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• Force: a push or a pull exerted on an object. • Mechanical forces require the objects to be in physical contact. The study of force is often called DYNAMICS.

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• Force: a push or a pull exerted on an object.

• Mechanical forces

require the objects to be in physical contact.

 The study of force is often called DYNAMICS.

(3)

• Friction is an example of a mechanical force.

• Sliding friction always acts in the opposite

direction as the motion of the object.

(4)

• Non-mechanical forces can act at a distance.

• e.g. gravity, electric force, magnetic force.

Force is a vector quantity

Gravitational Force

Electric Force Magnetic

Force

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Force was first mathematically defined by Sir Isaac Newton (1642-1727)

NEWTON’S FIRST LAW

• An object will remain at constant

velocity until an unbalanced force acts upon it.

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Free-body diagrams are used to illustrate the forces acting on an object.

e.g. a 20 000-N stationary rock

Free-body diagram FN

Fg Fg= force of gravity

FN= normal force or “support force”

Fnet = Fg + FN = (-20 000 N) + (+20 000 N) = 0 N

Balanced Forces

No

acceleration

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e.g. A 0.50 N air-hockey puck on a frictionless surface, moving with a constant speed of 15 m/s.

FN

Fg

Fnet = Fg + FN = (-0.50) + (+0.50) = 0 N

Balanced Forces

No

acceleration

(9)

e.g. a girl bikes along at a constant speed of 5.0 m/s.

FN

Fg

FA Ff

Fnet = Ff + FA = 0 N x-direction

Fnet = FN + Fg = 0 N y-direction

Balanced Forces

No

acceleration

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e.g. an accelerating race-car

FN

Fg

FA Ff

Unbalanced Forces

Acceleration

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e.g. a falling car

Ff

Fg

Unbalanced Forces

Acceleration

(12)

e.g. a falling car with open parachute:

Ff

Fg

Balanced Forces

No

acceleration

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a m 1

a F net

a m Fnet

NEWTON’S SECOND LAW

• An unbalanced force acting on an object

causes it to accelerate uniformly.

• The acceleration is proportional to the force

• The acceleration is inversely proportional to the mass (called the LAW OF

INERTIA)

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Let’s test the Newton’s Second Law Fnet = ma, by

analyzing the relationship between force and acceleration

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Conclusions:

a

Fnet

• Fnet and a are directly proportional

• According to Fnet = ma, the slope should be equal to (mass)-1

net net

net

m F a

m a F

ma F

 

 

 

1

Slo

pe

What would the graph for a more massive object look like?

 More massive objects require more force to accelerate. This property of mass is called INERTIA.

Less massive

More massive

 To verify this compare the measured mass to the reciprocal of the slope.

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e.g. a golf ball has little mass and therefore little inertia;

a truck has much mass and therefore much inertia

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NEWTON’S LAW & GRAVITY

• The force of gravity acting on an object is often called weight

Force of gravity or

WEIGHT (N) Mass (kg) Acceleration due to gravity (m/s2)

e.g. Calculate the weight of a 3.0-kg human head on the surface of Planet Earth.

29 N

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Fg =mg explains why all objects fall at the same rate of acceleration if air resistance is negligible.

(21)

… when air resistance is a factor objects fall with varying rates of acceleration.

(22)

Terminal velocity and sky-diving:

(23)

NEWTON’S THIRD LAW

• If OBJECT A exerts a force on OBJECT B, then OBJECT B will exert a force on OBJECT A of equal magnitude and opposite direction.

(24)

Girl exerts force on wall

Wall exerts force on girl

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Air exerts force on balloon Balloon exerts

force on air

(26)

Rocket exerts force

on fuel exhaust

Fuel exhaust exerts force

on rocket

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Ball exerts force on cannon

Cannon exerts force on ball

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Gun exerts force on bullet

Bullet exerts force on gun

(29)

Boy runs and jumps from canoe to dock:

Boy exerts force on canoe

Canoe exerts force on boy

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Skater exerts a force on ice

Ice exerts a force on skater

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• Friction is an example of a mechanical force.

• Friction always acts in a direction opposite to the motion of the object.

(33)

•Friction can be measured by

seeing how much force is needed to slide an object

along at a constant speed

FA Ff

Ff = Fa

• The force of friction

depends on two variables

Normal force – force perpendicular to the surface (i.e. the

support force FN or Fs)

Coefficient of friction between the two

surfaces (μ or “mu”)

Fg

N g

FF FN

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… pronounced “mew”

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N

f F

F  

Force of friction

(N)

Coefficient of friction

(NO UNITS)

Normal force (N)

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For objects on flat surfaces:

mg F

F F F

f

g N f

FN

Fg

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…for flat surfaces

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Example:

1. A rocked is accelerating upward at 20 m/s2 a) How much force would the

thrusters of a 500-kg rocket have to apply to the rocket in order to achieve this?

(Assume no air resistance)

b) How much force would an astronaut’s seat have to apply to her as she

accelerated upward with the rocket?

(mastronaut = 65 kg) Fa

Fg Fa (applied by seat)

Fg

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Does that astronaut feel heavier, lighter or normal as the rocket accelerates upward?

HEAVIER!

Fg FN

• A stopped astronaut: • An astronaut accelerating upward

The force felt by the astronaut

Fg FN

This force would register

on a weight scale!

This force would register

on a weight scale!

e.g. Scale reading = 500 N e.g. Scale reading = 900 N

F

net

(43)

How would the astronaut feel if the rocket was traveling upward at a constant velocity?

F

net

=0

Fg FN

Fg FN NORMAL

e.g. Scale reading = 500 N e.g. Scale reading = 500 N

(44)

How does he feel traveling upward with a downward acceleration?

LIGHTER!

Fg FN

Fg FN

e.g. Scale reading = 500 N e.g. Scale reading = 100 N Fnet

(45)

SUMMARY v-t graph: A trip up and then back down again:

v

+

-

Going up,(+) accel Going up,(0) accel Going up,(-) accel Going down,(-) accel Going down,(0) accel Going down,(+) accel

“Heavy” “Normal” “Light” “Light” “Normal” “Heavy”

t

“Normal”

Stopped,(0) accel

(46)

… now let’s add a d-t graph:

v

+

-

t

t

d

(47)

How does he feel if the downward acceleration is equal to 9.81 m/s2?

Vomit Comet Movie

WEIGHTLESS!

(48)

The same effects happen in elevators…

…as you will observe in the lab.

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Example Problems (Vertical Forces)

1) An astronaut with a mass of 75.0 kg is astonished to find that she weighs 500 N during a trip in her rocket.

Calculate the rocket’s vertical acceleration.

3.14 m/s2 down

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2) Jimmy (mass = 65 kg) is hanging from a newton-metre while riding an elevator. If the elevator is accelerating at 7.0 m/s2, upward, then what would be the reading on the newton- metre?

References

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