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Name:

U NIT 1 L EARNING G UIDE – E XPONENTS

I

NSTRUCTIONS

:

Using a pencil, complete the following questions as you work through the related lessons.

Show ALL of your work as is explained in the lessons. Do your best and always ask questions if there is anything that you don’t understand.

1.1 E

XPONENTS

1. Rewrite the following using digits.

Ex. Base: 3 Exponent: 5 πŸ‘πŸ‘

πŸ“πŸ“

a. Base: 7 Exponent: 4 b. Base: 9 Exponent: 3 c. Four to the power of one d. Base: 5 Exponent: 10

e. Twenty squared f. Two cubed

g. Base: 12 Exponent: 6 h. Base: 45 Exponent: 2 i. Seven to the power of eight 2. Expand.

Ex. 5

6

πŸ“πŸ“ Γ— πŸ“πŸ“ Γ— πŸ“πŸ“ Γ— πŸ“πŸ“ Γ— πŸ“πŸ“ Γ— πŸ“πŸ“ a. 2

4

b. 7

2

c. 9

8

d. 25

1

e. 3

5

3. Evaluate the following using your calculator.

Ex. 4

6

πŸ’πŸ’πŸ’πŸ’πŸ’πŸ’πŸ’πŸ’ a. 2

8

b. 5

5

c. 9

3

d. 25

4

e. 3

4

(2)

4. Insert >, <, or = to make each statement true.

Ex. 2

6

> 6

2

a. 3

3

____ 27 b. 7

3

____ 12

2

c. 20

3

____ 10

4

d. 4

2

____ 2

4

e. 10

1

____ 5

2

f. 8

3

____ 500 g. 50 ____ 25

2

h. 2

6

____ 8

2

5. Complete the table.

Perfect Squares

Exponent Expanded Perfect

Square 1

2

2 Γ— 2 4

9 4 Γ— 4

5

2

36 7 Γ— 7

64 9

2

10 Γ— 10

121 12

2

6. Circle the perfect squares.

βˆ’πŸ’πŸ’ πŸ‘πŸ‘πŸ’πŸ’

𝟐𝟐

πŸ’πŸ’πŸ’πŸ’πŸ’πŸ’ πŸπŸπŸ’πŸ’ 𝟐𝟐. πŸ“πŸ“

𝟐𝟐

πŸ’πŸ’πŸ’πŸ’

πŸ‘πŸ‘ 𝟏𝟏𝟏𝟏

𝟐𝟐

𝟏𝟏

𝟐𝟐

𝟐𝟐

βˆ’πŸπŸπŸ’πŸ’πŸ’πŸ’ πŸ’πŸ’πŸπŸπŸ“πŸ“ πŸ‘πŸ‘πŸ’πŸ’. 𝟏𝟏

(3)

1.2 BEDMAS

1. Solve. Reminder: Always use the Order of Operations (BEDMAS) when solving a problem.

Ex. 8

2

βˆ’ 2

5

πŸ’πŸ’πŸ’πŸ’ βˆ’ πŸ‘πŸ‘πŸπŸ πŸ‘πŸ‘πŸπŸ a. 3

4

βˆ’ 2

3

b. 4 Γ— 7

2

c. 3

3

+

182

d. (17 + 6) βˆ’ 5

2

e.

10222

2. Follow the steps to solve each problem. Reminder: After each operation that you complete, rewrite what remains in the problem.

Ex. 4 Γ— (12 βˆ’ 9)

3

βˆ’ 7

2

a. (31 βˆ’ 23)

2

βˆ’ 5

3

Γ— 3 b.

153

Γ—

(44βˆ’9)βˆ’5

+ 2

4 Step 1:

Brackets

πŸ’πŸ’ Γ— πŸ‘πŸ‘

πŸ‘πŸ‘

βˆ’ πŸ•πŸ•

𝟐𝟐 Step 2:

Exponents

πŸ’πŸ’ Γ— πŸπŸπŸ•πŸ• βˆ’ πŸ’πŸ’πŸ’πŸ’

Step 3:

Division &

Multiplication

πŸπŸπŸ’πŸ’πŸπŸ βˆ’ πŸ’πŸ’πŸ’πŸ’

Step 4:

Addition &

Subtraction

πŸ“πŸ“πŸ’πŸ’

3. Solve.

a. (9 βˆ’ 2)

2

+

168

b.

81

Γ— (3 βˆ’ 2)

5

c. (8 + 5 Γ— 5) βˆ’ οΏ½

366

οΏ½

2

95

(4)

4. Solve. Reminder: Treat numbers that are in the numerator and denominator of a fraction as though they are in brackets.

a.

532Γ—5βˆ’25

b.

18+(4+2)11βˆ’2 2

c.

100βˆ’46 3

Γ— (8 βˆ’ 3)

d. (49 βˆ’ 57) Γ—

17βˆ’8Γ—242

e. (63 Γ· 9)

2

+

16βˆ’1152

Γ— 4 f. 2 + [9 + (9 βˆ’ 4)

2

] Γ— 2

(5)

1.3 S

QUARE

R

OOTS OF

P

ERFECT

S

QUARES

1. Follow the steps to find the square root of each number.

Question:

β€œWhat is the square root

of ___?”

Step 1: Find 2 identical numbers that have a product equal to the number in the square root sign.

Step 2: Use one of the numbers from Step 1.

Answer

How to say the answer.

Ex. √121 𝟏𝟏𝟏𝟏 Γ— 𝟏𝟏𝟏𝟏 𝟏𝟏𝟏𝟏

β€œ11 is the square

root of 121.”

a. √49

b. √100

c. √4

d. √144

e. √81

2. Write out the following using mathematical symbols.

Ex. The square root of 36 is 6.

βˆšπŸ‘πŸ‘πŸ’πŸ’ = πŸ’πŸ’

a. The square root of 9 is 3.

b. The square root of 64 is 8.

c. 8 squared is 64.

d. 12 squared is 144.

e. The square root of 196 is 14.

3. Evaluate without a calculator.

Ex. √25 5

a. √16 b. √64

c. √81 d. √1 e. √144

f. √36

g. √100

h. √121

(6)

4. Use prime factorization to find the square root of the perfect squares below.

Ex. √324

= 18

a. √256

b. √484

c. √1225

5. Look at the factors of each number to determine whether or not it is a perfect square. If the number is a perfect square, circle the factor that is its square root.

a. 128: 1, 2, 4, 8, 16, 32, 64, 128 Perfect Square? Yes No b. 332: 1, 2, 4, 83, 166, 332 Perfect Square? Yes No c. 625: 1, 5, 25, 125, 625 Perfect Square? Yes No d. 171: 1, 3, 9, 19, 57, 171 Perfect Square? Yes No e. 361: 1, 19, 361 Perfect Square? Yes No f. 729: 1, 3, 9, 27, 81, 243, 729 Perfect Square? Yes No

6. In your own words, explain why numbers that are perfect squares have an odd number

of factors?

(7)

1.4 S

QUARE

R

OOTS OF

W

HOLE

N

UMBERS

1. Fill in the missing information on the number line.

2. Determine between which two whole numbers each square root lies. Hint: Use the number line above to help you.

Ex. √105

Between 10 & 11

a. √57

b. √20 c. √2

d. √34 e. √139

3. Determine between which two square roots of perfect squares each number lies. Hint:

Use the number line above to help you.

Ex. 6.6

Between the βˆšπŸ‘πŸ‘πŸ’πŸ’ & βˆšπŸ’πŸ’πŸ’πŸ’

a. 2.1

b. 7.4 c. 9.3

d. 4.9 e. 1.5

4. Use a number line to estimate the value of each square root to the nearest tenth. Use the β€œapproximately equals” sign (β‰ˆ) to show that the value is not exact. Reminder: Place all of the square roots that are between the perfect squares on the number line (with equal spacing), then use this as a guide to estimate the value of the square root.

Ex. √12

√𝟏𝟏𝟐𝟐 β‰ˆ πŸ‘πŸ‘. πŸ’πŸ’

a. √46

(8)

b. √21

c. √126

d. √29

5. Use your answers from Question 4 to find the square root of each number to 2 decimal places. Do not use a calculator. Hint: Find this method in the Examples #1 page of the lesson Square Roots of Whole Numbers.

Ex. √12

On the number line, the answer looks to be between 3.4 and 3.5.

3.4 Γ— 3.4 = 11.56

3.5 Γ— 3.5 = 12.15 The answer is between 3.4 and 3.5, but closer to 3.5 3.46 Γ— 3.46 = 11.97

3.47 Γ— 3.47 = 12.04 The answer is between 3.46 and 3.47. but is closest to 3.46

√𝟏𝟏𝟐𝟐 = πŸ‘πŸ‘. πŸ’πŸ’πŸ’πŸ’

a. √46

(9)

b. √21

c. √126

6. Use your calculator to evaluate. Round your answer to 2 decimal places.

Ex. √88

= 9.38

a. √2

b. √96 c. √500 d. √75

e. √20 000

(10)

1.5 P

YTHAGOREAN

T

HEOREM

1. State whether each triangle is a right triangle or not. For each right triangle, identify the hypotenuse. Reminder: The hypotenuse is the side opposite the right angle.

Ex.

This is a right triangle.

a. d

b. d

c. d

d. d

e. d

2. Label the sides of the triangles with the letters a, b, and c. Reminder: The hypotenuse must be labelled β€œc”.

a. b. c.

3. Using numbers 1 – 5, order the steps used to determine the length of a side of a right triangle using Pythagoras’ Theorem.

____________ Write out the formula: π‘Žπ‘Ž

2

+ 𝑏𝑏

2

= 𝑐𝑐

2

____________ Add the unit of measure to your answer

____________ Replace the variables π‘Žπ‘Ž, 𝑏𝑏, and/or 𝑐𝑐 with known values

Step 1

Label the sides of the triangle π‘Žπ‘Ž, 𝑏𝑏, and 𝑐𝑐

____________ Calculate

(11)

4. Follow the steps to calculate the length of the hypotenuse.

Ex.

Step 1: Label sides.

Step 2: 𝒂𝒂

𝟐𝟐

+ 𝒃𝒃

𝟐𝟐

= 𝒄𝒄

𝟐𝟐

Step 3: 𝟏𝟏𝟐𝟐

𝟐𝟐

+ πŸ’πŸ’

𝟐𝟐

= 𝒄𝒄

𝟐𝟐

Step 4: πŸπŸπŸ’πŸ’πŸ’πŸ’ + 𝟏𝟏𝟏𝟏 = 𝒄𝒄

𝟐𝟐

πŸπŸπŸπŸπŸ“πŸ“ = 𝒄𝒄

𝟐𝟐

βˆšπŸπŸπŸπŸπŸ“πŸ“ = 𝒄𝒄 πŸπŸπŸ“πŸ“ = 𝒄𝒄 Step 5: 𝒄𝒄 = πŸπŸπŸ“πŸ“ 𝒄𝒄𝒄𝒄

a. a

b. a

c. a

d. a

e. a

(12)

5. Calculate the length of the hypotenuse. Round your answer to the nearest hundredth.

Reminder: Always write out the formula at the start of your calculations. Don’t forget to add the unit of measure to your answer.

a. s b. s c. s

6. Calculate the length of the unknown side. Round your answers to the nearest tenth.

Step 1: Label sides.

Step 2: 𝒂𝒂

𝟐𝟐

+ 𝒃𝒃

𝟐𝟐

= 𝒄𝒄

𝟐𝟐

Step 3: πŸ“πŸ“

𝟐𝟐

+ 𝒃𝒃

𝟐𝟐

= πŸ•πŸ•

𝟐𝟐

Step 4: πŸπŸπŸ“πŸ“ + 𝒃𝒃

𝟐𝟐

= πŸ’πŸ’πŸ’πŸ’ βˆ’πŸπŸπŸ“πŸ“ βˆ’ πŸπŸπŸ“πŸ“ 𝒃𝒃

𝟐𝟐

= πŸπŸπŸ’πŸ’ 𝒃𝒃 = βˆšπŸπŸπŸ’πŸ’ 𝒃𝒃 = πŸ’πŸ’. πŸ’πŸ’πŸ’πŸ’ Step 5: 𝒃𝒃 = πŸ’πŸ’. πŸ’πŸ’ 𝒄𝒄

a. b.

(13)

7. Which triangle in Question #6 is a Pythagorean triple? Why?

8. Use the Pythagorean Theorem to determine whether each triangle is a right triangle.

Reminder: After substituting in the values for π‘Žπ‘Ž, 𝑏𝑏, & 𝑐𝑐, if π‘Žπ‘Ž

2

+ 𝑏𝑏

2

= 𝑐𝑐

2

, then you know that a triangle is a right triangle.

a. s b. c.

9. Use the Pythagorean Theorem to solve the problems below. Round your answers to the nearest tenth. Hint Draw a diagram of the problem as a first step to solving.

a. What is the height of computer screen that has a diagonal measurement of 22 inches and a width of 12 inches?

b. A door jamb has a height of 2.08 m, a width of 1.05 m and a diagonal measurement of 2.33 m. Are the corners of the door jamb square (ie. 90Β°)?

c. After take-off from the airport, a plane travels for in a straight trajectory until it

reaches its cruising altitude of 11 000 metres (11 km). At this point, it is directly

over a town that is 200km from the airport. Calculate the actual distance

(14)

1.6 C

UBES

& C

UBE

R

OOTS

1. Circle the perfect cubes.

2. Complete the table.

Perfect Cubes

Exponent Expanded Perfect

Cube 1

3

2 Γ— 2 Γ— 2 8

27 4 Γ— 4 Γ— 4

5

3

216 10 Γ— 10 Γ— 10

3. Follow the steps to find the cube root of each number.

Question:

β€œWhat is the cube root of

___?”

Step 1: Find 3 identical numbers that have a product equal to the number in the cube root sign.

Step 2: Use one of the numbers from Step 1.

Answer

How to say the answer.

Ex.

3

√125 πŸ“πŸ“ Γ— πŸ“πŸ“ Γ— πŸ“πŸ“ πŸ“πŸ“

β€œ5 is the cube root

of 125.”

a.

3

√64

b.

3

√729 c.

3

√343 d.

3

√512

𝟐𝟐𝟏𝟏 πŸ‘πŸ‘πŸ’πŸ’

πŸ‘πŸ‘

𝟏𝟏 πŸπŸπŸπŸπŸ’πŸ’ βˆ’πŸ’πŸ’

πŸ“πŸ“

πŸ’πŸ’πŸ’πŸ’

πŸ‘πŸ‘ πŸ’πŸ’. 𝟏𝟏

πŸ‘πŸ‘

𝟏𝟏

𝟐𝟐

πŸ‘πŸ‘

πŸπŸπŸ’πŸ’πŸ’πŸ’πŸ’πŸ’ πŸπŸπŸπŸπŸ“πŸ“ πŸ‘πŸ‘πŸ’πŸ’

(15)

4. Fill in the number line below.

5. Estimate the cube root of the following numbers. Write your answers using 1 decimal point. Hint: Use the number line above to help with your estimations.

Ex. √24

3

β‰ˆ

𝟐𝟐. πŸ’πŸ’

a. √45

3

b. √143

3

c. √6

3

d. √120

3

e. √946

3

f. √2

3

g. √280

3

h. √530

3

6. Evaluate using your calculator. Round your answers to the nearest hundredth.

Ex. √50

3

3.68

a. √400

3

b. √16

3

c. √100

3

d. √1100

3

e. √2

3

f. √15 625

3

g. √36

3

h. √125 000

3

(16)

1.7 E

XPONENT

L

AWS

1. Expand, then simplify. Leave your answers in exponential form. Reminder: A number without an exponent is the same as that number having an exponent of 1.

Ex. 4

2

Γ— 4

5

(πŸ’πŸ’ Γ— πŸ’πŸ’) Γ— (πŸ’πŸ’ Γ— πŸ’πŸ’ Γ— πŸ’πŸ’ Γ— πŸ’πŸ’ Γ— πŸ’πŸ’) πŸ’πŸ’ Γ— πŸ’πŸ’ Γ— πŸ’πŸ’ Γ— πŸ’πŸ’ Γ— πŸ’πŸ’ Γ— πŸ’πŸ’ Γ— πŸ’πŸ’ πŸ’πŸ’

πŸ•πŸ•

a. 7

4

Γ— 7

2

b. 2

6

Γ— 2

3

c. 5

4

Γ— 5

2. Simplify. Leave your answers in exponential form. Reminder: To multiply terms with exponents, you can add the exponents if the terms have the same base.

Ex. 6

4

Γ— 6

3

πŸ’πŸ’

πŸ’πŸ’+πŸ‘πŸ‘

= πŸ’πŸ’

πŸ•πŸ•

a. 8

7

Γ— 8

2

b. 3

5

Γ— 3

5

Γ— 3

2

c. 9

3

Γ— 9

d. 15

2

Γ— 15

6

e. οΏ½

13

οΏ½

4

Γ— οΏ½

13

οΏ½

3

3. Expand, then simplify. Leave your answers in exponential form.

Ex. 4

5

Γ· 4

3

a. 10

7

Γ· 10

6

b.

6662

c. 14

6

Γ· 14

6

4. Simplify. Leave your answers in exponential form. Reminder: To divide terms with exponents, you can subtract the exponents if the terms have the same base.

Ex. 2

8

Γ· 2

2

𝟐𝟐

πŸπŸβˆ’πŸπŸ

= 𝟐𝟐

πŸ’πŸ’

a. 25

10

Γ· 25

7

b.

6695

c. 3

2

Γ· 3

6

d. 7

3

Γ· 7

e.

441615

(17)

5. Match each expression with its simplified form.

a. πŸ•πŸ•

πŸπŸπŸ’πŸ’

Γ· πŸ•πŸ•

𝟏𝟏𝟏𝟏

πŸ•πŸ•

πŸπŸπŸ’πŸ’

Γ— πŸ“πŸ“

πŸ“πŸ“

b. πŸ•πŸ•

𝟐𝟐

Γ— πŸ•πŸ•

πŸ“πŸ“

Γ— πŸ•πŸ•

𝟐𝟐

πŸ•πŸ•

πŸ‘πŸ‘

c. πŸ•πŸ•

πŸ’πŸ’

Γ— πŸ•πŸ•

πŸ’πŸ’

Γ— πŸ“πŸ“

𝟐𝟐

Γ— πŸ“πŸ“

πŸ‘πŸ‘

(βˆ’πŸ•πŸ•)

πŸ’πŸ’

d. πŸ•πŸ•

πŸ•πŸ•

Γ· πŸ•πŸ•

πŸ’πŸ’

πŸ•πŸ•

𝟏𝟏

Γ— πŸ“πŸ“

πŸ•πŸ•

e. (βˆ’πŸ•πŸ•)

πŸ’πŸ’

Γ· (βˆ’πŸ•πŸ•)

πŸ“πŸ“

πŸ•πŸ•

πŸ’πŸ’

f. πŸ•πŸ•

πŸ’πŸ’

Γ— πŸ•πŸ•

πŸ’πŸ’

Γ— πŸ•πŸ•

𝟐𝟐

Γ— πŸ“πŸ“

πŸ‘πŸ‘

πŸ•πŸ•

πŸ“πŸ“

g. πŸ•πŸ• Γ— πŸ•πŸ•

πŸ‘πŸ‘

Γ— πŸ•πŸ• πŸ•πŸ•

𝟏𝟏𝟐𝟐

Γ— πŸ“πŸ“

πŸ‘πŸ‘

h. πŸ“πŸ“

πŸ’πŸ’

Γ— πŸ•πŸ•

πŸ’πŸ’

Γ— πŸ•πŸ•

𝟐𝟐

Γ— πŸ“πŸ“

πŸ‘πŸ‘

πŸ•πŸ•

πŸ•πŸ•

6. Simplify.

a. π‘₯π‘₯

10

Γ— π‘₯π‘₯

3

b. 𝑛𝑛

5

Γ— 𝑛𝑛

6

c. π‘Žπ‘Ž Γ— π‘Žπ‘Ž Γ— π‘Žπ‘Ž Γ— π‘Žπ‘Ž

d. 𝑦𝑦

12

Γ· 𝑦𝑦

8

e.

π‘šπ‘šπ‘šπ‘š72

f.

𝑓𝑓𝑓𝑓6

7. Simplify the expressions as much as possible.

a. π‘₯π‘₯

2

𝑦𝑦

3

π‘₯π‘₯

5

𝑦𝑦

7

b. π‘Žπ‘Ž

4

𝑏𝑏

3

π‘Žπ‘Ž

5

𝑏𝑏

2

c. (π‘₯π‘₯

5

𝑦𝑦

3

)(π‘₯π‘₯

2

𝑦𝑦

4

)

d.

𝑦𝑦𝑦𝑦96𝑧𝑧𝑧𝑧43

e.

π‘Ÿπ‘Ÿπ‘Ÿπ‘Ÿ52𝑠𝑠𝑠𝑠73𝑑𝑑𝑑𝑑3

f.

π‘Žπ‘Žπ‘Žπ‘Ž8𝑏𝑏4𝑏𝑏4𝑐𝑐32

(18)

8. Simplify the expressions. Reminder: We can evaluate a number with an exponent, but not a variable with an exponent, unless we know the value of that exponent.

a.

33π‘₯π‘₯π‘₯π‘₯52𝑦𝑦2

b.

𝑑𝑑4𝑑𝑑π‘₯π‘₯65π‘₯π‘₯𝑓𝑓𝑑𝑑27

c.

52β„Žπ‘€π‘€23π‘€π‘€β„Žπ‘€π‘€π‘‘π‘‘8

d.

2π‘Žπ‘Ž52π‘Žπ‘Žπ‘π‘62π‘π‘π‘Žπ‘Ž32

e.

π‘₯π‘₯5π‘₯π‘₯𝑦𝑦2𝑧𝑧2π‘₯π‘₯3𝑧𝑧42𝑧𝑧8

f.

8π‘šπ‘š4π‘šπ‘š106𝑛𝑛𝑛𝑛9

(19)

1.8 E

XPONENT

L

AWS

2

1. Simplify. Reminder: The exponent outside of the brackets is applied to everything in the brackets.

Ex. (2𝑦𝑦

5

)

3

𝟐𝟐

πŸ‘πŸ‘

= 𝟏𝟏

(π’šπ’š

πŸ“πŸ“

)

πŸ‘πŸ‘

= π’šπ’š

πŸ“πŸ“Γ—πŸ‘πŸ‘

= π’šπ’š

πŸπŸπŸ“πŸ“

πŸπŸπ’šπ’š

πŸπŸπŸ“πŸ“

a. (π‘₯π‘₯

4

)

5

b. (π‘Žπ‘Ž

2

𝑏𝑏

3

)

5

c. (𝑑𝑑

6

𝑒𝑒

2

𝑓𝑓

4

)

4

d. (2𝑛𝑛

3

)

6

e. (5π‘₯π‘₯

7

)

2

f. (3π‘Žπ‘Ž

2

𝑏𝑏)

3

g. (4𝑓𝑓

2

π‘”π‘”β„Ž

10

)

4

2. Circle the expressions that are equal to 1. Reminder: Any number or variable to the power of 0 is equal to 1.

3. Expand, then evaluate. Reminder: Don’t forget to use the rules for multiplying negative numbers: (βˆ’)(βˆ’) = (+), (βˆ’)(+) = (βˆ’)

Ex. βˆ’πŸπŸ

πŸ‘πŸ‘

βˆ’(𝟐𝟐 Γ— 𝟐𝟐 Γ— 𝟐𝟐) = βˆ’πŸπŸ a. (βˆ’πŸπŸ)

πŸ‘πŸ‘

c. (βˆ’πŸπŸ)

πŸ’πŸ’

d. (βˆ’πŸπŸπŸπŸ)

πŸ“πŸ“

e. (βˆ’πŸπŸπŸπŸ)

πŸ’πŸ’

a. πŸ•πŸ•

πŸ’πŸ’

b. (πŸπŸπ’šπ’š)

πŸ’πŸ’

c. 𝟐𝟐

πŸ’πŸ’

𝟐𝟐

πŸ’πŸ’

d. πŸπŸπ’šπ’š

πŸ’πŸ’

e. πŸ’πŸ’πŸ•πŸ•πŸ“πŸ“

πŸ’πŸ’

f. πŸ’πŸ’

πŸ’πŸ’

g. πŸ“πŸ“π’‚π’‚

πŸ’πŸ’

πŸ‘πŸ‘π’ƒπ’ƒ

𝟐𝟐

h. 𝒉𝒉

πŸ’πŸ’

i. (πŸ’πŸ’πŸ—πŸ—

πŸ“πŸ“

)

πŸ’πŸ’

j. (πŸ’πŸ’πŸ—πŸ—

πŸ’πŸ’

)

πŸ“πŸ“

(20)

4. Determine whether the product will be positive or negative and circle your answer. You do not have to evaluate the expressions. Reminder: When the negative sign is not inside brackets, the exponent does not affect the negative.

a. (βˆ’πŸπŸ)

πŸ‘πŸ‘

POS NEG b. (βˆ’πŸπŸ)

πŸ’πŸ’

POS NEG c. βˆ’πŸπŸ

𝟐𝟐

POS NEG d. βˆ’(𝟐𝟐𝟐𝟐)

𝟐𝟐

POS NEG

e. βˆ’πŸπŸπŸπŸ

πŸ’πŸ’

POS NEG f. βˆ’(𝟐𝟐𝟐𝟐)

πŸ•πŸ•

POS NEG g. (βˆ’πŸπŸπŸπŸ

πŸ“πŸ“

)

𝟐𝟐

POS NEG h. (βˆ’πŸπŸπŸπŸ

πŸ“πŸ“

)

πŸ‘πŸ‘

POS NEG 5. Simplify and evaluate.

a. (𝑑𝑑

6

𝑒𝑒

2

)

2

(𝑑𝑑𝑒𝑒

3

)

5

b. (π‘₯π‘₯

2

𝑦𝑦

2

𝑧𝑧

2

)

5

(π‘₯π‘₯

6

𝑦𝑦)

3

c. (5π‘šπ‘š

4

𝑛𝑛

2

)

3

(π‘šπ‘š

2

𝑛𝑛

0

)

4

d. (2π‘Žπ‘Ž

2

𝑏𝑏

2

)

4

(6π‘Žπ‘Ž

6

𝑏𝑏

2

)

0

(βˆ’3π‘Žπ‘Ž

3

)

3

6. Simplify in order to remove the negative exponents. Leave you answers in exponent form.

Reminder: A negative exponent can be removed by taking the reciprocal (ie. opposite) of that number.

Ex. 6

βˆ’2

𝟏𝟏

πŸ’πŸ’πŸπŸ

a. 4

βˆ’6

b. 𝑦𝑦

βˆ’3

c. (5π‘₯π‘₯)

βˆ’4

d. 5π‘₯π‘₯

βˆ’4

e. 3

βˆ’8

𝑦𝑦

2

7. Simplify in order to remove the negative exponents. Leave you answers in exponent form.

a.

31βˆ’2

b.

π‘₯π‘₯1βˆ’2

c.

𝑦𝑦5βˆ’6

(21)

d.

32βˆ’4βˆ’2

e.

π‘₯π‘₯π‘¦π‘¦βˆ’2βˆ’8

f.

33βˆ’23

8. Simplify. Answer in exponent form and with no negative exponents. Reminder: The rules of multiplying negative and positive numbers applies to exponents as well.

a. (4

2

)

βˆ’3

b. (4

βˆ’2

)

βˆ’3

c. (π‘₯π‘₯

βˆ’5

)

0

d. (17

0

)

βˆ’6

e. (99

βˆ’9

)

9

f. (2𝑦𝑦

βˆ’2

)

3

9. Expand. Do not simplify.

Ex. (3π‘Ÿπ‘Ÿ + 1)

2

(πŸ‘πŸ‘πŸ‘πŸ‘ + 𝟏𝟏)(πŸ‘πŸ‘πŸ‘πŸ‘ + 𝟏𝟏)

a. (βˆ’4𝑑𝑑 + 5)

2

b. (π‘₯π‘₯ βˆ’ 3)

4

c. (3π‘Žπ‘Ž + 2𝑏𝑏 βˆ’ 6)

3

d. (6π‘šπ‘š

2

𝑛𝑛)

4

e. (βˆ’2π‘₯π‘₯

2

+ 5π‘₯π‘₯ + 4)

2

10. Use all of the skills you have learned so far to simplify the following expressions as much as possible. Answer without negative exponents.

a. (π‘Žπ‘Ž

6

)

3

(π‘Žπ‘Ž

3

)

βˆ’4

b.

(40𝑦𝑦(9𝑦𝑦)5βˆ’2)0

(22)

1.9 M

IXED

E

XPONENTS

1. Identify the base. Reminder: The base is everything that the exponent is applied to.

Ex. (βˆ’4𝑑𝑑 + 5)

2

(βˆ’πŸ’πŸ’πŸ’πŸ’ + πŸ“πŸ“) a. βˆ’4𝑑𝑑 + 5

2

b. (βˆ’6)(3𝑣𝑣)

βˆ’3

c. (6π‘Žπ‘Žπ‘π‘)

4

d. 100π‘₯π‘₯

3

e. (63)(βˆ’1)(8)

10

2. Identify the coefficient in each of the following a. -4t ____________

b. 14v

3

___________

c. 345a

4

b

4

___________

d. 100___________

e.

π‘₯π‘₯104

___________

3. Simplify.

Ex.

a.

b.

c.

d.

e.

4. Simplify so that only positive exponents remain in your answer. Hint: Take your time and keep your work neat.

a. b.

οΏ½ 2 π‘₯π‘₯οΏ½

3

οΏ½ 1 π‘”π‘”β„ŽοΏ½

6

οΏ½ 4 𝑦𝑦�

2

οΏ½ 5 𝑀𝑀�

βˆ’3

(23)

c.

d.

e.

f.

g.

i. (π‘₯π‘₯

3+π‘₯π‘₯

)(2π‘₯π‘₯

4

)

j.

k.

l.

m.

3

π‘₯π‘₯βˆ’2

3

βˆ’2π‘₯π‘₯+1

(3π‘₯π‘₯

2βˆ’π‘§π‘§

) Γ— (π‘₯π‘₯

4

) Γ· (3

2

π‘₯π‘₯

βˆ’4

)

οΏ½3π‘₯π‘₯2

βˆ’2𝑦𝑦� οΏ½

8π‘₯π‘₯βˆ’3𝑦𝑦4 33π‘₯π‘₯βˆ’5οΏ½

βˆ’2π‘₯π‘₯

2

𝑦𝑦

5𝑦𝑦

βˆ’3

Γ— 15π‘₯π‘₯

0

𝑦𝑦

π‘₯π‘₯𝑦𝑦

βˆ’2

(24)

1.10 E

XPONENT

A

PPLICATIONS

1. Solve the following equations for x.

Ex. 10

5π‘₯π‘₯+2

= 10

12

πŸ“πŸ“πŸπŸ + 𝟐𝟐 = 𝟏𝟏𝟐𝟐 πŸ“πŸ“πŸπŸ = πŸπŸπŸ’πŸ’ 𝟐𝟐 = 𝟐𝟐 a. 5

π‘₯π‘₯

= 5

6

b. 𝑛𝑛

3

= 𝑛𝑛

π‘₯π‘₯

c. 3

π‘₯π‘₯

= 27

d. 81 = 9

π‘₯π‘₯

e. 8

π‘₯π‘₯+3

= 8

7

f. 6

2π‘₯π‘₯βˆ’2

= 6

π‘₯π‘₯+3

g.

h. 216 = 6

4π‘₯π‘₯+5

2. Solve. Round your answers to the nearest hundredth. Reminder: The opposite of a power is a root.

Ex. 66 = π‘₯π‘₯

3 βˆšπŸ’πŸ’πŸ’πŸ’πŸ‘πŸ‘

= 𝟐𝟐

𝟐𝟐 = πŸ’πŸ’. πŸ’πŸ’πŸ’πŸ’

a. 37 = π‘₯π‘₯

2

b. 102 = 𝑦𝑦

3

c. π‘Žπ‘Ž

2

= 550

d. 𝑑𝑑

2

βˆ’ 9 = 254

e. β„Ž

3

+ 100 = 725

f.

π‘šπ‘š42

= 79

g. 1038 = 6π‘₯π‘₯

3

οΏ½ 1

4

π‘₯π‘₯

οΏ½

3

= 4

(25)

3. Find the length of a side for each square. Round your answers to the nearest hundredth. Reminder: The formula for the area of a square is 𝐴𝐴 = 𝑠𝑠𝑠𝑠𝑑𝑑𝑒𝑒

2

a. A square with area: 700 π‘π‘π‘šπ‘š

2

b. A square with area:

48.5 π‘˜π‘˜π‘šπ‘š

2

c. A square with area: 15 π‘šπ‘šπ‘šπ‘š

2

d. A square with area: 2700 π‘šπ‘š

2

4. Find the radius of each circle. Use 3.14 for πœ‹πœ‹. Round your answers to the nearest thousandth. Reminder: The formula for the area of a circle is 𝐴𝐴 = πœ‹πœ‹π‘Ÿπ‘Ÿ

2

a. A circle with area: 29 π‘˜π‘˜π‘šπ‘š

2

b. A circle with area: 221 π‘šπ‘š

2

c. A circle with area: 504 π‘π‘π‘šπ‘š

2

d. A circle with area: 8060 π‘šπ‘š

2

5. Find the radius of each sphere. Use 3.14 for πœ‹πœ‹. Round your answers to the nearest tenth.

Reminder: The formula for the volume of a sphere is 𝑉𝑉 =

43

πœ‹πœ‹π‘Ÿπ‘Ÿ

3

a. A sphere with volume: 29 π‘šπ‘šπ‘šπ‘š

3

c. A sphere with volume: 950 π‘π‘π‘šπ‘š

3

(26)

6. You have $10 000 in a Education Savings Fund. It is in an investment with a

compounding annual interest rate of 3%. What is the value of the fund after 15 years?

Use the following formula: 𝐴𝐴 = 𝑃𝑃(1 + 𝑠𝑠)

𝑛𝑛

A = Final value (Principle + Interest)

P = Principal amount (Starting or Initial investment amount) i = interest rate as a decimal

n = number of years invested

(27)

U NIT 1 – A NSWER K EY

S

ECTION

1.1

1. a. 7

4

b. 9

3

c. 4

1

d. 5

10

e. 20

2

f. 2

3

g. 12

6

h. 45

2

i. 7

8

2. a. 2 Γ— 2 Γ— 2 Γ— 2 b. 7 Γ— 7 c. 9 Γ— 9 Γ— 9 Γ— 9 Γ— 9 Γ— 9 Γ— 9 Γ— 9 d. 25 e. 3 Γ— 3 Γ— 3 Γ— 3 Γ— 3

3. a. 256 b. 3125 c. 729 d. 390 625 e. 81 4. a. = b. > c. < d. = e. < f. > g. < h. = 5.

6. 30

2

, 400, 64, 11

2

, 625

S

ECTION

1.2

1. a. 73 b. 196 c. 36 d. -2 e. 25 2. a. -311 b. -19

3. a. 51 b. 9 c. -3 d. -316

Perfect Squares

Exponent Expanded Perfect Square

12 1 Γ— 1 1

22 2 Γ— 2 4

32 3 Γ— 3 9

42 4 Γ— 4 16

52 5 Γ— 5 25

62 6 Γ— 6 36

72 7 Γ— 7 49

82 8 Γ— 8 64

92 9 Γ— 9 81

102 10 Γ— 10 100

112 11 Γ— 11 121

122 12 Γ— 12 144

(28)

S

ECTION

1.3

1. a. 7 b. 10 c. 2 d. 12 e. 9

2. a. √9 = 3 b. √64 = 8 c. 8

2

= 64 d. 12

2

= 144 e. √196 = 14 3. a. 4 b. 8 c. 9 d. 1 e. 12 f. 6 g. 10 h. 11

4. a. 16 b. 22 c. 35

5. a. No b. No c. Yes, 25 d. No e. Yes, 19 f. Yes, 27

6. Because the factor pair of a perfect square is a repeat of itself, therefore you only see one of that number in the list of factors, turning the list of factors pairs into a odd number.

S

ECTION

1.4

1.

2. a. 7 & 8 b. 4 & 5 c. 1 & 2 d. 5 & 6 e. 11 & 12

3. a. √4 & √9 b. √49 & √64 c. √81 & √100 d. √16 & √25 e. √1 & √4 4. a. β‰ˆ 6.8 b. β‰ˆ 4.6 c. β‰ˆ 11.2 d. β‰ˆ 5.4

5. a. 6.78 b. 4.58 c. 11.22

6. a. 1.41 b. 9.8 c. 22.36 d. 8.66 e. 141.42

S

ECTION

1.5

1. a. Yes b. Yes c. No d. No e. Yes

2. Note: a & b can be switched places, but c must always be the longest side.

3. 2, 5, 3, 1, 4

4. a. 10 cm b. 13 cm c. 35 mm d. 20 cm e. 26 m 5. a. 6.08 cm b. 17.80 km c. 78.87 m

6. a. 15 cm b. 13.2 m

(29)

7. 6.a. Because all of its sides are positive integers.

8. a. Yes b. No c. Yes

9. a. 18.4 in b. Yes, the corners are square. This is because the triangles formed by the diagonal are right triangles (as proven by Pythagoras’ Theorem), which means the angles in the corners of the door jamb are 90Β°. c. 200.3 km

S

ECTION

1.6

1. 30

3

, 8, 216, 64, 1000, 125 2.

3. a. 4 b. 9 c. 7 d. 8

4. √1

3

, √8

3

, √27

3

, √64

3

, √125

3

, √216

3

, √343

3

, √512

3

, √729

3

, √1000

3

5. Note: Answers +/- 0.1 from the stated answer are considered accurate estimations.

a. β‰ˆ 3.6 b. β‰ˆ 5.2 c. β‰ˆ 1.8 d. β‰ˆ 4.9 e. β‰ˆ 9.8 f. β‰ˆ 1.3 g. β‰ˆ 6.5 h. β‰ˆ 8.1 6. a. 7.37 b. 2.52 c. 4.64 d. 10.32 e. 1.26 f. 25 g. 3.3 h. 50

S

ECTION

1.7

1. a. 7

6

b. 2

9

c. 5

5

2. a. 8

9

b. 3

12

c. 9

4

d. 15

8

e. οΏ½

13

οΏ½

7

3. a. 10

1

π‘œπ‘œπ‘Ÿπ‘Ÿ 10 b. 6

4

c. 14

0

4. a. 25

3

b. 6

4

c. 3

βˆ’4

d. 7

2

e. 4

1 Perfect Cubes

Exponent Expanded Perfect

Cube

13 1 Γ— 1 Γ— 1 1

23 2 Γ— 2 Γ— 2 8

33 3 Γ— 3 Γ— 3 27

43 4 Γ— 4 Γ— 4 64

53 5 Γ— 5 Γ— 5 125

63 6 Γ— 6 Γ— 6 216

103 10 Γ— 10 Γ— 10 1000

(30)

7. a. π‘₯π‘₯

7

𝑦𝑦

10

b. π‘Žπ‘Ž

9

𝑏𝑏

5

c. π‘₯π‘₯

7

𝑦𝑦

7

d. 𝑦𝑦

3

𝑧𝑧 e. π‘Ÿπ‘Ÿ

3

𝑠𝑠

4

𝑑𝑑

2

f. π‘Žπ‘Ž

4

𝑏𝑏𝑐𝑐

2

8. a. 27π‘₯π‘₯

3

𝑦𝑦

2

b. 𝑑𝑑

5

π‘₯π‘₯

3

𝑓𝑓 c.

β„Žπ‘€π‘€25𝑑𝑑4

d. 32π‘Žπ‘Ž

2

𝑏𝑏 e. π‘₯π‘₯

7

𝑦𝑦

2

𝑧𝑧

3

f. 2π‘šπ‘š

4

𝑛𝑛

8

S

ECTION

1.8

1. a. π‘₯π‘₯

20

b. π‘Žπ‘Ž

10

𝑏𝑏

15

c. 𝑑𝑑

24

𝑒𝑒

8

𝑓𝑓

16

d. 64𝑛𝑛

18

e. 25π‘₯π‘₯

14

f. 27π‘Žπ‘Ž

6

𝑏𝑏

3

g. 256𝑓𝑓

8

𝑔𝑔

4

β„Ž

40

2. a, b, e, h, i

3. a. -8 b. -16 c. 16 d. βˆ’32π‘₯π‘₯

5

e. 64π‘₯π‘₯

6

4. a. NEG b. POS c. NEG d. NEG e. NEG f. NEG g. POS h. NEG 5. a. 𝑑𝑑

17

𝑒𝑒

19

b. π‘₯π‘₯

28

𝑦𝑦

13

𝑧𝑧

10

c. 125π‘šπ‘š

20

𝑛𝑛

6

d. βˆ’432π‘Žπ‘Ž

17

𝑏𝑏

8

6. a.

416

b.

𝑦𝑦13

c.

541π‘₯π‘₯4

π‘œπ‘œπ‘Ÿπ‘Ÿ

(5π‘₯π‘₯)1 4

d.

π‘₯π‘₯54

e.

𝑦𝑦382

7. a. 3

2

b. π‘₯π‘₯

2

c. 5𝑦𝑦

6

d.

2324

e.

𝑦𝑦π‘₯π‘₯82

f. (3

2

)(3

3

) π‘œπ‘œπ‘Ÿπ‘Ÿ 3

5

8. a.

416

b. 4

6

c. π‘₯π‘₯

0

d. 17

0

e.

99181

f.

𝑦𝑦236

9. a. (βˆ’4𝑑𝑑 + 5)(βˆ’4𝑑𝑑 + 5) b. (π‘₯π‘₯ βˆ’ 3)(π‘₯π‘₯ βˆ’ 3)(π‘₯π‘₯ βˆ’ 3)(π‘₯π‘₯ βˆ’ 3)

c. (3π‘Žπ‘Ž + 2𝑏𝑏 βˆ’ 6)(3π‘Žπ‘Ž + 2𝑏𝑏 βˆ’ 6)(3π‘Žπ‘Ž + 2𝑏𝑏 βˆ’ 6) d. (6π‘šπ‘š

2

𝑛𝑛)(6π‘šπ‘š

2

𝑛𝑛)(6π‘šπ‘š

2

𝑛𝑛)(6π‘šπ‘š

2

𝑛𝑛) e. (βˆ’2π‘₯π‘₯

2

+ 5π‘₯π‘₯ + 4)(βˆ’2π‘₯π‘₯

2

+ 5π‘₯π‘₯ + 4)

10. a. π‘Žπ‘Ž

6

b.

81𝑦𝑦12

S

ECTION

1.9

1. a. 5 b. 3v c. 6ab d. x e. 8

2. a. -4 b. 14 c. 345 d. none e. 1/10

3. a.

16𝑦𝑦2

b.

𝑔𝑔61β„Ž6

c.

243π‘Žπ‘Žπ‘π‘1020

d.

64π‘Žπ‘Žπ‘π‘1212

e. βˆ’8π‘₯π‘₯

3

𝑦𝑦

3

4. a.

125𝑀𝑀3

b.

3π‘₯π‘₯𝑦𝑦34

c.

25β„Žπ‘§π‘§84

d.

216𝑓𝑓1 15

e.

81𝑦𝑦648𝑧𝑧2

f.

16𝑦𝑦π‘₯π‘₯8𝑧𝑧84

g.

𝑔𝑔24096π‘˜π‘˜10𝑧𝑧6

h.

16𝑦𝑦𝑧𝑧59

i. 2π‘₯π‘₯

7+π‘₯π‘₯

j. 3

3x-3

π‘œπ‘œπ‘Ÿπ‘Ÿ

3273π‘₯π‘₯

k.

π‘₯π‘₯10βˆ’π‘§π‘§3

l. βˆ’

4π‘₯π‘₯94𝑦𝑦3

m. βˆ’6π‘₯π‘₯𝑦𝑦

7

(31)

S

ECTION

1.10

1. a. 6 b. 3 c. 3 d. 2 e. 4 f. 5 g. βˆ’

13

h. βˆ’

12

2. a. Β±6.08 b. 4.67 c. Β±23.45 d. Β±16.22 e. 8.55 f. Β±17.78 g. 5.57 3. a. 26.46 cm b. 6.96 km c. 3.87 mm d. 51.96 m

4. a. 3.039 km b. 8.389 m c. 12.669 cm d. 50.664 m 5. a. 1.9 mm b. 3.0 m c. 6.1 cm d. 1.1 km

6. $15 579.67

References

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