Exercise 1
Solving problems such as temperature conversion, student grading, income tax calculation, etc which expose the students to use basic C operators.
a) Temperature Conversion from Fahrenheit to Celsius. Program #include<stdio.h> #include<conio.h> void main() { float f,c; clrscr();
printf("\n Enter Temperature in F: "); scanf("%f",&f); c=5.0/9*(f-32); printf(" Temperature in C: %f",c); getch(); } Output Enter Temperature in F: 98 Temperature in C: 36.666668
b) Student grading based on his percentage. Program #include<stdio.h> #include<conio.h> void main() { int p; clrscr();
printf("\n Enter Percentage: "); scanf("%d",&p);
if(p>=70)
printf(" Distinction"); else if(p>=60&&p<70) printf(" First class"); else if(p>=50&&p<60) printf(" Second class");
else if(p>=40&&p<50) printf(" Third class"); else printf(" Fail"); getch(); } Output Enter Percentage: 73 Distinction
c) Average of three numbers Program #include<stdio.h> #include<conio.h> void main() { int a,b,c; float avg; clrscr();
printf("\n Enter a,b,c: "); scanf("%d%d%d",&a,&b,&c); avg=(float)(a+b+c)/3;
printf(" Avg: %f",avg); getch();
} Output
Enter a,b,c: 62 45 90 Avg: 65.666664
d) Largest among three numbers Program #include<stdio.h> #include<conio.h> void main() { int a,b,c; clrscr();
printf("\n Enter a,b,c: "); scanf("%d%d%d",&a,&b,&c); if(a>b) { if(a>c) printf(" a is large"); else printf(" c is large"); } else if(b>c) printf(" b is large"); else printf(" c is large"); getch(); } Output Enter a,b,c: 5 9 3 b is large
e) Income Tax calculation 0 – 2000000% 200000– 30000010% 300000– 50000020% Above 500000 30% Program #include<stdio.h> #include<conio.h> void main() {
long int a,tax=0; clrscr();
printf("\n Enter amount: "); scanf("%ld",&a); if(a<=200000) tax=0; else if(a>200000&&a<=300000) tax=(a-200000)*10/100; else if(a>300000&&a<=500000) tax=10000+(a-300000)*20/100; else if(a>500000) tax=50000+(a-500000)*30/100; printf(" Tax: %ld",tax);
getch(); } Output
Enter amount: 600000 Tax: 80000
Exercise 2
2’s complement of a number is obtained by scanning it from right to left and complementing all the bits after the first appearance of a 1. Thus 2’s complement of 11100 is 00100. Write a C program to find the 2’s complement of a binary number.
Program #include<stdio.h> #include<conio.h> #include<string.h> #include<stdlib.h> void main() { char a[20]; int i,j,k,len; clrscr();
printf("\n Enter Binary string: "); gets(a); len=strlen(a); for(k=0;a[k]!='\0';k++) { if(a[k]!='0'&&a[k]!='1') {
printf(" Incorrect Binary number..."); getch(); exit(0); } } for(i=len-1;a[i]!='1';i--); for(j=i-1;j>=0;j--) { if(a[j]=='1') a[j]='0'; else a[j]='1'; }
getch(); } Output
Enter Binary string: 110101010 2's complement: 001010110
Exercise 3
a) Write a C Program to find the sum of individual digits of a positive integer Program #include<stdio.h> #include<conio.h> void main() { int n,sum=0; clrscr(); printf("\n Enter n: "); scanf("%d",&n); if(n<0) {
printf("Enter positive integer.."); } else { while(n!=0) { sum=sum+n%10; n=n/10; }
printf(" Sum of individual digits: %d",sum); }
getch(); } Output Enter n: 2346
b) A Fibonacci sequence is defined as follows: the first and second terms in the sequence are 0 and 1. Subsequent terms are found by adding the preceding two terms in the sequence. Write a C program to generate the first n terms of the sequence.
Program #include<stdio.h> #include<conio.h> void main() { int a=0,b=1,c,n,i; clrscr(); printf("\n Enter n: "); scanf("%d",&n);
printf("\n The Fibonacci sequence...\n"); printf(" %d\n %d",a,b); for(i=3;i<=n;i++) { c=a+b; printf("\n %d",c); a=b; b=c; } getch(); } Output Enter n: 10
The Fibonacci sequence… 0 1 1 2 3 5 8
13 21 34
c) Write a C program to generate all the prime numbers between 1 and n, where n is a value supplied by the user.
Program #include<stdio.h> #include<conio.h> void main() { int i,j,n,count=0; clrscr(); printf("\n Enter n: "); scanf("%d",&n);
printf(" Prime numbers between 1 and %d are...",n); for(i=2;i<=n;i++) { count=0; for(j=2;j<=i-1;j++) { if(i%j==0) count++; } if(count==0) printf("\n %d",i); } getch(); } Output Enter n: 45
Prime numbers between 1 and 45 are... 2 3 5 7 11 13 17
19 23 29 31 37 41 43
d) Write a program which checks a given integer is Fibonacci number or not Program #include<stdio.h> #include<conio.h> void main() { int n,i,a[20],count=0; clrscr(); a[0]=0; a[1]=1; for(i=2;i<20;i++) { a[i]=a[i-1]+a[i-2]; } printf("\n Enter n: "); scanf("%d",&n); for(i=0;i<20;i++) { if(n==a[i]) { count++; break; } } if(count>0)
printf(" Fibonacci number..."); else
printf(" Not a fibonacci number..."); getch();
} Output Enter n: 144
Exercise 4
a) Write a C program to calculate the following Sum: Sum=1-x2/2! +x4/4!-x6/6!+x8/8!-x10/10! Program #include<stdio.h> #include<conio.h> #include<math.h> void main() {
long int i,t,f=1,k=1; float sum=1.0,x; clrscr(); printf("\n Enter x: "); scanf("%f",&x); for(i=2;i<=10;i=i+2) { t=i; while(t!=0) { f=f*t; t--; } sum=sum+(pow(-1,k)*pow(x,i))/(float)f; k++; f=1; }
printf("\n The Sum of Series: %f",sum); getch();
} Output
Enter x: 2
b) Write a C program toe find the roots of a quadratic equation. Program #include<stdio.h> #include<conio.h> #include<math.h> void main() { float a,b,c,d,p,q,x1,x2; clrscr();
printf("\n Enter a,b,c: "); scanf("%f%f%f",&a,&b,&c); d=b*b-4*a*c;
if(d==0) {
printf(" Roots are real and equal..."); printf("\n x1=x2=%f",-b/(2*a)); }
else if(d>0) {
printf(" Roots are real..."); x1=(-b+sqrt(d))/(2*a); x2=(-b-sqrt(d))/(2*a); printf("\n x1=%f \n x2=%f",x1,x2); } else //if(d<0) {
printf(" Roots are imaginary..."); p=-b/(2*a);
q=sqrt(-d)/(2*a); if(q<0)
printf("\n x1=%f+i%f x2=%f-i%f",p,-q,p,-q); else
printf("\n x1=%f+i%f x2=%f-i%f",p,q,p,q); }
} Output
Enter a,b,c: 4 4 1
Roots are real and equal... x1=x2=-0.500000
Exercise 5
a) The total distance traveled by vehicle in ‘t’ seconds is given by distance = ut+1/2at2 where ‘u’ and ‘a’ are the initial velocity (m/sec.) and acceleration (m/sec2). Write C program to find the distance traveled at regular intervals of time given the values of ‘u’ and ‘a’. The program should provide the flexibility to the user to select his own time intervals and repeat the calculations for different values of ‘u’ and ‘a’.
Program #include<stdio.h> #include<conio.h> void main() { float s,a,u; int t,n; clrscr();
printf("\n Enter Time Intervals: "); scanf("%d",&n);
for(t=0;t<=n;t++) {
printf(" Enter u and a: "); scanf("%f%f",&a,&u); s=u*t+0.5*a*t*t;
printf(" Distance traveled at %d time interval: %f \n",t,s); }
getch(); } Output
Enter Time Intervals: 2 Enter u and a: 2 7
Distance traveled at 0 time interval: 0.000000 Enter u and a: 4 9
Distance traveled at 1 time interval: 11.000000 Enter u and a: 3 4
Distance traveled at 2 time interval: 14.000000
b) Write a C program, which takes two integer operands and one operator form the user, performs the operation and then prints the result. (Consider the operators +,-,*, /, % and use Switch Statement) Program #include<stdio.h> #include<conio.h> void main() { int a,b,c; char op; clrscr();
printf("\n Enter a,b: "); scanf("%d%d",&a,&b);
printf(" Enter Operator (+,-,*,/,%): "); op=getche();
switch(op) {
case '+': c=a+b; break; case '-': c=a-b; break; case '*': c=a*b; break; case '/': c=a/b; break; case '%': c=a%b; break;
default : printf("\n Enter correct operator.."); getch(); exit(0); } printf("\n Result: %d",c); getch(); } Output Enter a,b: 87 34 Enter Operator (+,-,*,/,%): % Result: 19
Exercise 6
a) Simple programming examples to manipulate strings. Program #include<string.h> void main() { char a[10]="srinivas",b[10]="KRISHNA",c[10]="srinivas",d[10],e[20]; int len; clrscr(); len=strlen(a); printf("\n Length=%d",len); strcpy(d,a); printf("\n %s",d); strcpy(e,a); strcat(e,b); printf("\n %s",e); strrev(d); printf("\n %s",d); strlwr(b); printf("\n %s",b); strupr(a); printf("\n %s",a);
if(strcmp(a,c)==0) //compares with case sensitivity printf("\n Two strings are equal ");
else
printf("\n Two strings are not equal");
if(stricmp(a,c)==0) //compares without case sensitivity printf("\n Two strings are equal");
else
printf("\n Two strings are not equal"); getch();
} Output
Length=8 srinivas srinivasKRISHNA savinirs krishna SRINIVAS
Two strings are not equal Two strings are equal
b) Verifying a string for its palindrome property
Program #include<stdio.h> #include<conio.h> #include<string.h> void main() { char a[20]; int len,i; clrscr();
printf("\n Enter String: "); gets(a); len=strlen(a); for(i=0;i<len/2;i++) { if(a[i]==a[len-1]) len--; else {
printf("\n Not Palindrome..."); getch(); exit(); } } printf("\n Palindrome…"); getch(); } Output
Enter String: srinirs Palindrome…
Exercise 7
Write a C program that uses functions to perform the following operations i) To insert a sub-string in to given main string from a given position. Program #include<stdio.h> #include<conio.h> #include<string.h> void main() { int i,p,n,r,k,j=0; char a[20],b[10],c[30]; clrscr();
printf("\n Enter the Main String: "); gets(a);
printf(" Enter the String to insert: "); gets(b);
printf(" Enter position to insert: "); scanf("%d",&p); n=strlen(a); r=strlen(b); for(i=0;i<p-1;i++) c[i]=a[i]; k=i; for(i=p-1;i<p+r-1;i++) c[i]=b[j++]; for(i=p+r-1;i<n+r;i++) c[i]=a[k++]; c[i]='\0';
printf(" Resultant String: %s",c); getch();
} Output
Enter the Main String: srinivas Enter the String to insert: Hari Enter position to insert: 4 Resultant String: sriHarinivas
ii) To delete n Characters from a given position in a given string. Program #include<stdio.h> #include<conio.h> #include<string.h> void main() { char a[20]; int i,p,len,n,k; clrscr();
printf("\n Enter String: "); gets(a);
len=strlen(a);
printf(" Enter Position: "); scanf("%d",&p);
printf(" Enter Number of chars to delete: "); scanf("%d",&n);
k=p+n-1;
for(i=p-1;i<len-n;i++) a[i]=a[k++];
a[i]='\0';
printf(" Resultant String: %s",a); getch();
} Output
Enter String: srinivas Enter Position: 4
Enter Number of chars to delete: 2 Resultant String: srivas
iii) To replace a character of a string either from beginning or ending or at a specified location. Program #include<stdio.h> #include<conio.h> #include<string.h> void main() { char a[20],ch; int choice,pos,len; clrscr();
printf("\n Enter string: "); gets(a);
printf(" 1.At Begin \n 2.At End \n 3.At position \n"); printf(" Enter choice: ");
scanf("%d",&choice); switch(choice)
{
case 1: printf(" Enter character to replace at begin: "); ch=getche();
a[0]=ch;
printf("\n New string: %s",a); break;
case 2: printf(" Enter character to replace at end: "); ch=getche();
len=strlen(a); a[len-1]=ch;
printf("\n New string: %s",a); break;
case 3: printf(" Enter character to replace at given position: "); ch=getche();
printf("\n Enter position: "); scanf("%d",&pos);
a[pos-1]=ch;
printf(" New string: %s",a); break;
default:printf(" Enter correct choice"); break; } getch(); } Output
Enter string: sri nivas 1.At Begin
2.At End 3.At position Enter choice: 1
Enter character to replace at begin: Q New string: Qri nivas
Enter string: sri nivas 1.At Begin
2.At End 3.At position Enter choice: 2
Enter character to replace at end: W New string: sri nivaW
Enter string: sri nivas 1.At Begin
2.At End 3.At position Enter choice: 3
Enter character to replace at given position: Z Enter position: 4
Exercise 8
Write a C program that uses functions to perform the following operations: i) Reading a complex number
ii) Writing a complex number
iii) Addition of two complex numbers iv) Multiplication of two complex numbers Program
#include<stdio.h> #include<conio.h>
struct complex add(struct complex a,struct complex b); struct complex mul(struct complex a,struct complex b); void write(struct complex s);
struct complex read(); struct complex { float r,i; }; void main() {
struct complex a,b,c; int ch;
clrscr();
printf("\n Enter Real and Imag for 1st Complex Number: "); a=read();
printf("\n Enter Real and Imag for 2nd Complex Number: "); b=read();
printf("\n 1.Add \n 2.Multiplication "); printf("\n Enter choice: ");
scanf("%d",&ch); switch(ch)
case 1 : c=add(a,b); write(c); break; case 2 : c=mul(a,b); write(c); break;
default: printf("\n Enter Correct choice.."); break;
} getch(); }
struct complex read() {
struct complex s;
scanf("%f%f",&s.r,&s.i); return s;
}
struct complex add(struct complex a,struct complex b) { struct complex s; s.r=a.r+b.r; s.i=a.i+b.i; return s; }
struct complex mul(struct complex a,struct complex b) { struct complex s; s.r=a.r*b.r-a.i*b.i; s.i=a.r*b.i+a.i*b.r; return s; }
void write(struct complex s) { if(s.i>0) printf("\n Result=%f+i%f",s.r,s.i); else printf("\n Result=%f-i%f",s.r,-1*s.i); } Output
Enter Real and Imag for 1st Complex Number: 3 -2
Enter Real and Imag for 2nd Complex Number: -5 6
1.Add
2.Multiplication Enter choice: 2
Result=-3.000000+i28.000000
Exercise 9
a) Addition of two matrices Program #include<stdio.h> #include<conio.h> void main() { int a[4][4],b[4][4],c[4][4],i,j,m,n,p,q; clrscr();
printf("\n Enter Order for 1st Matrix: "); scanf("%d%d",&m,&n);
printf("\n Enter Order for 2nd Matrix: "); scanf("%d%d",&p,&q);
if((m==p)&&(n==q)) {
printf("\n Enter 1st Matrix elements: "); for(i=0;i<m;i++) { for(j=0;j<n;j++) { scanf("%d",&a[i][j]); } }
printf("\n Enter 2nd Matrix elements: "); for(i=0;i<p;i++) { for(j=0;j<q;j++) { scanf("%d",&b[i][j]); } }
printf("\n Addition of two matrices: \n"); for(i=0;i<m;i++)
for(j=0;j<n;j++) { c[i][j]=a[i][j]+b[i][j]; printf("%d \t",c[i][j]); } printf("\n"); } } else {
printf("\n Addition not possible..."); }
getch(); }
Output
Enter Order for 1st Matrix: 3 2 Enter Order for 2nd Matrix: 3 2 Enter 1st Matrix elements: 1 2
3 4 5 6
Enter 2nd Matrix elements: 6 5
4 3 2 1
Addition of two matrices: 7 7
7 7 7 7
b) Calculating transpose of matrix in-place manner Program #include<stdio.h> #include<conio.h> void main() { int a[4][4],b[4][4],i,j,m,n; clrscr();
printf("\n Enter Order for matrix: "); scanf("%d%d",&m,&n);
printf(" Enter Matrix elements: "); for(i=0;i<m;i++) { for(j=0;j<n;j++) { scanf("%d",&a[i][j]); b[j][i]=a[i][j]; } }
printf(" Transpose of Matrix: "); for(i=0;i<n;i++) { printf("\n"); for(j=0;j<m;j++) { printf("%d \t",b[i][j]); } } getch(); } Output
Enter Order for matrix: 3 4 Enter Matrix elements:
1 2 3 4 5 6 7 8 9 10 11 12 Transpose of Matrix: 1 5 9 2 6 10 3 7 11 4 8 12
c) Matrix Multiplication by checking compatibility Program #include<stdio.h> #include<conio.h> void main() { int a[4][4],b[4][4],c[4][4],i,j,m,n,p,q,k; clrscr();
printf("\n Enter Order for 1st Matrix: "); scanf("%d%d",&m,&n);
printf("\n Enter Order for 2nd Matrix: "); scanf("%d%d",&p,&q);
if(n==p) {
printf("\n Enter 1st Matrix elements: "); for(i=0;i<m;i++) { for(j=0;j<n;j++) { scanf("%d",&a[i][j]); } }
printf("\n Enter 2nd Matrix elements: "); for(i=0;i<p;i++) { for(j=0;j<q;j++) { scanf("%d",&b[i][j]); } }
printf("\n Multiplication of two matrices: \n"); for(i=0;i<m;i++)
{
for(j=0;j<q;j++) {
c[i][j]=0; for(k=0;k<n;k++) c[i][j]=c[i][j]+a[i][k]*b[k][j]; printf("%d \t",c[i][j]); } printf("\n"); } } else {
printf("\n Multiplication not possible..."); }
getch(); } Output
Enter Order for 1st Matrix: 3 3 Enter Order for 2nd Matrix: 3 2
Enter 1st Matrix elements: 1 2 3 4 5 6 7 8 9 Enter 2nd Matrix elements: 6 5 4 3 2 1 Multiplication of two matrices:
20 14 56 41 92 68
Exercise 10
a) Write C programs that use both recursive and non-recursive functions.
i) To find the factorial of a given integer.
Program using Non-Recursive #include<stdio.h> #include<conio.h> void main() { int f=1,i,n; clrscr(); printf("\n Enter n: "); scanf("%d",&n); for(i=1;i<=n;i++) { f=f*i; }
printf("\n Factorial of %d is: %d",n,f); getch();
} Output Enter n: 7
Factorial of 7 is: 5040
Program using Recursive #include<stdio.h>
#include<conio.h> void main()
{
int f,i,n; clrscr();
printf("\n Enter n: "); scanf("%d",&n);
printf("\n Factorial of %d is: %d",n,fact(n)); getch(); } int fact(int n) { int p; if(n==1) return 1; else p=n*fact(n-1); return p; } Output Enter n: 7 Factorial of 7 is: 5040
ii) To find the GCD (greatest common divisor) of two given integers.
GCD using Non-Recursive #include<stdio.h> #include<conio.h> void main() { int a,b,gcd,i,m; clrscr();
printf("\n Enter a,b: "); scanf("%d%d",&a,&b); if(a>b) m=b; else m=a; for(i=1;i<=m;i++) { if(a%i==0&&b%i==0) gcd=i;
}
printf("\n GCD of %d and %d is: %d",a,b,gcd); getch(); } Output Enter a,b: 36 24 GCD of 36 and 24 is: 12 GCD using Recursive #include<stdio.h> #include<conio.h> void main() { int a,b; clrscr();
printf("\n Enter a,b: "); scanf("%d%d",&a,&b);
printf("\n GCD of %d and %d is: %d",a,b,gcd(a,b)); getch();
}
int gcd(int a,int b) { if(b>a) return gcd(b,a); if(b==0) return a; else return gcd(b,a%b); } Output Enter a,b: 36 24 GCD of 36 and 24 is: 12
iii) To solve Towers of Hanoi problem.
Program using Recursive #include<stdio.h>
#include<conio.h>
void towers(int n,char src, char target, char temp); void main()
{ int n; clrscr();
printf("\n How Many disks: "); scanf("%d",&n);
towers(n,'A','C','B'); getch();
}
void towers(int n, char src, char target, char temp) {
if(n==1) {
printf("\n Move top disk from %c to %c",src,target); return;
}
towers(n-1,src,temp,target);
printf( "\n Move top disk from %c to %c",src,target); towers(n-1,temp,target,src);
} Output
How Many disks: 4
Move top disk from A to B Move top disk from A to C Move top disk from B to C Move top disk from A to B Move top disk from C to A Move top disk from C to B Move top disk from A to B Move top disk from A to C Move top disk from B to C Move top disk from B to A Move top disk from C to A Move top disk from B to C Move top disk from A to B Move top disk from A to C Move top disk from B to C
Exercise 11
a) Write a C Function to find both largest and smallest numbers of an array of integers. Program #include<stdio.h> #include<conio.h> void main() { int a[10],n,i,max,min; clrscr(); printf("\n Enter n: "); scanf("%d",&n);
printf(" Enter elements: "); for(i=0;i<n;i++) scanf("%d",&a[i]); min=max=a[0]; for(i=0;i<n;i++) { if(a[i]<min) min=a[i]; if(a[i]>max) max=a[i]; }
printf(" Largest=%d \n Smallest=%d ",max,min); getch(); } Output Enter n: 6 Enter elements: 1 5 -65 8 936
421
Largest=936 Smallest=-65
b) Write a C function that uses functions to perform the following.
i) Write a C program that displays the position or index in the string S where the string T begins, or – 1 if S doesn’t contain T. Program #include<stdio.h> #include<conio.h> #include<string.h> void main() { char s[20],t[10],*found; clrscr();
printf("\n Enter String: "); gets(s);
printf(" Enter Substring to find: "); gets(t);
found=strstr(s,t); if(found)
printf(" Found at %d position...",found-s+1); else
printf(" Substring not found..."); getch();
} Output
Enter String: srinivas Enter Substring to find: iva Found at 6 position
ii) Write a C program to count the lines, words and characters in a given text. Program
#include<stdio.h> #include<conio.h> #include<string.h> void main() { char a[80],ch; int i,k,end=0,nc=0,nw=0,nl=0; clrscr();
printf("\n Enter the Text and press ENTER at end..\n"); while(end==0) { k=0; while((ch=getchar())!='\n') a[k++]=ch; a[k]='\0'; if(a[0]=='\0') break; else { nw++; for(i=0;a[i]!='\0';i++) { if(a[i]==' '||a[i]=='\t') nw++; } } nl=nl+1; nc=nc+strlen(a); }
printf("\n Number of Lines : %d",nl); printf("\n Number of Words : %d",nw); printf("\n Number of Characters: %d",nc); getch();
}
Output
Enter the Text and press ENTER at end.. Hello World
Number of Lines : 2 Number of Words : 6 Number of Characters: 27
Exercise 12
a) Write a C function to generate Pascal’s triangle. Program #include<stdio.h> #include<conio.h> void main() { int p=1,y=0,i,r,x; clrscr();
printf("\n Rows you want to input: "); scanf("%d",&r);
printf("\n Pascal's Triangle:\n"); while(y<r) { for(i=40-3*y;i>0;i--) printf(" "); for(x=0;x<=y;x++) { if((x==0)||(y==0)) p=1; else p=(p*(y-x+1))/x; printf("%6d",p); } printf("\n"); y++; } getch(); } Output
Pascal's Triangle: 1 1 1 1 2 1 1 3 3 1 1 4 6 4 1 1 5 10 10 5 1
b) Write a C function to construct a pyramid of numbers. Program #include<stdio.h> #include<conio.h> void main() { int n,i,y,x=35; clrscr(); printf("\n Enter n: "); scanf("%d",&n);
printf("\n Pyramid Triangle \n"); for(y=0;y<=n;y++) { gotoxy(x,y+4); for(i=-y;i<=y;i++) printf("%2d",abs(i)); x=x-2; } getch(); } Output Enter n: 4 Pyramid Triangle 0 1 0 1 2 1 0 1 2 3 2 1 0 1 2 3 4 3 2 1 0 1 2 3 4
Exercise 13
Write a C program to read in two numbers, x and n, and then compute the sum of this geometric progression: 1+x+x2+x3+………….+xn Program #include<stdio.h> #include<conio.h> #include<math.h> void main() { int i,x,n; long int sum; clrscr();
printf("\n Enter the values for x and n: "); scanf("%d%d",&x,&n);
if(n<=0||x<=0) {
printf("\n Value is not valid.."); getch(); main(); } else { sum=1; for(i=1;i<=n;i++) { sum=sum+pow(x,i); }
printf("\n Sum of series: %ld",sum); }
getch(); } Output
Enter the values for x and n: 5 3 Sum of series: 156
Write a C function to read in two numbers, x and n (number of terns) and then compute sin(x) and cos(x). cos(x)=1-x2/2!+x4/4!-x6/6!+x8/8!-……. Program #include<stdio.h> #include<conio.h> #include<math.h> void main() {
long int i,t,f=1,k=1,n; float sum=1,x; clrscr(); printf("\n Enter x: "); scanf("%f",&x); printf(" Enter n: "); scanf("%ld",&n); for(i=2;i<n*2;i=i+2) { t=i; while(t!=0) { f=f*t; t--; } sum=sum+(pow(-1,k)*pow(x,i))/f; k++; f=1; }
printf("\n cos(x)= %f",sum); getch();
} Output
Enter x: 2 Enter n: 6 cos(x)= -0.416155 sin(x)=x-x3/3!+x5/5!-x7/7!+x9/9!-……. Program #include<stdio.h> #include<conio.h> #include<math.h> void main() {
long int i,t,f=1,k=1; float sum,x; clrscr(); printf("\n Enter x: "); scanf("%f",&x); printf(" Enter n: "); scanf("%ld",&n); sum=x; for(i=3;i<n*2;i=i+2) { t=i; while(t!=0) { f=f*t; t--; } sum=sum+(pow(-1,k)*pow(x,i))/f; k++; f=1; }
printf("\n sin(x)= %f",sum); getch();
} Output Enter x: 2 Enter n: 4
