Nominal rates of interest and discount
• i(m): The nominal rate of interest payable m times per period, where m is a positive integer > 1. By a nominal rate of interest i(m), we mean a rate payable mthly, i.e. the rate of interest is i(m)/m for each mth of a period and not i(m). Thus,
1 + i =
1 + i
(m)
m
and
i =
1 + i
(m)
m
m
− 1 i(m) = m[(1 + i)m1 − 1]
• d(m): The nominal rate of discount payable m times per period. Thus,
1 − d =
1 − d
(m)
m
and
d = 1 −
1 − d
(m)
m
m
d(m) = m[1 − (1 − d)m1 ] = m[1 − vm1 ]
Generally,
1 + i
(m)
m
m
=
1 − d
(p)
p
If m = p,
1 + i
(m)
m
=
1 − d
(m)
m
−1
=⇒ i
(m)
m −
d(m)
m =
i(m) m ·
d(m) m .
Force of interest and discount
• δt: the force of interest at time t, is defined asδt = a
0(t)
a(t) =
A0(t) A(t)
= d
dt ln A(t) = d
dt ln a(t) Thus,
Z t
0
δrdr =
Z t
0
d
dr ln A(r)dr = ln A(r)|
t
0 = ln
A(t) A(0)
Hence,
eR0t δrdr = A(t)
A(0) =
a(t)
a(0) = a(t) Note that
Z n
0
A(t)δt =
Z n
0
A0(t)dt = A(n) − A(0).
If δt = δ, 0 ≤ t ≤ n, then
so that
eδ = 1 + i =⇒ i = eδ − 1 =⇒ δ = ln(1 + i)
• δt0: the force of discount at time t, is defined by
δt0 = −
d dta
−1(t)
a−1(t) .
δt0 = −
d dta
−1(t)
= a
−2(t) d
dta(t)
a−1(t)
= a
−2(t)a(t)δ
t
a−1(t) = δt
Some properties of force of interest
• For simple interest
δt =
d
dta(t)
a(t)
=
d
dt(1 + it)
1 + it
= i
• For simple discount
δt = δt0 = −
d dta
−1(t)
a−1(t)
= −
d
dt(1 − dt)
1 − dt
= d
1 − dt for 0 ≤ t < 1 d.
• i > δ
i = eδ − 1 = δ + δ
2
2! + δ3
3! + δ4
• lim
m→∞ i
(m)
= δ
1 + i
(m)
m
m
= eδ
i(m) = m
emδ − 1
= m δ m + 1 2! δ m 2 + 1 3! δ m 3 + · · ·
= δ + δ
2
2!m +
δ3
• lim
m→∞ d
(m)
Varying interest
Let ik denote the rate interest applicable for period k. We consider first the present value of an n-period
annuity-immediate.
an| = (1 + i1)−1 + (1 + i1)−1(1 + i2)−1 + · · · + (1 + i1)−1(1 + i2)−1 · · · (1 + in)−1
=
n
X
t=1
t
Π
s=1
(1 + is)−1
The second pattern would be to compute present values using rate ik for the payment made at time k over all k
periods. In this case the present value becomes
an| = (1 + i1)−1 + (1 + i2)−2 + · · · + (1 + in)−n
=
n
X
t=1
(1 + it)−t
Similarily, ¨
sn| = (1 + in) + (1 + in)(1 + in−1) + · · ·
+ (1 + in)(1 + in−1) · · · (1 + i1) =
n
X
t=1
t
Π
s=1
Alternately, if the payment made at time k earns at rate ik over the rest of the accumulation period, we have
¨
sn| = (1 + in) + (1 + in−1)2 + · · · + (1 + i1)n
=
n
X
t=1
Linear interpolation of
(1 +
i)
n+k, v
n+k(1 + i)n+k = (1. − k)(1 + i)n + k(1 + i)n+1 = (1 + i)n[(1 − k) + k(1 + i)] = (1 + i)n(1 + ki)
Similarily,
vn+k = (1 − d)n+k = (1. − k)(1 − d)n + k(1 − d)n+1 = (1 − d)n[(1 − k) + k(1 − d)] = vn(1 − kd)
Method of equated time
Let amounts s1, s2, · · · , sn be paid at times t1, t2, · · · , tn respectively. The problem is to find t, such that
s1 + s2 + · · · + sn paid at time t is equivalent to the payments. of s1, s2, · · · , sn made separately.
(s1 + s2 + · · · + sn)vt = s1vt1 + s
2vt2 + · · · + snvtn
As a first approximation, t is calculated as a weighted average of the various times of payment, where the
weights are the various amounts paid, i.e.
¯
t = s1t1 + s2t2 + · · · + sntn s1 + s2 + · · · + sn =
n
X
k=1
sktk
n
X
k=1
sk
This approximation is denoted by t¯ and is often called using the method of equated time.
Consider s1 quantities each equal to vt1, s
2 quantities
each equal to vt2, and so forth until there are s
quantities each equal to vtn. The arithmetic mean of
these quantities is
s1vt1 + s
2vt2 + · · · + snvtn
s1 + s2 + · · · + sn
The geometric mean of these quantities is v
s1t1+s2t2+···+sntn
s1+s2+···+sn = v¯t
And,
s1vt1 + s
2vt2 + · · · + snvtn
s1 + s2 + · · · + sn > v
¯
=⇒ s1vt1 + s
2vt2 + · · · + snvtn > (s1 + s2 + · · · + sn)v
¯
t
This means that the value of t¯ is always greater than the true value of t.
Basic annuities
• annuity-immediatean| = v + v2 + · · · + vn−1 + vn = v1 − v
n
1 − v = v1 − v
n
iv = 1 − v
i
= (1 + i)
n − 1
(1 + i) − 1 = (1 + i)
n − 1
i ? 1 = ian| + vn
? sn| = an|(1 + i)n
? 1
an| = 1
sn| + i
1
sn| + i =
i
= i + i(1 + i)
n − i
(1 + i)n − 1
= i
1 − vn
= 1
an|
• annuity-due ¨
an| = 1 + v + v2 + · · · + vn−1 = 1 − v
n
= 1 − v
n
iv = 1 − v
n
d
¨
sn| = (1 + i) + (1 + i)2 + · · · + (1 + i)n
= (1 + i)(1 + i)
n − 1
(1 + i) − 1 = (1 + i)
n − 1
= (1 + i)
n − 1
d
? s¨n| = ¨an|(1 + i)n
? 1
¨
an| = 1 ¨
sn| + d ? ¨an| = an|(1 + i) ? s¨n| = sn|(1 + i) ? ¨an| = 1 + an−1| ? s¨n| = sn+1| − 1
• Perpetuities
a∞| = v + v2 + v3 + · · ·
= v
1 − v
= v
iv
= 1
i Alternatively, we have
a∞| = lim
n→∞an| = limn→∞
1 − vn
i =
1 i .
For a perpetuity-due, we have ¨
a∞| = 1 d.
Nonstandard terms
a
n+k|,
0
< k <
1
an+k| = 1 − v
n+k
i = 1 − v
n + vn − vn+k
i = an| + vn+k
(1 + i)k − 1 i
Yiele rate
Consider a situation in which an investor makes deposits or contributions into an investment of C0, C1, · · · , Cn at times 0, 1, 2, · · · , n. Thus, we can denote the returns as R0, R1, · · · , Rn at times 0, 1, · · · , n. Then we have
Rt = −Ct for t = 0, 1, · · · , n.
Assume that the rate of interest per period is i. Then the net present value at rate i of investment returns by the discounted cash flow technique is denoted be P (i) and is
given by
P (i) =
n
X
t=0
vtRt.
An important special case of this formula is the one in which P (i) = 0,
P (i) =
n
X
t=0
vtRt = 0.
The rate of interest i which satisfies P (i) = 0 is called the yield rate on the investment. Stated in words:
The yield rate is that rate of interest at which the
present value of returns from the investment is equal to the present value of contributions into the investment. It is often called the internal rate of return.
Dollar-weighted rate of interest
Consider finding the effective rate of interest earned by a fund over one measurement period. We make the
following definitions:
• A = the amount in the fund at the beginning of the period
• B = the amount in the fund at the end of the period
• Ct = the net amount of principal contributed at time t (positive or negative), where 0 ≤ t ≤ 1
• C = the total net amount of principal contributed during the period
C = X
t
Ct
• aib = the amount of interest earned by 1 invested at time b over the following period of length a, where a ≥ 0, b ≥ 0, and a + b ≤ 1
Note that
B = A + C + I
I = iA + X
t
Ct · 1−tit.
Assuming compound interest throughout the period, we have
1−tit = (1 + i)1−t − 1
.
Hence,
i =. I
A + X
t
Ct(1 − t) .
Assume that the net principal contributions occur at time t = 1
2, we have i =. I
A + .5C =
I
A + .5(B − A − I) =
2I
A + B − I If it is known that net principal contributions occur at
time k on the average, then
i =. I
Time-weighted rate of interest
Let the amount of the net contribution to the
fund(Positive or negative) at time tk be denoted by Ck0 for k = 1, 2, · · · , m − 1.
Let the fund values immediately before each contribution to the fund be denoted by Bk0 for k = 1, 2, · · · , m − 1.
Also the fund value at the beginning of the year is
denoted by B00 = B0, while the fund value at the end of year is denoted by Bm0 = B1.
time-weighted method are given by
1 + jk = B
0 k
Bk−0 1 + Ck−0 1
The overall yield rate for the entire year is then given by 1 + i = (1 + j1)(1 + j2) · · · (1 + jm)
Finding the outstanding loan balance
• L = B0: The original loan balance.
• Bt: The outstanding loan balance at time t.
• The methods of finding the outstanding loan balance Consider a loan of L = an| at interest rate i per period being repaid with payments of 1 a the end of each period for n period.
1. Prospective method
Btp = an−t|
2. Retrospective method
Amortization schedules
L = B0 = an|
I1 = ian| = 1 − vn
P1 = 1 − (1 − vn) = vn B1 = an| − vn = an−1|
I2 = ian−1| = 1 − vn−1
P2 = 1 − (1 − vn−1) = vn−1 B2 = an−1| − vn−1 = an−2|
...
It = iBt−1 = ian−t+1| = 1 − vn−t+1 Pt = 1 − (1 − vn−t+1) = vn−t+1
Payment Interest Principal Outstanding
Period amount paid repaid loan balance
0 an|
1 1 1 − vn vn an−1|
2 1 1 − vn−1 vn−1 an−2|
... ... ... ... ...
t 1 1 − vn−t+1 vn−t+1 an−t|
... ... ... ... ...
n − 1 1 1 − v2 v2 a1|
n 1 1 − v v a1| − v = 0