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http://dx.doi.org/10.12988/ams.2016.512746

Intersections among P

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(1, 5)-Designs

Mario Gionfriddo and Salvatore Milici

Department of Mathematics and Computer Sciences University of Catania, Catania, Italy

Copyright c⃝ 2016 Mario Gionfriddo and Salvatore Milici. This article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.

Abstract

A path-hypergraph P(3)(1, 5) is the uniform hypergraph of rank 3, having five vertices and two edges with exactly one vertex in common. In this paper, the intersection problem among P(3)(1, 5)-designs of order v is studied, determining the intersection-set J (v) for every admissible v.

Nathematics Subject Classification: 05B05, 05C05 Keywords: Hypergraph P(3)(1, 5); Hypergraph Designs

1

Introduction

Let Kv(3) = (X,E) be the complete hypergraph, uniform of rank 3, defined in

a vertex set X = {x1, x2, ..., xv}. This means that E = P3(X), the family of

all 3-subsets of X. Let H(3) be a subhypergraph of K(3)

v .

An H(3)-design, or an H(3)-decomposition of Kv(3), is a pair Σ = (X,B),

where B is a partition of the edge-set P3(X) of K

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v into subsets all of which

yields subhypergraphs isomorphic to H(3). The order v of an H(3)-design Σ =

(X,B) is the cardinality of |X|. The hypergraphs belonging to B are called the blocks of Σ. If H(3) = K(3)

4 , an H(3)-design is a Steiner Quadruple System.

Two H(3)-designs Σ

1 = (X,B1) and Σ2 = (X,B2), defined on the same

set X, are said to have intersection in k blocks provided |B1 ∩ B2| = k. If

k = 0, Σ1 and Σ2 are said disjoint. The intersection problem for Steiner

systems has been studied by C.C.Lindner and A.Rosa for ST Ss [19], while M.Gionfriddo and C.C.Lindner studied intersections among SQSs [17]. Other

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We recall that there exists an 1-factorization F = {F1, F2, ..., Fv−1} of the

complete graph Kv defined in X (or simply an 1-factorization of X), into the

1-factors F1, F2, ..., Fv−1, if and only if v is even. In the case v odd, v = 2k + 1,

there exists a partitionF∗of the edge-set of Kv into 2k +1 classes F1, F2, ..., Fv,

such that every class contains k pairwise disjoint edges and, for every xi ∈ X,

i = 1, 2, ..., v, the vertex-set of Fi is X − {xi}. When v is odd, we call the

partition F∗ an 1-factorization of Kv (of X), into the 1-factors F1, F2, ..., Fv.

In this paper we study the intersection problem for P(3)(1, 5)-designs, where

P(3)(1, 5) = (V,E) is the path-hypergraph, having 5 vertices, 2 triples as edges,

and exactly one vertex in common between the two triples of E. In other

words, if V = {x, y1, y2, y3, y4}, then E = {{x, y1, y2}, {x, y3, y4}}. In what

follows, such a hypergraph will be indicated by [y1, y2, (x), y3, y4] [1]. Further,

to be clear, we will call 3-edges the triples of E and edges the pairs contained

in the triples ofE.

Observe that the spectrum of P(3)(1, 5)-designs has already known. It has

been determined in [3], where it is proved that:

Theorem 1.1 : There exists a P(3)(1, 5)-design of order v if and only if v

0, 1, 2 (mod 4), v≥ 5.

Following the same symbolism and terminology of [1][5][15][17], if v is an

admissible value for the existence of a P(3)(1, 5)-design, it will be:

- pv = v(v− 1)(v − 2)/12: number of blocks of any P(3)(1, 5)-design;

- I(v) = {0, 1, 2, ..., pv − 2, pv}: set of all the possible values k for which

there exist two P(3)(1, 5)-designs having exactly k blocks in common;

- J (v): set of all h ∈ N for which there are two P(3)(1, 5)-design-designs

having exactly k blocks in common.

Note that it is always: pv − 1 /∈ J(v), pv ∈ J(v), J(v) ⊆ I(v). Further,

consider that in [15] the following results are proved:

Theorem 1.2 : J (5) ={1, 5} = I(5)−{0, 2, 3}, J(6) = {0, 1, 2, 3, 4, 5, 6, 7, 8, 10} = I(6), J (8) ={0, 1, 2, ..., 26, 28} = I(8).

2

Construction v = 4h

−→ v

= 4h + 4

In this section we describe a construction v = 4h−→ v′ = 4h + 4, by which we

will study the intersections among P(3)(1, 5)-designs having order a multiple

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Construction v = 4h−→ v′ = 4h + 4

Let Σ = (X,B) be a P(3)(1, 5)-design of order v = 4h, for any h∈ N, h ≥ 2,

defined in X ={1, 2, ..., v}. Further, let Y = {A, B, C, D} be a set such that

X∩ Y = ∅. Define the following families of P(3)(1, 5)s. 1) Family ∆ - Blocks of type ∆:

∆(1) ={[C, D, (A), 1, B], [A, D, (B), 1, C], [A, B, (C), 1, D], [B, C, (D), 1, A], [A, C, (1), B, D]};

and, for every x∈ X − {1}:

∆(x) ={[A, B, (x), C, D], [A, C, (x), B, D], [A, D, (x), B, C]}.

Further: ∆ =∪x∈X∆(x).

2) Family Ω - Blocks of type Ω:

Consider a factorizationF = {F1, F2, ..., F4h−1} of K4hdefined in X. Since,

for every i = 1, 2, ..., 4h− 1, every factor Fi ∈ F has cardinality 2h, it is

pos-sible to define in each of them a partition Πi ={Bi,1, Bi,2, ..., Bi,h−1, Bi,h}, in

which every class Bi,j has cardinality 2. Let:

Bi,1 ={{xi,1, yi,1}, {zi,1, ti,1}},

Bi,2 ={{xi,2, yi,2}, {zi,2, ti,2}},

...

Bi,h ={{xi,h, yi,h}, {zi,h, ti,h}}.

For every y∈ Y = {A, B, C, D} and for every i = 1, 2, ..., 4h − 1, define the

following families of P(3)(1, 5)s.

Ω(y, i):

[xi,1, yi,1, (y), zi,1, ti,1], [xi,2, yi,2, (y), zi,2, ti,2],

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[xi,h−1, yi,h−1, (y), zi,h−1, ti,h−1], [xi,h, yi,h, (y), zi,h, ti,h].

Further: Ω(y) =∪4hi=1−1Ω(y, i) and Ω =∪y∈YΩ(y).

If X′ = X ∪ Y , B′ = B ∪ ∆ ∪ Ω, we can verify that Σ′ = (X′,B′) is a

P(3)(1, 5)-design of order v′ = 4h + 4.

Constructions v→ v + 1, for v ≡ 0 or 1 mod 4

Let Σ = (X,B) be a P(3)(1, 5)-design of order v = 4h≥ 8 or v = 4h+1 ≥ 5,

defined in X = {1, 2, ..., v}. Further, let A be a vertex not belonging to

X. Define in X a factorization F = {F1, F2, ..., F4h−1} of K4h [respectively G = {G1, G2, ..., G4h+1} of K4h+1 in the case v = 4h + 1]. Observe that,

for every i = 1, 2, ..., 4h− 1 [resp. i = 1, 2, ..., 4h + 1], every factor Fi ∈ F

[Gi ∈ G] has cardinality 2h. Therefore, we can consider a partition Πi =

{Bi,1, Bi,2, ..., Bi,h−1, Bi,h}, in which every class Bi,j has cardinality 2 and

de-fine the families Ω(A, i), Ω(A), Ω, as in the previous Construction v→ v+4. If

X′ = X∪ Y , B′ =B ∪ Ω, we can verify that Σ′ = (X′,B′) in a P(3)(1, 5)-design

of order v′ = 4h + 1 [resp. 4h + 2].

Observe that the families ∆ and Ω, in both Constructions, generate com-binatorial structures in X, in which “for every triple of vertices x, y, z there

exists at most one block P(3)(1, 5) containing them as 3-edge”.

Usually, these structures are called partial designs. Therefore, the fami-lies ∆, Ω generate partial P(3)(1, 5)-designs. Further, if Σ = (V,C), Σ′′ =

(V,C′′) are two partial P(3)(1, 5)-designs, both defined in V , such that a triple

{x, y, z} ⊆ V is a 3-edge of a block C ∈ C′ if and only if {x, y, z} is a 3-edge

of a block C∈ C′′, then we say that Σ′, Σ′′ are mutually balanced.

3

Ω - Partial P

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(1, 5)-designs

In this section we determine all the possible intersections among mutually

bal-anced partial P(3)(1, 5)-designs of type Ω. We will indicate by:

- Jv(Ω) the set of all possible integers r such that there exist two mutually

balanced partial P(3)(1, 5)-designs of type Ω, defined on v = 4h or v = 4h + 1

vertices, having exactly r blocks in common;

- and Jv(Ω, y) the set of all possible integers r such that there exist two

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v = 4h + 1 vertices, containing in the central position the vertex y and having

exactly r blocks in common.

Theorem 3.1 : J4h(Ω, y) ={0, 1, 2, ..., 4h2− h − 2, 4h2− h}, for every h ≥ 2.

Proof. Let h be a positive integer, h ≥ 3. Of course, 4h2 − h ∈ J

4h(Ω, y).

Fixed any index i = 1, 2, ..., 4h− 1 and a vertex y ∈ Y = {A, B, C, D}, let

Ω(y, i, j) be the family of P(3)(1, 5)s, where j = 1, 2, ..., h, having the blocks: [xi,1, yi,1, (y), zi,1, ti,1], [xi,2, yi,2, (y), zi,2, ti,2], ...

..., [xi,j, yi,j, (y), zi,j, ti,j],

[xi,j+1, yi,j+1, (y), zi,j+2, ti,j+2], [xi,j+2, yi,j+2, (y), zi,j+3, ti,j+3], ...,

[xi,h−1, yi,h−1, (y), zi,h, ti,h], [xi,h, yi,h, (y), zi,j+1, ti,j+1].

We can observe that the families Ω(y, i) and Ω(y, i, j) have exactly the same first j blocks in common (the others are all different). It follows that, for every

i = 1, 2, ..., 4h− 1, it is possible to choose j = 1, 2, ..., h − 2, h in such a way

that:

|Ω(y, 1) ∩ Ω(y, 1)| = 0, 1, 2, ..., h − 2, h; |Ω(y, 2) ∩ Ω(y, 2)| = 0, 1, 2, ..., h − 2, h;

...

|Ω(y, h) ∩ Ω(y, h)| = 0, 1, 2, ..., h − 2, h;

where, for h = 2, we have only 0, 2. Therefore, it is possible to construct

two mutually balanced partial P(3)(1, 5)-designs of type Ω, having exactly k

blocks in common, for every k = 0, 1, 2, ..., h(4h− 1) − 2, h(4h − 1). Hence

J4h(Ω, y) ={0, 1, 2, ..., 4h2− h − 2, 4h2− h}. 2

Theorem 3.2 : J4h+1(Ω, y) ={0, 1, 2, ..., 4h2+h−2, 4h2+h} for every h ≥ 2.

Proof. Following the same proof of he previous Theorem, we arrive to the

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In this section we determine all the possible intersections among mutually

bal-anced partial P(3)(1, 5)-designs of type Ω. We will indicate by:

- Jv(∆) the set of all possible integers r such that there exist two mutually

balanced partial P(3)(1, 5)-designs of type ∆, defined on v vertices, having

ex-actly r blocks in common;

- and Jv(∆, x) the set of all possible integers r such that there exist two

mutu-ally balanced partial P(3)(1, 5)-designs of type ∆, defined on v vertices, contain-ing in the central position the vertex x and havcontain-ing exactly r blocks in common.

Theorem 4.1 : {0, 2, 4, 6, ..., 12h − 6, 12h + 2} ⊆ J4h(∆).

Proof. Of course, 12h + 2∈ J4h(Ω). Let x′, x′′ ∈ X. From the Construction v → v + 4, for x′, x′′∈ X − {1, 2} let

∆(x′, x′′) = ∆(x′)∪∆(x′′) ={[A, B, (x′), C, D], [A, C, (x′), B, D], [A, D, (x′), B, C], [A, B, (x′′), C, D], [A, C, (x′′), B, D], [A, D, (x′′), B, C]}.

If: 1) ∆0(x′, x′′) = {[x′, B, (A), x′′, C], [x′, C, (D), x′′, B], [x′, C, (A), x′′, D], [x′, D, (B), x′′, C], [x′, D, (A), x′′, B], [x′, B, (C), x′′, D]}; 2) ∆2(x′, x′′) = {[x′, B, (A), x′′, C], [x′, C, (D), x′′, B], [x′, C, (A), x′′, D], [x′, D, (B), x′′, C], [A, C, (x′′), B, D], [A, D, (x′′), B, C]}; 3) ∆3(x′, x′′) = {[x′, B, (A), x′′, C], [x′, C, (D), x′′, B], [A, D, (x′), B, C],

[A, B, (x′′), C, D], [A, C, (x′′), B, D], [A, D, (x′′), B, C]}; then we can verify that:

|∆(x′, x′′)∩ ∆ 0(x′, x′′)| = 0; |∆(x′, x′′)∩ ∆ 2(x′, x′′)| = 2; |∆(x′, x′′)∩ ∆ 4(x′, x′′)| = 4; further |∆(x′, x′′)∩ ∆(x′, x′′)| = 6.

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If we partition X− {1, 2} in 2h − 1 pairs and exchange in ∆(1) and ∆(2)

the vertices 1 and 2, we can define two mutually balanced partial P(3)(1,

5)-designs, one of them of type ∆, having exactly k blocks in common, for every

k = 0, 2, 4, 6, ..., 12h− 6. 2

5

Main results

In this section we determine J (v) for P(3)(1, 5)-designs.

Theorem 5.1 : For P(3)(1, 5)-designs of order v = 4h, h ≥ 2, it is J(v) = I(v) ={0, 1, 2, ..., pv − 2, pv}.

Proof. In [15] it is proved that J (8) = I(8) = {0, 1, 2, ..., 26, 28}. Let Σ = (X,B) be a P(3)(1, 5)-design of order v = 4h, h≥ 2, and let Σ = (X,B) be a

P(3)(1, 5)-design of order v = 4h + 4, obtained by a construction v −→ v + 4,

described in Section 2. Observe that: 1)B′ =B ∪ ∆ ∪ Ω;

2)B, ∆ and Ω generate in Σ three partial P(3)(1, 5)-designs, without blocks

in common, such that:

|B| = pv =

4h(4h− 1)(4h − 2)

3 , |∆| = p= 12h + 2, |Ω| = p= h(4h− 1); 3) if C′,C′′ are two mutually balanced partial P(3)-designs, defined in the

same vertex set contained in X′ and C′ ⊆ B′, then Σ′′ = (X′,C′′), where

C′′ =B− C∪ C′′, is a P(3)-design of order v′′= 4h + 4.

Now, use 3) taking C′,C′′ both of type ∆, or both of type Ω, or both of

type ∆ and Ω together. By the results of Theorems 3.1, 4.1, we can determine

J (v).

Therefore, let Σ1 = (X,B1),Σ2 = (X,B2) be two P(3)(1, 5)-designs of order v = 4h, h ≥ 2, and let Σ′1 = (X′,B1),Σ2 = (X′,B′2) be two P(3)(1, 5)-designs

of order v = 4h + 4 obtained by Construction v = 4h → v + 4, with X′ =

X∪ {A, B, C, D}, B′1 =B1∪ ∆1∪ Ω1 and B′2 =B2∪ ∆2∪ Ω2.

Further, let |B1∩ B2| = r, |∆1∩ ∆2| = s, |Ω1∩ Ω2| = t.

Fixed Σ1 = (X′,B′1), by Theorems 3.1,4.1, it is possible to define Σ2 =

(X′,B2′) such that r ∈ J(v) and s = t = 0. This implies that J(v) ⊆ J(v +

4). Further, it possible to define Σ2 such that B1 = B2, so r = h(4h

1)(4h− 2)/3, s = 0, 2, 4, ..., 12h − 6 and t = 0, 1. It follows that for every

u = 0, 1, 2, 3, ..., 12h− 5

h(4h− 1)(4h − 2)

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∪ J4h ⊆ J(v + 4).

To conclude, we observe that it possible to define Σ2 such that B1 = B2,

∆1 = ∆2, so r = h(4h− 1)(4h − 2)/3, s = 12h + 5, and t ∈ J4h(Ω). Thus, the

statement is proved. 2

Theorem 5.2 : For P(3)(1, 5)-designs of order v = 4h + 1, h ≥ 2, it is J (v) = I(v) ={0, 1, 2, ..., pv− 2, pv}.

Proof. In [15] it is proved that J (8) = I(8) ={0, 1, 2, 3, ..., 28, 30}. Let Σ = (X,B) be a P(3)(1, 5)-design of order v = 4h, h≥ 2, and let Σ′ = (X′,B′) be a

P(3)(1, 5)-design of order v = 4h + 1, obtained by a construction v −→ v + 1,

described in Section 2. Following the same technique used in Theorem 5.1, we

can arrive the a similar conclusion and prove the statement. 2

Theorem 5.3 : For P(3)(1, 5)-designs of order v = 4h + 2, h ≥ 1, it is J (v) = I(v) ={0, 1, 2, ..., pv− 2, pv}.

Proof. In the Theorem 5.2 it is proved that J (9) = I(9) ={0, 1, 2, 3, ..., 40, 42}.

Let Σ = (X,B) be a P(3)(1, 5)-design of order v = 4h + 1, h ≥ 2, and let

Σ = (X′,B′) be a P(3)(1, 5)-design of order v′ = 4h + 2, obtained by a

con-struction v −→ v + 1, described in Section 2. Also in this case, following the

same technique used in Theorem 5.1, we can prove the statement. 2

Collecting together Theorems 5.1, 5.2, 5.3, and considering Theorem 1.2 proved in [15], it follows that:

Theorem 5.4 : For P(3)(1, 5)-designs of any admissible order v it is J (v) = I(v) ={0, 1, 2, ..., pv − 2, pv}, for v ≥ 6 and J(5) = {1, 5} = I(5) − {0, 2, 3}

Acknowledgements. The present research has been supported by

MIUR-PRIN(2012), INDAM-GNSAGA.

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