• No results found

Nominal rates of interest and discount

N/A
N/A
Protected

Academic year: 2021

Share "Nominal rates of interest and discount"

Copied!
43
0
0

Loading.... (view fulltext now)

Full text

(1)

Nominal rates of interest and discount

• i(m): The nominal rate of interest payable m times per period, where m is a positive integer > 1. By a nominal rate of interest i(m), we mean a rate payable mthly, i.e. the rate of interest is i(m)/m for each mth of a period and not i(m). Thus,

1 + i =

1 + i

(m)

m

(2)

and

i =

1 + i

(m)

m

m

− 1 i(m) = m[(1 + i)m1 − 1]

• d(m): The nominal rate of discount payable m times per period. Thus,

1 − d =

1 − d

(m)

m

(3)

and

d = 1 −

1 − d

(m)

m

m

d(m) = m[1 − (1 − d)m1 ] = m[1 − vm1 ]

Generally,

1 + i

(m)

m

m

=

1 − d

(p)

p

(4)

If m = p,

1 + i

(m)

m

=

1 − d

(m)

m

−1

=⇒ i

(m)

m −

d(m)

m =

i(m) m ·

d(m) m .

(5)

Force of interest and discount

• δt: the force of interest at time t, is defined as

δt = a

0(t)

a(t) =

A0(t) A(t)

= d

dt ln A(t) = d

dt ln a(t) Thus,

Z t

0

δrdr =

Z t

0

d

dr ln A(r)dr = ln A(r)|

t

0 = ln

A(t) A(0)

(6)

Hence,

eR0t δrdr = A(t)

A(0) =

a(t)

a(0) = a(t) Note that

Z n

0

A(t)δt =

Z n

0

A0(t)dt = A(n) − A(0).

If δt = δ, 0 ≤ t ≤ n, then

(7)

so that

eδ = 1 + i =⇒ i = eδ − 1 =⇒ δ = ln(1 + i)

• δt0: the force of discount at time t, is defined by

δt0 = −

d dta

−1(t)

a−1(t) .

δt0 = −

d dta

−1(t)

(8)

= a

−2(t) d

dta(t)

a−1(t)

= a

−2(t)a(t)δ

t

a−1(t) = δt

(9)

Some properties of force of interest

• For simple interest

δt =

d

dta(t)

a(t)

=

d

dt(1 + it)

1 + it

= i

(10)

• For simple discount

δt = δt0 = −

d dta

−1(t)

a−1(t)

= −

d

dt(1 − dt)

1 − dt

= d

1 − dt for 0 ≤ t < 1 d.

• i > δ

i = eδ − 1 = δ + δ

2

2! + δ3

3! + δ4

(11)

• lim

m→∞ i

(m)

= δ

1 + i

(m)

m

m

= eδ

i(m) = m

emδ − 1

= m δ m + 1 2! δ m 2 + 1 3! δ m 3 + · · ·

= δ + δ

2

2!m +

δ3

(12)

• lim

m→∞ d

(m)

(13)

Varying interest

Let ik denote the rate interest applicable for period k. We consider first the present value of an n-period

annuity-immediate.

an| = (1 + i1)−1 + (1 + i1)−1(1 + i2)−1 + · · · + (1 + i1)−1(1 + i2)−1 · · · (1 + in)−1

=

n

X

t=1

t

Π

s=1

(1 + is)−1

The second pattern would be to compute present values using rate ik for the payment made at time k over all k

(14)

periods. In this case the present value becomes

an| = (1 + i1)−1 + (1 + i2)−2 + · · · + (1 + in)−n

=

n

X

t=1

(1 + it)−t

Similarily, ¨

sn| = (1 + in) + (1 + in)(1 + in−1) + · · ·

+ (1 + in)(1 + in−1) · · · (1 + i1) =

n

X

t=1

t

Π

s=1

(15)

Alternately, if the payment made at time k earns at rate ik over the rest of the accumulation period, we have

¨

sn| = (1 + in) + (1 + in−1)2 + · · · + (1 + i1)n

=

n

X

t=1

(16)

Linear interpolation of

(1 +

i)

n+k

, v

n+k

(1 + i)n+k = (1. − k)(1 + i)n + k(1 + i)n+1 = (1 + i)n[(1 − k) + k(1 + i)] = (1 + i)n(1 + ki)

Similarily,

vn+k = (1 − d)n+k = (1. − k)(1 − d)n + k(1 − d)n+1 = (1 − d)n[(1 − k) + k(1 − d)] = vn(1 − kd)

(17)

Method of equated time

Let amounts s1, s2, · · · , sn be paid at times t1, t2, · · · , tn respectively. The problem is to find t, such that

s1 + s2 + · · · + sn paid at time t is equivalent to the payments. of s1, s2, · · · , sn made separately.

(s1 + s2 + · · · + sn)vt = s1vt1 + s

2vt2 + · · · + snvtn

As a first approximation, t is calculated as a weighted average of the various times of payment, where the

(18)

weights are the various amounts paid, i.e.

¯

t = s1t1 + s2t2 + · · · + sntn s1 + s2 + · · · + sn =

n

X

k=1

sktk

n

X

k=1

sk

This approximation is denoted by t¯ and is often called using the method of equated time.

Consider s1 quantities each equal to vt1, s

2 quantities

each equal to vt2, and so forth until there are s

(19)

quantities each equal to vtn. The arithmetic mean of

these quantities is

s1vt1 + s

2vt2 + · · · + snvtn

s1 + s2 + · · · + sn

The geometric mean of these quantities is v

s1t1+s2t2+···+sntn

s1+s2+···+sn = v¯t

And,

s1vt1 + s

2vt2 + · · · + snvtn

s1 + s2 + · · · + sn > v

¯

(20)

=⇒ s1vt1 + s

2vt2 + · · · + snvtn > (s1 + s2 + · · · + sn)v

¯

t

This means that the value of t¯ is always greater than the true value of t.

(21)

Basic annuities

• annuity-immediate

an| = v + v2 + · · · + vn−1 + vn = v1 − v

n

1 − v = v1 − v

n

iv = 1 − v

i

(22)

= (1 + i)

n 1

(1 + i) − 1 = (1 + i)

n 1

i ? 1 = ian| + vn

? sn| = an|(1 + i)n

? 1

an| = 1

sn| + i

1

sn| + i =

i

(23)

= i + i(1 + i)

n i

(1 + i)n − 1

= i

1 − vn

= 1

an|

• annuity-due ¨

an| = 1 + v + v2 + · · · + vn−1 = 1 − v

n

(24)

= 1 − v

n

iv = 1 − v

n

d

¨

sn| = (1 + i) + (1 + i)2 + · · · + (1 + i)n

= (1 + i)(1 + i)

n 1

(1 + i) − 1 = (1 + i)

n 1

(25)

= (1 + i)

n 1

d

? s¨n| = ¨an|(1 + i)n

? 1

¨

an| = 1 ¨

sn| + d ? ¨an| = an|(1 + i) ? s¨n| = sn|(1 + i) ? ¨an| = 1 + an−1| ? s¨n| = sn+1| − 1

(26)

• Perpetuities

a∞| = v + v2 + v3 + · · ·

= v

1 − v

= v

iv

= 1

i Alternatively, we have

a∞| = lim

n→∞an| = limn→∞

1 − vn

i =

1 i .

(27)

For a perpetuity-due, we have ¨

a∞| = 1 d.

(28)

Nonstandard terms

a

n+k|

,

0

< k <

1

an+k| = 1 − v

n+k

i = 1 − v

n + vn vn+k

i = an| + vn+k

(1 + i)k − 1 i

(29)

Yiele rate

Consider a situation in which an investor makes deposits or contributions into an investment of C0, C1, · · · , Cn at times 0, 1, 2, · · · , n. Thus, we can denote the returns as R0, R1, · · · , Rn at times 0, 1, · · · , n. Then we have

Rt = −Ct for t = 0, 1, · · · , n.

Assume that the rate of interest per period is i. Then the net present value at rate i of investment returns by the discounted cash flow technique is denoted be P (i) and is

(30)

given by

P (i) =

n

X

t=0

vtRt.

An important special case of this formula is the one in which P (i) = 0,

P (i) =

n

X

t=0

vtRt = 0.

The rate of interest i which satisfies P (i) = 0 is called the yield rate on the investment. Stated in words:

(31)

The yield rate is that rate of interest at which the

present value of returns from the investment is equal to the present value of contributions into the investment. It is often called the internal rate of return.

(32)

Dollar-weighted rate of interest

Consider finding the effective rate of interest earned by a fund over one measurement period. We make the

following definitions:

• A = the amount in the fund at the beginning of the period

• B = the amount in the fund at the end of the period

(33)

• Ct = the net amount of principal contributed at time t (positive or negative), where 0 ≤ t ≤ 1

• C = the total net amount of principal contributed during the period

C = X

t

Ct

aib = the amount of interest earned by 1 invested at time b over the following period of length a, where a ≥ 0, b ≥ 0, and a + b ≤ 1

(34)

Note that

B = A + C + I

I = iA + X

t

Ct · 1−tit.

Assuming compound interest throughout the period, we have

1−tit = (1 + i)1−t − 1

.

(35)

Hence,

i =. I

A + X

t

Ct(1 − t) .

Assume that the net principal contributions occur at time t = 1

2, we have i =. I

A + .5C =

I

A + .5(B − A − I) =

2I

A + B − I If it is known that net principal contributions occur at

(36)

time k on the average, then

i =. I

(37)

Time-weighted rate of interest

Let the amount of the net contribution to the

fund(Positive or negative) at time tk be denoted by Ck0 for k = 1, 2, · · · , m − 1.

Let the fund values immediately before each contribution to the fund be denoted by Bk0 for k = 1, 2, · · · , m − 1.

Also the fund value at the beginning of the year is

denoted by B00 = B0, while the fund value at the end of year is denoted by Bm0 = B1.

(38)

time-weighted method are given by

1 + jk = B

0 k

Bk−0 1 + Ck−0 1

The overall yield rate for the entire year is then given by 1 + i = (1 + j1)(1 + j2) · · · (1 + jm)

(39)

Finding the outstanding loan balance

• L = B0: The original loan balance.

• Bt: The outstanding loan balance at time t.

• The methods of finding the outstanding loan balance Consider a loan of L = an| at interest rate i per period being repaid with payments of 1 a the end of each period for n period.

(40)

1. Prospective method

Btp = an−t|

2. Retrospective method

(41)

Amortization schedules

L = B0 = an|

I1 = ian| = 1 − vn

P1 = 1 − (1 − vn) = vn B1 = an| − vn = an−1|

I2 = ian−1| = 1 − vn−1

P2 = 1 − (1 − vn−1) = vn−1 B2 = an−1| − vn−1 = an−2|

(42)

...

It = iBt−1 = ian−t+1| = 1 − vn−t+1 Pt = 1 − (1 − vn−t+1) = vn−t+1

(43)

Payment Interest Principal Outstanding

Period amount paid repaid loan balance

0 an|

1 1 1 − vn vn an−1|

2 1 1 − vn−1 vn−1 an−2|

... ... ... ... ...

t 1 1 − vn−t+1 vn−t+1 an−t|

... ... ... ... ...

n − 1 1 1 − v2 v2 a1|

n 1 1 − v v a1| − v = 0

References

Related documents

 Partner the designated compliance subject matter experts with line of business specialists to guide the targeted and tailored training, using as a foundation the existing or

Cofely delivers both energy and facilities services at the Queen Elizabeth Olympic Park, as well as providing low carbon energy to the surrounding areas.. The Queen Elizabeth

INSIGHT-E (2015) [8] defines an evaluation framework to compare the situation across different Member States dividing the policies implementation process in three

Haplotype capture at three sets of target genes using genomewide single nucleotide polymorphism (SNP), geographic, and environmental data to assemble subsets in sorghum.. Target

To identify barley calcium protein kinases (CPKs) involved in the drought stress response, total protein was isolated from drought-stressed barley plants using protein isolation

neuroscience research that can provide insights for the ethical leader as a moral person and moral manager: self-reflection, self-regulation, theory of mind and empathy, trust

UNIT I  Introduction to Marketing: Meaning, nature and scope of marketing; Marketing philosophies; Marketing management process; Concept of marketing mix.. UNIT II  Market

People still seek out the physical library buildings for information, leisure, and social interaction, providing evidence for the importance of libraries for social capital