Technical Science
Introduction to Chemistry
Using Chemical Equations
●
In this tutorial you will…
–
Determine Atomic and Molecular Weight
–
Define a Mole
–
Convert Between Moles and Grams
Determine Atomic
and Molecular Weight
●
Any recipe will tell you at least two things:
–
The names of ingredients
–
The amounts of the ingredients
●
When preparing food, the amounts of ingredients
may be measured by mass, weight, or volume
●
But when dealing with a chemical reaction, the
amounts of reactant and product are always
measured by mass.
●
So, lets review how we find the mass of atoms and
molecules.
●
Chemical Equations are simply recipes.
1 of 5
Determine Atomic
and Molecular Weight
2 of 5
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Find the mass of an atom of Iodine
I
1 atom
=
To find the mass of an atom, simply look up that atom on
the Periodic Table
Periodic Table of the Elements
53 I
Iodine
127.0 Don’t confuse atomic
number with atomic mass. The mass of Iodine is 127.0
127.0
Remember, an atom’s mass is measured in units called AMU’s (atomic mass units)
Determine Atomic
and Molecular Weight
3 of 5
●
Use your Periodic Table to find the atomic masses
of the following atoms in AMU’s
Helium
B
Mg
Cobalt
Sulfur
Sb
Au
Uranium
4.0 AMU
24.5 AMU
32.0 AMU
197.0 AMU
11.0 AMU
59.0 AMU
122.0 AMU
Determine Atomic
and Molecular Weight
4 of 5
●
Find the mass of a molecule of sulfur dioxide.
SO
2
1 molecule
=
To find the mass of a molecule, first, find the masses of all the atoms in that molecule.
Periodic Table of the Elements
8 O
Oxygen
16.0
16 S
Sulfur
32.0
The mass of one Oxygen = 16.0 The mass of one Sulfur = 32.0
In this molecule there is one atom of Sulfur bonded to
two atoms of Oxygen 1 Sulfur (32 AMU) = 32 2 Oxygen (16 AMU each) = 32
32 + 32 = 64
64
! Remember the Units ! The mass of an atom or molecule is measured in AMU’s
AMU’s
16.0
Determine Atomic
and Molecular Weight
5 of 5
●
Use your Periodic Table to find the masses of the
following molecules.
Home
N
2HNO
3Water
Mg(OH)
2SbCl
3Potassium
Chloride
ZnSO
4C
6H
12O
628.0 AMU
H
2O
18 AMU
228.5 AMU
161.5 AMU
63.0 AMU
58.5 AMU
KCl 74.5 AMU
Define a Mole
1 of 10
Home
●
What does the balanced equation below tell you?
2 NH
3
N
2
+ 3 H
2
●
This equation tells us that 2 molecules of ammonia
(NH
3) react to produce 1 molecule of nitrogen gas
and 3 molecules of hydrogen gas.
●
With this information, you could determine the
amount of any reactant or product so long as you
know the amount of one of the ingredients.
Define a Mole
2 of 10
●
If 4 molecules of ammonia react how many
molecules of N
2and H
2will be produced?
2 NH
3
N
2
+ 3 H
2
First, write down the amount of the reactant or product that you are given.
4 molecules of NH3 in this case. 4 molecules NH3
Use the information from the balanced equation to determine the relationship between the given
substance and the unknown substance. Let’s find the amount of N2 first.
The relationship between NH3 and N2 is 2 to 1. Two molecules of NH3 produces one molecule of N2.
We will use this ratio ( 2 NH3 to 1 N2 ) as a conversion factor to convert from
an amount of ammonia to an amount of nitrogen.
x
2 molecules NH3 1 molecule N2
Perform the calculation: 4 ÷ 2 = 2
Two NH3 molecules produce one N2 molecule. So, four NH3 molecules produces two N2 molecules.
2 molecules N2
=
Calculate the number of molecules of H2 produced. Again, start your calculation with the
given information: 4 molecules of NH3 4 molecules NH3
What’s the relationship between NH3 and H2? The equation tells us that 2 ammonia molecules
will produce 3 hydrogen molecules. Use that ratio as a conversion factor.
2 NH3 to 3 H2
x
2 molecules NH3 3 molecules H
2
Perform the calculation: 4 x 3 ÷ 2 = 6
Two NH3 molecules produces three H2 molecules. So, four NH3 molecules produces six H2 molecules.
6 molecules H2
=
The coefficients provided by the balanced chemical equation can be used as conversion factors to convert
Define a Mole
3 of 10
●
If 8 molecules of MnCl
2were produced, how
many molecules of HCl and MnO
2reacted?
MnO
2+ 4 HCl MnCl
2+ Cl
2+ 2 H
2O
8 molecules MnCl
2
x
1 molecule MnCl2 4 molecules HCl
32 molecules HCl
=
8 molecules MnCl2
x
1 molecule MnCl2 1 molecule MnO
2 8 molecules MnO 2
Define a Mole
4 of 10
●
The coefficients in a balanced chemical reaction
can be used as conversion factors.
●
They can determine the number of molecules of
any reactant or product if you are given a number
of molecules of one other substance.
●
To determine a number of atoms or molecules is
good information but it really isn’t very practical.
●
It would be nearly impossible to measure out
substances an atom or a molecule at a time.
Define a Mole
5 of 10
●
Take another look at the following equation.
2 Na + Cl
2
2 NaCl
●
We have a recipe for making 2 molecules of
sodium chloride.
●
But what if we wanted more than two molecules of
sodium chloride? Would we need another recipe?
●
No, like any recipe, if you want more product you
increase the amounts of the ingredients.
Define a Mole
6 of 10
●
This equation can be read in a number of ways.
2 Na + Cl
2
2 NaCl
2 atoms of Na react with
1 molecule of Cl
2to produce
2 molecules of NaCl
But since it is nearly impossible to measure out
a single atom or molecule,
the equation could also be read this way.
200 atoms of Na react with
100 molecules of Cl
2to produce
200 molecules of NaCl
It could be read this way.
2 million atoms of Na react with
1 million molecules of Cl
2to produce
2 million molecules of NaCl
We will continue to scale up our recipe
until we get enough atoms or molecules
that we can conveniently measure.
As it turns out, the most convenient
number to work with
is 6.02 x 10
23atoms or molecules.
6.02 x 10
23is a very large number.
602,000,000,000,000,000,000,000
Why does it have to be so large?
Atoms and molecules are very small
and it takes a lot of them to make
a significant amount of matter.
In fact it would take about 20 million atoms
lined up end to end to cross the period
at the end of this sentence.
6.02 x 10
23is enough atoms or molecules to
actually see, touch, and measure.
Since 6.02 x 10
23is so large,
chemists have given this number a name.
6.02 x 10
23is called one Mole.
Just like 12 is one Dozen,
and 144 is one Gross,
6.02 x 10
23is one Mole.
So, our chemical equation
could also be read
in terms of moles.
2 moles of Na atoms react with
1 mole of Cl
2molecules to produce
Define a Mole
7 of 10
●
Define a mole
Α
A mole is a convenient number of atoms or
molecules with which to work.
One mole is 6.02 x 10
23particles.
Define a Mole
8 of 10
●
If 5 moles of ammonia react how many moles
of N
2and H
2will be produced?
2 NH
3
N
2
+ 3 H
2
First, write down the amount of the reactant or product that you are given.
5 moles of NH3 in this case. 5 moles NH3
Use the information from the balanced equation to determine the relationship between the given
substance and the unknown substance. Let’s find the amount of N2 first.
The relationship between NH3 and N2 is 2 to 1. Two moles of NH3 produces one mole of N2.
We will use this ratio ( 2 NH3 to 1 N2 ) as a conversion factor to convert from
an amount of ammonia to an amount of nitrogen.
x
2 moles NH3 1 mole N2
Perform the calculation: 5 ÷ 2 = 2.5
Two moles of NH3 produce one mole of N2. So, five moles of NH3 produces 2.5 moles of N2.
2.5 moles N2
=
5 moles NH3
x
2 moles NH3 3 moles H
2 7.5 moles H
2
=
It’s okay to have a part of a mole of a substance. Like a dozen, a mole is just a number. You can have
a 2.5 dozen so you can have 2.5 moles.
Calculate the number of moles of H2 produced. Again, start your calculation with the
given information: 5 moles of NH3
What’s the relationship between NH3 and H2? The equation tells us that 2 moles of ammonia will
produce 3 moles of hydrogen. Use that ratio as a conversion factor.
2 NH3 to 3 H2
Perform the calculation: 5 x 3 ÷ 2 = 7.5 Two moles of NH3 produces three moles of H2. So, five moles of NH3 produces 7.5 moles of H2. The coefficients provided by the balanced chemical equation can be used as conversion factors to convert
Define a Mole
9 of 10
●
If 0.5 moles of MnCl
2were produced, how many
moles of HCl and MnO
2reacted?
MnO
2+ 4 HCl MnCl
2+ Cl
2+ 2 H
2O
0.5 moles MnCl
2
x
1 mole MnCl2 4 moles HCl
2 moles HCl
=
0.5 moles MnCl2
x
1 mole MnCl2 1 mole MnO
2 0.5 moles MnO 2
Define a Mole
10 of 10
●
In this section, you found that a chemical equation
can be interpreted in terms of atoms & molecules
or in terms of moles.
●
You discovered that a mole (6.02 x 10
23) particles
is a convenient number of atoms or molecules
●
You also calculated the amounts of reactants and
products in terms of atoms and molecules and in
terms of moles.
●
However, even with what we know now, our
chemical equation still isn’t very practical.
●
The next section will show how to make a
chemical equation functional.
Convert Between
Moles and Grams
1 of 10
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Read the following equation in terms of moles.
Home
4 Al + 3 O
2
2 Al
2
O
3
4 moles of Al atoms react with
3 moles of O
2molecules to produce
2 moles of Al
2O
3molecules.
Once again, this is good information because it shows the ratio of the amounts of reactants and products.
We also know that a mole of a substance is convenient to work with because it represents
enough particles to actually measure. However, there is still a problem.
Let’s say we want to produce 2 moles of Al2O3. We would need 4 moles of Aluminum (Al). How would you measure 4 moles of aluminum? Would you count out the aluminum atoms one at
a time until you got to 4 moles? Of course not.
Atoms are too small to count individually and it would take forever to count to 4 moles.
So what would you do?
If a mole is a convenient amount of particles, there must be a convenient way
to measure a mole of atoms or molecules. The rest of this section will show you how to
measure a mole of atoms or molecules. This is going to make chemical equations
2 of 10
●
The primary means of measuring amounts of
substances in a chemistry lab is by mass.
●
In the first section, we found masses of atoms and
molecules by reading the Periodic Table.
●
Now we will determine the mass of a mole of
atoms or molecules.
●
This really isn’t as difficult as it may sound
3 of 10
Convert Between
Moles and Grams
●
Find the mass of one atom of hydrogen and the
mass of one mole of hydrogen atoms.
1 Atom of Hydrogen
=
Mass of 1 Atom of Hydrogen
To find the mass of a single atom, simply look up the mass of that atom on the Periodic Table.
Hydrogen has a mass of 1.0 AMU
1.0 AMU
1 mole of Hydrogen Atoms
Now let’s find the mass of one mole of hydrogen atoms.
Remember:
A mole is 6.02 x 1023 particles.
602,000,000,000,000,000,000,000 atoms
=
Mass of 1 Mole of Hydrogen Atoms
6.02 x 1023 atoms
If one atom of hydrogen has a mass of 1 AMU, then 1 mole of hydrogen atoms must have a
mass of 6.02 x 1023 AMU’s
6.02 x 10
23AMU’s
You’re probably saying this doesn’t look very easy or convenient. However, there is a
relationship that simplifies the process. 6.02 x 1023 AMU’s is equal to 1.0 gram.
1.0 Gram
So, the mass of 1 atom of H is 1.0 AMU. The mass of 1 mole of H atoms is 1.0 gram.
Notice the number (1.0) is the same.
This simplifies the process a great deal because that number was very easy to find.
We just read it off the Periodic Table.
This relationship holds true for any atom or molecule. If one molecule of water has a mass of 18 AMU’s, then
one mole of water molecules has a mass of 18 grams. Note: Don’t get the idea that 1 AMU is equal to 1 gram
4 of 10
Convert Between
Moles and Grams
●
Determine the mass of 1 mole of the following
atoms and molecules.
Atom
Mass
(1 mole)
Molecule
Mass
(1 mole)
Be
CH
4Iron
N
2Ba
Ca(NO
3)
2Gold
H
2CO
39.0 grams
56.0 grams
137.5 grams
197.0 grams
16.0 grams
28.0 grams
164.0 grams
62.0 grams
The mass of one mole of a substance is such an important relationship it is given its own name.
The mass of one mole of atoms is called the Gram Atomic Weight
The mass of one mole of molecules is called the Gram Molecular Weight
The Gram Atomic Weight of iron is 56.0 grams / 1 mole
Convert Between
Moles and Grams
5 of 10
●
How much Al would be required to produce
2 moles of Al
2O
3?
4 Al + 3 O
2
2 Al
2
O
3
From the information given in the balanced chemical equation, you know that it would take
4 moles of Al to produce 2 moles of Al2O3.
4 moles Al
It is important to know we need 4 moles of Al. But that information isn’t very practical.
We want to know the amount in grams. We need to know the amount
in grams rather than moles
because we measure substances by mass. We can convert from moles to grams by using
the Gram Atomic Weight of Al. 27.0 grams / 1 mole of Al The Gram Atomic Weight of Al
27.0 grams / 1 mole of Al
will be used as a conversion factor.
x
1 mole Al
27.0 grams
Perform the calculation: 4 x 27.0 = 108 4 moles of Al = 108 grams
= 108 grams
The Gram Atomic Weight allows us to determine amounts of reactants and products in terms of
grams rather than moles.
That’s important because, if we were to actually perform this reaction in the lab, the reactants
6 of 10
Convert Between
Moles and Grams
●
Calculate mass in grams of the given number of
moles of the following substances.
5 moles Na
1.5 moles O
20.75 moles H
2O
3 moles NaOH
x
1 mole Na
23 grams
= 115 grams of Na
x
1 mole O
232 grams
= 48 grams of O
2x
1 mole H
2O
18 grams
= 13.5 grams of H
2O
x
1 mole NaOH
40 grams
Convert Between
Moles and Grams
7 of 10
●
We determined the Gram Atomic Weight and the
Gram Molecular Weight for atoms and molecules.
●
We also used the Gram Molecular Weight (GMW)
and the Gram Atomic Weight (GAW) as a
conversion factor.
●
This allowed us to calculate the amount in grams
of a substance when given the number of moles.
●
We can also use the Gram Molecular Weight
(or the GAW) to convert from grams of a
8 of 10
Convert Between
Moles and Grams
●
153 grams of Al
2O
3is how many moles.
Just like any conversion, the first step is to write down the measurement
you are trying to convert.
Next, we need a conversion factor.
The Gram Molecular Weight is the conversion factor because it relates mass to moles.
153 g Al
2
O
3GMW of Al2O3 = 102 grams / 1 mole Al 2 x 27 = 54
O 3 x 16 = 48 54 + 48 = 102
The GMW of Al2O3 is 102 grams / mole We want to convert from grams to moles. So, grams must cancel which means 102 grams
will be on the bottom of the conversion factor.
x
102 grams
1 mole Al
2O
3Perform the calculation: 153 ÷ 102 = 1.5
153 grams of Al2O3 is 1.5 moles
9 of 10
Convert Between
Moles and Grams
●
Calculate number of moles of the following
substances given the mass in grams.
3 grams C
142 grams Cl
2595 g AgNO
3234 g Mg(OH)
2x
12 grams
1 mole C
= 0.25 moles of C
x
71 grams
1 mole Cl
2= 2 moles of Cl
2x
170 grams
1 mole AgNO
3= 3.5 moles of AgNO
3x
58.5 grams
1 mole Mg(OH)
2= 4 moles of
10 of 10
Convert Between
Moles and Grams
●
In this section we determined Gram Atomic
Weights and Gram Molecular Weights of atoms and
molecules
●
We used the Gram Molecular Weight (GMW) and
the Gram Atomic Weight (GAW) as conversion
factors.
●
This allowed us to convert from moles to grams
and from grams to moles
●
In the next section we put all this information
together to solve some practical problems in
chemistry.
Calculate Amounts of
Reactant and Product
1 of 5
●
Chemical equations are essential to any industry
that produces or uses chemicals.
Home
●
A company doesn’t want to use more of a reactant
than is necessary or produce extra product that
could end up as waste.
●
Chemical equation can be used to determine exact
amounts of reactants and products.
●
All we need is a balanced chemical equation and
the amount in grams of one reactant or product.
?
2 moles Fe
112 g
2 of 5
Calculate Amounts of
Reactant and Product
●
How many g of C is needed to produce 112 g of Fe.
2 Fe
2
O
3
+ 3 C 4 Fe + 3 CO
2
Solving this problem involves three steps. The good news is that we have already done each of these steps independently.
Now, we will put them all together. Identify the given information and the information you are supposed to find.
Given = 112 g Fe Find = ? g C
Step 1: Convert grams of the given substance (Fe) to moles. Use the Gram Atomic Weight as the conversion factor.
GAW of Fe = 56.0 grams / mole
112 g Fe x
56 grams 1 mole Fe
= 2 moles Fe
Step 2: Convert moles of iron to moles of carbon. Use the ratio from the balanced chemical equation.
3 moles of C react to form 4 moles of Fe. x
4 moles Fe 3 moles C
= 1.5 moles C
Step 3: Convert moles of the desired substance (C) to grams. Use the Gram Atomic Weight as the conversion factor.
GAW of C = 12.0 grams / mole
1.5 moles C x
1 mole C 12 grams
= 18 grams C
112 g of iron is 2 moles. The ratio of Cto Fe is 3 to 4, so 1.5 moles of C is needed to produce 2 moles of Fe.
1.5 moles of C is 18 grams.
18 g
On the next slide,
Calculate Amounts of
Reactant and Product
3 of 5
●
How much (g) Fe
2O
3is needed to make 112 g of Fe
2 Fe
2
O
3
+ 3 C 4 Fe + 3 CO
2
112 g 18 g
Step 1: Convert grams of the given substance (Fe) to moles. Use the Gram Atomic Weight as a conversion factor.
Fe = 56 grams / 1 mole
112 g Fe x
56 grams 1 mole Fe
= 2 moles Fe
We already did this calculation when we solved the first problem so we could have started this problem with Step 2.
However, we did the calculation again for practice. Step 2: Convert moles of Fe to moles of Fe2O3. Use the ratio from the balanced chemical equation.
2 moles of Fe2O3 react to produce 4 moles of Fe
2 moles Fe x
4 moles Fe 2 moles Fe
2O3 = 1 mole Fe 2O3
Step 3: Convert moles of Fe2O3 to grams of Fe2O3. Use the Gram Molecular Weight as a conversion factor.
GMW of Fe2O3 = 160 grams / 1 mole
1 mole Fe
2O3 x
1 mole Fe
2O3
160 grams
= 160 grams Fe2O3
112 g of iron is 2 moles. The ratio of Fe2O3 to Fe is 2 to 4, so 1 mole of Fe2O3 is needed to produce 2 moles of Fe.
1 mole of Fe2O3 is 160 grams.
160 g
On the next slide,
4 of 5
Calculate Amounts of
Reactant and Product
●
How much (g) CO
2is needed to make 112 g of Fe
2 Fe
2
O
3
+ 3 C 4 Fe + 3 CO
2
112 g 18 g
160 g
Step 1: Convert grams of the given substance (Fe) to moles. Use the Gram Atomic Weight as a conversion factor.
Fe = 56 grams / 1 mole
112 g Fe x
56 grams 1 mole Fe
= 2 moles Fe
We already did this calculation when we solved the first problem so we could have started this problem with Step 2.
However, we did the calculation again for practice. Step 2: Convert moles of Fe to moles of CO2. Use the ratio from the balanced chemical equation. 4 moles of Fe are produced along with 3 moles of CO2
2 moles Fe x
4 moles Fe 3 moles CO
2 = 1.5 moles CO 2
Step 3: Convert moles of CO2 to grams of CO2.
Use the Gram Molecular Weight as a conversion factor. GMW of CO2 = 44 grams / 1 mole
1.5 moles CO
2 x
1 mole CO
2
44 grams
= 66 grams CO2
112 g of iron is 2 moles. The ratio of CO2 to Fe is 3 to 4, so 1.5 moles of CO2 is produced along with 2 moles of Fe.
1.5 moles of CO2 is 66 grams.
We have now calculated the amounts of each reactant and product in this equation starting from a single given amount.
Best of all we used a practical unit of measure (grams).
66 g
There is one more thing you should notice. Look at the total amount of the reactants compared to the total amount of the products.
Reactants 160 g + 18 g = 178 grams Products 112 g + 66 g = 178 grams
The total mass of reactants equals the total mass of products. This is confirmation of the Law of Conservation of Matter. Matter can’t be created or destroyed only changed in form.