CHARACTER VALUES AND DADE’S CONJECTURE
Full text
Now we mention some notations used in this paper. We denote by N : G = NoG and N.G a split and non-split extention of N by G, respectively. We use n to denote a group of order n, and Z n to denote a cyclic group of order n. For a prime p, an elementary abelian group of order p n is denoted by E pn
Throughout the paper, a character means an irreducible complex character. Let G be a finite group and H a subgroup of G. When a prime p is fixed, for a positive integer n, we denote by n p the p-part of n, and by n p0
(|H|/χ(1)) p0
|G|-th root of unity. Let e be a non-negative integer and let σ ∈ Gal(Q(ζ |G| )/Q) be any Galois automorphism sending every p 0 -root of unity ζ to ζ pe
Conjecture 1.4. Let G be a finite group of order n with O p (G) = 1, p a prime and B a p-block of G with defect d(B) > 0. Let e be a non-negative integer and let σ ∈ Gal(Q n /Q) be any Galois automorphism sending every p 0 -root of unity ζ to ζ pe
such that F(χ σ ) = F(χ) σ for all χ ∈ Irr(B), and that F sends exceptional (resp. non- exceptional) characters of B onto exceptional (resp. non-exceptional) characters of b. By [15, Theorem(2.1)] of Isaacs and Navarro and [8, Proposition 2.1] of An and O’Brien, a bijection which sends exceptional (resp. non-exceptional) characters of B onto exceptional (resp. non-exceptional) characters of b preserves the defects and ±(|G|/χ(1)) p0
For a prime p which divides n and a non-negative integer e, we have σ t (ζ np0
⇔ t ≡ p e (mod n p0
t = p e + r · n p0
1 ≤ t ≤ n , r · n p0
i f e = 0, t = p e + r · n p0
! . Furthermore, let m = q e 11
Let N = q e 00
(G)/G (−1) |C| k(N G (C), B, d, [κ], σ t ) .
k(N G (C 1 ), B 0 , d, [1], σ ti
k(N G (C 2 ), B 0 , d, [1], σ ti
k(N G (C 3 ), B 0 , d, [1], σ ti
k(N G (C 4 ), B 0 , d, [1], σ ti
(d) (6) (5) (4) (3) (2) Parity k(N G (C 1 ), B 0 , d, [1], σ t1
k(N G (C 1 ), B 0 , d, [1], σ t2
(d, t i ) (3, t 1 ) (2, t 1 ) (3, t 2 ) (2, t 2 ) Parity k(N G (C 1 ), B 0 , d, [1], σ ti
Let t 1 and t 2 be such that e is even and odd, respectively, in the condition (3.1) in §3. Then the value of k(N G (C), B 0 , d, [κ], σ t1
for every C and d. Thus the result follows from [10, Theorem 10.1]. For σ t2
k(N G (C 1 ), B 0 , d, [1], σ t2
(d) (7) (6) (5) (4) (3) Parity k(N G (C 1 ), B 0 , d, [1], σ t2
Let t 1 and t 2 be such that e is even and odd, respectively, in the condition (3.1) in §3. Then the value of k(N G (C), B 0 , d, [κ], σ t1
for every C and d, and thus the result follows from [14, Theorem 2]. For σ t2
(d) (7) (6) (5) (4) (3) (2) Parity k(N G (C 1 ), B 0 , d, [1], σ t1
(d) (7) (6) (5) (4) (3) (2) Parity k(N G (C 1 ), B 0 , d, [1], σ t2
(d, t i ) (3, t 1 ) (2, t 1 ) (3, t 2 ) (2, t 2 ) Parity k(N G (C 1 ), B 0 , d, [1], σ ti
(d, t i ) (3, t 3 ) (2, t 3 ) (3, t 4 ) (2, t 4 ) Parity k(N G (C 1 ), B 0 , d, [1], σ ti
k(N G (C 1 ), B 0 , d, [κ], σ ti
k(N G (C 2 ), B 0 , d, [κ], σ ti
k(N G (C 3 ), B 0 , d, [κ], σ ti
k(N G (C 4 ), B 0 , d, [κ], σ ti
= −1 and e is odd in the condition (3.1) in §3. Then the value of k(N G (C), B j , d, [κ], σ t1
(d) (9) (8) (7) (6) (5) (4) Parity k(N G (C 1 ), B 0 , d, [1], σ t2
(d) (9) (8) (7) (6) (5) (4) Parity k(N G (C 1 ), B 0 , d, [1], σ t3
(d) (9) (8) (7) (6) (5) (4) Parity k(N G (C 1 ), B 0 , d, [1], σ t4
Let t 1 and t 2 be such that e is even and odd, respectively, in the condition (3.1) in §3. Then the value of k(N G (C), B 0 , d, [κ], σ t1
for every C and d, and thus the result follows from [17, Theorem 2.10.1]. For σ t2
(d, [κ]) (3, [1]) (3, [2]) (2, [1]) (2, [2]) Parity k(N G (C 1 ), B 0 , d, [κ], σ t1
(d, [κ]) (3, [1]) (3, [2]) (2, [1]) (2, [2]) Parity k(N G (C 1 ), B 0 , d, [κ], σ t2
k(N G (C 2 ), B 0 , d, [κ], σ t2
k(N G (C 3 ), B 0 , d, [κ], σ t2
k(N G (C 4 ), B 0 , d, [κ], σ t2
(d) (7) (6) (5) (4) (3) Parity k(N G (C 1 ), B 0 , d, [1], σ t2
k(N G (C 1 ), B 0 , d, [1], σ ti
k(N G (C 2 ), B 0 , d, [1], σ ti
k(N G (C 3 ), B 0 , d, [1], σ ti
k(N G (C 4 ), B 0 , d, [1], σ ti
k(N G (C 1 ), B 0 , d, [1], σ ti
k(N G (C 2 ), B 0 , d, [1], σ ti
k(N G (C 3 ), B 0 , d, [1], σ ti
k(N G (C 4 ), B 0 , d, [1], σ ti
k(N G (C 1 ), B 0 , d, [1], σ ti
k(N G (C 2 ), B 0 , d, [1], σ ti
k(N G (C 3 ), B 0 , d, [1], σ ti
k(N G (C 4 ), B 0 , d, [1], σ ti
k(N G (C 1 ), B 0 , d, [1], σ ti
k(N G (C 2 ), B 0 , d, [1], σ ti
k(N G (C 3 ), B 0 , d, [1], σ ti
k(N G (C 4 ), B 0 , d, [1], σ ti
k(N G (C 1 ), B 0 , d, [1], σ ti
k(N G (C 2 ), B 0 , d, [1], σ ti
k(N G (C 3 ), B 0 , d, [1], σ ti
k(N G (C 4 ), B 0 , d, [1], σ ti
k(N G (C 1 ), B 0 , d, [1], σ ti
k(N G (C 2 ), B 0 , d, [1], σ ti
k(N G (C 3 ), B 0 , d, [1], σ ti
k(N G (C 4 ), B 0 , d, [1], σ ti
T 27. Conjecture 1.4 for M 24 , p = 3 (d) (3) (2) Parity k(N G (C 1 ), B 0 , d, [1], σ t2
= −1. Then the value of k(N G (C), B 0 , d, [κ], σ t1
Let t 1 and t 2 be such that e is even and odd, respectively, in the condition (3.1) in §3. Then the value of k(N G (C), B 0 , d, [κ], σ t1
for every C and d, and thus the result follows from [20, Theorem 4.8.3]. For σ t2
(d) (7) (6) (5) (4) (3) Parity k(N G (C 1 ), B 0 , d, [1], σ t2
= −1 and e is odd in the condition (3.1) in §3. Then the value of k(N G (C), B 0 , d, [κ], σ t1
T 31. Conjecture 1.4 for McL, p = 3 (d) (6) (5) (4) (3) Parity k(N G (C 1 ), B 0 , d, [1], σ t2
(d) (6) (5) (4) (3) Parity k(N G (C 1 ), B 0 , d, [1], σ t3
(d) (6) (5) (4) (3) Parity k(N G (C 1 ), B 0 , d, [1], σ t4
(d, [κ] (3, [1]) (3, [2]) (2, [1]) Parity k(N G (C 1 ), B 0 , d, [κ], σ t1
(d, [κ], t i ) (3, [1]) (3, [2]) (2, [1]) Parity k(N G (C 1 ), B 0 , d, [κ], σ t2
(d, [κ] (3, [1]) (3, [2]) (2, [1]) Parity k(N G (C 1 ), B 0 , d, [κ], σ t3
(d, [κ], t i ) (3, [1]) (3, [2]) (2, [1]) Parity k(N G (C 1 ), B 0 , d, [κ], σ t4
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