Chapter 10
10.1 Alkynes
10.1 Alkynes
• Given the presence of two pi bonds and their associated electron density, alkynes are similar to alkenes in their ability to act as a nucleophile
10.1 Alkyne Uses
• Acetylene is the simplest alkyne• It is used in blow torches and as a precursor for the synthesis of more complex alkynes
• More than 1000 different alkyne natural products have been isolated
• One example is
histrionicotoxin, which can be isolated from South American frogs and is used on poison-tipped arrows by South
• An example of a synthetic alkyne is ethynylestradiol
• How do you think a CC triple bond affects the
molecules geometry? Its rigidity? Its intermolecular
10.1 Alkyne Uses
• Ethynylestradiol is the active
ingredient in many birth control pills
• The presence of the triple bond increases the potency of the drug compared to
10.2 Alkyne Nomenclature
• Alkynes are named using the same procedure we used in Chapter 4 to name alkanes with minor modifications
1. Identify the parent chain, which should include the CC triple bond
2. Identify and Name the substituents
3. Assign a locant (and prefix if necessary) to each substituent
giving the CC triple bond the lowest number possible
4. List the numbered substituents before the parent name in alphabetical order. Ignore prefixes (except iso) when ordering alphabetically
• Alkynes are named using the same procedure we used in Chapter 4 to name alkanes with minor modifications
1. Identify the parent chain, which should include the CC triple bond
10.2 Alkyne Nomenclature
• Alkynes are named using the same procedure we used in Chapter 4 to name alkanes with minor modifications
3. Assign a locant (and prefix if necessary) to each substituent
giving the CC triple bond the lowest number possible
10.2 Alkyne Nomenclature
• Alkynes are named using the same procedure we used in Chapter 4 to name alkanes with minor modifications
4. List the numbered substituents before the parent name in alphabetical order. Ignore prefixes (except iso) when ordering alphabetically
10.2 Alkyne Nomenclature
• In addition to the IUPAC naming system, chemists often use common names that are derived from the common parent name acetylene
10.2 Alkyne Nomenclature
• Name the molecule below10.3 Alkyne Acidity
• Recall that terminal alkynes have a lower pKa than other hydrocarbons
• Acetylene is 19 pKa units more acidic than ethylene, which is 1019 times stronger
10.3 Alkyne Acidity
• Because acetylene (pKa=25) is still much weaker than water (pKa=15.7), a strong base is needed to make it react, and water cannot be used as the solvent
• Recall from chapter 3 we used the acronym, ARIO, to rationalize differences in acidity strengths
10.3 Alkyne Acidity
• Use ARIO to rationalize the equilibria below10.4 Preparation of Alkynes
• Like alkenes, alkynes can also be prepared by10.4 Preparation of Alkynes
• Such eliminations usually occur via an E2 mechanism
• Geminal dihalides can be used
• Vicinal dihalides can also be used
10.4 Preparation of Alkynes
• Often, excess equivalents of NaNH2 are used to shift the equilibrium toward the elimination products
• NH21- is quite strong, so if a terminal alkyne is produced, it will be deprotonated
10.4 Preparation of Alkynes
• A proton source is needed to produce the alkyne10.5 Reduction of Alkynes
• Like alkenes, alkynes can readily undergo hydrogenation
• Two equivalents of H2 are consumed for each alkynealkane
conversion
• The cis alkene is produced as an
10.5 Reduction w/ a Poisoned Catalyst
• A deactivated or poisoned catalyst can be used toselectively react with the alkyne
10.5 Reduction w/ a Poisoned Catalyst
• Is this a syn or anti addition? • Practice with10.5 Dissolving Metal Reductions
• Reduction with H2 gives syn addition• Dissolving metal conditions can give Anti addition producing the trans alkene
• Ammonia has a boiling point = -33°C, so the
temperature for these reactions must remain very low
• Mechanism: Step 1
10.5 Dissolving Metal Reductions
• Note the single-barbed and double-barbed (fishhook) arrows.
10.5 Dissolving Metal Reductions
• Mechanism: Step 1
• Why is the first intermediate called a radical anion?
• Mechanism: step 2 and 3
• Mechanism: step 4
• Do the pKa values for NH3 and the alkene favor the proton transfer?
• Predict the product(s) for the following reaction
• Familiarize yourself with the reagents necessary to manipulate alkynes
• Like alkenes, alkynes also undergo hydrohalogenation
• Draw the final product for the reaction above
• Do the reactions above exhibit Markovnikov
• You might expect alkynes to undergo
hydrohalogenation by a mechanism similar to alkenes
• Yet, the mechanism above does not explain all observed phenomena
– A slow reaction rate, 3rd order overall rate law, like 1°
carbocations, vinylic carbocations are especially
10.6 Hydrohalogenation of Alkynes
• Kinetic studies on the hydrohalogenation of an alkyne suggest that the rate law is 1st order with respect to the alkyne and 2nd order with respect to HX
• What type of collision would result in such a rate law? Unimolecular, bimolecular, or termolecular?
• Reaction rate is generally slow for termolecular collisions. WHY?
• Considering the polarizability of the alkyne, does the mechanism explain the regioselectivity?
• Peroxides can be used in the hydrohalogenation of
alkynes to promote anti-Markovnikov addition just like with alkenes
• Which product is E and which is Z?
• The process proceeds through a free radical mechanism that we will discuss in detail in Chapter 11
• Like alkenes, alkynes can also undergo acid catalyzed Markovnikov hydration
• The process is generally catalyzed with HgSO4 to
compensate for the slow reaction rate that results from the formation of vinylic carbocation
• HgSO4 catalyzed hydration involves the mecury (II) ion interacting with the alkyne
• Can you imagine what that interaction might look like and how it will increase the rate of reaction for the process?
• The enol/ketone tautomerization generally cannot be prevented and favors the ketone greatly
• Tautomers are constitutional isomers that rapidly interconvert. How is that different from resonance?
• Hydroboration-oxidation for alkynes proceeds through the same mechanism as for alkenes giving the anti
-Markovnikov product
• It also produces an enol that will quickly tautomerize
• In this case, the tautomerization is catalyzed by the
• In general, we can conclude that a C=O double bond is more stable than a C=C double bond. WHY?
• After the –BH2 and –H groups have been added across the C=C double bond, in some cases, an undesired
second addition can take place
• To block out the second unit of BH3 from reacting with the intermediate, bulky borane reagents are often used
• Some bulky borane reagents are shown below
• Predict products for the following reaction
• Draw the alkyne reactant and reagents that could be used to synthesize the following molecule
• Markovnikov hydration leads to a ketone
• Anti-Markovnikov hydration leads to an aldehyde
• Alkynes can also undergo halogenation
• Two equivalents of halogen can be added
• You might expect the mechanism to be similar to the halogenation of alkenes, yet stereochemical evidence suggests otherwise – see next slide
• When one equivalent of halogen is added to an alkyne, both anti and syn addition is observed
• The halogenation of an alkene undergoes anti addition ONLY
• The mechanism for alkyne halogenation is not fully elucidated
• When alkynes react under ozonolysis conditions, the pi system is completely broken
• The molecule is cleaved, and the alkyne carbons are
• Predict the product(s) for the following reaction
• As acids, terminal alkynes are quite weak
• Yet, with a strong enough base, a terminal alkyne can be deprotonated and converted into a good nucleophile
• What has a higher pKa, NH3 or R-CC-H? WHY?
• The alkynide ion can attack a methyl or 1° alkyl halide electrophile
• Such reactions can be used to develop molecular complexity
• Alkynide ions usually act as bases with 2° or 3° alkyl halides to cause elimination rather than
• Acetylene can be used to perform a double alkylation
• Why will the reaction be unsuccessful if the NaNH2 and Et-Br are added together?
• Complex target molecules can be made by building a
• Recall the methods for increasing the saturation of alkenes and alkynes
• But, what if you want to reverse the process or decrease saturation? See next slide
• Halogenation of an alkene followed by two
dehydrohalogenation reactions can decrease saturation
• We will have to wait until chapter 11 to see how to
convert an alkane into an alkene, but here is a preview
• In the alkene to alkyne conversion above, why is water needed in part 3) of that reaction?
• Give necessary reaction conditions for the multi-step conversions below
Additional Practice Problems
• Name the moleculeAdditional Practice Problems
Additional Practice Problems
• Give a set of reagents that could be used to synthesize
cis-2-pentene from an addition reaction.
• Give a set of reagents that could be used to synthesize
Additional Practice Problems
• Give a set of reagents that could be used to synthesize a ketone from an addition reaction.