s
Energy Automation
7UT6: Low impedance
Restricted Earth Fault
No. 1 with
Energy Automation
Internal single pole fault’s close to transformer star point
? ?
w1
w2
(1
f)
w2
f
I
I
;
R
X
f
3
/
U
f
I
;
L
?
X
FHV FLV 2 F 2 2 LV LV F?
?
?
?
?
?
?
?
?
?
?
Example: Autotransformer 500MVA , 400/230kV, u
k12= 15.8%
Inductivity L
? winding
2; R
F
= fault resistance
Short circuited winding part f
I
F HV[p.u. HV side]
I
F LV[p.u. LV side]
I
F tot[p.u. LV side]
I
F[p.u.]
400kV 230kVf
0 1 L2 L3w2
w1
Trip F 2 Ftot F F 2 Ftot FI
R
;
Energy
:
W
I
R
t
P
?
?
?
?
?
No. 1 with
Energy Automation
Limits of the differential protection (1 of 2)
Earth fault current limited by R
Eto I
Emax= 2000A ; R
E>> X
Tr?
?
?
?
?
?
1N 2N Emax 2 1N 2N F K Emax E 2N FU
3
/
U
I
f
U
3
/
U
f
I
I
and
I
f
R
3
/
U
f
I
?
?
?
?
?
?
?
?
?
?
?
?
* *?
* nO * K * K * K Elim D nO1 K * K nO2 F * F 2 K FI/I
0.222
I/I
0.478
0.063I/I
I
1
I
I
0
1
I
:
Correction
Io
0.063I/I
I
1.154
I
I
0
3
1
I
:
n
Eliminatio
-Io
0.055
A
4.82A/87.5
/I
I
I
;
0.478
400A/837A
/I
I
I
;
4.82A
132kV
3
13.8kV/
2000A
0.2
I
;
400A
2000A
0.2
I
?
?
?
?
?
?
?
?
?
?
?
?
?
?
?
?
?
?
?
?
?
?
?
?
?
?
Will the differential protection detect the fault (setting I
Diff> = 0.25I/InO , slope 1 = 0.25) ?
(fault location 20% from the star point)
…/1A
20 MVA ; YNd5 Side 1: 132kV Side 2: 13.8kV
2L1
2L2
2L3
1L1
1L2
1L3
100/1A
…/1A
~
~
~
R
Ef
1
0
I
nO2= 837A
I
nO1= 87.5A
No. 1 with
Energy Automation
Limits of the differential protection (2 of 2)
With the above setting the differential protection (with Io-correction)
would only just fail to pick up!
Short circuited winding part f
I
F[p.u. 13.8kV side]
I
D CorIo-correction
I
D ElimIo-elimination
I
K[p.u. 132kV side]
I
F,I
D,I
K[p.u.]
Diff. pickup at nom. load
Diff. pickup at no load
REF
Example
In the example at hand, it is therefore advisable to connect a CT with earth
current relay (pick up threshold 200A) in the earth connection of the star-point,
to increase the range of protection coverage to 90%.
This protection however requires a large time delay setting as the earth current
relay in the system must trip faster to maintain selectivity.
No. 1 with
Energy Automation
7UT6: Restricted Earth Fault Protection (General)
The REF measures the Neutral current of the object ( I
SP= 3I
0’ ) and, depending on the
angle (? f ) between 3I
0’and the also measured sum of the phase currents
( 3I
0’’ = I
L1+ I
L2+ I
L3), decides for internal or external fault.
The sensitivity of the REF is almost independent from the load of the object.
(The sensitivity of the “Differential Function” especially for high ohm faults will be reduced
by the load due to the slope of its “Tripping Characteristic” ).
The REF can be stetted to 0.1 I/I
NOand is therefore more sensitive as the
“Differential Protection” (even without load).
No. 1 with
Energy Automation
7UT6: Tripping Characteristic of REF (1 of 3)
?
?
?
?
???
?
???
?
?
?
?
?
?
?
?
?
?
?
?
?
???
?
???
?
?
?
?
?
?
?
?
?
?
?
?
?
?
?
?
?
?
?
?
?
?
?
?
?
?
?
?
?
3Io'
'
3Io'
e
1
3Io'
'
3Io'
e
1
k
1
I
I
3Io'
o'
I
3
I
3Io'
'
3Io'
e
1
3Io'
'
3Io'
e
1
k
o'
I
3
I
1
'
3Io'
e
3Io'
'
3Io'
e
3Io'
k
I
I
0
)
'
o'
I
(3
reference,
'
o'
I
3
'
o'
I
3
o'
I
3
'
o'
I
3
o'
I
3
k
I
I
j? j? REF REF REF j? j? REF j? j? REF REF ? ? ? ? ? ??
REF REFfor 7UT612 : k ˜ 2
for 7UT613/63 k ˜ 4
2) for extended Trip-Area (90° = ? f = 180°):
I
REF> = Setting value (Trip Threshold)
I
Rest= Restraint current
I
REF= ¦ 3I
0’¦
1) for basic Trip-Area (0° = ? f = 90°):
I
REF= ¦ 3I
0’¦ and must be = I
REF>
Characteristic_1)
:
I
REF/ I
REF> = 1 (no restraining current I
Resteffective)
?
?
?
?
?
?
?
?
?
?
?
?
?
?
?
3Io'
'
3Io'
e
1
3Io'
'
3Io'
e
1
k
1
1
I
I
:
stic_2)
Characteri
j? j? REF REF ? ?I
REF= I
REF> + k·I
Restwhere I
Rest= (¦ 3I
0’-3I
0’’¦ -¦ 3I
0’+3I
0’’¦ )
I
Restincludes the direction
No. 1 with
Energy Automation
7UT6: Tripping Characteristic of REF (2 of 3)
90° = ? f = 0°
Characteristic _1)
180° = ? f > 90°
Characteristic_2)
-0.1
-0.2
-0.3
+0.1
+0.2
+0.3
1
2
3
4
0.0
?
REF REFI
I
' 0 '' 03I
3I
Tripping
Blocking
Char. for
?f = 180°
No. 1 with
Energy Automation
7UT6: Tripping Characteristic of REF (3 of 3)
3I
0’
I
Rest= (¦ 3I
0’-3I
0’’¦ -¦ 3I
0’+3I
0’’¦ ) = 0
-3I
0’’
+3I
0’’
3I
0’-3I
0’’
3I
0’+3I
0’’
3I
0’’
Figure 4
?f =90°
Figure 5
?f < 90°
3I
0’
-3I
0’’
+3I
0’’
3I
0’+3I
0’’
3I
0’-3I
0’’
I
Rest3I
0’’
I
Rest= (¦ 3I
0’-3I
0’’¦ -¦ 3I
0’+3I
0’’¦ )
< 0
(neg. values will be set to 0)
? f = 45°
Figure 3
?f > 90°
3I
0’
-3I
0’’
+3I
0’’
3I
0’+3I
0’’
3I
0’-3I
0’’
I
Rest3I
0’’
I
Rest= (¦ 3I
0’-3I
0’’¦ -¦ 3I
0’+3I
0’’¦ ) > 0
? f = 135°
No. 1 with
Energy Automation
7UT6: REF CT saturation at star point CT (1 of 2)
The star point CT can or even should be weaker designed than the phase Ct’s !
In case of an external fault and saturation on this CT there will be no false trip.
No. 1 with
Energy Automation
No. 1 with
Energy Automation
Comparison of sensitivity between
Differential Protection and REF
200/1A
38.1 MVA ; Vector group: YNd5
Side 2: 11kV Side 1: 110kV
1L1
1L2
1L3
2L1
2L2
2L3
2000/1A
200/1A
No. 1 with
Energy Automation
Settings
No. 1 with
Energy Automation
No. 1 with
Energy Automation
Fault 1: Internal high ohm Fault L1-E Side 1, without Load (2 of 3)
Idiff ? 0.11 I/InO
Only Ires, no Idiff for L2,L3
No. 1 with
Energy Automation
Fault 1: Internal high ohm Fault L1-E Side 1, without Load (3 of 3)
Trip Area
Block Area
No. 1 with
Energy Automation
No. 1 with
Energy Automation
Fault 2: Internal high ohm Fault L1-E Side 1, with Load (2 of 3)
I
ref= actual current, I
REF= Setting I
REF>,
Ks = 1, IoL = I
0’’, IoSt = I
0’
No. 1 with
Energy Automation
Fault 2: Internal high ohm Fault L1-E Side 1, with Load (3 of 3)
3I
0’’ = 3·6.49mA = 19.47mA, ? 3I
0’/ 3I
0’’ = 19.47/140 = 0.139
InO = 200A ? 1000mA, I
= 140mA, I
> = 0.1 ? I
/I
> = 1.4
No. 1 with
Energy Automation
7UT6: REF settings
1.0
?
I
InO
InO
I
Ref3.5
1313A slope = 0.1I
Ref>
0
0.5
1.5
2.0
2.5
3.0
0
0.2
0.1
0.3
Increasing the pickup value
nominal
load
? I = ¦ I
L1¦ + ¦ I
L2¦ + ¦ I
L3¦ + ¦ I
SP¦
(to be handled with care) !!!
proposed value
No. 1 with
Energy Automation
Setting the direction of the Star point CT
Transformer-winding
L1
L2
L3
7UT612
Q7
Q8
0230 Earthing Electrode versus Terminal Q7
7UT612
Q7
Q8
0230 Earthing Electrode versus Terminal Q7
7UT612
Q7
Q8
0230 Earthing Electrode versus Terminal Q8
7UT612
Q7
Q8
0230 Earthing Electrode versus Terminal Q8
Secondary earthing of Star point CT has no influence on the direction
Setting for “CT-Strpnt in Direct. Of Object”
No. 1 with Energy Automation
7UT6: versions
No
1
7UT612
Version 4.0
Yes
No
REF for
Autotransformer
2
1
Number of
Low impedance REF
7UT613/63.
Version 4.6
(Jan. 2006)
7UT613/63.
No. 1 with
Energy Automation
Application
Device Configuration
0105 Protected Object 3 phase Transformer
0112 Differential Protection Enabled
0113 REF Protection Enabled
Power System Data 1
CT-Numbers
0211 No. of connected Meas. Loc. 2
0212 No. of assigned Meas. Loc. 2
0213 No. of sides 2
CT-Assign
0222 Assignment at 2 assig.
Meas.Loc./2 sides S1:M1, S2:M2
0251 Auxiliary CT IX1 is used as Side 1 earth
0252 Auxiliary CT IX2 is used as Side 2 earth
Transf. ….
0313 Starpoint of Side 1 is Solid Earthed
0314 Transf. Winding Connection Side 1 Y (Wye) ….
0323 Starpoint of Side 2 is Solid Earthed (!!)
0324 Transf. Winding Connection Side 2 D (Delta)
0325 Vector Group Numeral of Side 2 11
Funct.
0413 REF assigned to Side 2
0420 DMT/IDMT Phase assigned to Side 1
Setting Group A
Differential Protection-Settings Group A
1211A Diff-Prot. with meas. Earth Curr. S1 Yes (Io- correct. Side 1)
1212A Diff-Prot. with meas. Earth Curr. S2 No
X2 X1
Y
?
7UT613
M1 M2 Main protect. object S1 S2 Starpoint-bilder Sides:S1 High voltage side (HV) S2 Low voltage side (LV)
Measuring locations 3-phase , assigned
M1 assigned to the main protected object (side 1) M2 assigned to the main protected object (side 2) Auxiliary measuring locations 1-phase
X1 assigned to the main protected object (side 1) X2 assigned to the main protected object (side 2) X3 not assigned to the main protected object
No. 1 with
Energy Automation
7UT6: REF Interturn fault / terminal earth fault
? ?
= 180° ? no Trip by REF
200/1A
38.1 MVA ; Vector group: YNd5
Side 2: 11kV Side 1: 110kV
1L1
1L2
1L3
2L1
2L2
2L3
2000/1A
200/1A
~
~
~
(+)
(-)
I
SP
= 0 ? no Trip by REF
200/1A
38.1 MVA ; Vector group: YNd5
Side 2: 11kV Side 1: 110kV
1L1
1L2
1L3
2L1
2L2
2L3
2000/1A
200/1A
~
~
~
I
SP
No. 1 with
Energy Automation
7UT6: REF, testing the characteristic
(1 of 3)
Configuration:
Winding 1:
80MVA,110kV 500/1A
500/1A
A
A
kV
A
kVA
I
U
I
S
I
im NCT NTr NCTSec NTr n0
.
839
500
110
3
1
80000
3
Pr?
?
?
?
?
?
?
?
?
No. 1 with
Energy Automation
7UT6: REF testing the characteristic
(2 of 3)
Test point 1:
Io’ = 2 I
REF> = 2
?
0.1
?
0.839A = 0.168A = constant. Io’’: at the begin approximate 0.4
?
0.168A
e
j180°=0.067A, than reducing step by step until trip
?
Result: -21mA/168mA = -0.125
Test point 2:
Io’ = 4 I
REF> = 4
?
0.1
?
0.839A = 0.336A = constant. Io’’: at the begin approximate 0.4
?
0.336A
e
j180°=0.134A, than reducing step by step until trip
?
Result: -60mA/336mA
?
0.18
No. 1 with
Energy Automation