ON
THE
DIFFERENTIABILITY OF
T(r,f)
DOUGLAS W.
TOWNSEND
Department
of Mathematical SciencesIndiana University-Purdue University
at Fort Wayne
Fort Wayne,
Indiana46805
U.S.A.
(Received
June
16,
1980)
ABSTRACT.
It
is well known thatT(r,f)
is differentiableat
least for r > r0.
We
show that, in fact,T(r,f)
is differentiable for all but atmost
one value ofr,
and ifT(r,f)
failsto
have a derivative for some value of r, then f is acon-stant
times a quotient of finite Blaschke products.KEY
WORDSAND PHRASES.
Nevanlinna Theory, Nevanlinna Characteristic Function.1980
MATHEMATICS SUBJECT CLASSIFICATION CODE:
30A70
i. INTRODUCTION.
In
thispaper
we will discuss the differentlability of the Nevanlinna charac-teristic function,T(r,f),
for f meromorphic inIzl
< R <.
As
early as1929
Cartan stated in
[13
thatT(r,f)
is differentiable, and gave a formula fordT(r,f)/d
logr,
but didnot
indicate whether the derivative may fallto
existfor some values of r.
We
will show thatT(r,f)
is differentiable for all butat
most
one value ofr,
and if the derivative failsto
exist for some value ofr,
then f is a
constant
times a quotient of finite Blaschke products.2.
DEFINITIONS AND STATEMENT
OFTHE THEOP.
DEFINITION.
r<R,
1,
Let
f be a meromorphic function inzl
<R
< (R). Then forn(r,f)
n(r,(R),f)
the number of poles of f inIzl
<r,
and1
..a)
the number of solutionsto
the equationn(r,a,f)
n(r,
f
2.
N(r,f)
N(r,(R),f)
r
f(z)
a inIzl
< r.n(t,f)
n(0,f
dt +n(O,f)log
r,
andt
0
1
N(r,a,f)
N(r,f
a).
1
i
+f(re+/-e’)
de andm(r,f)
-
0m(r,a,f)
m(r,
1___)
f4.
T(r,f)
m(r,f)
+N(r,f),
and1
+
N(r,
..1.
)
T(r,a,f)
T(r,
m(r,
f a
f-For
thepurposes
of thispaper
we define the additional functional5.
n-(r,a,f)
n(r,a,f)
{the number of solutionsto f(z)
a onIzl
r).We
note
that the derivative ofN(r,a,f)
from the right withrespect to
log ris
n(r,a,f)
n(0,a,f),
and the derivative from the left withrespec
to
log r isn-(r,a,f)
n(0,a,f)
Thus, dN(r,a,f)
d log r
n(r,a,f)
n(0,a,f)
providedf(z) #
a onIzl
r. SinceN(r,a,f)
is continuous andn(r,a,f)
n(0,a,f)
ismonotonically increasing,
N(r,a,f)
is an increasing convex function of log r.The following lemma, which we
state
without proof, givesa characterization ofT(r,f)
which has provedto
be ofgreat
importance in thedevelopment
ofNevanlinna theory.
We
will base our discussion of the differentiability ofT(r,f)
largely on this lemma.CARTAN’S
LEMMA. If f is meromorphic inIzl
<R
and 0 < r <R,
then 2ni
N(r,ele
log+if(0)l.
T(r,f)
=
,f)
d +0
a well known theorem concerning convex functions,
T(r,f)
has derivatives from the right and from the left for all r > 0, and is differentlable for all butat
most
countablymany
values of r.We
give an example to show thatT(r,f)
neednot
be differentiable for all values of r.EXAMPLE.
Let
f(x)
2 1 + iz/2i + 2iz The function f is a
one-to-one map
of theextended plane,
8,
onto
8,.and
takes the unit circleonto
the unit circle. Thus,for all real
e,
n(r’eie’f)
=01
if r >
lif
r < iAlso,
N(r,eie,f)
n(t
dtt
flog
r if r > 1and by
Cartan’
sLemma
1
T(r,f)
log 2N(r,eie,f)
de0(
if r< 1
og r if r > 1 0
Thus,
T(r,f)
isnot
differentiableat
r 1.That this example is representative of the class
f
functions for whichT(r,f)
failsto
have a derivative for some value ofr,
is evident from theproof
of the following theorem.THEORg.
Let
f be anonconstant
meromorphic function inIzl
<R
(R). ThenT(r,f)
is differentiable for all butat
most
one value of r < R. IfT(r,f)
failsto
have a derivativeat
r r0, then f is aconstant
times a quotient of finite Blaschke products.3.
PROOF OFTHE
TkOREM.STEP i.
In
thispart
of the proof we will use the fact that for r < rI
n(r,a,f)
is uniformly bounded for all a e C by a finiteconstant
depending< R
only on r
I.
Suppose
that 0 <r’
< r0 <
r"
<R,
and consider asequence
{rk}
satisfyingr’
< rBy Cartan’
sLemma
we haveT(rk’f)
T(ro’f)
illm
rk_
r0
limm
2k k 21
N(rk,eie,f)
N(r0,eie,f
rl’
r 0 0 de.(B.1)
Since
n(r,a,f)
<K(r")
for all a aC
and all r <r"
the integrand of theintegral in
(3.
I)
isr
k
I
r0
n(t,eie,f)t
-I
dtn(t,eie,f)t
-1dt)(r
k
r0)-i
0 0
r
k
log r
k log
r0
<
K(r’,r")
iele
t-I
r"
-rk_
r.
0n(t,
,f)
dt <K(
rk
r0
r 0
where
K(r’,r")
is aconstant
depending only onr’
andr".
Therefore, by the Lebesgue Dominated Convergence Theorem2w
T(rk’f)
T(ro’f)
1 lira r-r k k 0 0 limr
k r0 k
N(rk,e
ie,f)
N(r
0,eie,f)
d8,
provided the limit in the integrand above exists off a set of Lebesge measure
zero.
From
the definition ofN(r,a,f)
we have thatlim k
N(rk,eiO,f)-
N(r0,e
ie,f)
n(r0,eie,f)
rk r0 r0
provided
f(r0ei)
W
eiea
set
of measure zero then, since {rk}
is an arbitrary sequence convergingto
r0,
2
r0
dT(.rf)
l__
n(r0,e
ie
f)
de.dr 2
r=r0
0i
STEP 2.Suppose
that for some r0 <
R,
If(r0e
)I
1 for 1,2,3... and limCj
0"
Let L
1 be a linear fractional transformation mapping the real line
J
to
zl
r0 and a linear fractional transformation mapping
zl
1to
the realline.
Let
gL
2 f
L
1. Then g is meromorphic in a neighborhood of the realaxis and there exists a finite x0 which is a limit point of {x
g(x)
is real}.for all 0
_
_
27. Therefore, iff(roel)
i only onFrom
elementary power series considerations it follows that g is(extended)
real-everywhere on the real axis.
Hence,
If(r0ei)
1 for all 0 27. valuedThus, for an interval of
e
values in[0,2)
having positive lengthn(r0,eie,f) n-(ro,eie,f)
+ 1. If rk+r
0, then as in
Step
1 above2
(rk’f)
(r0’f)
1lim
r
k r
k- 0
0
llm
,e
ieN(r
k
eie,f)
N(r
0,f)
k
rk
r0
(3.2)
1
n-(r0,eie,f) r0-1
deSimilarly, if
rk+r0,
thenT(rk’f)
T(r0’f)
1,ei8
lim
n(r
0
f)r81
de(3
4)
r
k r0 k+
0
By
(3.2)
the limits in(3.3)
and(3.4)
arenot
equal and henceT(r,f)
fails tohave a derivative
at
r r 0.To summarize
steps
1 and 2, eitherIf(z)l
1 finitely often onIzl
r0,in which case
T(r,f)
possesses a derivativeat
r r0, orIf(z)l
1 everywhereon
Izl
to,
in which caseT(r,f)
failsto
have a derivativeat
r r 0.STEP
3.
Suppose
f(z)l
1 everywhere onzl
r0.
Let
the zeros and poles of f, counting multiplicity, inIzl
< r0 be
(al,a
2 aM
and{b
1,b
2 bN},
respectively. DefineM
lajl
1zal
/
NIbl
1zb
1H
r0
zr
2B(z)
j=IH
r0
i-jzr
2 j=lI
b%
lal
i za-I
The function
P(z)
is a Blaschke factor having a zeroat
ro
1zr
2z a and a pole at z
r()
-I
and having modulus one onIzl
r0 Thus
f(z)
(z)
and
and have modulus one on
zl
rO.
It
follows from the maximum modulus theorem thatf(z)=
aB(z),
whereII
1.It
remains onlyto
show thatIf(z)ol
1 onIzl
r forat
most one
valueof r.
Noe
that from the aboveargument,
ifIf(z)
1 forIzl
ro,
thenf(z)
has as
many
zeros(poles)
inIzl
< r0 as it has poles
(zeros)
inIzl
> rO.
Iff(z)l
1 forzl
r
>ro,
then by the same argumentf(z)
has asmany
zeros
(poles)
inzl
<r8
as it has poles(zeros)
inzl
r.
It
follows readily thatf(z)
must have no zeros or poles in rn <Izl
<r.
Therefore,
f(z)
and1
are analytic in r
0 <
zl
<r
and both have modulus one onzl
r0 andzl
r.
By
the MaximumModulus Theorem,f(z)
must
be aconstant,
which contradicts one of the hypotheses.Hence,
If(z)l
1 onIzl
r forat
most
one value of r, which completes the proof of the theorem.If we let
(r,f)
be the number of solutions of the equationIf(z)l
1 forzl
r, then we have shown that(r,f)
< for all butat most
one value of r.Questions concerning the growth of
(r,f)
have been posed in[2]
and[3],
and these questions have been investigated by the author and J. Miles in[4]
and[5].
REFERENCES
i.
Cartan,
H. Sur ladrive
parrapport
log r de la fonction de croissanceT(r,f),
Comptes Rendus,189
(1929),
p.525-527.
2. Clunie, J. and
W. K.
Hayman,
editors, Symposium on complex analysis, London Mathematical SocietyLecture Note
Series 12,1973.
3.
Hellerstein, S. The distribution of values of a meromorphic function and a theorem ofH.
S. Will, DukeMath,
J_.
32
(1965),
p.749-764
4.
Miles, J. and D.Townsend,
Imaginary values of meromorphic functions, Indiana University Mathematics Journal, Vol. 27, No.3
(1978),
p.
491-503.
5.
Townsend, D. Imaginary values of meromorphic functions in the disk,