SPM Chemistry Form 4 Notes – Chemical Bonds
(Part 1)
Formation of Compounds
Compounds – different elements that chemically bonded together
Octet electron arrangement – electron arrangement of an atom where the outermost occupied shell is filled with eight valence electrons
Duplet electron arrangement – electron arrangement of an atom where a single shell filled with two valence electrons
Example:
Compound water is hydrogen and oxygen atoms are chemically bonded together.
Stability of Noble Gases
Atom of noble gas does not gain, lose nor share electrons with other atoms.
Noble gas atoms do not combine with atoms of other elements to form compounds or with each other to form molecules.
Noble gases are chemically unreactive.
Noble gases exist as monoatomic. Chemical Bonds
Chemical Bond
Types of chemical bonds:
ionic bonds (metal + non-metal)
Atoms of other elements can achieve the stable octet electron arrangement by transfer of electrons
Scientist
Italian physicist Amedeo Avogadro (Name at birth: Lorenzo Romano Amedeo Carlo Avogadro)
Born: 9 August 1776
Birthplace: Turin, Piedmont, Italy
Died: 9 July 1856
Best Known As: The guy they named Avogadro’s number after
1. Avogadro constant / Avogadro’s number is 6.02 x 1023 2. Atomic substances
Elements – all the particles are atoms.
Example: zinc (Zn), sodium (Na), aluminium (Al) and all noble gases, argon (Ar), helium (He) and neon (Ne).
RAM (Relative Atomic Mass) of Na = 23 3. Molecular substances
Covalent compounds – the particles are molecules.
Example: carbon dioxide (CO2), water (H2O) and non-metal elements, iodine (I2),
nitrogen (N2) and oxygen (O2).
RMM (Relative Molecular Mass) of I2 = 127 + 127 = 254
4. Ionic substances
Ionic compounds – the particles are ions.
Example: sodium chloride (NaCl), hydrochloric acid (HCl) and potassium iodide (KI).
RFM (Relative Formula Mass) of HCl = 1 + 35.5 = 36.5
5. Avogadro’s Law / Gas Law states that equal volumes of all gases contain the same number of molecules under the same temperature and pressure.
Example: equal volumes of molecular hydrogen and nitrogen would contain the same number of molecules under the same temperature and pressure.
6. Volume of gas (dm3) = Number of moles of gas x Molar volume
7. Room temperature and pressure (r.t.p.) = 24 dm3 mol-1 (25°C and 1 atm) Example: What is the volume of 5.0 mol helium gas at s.t.p.?
Volume of gas = Number of moles x Molar gas volume = 5.0 mol x 24 dm3 mol-1
= 120 dm3
Example: What is the volume of 5.0 mol helium gas at s.t.p.? Volume of gas = Number of moles x Molar gas volume
= 5.0 mol x 22.4 dm3 mol-1 = 112 dm3
9. Mass (g) = Number of moles x Molar mass
10. Number of particles = Number of moles x Avogadro constant 11. Volume (dm3) = Number of moles x Molar volume
Be sure to copy down all these formulae a few times on paper so that you will have a better chance recalling it in the future. Copying them onto a card to bring around will be very helpful.
Empirical and Molecular Formulae
1. Empirical (simplest ratio of atoms of each element that present in the compound) and molecular formulae (actual number of atoms of each element that are present in one molecule of the compound) indicate:
the types of the elements
the symbols of the elements and the ratio of atoms or moles of atoms of each element in a compound. 2. Molecular formula = (empirical formula)n
n is a positive number
Compound Molecular formula n Empirical formula
Carbon dioxide CO2 1 (CO2) = CO2
Ethane CH3 2 (CH3)2 = C2H6
Propene CH2 3 (CH2)3 = C3H6
Glucose CH2O 6 (CH2O)6 = C6H12O6
Quinine C10H12NO 2 C20H24N2O2
3. Chemical formulae for covalent compounds.
Name Chemical
formula
Number of each element
Oxygen gas O2 2 oxygen atoms
Ammonia NH3 1 nitrogen atom and 3
hydrogen atoms
Water H2O 2 hydrogen atoms and 1
oxygen atom 4. Cations are positively-charged ions.
Charge Cations Formula
+1 Ammonium ion NH4+ +1 * Copper(I) ion Cu+ +1 Hydrogen ion H+ +1 Lithium ion Li+ +1 * Nickel(I) ion Ni+ +1 Potassium ion K+ +1 Silver ion Ag+ +1 Sodium ion Na+ +2 Barium ion Ba2+ +2 Calcium ion Ca2+ +2 * Copper(II) ion Cu2+ +2 * Iron(II) ion Fe2+ +2 * Lead(II) ion Pb2+ +2 Magnesium ion Mg2+ +2 * Manganese(II) ion Mn2+ +2 Nickel(II) ion Ni2+ +2 * Tin(II) ion Sn2+ +2 Zinc ion Zn2+ +3 Aluminium ion Al3+ +3 * Chromium(III) ion Cr3+ +3 * Iron(III) ion Fe3+ +4 * Lead(IV) ion Pb4+ +4 * Tin(IV) ion Sn4+
* refer to the Roman numerals
5. Anions are negatively-charged ions.
Charge Anions Formula
-1 Bromide ion Br
--1 Chloride ion Cl
--1 Chlorate(V) ion ClO3
--1 Ethanoate ion CH3COO
--1 Fluoride ion F
--1 Hydride ion H
--1 Hydroxide ion OH
--1 Manganate(VII) ion MnO4
--1 Nitrate ion NO3
--1 Nitrite ion NO2
--2 Oxide ion O
2--2 Carbonate ion CO3
2--2 Chromate(VI) ion CrO4
2--2 Dichromate(VI) ion Cr2O7 2--2 Sulphide ion S 2--2 Sulphate ion SO4 2--2 Sulphite ion SO3 2--2 Thiosulphate ion S2O3 2--3 Nitride ion N 3--3 Phosphate ion PO4 3--3 Phosphite ion PO3
3-6. Chemical formulae for ionic compounds
Name Chemical formula Number of
cation
Number of anion
Zinc chloride ZnCl2 1 Zn2+ 2 Cl
-Copper(II) sulphate CuSO4 2 Cu2+ 2 SO4
2-Aluminium sulphate Al2(SO4)3 2 Al3+ 3 SO4
2-7. Meaning of prefixes Prefix Meaning Mono- 1 Di- 2 Tri- 3 Tetra- 4 Penta- 5 Hexa- 6 Hepta- 7 Octa- 8 Nona- 9 Deca- 10
8. Naming of chemical (non-metal) compounds with Greek numerical prefixes. Non-metal compound Chemical formula
Carbon monoxide CO Carbon dioxide CO2 Sulphur dioxide SO2 Sulphur trioxide SO3 Carbon tetrachloride (tetrachloromethane) CCl4
So, do come back for more Chemistry Essential Notes. If it is not simplified to its essense, then it is not from Study Very Very Easy. Let us do the summarising while you understand the core before you master the whole topic. Do share out this site with your friends.
Chemical Equation
1. Importance of chemical equation:
The types of reactants; the physical conditions; the quantity of reactants and products and stated in moles.
nA + nB –> pC + pD
2. Reactants are written in the left side of the reaction and products are written in the right side of the reaction.
Example 1:
Word equation: Sodium hydroxide + sulphuric acid –> sodium sulphate + water Chemical equation: NaOH + H2SO4 –> Na2SO4 + H2O
Balancing equation: 2NaOH + H2SO4 –> Na2SO4 + 2H2O
Complete chemical equation: 2NaOH + H2SO4 –> Na2SO4 + 2H2O
Example 2:
Word equation: Aluminium + copper(II) oxide –> aluminium(III) oxide + copper Chemical equation: Al + CuO –> Al2O3 + Cu
Balancing equation: 2Al + 3CuO –> Al2O3 + 3Cu
Complete chemical equation: 2Al + 3CuO –> Al2O3 + 3Cu
Example 3:
Word equation: Nitrogen + hydrogen <–> ammonia Chemical equation: N2 + H2 <–> NH3
Balancing equation: N2 + 3H2 <–> 2NH3
Complete chemical equation: N2 + 3H2 <–> 2NH3
3. Information obtainable from chemical equations. i) mass of reactants
ii) volume of reacting gas iii) mass of products formed iv) volume of gas produced Example:
2 cm3 of lead (II) nitrate solution is added to excess of potassium iodide solution. How many molecules of potassium nitrate will be formed?
[Relative atomic mass: N, 14; O, 16; K, 39; I, 127; Pb, 207; Avogadro's constant: 6.02 x 1023 mol-1]
Step 1: Write a complete chemical equation.
Pb(NO3)2(aq) + 2KI(aq) –> PbI2(s) + 2KNO3(aq)
From the equation, 1 mole of Pb(NO3)2 reacts with 2 moles of KI formed 1 mole PbI2
of and 2 moles of KNO3.
Step 2: Convert to moles.
No. of moles of Pb(NO3)2
= Mass of Pb(NO3)2 / Relative molecular mass
= 2 / [207 + 2(14 + 3 x 16)] = 6.04 x 10-3 mol
Step 3: Ratio of moles.
Number of moles of KNO3/ Number of moles of Pb(NO3)2
= 2/1
Number of moles of KNO3
= (2 x 6.04 x 10-3) / 1 = 12.08 x 10-3 mol
Step 4: Convert to the number of molecules of potassium nitrate. Number of molecules of KNO3
= 12.08 x 10-3 x 6.02 x 1023 = 7.27 x 1021
Once you have completed all parts in this series, you would have mastered the most basic of knowledge in SPM Chemistry. So make sure all Readers understand the basics before moving on to more advance topics.
SPM Chemistry Form 4 Notes – Periodic Table of Elements (Part 1) Development of the Periodic Table
Periodic Table
A) Antoine Lavoisier (1743 – 1794) – French chemist Elements were classified into 4 groups
Limitation – some wrong information (light and heat were consider as elements B) Johann Dobereiner (1780 – 1849) – German chemist
Elements were classified into groups named as triad (Triad Law – relationship between properties and atomic masses of the elements)
Limitation – few elements were classified C) John Newlands (1837 – 1898) – British chemist
Elements were arranged horizontally in ascending order of their atomic masses and each row consisted of 7 elements (Law of Octaves – same properties were repeated at every eight element)
Limitation – obeyed by the first 17 elements only (from H to Ca) D) Lothar Meyer (1830 – 1895) – German chemist
Properties of the elements were in a periodic pattern with their atomic masses Similar chemical properties occupied the same relative positions on the curve E) Dmitri Mendeleev (1834 – 1907) – Russian chemist
Elements were arranged in ascending order of their atomic masses Elements with similar chemical properties were placed in a group Gap for undiscovered elements
Prediction: gallium, scandium and germanium (discover later) Separate groups for certain elements: transition elements
Meedeleev’s Periodic Table was used as a basis for the formation of the Periodic Table
F) H. J. G. Moseley (1887 – 1915) – British physicist
Elements were arranged horizontally in ascending order – proton numbers Elements with the same number valence electrons – same group
18 vertical columns – Group 1, Group 2, until Group 18 Alkali metal – Group 1
Alkaline earth metal – Group 2
Transition elements – Group 3 to Group 12 Halogen – Group 17
Noble gas – Group 18
Horizontal row of the elements – period Period 1 – 2 elements
Period 2 and 3 – 8 elements Period 4 and 5 – 18 elements Period 6 – 32 elements Period 7 – 27 elements
Lantanides – proton numbers 58 to 71 Actinides – proton numbers 90 to 103 Elements (Group 1, 2 and 13) – metal Transition elements (Group 3 to 12) – metal Elements (Group 15, 16 and 17) – non-metal Carbon and silicon (Group 14) – non-metal
The next part, Part 2 Notes on Periodic Table of Elements for SPM Chemistry students will focus on the relationship between electron arrangement of the atom of an element to
its group and period. It’s easy for a Form 5 student when they look back but rather difficult
for a Form 4 student. So Form 4 students need to pay full attention when your teacher is teaching this part, or you can always refer back to Berry Berry Easy for our notes