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R E S E A R C H

Open Access

On a product-type operator between

Hardy and

α-Bloch spaces of the upper

half-plane

Stevo Stevi´c

1,2*

and Ajay K. Sharma

3

*Correspondence:sstevic@ptt.rs

1Mathematical Institute of the

Serbian Academy of Sciences, Beograd, Serbia

2Department of Medical Research,

China Medical University Hospital, China Medical University, Taichung, Taiwan, Republic of China Full list of author information is available at the end of the article

Abstract

Recently we have introduced a product-type operator and studied it on some spaces of analytic functions on the unit disc. Here we start investigating the operator on the space of analytic functions on the upper half-plane. We characterize the boundedness and compactness of the operator between Hardy and

α

-Bloch spaces on the domain.

MSC: Primary 47B38; 46E10; secondary 30D45

Keywords: Product-type operator; Hardy space; Bloch space; Boundedness; Compactness; Upper half-plane

1 Introduction

LetDbe the unit disc in the complex planeC,+={zC:z> 0}the upper half-plane

inC, and+=+∪ {∞}. Letbe a domain inC. We denote byH() the space of all

analytic functions onand byS() the class of all analytic self-maps of.

For 0 <p<∞, theHardy spaceof+, denoted byHp(+), consists of allf H(+) such

that

fpHp(+)=sup

y>0

–∞

f(x+iy)p

dx<∞.

For 1≤p<∞,Hp(+) is a Banach space.

Letα> 0. Theα-BlochorBloch-typespace on+, denoted by(+), consists of all

fH(+) such that

fBα(+):=f(i)+sup

z+(z)

α

f(z)<∞. (1)

With the norm (1), theα-Bloch space is a Banach space. For Bloch-type spaces on various domains and operators on them, see, for example, [1–13] and the references therein. For a natural extension of Bloch-type spaces and for Zygmud-type spaces, see [14–16].

ForϕS(), thecomposition operator Cϕis the linear operator defined by

(f)(z) = (fϕ)(z) forfH(). (2)

(2)

ForψH(), themultiplication operator Mψis defined onH() by

Mψf(z) =ψ(z)f(z) forfH(). (3)

The product of these two operators

,ψ= (4)

is the so-calledweighted composition operator. ByDwe denote thedifferentiation operator, that is,

Df =f, fH(). (5)

These concrete operators, along with some integral-type ones, are among those con-siderably studied, during the last five decades, on spaces of analytic functions on various domains inCor domains in the complex-vector spaceCn. Majority of the papers on the operators are devoted to investigating them on spaces of analytic functions onD. Much less papers consider the operators on spaces of analytic functions on other domains, in-cluding the upper half-plane. Even for some popular operators, such as the composition ones, up to the end of the previous century, there are no many papers on popular spaces such asHp(+) (see, e.g., [1720] and the references therein). Hence, any new result on

the spaces and operators on+is of some interest. Regarding some operators on the men-tioned spaces, let us mention that some basic results on the boundedness of composition operators fromHp(+) to the classical Bloch spaceB(+) can be found in note [21]. For

related investigations of composition or weighted composition operators on some other spaces, see [14,15,22–25]. Let us mention that the behavior of composition operators on spaces of analytic functions in+is considerably different from the behavior of composi-tion operators on spaces of analytic funccomposi-tions inD. For example, every analytic self-map ofDinduces a bounded composition operator on the corresponding Hardy space, which is not always the case on the spaceHp(+) [17,18].

From 1968 to 2005, experts more or less studied theoretic properties of only opera-tors (2)–(5) and integral-type ones on spaces of analytic functions in terms of their sym-bols. The only product-type operator among (2)–(5) is the weighted composition operator. Since 2005, some experts started studying some other product-type operators. The first product-type operators different from weighted composition ones that attracted some at-tention were the products of composition and differentiation operators (see, e.g., [7,11,13,

26–29] and the references therein). Some generalizations of the products of composition and differentiation operators, containing iterated differentiation, have appeared soon af-ter them (see [12,30–33]). Around 2008, Li and Stević have initiated studying products of integral and composition operators, including in some cases the differentiation operator, on spaces of analytic functions onD(see, e.g., [34]), which have been considerably studied recently (see, e.g., [3,35–40]). For some other results and related product-type operators, see, for example, [4–6,35,41–46].

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[5,42] on the operator on some other spaces of functions defined by

1,ψ2,ϕf(z) =ψ1(z)f

ϕ(z)+ψ2(z)f

ϕ(z), fH(D), (6)

whereψ1,ψ2∈H(D) andϕS(D).

It is clear that operator (6) includes the composition, multiplication, differentiation, weighted composition, weighted differentiation composition, and many other concrete operators, including those in [6,41,43], which are obtained by some concrete choices of the symbolsψ1,ψ2, andϕ. This is one of the reasons why the operator is of some

impor-tance for investigation.

So far the operator has not been considered between spaces of analytic functions on the upper half-plane. Here we start investigating the operator on such spaces by characteriz-ing the boundedness and compactness of the operator between the Hardy andα-Bloch spaces on the domain, that is, of 1,ψ2,ϕ:Hp(+)→(+). We provide a complete

characterization of the compactness. The paper can be regarded as a continuation of our investigations in [14,15,22–25].

Throughout this paper, constants are denoted byC; they are positive and not necessarily the same at each occurrence. The notation ABmeans thatBAB, whereAB

means that there is a positive constantCsuch thatACB.

2 Auxiliary results

First, we quote a point evaluation lemma, which is a folklore result (see, e.g., [15, Lemma 3]).

Lemma 1 Let p∈(0,∞)and n∈N0.Then

f(n)(z)≤CfHp(+) yn+1p

for some positive constant C=C(p,n)independent of f.

The following lemma can be found in [14, Lemma 2.1].

Lemma 2 Let p∈[1,∞),k∈N0,ζ+,and

,k(z) =

(ζ)k–1p

(zζ)k.

Then

sup

ζ+,kH

p(+)π 1 p.

To deal with the compactness of the operator1,ψ2,ϕ:H

p(+)Bα(+), in the lemma

(4)

composition operator. It is interesting that the proof of our present lemma is more com-plicated than those of the corresponding lemmas that we have had so for (for example, the lemma in [24]). Hence we will present a detailed proof of the lemma.

We say that a sequence (fn)n∈NinHp(+) converges weakly to zero if it is norm bounded

inHp(+) and converges to zero on compacts of+.

Lemma 3 Let p≥ 1, α ∈ (0, +∞), ψ1,ψ2 ∈ H(+), and ϕS(+). Then Tψ1,ψ2,ϕ : Hp(+)→(+)is compact if and only if for any sequence(f

n)n∈N weakly convergent

to zero,we have

lim

n→∞1,ψ2,ϕfnBα(

+)= 0. (7)

Proof Let the operator be compact. Suppose that (fn)n∈Nweakly converges to zero. Then

there are a subsequence (fnk)k∈NandgB

α(+) such that

lim

k→∞1,ψ2,ϕfnkgBα(+)= 0. (8)

LetK+be compact. Then

dK:=d

K,+= inf

zK,x∈R|zx|> 0.

From this and from (1) we have

1,ψ2,ϕfnk(i) –g(i)≤ 1,ψ2,ϕfnkgBα(+) (9)

and

sup zK

1,ψ2,ϕfnk(z) –g(z)

≤ 1

dK

1,ψ2,ϕfnkgBα(+). (10)

LetA+andA

ε={z+:d(z,K)≤ε}, whereε> 0. Note that ifAis compact, then

for eachε<dK, the setis also a compact set as bounded and closed.

On the other hand, we have

f(z) =f(i) +

z

i

f(ζ) (11)

for allfH(+) andz+. LetA+and

A(i) =w+:∃zA,w∈[i,z].

Note that ifAis compact, thenA(i) is also compact. Hence from (11) we easily get

f(z)≤f(i)+diamK(i) sup wK(i)

f(w) (12)

(5)

From (9), (10), and (12) it follows that

sup zK

1,ψ2,ϕfnk(z) –g(z)≤(1,ψ2,ϕfnk(i) –g(i)

+diamK(i) sup zK(i)

1,ψ2,ϕfnk(z) –h(z)

≤ 1 +diam(K(i))

dK(i)

1,ψ2,ϕfnkgBα(+). (13)

From (8) and (13) it follows that

1,ψ2,ϕfnk(z) –g(z)⇒0, k→ ∞, (14)

on each compactK+. Further, note that

Mj:=sup zK

ψj(z)<∞, j= 1, 2,

for each compactK. The compactness of the setϕ(K) also implies that maxfnk

ϕ(z),fnkϕ(z)⇒0, k→ ∞,

on each compactK+. From this, since

1,ψ2,ϕfnk

ϕ(z)≤M1 sup wϕ(K)

fnk(w)+M2 sup

wϕ(K) fnk(w),

it follows that

1,ψ2,ϕfnk(z)⇒0, k→ ∞, (15)

on each compactK+.

From (14) and (15) we obtaing(z) = 0 for everyz+, since eachz+lies in a

com-pact subset of+.

Using the fact in (8), it follows that

lim

k→∞1,ψ2,ϕfnkB

α(+)= 0. (16)

Such a procedure can be applied to any subsequence of (fn)n∈N, from which it follows that (7) holds.

Now assume that, for any sequence (fn)n∈N weakly convergent to zero, we have limn→∞1,ψ2,ϕfnBα(+) = 0. Let (fn)n∈N be a sequence of functions such that M:=

supnNfnHp(+) < +∞. By Lemma1 the sequence is uniformly bounded on compacts

of+, and consequently normal. Hence there are a subsequence (f

nk)k∈N andfH(+)

such that

(6)

on each compactK+. The Fatou lemma along with (17) impliesf

Hp(+)M. Hence,

the sequence (fnkf)k∈Nweakly converges to zero, and consequently

lim

k→∞1,ψ2,ϕ

fnk1,ψ2,ϕfBα(+)= 0,

from which the compactness of the operator1,ψ2,ϕ:H

p(+)Bα(+) follows.

3 Boundedness and compactness ofTψ1,ψ2,ϕ:H

p(

+)Bα(

+)

In this section, we characterize the boundedness and compactness of the operator

1,ψ2,ϕ:Hp(+)→B

α(+). We also give upper and lower bounds for the norm ofT

ψ1,ψ2,ϕ

acting between these spaces.

Theorem 4 Let 1 ≤p< ∞, α > 0, ψ1,ψ2 ∈ H(+) and ϕS(+). Then Tψ1,ψ2,ϕ : Hp(+)Bα(+)is bounded if and only if the following conditions are satisfied:

(i) M1=sup z+

(z)α

(ϕ(z))1/

1(z)<∞;

(ii) M2=sup z+

(z)α

(ϕ(z))1+1/1(z)ϕ

(z) +ψ

2(z)<∞;

(iii) M3=sup z+

(z)α

(ϕ(z))2+1/2(z)ϕ

(z)<∞.

Moreover,

M1+M2+M31,ψ2,ϕHp(+)Bα(+)

|ψ1(i)|

(ϕ(i))1/p +

|ψ2(i)|

(ϕ(i))1+1/p +M1+M2+M3. (18)

Proof First, suppose that conditions (i)–(iii) hold. Then by Lemma1we have

(z)α(T

ψ1,ψ2,ϕf)(z)

= (z)αψ1(z)(z)+ψ1(z)ϕ(z) +ψ2(z)

(z)+ψ2(z)ϕ(z)f

ϕ(z) ≤CfHp(+) (z)

α

(ϕ(z))1/

1(z)+

(z)α

(ϕ(z))1+1/1(z)ϕ

(z) +ψ

2(z)

+ (z)

α

(ϕ(z))2+1/2(z)ϕ

(z)

C(M1+M2+M3)fHp(+). (19)

We also have

1,ψ2,ϕf(i)=ψ1(i)f

ϕ(i)+ψ2(i)f

ϕ(i) ≤CfHp(+) |ψ1(i)|

(ϕ(i))1/p +

|ψ2(i)|

(ϕ(i))1+1/p

(7)

Combining (19) and (20), we have

1,ψ2,ϕfBα(+)

|ψ1(i)|

(ϕ(i))1/p +

|ψ2(i)|

(ϕ(i))1+1/p +M1+M2+M3

fHp(+),

from which it follows that

1,ψ2,ϕHp(+)Bα(+) |ψ1(i)|

(ϕ(i))1/p +

|ψ2(i)|

(ϕ(i))1+1/p+M1+M2+M3. (21) Conversely, suppose that1,ψ2,ϕ:H

p(+)Bα(+) is bounded. Consider the family

of functions

fw(z) =

(w)2–1/p

π1/p(zw)2 – 4i

(w)3–1/p

π1/p(zw)3 – 4

(w)4–1/p

π1/p(zw)4,

wherew+.

Since the functions fware linear combinations of the functions in Lemma 2(fork= 2, 3, 4), from this by using the lemma it follows that

L1:= sup w+fwH

p(+)<∞. (22)

We also have

fw(z) =–2(w)

2–1/p

π1/p(zw)3 + 12i

(w)3–1/p

π1/p(zw)4+ 16

(w)4–1/p

π1/p(zw)5,

fw(z) = 6(w)

2–1/p

π1/p(zw)4 – 48i

(w)3–1/p

π1/p(zw)5 – 80

(w)4–1/p

π1/p(zw)6,

from which with some simple calculation we obtain

fw(w) = 0, fw(w) = 0 and fw(w) =

1

8π1/p(w)2+1/p. (23)

Since1,ψ2,ϕ:Hp(+)→(+) is bounded, we have

1,ψ2,ϕfwBα(+)≤ 1,ψ2,ϕHp(+)→(+)fwHp(+)

L11,ψ2,ϕHp(+)Bα(+)

for everyw+.

Thus for eachζ+, we have

L11,ψ2,ϕHp(+)Bα(+)≥(ζ)α(Tψ1,ψ2,ϕfϕ(ζ))(ζ)

= (ζ)αψ

1(ζ)(ζ)

ϕ(ζ)+ψ1(ζ)ϕ(ζ) +ψ2(ζ)

fϕ(ζ)ϕ(ζ) +ψ2(ζ)ϕ(ζ)(ζ)

ϕ(ζ) =(ζ)

α|ψ

2(ζ)ϕ(ζ)|

(8)

Sinceζ+is arbitrary, we have that

M3= sup

ζ+

(ζ)α|ψ

2(ζ)ϕ(ζ)|

(ϕ(ζ))2+1/p ≤8π 1/pL

11,ψ2,ϕHp(+)Bα(+). (24)

Now, consider the family of functions

gw(z) = 12

(w)2–1/p

π1/p(zw)2 – 32i

(w)3–1/p

π1/p(zw)3– 24

(w)4–1/p

π1/p(zw)4.

Since the functionsgware also linear combinations of the functions in Lemma2, we have

L2:=supw+gwHp(+)≤1.

We also have

gw(z) = –24 (w)

2–1/p

π1/p(zw)3+ 96i

(w)3–1/p

π1/p(zw)4 + 96

(w)4–1/p

π1/p(zw)5,

gw(z) = 72 (w)

2–1/p

π1/p(zw)4 – 384i

(w)3–1/p

π1/p(zw)5 – 480

(w)4–1/p

π1/p(zw)6,

from which it follows that

gw(w) = 0, gw(w) = 0, and gw(w) = – 1 2π1/p(w)1/p.

Since1,ψ2,ϕ:Hp(+)→(+) is bounded, for eachζ+, we have

L21,ψ2,ϕHp(+)→(+)≥ 1,ψ2,ϕgϕ(ζ)Bα(+)

= (ζ)αψ1(ζ)(ζ)

ϕ(ζ)+ψ1(ζ)ϕ(ζ) +ψ2(ζ)

(ζ)

ϕ(ζ) +ψ2(ζ)ϕ(ζ)(ζ)

ϕ(ζ) = (ζ)

α|ψ

1(ζ)|

2π1/p(ϕ(ζ))1/p. Sinceζ+is arbitrary, we have that

M1= sup

ζ+

(ζ)α|ψ

1(ζ)|

(ϕ(ζ))1/p ≤2π 1/pL

21,ψ2,ϕHp(+)→(+). (25)

Now, consider the family of functions

hw(z) = 8 (

w)2–1/p

π1/p(zw)2 – 28i

(w)3–1/p

π1/p(zw)3 – 24

(w)4–1/p

π1/p(zw)4.

Once again proceeding as before, we can show thatsupw+hwHp(+)1.

We have

hw(z) = –16 (w)

2–1/p

π1/p(zw)3+ 84i

(w)3–1/p

π1/p(zw)4 + 96

(w)4–1/p

π1/p(zw)5;

hw(z) = 48 (w)

2–1/p

π1/p(zw)4– 336i

(w)3–1/p

π1/p(zw)5– 480

(w)4–1/p

(9)

Thus

hw(w) = 0, hw(w) = 0 and hw(w) =

i

4π1/p(w)1+1/p.

Therefore by the boundedness of1,ψ2,ϕ:Hp(+)→(+), for eachζ+, we have

L31,ψ2,ϕHp(+)→(+)≥(ζ)

αψ

1(ζ)(ζ)

ϕ(ζ)+ψ1(ζ)ϕ(ζ) +ψ2(ζ)

(ζ)

ϕ(ζ) +ψ2(ζ)ϕ(ζ)(ζ)

ϕ(ζ) =(ζ)

α|ψ

1(ζ)ϕ(ζ) +ψ2(ζ)|

4π1/p(ϕ(ζ))1+1/p , and consequently

M2= sup

ζ+

(ζ)α|ψ

1(ζ)ϕ(ζ) +ψ2(ζ)|

(ϕ(ζ))1+1/p ≤4π 1/pL

31,ψ2,ϕHp(+)→(+). (26)

Combining (24), (25), and (26), we have

M1+M2+M31,ψ2,ϕHp(+)Bα(+),

finishing the proof of the theorem.

Corollary 5 Let1≤p<∞,α> 0andϕS(+).Then Cϕ:Hp(+)→(+)is bounded

if and only if

M4=sup z+

(z)α

(ϕ(z))1+1/

(z)<∞.

Moreover,

M4CϕHp(+)Bα(+) 1

(ϕ(i))1/p+M4. (27)

Corollary 6 Let1≤p<∞,α> 0,ψH(+)andϕS(+).Then MψCϕ:Hp(+)→

(+)is bounded if and only if

(i) M5=sup z+

(z)α

(ϕ(z))1/

(z)<∞,

(ii) M6=sup z+

(z)α

(ϕ(z))1+1/(z)ϕ

(z)<∞.

Moreover,

M5+M6MψCϕHp(+)Bα(+) |ψ(i)|

(ϕ(i))1/p +M5+M6. (28)

Corollary 7 Let1≤p<∞,α> 0,ψH(+)andϕS(+).Then CϕMψ:Hp(+)→

(+)is bounded if and only if

(i) M7=sup z+

(z)α

(ϕ(z))1/

ϕ(z)ϕ(z)<∞,

(ii) M8=sup z+

(z)α

(ϕ(z))1+1/

(10)

Moreover,

M7+M8CϕMψHp(+)Bα(+) |ψ(ϕ(i))|

(ϕ(i))1/p +M7+M8. (29)

Corollary 8 Let 1≤p<∞, α > 0 and ϕS(+). Then CϕD:Hp(+)→(+) is

bounded if and only if

M9=sup z+

(z)α

(ϕ(z))2+1/

(z)<∞.

Moreover,

M9CϕDHp(+)Bα(+) 1

(ϕ(i))1+1/p +M9. (30)

Corollary 9 Let1 ≤p<∞, α > 0 andϕS(+). Then DCϕ :Hp(+)→(+) is

bounded if and only if

(i) M10=sup z+

(z)α

(ϕ(z))1+1/

(z)<∞,

(ii) M11=sup z+

(z)α

(ϕ(z))2+1/

(z)2

<∞.

Moreover,

M10+M11DCϕHp(+)Bα(+) |ϕ (i)|

(ϕ(i))1+1/p +M10+M11. (31) Corollary 10 Let1≤p<∞,α> 0,ψH(+)andϕS(+).Then MψCϕD:Hp(+)→

(+)is bounded if and only if

(i) M12=sup z+

(z)α

(ϕ(z))1+1/

(z)<,

(ii) M13=sup z+

(z)α

(ϕ(z))2+1/(z)ϕ

(z)<.

Moreover,

M12+M13MψCϕDHp(+)Bα(+) |ψ(i)|

(ϕ(i))1+1/p +M12+M13. (32) Corollary 11 Let1≤p<∞,α> 0,ψH(+)andϕS(+).Then CϕMψD:Hp(+)→

(+)is bounded if and only if

(i) M14=sup z+

(z)α

(ϕ(z))1+1/

ϕ(z)ϕ(z)<∞,

(ii) M15=sup z+

(z)α

(ϕ(z))2+1/

(11)

Moreover,

M14+M15CϕMψDHp(+)Bα(+) |

ψ(ϕ(i))|

(ϕ(i))1+1/p +M14+M15. (33) Corollary 12 Let1≤p<∞,α> 0,ψH(+)andϕS(+).Then M

ψDCϕ:Hp(+)→

(+)is bounded if and only if

(i) M16=sup z+

(z)α

(ϕ(z))1+1/pψ ϕ

(z)<∞,

(ii) M17=sup z+

(z)α

(ϕ(z))2+1/(z)

ϕ(z)2<∞.

Moreover,

M16+M17MψDCϕHp(+)Bα(+) |ψ(i)ϕ (i)|

(ϕ(i))1+1/p +M16+M17. (34) Corollary 13 Let1≤p<∞,α> 0,ψH(+)andϕS(+).Then DMψCϕ:Hp(+)→

(+)is bounded if and only if

(i) M18=sup z+

(z)α

(ϕ(z))1/

(z)<∞,

(ii) M19=sup z+

(z)α

(ϕ(z))1+1/p2ψ

(z)ϕ(z) +ψ(z)ϕ(z)<∞,

(iii) M20=sup z+

(z)α

(ϕ(z))2+1/(z)

ϕ(z)2<∞.

Moreover,

M18+M19+M20DMψCϕHp(+)Bα(+)

(|ψ(i)|

ϕ(i))1/p +

|ψ(i)ϕ(i)|

(ϕ(i))1+1/p +M18+M19+M20. Corollary 14 Let1≤p<∞,α> 0,ψH(+)andϕS(+).Then C

ϕDMψ:Hp(+)→

(+)is bounded if and only if

(i) M21=sup z+

(z)α

(ϕ(z))1/

ϕ(z)ϕ(z)<∞,

(ii) M22=sup z+

(z)α

(ϕ(z))1+1/

ϕ(z)ϕ(z)<∞,

(iii) M23=sup z+

(z)α

(ϕ(z))2+1/

ϕ(z)ϕ(z)<∞.

Moreover,

M21+M22+M23CϕDMψHp(+)Bα(+)

|(ψ(ϕ(i))|

ϕ(i))1/p +

|ψ(ϕ(i))|

(12)

Corollary 15 Let1≤p<∞,α> 0,ψH(+)andϕS(+).Then DC

ϕMψ:Hp(+)→

(+)is bounded if and only if

(i) M24=sup z+

(z)α

(ϕ(z))1/

ϕ(z)ϕ(z) +ψϕ(z)ϕ(z)2<,

(ii) M25=sup z+

(z)α

(ϕ(z))1+1/p2ψ

ϕ(z)ϕ(z)2+ψϕ(z)ϕ(z)<∞,

(iii) M26=sup z+

(z)α

(ϕ(z))2+1/

ϕ(z)ϕ(z)2<∞.

Moreover,

M24+M25+M26DCϕMψHp(+)Bα(+)

|ψ(ϕ(i))ϕ(i)| (ϕ(i))1/p +

|ψ(ϕ(i))ϕ(i)|

(ϕ(i))1+1/p +M24+M25+M26.

Recall that for a functionf defined in+,limz+f(z) = 0 if and only if for everyε> 0,

there is a compact setK+such that|f(z)|<εforz+\K.

The following result characterizes the compactness of the operator1,ψ2,ϕ:Hp(+)→

(+).

Theorem 16 Let 1 ≤p<∞, α > 0, ψ1,ψ2 ∈H(+), and ϕS(+). Then Tψ1,ψ2,ϕ :

Hp(+)Bα(+)is compact if and only if it is bounded and the following conditions

are satisfied:

(i) lim

ϕ(z)→+

(z)α

(ϕ(z))1/

1(z)= 0,

(ii) lim

ϕ(z)→+

(z)α

(ϕ(z))1+1/1(z)ϕ

(z) +ψ

2(z)= 0,

(iii) lim

ϕ(z)→+

(z)α

(ϕ(z))2+1/2(z)ϕ

(z)= 0.

Proof Assume that the operator is bounded and conditions (i)–(iii) hold. Then by Theo-rem4the quantitiesMj,j= 1, 3, are finite, whereas from conditions (i)–(iii) we have that, for eachε> 0, there exists a compact setKin+such that

(z)α

(ϕ(z))1/

1(z)<ε, (35)

(z)α

(ϕ(z))1+1/1(z)ϕ

(z) +ψ

2(z)<ε, (36)

(z)α

(ϕ(z))2+1/2(z)ϕ

(z)<ε, (37)

provided thatϕ(z)∈+\K.

(13)

(z)α(1,ψ2,ϕfn) (z)

≤(z)αψ1(z)fn

ϕ(z)+ψ1(z)ϕ(z) +ψ2(z)

fnϕ(z)+ψ2(z)ϕ(z)fn

ϕ(z)

C (z)

α

(ϕ(z))1/

1(z)+

(z)α

(ϕ(z))1+1/1(z)ϕ

(z) +ψ

2(z)

+ (z)

α

(ϕ(z))2+1/2(z)ϕ

(z)f

nHp(+)

<.

SinceKis compact,ϕ(K) is also compact. Hence

M27:= sup wϕ(z)

w∈(0,∞).

Choosen0∈Nsuch that

max zK

fn(z)<

ε

M1M1/27p

, max

zK

fn(z)< ε

M2M1/27p+1

,

max zKf

n(z)<

ε

M3M1/27p+2

,

(38)

and

maxfn(i),fn(i)<ε (39)

for allnn0.

Then, by the preceding and (38), for everyz+such thatϕ(z)K, we have

(z)αψ1(z)fn

ϕ(z)+ψ1(z)ϕ(z) +ψ2(z)

fnϕ(z)+ψ2(z)ϕ(z)fn

ϕ(z) ≤(z)αψ1(z)max

wK

fn(w)+ (z)αψ1(z)ϕ(z) +ψ2(z)max wK

fn(w)

+ (z)αψ2(z)ϕ(z)max wKf

n(w)

M1

ϕ(z)1/pmax wK

fn(w)+M2

ϕ(z)1+1/pmax wK

fn(w)

+M3

ϕ(z)2+1/pmax wK

fn(w)

M1max wK(w)

1/pmax wK

fn(w)+M2max wK(w)

1+1/pmax wK

fn(w)

+M3(w)2+1/pmax wK

fn(w)

< 3ε. (40)

Further, using (39), we have

1,ψ2,ϕfn(i)=ψ1(i)fn

ϕ(i)+ψ2(i)fn

ϕ(i)≤ψ1(i)+ψ2(i)ε (41)

(14)

From (40) and (41) it follows that

1,ψ2,ϕfnBα(+)<

3 +ψ1(i)+ψ2(i)ε

fornn0.

Sinceε> 0 is arbitrary, by Lemma3it follows that1,ψ2,ϕ:H

p(+)Bα(+) is

com-pact.

Conversely, suppose that 1,ψ2,ϕ:H

p(+)Bα(+) is compact. Then, clearly, it is

bounded. Let (zn)n∈N be a sequence in+such thatϕ(zn)→+asn→ ∞. If such a sequence does not exist, then conditions (i)–(iii) vacuously hold.

Letwn=ϕ(zn),n∈N, and let the family of functions (fn)n∈Nbe defined by

fn(z) =

(wn)2–1/p

π1/p(zw n)2

– 4i (wn)

3–1/p

π1/p(zw n)3

– 4 (wn)

4–1/p

π1/p(zw n)4

.

Then by using (22) and some simple estimates it is easy to see that (fn)n∈Nweakly converges to zero asn→ ∞(including the case whenwn→ ∞asn→ ∞). Hence

lim

n→∞1,ψ2,ϕfnB

α(+)= 0. (42)

The boundedness of1,ψ2,ϕ:Hp(+)→(+), together with (23), implies

1,ψ2,ϕfnBα(+)≥(zn)

αψ

1(zn)fn

ϕ(zn)

+ψ1(zn)ϕ(zn) +ψ2(zn)

fnϕ(zn)

+ψ2(zn)ϕ(zn)fn

ϕ(zn)

= (zn)

α

8π1/p(ϕ(z n))2+1/p

ψ2(zn)ϕ(zn). (43)

From (42) and (43) we obtain

lim

ϕ(zn)→+

(zn)α (ϕ(zn))2+1/p

ψ2(zn)ϕ(zn)= 0, (44)

from which it follows that condition (i) holds. By considering families of functions

gn(z) = 12 (

wn)2–1/p

π1/p(zw n)2

– 32i (wn)

3–1/p

π1/p(zw n)3

– 24 (wn)

4–1/p

π1/p(zw n)4

and

hn(z) = 8

(wn)2–1/p

π1/p(zw n)2

– 28i (wn)

3–1/p

π1/p(zw n)3

– 24 (wn)

4–1/p

π1/p(zw n)4

and proceeding as before, we can similarly show that

lim

ϕ(zn)→+

(zn)α (ϕ(zn))1+1/p

(15)

and

lim

ϕ(zn)→+

(zn)α (ϕ(zn))1/p

ψ1(zn)= 0, (46)

from which it follows that conditions (ii) and (iii) hold, respectively.

Corollary 17 Let1≤p<∞,α> 0andϕS(+).Then Cϕ:Hp(+)→(+)is

com-pact if and only if it is bounded and

lim

ϕ(z)→+

(z)α

(ϕ(z))1+1/

(z)= 0.

Corollary 18 Let1≤p<∞,α> 0,ψH(+)andϕS(+).Then MψCϕ:Hp(+)→

(+)is compact if and only if it is bounded and

(i) lim

ϕ(z)→+

(z)α

(ϕ(z))1/

(z)= 0,

(ii) lim

ϕ(z)→+

(z)α

(ϕ(z))1+1/(z)ϕ

(z)= 0.

Corollary 19 Let1≤p<∞,α> 0,ψH(+)andϕS(+).Then CϕMψ:Hp(+)→

(+)is compact if and only if it is bounded and

(i) lim

ϕ(z)→+

(z)α

(ϕ(z))1/

ϕ(z)ϕ(z)= 0,

(ii) lim

ϕ(z)→+

(z)α

(ϕ(z))1+1/

ϕ(z)ϕ(z)= 0.

Corollary 20 Let1≤p<∞,α> 0andϕS(+).Then C

ϕD:Hp(+)→(+)is

com-pact if and only if it is bounded and

lim

ϕ(z)→+

(z)α

(ϕ(z))2+1/

(z)= 0.

Corollary 21 Let1≤p<∞,α> 0andϕS(+).Then DCϕ:Hp(+)→(+)is

com-pact if and only if it is bounded and

(i) lim

ϕ(z)→+

(z)α

(ϕ(z))1+1/

(z)= 0,

(ii) lim

ϕ(z)→+

(z)α

(ϕ(z))2+1/

(z)2

= 0.

Corollary 22 Let1≤p<∞,α> 0,ψH(+)andϕS(+).Then M

ψCϕD:Hp(+)→

(+)is compact if and only if it is bounded and

(i) lim

ϕ(z)→+

(z)α

(ϕ(z))1+1/

(z)= 0,

(ii) lim

ϕ(z)→+

(z)α

(ϕ(z))2+1/(z)ϕ

(16)

Corollary 23 Let1≤p<∞,α> 0,ψH(+)andϕS(+).Then C

ϕMψD:Hp(+)→

(+)is compact if and only if it is bounded and

(i) lim

ϕ(z)→+

(z)α

(ϕ(z))1+1/

ϕ(z)ϕ(z)= 0,

(ii) lim

ϕ(z)→+

(z)α

(ϕ(z))2+1/

ϕ(z)ϕ(z)= 0.

Corollary 24 Let1≤p<∞,α> 0,ψH(+)andϕS(+).Then M

ψDCϕ:Hp(+)→

(+)is compact if and only if it is bounded and

(i) lim

ϕ(z)→+

(z)α

(ϕ(z))1+1/pψ ϕ

(z)= 0,

(ii) lim

ϕ(z)→+

(z)α

(ϕ(z))2+1/(z)

ϕ(z)2= 0.

Corollary 25 Let1≤p<∞,α> 0,ψH(+)andϕS(+).Then DMψCϕ:Hp(+)→

(+)is compact if and only if it is bounded and

(i) lim

ϕ(z)→+

(z)α

(ϕ(z))1/

(z)= 0,

(ii) lim

ϕ(z)→+

(z)α

(ϕ(z))1+1/p2ψ

(z)ϕ(z) +ψ(z)ϕ(z)= 0,

(iii) lim

ϕ(z)→+

(z)α

(ϕ(z))2+1/(z)

ϕ(z)2= 0.

Corollary 26 Let1≤p<∞,α> 0,ψH(+)andϕS(+).Then C

ϕDMψ:Hp(+)→

(+)is compact if and only if it is bounded and

(i) lim

ϕ(z)→+

(z)α

(ϕ(z))1/

ϕ(z)ϕ(z)= 0,

(ii) lim

ϕ(z)→+

(z)α

(ϕ(z))1+1/

ϕ(z)ϕ(z)= 0,

(iii) lim

ϕ(z)→+

(z)α

(ϕ(z))2+1/

ϕ(z)ϕ(z)= 0.

Corollary 27 Let1≤p<∞,α> 0,ψH(+)andϕS(+).Then DCϕMψ:Hp(+)→

(+)is compact if and only if it is bounded and

(i) lim

ϕ(z)→+

(z)α

(ϕ(z))1/

ϕ(z)ϕ(z) +ψϕ(z)ϕ(z)2= 0,

(ii) lim

ϕ(z)→+

(z)α

(ϕ(z))1+1/p2ψ

ϕ(z)ϕ(z)2+ψϕ(z)ϕ(z)= 0,

(iii) lim

ϕ(z)→+

(z)α

(ϕ(z))2+1/

(17)

Acknowledgements

The study in the paper is a part of the investigation at the projects III 41025 and III 44006 by the Serbian Ministry of Education and Science.

Funding

Not applicable.

Availability of data and materials

Not applicable.

Competing interests

The authors declare that they have no competing interests.

Authors’ contributions

The authors have contributed equally to the writing of this paper. They read and approved the manuscript.

Author details

1Mathematical Institute of the Serbian Academy of Sciences, Beograd, Serbia.2Department of Medical Research, China

Medical University Hospital, China Medical University, Taichung, Taiwan, Republic of China.3Department of Mathematics, Central University of Jammu, Jammu, India.

Publisher’s Note

Springer Nature remains neutral with regard to jurisdictional claims in published maps and institutional affiliations.

Received: 10 August 2018 Accepted: 30 September 2018 References

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