Name:
U NIT 1 L EARNING G UIDE β E XPONENTS
I
NSTRUCTIONS:
Using a pencil, complete the following questions as you work through the related lessons.
Show ALL of your work as is explained in the lessons. Do your best and always ask questions if there is anything that you donβt understand.
1.1 E
XPONENTS1. Rewrite the following using digits.
Ex. Base: 3 Exponent: 5 ππ
ππa. Base: 7 Exponent: 4 b. Base: 9 Exponent: 3 c. Four to the power of one d. Base: 5 Exponent: 10
e. Twenty squared f. Two cubed
g. Base: 12 Exponent: 6 h. Base: 45 Exponent: 2 i. Seven to the power of eight 2. Expand.
Ex. 5
6ππ Γ ππ Γ ππ Γ ππ Γ ππ Γ ππ a. 2
4b. 7
2c. 9
8d. 25
1e. 3
53. Evaluate the following using your calculator.
Ex. 4
6ππππππππ a. 2
8b. 5
5c. 9
3d. 25
4e. 3
44. Insert >, <, or = to make each statement true.
Ex. 2
6> 6
2a. 3
3____ 27 b. 7
3____ 12
2c. 20
3____ 10
4d. 4
2____ 2
4e. 10
1____ 5
2f. 8
3____ 500 g. 50 ____ 25
2h. 2
6____ 8
25. Complete the table.
Perfect Squares
Exponent Expanded Perfect
Square 1
22 Γ 2 4
9 4 Γ 4
5
236 7 Γ 7
64 9
210 Γ 10
121 12
26. Circle the perfect squares.
βππ ππππ
ππππππππ ππππ ππ. ππ
ππππππ
ππ ππππ
ππππ
ππ
ππ
βππππππ ππππππ ππππ. ππ
1.2 BEDMAS
1. Solve. Reminder: Always use the Order of Operations (BEDMAS) when solving a problem.
Ex. 8
2β 2
5ππππ β ππππ ππππ a. 3
4β 2
3b. 4 Γ 7
2c. 3
3+
182d. (17 + 6) β 5
2e.
102222. Follow the steps to solve each problem. Reminder: After each operation that you complete, rewrite what remains in the problem.
Ex. 4 Γ (12 β 9)
3β 7
2a. (31 β 23)
2β 5
3Γ 3 b.
153Γ
(44β9)β5+ 2
4 Step 1:Brackets
ππ Γ ππ
ππβ ππ
ππ Step 2:Exponents
ππ Γ ππππ β ππππ
Step 3:Division &
Multiplication
ππππππ β ππππ
Step 4:Addition &
Subtraction
ππππ
3. Solve.
a. (9 β 2)
2+
168b.
81Γ (3 β 2)
5c. (8 + 5 Γ 5) β οΏ½
366οΏ½
295
4. Solve. Reminder: Treat numbers that are in the numerator and denominator of a fraction as though they are in brackets.
a.
532Γ5β25b.
18+(4+2)11β2 2c.
100β46 3Γ (8 β 3)
d. (49 β 57) Γ
17β8Γ242e. (63 Γ· 9)
2+
16β1152Γ 4 f. 2 + [9 + (9 β 4)
2] Γ 2
1.3 S
QUARER
OOTS OFP
ERFECTS
QUARES1. Follow the steps to find the square root of each number.
Question:
βWhat is the square root
of ___?β
Step 1: Find 2 identical numbers that have a product equal to the number in the square root sign.
Step 2: Use one of the numbers from Step 1.
Answer
How to say the answer.
Ex. β121 ππππ Γ ππππ ππππ
β11 is the squareroot of 121.β
a. β49
b. β100
c. β4
d. β144
e. β81
2. Write out the following using mathematical symbols.
Ex. The square root of 36 is 6.
βππππ = ππ
a. The square root of 9 is 3.
b. The square root of 64 is 8.
c. 8 squared is 64.
d. 12 squared is 144.
e. The square root of 196 is 14.
3. Evaluate without a calculator.
Ex. β25 5
a. β16 b. β64
c. β81 d. β1 e. β144
f. β36
g. β100
h. β121
4. Use prime factorization to find the square root of the perfect squares below.
Ex. β324
= 18a. β256
b. β484
c. β1225
5. Look at the factors of each number to determine whether or not it is a perfect square. If the number is a perfect square, circle the factor that is its square root.
a. 128: 1, 2, 4, 8, 16, 32, 64, 128 Perfect Square? Yes No b. 332: 1, 2, 4, 83, 166, 332 Perfect Square? Yes No c. 625: 1, 5, 25, 125, 625 Perfect Square? Yes No d. 171: 1, 3, 9, 19, 57, 171 Perfect Square? Yes No e. 361: 1, 19, 361 Perfect Square? Yes No f. 729: 1, 3, 9, 27, 81, 243, 729 Perfect Square? Yes No
6. In your own words, explain why numbers that are perfect squares have an odd number
of factors?
1.4 S
QUARER
OOTS OFW
HOLEN
UMBERS1. Fill in the missing information on the number line.
2. Determine between which two whole numbers each square root lies. Hint: Use the number line above to help you.
Ex. β105
Between 10 & 11
a. β57
b. β20 c. β2
d. β34 e. β139
3. Determine between which two square roots of perfect squares each number lies. Hint:
Use the number line above to help you.
Ex. 6.6
Between the βππππ & βππππ
a. 2.1
b. 7.4 c. 9.3
d. 4.9 e. 1.5
4. Use a number line to estimate the value of each square root to the nearest tenth. Use the βapproximately equalsβ sign (β) to show that the value is not exact. Reminder: Place all of the square roots that are between the perfect squares on the number line (with equal spacing), then use this as a guide to estimate the value of the square root.
Ex. β12
βππππ β ππ. ππ
a. β46
b. β21
c. β126
d. β29
5. Use your answers from Question 4 to find the square root of each number to 2 decimal places. Do not use a calculator. Hint: Find this method in the Examples #1 page of the lesson Square Roots of Whole Numbers.
Ex. β12
On the number line, the answer looks to be between 3.4 and 3.5.
3.4 Γ 3.4 = 11.56
3.5 Γ 3.5 = 12.15 The answer is between 3.4 and 3.5, but closer to 3.5 3.46 Γ 3.46 = 11.97
3.47 Γ 3.47 = 12.04 The answer is between 3.46 and 3.47. but is closest to 3.46
βππππ = ππ. ππππ
a. β46
b. β21
c. β126
6. Use your calculator to evaluate. Round your answer to 2 decimal places.
Ex. β88
= 9.38a. β2
b. β96 c. β500 d. β75
e. β20 000
1.5 P
YTHAGOREANT
HEOREM1. State whether each triangle is a right triangle or not. For each right triangle, identify the hypotenuse. Reminder: The hypotenuse is the side opposite the right angle.
Ex.
This is a right triangle.
a. d
b. d
c. d
d. d
e. d
2. Label the sides of the triangles with the letters a, b, and c. Reminder: The hypotenuse must be labelled βcβ.
a. b. c.
3. Using numbers 1 β 5, order the steps used to determine the length of a side of a right triangle using Pythagorasβ Theorem.
____________ Write out the formula: ππ
2+ ππ
2= ππ
2____________ Add the unit of measure to your answer
____________ Replace the variables ππ, ππ, and/or ππ with known values
Step 1Label the sides of the triangle ππ, ππ, and ππ
____________ Calculate
4. Follow the steps to calculate the length of the hypotenuse.
Ex.
Step 1: Label sides.
Step 2: ππ
ππ+ ππ
ππ= ππ
ππStep 3: ππππ
ππ+ ππ
ππ= ππ
ππStep 4: ππππππ + ππππ = ππ
ππππππππ = ππ
ππβππππππ = ππ ππππ = ππ Step 5: ππ = ππππ ππππ
a. a
b. a
c. a
d. a
e. a
5. Calculate the length of the hypotenuse. Round your answer to the nearest hundredth.
Reminder: Always write out the formula at the start of your calculations. Donβt forget to add the unit of measure to your answer.
a. s b. s c. s
6. Calculate the length of the unknown side. Round your answers to the nearest tenth.
Step 1: Label sides.
Step 2: ππ
ππ+ ππ
ππ= ππ
ππStep 3: ππ
ππ+ ππ
ππ= ππ
ππStep 4: ππππ + ππ
ππ= ππππ βππππ β ππππ ππ
ππ= ππππ ππ = βππππ ππ = ππ. ππππ Step 5: ππ = ππ. ππ ππ
a. b.
7. Which triangle in Question #6 is a Pythagorean triple? Why?
8. Use the Pythagorean Theorem to determine whether each triangle is a right triangle.
Reminder: After substituting in the values for ππ, ππ, & ππ, if ππ
2+ ππ
2= ππ
2, then you know that a triangle is a right triangle.
a. s b. c.
9. Use the Pythagorean Theorem to solve the problems below. Round your answers to the nearest tenth. Hint Draw a diagram of the problem as a first step to solving.
a. What is the height of computer screen that has a diagonal measurement of 22 inches and a width of 12 inches?
b. A door jamb has a height of 2.08 m, a width of 1.05 m and a diagonal measurement of 2.33 m. Are the corners of the door jamb square (ie. 90Β°)?
c. After take-off from the airport, a plane travels for in a straight trajectory until it
reaches its cruising altitude of 11 000 metres (11 km). At this point, it is directly
over a town that is 200km from the airport. Calculate the actual distance
1.6 C
UBES& C
UBER
OOTS1. Circle the perfect cubes.
2. Complete the table.
Perfect Cubes
Exponent Expanded Perfect
Cube 1
32 Γ 2 Γ 2 8
27 4 Γ 4 Γ 4
5
3216 10 Γ 10 Γ 10
3. Follow the steps to find the cube root of each number.
Question:
βWhat is the cube root of
___?β
Step 1: Find 3 identical numbers that have a product equal to the number in the cube root sign.
Step 2: Use one of the numbers from Step 1.
Answer
How to say the answer.
Ex.
3β125 ππ Γ ππ Γ ππ ππ
β5 is the cube rootof 125.β
a.
3β64
b.
3β729 c.
3β343 d.
3β512
ππππ ππππ
ππππ ππππππ βππ
ππππππ
ππ ππ. ππ
ππππ
ππ
ππ
ππππππππ ππππππ ππππ
4. Fill in the number line below.
5. Estimate the cube root of the following numbers. Write your answers using 1 decimal point. Hint: Use the number line above to help with your estimations.
Ex. β24
3β
ππ. ππ
a. β45
3b. β143
3c. β6
3d. β120
3e. β946
3f. β2
3g. β280
3h. β530
36. Evaluate using your calculator. Round your answers to the nearest hundredth.
Ex. β50
33.68
a. β400
3b. β16
3c. β100
3d. β1100
3e. β2
3f. β15 625
3g. β36
3h. β125 000
31.7 E
XPONENTL
AWS1. Expand, then simplify. Leave your answers in exponential form. Reminder: A number without an exponent is the same as that number having an exponent of 1.
Ex. 4
2Γ 4
5(ππ Γ ππ) Γ (ππ Γ ππ Γ ππ Γ ππ Γ ππ) ππ Γ ππ Γ ππ Γ ππ Γ ππ Γ ππ Γ ππ ππ
ππa. 7
4Γ 7
2b. 2
6Γ 2
3c. 5
4Γ 5
2. Simplify. Leave your answers in exponential form. Reminder: To multiply terms with exponents, you can add the exponents if the terms have the same base.
Ex. 6
4Γ 6
3ππ
ππ+ππ= ππ
ππa. 8
7Γ 8
2b. 3
5Γ 3
5Γ 3
2c. 9
3Γ 9
d. 15
2Γ 15
6e. οΏ½
13οΏ½
4Γ οΏ½
13οΏ½
33. Expand, then simplify. Leave your answers in exponential form.
Ex. 4
5Γ· 4
3a. 10
7Γ· 10
6b.
6662c. 14
6Γ· 14
64. Simplify. Leave your answers in exponential form. Reminder: To divide terms with exponents, you can subtract the exponents if the terms have the same base.
Ex. 2
8Γ· 2
2ππ
ππβππ= ππ
ππa. 25
10Γ· 25
7b.
6695c. 3
2Γ· 3
6d. 7
3Γ· 7
e.
4416155. Match each expression with its simplified form.
a. ππ
ππππΓ· ππ
ππππππ
ππππΓ ππ
ππb. ππ
ππΓ ππ
ππΓ ππ
ππππ
ππc. ππ
ππΓ ππ
ππΓ ππ
ππΓ ππ
ππ(βππ)
ππd. ππ
ππΓ· ππ
ππππ
ππΓ ππ
ππe. (βππ)
ππΓ· (βππ)
ππππ
ππf. ππ
ππΓ ππ
ππΓ ππ
ππΓ ππ
ππππ
ππg. ππ Γ ππ
ππΓ ππ ππ
ππππΓ ππ
ππh. ππ
ππΓ ππ
ππΓ ππ
ππΓ ππ
ππππ
ππ6. Simplify.
a. π₯π₯
10Γ π₯π₯
3b. ππ
5Γ ππ
6c. ππ Γ ππ Γ ππ Γ ππ
d. π¦π¦
12Γ· π¦π¦
8e.
ππππ72f.
ππππ67. Simplify the expressions as much as possible.
a. π₯π₯
2π¦π¦
3π₯π₯
5π¦π¦
7b. ππ
4ππ
3ππ
5ππ
2c. (π₯π₯
5π¦π¦
3)(π₯π₯
2π¦π¦
4)
d.
π¦π¦π¦π¦96π§π§π§π§43e.
ππππ52π π π π 73π‘π‘π‘π‘3f.
ππππ8ππ4ππ4ππ328. Simplify the expressions. Reminder: We can evaluate a number with an exponent, but not a variable with an exponent, unless we know the value of that exponent.
a.
33π₯π₯π₯π₯52π¦π¦2b.
ππ4πππ₯π₯65π₯π₯ππππ27c.
52βπ€π€23π€π€βπ€π€ππ8d.
2ππ52ππππ62ππππ32e.
π₯π₯5π₯π₯π¦π¦2π§π§2π₯π₯3π§π§42π§π§8f.
8ππ4ππ106ππππ91.8 E
XPONENTL
AWS2
1. Simplify. Reminder: The exponent outside of the brackets is applied to everything in the brackets.
Ex. (2π¦π¦
5)
3ππ
ππ= ππ
(ππ
ππ)
ππ= ππ
ππΓππ= ππ
ππππππππ
ππππa. (π₯π₯
4)
5b. (ππ
2ππ
3)
5c. (ππ
6ππ
2ππ
4)
4d. (2ππ
3)
6e. (5π₯π₯
7)
2f. (3ππ
2ππ)
3g. (4ππ
2ππβ
10)
42. Circle the expressions that are equal to 1. Reminder: Any number or variable to the power of 0 is equal to 1.
3. Expand, then evaluate. Reminder: Donβt forget to use the rules for multiplying negative numbers: (β)(β) = (+), (β)(+) = (β)
Ex. βππ
ππβ(ππ Γ ππ Γ ππ) = βππ a. (βππ)
ππc. (βππ)
ππd. (βππππ)
ππe. (βππππ)
ππa. ππ
ππb. (ππππ)
ππc. ππ
ππππ
ππd. ππππ
ππe. ππππππ
ππf. ππ
ππg. ππππ
ππππππ
ππh. ππ
ππi. (ππππ
ππ)
ππj. (ππππ
ππ)
ππ4. Determine whether the product will be positive or negative and circle your answer. You do not have to evaluate the expressions. Reminder: When the negative sign is not inside brackets, the exponent does not affect the negative.
a. (βππ)
ππPOS NEG b. (βππ)
ππPOS NEG c. βππ
ππPOS NEG d. β(ππππ)
ππPOS NEG
e. βππππ
ππPOS NEG f. β(ππππ)
ππPOS NEG g. (βππππ
ππ)
ππPOS NEG h. (βππππ
ππ)
ππPOS NEG 5. Simplify and evaluate.
a. (ππ
6ππ
2)
2(ππππ
3)
5b. (π₯π₯
2π¦π¦
2π§π§
2)
5(π₯π₯
6π¦π¦)
3c. (5ππ
4ππ
2)
3(ππ
2ππ
0)
4d. (2ππ
2ππ
2)
4(6ππ
6ππ
2)
0(β3ππ
3)
36. Simplify in order to remove the negative exponents. Leave you answers in exponent form.
Reminder: A negative exponent can be removed by taking the reciprocal (ie. opposite) of that number.
Ex. 6
β2ππ
ππππ
a. 4
β6b. π¦π¦
β3c. (5π₯π₯)
β4d. 5π₯π₯
β4e. 3
β8π¦π¦
27. Simplify in order to remove the negative exponents. Leave you answers in exponent form.
a.
31β2b.
π₯π₯1β2c.
π¦π¦5β6d.
32β4β2e.
π₯π₯π¦π¦β2β8f.
33β238. Simplify. Answer in exponent form and with no negative exponents. Reminder: The rules of multiplying negative and positive numbers applies to exponents as well.
a. (4
2)
β3b. (4
β2)
β3c. (π₯π₯
β5)
0d. (17
0)
β6e. (99
β9)
9f. (2π¦π¦
β2)
39. Expand. Do not simplify.
Ex. (3ππ + 1)
2(ππππ + ππ)(ππππ + ππ)
a. (β4π‘π‘ + 5)
2b. (π₯π₯ β 3)
4c. (3ππ + 2ππ β 6)
3d. (6ππ
2ππ)
4e. (β2π₯π₯
2+ 5π₯π₯ + 4)
210. Use all of the skills you have learned so far to simplify the following expressions as much as possible. Answer without negative exponents.
a. (ππ
6)
3(ππ
3)
β4b.
(40π¦π¦(9π¦π¦)5β2)01.9 M
IXEDE
XPONENTS1. Identify the base. Reminder: The base is everything that the exponent is applied to.
Ex. (β4π‘π‘ + 5)
2(βππππ + ππ) a. β4π‘π‘ + 5
2b. (β6)(3π£π£)
β3c. (6ππππ)
4d. 100π₯π₯
3e. (63)(β1)(8)
102. Identify the coefficient in each of the following a. -4t ____________
b. 14v
3___________
c. 345a
4b
4___________
d. 100___________
e.
π₯π₯104___________
3. Simplify.
Ex.
a.
b.
c.
d.
e.
4. Simplify so that only positive exponents remain in your answer. Hint: Take your time and keep your work neat.
a. b.
οΏ½ 2 π₯π₯οΏ½
3
οΏ½ 1 ππβοΏ½
6
οΏ½ 4 π¦π¦οΏ½
2
οΏ½ 5 π€π€οΏ½
β3
c.
d.
e.
f.
g.
i. (π₯π₯
3+π₯π₯)(2π₯π₯
4)
j.
k.
l.
m.
3
π₯π₯β23
β2π₯π₯+1(3π₯π₯
2βπ§π§) Γ (π₯π₯
4) Γ· (3
2π₯π₯
β4)
οΏ½3π₯π₯2
β2π¦π¦οΏ½ οΏ½
8π₯π₯β3π¦π¦4 33π₯π₯β5οΏ½
β2π₯π₯
2π¦π¦
5π¦π¦
β3Γ 15π₯π₯
0π¦π¦
π₯π₯π¦π¦
β21.10 E
XPONENTA
PPLICATIONS1. Solve the following equations for x.
Ex. 10
5π₯π₯+2= 10
12ππππ + ππ = ππππ ππππ = ππππ ππ = ππ a. 5
π₯π₯= 5
6b. ππ
3= ππ
π₯π₯c. 3
π₯π₯= 27
d. 81 = 9
π₯π₯e. 8
π₯π₯+3= 8
7f. 6
2π₯π₯β2= 6
π₯π₯+3g.
h. 216 = 6
4π₯π₯+52. Solve. Round your answers to the nearest hundredth. Reminder: The opposite of a power is a root.
Ex. 66 = π₯π₯
3 βππππππ= ππ
ππ = ππ. ππππa. 37 = π₯π₯
2b. 102 = π¦π¦
3c. ππ
2= 550
d. ππ
2β 9 = 254
e. β
3+ 100 = 725
f.
ππ42= 79
g. 1038 = 6π₯π₯
3οΏ½ 1
4
π₯π₯οΏ½
3= 4
3. Find the length of a side for each square. Round your answers to the nearest hundredth. Reminder: The formula for the area of a square is π΄π΄ = π π π π ππππ
2a. A square with area: 700 ππππ
2b. A square with area:
48.5 ππππ
2c. A square with area: 15 ππππ
2d. A square with area: 2700 ππ
24. Find the radius of each circle. Use 3.14 for ππ. Round your answers to the nearest thousandth. Reminder: The formula for the area of a circle is π΄π΄ = ππππ
2a. A circle with area: 29 ππππ
2b. A circle with area: 221 ππ
2c. A circle with area: 504 ππππ
2d. A circle with area: 8060 ππ
25. Find the radius of each sphere. Use 3.14 for ππ. Round your answers to the nearest tenth.
Reminder: The formula for the volume of a sphere is ππ =
43ππππ
3a. A sphere with volume: 29 ππππ
3c. A sphere with volume: 950 ππππ
36. You have $10 000 in a Education Savings Fund. It is in an investment with a
compounding annual interest rate of 3%. What is the value of the fund after 15 years?
Use the following formula: π΄π΄ = ππ(1 + π π )
ππA = Final value (Principle + Interest)
P = Principal amount (Starting or Initial investment amount) i = interest rate as a decimal
n = number of years invested
U NIT 1 β A NSWER K EY
S
ECTION1.1
1. a. 7
4b. 9
3c. 4
1d. 5
10e. 20
2f. 2
3g. 12
6h. 45
2i. 7
82. a. 2 Γ 2 Γ 2 Γ 2 b. 7 Γ 7 c. 9 Γ 9 Γ 9 Γ 9 Γ 9 Γ 9 Γ 9 Γ 9 d. 25 e. 3 Γ 3 Γ 3 Γ 3 Γ 3
3. a. 256 b. 3125 c. 729 d. 390 625 e. 81 4. a. = b. > c. < d. = e. < f. > g. < h. = 5.
6. 30
2, 400, 64, 11
2, 625
S
ECTION1.2
1. a. 73 b. 196 c. 36 d. -2 e. 25 2. a. -311 b. -19
3. a. 51 b. 9 c. -3 d. -316
Perfect Squares
Exponent Expanded Perfect Square
12 1 Γ 1 1
22 2 Γ 2 4
32 3 Γ 3 9
42 4 Γ 4 16
52 5 Γ 5 25
62 6 Γ 6 36
72 7 Γ 7 49
82 8 Γ 8 64
92 9 Γ 9 81
102 10 Γ 10 100
112 11 Γ 11 121
122 12 Γ 12 144
S
ECTION1.3
1. a. 7 b. 10 c. 2 d. 12 e. 9
2. a. β9 = 3 b. β64 = 8 c. 8
2= 64 d. 12
2= 144 e. β196 = 14 3. a. 4 b. 8 c. 9 d. 1 e. 12 f. 6 g. 10 h. 11
4. a. 16 b. 22 c. 35
5. a. No b. No c. Yes, 25 d. No e. Yes, 19 f. Yes, 27
6. Because the factor pair of a perfect square is a repeat of itself, therefore you only see one of that number in the list of factors, turning the list of factors pairs into a odd number.
S
ECTION1.4
1.
2. a. 7 & 8 b. 4 & 5 c. 1 & 2 d. 5 & 6 e. 11 & 12
3. a. β4 & β9 b. β49 & β64 c. β81 & β100 d. β16 & β25 e. β1 & β4 4. a. β 6.8 b. β 4.6 c. β 11.2 d. β 5.4
5. a. 6.78 b. 4.58 c. 11.22
6. a. 1.41 b. 9.8 c. 22.36 d. 8.66 e. 141.42
S
ECTION1.5
1. a. Yes b. Yes c. No d. No e. Yes
2. Note: a & b can be switched places, but c must always be the longest side.
3. 2, 5, 3, 1, 4
4. a. 10 cm b. 13 cm c. 35 mm d. 20 cm e. 26 m 5. a. 6.08 cm b. 17.80 km c. 78.87 m
6. a. 15 cm b. 13.2 m
7. 6.a. Because all of its sides are positive integers.
8. a. Yes b. No c. Yes
9. a. 18.4 in b. Yes, the corners are square. This is because the triangles formed by the diagonal are right triangles (as proven by Pythagorasβ Theorem), which means the angles in the corners of the door jamb are 90Β°. c. 200.3 km
S
ECTION1.6
1. 30
3, 8, 216, 64, 1000, 125 2.
3. a. 4 b. 9 c. 7 d. 8
4. β1
3, β8
3, β27
3, β64
3, β125
3, β216
3, β343
3, β512
3, β729
3, β1000
35. Note: Answers +/- 0.1 from the stated answer are considered accurate estimations.
a. β 3.6 b. β 5.2 c. β 1.8 d. β 4.9 e. β 9.8 f. β 1.3 g. β 6.5 h. β 8.1 6. a. 7.37 b. 2.52 c. 4.64 d. 10.32 e. 1.26 f. 25 g. 3.3 h. 50
S
ECTION1.7
1. a. 7
6b. 2
9c. 5
52. a. 8
9b. 3
12c. 9
4d. 15
8e. οΏ½
13οΏ½
73. a. 10
1ππππ 10 b. 6
4c. 14
04. a. 25
3b. 6
4c. 3
β4d. 7
2e. 4
1 Perfect CubesExponent Expanded Perfect
Cube
13 1 Γ 1 Γ 1 1
23 2 Γ 2 Γ 2 8
33 3 Γ 3 Γ 3 27
43 4 Γ 4 Γ 4 64
53 5 Γ 5 Γ 5 125
63 6 Γ 6 Γ 6 216
103 10 Γ 10 Γ 10 1000