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(1)

Redox:

(2)

Definitions

Oxidation

:

loss of e- in an atom

increase in oxidation number

(ex: -1

0 or +1

+2)

Reduction

:

gain of e- by an atom

(3)

Trick to remember this

:

OIL RIG

O

xidation

i

s

l

oss

(4)

Another trick

….

LEO

(the lion says…)

GER

LEO

-

L

ose

E

lectrons

O

xidation

(5)

Assigning Oxidation Numbers

(What are they?)

Definition:

The apparent charge assigned to an atom of an element.

Numbers may

be

+, -, or 0

• These are not ionic charges, but maybe the same as the ionic charge.

To distinguish oxidation numbers from charges on ions, the sign of the oxidation number precedes the number.

Example: Ionic Charge = Mg2+

(6)

Assigning Oxidation Numbers

(Why do we use them?)

During an Oxidation-Reduction reaction electrons are exchanged or transferred.

Its not always possible to determine whether atoms have exchanged electrons by simply reading an equation.

Chemists have devised a system that makes it easier to keep track of the number of electrons lost or gained during a reaction.

Positive, negative or neutral values known as Oxidation Numbers or States

can be assigned to atoms.

Oxidation numbers help show which atoms and how many electrons are either gained or lost by an atom.

(7)

Assigning Oxidation Numbers

(How do we assign them?)

You must!!! Learn the rules for assigning oxidation states to atoms in an equation.

These numbers will be used to identify what is being oxidized and reduced. Rules for assigning Oxidation #’s

1. Each uncombined or lone element has an oxidation number of “0”. Ex. Na + Cl2 >>> NaCl – both Na and Cl2 have oxidation numbers of “0”

2. Monatomic ions have an oxidation number equal to its ionic charge.

Ex. Na + Cl2 >>> NaCl – the Na ion in NaCl will have an oxidation # of +1 the Cl ion in NaCl will have an oxidation # of -1.

3. The metals in group 1 always have oxidation numbers of +1 in compounds, and the metals in group 2 always have an oxidation number of +2 in

compound.

4. Fluorine always has an oxidation number -1 in compound. All the halogens (group 17) will be -1 if they are the most electronegative element in the

(8)

Assigning Oxidation Numbers (How

do we assign them? continued)

5. Hydrogen is +1 in compounds unless it is combined with a metal, in which it is -1.

Example: Hydrogen is +1 in HCl but -1 in LiH

6. Oxygen is usually -2 in compounds. Except when its is combined with fluorine, which is more electronegative, its +2.

Example: Oxygen is -2 in H2O, and +2 in OF2. In the peroxide polyatomic ion (O22-)

oxygen is -1.

These 6 rules can be used along with the following 2 additional rules to calculate oxidation numbers for other elements in compounds or polyatomic ions in an

equation.

7. The sum of the oxidation numbers in all compounds must be zero.

(9)

Practice Assigning Oxidation

Numbers

Example # 1 HNO3

What are the oxidation numbers of the atoms?

Use the first six rules to assign oxidation numbers first then if you still have some to assign make sure the sum of the oxidation numbers is 0 (rule 7)

Rule 5 states H must be +1

Rule 6 states each oxygen must be -2, and since there are three oxygen atoms they must total (3 x -2) -6

So the total of 1 hydrogen and 3 oxygen atoms is (+1 + -6) -5 which means using rule 7 each nitrogen must be +5 to make the total charge of the compound “0”.

Final answer H = +1 N = +5

(10)

More Practice Assigning Oxidation

Numbers

What is the oxidation number of chromium in the dichromate ion? Cr2O7

2-Use as many of the first six rules as possible

O has an oxidation number -2 (rule6), producing a total of (7 x -2) -14 for the seven O atoms.

Using rule 8 the sum of the oxidation numbers must be equal to the charge of the polyatomic ions charge

2 x (the oxidation of Cr) + (-14) = -2 2 x (the oxidation of Cr) must = +12 oxidation of Cr = +12/2

oxidation of Cr = +6

(11)

Oxidation

Losing electrons

Any chemical change in which the oxidation number

increases.

Example

2Mg(s) + O2(g) → 2MgO(s)

(Magnesium loses, oxygen gains)

(12)

Rusting

Occurs when metals react with oxygen.

(accelerated by water and salts).

(13)

Reduction

Gaining electrons.

Any chemical change in which an oxidation

number of an element

decreases

.

Example:

(14)

Metal Ores

Occur naturally in

combination or in oxidized state.

(15)

Practice

Given a redox reaction… Which is being oxidized?

Which is being reduced?

Magnesium + Oxygen yields Magnesium oxide 2Mg0 + O

20 2Mg+2O-2

Zinc + Copper (II) Sulfate Yields Zinc Sulfate + Copper Zn0 + Cu+2S+6O-2

(16)

Redox Reactions

Oxidation cannot occur without reduction.

When electrons from one atom are lost, they must be gained by

another.

We call reactions that involve oxidation and reduction REDOX

reactions.

Not all reactions are redox reactions. To determine whether or

not a reaction is redox, assign oxidation numbers to each atom,

both on the reactant and product side.

If there is a change in oxidation number for any atom, the

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Redox Reactions (Continued)

If an element exists alone on one side and in a

compound on the other, then it is a Redox Reaction.

Most single replacement, decomposition and synthesis reactions are Redox

(18)

Reducing Agents: Metals

– The

reducing agent

is the species being oxidized.

(19)

Oxidizing Agents: Non-metals

The

oxidizing agent

is the species being

reduced.

Oxidation number decreases.

(20)

Half-Reactions

A half-reaction shows either the oxidation or reduction portion of a redox reaction, including the electrons

gained or lost.

A reduction half-reaction shows an atom or an ion

gaining one or more electrons while its oxidation number decreases

Ex. Na+1 + 1e- Na0

An oxidation half-reaction shows an atom or an ion

losing one or more electrons while its oxidation number increases.

(21)

1e-Half-Reactions (continued)

Half-reactions must show conservation of mass and charge when written properly.

In a half-reaction there will be only one type of atom or ion shown on both reactant and product sides.

In a half-reaction the net charge on both sides of the equation must be equal, but it does not have to be “0”. Ex. Sn+4 + 2e- Sn+2 Net Charge/side = +2

Mass is conserved with 1

(22)

Writing Half-Reactions

To write the half-reactions for an equation such as MgCl2 + 2Na 2NaCl + Mg Make sure the equation is balanced

Next assign oxidation numbers to each atom, then write a partial half-reaction to show the change in oxidation number including the coefficients from the balanced equation.

Oxidation: 2Na0 2Na+1

Reduction Mg+2 Mg0

Then place the correct number of electrons on one side of the equation to make the net charge equal on both sides. (remember electrons will always be a product in oxidation and a reactant in reduction)

Oxidation: 2Na0 2Na+1 +

2e-Reduction: 2e- + Mg+2 Mg0

When you have written a correct oxidation and reduction half-reaction the electrons lost (oxidation) should be equal to the electrons gained (reduction)

(23)

ELECTROCHEMICAL CELL

The exchange of electrons during a redox reaction can be useful

to us.

One practical use of a redox reaction is in an electrochemical

cell. An electrochemical cell involves a chemical reaction and

the flow of electrons.

There are two common electrochemical cells.

Voltaic cells, which use a spontaneous reaction to produce a flow of electrons or an electric current.

(24)

ELECTROCHEMICAL CELL

(continued)

Electrochemical cells have two surfaces called electrodes that

can conduct electricity.

An electrode is were oxidation or reduction will occur.

The electrode at which oxidation occurs is called the anode.

The electrode at which reduction occurs is called the cathode.

(25)

Voltaic Cells

Voltaic cells take advantage of electron transfers

during

spontaneous reactions

usually single

replacement.

When you have two metals that differ in

reactivity one will

lose electrons

easily

(oxidation) and the other will

gain the electrons

(reduction) the other has lost.

(26)

Voltaic Cells

The metals must be placed in separate ionic solutions that are connected by a salt bridge.

The metals act as electrodes the one that is more

reactive, loses electrons (oxidation), will be the anode, the less reactive metal, gains electrons (reduction), is the cathode.

A voltmeter can be attached to the wire connecting the metals to detect electric current.

(27)
(28)

Drawing an Voltaic Cell

Solution A Solution

B Salt Bridge

Voltmete r

(29)

Voltaic Cells

Each vessel is called a half cell because a half reaction takes place here.

The salt bridge connects the two half cell solutions allowing ions to flow from one solution to the other to balance out the charge.

The electrodes (metals) are connected by a wire which acts as an electrical conductor. The flow of electrons through the wire creates an electric current.

(30)

Voltaic Cells & Table J

Oxidation and reduction occur at the electrodes.

To identify which electrode is your anode or the site of oxidation and which is your cathode the sight of

reduction you must compare the reactivity of the metals on Table J in your reference table.

The more reactive metal will always lose electrons (oxidation) which makes it your Anode.

The less reactive metal will always gain electrons (reduction) it is always your cathode.

(31)

Table J

So in summary the metal higher up on Table J is your Anode (oxidation) the metal lower on Table J is your cathode (reduction).

Once you identify your anode and cathode you can identify the flow of electrons they flow from the Anode to the Cathode.

(32)

Electrolytic Cells

• In a

voltaic cell

electrons flow spontaneously

from anode to cathode.

• The opposite occurs in an

electrolytic cell

,

since the reaction is

non-spontaneous

there

must be an electrical

power source

placed in

the circuit to force the electrons from anode to

cathode.

(33)

Electroplating

• The most common use of electrolytic cells is an

electroplating cell.

Electroplating involves plating a small layer of usually a precious metal on another metal.

• The material to be plated for example a spoon or a

piece of jewelry, would be the cathode were reduction occurs.

(34)

Electrolytic Cell For Electroplating

Anode

Cathode Power Source

•Anode-Oxidation •Ag0 Ag+1

(35)

Electrolysis

Electrolysis can be used to break up compounds to reform the elements it is made up of.

• For instance if you wanted to break up water molecules into hydrogen and oxygen gas you could use an

Electrolytic Cell.

• Since the reaction will be non-spontaneous a power source must be used to force the reaction to occur.

• The power source is usually a battery.

(36)

Electrolytic Cell for Electrolysis

Power Source

Write the half-reactions:

Reduction: 4H+1 + 4e- 2H

2 (Cathode)

Oxidation: 2O-2 O

(37)

Comparing Voltaic and Electrolytic

Comparing Voltaic and Electrolytic

Cells

Cells

Voltaic and Electrolytic cells have several

similarities and differences.

Similarities

1. Both use redox reactions 2. The anode is the site of

oxidation

3. The cathode is the site of reduction

4. The electron flow through the wire is from anode to cathode

Differences

1. Voltaic cells use spontaneous reactions to produce energy (voltmeter)

2. Electrolytic use non-spontaneous reactions that requires energy (power source)

3. Voltaic cells the anode is negative and the cathode is positive

4. Electrolytic cells the anode is

AnodeCathode

References

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