Terms To Know
OUTLINE
6.1 Discrete Random Variables
6.2 The Binomial Probability Distribution
VOCABULARY
Random variable (p. 298) Probability histogram (p. 300) Binomial random variable (p. 310) Discrete random variable (p. 298) Expected value (p. 303)
Binomial probability distribution (p. 313) Continuous random variable (p. 298) Binomial experiment (p. 310)
Cumulative distribution function (p. 316) Probability distribution (p. 299) Trial (p. 310)
MyMathLab Homework for Chapter 6
6.1 Discrete Random Variables
6.2 The Binomial Probability Distribution
For your homework, you could use StatCrunch when working on certain problems.
6.2 population size N = sample p = n = x = success: Population
Two Types of Binomail Distribution Problems
population size N = sample p = n = x = success: Population p-value known p-value unknown given random sample no random sample given 6.2
Which criteria requires that a sample size be given?
Chapter 6 (Discrete Probability Distributions): page 2
Experiment: Roll a single fair die ten times in succession. Experiment Outcome:
Random Variable x: the number of fours facing up
: x: : x: : x:
Values of x:
Graph of x:
Experiment: A card is to selected from a well shuffled poker deck. Suppose that the casino will pay you $10 if you select
an ace. If you fail to select an ace, you are required to pay the casino $2.
Experiment Outcome: number of outcomes :
Random Variable x: gambler’s winnings for playing the game once
Values of x : Graph of x:
Experiment: A randomly selected student takes a ten-question multiple choice IQ test by guessing. Afterwards, the test is
graded.
Experiment Outcome: W C W C W W W W W W
Random Variable x: the number of correct answers
C W C C C C C C C C: x = W W W C W W W W W W: x = W C W C W W W W W W: x = W W W W W W W W W W: x = Values of x : Graph of x:
two types of outcomes
experiment outcome trial outcome
loss = negative gain
IQ TEST Name:____________ 1. Who is John?
a) John
b) none of the above 2. Who ate 9?
a) 7
b) none of the above 3. Is N.Y. city a country?
a) yes
b) none of the above 4. Is 0 a negative number?
a) yes
b) none of the above 5. What is good?
a) smoking b) none of the above 6. The color red is what color?
a) red
b) none of the above 7. What is the first integer?
a) 0
b) none of the above 8. Are footballs made from feet?
a) yes
b) none of the above 9. What is 5 divided by 0?
a) 0
b) none of the above 10. What is 0 divided by 5?
a) 0
b) none of the above from the gambler’s point of view
not from the casino’s point of view
x: x: x: experiment outcome
Random Variable
6.1 discrete number of outcomes Multiplication Rule of Counting q r s! ! ! ...two types of outcomes
experiment outcome trial outcome number of outcomes Multiplication Rule of Counting q r s! ! !...
Experiment: Toss a single fair coin ten times in succession. Experiment Outcome:
Random Variable x: the number of heads facing up
Values of x :
P 0
( )
=P 1
( )
= P 2( )
=P 10
( )
=cash prize: amount earned winnings: amount earned profit: amount earned - amount spent net winnings: amount earned - amount spent
Probability Distribution of a Random Variable
6.1discrete 5 6 7 8 9 10 0 0.05 0 . 1 0.15 0 . 2 0.25 0 1 2 3 4
(the base of each rectangle is 1 unit) area=height$width
Probability Histogram 0 0.05 0 . 1 0.15 0 . 2 0.25 0 Probability Histogram
Experiment: A card is to selected from a well shuffled poker deck. Suppose that the casino will pay you $10 if you select
an ace. If you fail to select an ace, you are required to pay the casino $2.
Experiment Outcome:
Random Variable x: gambler’s winnings for playing the game once
Values of x :
two types of outcomes
experiment outcome trial outcome number of outcomes Multiplication Rule of Counting q r s! ! ! ... 10C =2 45 P x nCx p p x n x
( )
= ! ! "(
1)
" Probability Distribution x P x( )
Probability Distribution x P x( )
P 17 1 38( )
= P 17 1 37( )
= 1. 2. 3. 4. ..., 36, 0, 00: P 17( )
= 1. 2. 3. 4. ..., 40, 0, 00: P 17( )
= 1. 2. 3. 4. ..., 33, 0, 00: P 17( )
= hw P# $ % & ' ( = P# $ % & ' ( =Chapter 6 (Discrete Probability Distributions): page 4
Experiment: A life insurance company sells a $250,000 one-year term life insurance policy to a 20-year old female for $200.
According to the National Vital Statistics Report, the probability that the female survives the year is 0.999546.
Experiment Outcome: (20-year old female policy holder)
Random Variable x: the life insurance company’s profit for a $250,000
one-year term life insurance policy for a randomly selected 20-year old female
Values of x:
Mean of a Random Variable
6.1discrete
from the life insurance company’s point of view, not from the policy holder’s point of view
Experiment: A card is to selected from a well shuffled poker deck. Suppose that the casino will pay you $10 if you select
an ace. If you fail to select an ace, you are required to pay the casino $2.
Experiment Outcome:
Random Variable x: gambler’s winnings for playing the game once
Values of x :
cash prize: amount earned winnings: amount earned profit: amount earned - amount spent net winnings: amount earned - amount spent
Probability Distribution
x P x
( )
x P x!( )
THE BIG QUESTION
In the long run, how much will John win/lose per game?
• approximate answer using data • find exact answer using formula
1st game: $ 2nd game: $ 3rd game: $ 4th game: $ 5th game: $ 6th game: $ . . . . . . x x n =
)
%x=)
*+x P x!( )
,-The insurance company is gambling on whether the 20-year old female policy holder will die before the policy expires in one year.
Probability Distribution x P x
( )
x P x!( )
%x: Mean or Expected Value %x=)
*+x P x!( )
,-%x=)
*+x P x!( )
,-: Mean %x: Mean or Expected ValueIf the insurance company sells many policies, the company is expected to $ per policy, on average. make/lose
If John plays many games, he is expected to $ per game, on average. win/lose
Standard Deviation of a Random Variable
6.1 discrete .x x P x %x 2 2 2 =)
*+ !( )
,-" .x x %x P x 2 2 =)
*+(
")
!( )
, -.x x %x P x 2 2 =)
*+(
")
!( )
,-: Variance .x x P x %x 2 2 2 =)
*+ !( )
,-" : Variance .x= .x 2 : Standard Deviation Probability Distribution %x: .x 2: - = .x:3 decimal places 3 decimal places 3 decimal places 3 decimal places 1 decimal place .x= .x 2 .x= .x 2 1 decimal place .x: fill in x P x
( )
x P x!( )
x"%x(
x"%x)
2(
x"%x)
2!P x( )
x P x( )
x P x!( )
x2 x2!P x( )
fill inChapter 6 (Discrete Probability Distributions): page 6
Factorial and Combination Formulas
6.2n!= ! ! ! !1 2 3 ... n: factorial formula nCr n r n r = !
(
")
! ! !: combination formula n!= ! ! ! !1 2 3 ... n 1!: 2!: 3!: 4!: 5!: 6!: 7!: 8!: 0!: nCr n r n r = !(
")
! ! ! 3 1 3 1 3 1 C = !(
")
! ! !: 7 0 7 0 7 0 C = !(
")
! ! !: 5 2 5 2 5 2 C = !(
")
! ! !: 8 5 8 5 8 5 C = !(
")
! ! !: n factorial n choose r n! nCr nCr n r = # $ % & ' ( same thingOnly Use Calculator
20C12: 25C15: 40C30:
20 12
20 12
MATH PRB 3:n r ENTER ENTER
n r
C
C =
22 15
22 115
MATH PRB 3:n r ENTER ENTER
n r
C
C =
7 7
MATH PRB 4:! ENTER ENTER x!
8 8
MATH PRB 4:! ENTER ENTER x!
Binomial Distribution
6.2 Experiment: Roll a single fair die two times in succession.Experiment Outcome: Trial Outcome: Number of trials: Success for a trial:
Failure for a trial: , , , ,
Probability of success for a trial: p =
Probability of failure for a trial: 1" p =
Random Variable x: number of successes
x = x =
x = x =
Values of x :
Binomial Probability Function P x
( )
: P x Cxx x
( )
= !# $ % & ' ( !# $ % & ' ( " 2 2 1 6 5 6 P 0 C 1 6 5 6 2 0 0 2 0( )
= !# $ % & ' ( !# $ % & ' ( " : 2C0: P 1 C 1 6 5 6 2 1 1 2 1( )
= !# $ % & ' ( !# $ % & ' ( " : 2C1: P 2 C 1 6 5 6 2 2 2 2 2( )
= !# $ % & ' ( !# $ % & ' ( " : 2C2:equally likely outcomes
two types of outcomes
experiment outcome trial outcome
Binomial Random Variable
x: number of successes out of n
Binomial Probability Function
P x nCx p p x n x
( )
= ! ! "(
1)
" for 0 / /x n 4 decimal places 4 decimal places 4 decimal places x P x( )
x P x!( )
x"%x(
x"%x)
2(
x"%x)
2!P x( )
Binomial Distribution Shortcut Formulas %x=np .x2 np 1 p =(
")
.x= np(
1"p)
%x= # $ % & ' ( 2 1 6 : .x= # $ % & ' (# $ % & ' ( 2 1 6 5 6 : 4 decimal places 4 decimal places Discrete Distribution General Formulas %x=)
*+x P x!( )
,-: .x=)
*+(
x"%x)
!P x( )
, -2 : 4 decimal placesChapter 6 (Discrete Probability Distributions): page 8
Experiment: A random sample of 5 light bulbs is taken from a shipment of 1,000,000 light bulbs
with a 1% defect rate. Sampling is done without replacement.
Experiment Outcome: Trial Outcome: Number of trials:
Success for a trial: defective bulb Failure for a trial: non-defective bulb Probability of success for a trial: p = Probability of failure for a trial: 1" p =
Random Variable x: number of successes
x = x =
x = x =
Values of x :
Binomial Probability Function P x
( )
: P x( )
=5Cx!(
)
x!(
)
"x5 0 01. 0 99. P 0 5C0 0 01 0 99 0 5 0
( )
= !(
.)
!(
.)
" : 5C0: P 1 5C1 0 01 0 99 1 5 1( )
= !(
.)
!(
.)
" : 5C1: P( )
2 =5C2!(
0 01.)
2!(
0 99.)
5 2" : 5C2: P( )
3 =5C3!(
0 01.)
3!(
0 99.)
5 3" : $ 10 5C3: P( )
4 =5C4!(
0 01.)
4!(
0 99.)
5 4" : $ 10 5C4: P 5 5C5 0 01 0 99 5 5 5( )
= !(
.)
!(
.)
" : $ 10 5C5:Binomial Distribution
6.2Binomial Random Variable
x: number of successes out of n
Binomial Probability Function
P x nCx px p n x
( )
= ! ! "(
1)
" for 0 / /x n x P x( )
x P x!( )
x"%x(
x"%x)
2 x" x P x(
%)
2!( )
Binomial Distribution Shortcut Formulas %x=np .x np p 2 1 =(
")
.x= np(
1"p)
%x=5 0 01(
.)
: .x= 5 0 01 0 99(
.)(
.)
: 4 decimal places 2 decimal places 4 decimal places 4 decimal places 4 decimal places scientific notation scientific notation scientific notation Discrete Distribution General Formulas %x=)
*+x P x!( )
,-: .x=)
*+(
x"%x)
!P x( )
, -2 : 4 decimal places 4 decimal placesN
=
large/small sampling without replacementBinomial Distribution
6.2only %x=
)
*+x P x!( )
,-only %x=np
both %x=
)
*+x P x!( )
,- and %x=npnone of the above
only .x=
)
*+(
x"%x)
!P x( )
, -2 only .x= np(
1"p)
both .x=)
*+(
x"%x)
!P x( )
, -2 and .x= np(
1"p)
none of the above
N
=
n
=
N
=
n
=
p : probability of success for a trial or proportion of the population being successful % of the population at home.
large/small
sampling without replacement
Chapter 6 (Discrete Probability Distributions): page 10
P< % P< %
Binomial Distribution
6.2Binomial Distribution: n = 300, p = 0.25
np
(
1"p)
:Is the binomial histogram bell-shaped? %: . :
Which x-values are considered unusual? whole number
yes/no
2 decimal places 2 decimal places
Binomial Distribution: n = 200, p = 0.90 np
(
1"p)
:Is the binomial histogram bell-shaped? %: . :
Which x-values are considered unusual? whole number
yes/no
2 decimal places 2 decimal places
whole number whole number whole number
unusual result unusual result
0
whole number whole number whole number
unusual result unusual result 0 200x x x = 0, 1, 2, 3, ..., 300 x = 0, 1, 2, 3, ..., 200 %x=np .x= np
(
1"p)
%x=np .x= np(
1"p)
unusually event: P < see pages 225-226