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Volume 2010, Article ID 754210,18pages doi:10.1155/2010/754210

Research Article

Random Stability of an Additive-Quadratic-Quartic

Functional Equation

M. Mohamadi,

1

Y. J. Cho,

2

C. Park,

3

P. Vetro,

4

and R. Saadati

5

1Department of Mathematics, Islamic Azad University-Ayatollah Amoli Branch, Amol, P.O. Box 678, Iran

2Department of Mathematics Education and the RINS, Gyeongsang National University, Chinju 660-701, South Korea

3Department of Mathematics, Research Institute for Natural Sciences, Hanyang University, Seoul 133-791, South Korea

4Dipartimento di Matematica ed Applicazioni, Universit`a degli Studi di Palermo, Via Archirafi, 34 - 90123 Palermo, Italy

5Faculty of Sciences, Islamic Azad University-Ayatollah Amoli Branch, Amol, P.O. Box 678, Iran

Correspondence should be addressed to C. Park,[email protected] R. Saadati,[email protected]

Received 7 December 2009; Accepted 8 February 2010

Academic Editor: Jong Kim

Copyrightq2010 M. Mohamadi et al. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.

Using the fixed point method, we prove the generalized Hyers-Ulam stability of the following additive-quadratic-quartic functional equationfx2y fx−2y 2fxy 2fxy

2fxy 2fyx−4fx−2fx f2y f−2y−4fy−4fyin complete random normed spaces.

1. Introduction

The stability problem of functional equations originated from a question of Ulam 1

concerning the stability of group homomorphisms. Hyers2gave a first affirmative partial answer to the question of Ulam for Banach spaces. Hyers’ theorem was generalized by Aoki

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The functional equation

fxyfxy2fx 2fy 1.1

is called aquadratic functional equation. In particular, every solution of the quadratic functional equation is said to be aquadratic mapping. A generalized Hyers-Ulam stability problem for the quadratic functional equation was proved by Skof6for mappings f :XY, whereXis a normed space andY is a Banach space. Cholewa7noticed that the theorem of Skof is still true if the relevant domainX is replaced by an Abelian group. Czerwik8proved the generalized Hyers-Ulam stability of the quadratic functional equation. The stability problems of several functional equations have been extensively investigated by a number of authors and there are many interesting results concerning this problemsee4,9–26.

In27, Lee et al. considered the following quartic functional equation

f2xyf2xy4fxy4fxy24fx−6fy. 1.2

It is easy to show that the functionfx x4satisfies the functional equation1.2, which is

called aquartic functional equationand every solution of the quartic functional equation is said to be aquartic mapping.

LetXbe a set. A functiond :X×X → 0,∞is called ageneralized metriconX ifd

satisfies

1dx, y 0 if and only ifxy,

2dx, y dy, xfor allx, yX,

3dx, zdx, y dy, zfor allx, y, zX.

We recall a fundamental result in fixed point theory.

Theorem 1.128,29. LetX, dbe a complete generalized metric space and letJ :XXbe a

strictly contractive mapping with Lipschitz constantL <1. Then for each given elementxX, either

dJnx, Jn1x∞ 1.3

for all nonnegative integersnor there exists a positive integern0such that

1dJnx, Jn1x<, for allnn0,

2the sequence{Jnx}converges to a fixed pointyofJ,

3yis the unique fixed point ofJin the setY {yX|dJn0x, y<∞},

4dy, y∗≤1/1−Ldy, Jyfor allyY.

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2. Preliminaries

In the sequel we adopt the usual terminology, notations and conventions of the theory of random normed spaces, as in37–41. Throughout this paper,Δis the space of all probability distribution functions that is, the space of all mappingsF:R∪ {−∞,∞} → 0,1, such that

F is left-continuous, non-decreasing on R,F0 0 andF∞ 1.D is a subset of Δ consising of all functionsF ∈Δ for whichlF∞ 1, wherelfxdenotes the left limit of the functionfat the pointx, that is,lfx limtxft. The spaceΔis partially ordered

by the usual point-wise ordering of functions, that is,FGif and only ifFtGtfor allt

inR. The maximal element forΔin this order is the distribution functionε0given by

ε0t ⎧ ⎨ ⎩

0, ift≤0,

1, ift >0.

2.1

Definition 2.140. A mappingT :0,1×0,1 → 0,1is a continuous triangular norm

briefly, at-normifTsatisfies the following conditions:

aT is commutative and associative;

bT is continuous;

cTa,1 afor alla∈0,1;

dTa, b≤Tc, dwheneveracandbdfor alla, b, c, d∈0,1.

Typical examples of continuoust-norms areTPa, b ab,TMa, b mina, band

TLa, b maxab−1,0 theŁukasiewiczt-norm.

Recallsee42,43that ifT is at-norm and{xn}is a given sequence of numbers in

0,1,Tin1xiis defined recurrently byTi11xi x1andTin1xi TTin11xi, xnforn≥2.Tinxiis

defined asTi1xni.

It is known43that for theŁukasiewiczt-norm the following implication holds:

lim

n→ ∞TL

i1xni1⇐⇒

n1

1−xn<. 2.2

Definition 2.241. ARandom Normed spacebriefly, RN-spaceis a tripleX, μ, T, whereX

is a vector space,Tis a continuoust-norm, andμis a mapping fromXintoDsuch that, the following conditions hold:

RN1μxt ε0tfor allt >0 if and only ifx0;

RN2μαxt μxt/|α|for allxX,α /0;

RN3μxytsTμxt, μysfor allx, yXandt, s≥0.

Definition 2.3. LetX, μ, Tbe a RN-space.

1A sequence{xn}inXis said to beconvergenttoxinXif, for every >0 andλ >0,

there exists positive integerNsuch thatμxnx>1−λwhenevernN.

2A sequence {xn}inX is called Cauchyif, for every > 0 andλ > 0, there exists

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3A RN-spaceX, μ, Tis said to becompleteif and only if every Cauchy sequence in

Xis convergent to a point inX. A complete RN-space is said to be random Banach space.

Theorem 2.4 40. If X, μ, Tis a RN-space and {xn}is a sequence such thatxnx, then

limn→ ∞μxnt μxtalmost everywhere.

The theory of random normed spacesRN-spaces is important as a generalization of deterministic result of linear normed spaces and also in the study of random operator equations. The RN-spaces may also provide us the appropriate tools to study the geometry of nuclear physics and have important application in quantum particle physics. The generalized Hyers-Ulam stability of different functional equations in random normed spaces, RN-spaces and fuzzy normed RN-spaces has been recently studied in, Alsina 44, Mirmostafaee, Mirzavaziri and Moslehian33,45–47, Mihet¸ and Radu38,39,48,49, Mihet, Saadati and Vaezpour50,51, Baktash et al.52and Saadati et al.53.

3. Generalized Hyers-Ulam Stability of the Functional Equation

f

x

2

y

f

x

2

y

2

f

x

y

2

f

x

y

2

f

x

y

2

f

y

x

4

f

x

2

f

x

f

2

y

f

2

y

4

f

y

4

f

y

: An Odd Case

One can easily show that an odd mapping f : XY satisfiesfx2y fx−2y 2fxy2fxy2fxy2fyx−4fx−2fxf2yf−2y−4fy−4fy if and only if the odd mapping mappingf :XY is an additive mapping, that is,

fx2yfx−2y2fx. 3.1

One can easily show that an even mappingf :XYsatisfiesfx2y fx−2y 2fxy2fxy2fxy2fyx−4fx−2fxf2yf−2y−4fy−4fy if and only if the even mappingf:XY is a quadratic-quartic mapping, that is,

fx2yfx−2y4fxy4fxy−6fx 2f2y−8fy. 3.2

It was shown in54, Lemma 2.1thatgx:f2x−4fxandhx :f2x−16fxare quartic and quadratic, respectively, and thatfx 1/12gx−1/12hx.

For a given mappingf:XY, we define

Dfx, y:fx2yfx−2y−2fxy−2fxy−2fxy−2fyx 4fx 2fxf2yf−2y4fy4fy 3.3

for allx, yX.

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Theorem 3.1. LetXbe a linear space,Y, μ, TMbe a complete RN-space andΦbe a mapping from

X2toDΦx, yis denoted byΦ

x,ysuch that, for some0< α <1/3,

Φ3x,3yt≤Φx,yαt

x, yX, t >0 3.4

Letf:XY be an odd mapping satisfying

μDfx,yt≥Φx,yt 3.5

for allx, yXand allt >0. Then

Ax: lim

n→ ∞3 nf

x

3n

3.6

exists for eachxXand defines a unique additive mappingA:XYsuch that

μfx−Axt≥Φx,x

1−3α α t

3.7

for allxXand allt >0.

Proof. Lettingxyin3.5, we get

μf3x−3fxt≥Φx,xt 3.8

for allxXand allt >0. Consider the set

S:g:X−→Y, 3.9

and introduce the generalized metric onS:

dg, hinfu∈R:μgxhxut≥Φx,xt,∀xX,t >0

, 3.10

where, as usual, inf∅ ∞. It is easy to show thatS, dis complete.See the proof of Lemma 2.1 in38.

Now we consider the linear mappingJ:SSsuch that

Jgx:3g

x

3

3.11

(6)

Letg, hSbe given such thatdg, h< ε. Then

μgxhxεt≥Φx,xt 3.12

for allxXand allt >0. Hence

μJgxJhx3αεt μ3gx/3−3hx/33αεt

μgx/3−hx/3αεt

≥Φx/3,x/3αt

≥Φx,xt

3.13

for allxXand allt >0. Sodg, h< εimplies thatdJg, Jh≤3αε. This means that

dJg, Jh≤3αdg, h 3.14

for allg, hS.

It follows from3.8that

μfx−3fx/3αt≥Φx,xt, 3.15

for allxXand allt >0. So

df, Jfα < 1

3. 3.16

ByTheorem 1.1, there exists a mappingA:XY satisfying the following:

1Ais a fixed point ofJ, that is,

A

x

3

1

3Ax 3.17

for allxX. The mappingAis a unique fixed point ofJin the set

MhS:dh, g<. 3.18

This implies thatAis a unique mapping satisfying3.17such that there exists au∈0,

satisfying

μfxAxut≥Φx,xt, 3.19

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2dJnf, A 0 asn → ∞. This implies the equality

lim

n→ ∞3 nf

x

3n

Ax 3.20

for allxX. Sincef:XY is odd,A:XYis an odd mapping;

3df, A≤1/1−3αdf, JfwithfM, which implies the inequality

df, Aα

1−3α, 3.21

from which it follows

μfxAx

α

1−3αt

≥Φx,xt. 3.22

This implies that the inequality3.7holds. Now, we have,

μ3nDfx/3n,y/3nt μDfx/3n,y/3n

t

3n

≥Φx/3n,y/3n

t

3n

3.23

for allx, yX, allt >0 and alln∈N. So, we obtain by3.4

μ3nDfx/3n,y/3nt≥Φx,y

t 3αn

3.24

for allx, yX, allt >0 and alln∈N.

Since limn→ ∞Φx,yt/3αn 1 for allx, yX and all t > 0, byTheorem 2.4, we

deduce that

μDAx,yt 1 3.25

for allx, yXand allt >0. Thus the mappingA:XYis additive, as desired.

Corollary 3.2. Letθ≥0and letpbe a real number withp >3. LetXbe a normed vector space with norm · . Letf :XYbe an odd mapping satisfying

μDfx,yt≥ t

tθxpyp 3.26

for allx, yXand allt >0. Then

Ax: lim

n→ ∞3 nf

x

3n

(8)

exists for eachxXand defines an additive mappingA:XYsuch that

μfx−Axt≥ 3 p3t

3p3t2.3pθxp 3.28

for allxXand allt >0.

Proof. The proof follows fromTheorem 3.1by taking

Φx,yt:

t

tθxpyp 3.29

for allx, yX. Then we can chooseα3−pand we get the desired result.

Similarly, we can obtain the following. We will omit the proof.

Theorem 3.3. LetXbe a linear space,Y, μ, TMbe a complete RN-space andΦbe a mapping from

X2toD(Φx, yis denoted byΦ

x,y)such that, for some0< α <3,

Φx/3,y/3t≤Φx,yαt

x, yX, t >0. 3.30

Letf:XY be an odd mapping satisfying3.5. Then

Ax: lim

n→ ∞

1 3nf3

nx 3.31

exists for eachxXand defines a unique additive mappingA:XYsuch that

μfx−Axt≥Φx,x3−αt 3.32

for allxXand allt >0.

Corollary 3.4. Letθ≥0and letpbe a real number with0< p <1. LetXbe a normed vector space with norm · . Letf :XY be an odd mapping satisfying3.26. Then

Ax: lim

n→ ∞3

nf3nx

3.33

exists for eachxXand defines a unique additive mappingA:XYsuch that

μfxAxt≥ 3−3

pt

3−3pt2θxp 3.34

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Proof. The proof follows fromTheorem 3.3by taking

μDfx,yt≥ t

tθxpyp 3.35

for allx, yX. Then we can chooseα3pand we get the desired result.

4. Generalized Hyers-Ulam Stability of the Functional Equation

f

x

2

y

f

x

2

y

2

f

x

y

2

f

x

y

2

f

x

y

2

f

y

x

4

f

x

2

f

x

f

2

y

f

2

y

4

f

y

4

f

y

: An Even Case

Using the fixed point method, we prove the generalized Hyers-Ulam stability of the functional equationDfx, y 0 in random Banach spaces: an even case.

Theorem 4.1. LetX be a linear space, let Y, μ, TMbe a complete RN-space and Φbe a mapping

fromX2toD(Φx, yis denoted byΦx,y) such that, for some0< α <1/16,

Φx,yαt≥Φ2x,2yt

x, yX, t >0. 4.1

Letf:XY be an even mapping satisfyingf0 0and3.5. Then

Qx: lim

n→ ∞16 n

f

x

2n−1

−4fx

2n

4.2

exists for eachxXand defines a quartic mappingQ:XY such that

μf2x−4fx−Qxt≥TM

Φx,x

1−16α

5α t

,Φ2x,x

1−16α

5α t

4.3

for allxXand allt >0.

Proof. Lettingxyin3.5, we get

μf3y−6f2y15fyt≥Φy,yt 4.4

for allyXand allt >0.

Replacingxby 2yin3.5, we get

μf4y4f3y4f2y4fyt≥Φ2y,yt 4.5

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By4.4and4.5,

μf4x−20f2x64fx5t

TM

μ4f3x−6f2x15fx4t, μf4x−4f3x4f2x4fxt

TMΦx,xt,Φ2x,xt

4.6

for allxXand allt >0. Lettinggx:f2x−4fxfor allxX, we get

μgx16gx/25tTMΦx/2,x/2t,Φx,x/2t 4.7

for allxXand allt >0.

LetS, dbe the generalized metric space defined in the proof ofTheorem 3.1. Now we consider the linear mappingJ:SSsuch that

Jhx:16hx

2

4.8

for all xX. It is easy to see that J is a strictly contractive self-mapping on S with the Lipschitz constant 16α.

It follows from4.7that

μgx−16gx/25αtTMΦx,xt,Φ2x,xt 4.9

for allxXand allt >0. So

dg, Jg≤5α≤ 5

16 <. 4.10

ByTheorem 1.1, there exists a mappingQ:XYsatisfying the following:

1Qis a fixed point ofJ, that is,

Qx

2

1

16Qx 4.11

for allxX. Sinceg :XY is even withg0 0,Q :XY is an even mapping with

Q0 0. The mappingQis a unique fixed point ofJin the set

MhS:dh, g<. 4.12

This implies thatQis a unique mapping satisfying4.11such that there exists au∈0,

satisfying

μgxQxut≥TMΦx,xt,Φ2x,xt 4.13

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2dJng, Q 0 asn → ∞. This implies the equality

lim

n→ ∞16 ngx

2n

Qx 4.14

for allxX;

3dh, Q≤1/1−16αdh, Jhfor everyhM, which implies the inequality

dg, Q≤ 5α

1−16α. 4.15

This implies that the inequality4.3holds.

Proceeding as in the proof ofTheorem 3.1, we obtain that the mappingQ : XY

satisfiesfx2y fx−2y 2fxy 2fxy 2fxy 2fy−x−4fx− 2fx f2y f−2y−4fy−4fy.

Now, we have

Q2x−16Qxlim

n→ ∞

16ng

x

2n−1

−16n1gx

2n

16 lim

n→ ∞

16n−1g

x

2n−1

−16ngx

2n

0

4.16

for everyxX. Since the mappingxQ2x−4Qxis quarticsee54, Lemma 2.1, we get that the mappingQ:XYis quartic.

Corollary 4.2. Letθ≥0and letpbe a real number withp >4. LetXbe a normed vector space with norm · . Letf :XYbe an even mapping satisfyingf0 0and3.26. Then

Qx: lim

n→ ∞16 n

f

x

2n−1

−4fx

2n

4.17

exists for eachxXand defines a quartic mappingQ:XY such that

μf2x−4fx−Qxt≥ 2 p16t

2p16t512pθxp 4.18

for allxXand allt >0.

Proof. The proof follows fromTheorem 3.1by taking

μDfx,yt≥ t

tθxpyp 4.19

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Similarly, we can obtain the following. We will omit the proof.

Theorem 4.3. LetXbe a linear space,Y, μ, TMbe a complete RN-space andΦbe a mapping from

X2toD(Φx, yis denoted byΦ

x,y) such that, for some0< α <16,

Φx,yαt≥Φx/2,y/2t

x, yX, t >0. 4.20

Letf:XY be an even mapping satisfyingf0 0and3.5. Then

Qx: lim

n→ ∞

1 16n

f2n1x4f2nx 4.21

exists for eachxXand defines a quartic mappingQ:XY such that

μf2x−4fxQxt≥TM

Φx,x

16−α

5 t

,Φ2x,x

16−α

5 t

4.22

for allxXand allt >0.

Corollary 4.4. Letθ≥0and letpbe a real number with0< p <4. LetXbe a normed vector space with norm · . Letf :XY be an even mapping satisfyingf0 0and3.26. Then

Qx: lim

n→ ∞

1 16n

f2n1x−4f2nx 4.23

exists for eachxXand defines a quartic mappingQ:XY such that

μf2x−4fx−Qxt≥ 16−2 pt

16−2pt512pθxp 4.24

for allxXand allt >0.

Proof. The proof follows fromTheorem 3.3by taking

μDfx,yt≥ t

tθxpyp 4.25

for allx, yX. Then we can chooseα2pand we get the desired result.

Theorem 4.5. LetXbe a linear space,Y, μ, TMbe a complete RN-space andΦbe a mapping from

X2toD(Φx, yis denoted byΦ

x,y)such that, for some0< α <1/4,

Φx,yαt≥Φ2x,2yt

(13)

Letf:XY be an even mapping satisfyingf0 0and3.5. Then

Tx: lim

n→ ∞4 n

f

x

2n−1

−16fx

2n

4.27

exists for eachxXand defines a quadratic mappingT:XYsuch that

μf2x−16fx−Txt≥TM

Φx,x

1−4α

5α t

,Φ2x,x

1−4α

5α t

4.28

for allxXand allt >0.

Proof. LetS, dbe the generalized metric space defined in the proof ofTheorem 4.1. Lettinggx:f2x−16fxfor allxXin4.6, we get

μgx−4gx/25tTMΦx/2,x/2t,Φx,x/2t 4.29

for allxXand allt >0.

It is easy to see that the linear mappingJ:SSsuch that

Jhx:4hx

2

, 4.30

for allxX, is a strictly contractive self-mapping with the Lipschitz constant 4α. It follows from4.29that

μgx4gx/25αtTMΦx,xt,Φ2x,xt 4.31

for allxXand allt >0. So

dg, Jg≤5α <. 4.32

ByTheorem 1.1, there exists a mappingT :XY satisfying the following.

1Tis a fixed point ofJ, that is,

Tx

2

1

4Tx 4.33

for allxX. Sinceg :XY is even withg0 0,T :XY is an even mapping with

T0 0. The mappingTis a unique fixed point ofJin the set

(14)

This implies thatT is a unique mapping satisfying4.33such that there exists au ∈0,

satisfying

μgxTxut≥TMΦx,xt,Φ2x,xt 4.35

for allxXand allt >0;

2dJng, T 0 asn → ∞. This implies the equality

lim

n→ ∞4 ngx

2n

Tx 4.36

for allxX;

3dh, T≤ 1

1−4αdh, Jhfor eachhM, which implies the inequality

dg, T≤ 5α

1−4α. 4.37

This implies that the inequality4.28holds.

Proceeding as in the proof ofTheorem 4.1, we obtain that the mappingT : XY

satisfiesfx2y fx−2y 2fxy 2fxy 2fxy 2fy−x−4fx− 2fx f2y f−2y−4fy−4fy.

Now, we have

T2x−4Tx lim

n→ ∞

4ng

x

2n−1

−4n1gx

2n

4 lim

n→ ∞

4n−1g

x

2n−1

−4ngx

2n

0

4.38

for everyxX. Since the mappingxT2x−16Txis quadraticsee54, Lemma 2.1, we get that the mappingT :XY is quadratic.

Corollary 4.6. Letθ≥0and letpbe a real number withp >2. LetXbe a normed vector space with norm · . Letf :XYbe an even mapping satisfyingf0 0and3.26. Then

Tx: lim

n→ ∞4 n

f

x

2n−1

−16fx

2n

4.39

exists for eachxXand defines a quadratic mappingT:XYsuch that

μf2x−16fxTxt≥ 2 p4t

2p4t512pθxp 4.40

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Proof. The proof follows fromTheorem 4.5by taking

Φx,yt: t

tθxpyp 4.41

for allx, yX. Then we can chooseα2−pand we get the desired result.

Similarly, we can obtain the following. We will omit the proof.

Theorem 4.7. LetXbe a linear space,Y, μ, TMbe a complete RN-space andΦbe a mapping from

X2toD(Φx, yis denoted byΦ

x,y) such that, for some0< α <4,

Φx,yαt≥Φx/2,y/2t

x, yX, t >0. 4.42

Letf:XY be an even mapping satisfyingf0 0and3.5. Then

Tx: lim

n→ ∞

1 4n

f2n1x−16f2nx 4.43

exists for eachxXand defines a quadratic mappingT:XYsuch that

μf2x−16fxTxt≥TM

Φx,x

4−α

5 t

,Φ2x,x

4−α

5 t

4.44

for allxXand allt >0.

Corollary 4.8. Letθ≥0and letpbe a real number with0< p <2. LetXbe a normed vector space with norm · . Letf :XY be an even mapping satisfyingf0 0and3.26. Then

Tx: lim

n→ ∞

1 4n

f2n1x−16f2nx 4.45

exists for eachxXand defines a quadratic mappingT:XYsuch that

μf2x−16fxTxt≥

4−2pt

4−2pt512pθxp 4.46

for allxXand allt >0.

Proof. The proof follows fromTheorem 4.7by taking

Φx,yt:

t

tθxpyp 4.47

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Acknowledgments

The authors would like to thank referees for giving useful suggestions for the improvement of this paper. The first author is supported by Islamic Azad University-Ayatollah Amoli Branch, Amol, Iran. The second author was supported by the Korea Research Foundation Grant funded by the Korean GovernmentKRF-2008-313-C00050and the third author was supported by Basic Science Research Program through the National Research Foundation of Korea funded by the Ministry of Education, Science and TechnologyNRF-2009-0070788. The fourth author is supported by Universit`a degli Studi di Palermo, R.S. ex 60%.

References

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References

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