R E S E A R C H
Open Access
Two new regularization methods for solving
sideways heat equation
Huy Tuan Nguyen
1*and Vu Cam Hoan Luu
2*Correspondence: [email protected] 1Applied Analysis Research Group, Faculty of Mathematics and Statistics, Ton Duc Thang University, Ho Chi Minh City, Vietnam Full list of author information is available at the end of the article
Abstract
We consider a non-standard inverse heat conduction problem in a bounded domain which appears in some applied subjects. We want to know the surface temperature in a body from a measured temperature history at a fixed location inside the body. This is an exponentially ill-posed problem in the sense that the solution (if it exists) does not depend continuously on the data. In this paper, we introduce the two new classes of quasi-type methods and iteration methods to solve the problem and prove that our methods are stable under botha priorianda posterioriparameter choice rules. An appropriate selection of a parameter in the scheme will get a satisfactory approximate solution. Furthermore, if we use the discrepancy principle we can avoid the selection of thea prioribound.
MSC: 35K05; 35K99; 47J06; 47H10
Keywords: Cauchy problem; sideways heat equation; ill-posed problem; error estimates
1 Introduction
In this paper, we want to determine the surface temperatureu(x,t) for <x<Lfrom well-known temperature measurementsu(L,t) =g(t) whenu(x,t) satisfies the following system:
⎧ ⎪ ⎨ ⎪ ⎩
ut=uxx, <x<L, ≤t≤π, u(L,t) =g(t), ≤t≤π,
u(x, ) = , ≤t≤π.
()
In order to guarantee the uniqueness of the solution, here we assume thatube bounded as
x→+∞. The functionsg,hgiven inL(, π) are to be noised. Physically, we only obtain the measured Cauchy data with measurement errors. This is a severely ill-posed problem: any small perturbation in the observation data can cause large errors in the solutionu(x,t) forx∈[,L). Therefore, most classical numerical methods often fail to give an acceptable approximation of the solution. Thus it requires regularization techniques to stabilize the numerical computations [].
The problem has a long history and has attracted to many authors. In several engineering contexts, it is sometimes necessary to determine the surface temperature and heat flux in a body from a measured temperature history at a fixed location inside the body [, ]. The physical situation at the surface may be unsuitable for attaching a sensor, or the accuracy
of a surface measurement may be seriously impaired by the presence of the sensor. The special case of estimating a surface condition from interior measurements has come to be known as the inverse heat conduction problem (IHCP).
In recent years, IHCP have been researched by many authors and some valuable method are proposed, such as the difference regularization method [], the Fourier method [], quasi-reversibility method [, ], wavelet and wavelet-Galerkin method [], a spectral reg-ularization method [, ],etc.
Most of the papers involving regularization methods for sideways heat are devoted to giving a convergence analysis with the regularization parameter chosen by ana priori
choice rule, under which somea prioriinformation on the unknown exact solution which is to be simulated is often used. However, in general, thea prioriboundMcannot be known exactly in practice, and working with a wrong constantMmay lead to the bad regularized solution. In the present paper, we proposed two new regularization method: a modified quasi-boundary value method and an iteration method for solving Problem (). This method has been used by Deng and Liu to deal with the sideways parabolic equation [], but here we give another way to choose the regularization parameter by ana posteriori
rule. Moreover, we shall give a criterion for making ana posteriorichoice of the regular-ization parameter. To the authors’ knowledge, there are very few papers for choosing the regularization parameter by thea posteriorirule for this sideways heat.
This paper is constructed as follows: in Section , we propose two new regularization method. Convergence estimates under priori and posteriori assumptions are given in Sec-tion and SecSec-tion . Finally, we draw a conclusion to our method.
2 Formulation of the problem and a quasi-boundary value regularization method
Supposeg is for measured data inL(, π) and satisfies
g–gL(,π)≤, ()
where> represents a noisy level. Forf ∈L(, π), we have the Fourier series
f(t) =
k∈Z
fkeikt, ()
where the Fourier coefficient is
fk=
π
π
f(t)e–iktdt. ()
The norm off inLis
fL(,π)= π
k∈Z
|fk|. ()
The principal value of√ikis
√
ik=
⎧ ⎨ ⎩
( +i) |k|, k≥, ( –i) |k|, k< .
Suppose that the solution of the problem is represented as a Fourier series
u(x,t) =
k∈Z
uk(x)eikt, ()
with
uk(x) =
π
π
u(x,t)e–iktdt. ()
LetF(x,t) =k∈ZFk(x)eiktwith
Fk(x) =
π
π
F(x,t)e–iktdt. ()
Then by taking the partial derivative with respect totandx, we obtain
ut(x,t) =
k∈Z
uk(x)ikeikt,
uxx(x,t) =
k∈Z d
dxuk(x)e
ikt.
()
The main equationut=uxxleads to
k∈Z
uk(x)ikeikt=
k∈Z
d
dxuk(x)e
ikt.
Combining the Cauchy datag,h, we have the following systems of second ordinary equa-tions:
d
dxuk(x) –ikuk(x) = , uk(L) =gk, ()
where
gk=
g(t),e–ikt= π
π
g(t)e–iktdt.
The solution of () is
uk(x) =Ckexp(
√
ikx) +Dkexp(–
√
ikx). ()
Sinceu(x,t) is bounded whenx→+∞, we conclude thatCk= . It follows fromuk(L) = Dkexp(–
√
ikL) =gkthat
Dk=gkexp(
√
ikL).
This leads to the formula ofuk:
uk(x) =exp
√
The exact form ofuis
u(x,t) =
k∈Z
exp√ik(L–x)g(t),e–ikteikt, ≤x≤L. ()
Lemma For y∈R,we have
e
√
iky=e |k|y. ()
Proof We can rewrite the term|e
√
iky|by
e
√
iky=e(+i) |k|y
=e |k|y
cos
|k|y
+sin
|k|y
=e |k|y. ()
3 Quasi-boundary value method for a sideways heat equation
Define the Sobolev spaceHs(, π) as
u(,t)Hs(,π)=
k∈Z
+ksu(,t),e–ikt.
In this section, we present a QBV regularization problem as follows:
⎧ ⎪ ⎨ ⎪ ⎩
uβt()=u β()
xx , <x<L, ≤t≤π, uβ()(L,t) =Bg(t), ≤t≤π, uβ()(x, ) = , ≤t≤π,
()
with the additive information thatu(x,t) bounded whenx→+∞. AndBis defined as
Bg(t) =
k∈Z
exp(– |k|L)
β() +exp(– |k|L)
g(t),e–ikteikt. ()
3.1 A priori parameter choice rule
Theorem Let u be an exact solution to Problem().Let gbe as in().
() Ifu(,t)L(,π)≤Mthen byβ() =
M,we have
uβ()(x,·) –u(x,·)
L(,π)≤M–
x
L
x L.
() Ifu(,t)Hs(,π)≤Mthen byβ() = k
M, <k< ,we have
uβ()(x,·) –u(x,·)
L(,π)
M
x L
kxL–k+M
A(s)
L
ln(M/)
s
,
where
Proof
Proof of Part. The solution of this regularized problem is
uβ()(x,t) =
k∈Z
exp(– |k|L)exp(√ik(L–x))
β() +exp(– |k|L)
g(t),e–ikteikt. ()
Letvβ()obey
vβ()(x,t) =
k∈Z
exp(– |k|L)exp(√ik(L–x))
β() +exp(– |k|L)
g(t),e–ikteikt.
Step. Estimateuβ()–vβ()
L(,π).
We have
uβ()–vβ()L(,π) = π
k∈Z
exp(– |k|L) β() +exp(– |k|L)
exp√ik(L–x)
×g(t) –g(t),e–ikt
= π
k∈Z
exp(–√|k|x)
[β() +exp(– |k|L)]
g(t) –g(t),e–ikt
≤β()Lx–g(t) –g(t)
L(,π)≤β() x
L–. ()
This implies that
uβ()–vβ()L(,π)≤β()
x
L–=M–xLLx. ()
Step. Estimatevβ()–u
L(,π). Using u(,t),e–ikt=exp(
√
ikL)g(t),e–ikt, we have
vβ()–uL(,π) = π
k∈Z
β()exp( |
k| L)
+βexp( |k|L)
exp√ik(L–x)g(t),e–ikt
= π
k∈Z
β|exp(–√ikx)|
[β() +exp(– |k|L)]
u(,t),e–ikt
=β()π
k∈Z
exp(– |k|
x)
β() +exp(– |k|L)
u(,t),e–ikt
≤β()β()Lx–u(,t)
L(,π)≤β() x
LM. ()
Fromβ() =
M, we obtain vβ()–uL(,π)≤ x
This implies that
vβ()–uL(,π)≤M–
x
LxL. ()
Combining () and (), we obtain
uβ()–u
L(,π)≤uβ()–vβ()L(,π)+vβ()–uL(,π)≤M–
x
L
x L.
Proof of Part.
Lemma Let s> ,X≥.Then for <β< ,we have
β
( + |k|)s(β+exp(– |k|
L))
≤sse–s +L–s L
ln(/β)
s
.
Proof
Case. |k|∈[,L]. It is clear to see that
β
( + |k|)s(β+exp(– |k|
L))
≤ β
( + |k|)sexp(– |k|
L)
≤βexp
|
k|
L
≤eβ.
From the inequalityβ≤(se)s(
ln(/β))s, we get
β
( + |k|)s(β+exp(– |k|
L))
≤sse–s +L–s L
ln(/)
s
. ()
Case. |k|>L. SetY=exp(– |k|
L)
β . Then we obtain
β
( + |k|)s(β+exp(– |k|
L))
= β
β+βY
L L–ln(βY)
s
= +Y
L L–ln(βY)
s
= +Y
L
ln(/β)
s
–ln(β)
L–ln(βY)
s
=
L
ln(/β)
s
+Y
–ln(β)
L–ln(βY)
s
. ()
We continue to estimate the term +Y(L––ln(ln(ββY)))s.
If <Y≤ then < –ln(β) < –ln(βY), thus
+Y
–ln(β)
L–ln(βY)
s
else ifY> thenlnY> andln(βY) = –L |k|< – due to the assumption |k|∈(L,∞). ThereforelnY( +ln(βY))≤. This implies that
< –lnβ
L–ln(βY)< –lnβ
–ln(βY)< +lnY.
Hence, in this case, we get
+Y
–ln(β)
L–ln(βY)
s
<( +lnY)
s
Y = ( +lnY) sY–.
Setg(Y) = ( +lnY)sY–forY>e–. Taking the derivative of this function, we get
g(Y) = ( +lnY)s–Y–(s– –lnY).
The function g has a maximum at the point Y such thatg(Y) = . This implies that
Y=es–. And therefore
sup
Y≥
( +lnY)sY–≤g(Y) =sse–s. ()
Since () and () hold, we have
+Y
–ln(β)
L–ln(βY)
s
≤sse–s.
From (), we get
β
( + |k|)s(β+exp(– |k|
L)) ≤sse–s
T
ln(/β)
s
≤sse–s +T–s T
ln(/β)
s
. ()
We have
v–uL(,π)
= π
k∈Z
βexp(– |k|
x)
β+exp(– |k|L)
u(,t),e–ikt
≤π
k∈Z
β
( + |k|)s(β+exp(– |k| L))
+
|k|
s
u(,t),e–ikt
≤(s)se–s +L–s
L
ln(/β)
s
π
k∈Z
+
|k|
s
u(,t),e–ikt
≤s(s)se–s +L–s
L
ln(/β)
s
π
k∈Z
+ksu(,t),e–ikt
≤A(s)
L
ln(/β)
s
where
A(s) = s(s)se–s +L–s.
This leads to
vβ()–u
L(,π)≤A(s)
L
ln(/β)
s
u(,t) Hs(,π)
≤MA(s)
L
ln(/β)
s
. ()
Combining () and (), we obtain
uβ()–uL(,π)≤u
β()–vβ()
L(,π)+v
β()–u
L(,π)
≤β()xL–+MA(s)
L
ln(/β)
s
.
3.2 A posteriori parameter choice rule
Theorem Suppose that <<g
L(,π).Choose m> such that
<m<g L(,π).
Then there exists a unique numberβ()such that
uβ()(L,t) –gL(,π)=m. ()
Furthermore,ifu(,t)L(,π)≤M then byβ() =
M,we have the following estimate:
uβ()(x,·) –u(x,·)L(,π)≤
m m– M
–Lx
(m+ )
x L.
Proof The following results are straightforward.
Lemma Setρ(β) =uβ()(L,t) –g
L(,π).If <<gL(,π)thenρis a continuous
strictly increasing function and satisfies
(a) limβ→ρ(β) = ,
(b) limβ→+∞ρ(β) =gL(,π).
From this lemma, it follows that there exists a unique numberβ() satisfying (). Setzβ()(x,t) =u(x,t) –uβ()(x,t). Thenzβ()satisfies the heat equation
ztβ()=zβxx(). ()
From the formula ofuanduβ(), we get
zβ()(x,t) =uβ()(x,t) –u(x,t) =
k∈Z
exp√ik(L–x)Rk
where
Rk
β,g,g=
exp(– |k|L)
β() +exp(– |k|L)
g(t),e–ikt–g(t),e–ikt.
Then using the Hölder inequality, we get
zβ()(x,t)L(,π) =
k∈Z
exp|k|L
–x
L
Rk
β,g,g–LxR k
β,g,gLx
≤
k∈Z
exp|k|L
–x
L
Rk
β,g,g–Lx
–xL–
x L
×
k∈Z Rk
β,g,g
x
L
x L
x L
=
k∈Z
exp|k|LRk
β,g,g
–xL
k∈Z
Rk
β,g,g x
L
=zβ()(,t)–
x L L(,π)z
β()(L,t)Lx L(,π).
This implies that
zβ()(x,t)L(,π)≤z
β()(,t)–xL L(,π)z
β()(L,t)xL
L(,π). ()
Proof of Part(a). It is easy to see that
zβ()(L,t)
L(,π) =uβ()(L,t) –u(L,t)L(,π)
≤uβ()(L,t) –gL(,π)+g–g
L(,π)≤(m+ ) ()
and
zβ()(,t)
L(,π)≤u(,t)L(,π)+uβ()(,t)L(,π). ()
We have
m =uβ()(L,t) –g(t)L(,π)
=
k∈Z
β()exp(– |k|L)
+β()exp(– |k|L)
g(t),e–ikteikt L(,π)
≤
k∈Z
β()exp(– |k|L)
+β()exp(– |k|L)
g(t) –g(t),e–ikteikt L(,π)
+
k∈Z
β()
β() +exp(– |k|L)
≤
k∈Z
g(t) –g(t),e–ikteikt L(,π)
+
k∈Z
β()exp
|
k|
L
g(t),e–ikteikt L(,π)
=g–g
L(,π)+β()u(,t)L(,π)
≤+β()u(,t)L(,π).
This implies that
β()≤
m– u(,t)L(,π). ()
It follows from () that
uβ()(,t)
L(,π) =
k∈Z
exp(– |k|L)
β() +exp(– |k|L)
exp(√ikL)g(t),e–ikteikt L(,π)
≤
k∈Z
exp(– |k|L)
β() +exp(– |k|L)
exp(√ikL)g(t) –g(t),e–ikteikt L(,π)
+
k∈Z
exp(– |k|L)
β() +exp(– |k|L)
exp(√ikL)g(t),e–ikteikt L(,π)
≤
k∈Z β()
g(t) –g(t),e–ikteikt L(,π)
+
k∈Z
exp(√ikL)g(t),e–ikteikt L(,π)
≤ β()g
–
gL(,π)+u(,t)L(,π)
≤
β()+u(,t)L(,π). ()
Combining () and (), we obtain
uβ()(,t)L(,π)≤
m– +
u(,t)L(,π)=
m
m– u(,t)L(,π). ()
From () and (), we obtain
zβ()(,t)L(,π)≤
+ m
m–
u(,t)L(,π)=
m–
m– u(,t)L(,π). ()
This together with () and () leads to
zβ()(x,t)L(,π)≤zβ()(,t)
–xL
L(,π)z
β()(L,t)xL L(,π)
≤
m–
m– u(,t)L(,π)
–xL
Hence
u(x,t) –uβ()(x,t)
L(,π)≤
(m– )M m–
–xL
(m+ )LxxL.
4 An iteration regularization method 4.1 A priori parameter choice
To the authors’ knowledge, there are few papers for choosing the regularization parameter bya posteriorirule for the sideways heat equation. In this section, a new regularization method of iteration type for solving this problem will be given. We will use this method solving Problem (), ana priorianda posteriorirule for choosing regularization param-eters and the Hölder-type error estimates are given. To solve the problem, we introduce the following iteration scheme:
un(x,t),e–ikt= ( –h)un–(x,t),e–ikt+hexp√ik(L–x)g(t),e–ikt ()
with initial guess u
(x,t),e–iktand <h=e–L |k|
< , which plays an important role in
the convergence proof. From the formula, it is easy to see that
u
n(x,t),e
–ikt= ( –h)nu
(x,t),e–ikt
+
n–
i=
( –h)ihexp√ik(L–x)g(t),e–ikt
= ( –h)nu(x,t),e–ikt+ – ( –h)nexp√ik(L–x)g(t),e–ikt. ()
Therefore, the approximate solution of Problem () has the following form:
u n(x,t) =
k∈Z
u
n(x,t),e–ikt
eikt. ()
We have the main theorem as follows.
Theorem Let u(x,t)be the exact solution of Problem(),and u
nbe its regularization approximation defined by()with u
(x,t),e–ikt= .Assume thatu(,t)L(,π)≤M
for M> and take n= [M],where[k]denotes the largest integer not exceeding k,then we have the estimate
un(x,·) –u(x,·)L(,π)≤M–
x LLx.
Lemma For≤h≤and n≥,the following inequalities hold:
( –h)nh≤ n+ , – ( –h)n
h ≤n.
Lemma For≤h≤, ≤α≤,and n≥,the following inequalities hold:
( –h)nhα≤
– ( –h)n
hα ≤n
α
.
From u
(x,t),e–ikt= , we see that
un(x,t) =
k∈Z
– ( –h)nexp√ik(L–x)g(t),e–ikteikt.
Letv(x,t) be given by
v n(x,t) =
k∈Z
– ( –h)nexp√ik(L–x)g(t),e–ikteikt.
We divide the argument into two steps.
Step. Estimateu
n(x,·) –vn(x,·)L(,π). We have
un(x,·) –vn(x,·)L(,π)
= π
k∈Z
– ( –h)nexp√ik(L–x)g–g(t),e–ikt
≤πsup
k∈Z
– ( –h)nexp√ik(L–x)
k∈Z
g–g(t),e–ikt
≤πsup
k∈Z
– ( –h)nexp|k|(L–x)g–gL(,π).
It follows fromexp(√|k|(L–x)) =hLx–andg–g
L(,π)≤that
un(x,·) –vn(x,·)L(,π)≤π sup
<h<
– ( –h)nhLx–.
Because of Lemma , we have
un(x,·) –vn(x,·)L(,π)≤n– x
L.
Therefore
un(x,·) –vn(x,·)L(,π)≤n–
x
L. ()
Step. Estimatev
n(x,·) –u(x,·)L(,π). We have
v
n(x,·) –u(x,·)
L(,π) = π
k∈Z
( –h)nexp|k|(L–x)g(t),e–ikt
≤u(,t)L(,π) sup
<h<
( –h)nhLx
≤M(n+ )–Lx.
This implies that
vn(x,·) –u(x,·)L(,π)≤M(n+ )–
x
Combining () and (), we obtain
un(x,·) –u(x,·)L(,π)≤u
(x,·) –v(x,·)L(,π)+v
(x,·) –u(x,·)L(,π)
≤n–xL+M(n+ )–Lx.
Due ton= [M], we haven≤M andn+ ≥M, and therefore
un(x,·) –u(x,·)L(,π)≤M
M
–Lx +
M
–xL
= M–xLxL.
4.2 The discrepancy principle
In this section, we discuss thea posterioristopping rule for iteration scheme () based on ‘discrepancy principle’ of Morozov in the following form:
g(t) –uβ(L,t)L(,π)=m, ()
wherem> is a constant andβdenotes the regularization parameter. If we take u
(x,t),e–ikt= , then () can be simplified to the form
g(t) –u
β(L,t)L(,π)=
k∈Z
g(t),e–ikteikt– k∈Z
– ( –h)βg(t),e–ikteikt L(,π)
=
k∈Z
( –h)βg(t),e–ikteikt L(,π)
=m. ()
We have the main theorem as follows.
Theorem Let u(x,t)be the exact solution of Problem(),and u
nbe its regularization ap-proximation defined by()with u
(x,t),e–ikt= .If the a priori boundu(,t)L(,π)≤
M is valid and the iteration()is stopped by the discrepancy principle(),then
u
β(x,·) –u(x,·)L(,π)≤EM–
x LxL,
where
E= (m+ )xL
m m–
–xL .
The following results are obvious.
Lemma Set P(β) =g(t) –u
β(L,t)L(,π)=( –h)βg(t)L(,π).
Lemma Setting
w β(x,t) =
k∈Z
exp√ik(L–x)g(t),e–ikt– – ( –h)n
the following inequality holds:
wβ(x,t)L(,π)≤wβ(,t)
–xL
L(,π)w
β(L,t)
x L L(,π).
Proof We have
w β(,t) =
k∈Z
exp(√ikL)g(t),e–ikt– – ( –h)nexp(√ikL)g(t),e–ikteikt
and
wβ(L,t) =
k∈Z
g(t),e–ikt– – ( –h)ng(t),e–ikteikt.
We have
wβ(x,t)
L(,π)=
k∈Z
exp|k|(L–x)g(t),e–ikt– – ( –h)ng(t),e–ikt.
For brevity in this case, we setQk(h,n) = g(t),e–ikt– [ – ( –h)n]g(t),e–ikt. Then using
the Hölder inequality, we get
wβ(x,t)
L(,π) =
k∈Z
exp|k|L
–x
L
Qk(h,n)
–Lx
Qk(h,n)
x L
≤
k∈Z
exp|k|L
–x
L
Qk(h,n)
–Lx
–x
L –xL
×
k∈Z
Qk(h,n)
x
L
x L
x L
=
k∈Z
exp|k|L∗Qk(h,n)
–xL
k∈Z
Qk(h,n) x
L
=w β(,t)
–Lx
L(,π)wβ(L,t)
x L L(,π).
This completes the proof of the lemma.
Lemma The following inequality holds:
β≤ M
m– .
Proof It follows from () that
m =
k∈Z
( –h)βg(t),e–ikteikt
L(,π)≤
k∈Z
( –h)βg(t) –g(t),e–ikteikt L(,π)
+
k∈Z
≤ sup <h<
( –h)β
k∈Z
g(t) –g(t),e–ikteikt L(,π)
+sup <h<
( –h)βg(t),e–ikteikt L(,π).
Moreover, it is easy to see that
( –h)β≤ β
and
g(t),e–ikteiktL(,π)=exp(–
√
ikL)u(,t),e–ikteiktL(,π)≤u(,t)L(,π)≤M.
This leads to
β≤+M
m.
This completes the proof of the lemma.
Lemma The following inequality holds:
w
β(L,·)L(,π)≤(m+ ).
Proof Due to the triangle inequality, we have
wβ(L,·)L(,π) =
k∈Z
g(t),e–ikt– – ( –h)ng(t),e–ikteikt L(,π)
≤
k∈Z
g(t) –g(t),e–ikteikt L(,π)
+
k∈Z
( –h)βg(t),e–ikteikt L(,π)
≤g–gL(,π)+
k∈Z
( –h)βg(t),e–ikteikt L(,π)
≤+m= (m+ ).
Lemma The following inequality holds:
w
β(,·)L(,π)≤
mM m– .
Proof Due to the triangle inequality andh=e–L |k|, we have
w
β(,·)L(,π)
=
k∈Z
≤
k∈Z
exp(√ikL)g(t),e–ikt– – ( –h)nexp(√ikL)g(t),e–ikteikt L(,π)
+
k∈Z
– ( –h)βexp(√
ikL)g(t) –g(t),e–ikteikt L(,π)
≤
k∈Z
( –h)βexp(√ikL)g(t),e–ikteikt L(,π)
+
k∈Z
– ( –h)β h
g(t) –g(t),e–ikteikt L(,π)
. ()
Moreover, we have
k∈Z
( –h)βexp(√ikL)g(t),e–ikteikt L(,π)
≤
k∈Z
exp(√ikL)g(t),e–ikteikt L(,π)
=u(,t)L(,π)≤M, ()
and using –(–hh)β ≤β, we have the estimate
k∈Z
– ( –h)β h
g(t) –g(t),e–ikteikt
L(,π)≤
β
k∈Z
g(t) –g(t),e–ikteikt L(,π)
≤βg–gL(,π)≤β. ()
Combining (), (), and (), we obtain
w
β(,·)L(,π)≤M+β.
Lemma leads to
wβ(,·)L(,π)≤M+
M m– =
Mm
m– .
Now, we return to the proof of the theorem.
Combining Lemma , Lemma , and Lemma , we obtain
u(x,·) –u(x,·)L(,π) =wβ(x,·)L(,π)
≤w β(,t)
–xL
L(,π)wβ(L,t) x L L(,π)
≤
Mm m–
–Lx
(m+ )xL
=EM–xLxL,
where
E= (m+ )xL
m m–
Competing interests
The authors declare that they have no competing interests.
Authors’ contributions
HTN and VCHL organized and wrote this manuscript. VCHL contributed to all the steps of the proofs in this research together. HTN participated in the discussion and corrected the main results. All authors read and approved the final manuscript.
Author details
1Applied Analysis Research Group, Faculty of Mathematics and Statistics, Ton Duc Thang University, Ho Chi Minh City, Vietnam.2Faculty of Basic Science, Posts and Telecommunications Institute of Technology, Ho Chi Minh City, Vietnam.
Acknowledgements
The authors wish to express their sincere thanks to the anonymous referees and the handling editor for many constructive comments, leading to the improved version of this paper. The second author is supported by Posts and Telecommunications Institute of Technology, Ho Chi Minh City, Vietnam.
Received: 22 September 2014 Accepted: 14 January 2015 References
1. Kirsch, A: An Introduction to the Mathematical Theory of Inverse Problems. Applied Mathematical Sciences, vol. 120. Springer, New York (1996)
2. Eldén, L: Approximations for a Cauchy problem for the heat equation. Inverse Problems3(2), 263-273 (1987) 3. Qian, Z, Fu, C-L, Xiong, X-T: A modified method for determining the surface heat flux of IHCP. Inverse Probl. Sci. Eng.
15(3), 249-265 (2007)
4. Xiong, X-T, Fu, C-L, Li, H-F: Central difference method of a non-standard inverse heat conduction problem for determining surface heat flux from interior observations. Appl. Math. Comput.173(2), 1265-1287 (2006) 5. Xiong, X-T, Fu, C-L, Li, H-F: Fourier regularization method of a sideways heat equation for determining surface heat
flux. J. Math. Anal. Appl.317(1), 331-348 (2006)
6. Liu, JC, Wei, T: A quasi-reversibility regularization method for an inverse heat conduction problem without initial data. Appl. Math. Comput.219(23), 10866-10881 (2013)
7. Reginska, T, Elden, L: Solving the sideways heat equation by a wavelet-Galerkin method. Inverse Probl.13(4), 1093-1106 (1997)
8. Elden, L, Berntsson, F, Reginska, T: Wavelet and Fourier methods for solving the sideways heat equation. SIAM J. Sci. Comput.21(6), 2187-2205 (2000)