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Volume 2009, Article ID 273063,18pages doi:10.1155/2009/273063

Research Article

Positive Solutions for a Class of Coupled System of

Singular Three-Point Boundary Value Problems

Naseer Ahmad Asif and Rahmat Ali Khan

Centre for Advanced Mathematics and Physics, Campus of College of Electrical and Mechanical

Engineering, National University of Sciences and Technology, Peshawar Road, Rawalpindi 46000, Pakistan

Correspondence should be addressed to Rahmat Ali Khan,rahmat [email protected] Received 27 February 2009; Accepted 15 May 2009

Recommended by Juan J. Nieto

Existence of positive solutions for a coupled system of nonlinear three-point boundary value problems of the type−xt ft, xt, yt, t ∈ 0,1, −yt gt, xt, yt, t ∈ 0,1,

x0 y0 0,x1 αxη,y1 αyη, is established. The nonlinearitiesf,g : 0,

0,∞×0,∞ → 0,∞are continuous and may be singular att0, t1, x0, and/ory0, while the parametersη,αsatisfyη∈0,1,0< α <1. An example is also included to show the applicability of our result.

Copyrightq2009 N. A. Asif and R. A. Khan. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.

1. Introduction

Multipoint boundary value problemsBVPsarise in different areas of applied mathematics and physics. For example, the vibration of a guy wire composed ofNparts with a uniform cross-section and different densities in different parts can be modeled as a Multipoint boundary value problem 1. Many problems in the theory of elastic stability can also be modeled as Multipoint boundary value problem2.

The study of Multipoint boundary value problems for linear second order ordinary differential equations was initiated by Il’in and Moiseev, 3, 4, and extended to nonlocal linear elliptic boundary value problems by Bitsadze et al.5,6. Existence theory for nonlinear three-point boundary value problems was initiated by Gupta7. Since then the study of nonlinear three-point BVPs has attracted much attention of many researchers, see8–11and references therein for boundary value problems with ordinary differential equations and also

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The study of system of BVPs has also fascinated many authors. System of BVPs with continuous nonlinearity can be seen in20–22and the case of singular nonlinearity can be seen in 8,21, 23–26. Wei 25, developed the upper and lower solutions method for the existence of positive solutions of the following coupled system of BVPs:

xt ft, xt, yt, t∈0,1,

yt gt, xt, yt, t∈0,1,

x0 0, x1 0,

y0 0, y1 0,

1.1

wheref, gC0,1×0,∞×0,,0,∞, and may be singular att0,t1,x0 and/or

y0.

By using fixed point theorem in cone, Yuan et al.26studied the following coupled system of nonlinear singular boundary value problem:

x4t ft, xt, yt, t∈0,1,

yt gt, xt, yt, t∈0,1,

x0 x1 x0 x1 0,

y0 y1 0,

1.2

f, gare allowed to be superlinear and are singular att0 and/ort1. Similarly, results are studied in8,21,23.

In this paper, we generalize the results studied in25,26to the following more general singular system for three-point nonlocal BVPs:

xt ft, xt, yt, t∈0,1,

yt gt, xt, yt, t∈0,1,

x0 0, x1 αxη,

y0 0, y1 αyη,

1.3

whereη∈0,1, 0< α <1,f, gC0,1×0,∞×0,,0,∞. We allowfandgto be singular att 0,t 1, and alsox 0 and/ory 0. We study the sufficient conditions for existence of positive solution for the singular system1.3under weaker hypothesis onfand

gas compared to the previously studied results. We do not require the system1.3to have lower and upper solutions. Moreover, the cone we consider is more general than the cones considered in20,21,26.

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studied in21,24–26. Throughout this paper, we assume thatf, g:0,1×0,∞×0,∞ →

0,∞are continuous and may be singular att0,t1,x0, and/ory0. We also assume that the following conditions hold:

A1f·,1,1, g·,1,1∈C0,1,0,∞and satisfy

a: 1

0

t1−tft,1,1dt <, b: 1

0

t1−tgt,1,1dt <. 1.4

A2There exist real constantsαi, βisuch thatαi≤0≤βi <1,i1,2,β1 β2<1 and for allt∈0,1,x, y∈0,∞,

1ft, x, yft, cx, ycα1ft, x, y, if 0< c1,

1ft, x, yft, cx, ycβ1ft, x, y, if c1,

2ft, x, yft, x, cycα2ft, x, y, if 0< c1,

2ft, x, yft, x, cycβ2ft, x, y, ifc1.

1.5

A3There exist real constantsγi, ρisuch thatγi≤0≤ρi<1,i1,2,ρ1 ρ2<1 and for allt∈0,1,x, y∈0,∞,

1gt, x, ygt, cx, ycγ1gt, x, y, if 0< c1,

1gt, x, ygt, cx, ycρ1gt, x, y, if c1,

2gt, x, ygt, x, cycγ2gt, x, y, if 0< c1,

2gt, x, ygt, x, cycρ2gt, x, y, ifc1,

1.6

for example, a function that satisfies the assumptionsA2andA3is

ht, x, y

m

i1 n

j1

pijtxriysj, 1.7

wherepijC0,1,0,∞,ri, sj<1,i1,2, . . . , m;j1,2, . . . , nsuch that

max

1≤i≤mri max1≤j≤nsj<1. 1.8

The main result of this paper is as follows.

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2. Preliminaries

For eachuE:C0,1, we writeumax{ut:t∈0,1}. LetP {uE:ut≥0, t

0,1}. Clearly,E, · is a Banach space andP is a cone. Similarly, for eachx, yE×E, we writex, y1x y. Clearly,E×E, · 1is a Banach space andP×Pis a cone in

E×E. For any real constantr >0, defineΩr {x, yE×E:x, y1 < r}. By a positive solution of1.3, we mean a vectorx, yC0,1∩C20,1×C0,1C20,1such thatx, y satisfies1.3andx >0,y >0 on0,1. The proofs of our main resultTheorem 1.1is based on the Guo’s fixed-point theorem.

Lemma 2.1Guo’s Fixed-Point Theorem27. LetKbe a cone of a real Banach spaceE,Ω1,Ω2

be bounded open subsets ofEandθ∈Ω1 ⊂Ω2. Suppose thatT :K∩Ω2\Ω1 → Kis completely

continuous such that one of the following condition hold:

iTxxforxΩ1∩KandTxxforxΩ2∩K;

iiTxxforxΩ2∩KandTxxforxΩ1∩K.

Then,T has a fixed point inK∩Ω2\Ω1.

The following result can be easily verified.

Result 1. Lett1, t2 ∈Rsuch thatt1 < t2. LetxCt1, t2,x≥0 and concave ont1, t2. Then,

xt≥min{tt1, t2−t}maxs∈t1,t2xsfor alltt1, t2.

Choosen0∈ {3,4,5, . . .}such thatn0>max{1/η,1/1−η,2−α/1−αη}. For fixed

n∈ {n0, n0 1, n0 2, . . .}andzC0,1, the linear three-point BVP

ut zt, t

1

n,1−

1

n

,

u

1

n 0, u

1− 1

n αu

η,

2.1

has a unique solution

ut

11/n

1/n

Hnt, szsds, 2.2

whereHn :1/n,1−1/n×1/n,1−1/n → 0,∞is the Green’s function and is given by

Hnt, s

⎧ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎨ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎩

t−1/n 1−1/ns

1− 2/n α/nαη

αt−1/nηs

1− 2/n α/nαηts,

1

nst≤1−

1

n, sη,

t−1/n 1− 1/ns

1−2/n α/nαη

αt−1/nηs

1− 2/n α/nαη,

1

nts≤1−

1

n, sη,

t−1/n 1− 1/ns

1− 2/n α/nαη ,

1

nts≤1−

1

n, sη,

t−1/n 1− 1/ns

1− 2/n α/nαηts,

1

nst≤1−

1

n, sη.

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We note thatHnt, sHt, sasn → ∞, where

Ht, s

⎧ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎨ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎩

t1−s

1−αη

αtηs

1−αηts, 0≤st≤1, sη, t1−s

1−αη

αtηs

1−αη , 0≤ts≤1, sη, t1−s

1−αη , 0≤ts≤1, sη,

t1−s

1−αηts, 0≤st≤1, sη,

2.4

is the Green’s function corresponding the boundary value problem

ut zt, t∈0,1,

u0 0, u1 αuη 2.5

whose integral representation is given by

ut

1

0

Ht, szsds. 2.6

Lemma 2.2see9. Let0< α <1/η. IfzC0,1andz≥0, then then unique solutionuof the problem2.5satisfies

min

t∈η,1utγu, 2.7

whereγmin{αη, α1−η/1−αη, η}.

We need the following properties of the Green’s functionHnin the sequel.

Lemma 2.3see11. The functionHncan be written as

Hnt, s Gnt, s

αt−1/n

1− 2/n α/nαηGn

η, s, 2.8

where

Gnt, s

n n−2

⎧ ⎪ ⎪ ⎪ ⎨ ⎪ ⎪ ⎪ ⎩

s− 1 n

1− 1

nt ,

1

nst≤1−

1

n,

t− 1 n

1−1

ns ,

1

nts≤1−

1

n.

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Following the idea in10, we calculate upper bound for the Green’s functionHn in

the following lemma.

Lemma 2.4. The functionHnsatisfies

Hnt, sμn

s− 1 n

1− 1

ns , t, s

1

n,1−

1

n

×

1

n,1−

1

n

, 2.10

whereμnmax{1, α}/1−2/n α/nαη.

Proof. Fort, s∈1/n,1−1/n×1/n,1−1/n, we discuss various cases.

Case 1. sη,st; using2.3, we obtain

Hnt, s s− 1

n α−1

t−1/n s−1/n

1−2/n α/nαη. 2.11

Ifα >1, the maximum occurs att1−1/n, hence

Hnt, sHn

1− 1

n, s α

s−1/n1−1/nη

1−2/n α/nαη

αs−1/n 1−1/ns

1−2/n α/nαημn

s− 1 n

1− 1

ns ,

2.12

and ifα≤1, the maximum occurs atts, hence

Hnt, sHns, s

s−1/n1−1/ns αsη

1−2/n α/nαη

s−1/n 1−1/ns

1−2/n α/nαημn

s− 1 n

1− 1

ns .

2.13

Case 2. sη,st; using2.3, we have

Hnt, s

t−1/n 1−1/ns

1−2/n α/nαηα

t−1/nηs

1−2/n α/nαη

t−1/n 1−1/ns

1−2/n α/nαη

s−1/n 1−1/ns

1−2/n α/nαημn

s−1 n

1− 1

ns .

2.14

Case 3. sη,ts; using2.3, we have

Hnt, s t−1/n 1−1/ns

1−2/n α/nαη

s−1/n 1−1/ns

1−2/n α/nαημn

s− 1 n

1− 1

ns .

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Case 4. sη,ts; using2.3, we have

Hnt, s s− 1

n

t− 1 n

αη−1/ns−1/n

1−2/n α/nαη . 2.16

Forαη−1/n> s−1/n, the maximum occurs att1−1/n, hence

Hnt, sHn

1− 1

n, s α

η−1/n1−1/ns

1−2/n α/nαηα

s−1/n 1−1/ns

1−2/n α/nαη

μn

s− 1 n

1− 1

ns .

2.17

Forαη−1/ns−1/n, the maximum occurs atts, so

Hnt, sHns, s

s−1/n 1−1/ns

1−2/n α/nαημn

s− 1 n

1− 1

ns . 2.18

Now, we consider the nonlinear nonsingular system of BVPs

xt f

t,max

xt 1 n, 1 n ,max

yt 1 n,

1

n , t

1

n,1−

1

n

,

yt g

t,max

xt 1 n, 1 n ,max

yt 1 n,

1

n , t

1

n,1−

1 n , x 1

n 0, x

1− 1

n αx

η,

y

1

n 0, y

1− 1

n αy

η.

2.19

We write2.19as an equivalent system of integral equations

xt

11/n

1/n

Hnt, sf

s,max

xs 1 n, 1 n ,max

ys 1 n,

1

n ds,

yt

1−1/n

1/n

Hnt, sg

s,max

xs 1 n, 1 n ,max

ys 1 n,

1

n ds.

2.20

By a solution of the system2.19, we mean a solution of the corresponding system of integral equations2.20. Define a retractionσn:0,1 → 1/n,1−1/nbyσnt max{1/n,min{t,1−

1/n}}and an operatorTn:E×EP×Pby

Tn

x, yAn

x, y, Bn

x, y, 2.21

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An

x, yt

11/n

1/n

Hnσnt, sf

s,max

xs 1 n, 1 n ,max

ys 1 n,

1

n ds,

Bn

x, yt

1−1/n

1/n

Hnσnt, sg

s,max

xs 1 n, 1 n ,max

ys 1 n,

1

n ds.

2.22

Clearly, ifxn, ynE×Eis a fixed point ofTn, thenxn, ynis a solution of the system2.19.

Lemma 2.5. Assume thatA1–A3holds. ThenTn:P×PP×Pis completely continuous.

Proof. Clearly, for anyx, yP×P,Anx, y, Bnx, yP. We show that the operatorAn :

P×PPis uniformly bounded. Letd >0 be fixed and consider

Dx, yP×P :x, y1d. 2.23

Choose a constantc ∈ 0,1such thatcx 1/3 ≤ 1,cy 1/3≤ 1,x, yD. Then, for everyx, yD, using2.22,Lemma 2.4,A1andA2, we have

An

x, yt

11/n

1/n

Hnσnt, sf

s, xs 1

n, ys

1

n ds

11/n

1/n

Hnσnt, sf

s, cxs 1/n c , c

ys 1/n c ds

1

c

β11−1/n

1/n

Hnσnt, sf

s, c

xs 1 n , c

ys 1/n c ds

1

c

β11

c

β21−1/n

1/n

Hnσnt, sf

s, c

xs 1 n , c

ys 1 n

ds

1−β1−β2

11/n

1/n

Hnσnt, s

xs 1 n

α1

f

s,1, c

ys 1 n

ds

1−β1 α2−β2

1−1/n

1/n

Hnσnt, s

xs 1 n

α1

ys 1 n

α2

fs,1,1ds

1−β1 α2−β2

1−1/n

1/n

Hnσnt, s

1

n

α11

n

α2

fs,1,1ds

μncα1−β1 α2−β2n−α1−α2

1−1/n

1/n

s− 1 n

1− 1

ns fs,1,1ds

μncα1−β1 α2−β2n−α1−α2

1−1/n

1/n

s1−sfs,1,1ds

μncα1−β1 α2−β2n−α1−α2

1

0

s1−sfs,1,1dsaμncα1−β1 α2−β2n−α1−α2,

(9)

which implies that

An

x, yaμncα1−β1 α2−β2n−α1−α2, 2.25

that is,AnDis uniformly bounded. Similarly, using2.22,Lemma 2.4,A1andA3, we can show thatBnDis also uniformly bounded. Thus,TnDis uniformly bounded. Now we

show thatAnDis equicontinuous. Define

ωmax

max

t,x,y∈1/n,1−1/n×0,d×0,df

t, x 1 n, y

1

n ,

max

t,x,y∈1/n,1−1/n×0,d×0,dg

t, x 1 n, y

1

n .

2.26

Lett1, t2 ∈0,1such thatt1 ≤ t2. SinceHnt, sis uniformly continuous on1/n,1−1/n×

1/n,1−1/n, for anyε >0, there existδδε>0 such that|t1−t2|< δimplies

|Hnσnt1, sHnσnt2, s|< ε

ω1−2/n fors

1

n,1−

1

n

. 2.27

Forx, yD, using2.22–2.27, we have

An

x, yt1−An

x, yt2

11/n

1/n

Hnσnt1, sHnσnt2, sf

s, xs 1

n, ys

1

n

ds

1−1/n

1/n

|Hnσnt1, sHnσnt2, s|f

s, xs 1

n, ys

1

n ds

ω

11/n

1/n

|Hnσnt1, sHnσnt2, s|ds

< ω ε ω1−2/n

11/n

1/n

ds ε

1−2/n

1− 2

n ε.

2.28

Hence,

An

x, yt1−An

x, yt2< ε,

x, yD, |t1−t2|< δ, 2.29

which implies that AnD is equicontinuous. Similarly, using 2.22–2.27, we can show

thatBnDis also equicontinuous. Thus,TnDis equicontinuous. By Arzel`a-Ascoli theorem,

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Now we show thatTnis continuous. Letxm, ym,x, yP×P such thatxm, ym

x, y1 → 0 asm → ∞.Then by using2.22andLemma 2.4, we have

An

xm, ym

tAn

x, yt

1−1/n

1/n

Hnσnt, s

f

s, xms

1

n, yms

1

nf

s, xs 1

n, ys

1

n

ds

1−1/n

1/n

Hnσnt, s

f

s, xms 1

n, yms

1

nf

s, xs 1

n, ys

1

n ds

μn

1−1/n

1/n

s−1 n

1−1

ns

f

s, xms 1

n, yms

1

nf

s, xs 1 n, ys

1

n ds.

2.30

Consequently, An

xm, ym

An

x, y

μn

1−1/n

1/n

s−1 n

1− 1

ns

×f

s, xms

1

n, yms

1

nf

s, xs 1

n, ys

1

n ds.

2.31

By Lebesgue dominated convergence theorem, it follows that An

xm, ym

An

x, y−→0 asm−→ ∞. 2.32

Similarly, by using2.22andLemma 2.4, we have Bn

xm, ym

Bn

x, y−→0 asm−→ ∞. 2.33

From2.32and2.33, it follows that

Tnxm, ymTnx, y

1−→0 asm−→ ∞, 2.34

that is,Tn:P×PP×Pis continuous. Hence,Tn:P×PP×Pis completely continuous.

3. Main Results

Proof ofTheorem 1.1. LetM max{μn0,max{1, α}/1−αη}. Choose a constantR > 0 such that

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Choose a constant c1 ∈ 0,1such that c1 xt 1/n0 ≤ 1,c1yt 1/n0 ≤ 1,x, y

ΩRP×P,t∈0,1. For anyx, yΩRP×P, using2.22,3.1,A1, andA2, we have

An

x, yt

11/n

1/n

Hnσnt, sf

s, xs 1

n, ys

1

n ds

11/n

1/n

Hnσnt, sf

s, c1

xs 1/n c1

, c1

ys 1/n c1 ds ≤ 1 c1

β11−1/n

1/n

Hnσnt, sf

s, c1

xs 1 n , c1

ys 1/n c1 ds ≤ 1 c1

β11

c1

β21−1/n

1/n

Hnσnt, sf

s, c1

xs 1 n , c1

ys 1 n

ds

1−β1−β2 1

11/n

1/n

Hnσnt, s

xs 1 n

α1

f

s,1, c1

ys 1 n

ds

1−β1 α2−β2 1

1−1/n

1/n

Hnσnt, s

xs 1 n

α1

ys 1 n

α2

fs,1,1ds

1−β1 α2−β2 1

1−1/n

1/n

Hnσnt, s xsα1

ysα2fs,1,1ds

μncα11−β1 α2−β2

1−1/n

1/n

s−1 n

1− 1

ns xs

α1ysα2fs,1,1ds

μncα11−β1 α2−β2

1−1/n

1/n

s1−s xsα1ysα2

fs,1,1ds

μncα11−β1 α2−β2

1

0

s1−s xsα1ysα2fs,1,1ds

Mcα1−β1 α2−β2 1

1

0

s1−s xsα1ysα2fs,1,1ds.

3.2

Since,

Mcα1−β1 α2−β2 1

1

0

s1−s xsα1ysα2

fs,1,1ds

M

1

0

s1−s xsα1ysα2fs,1,1ds

aMRα1 α2 ≤ R 2,

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it follows that

An

x, yR

2

x, y1

2 ,

x, yΩRP×P. 3.4

Similarly, using2.22,3.1,A1, andA3, we have

Bn

x, yx, y1

2 ,

x, yΩRP×P. 3.5

From3.4, and3.5, it follows that

Tnx, y1x, y1,

x, yΩRP×P. 3.6

Choose a real constantr∈0, Rsuch that

r≤min2aM1/1−β1−β2,2bM1/1−ρ1−ρ2. 3.7

Choose a constantc2 ∈ 0,1 such that c2xt 1/n0 ≤ 1, c2yt 1/n0 ≤ 1, x, y

ΩrP×P,t∈0,1. For anyx, yΩrP×P, using2.22,3.7,A1, andA2, we have

An

x, yt

1−1/n

1/n

Hnσnt, sf

s, xs 1

n, ys

1

n ds

1−1/n

1/n

Hnσnt, sf

s, c2xs 1/n

c2

, c2

ys 1/n c2

ds

1

c2

α11−1/n

1/n

Hnσnt, sf

s, c2

xs 1 n , c2

ys 1/n c2 ds

1

c2

α11

c2

α21−1/n

1/n

Hnσnt, sf

s, c2

xs 1 n , c2

ys 1 n

ds

1−α1−α2 2

11/n

1/n

Hnσnt, s

xs 1 n

β1

f

s,1, c2

ys 1 n

ds

1−α1 β2−α2 2

11/n

1/n

Hnσnt, s

xs 1 n

β1

ys 1 n

β2

fs,1,1ds

1−α1 β2−α2 2

11/n

1/n

Hnσnt, s xsβ1

ysβ2fs,1,1ds r 2.

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We used the fact that

1−α1 β2−α2 2

1−1/n

1/n

Hnσnt, s xsβ1

ysβ2fs,1,1ds

1−1/n

1/n

Hnσnt, s xsβ1

ysβ2

fs,1,1ds

aMrβ1 β2.

3.9

Thus,

An

x, yx, y1

2 ,

x, yΩrP×P. 3.10

Similarly, using2.22,3.7,A1andA3, we have,

Bn

x, yx, y1

2 ,

x, yΩrP×P. 3.11

From3.10and3.11, it follows that

Tnx, y1x, y1,

x, yΩrP×P. 3.12

Hence byLemma 2.1,Tnhas a fixed pointxn, ynP×P∩ΩRr, that is,

xnAn

xn, yn

, ynBn

xn, yn

. 3.13

Moreover, by3.4,3.5,3.10and3.11, we have

r

2 ≤ xn

R

2,

r

2 ≤yn

R

2.

3.14

Sincexn, ynis a solution of the system2.19, hencexnandynare concave on1/n,1−1/n.

Moreover, maxt∈1/n,1−1/nxnt xnand maxt∈1/n,1−1/nynt yn. Forh ∈ 1/n,1/2,

using result2.2and3.14, we have

rh

2 ≤xnt

R

2,th,1−h,

rh

2 ≤ynt

R

2,th,1−h,

(14)

which implies that{xn, yn}is uniformly bounded onh,1−h. Now we show that{xn, yn}

is equicontinuous onh,1−h. Chooseηh,1−hand 0< α <1−2h/ηhand consider the integral equation

xnt

xn1−hα xn

η−1−αxnh

1−2h αhαη th xnh

1−h

h

Hh−1t, sf

s, xns

1

n, yns

1

n ds, th,1−h.

3.16

UsingLemma 2.3, we have

xnt

xn1−hα xn

η−1−αxnh

1−2h αhαη th xnh

1−ht

1−2h

t

h

shf

s, xns 1

n, yns

1

n ds

th

1−2h

1−h

t

1−hsf

s, xns 1

n, yns

1

n ds

αth

1−2h αhαη

1−h

h

Gh−1η, sf

s, xns

1

n, yns

1

n ds, th,1−h.

3.17

Differentiating with respect tot, we obtain

xnt xn1−hα xn

η−1−αxnh

1−2h αhαη

− 1

1−2h

t

h

shf

s, xns 1

n, yns

1

n ds

1 1−2h

1−h

t

1−hsf

s, xns

1

n, yns

1

n ds

α

1−2h αhαη

1−h

h

Gh−1η, sf

s, xns

1

n, yns

1

n ds, th,1−h,

3.18

which implies that

x nt

1 αR

1−2h αhαη

1−h

h

f

s, xns

1

n, yns

1

n ds

α

1−2h αhαη

1−h

h

Gh−1

η, sf

s, xns 1

n, yns

1

n ds, th,1−h,

(15)

In view ofA2and3.15, we have

xnt≤ 1 αR

1−2h αhαη c

α1−β1 α2−β2 1

hr

2

α1 α21−h

h

fs,1,1ds

α

1−2h αhαηc

α1−β1 α2−β2 1

hr

2

α1 α21−h

h

Gh−1

η, sfs,1,1ds, th,1−h,

3.20

which implies that

xn ≤ 1 αR

1−2h αhαη c

α1−β1 α2−β2 1

hr

2

α1 α21−h

h

fs,1,1ds

α

1−2h αhαηc

α1−β1 α2−β2 1

hr

2

α1 α21−h

h

Gh−1η, sfs,1,1ds, th,1−h.

3.21

Similarly, consider the integral equation

ynt

yn1−hα yn

η−1−αynh

1−2h αhαη th ynh

1−h

h

Hh−1t, sg

s, xns

1

n, yns

1

n ds, th,1−h,

3.22

usingA3and3.15, we can show that

yn ≤ 1 αR

1−2h αhαη c

γ1−ρ1 γ2−ρ2 1

hr

2

γ1 γ21−h

h

gs,1,1ds

α

1−2h αhαηc

γ1−ρ1 γ2−ρ2 1

hr

2

γ1 γ21−h

h

Gh−1η, sgs,1,1ds, th,1−h.

3.23

In view of 3.21 and 3.23,{xn, yn} is equicontinuous on h,1 −h. Hence by

Arzel`a-Ascoli theorem, the sequence{xn, yn}has a subsequence{xnk, ynk}converging uniformly

onh,1−htox, yP×P∩ΩRr. Let us consider the integral equation

xnkt

xnk1−hα xnk

η−1−αxnkh

1−2h αhαη th xnkh

1−h

h

Hh−1t, sf

s, xnks

1

nk

, ynks

1

nk

ds, th,1−h.

(16)

Lettingnk → ∞, we have

xt x1−hα x

η−1−αxh

1−2h αhαη th xh

1−h

h

Hh−1t, sf

s, xs, ysds, th,1−h.

3.25

Differentiating twice with respect tot, we have

xt ft, xt, yt, th,1−h. 3.26

Lettingh → 0, we have

xt ft, xt, yt, t∈0,1. 3.27

Similarly, consider the integral equation

ynkt

ynk1−hα ynk

η−1−αynkh

1−2h αhαη th ynkh

1−h

h

Hh−1t, sg

s, xnks

1

nk

, ynks

1

nk

ds, th,1−h,

3.28

we can show that

yt gt, xt, yt, t∈0,1. 3.29

Now, we show thatx, yalso satisfies the boundary conditions. Since,

x0 lim

nk→ ∞

x

1

nk

lim

nk→ ∞

xnk

1

nk

0,

x1 lim

nk→ ∞

x

1− 1

nk

lim

nk→ ∞

xnk

1− 1

nk

lim

nk→ ∞

αxnk

ηαxη.

3.30

Similarly, we can show that

yt 0, y1 αyη. 3.31

Equations3.27–3.31imply thatx, yis a solution of the system1.3. Moreover,x, yis positive. In fact, by3.27xis concave and byLemma 2.2

x1≥ min

(17)

implies thatxt > 0 for all t ∈ 0,1. Similarly, yt > 0 for all t ∈ 0,1. The proof of Theorem 1.1is complete.

Example 3.1. Let

ft, x, y

m

i1

n

j1

tpi1tqjxriysj,

gt, x, y

m

k1 n

l1

tpk1−tqlxrk ysl,

3.33

where the real constantspi, qj, ri, sj satisfypi, qj > −2,ri, sj < 1, i 1,2, . . . , m;j 1,2, . . . , n,

with max1≤i≤mri max1≤j≤nsj <1 and the real constantspk, ql, rk, slsatisfypk, ql>−2,rk, sl <

1, k 1,2, . . . , m;l1,2, . . . , n,with max1≤k≤mrk max1≤l≤nsl<1. Clearly,fandgsatisfy the

assumptionsA1–A3. Hence, byTheorem 1.1, the system1.3has a positive solution.

Acknowledgement

Research of R. A. Khan is supported by HEC, Pakistan, Project 2- 350/PDFP/HEC/2008/1.

References

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4 V. A. Il’in and E. I. Moiseev, “A nonlocal boundary value problem of the second kind for the Sturm-Liouville operator,”Differential Equations, vol. 23, no. 8, pp. 979–987, 1987.

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9 R. Ma, “Positive solutions of a nonlinear three-point boundary-value problem,”Electronic Journal of Differential Equations, vol. 1999, no. 34, pp. 1–8, 1999.

10 J. R. L. Webb, “Positive solutions of some three point boundary value problems via fixed point index theory,”Nonlinear Analysis: Theory, Methods & Applications, vol. 47, no. 7, pp. 4319–4332, 2001.

11 Z. Zhao, “Solutions and Green’s functions for some linear second-order three-point boundary value problems,”Computers & Mathematics with Applications, vol. 56, no. 1, pp. 104–113, 2008.

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References

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