, fromL() intoE().

However, if we assume that∈/(∞) andw∈/L∞(,,μ), then defining the set

A=t:w(t)≥,

we haveμ(A) > . Therefore, we can buildxL() such thatsuppxA,I

(x)≤, and I(λx) =∞for anyλ>  (see [] and []). HenceI(Mwx)≥I(x) =∞, which means

thatMwx∈/E(), soMwdoes not act fromL() intoE().

Applying Theorem ., we directly get from Theorem . and the definition of a compact operator the following.

Theorem . If(,,μ)is a non-atomic complete finite or infinite butσ-finite measure space,then the multiplication operator cτ form L()into L()is compact whenever the set Mw(S(L))is relatively compact with respect to local convergence in measure and

condition()from Theorem.is satisfied.

Theorems . and . resemble closely the sufficiency part of Theorems . and . for the composition operator. Similarly, we will formulate necessary conditions for the equi-absolute continuity of the multiplication operator: one in the case whenμ() <∞and the other in the case whenμ() =∞. The respective proofs proceed along the lines of the proofs for the composition operator, and therefore will be omitted.

Theorem . If(,,μ)is a finite non-atomic and complete measure space and the mul-tiplication operator Mw:L()→L()is equi-absolutely continuous then the following

condition is satisfied:

σ> A∃∈

μ(A)=

L+()

t∈\Au∀≥

w(t)u(σu) +(t).

Theorem . If(,,μ)is an infinite but σ-finite non-atomic and complete measure space and the multiplication operator Mw:L()→L()is equi-absolutely continuous,

then the following condition is satisfied:

λ> A∃∈

μ(A)=

>L∃+()

t∈\Au∀≥

w(t)λu(u) +(t).

(17)

Competing interests

The authors declare that they have no competing interests.

Authors’ contributions

Although the subject of this paper was initiated by HH who was heading and controlling the scientific research of the other authors of the paper, all authors contributed equally to this paper. All authors read and approved the final manuscript.

Author details

1Department of Mathematics, Faculty of Mathematics and Computer Science, Adam Mickiewicz University in Pozna ´n,

Pozna ´n, Poland.2Department of Mathematics, Harbin University of Science and Technology, Harbin, 150080, P.R. China. 3Department of Mathematics, Payame Noor University (PNU), P.O. Box: 19395-3697, Tehran, Iran.

Acknowledgements

The second author is supported by NFS of Heilong Jiang province (A2015018).

Received: 11 August 2015 Accepted: 14 January 2016 References

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