To Asymptotic of the Solution of the Heat Conduction
Problem with Double Nonlinearity with Absorption
at a Critical Parameter
Aripov M.*, Mukimov A., Mirzayev B.
National University of Uzbekistan Named after M. Ulugbek, Uzbekistan
Received September 17, 2019; Revised October 30, 2019; Accepted November 12, 2019
Copyright©2019 by authors, all rights reserved. Authors agree that this article remains permanently open access under the terms of the Creative Commons Attribution License 4.0 International License
Abstract
We study the asymptotic behavior (for ) of solutions of the Cauchy problem for a nonlinear parabolic equation with a double nonlinearity, describing the diffusion of heat with nonlinear heat absorption at the critical value of the parameter . For numerical computations as an initial approximation we used founded the long time asymptotic of the solution. Numerical experiments and visualization were carried for one and two dimensional case.Keywords
Heat Conduction Problem, Critical Value of Parameter, Absorption, Maximum Principle, Numerical Computation, Visualization1. Introduction
As is well known for the numerical computation of a nonlinear problem, the choice of the initial approximation is essential, which preserves the properties of the final speed of propagation, spatial localization, bounded and blow-up solutions, which guarantees convergence with a given accuracy to the solution of the problem with minimum number of iterations.
It is very important to establish the values of numerical parameters at which the nature of the asymptotic behavior of the solution will change. Such values of numeric parameters are called critical or critical values of the Fujita type. He first established this for the semi-linear heat equation [1]. At the critical parameters we can observe new effects such as infinite energy, localization and others.
In the domain the
following Cauchy problem
(1)
(2) t and x are, respectively, the temporal and spatial
coordinates where given numerical
parameters, characterizing the nonlinear medium
, ( -critical value,
N-size of dimension). In case k=1, critical value of parameter was found in [2].
Problem (1.1) - (1.2) is the basis for modeling various processes of nonlinear heat diffusion, magnetic hydrodynamics, gas and liquid filtration, oil and gas, in the theory of non-Newtonian fluids, etc.
Under some suitable assumptions, the existence, uniqueness and regularity of a weak solution to the Cauchy problem (1.1) - (1.2) and their variants have been extensively investigated by many authors (see [3–5] and the references therein).
If the initial value is respectively smooth, there are many papers on the solvability of the Cauchy problem (1.1)-(1.2), we can refer to Wu-Zhao [6], Gmira [7], Yang-Zhao [8], Zhao [9-11], Zhao-Yuan [12], Dibenedetto-Friedman [13], LiHia [14], Dibenedetto-Herrero [15], Beniland-Crandal Pierre [16], Zhao-Xu [17], Fan [18] and links to them for details.
A lot of works studied properties of solutions of problem with critical value of parameter and were established asymptotic behavior for (see [1], [2], [19]-[27]). The long time asymptotic of solutions has been established for the critical value of parameter for problem (1.1)-(1.2) in case k=1, m=1, in [19],
case p=2, in [20].
In [21] authors were established the long time asymptotic of solutions for the critical value of parameter
t
→ ∞
β
{( , ) :
0,
N}
Q
=
t x t
>
x
∈
R
(
m1 k p2)
*u
u u u u
t
β −
−
∂ = ∇ ∇ ∇ −
∂
0
(0, )
( ),
Nu
x
=
u x
x
∈
R
1, 1, 2
m≥ k≥ p≥
( ) ( )
x
grad
∇ ⋅ = ⋅ * ( 2)
p
k p m
N
β = − + + β*
* β
0
( , 0) ( )
u x =u x
β
t
→ ∞
β
*
p
1
p N
/
β = − +
*
m
2 /
N
for problem (1.1) - (1.2) in case m=1, p=2. They considered following semi-linear parabolic equation
(3) (4)
The solution of problem (3) - (4) is “infinity” energy. The initial data is
They proved that for problem (3) - (4) the long time asymptotic of the solutions is the following approximate self-similar solution
(5)
For function upper and lower bounds were obtained
, where A, H –constants.
For , the approximate self-similar differs from (5), which means that for critical values the asymptotic of the solutions will change for .
In [22] was considered following nonlinear heat equation with absorption
in area (6)
for (7) Authors established the long time asymptotic of the solution for the critical exponent .
The following asymptotic
(8)
where the value of the numerical parameter a is determined from the law of energy conservation
where
В and Г is beta and gamma of Euler function.
They proved that solution (8) is the long time asymptotic of the solution to problem (6) - (7) by constructing lower and upper solutions. The following lower and upper solution with variable a
In [23] authors gave bounds for the blow-up rate of solution the following nonlinear parabolic equation
in
where is a radial function and for simplicity it taken like this ,
Here are some of them
Where , ,
,
(H gives the correct space-time scaling near the blow-up time, B gives the blow-up rate).
In [24] established conditions of norm of solution with critical exponent for following Cauchy problem
in
Here are some of them
2 1
N β = +
0,
0
t
u
− ∆ +
u
u
β=
t
>
0
(0, )
( )
0
u
x
=
u x
≥
2 2 1
2
/ , 1
N i
i= x β N ∆ =
∑
∂ ∂ = +2
0
( )
{exp(
)},
u x
=
o
−
γ
x
x
→ +∞
0
γ
>
[
]
2* 1
2
( , ) ( ) ln( )
( )
N x
u t x T t T t g
T t
−
= + +
+
*
g
2 2
*
exp ( ) exp
4 4
A − ξ ≤g ξ ≤H − ξ
2
2
x
T
t
ξ =
+
2 1
N
β≠ +
t
→ ∞
1
(u
)
u
t
u
= ∆
σ+−
βQ
=
R
N×
(0, )
∞
0
( , 0)
( )
u x
=
u x
x
∈
R
N* 1 2 /N
β β σ
= = + +u(x, t)
=
((
T
+
t
) ln(T t))
+
−kF
( ;a)
ξ
/ /2
(T t) k Nln(T t)k
x σ
ξ
= + − +[
]
2 2 1/ 0
1/ 0
/ (N 2), F( ;a) C (a ) ,
C / 2 ( 1) , 1
k N
k N T
σ σ
σ
ξ
ξ
σ
σ
+
= + = −
= + >
(x, t) dx ( ;a) d
M
w = F
ξ
ξ
=M∫
∫
/ 1
N k
M =C a σ /2
1 0
(N/ 2,1 1 /
) /
Г(N/ 2)
N
C
=
π
C B
+
σ
(( ) log(T t)) ( ;a ) u(x, t) (( ) log(T t)) ( ;a )
k
k
T t F
T t F
ξ ξ
− − −
−
+ + ≤ ≤
≤ + +
0<a− <a+
1 1
(
m)
( )
pt
u
−
div u
−Du
λ−Du
=
f x u
(0, ), 0
T
Q = Ωx T < < ∞T
( )
f x
( )
f x
=
x
−α −∞ < <α min( ,N λ+1)( , )
(
)
Bu x t
≤
γ
T
−
t
−0
γ
>
1/( ) H / 2
x < T−t
0< + − < < + − +m
λ
1 p mλ
1 (λ
+ −1α
) /N( 1)( 1) ( 2)
, 1 1
( 1)( 1) ( 2)
p m
H
p m B
p m
λ α λ
λ λ α
λ α λ
− + − + −
=
− − + + − =
− + − + −
*
1
K N
q Nv
+ =
+
*
1 1
(
m)
v q pt
u
−
div u
−Du
λ−Du
= −
ε
Du
+
δ
u
(0, )
N
R
×
T
0
( , 0)
( )
0
u x
=
u x
≥
*
1
* 1
( )
( ) [ln ]
A
vq
if q q then u t t
if q q then u t t
γ
γ
− −
−
< ≤
here , , ,
.
In [25] the long time asymptotic of the solution were established for the following problem with critical parameter
in area
Following asymptotic
where f is the rescaled kernel of the fundamental solution of the linear parabolic operator.
Mu et al. [26] studied the secondary critical exponent for the following p-Laplacian equation with slow decay initial values:
(9) (10) where p > 2, q > 1, and showed that, for
, there exists a secondary
critical exponent such that the
solution of (1.9)-(1.10) blows up in finite time for the initial data which behaves like at , if , and there exists a global solution for the initial data , which behaves like at
, if .
J.-S. Guo and Y. Y. Guo [27] obtained the secondary critical exponent for the following porous medium type equation in high dimensions:
(11) (12) where p > 1, m > 1 or max{0, 1 – (2/N)} <m< 1, is nonnegative bounded and continuous, and proved that for , there exists a secondary critical
exponent such that the solution
of (1.11)- (1.12) blows up in finite time for the
initial data .
The authors of [28] considered the fast diffusion equation for large t, when the degree of absorption is critical for the following equation
in area
They established a clear lower bound, which eliminates convergence to zero.
In this paper, we study the asymptotic behavior (for ) of solutions of the Cauchy problem (1)-(2) for a nonlinear parabolic equation with a double nonlinearity, describing the diffusion of heat with nonlinear heat absorption at the critical value of the parameter .
2. Asymptotic of the Solution
Based on the method of standard equation [2], the solution to the problem (1)-(2) will be find in the following form
13) Put (13) in (1) and select
For we get following equation
(14)
We note that for large t by the Hardy theorem on the behavior of the integral [2], the function has the following asymptotic
Where
Now put , in (14)
we get an approximately self-similar equation: *
( 1)
q q
A Nv
H
−
= + H=(λ+1)(vq− −1) q m( + −λ 2)
( 2) 1
K =N m+ − + +
λ
λ
0,
1,
m
2
0
δ
=
ε
=
+ − >
λ
1 2
/
c
p
= +
m N
1(
)
m pt
u
= − −∆ −
u
−u
R
N×
R
+0
( , 0)
( )
u x
=
u x
/ 2 /(2 )
0 1/ 2
( , )
N m(ln )
N m Q(
)
(1)
m
x
u x t
C t
t
f
o
t
− − +
= ±
+
(
2)
, ( , )
(0, )
p q N
t
u
=
div
∇
u
−∇ +
u
u
x t
∈
R
×
T
0
( , 0)
( ),
Nu x
=
u x x
∈
R
*
1 ( /
)
c
q
>
q
= − +
p
p N
*( / (
1
))
c
a
=
p
q
+ −
p
( , )
u x t
0
( )
u x
x
−αx
= ∞
*(0,
c)
a
∈
a
0
( )
u x
x
−αx
= ∞
*(
c,
)
a
∈
a N
, ( , )
(0, )
m p N
t
u
= ∆
u
+
u
x t
∈
R
×
T
0
( , 0)
( ),
Nu x
=
u x x
∈
R
0
( )
u x
*(2 /
)
m
p
>
p
= +
m
N
*2 / (
)
a
=
p
−
m
( , )
u x t
0
( )
u x
0
m q t
u
u
u
∂ − ∆
+
=
(0, ) xR∞ N0
(0, x)
u (x), x
R
Nu
=
∈
*
2 :
q q m
N
= = +
t
→ ∞
β
(
)
*1 1
( , ) ( ) ( ( ), ), ( ) ln
u t x =u t ω τ t x u t = t t −β−
)
(
t
τ
(
)
*( 2) 1 1
( )
ln
m k p
t
t
t
βdt
τ
− + − −−
=
∫
)
),
(
(
τ
t
x
ω
( ( 2))
1 2
( ( 2))
( m | k |p ) m k p
m k p
u du
u dt
β β
ω
ω
ω
ω
ω
τ
ω
− + −
− −
− + −
∂ = ∇ ∇ ∇ − −
∂ −
( )t
τ
1 2
( )
t
t
αln
αt t
,
τ
∞
1
2
( 2) 1 , ( ( ( 2) ) )
( 2) 1 1 ( ( ( 2) ) )
k p m
p k p m N p
k p m
p k p m N p
α
α
− + − =
+ − + − + −
= − +
+ − +
1/
( , )
x
f
( ),
x
[ ( )]
t
p(15)
We take as a generalized solution of the equation (15) the following function
(16)
After putting (16) into (15) a self-similar equation transforms to
(17)
Theorem 1
Let and
Where
, mentioned number Then for solution of problem (1) - (2) bounded above by function
, defined above Proof
Show that is the upper solution of problem (1) - (2). After putting in (17) we get the following estimates
To satisfy these estimates, the following conditions are sufficient
These conditions valid due to conditions of the theorem 1.
Theorem 2.
Let ,
and
, defined above
Then for solution of problem (1) - (2) bounded below by function
Proof
Show that is the lower solution of problem (1) - (2). After putting in (17), we get the following estimates
To satisfy these estimates, the following conditions are sufficient
These conditions are true due to conditions of the theorem 2.
From the last two theorems it follows that for all large t the self-similar solution is bounded above and below
For we get the following estimates
3. Results of the Numerical
Experiments
Problem (1) - (2) has no analytical solution. Therefore, we will discuss result of the numerical experiments. To find a solution of problem at some point we are using numerical methods (see [29]-[31]). The resulting asymptotic of the solutions were used as an initial approximation for numerical computation.
3.1. One Dimensional Case (N=1)
From problem (1) - (2) we have following one dimensional nonlinear heat equation with initial and boundary conditions
2
1 1 1
( ( 2)) 1 ( ( 2))
( )
( ) 0
p k
N N m
m k p m k p
d df df df
f
d d d p d
du
f u f u
dt
β β
ξ
ξ
ξ
ξ
ξ
ξ
ξ
τ
−
− − −
− + − − − + −
+ −
− − =
1 ( 2) 1 1
( )
p p m k p p
f ξ a bξ
− + − − −
+
= −
2 1
( ( 2) 1) / ( ), ( 2) 1 0
p p p
b= m+k p− − k − p − m+k p− − >
* 1 1
( ) ( (ln 1))
1
p N
N
L f f f u f t
p
β τ
β
−
= − − + +
−
*
(
z
−
1)(
β
− −
1) (
p
+
zN p
)
<
0
*
(
β
−1)((p+z N( −1))p− +z 1)− p p( +zN)<( 2)
z=k p− +m
β
*t
→ +∞
( , )
u t x
+,
b
ξ
u t
( )
( , )
u t x
+( , )
u t x
+*1
1
( ) ( (ln 1) ) 0
1
p p
N N N
L f f u t u f
p
β
τ τ
β
−
= + − − ≤
−
* *
* *
( 1)( 1) ( ) ( 1)(( ( 1)) 1) ( )
( 1)( ) ( 1)( )
*
1
ln (ln 1)
1 0
z p zN p p z N p z p p zN
p zN p p zN p
t t t
N P
β β
β β
β
− − − + − + − − + − +
− + − + + −
−
− ≤
*
( 2) 1 ( 1)( 1) *
1 1
m k p p a
β
β
+ − −
− −
≤ −
*
(
z
−
1)(
β
− −
1) (
p
+
zN p
)
>
0
*
(
β −
1)((
p
+
z N
(
−
1))
p
− + −
z
1)
p p
(
+
zN
)
>
0
( 2)
z=k p− +m
β
*t
→ +∞
( , )
u t x
−1 1
1 ( 2) 1 1
( , ) ( , ) ( ) ( (1 ln )), ( (1 ln )) 1
(1 )
ln
p p m k p p
u t x u t x u t f t f t
a b
t
ξ ξ
ξ
− −
−
− + − − −
+
≥ = + + =
= − +
( , )
u t x
−( , )
u t x
−1 1 1 1
( (1 ln )) ( ) [ (ln 1) ( (1 ln )) ] 0
1 p
N N
f t t u t f t
p β
ξ τ ξ
β
− − −
+ + − + − ≥
−
1 1
* *
1
ln
( (1 ln
))
0
1
1
Npt
N
f
t
p u
β
ξ
β
β
τ
− −
+
−
−
+
≥
−
−
( ) ( )
u t f
ξ
1
( , ) ( ) ( ) ( , ) ( , ) ( ) ( (1 ln ))
u t x+ =u t f ξ ≥u t x ≥u t x− =u t f ξ + − t
t
→ +∞
( , )
( ) ( )
( , )
( , )
( ) ( )
(18)
,
For problem (18) we construct the spatial grid x with steps h
And temporary grid with
replace problem (18) implicit two-layer difference scheme and obtain the difference task with error
(19)
Where and is nonlinear terms of the problem (18). In our case and are a thermal conductivity coefficients. To calculate and , use the following formulas [29]
(20)
when i=1 goes beyond the points, so following Milne formulas can be used[31]
or
(21) Scheme (19) is absolutely stable and has the first order of approximation for
τ
, and the second forh
[29].
System of algebraic equation (19) is nonlinear is relative
.
For solve a system of nonlinear equations (19), we apply an iterative method and obtain following system of algebraic equation [29]
(22)
where initial and boundary conditions unchanged
Now system of algebraic equation (3.1.5) is linear is relative . As the initial iteration for is taken from the previous time step . When counting by an iterative scheme, the accuracy of the iteration is set and the process continues until execution the following conditions
Remark. In all numerical calculations we take
Let following notation
, .
From different scheme (22) we will find tridiagonal matrix coefficients A, B, C, F and solve following system linear equations by method Thomas [29]
, .
Where
, ,
, ,
, .
3.2. Two-Dimensional Case (N=2)
From problem (1) - (2) we have following two-dimensional nonlinear heat equation with initial and boundary conditions * 2 1 1 p k m
u u u
u u
t x x x
β − − ∂ = ∂ ∂ ∂ − ∂ ∂ ∂ ∂
( )
x 0, )x , 0 (
u =ψ ≥ 0≤x≤b
= ϕ = > ϕ = 0 ) t ( ) b , t ( u 0 ) t ( ) 0 , t ( u 2
1 t∈
[
0,T]
{
xi ih, h 0, i 0,1,...,n, hn b}
h = = > = =
ω
τ
{
t
jj
,
0,
j
0,1,..., ,
m
m T
}
τ
ω
=
=
τ τ
>
=
τ
=
) h ( 2+τ
Ο
( )(
) ( )(
)
( )
( )
( )
( )
11 1 1 1 1 1
1 1 1
2 1 0 0 0 1 2 1
- , 1, 2,..., 1; j 0,1,..., 1 , 0,1,...,
, 1, 2,..., ,
j j
j j j j j j
i i
i i i i i i
j i i i j j j n j y y
a y y y a y y y
h
y i n m
y u x i n
y t j m
y t β τ φ φ + + + + + + + + + − + − = − − − = − = − = = = =
= j 1, 2,...,m
= 1 i
a
+a
i 1 ia
+a
i 1 ia
+a
i( )
( )
2 1 1 1 1 1 1 2 1 1 1 1 1 1 1 ( ) ( ) 12 ( ) ( )
( )
p
j k j k
m
j i i
i
i p
j k j k
m
j i i
i j y y y h a y y y h y − + + − + + + − + + − + + + − − = − + +
( )
( )
2 1 1 1 1 1 1 2 1 1 11 1 2
1
( ) ( )
1
2 ( )
(
( )
)
p
j k j k
m
j i i
i
i p
j k j k
m
j i i
i j y y y h a y y y h y − + + − + − − − + + − + − − + − + = − + i
a
h y y y dx du 2 3 4 1 0 2 0 − + − ≈ h y y y dxdu n n n
n 2
4
3 − −1+ −2
≈ 1 j
y
+,...
2
,
1
,
0
s
=
1 jy
+ sy1i+
y
j 0 1 j y y+ =ε
ε < − + ≤ ≤ i s i 1 s n i0 y y
max
3
10
ε
=
−y
y
j=
y
j+1=
y
i s 1 s 1 i i s 1 s i i s 1 s 1 i i s F y B y C y
A − + =−
+ + +
+
−
i
=
1
,
2
,...,
n
−
1
1 1 1 0
=
χ
y
+
µ
y
2 1
2
µ
χ
+
=
N−N
y
y
( )
12 s j s i i
a a
A
h
τ
+=
1( )
1 2 s j s i ia
a
B
h
τ
+ +=
1
B
A
C
i s i s i s+
+
=
( )
1s s
j
i i i
F
= −
y
y
+ β...
2
,
1
,
0
(23)
,
.
We construct the spatial grid ( ) with
steps and :
And time grid with
, .
For numerical solution of the Problem (23) used method of variable direction [30]
(24)
where
For nonlinear part and were used the following approximations
For computation on the end of the segment the Milne formulas (21) is also used.
Scheme (24) is stable both according to the initial data and on the right-hand side for any
τ
andh
.
Scheme has accuracy 2 2( )
O
τ
+h [30].
In this scheme, the transition from layer l to layer l+1 is carried out in two stages. In first stage find intermediate values for l+1/2 and in second stages find values for l+1 with usages founded value l+1/2 layer.
Rewrite the initial and boundary conditions as follows
*
2 1
1 1 1
2 1
2 2 2
p k m p k m u u u
x x x
u
u t
u u
u
x x x
β − − − − ∂ ∂ ∂ + ∂ ∂ ∂ ∂ = − ∂ ∂ ∂ ∂ + ∂ ∂ ∂
|
( , )
u
Γ=
µ
x t
u
(
0
,
x
)
=
u
0( )
x
≥
0
,
2
,
1
,
b
x
0
≤
α≤
αα
=
α
x
α
=
1
,
2
1 1 1 n b h = 2 2 2 n b h =
(
)
{
1, 2 , 1 1, 2 2, , 0,1,..., , 1, 2}
i j i j
h xij x x x ih x jh i j nα
ω = = = = = α=
τ
{
tk l , 0, l 0,1,..., ,m m T}
τ
ω
= =τ τ
> =τ
=0
T
>
1 2 1 2 1 2 1 2 , , 1 2 1, , 1 1
1 2
(
)
0.5
(
)
0.5
l li j i j l l l
l l
i j i j l l l
y
y
y
y
q y
y
y
y
y
q y
τ
τ
+ + + + + + +
−
= Λ
+ Λ
+
⋅
−
= Λ
+ Λ
+
⋅
( ) (
)
( ) (
)
( ) (
)
( ) (
)
( ) (
)
( )
1 1 1 1 1 1 1
2 2 2 2 2 2 2
1 2 1, 1, , , , 1,
1
2 2 , 1 , 1 , , , , 1
2
1 1 1 1 1 1
2 2 , 1 , 1 , , , , 1
2 1 , 1 , 1
l l l l l l l
i j i j i j i j i j i j
l l l l l l l
i j i j i j i j i j i j
l l l l l l l
i j i j i j i j i j i j
y a y y y a y y y
h
y b y y y b y y y
h
y b y y y b y y y
h + + + + + + + + + − + + − + + + + + + + + + −
Λ = − − −
Λ = − − −
Λ = − −
(
− 1)
1,2. , 1 n ,..., 2 , 1 j
,i = α− α=
( )
q y = −uβ
,
(
)
l i ja
y
a
i j,(
y
l)
(
)
(
)
2
1 1, ,
,
1
1, 2
1 , 1,
1/ 2 1/ 2 1/ 2
1/ 2
1/ 2 1/ 2 1/ 2
1,
1
( ) ( )
1
2 ( ) ( )
( )
p
k k
m i j i j i j
i j p
k k
m l
i j i j i l l l l l l j y y y h a y y y h y − + + + − + + + + + + − − − + − + = − +
(
)
(
)
1/ 2 1/ 2 1/
2 1
2 1/ 2
1/ 2 1/
, 1,
1,
1
, 2
1 2
1/ 2 1, 2,
,
1
( ) ( )
1
2 ( ) ( )
( )
p
k k
m i jl l l l l l l i j i j
i j p
k k
m i j i j i j y y y h a y y y h y − − − − + + + + + + − − − + − − + = − +
( )
(
)
21 , 1 ,
,
2
, 1 2
1 , 1,
1,
2
(
)
(
)
(
)
1
2
(
)
(
)
p
k k
m i j i j
i j
i j p
k k
m i j i j
i l l l l l l j l
y
y
y
h
y
y
y
h
b
y
− − + + − − − +
−
+
=
−
+
(
)
( )
21 , , 1
, 1
2
, 2
1 , 1 , 2
,
2
(
)
(
)
1
2
(
)
(
)
(
)
p
k k
m i j i j
i j
i j p
k k
m i j i j
i l l l l l l j l
y
y
y
h
y
y
y
h
b
y
− − − − − − − −
−
+
=
−
+
( )
(
)
21 , 1 ,
, 2 1 1 1 1 1 1 1
, 1 2
1 , 1,
1,
2
(
)
(
)
1
2
(
)
(
(
)
)
p
k k
m i j i j i j i l l l l l l j p k k
m i j i j i j l
y
y
y
h
y
y
y
b
y
h
+ + + + + − − + − + + + − − +
−
+
=
−
+
(
)
( )
21 , , 1
, 1
2
, 2
1 , 1 , 2
1 1 , 1 1 2 1 1 1
(
)
(
)
1
2
(
)
)
(
(
)
p
k k
m i j i j
i j
i j p
k k
m i j i
(25)
where [30].
Let following notation
, , .
For solve a system of nonlinear equations (3.2.2), we apply an iterative method and obtain following system of algebraic equation
(26) (27) Now system of algebraic equation (26) is linear to relative , (27) is linear is relative .As the initial iteration in (26) for is taken from the previous time step . When counting by an iterative scheme, the accuracy of the iteration is set and the process continues until execution the following conditions
As the initial iteration in (3.2.5) for is taken from the previous time step . When counting by an iterative scheme, the accuracy of the iteration is set and the process continues until execution the following conditions
Remark. In all numerical calculations we take
Difference equation (26) can be written as
(28)
. and (27) as
1 1 1
, , 1 , , , , 1 ,
2
ˆ
ˆ
ˆ
ˆ
, when
0,
s s s s s s s i j i j i j i j i j i j i j
A
y
C
y
B
y
F
y
φ
j
n
+ + +
+ −
−
+
= −
=
=
(29)After we have 3 diagonal matrix equations with following coefficients A, B, C, F and can solve following system linear equations by method Thomas.
, ,
, ,
, ,
,
(
)
1/ 2 1/ 2 1/ 2
, , 1
ˆ
ˆ
ˆ
2
2
s
s s
l l l
i i j i j
F
=
y
+−
τ
y
+ β+ Λ
τ
y
+The system of equations (28) is solved by lines and determined at all point of grid , then system of equations (29) is solved by columns and determined at all point of grid . During the transition from layer l+1 to layer l+2, the counting procedure is repeated.
3.3. Visualization
Notice that very important to found appropriate initial approximation of solution depending on value of numerical parameters. Therefore, an initial and a boundary values are calculated using the founded above following asymptotic
, (30) , ,
( )
1 1 2 2 0 , 0 1 1 , 2 , 1 ,, when 0 и , when i 0 и
i j h
l l i j
l l
i j
y u x x
y j j n
y i n
ω φ φ + + + + = ∈ = = = = = =
(
1)
(
1)
2
1
2
4
l l
τ
l lφ
=
φ
++
φ
− Λ
φ
+−
φ
l
y
=
y
y
l+12=
y
y
l+1=
y
ˆ
0 1
5 .
0 1, ,
1 , 1 , , 1 , 1 1 , 1 2 1 , 1 = + − − − = ⋅ − + + + + + + + j i s j i s j i s s j i j i s j i s s j i j i s F y y y a y y y a h y τ 0 ˆ ˆ ˆ ˆ ˆ ˆ 1 5 . 0 ˆ , 1 , 1 , 1 , , 1 1 , 1 1 , 2 2 , 1 = + − − − = ⋅ − + + + + + + + j i s j i s j i s s j i j i s j i s s j i j i s F y y y b y y y b h y τ j , i 1 s y + j , i 1 s
yˆ+ j , i 1 s y +
y
j , i j , i 0y
y
=
ε
ε < − + ≤ ≤≤≤ i,j
s j , i 1 s n j 0 n i
0max y y
2 1 j , i 1 s
yˆ
+y
j , i j , i 0y
yˆ
=
ε
ε
<
−
+ ≤ ≤≤≤ i,j
s j , i 1 s n j 0 n i
0
max
yˆ
yˆ
2 1
3
10
ε
=
−1 1 1
, 1, , , , 1, ,
1
, when 0,
s s s s s s s
i j i j i j i j i j i j i j
A y C y B y F
y
φ
i n+ + + + − − + = − = =
1,2
,
1
n
,...,
2
,
1
j
,
i
=
α−
α
=
( )
1/ 2 ,2 1
2
s l s i j
i a y A h
τ
+ =( )
1/ 2 1, 2 1 2 s l s i ji
a y
B
h
τ
+ += 1 B A C i s i s i s + +
= ,
( )
, 22 2
s s
s l l l
i i j i j
F y y y
β
τ
τ
= − + Λ
( )
1 , 2 2ˆ
2
s l s i j ib
y
A
h
τ
+=
( )
1 , 1 2 2ˆ
2
s l s i j ia
y
B
h
τ
+ +=
1
s s s
i i i
C
= + +
A
B
1
n
,...,
2
,
1
j
=
2−
y
h
ω
1
n
,...,
2
,
1
i
=
1−
y
ˆ
h
ω
(
)
*1 1
0
( , )
ln
( )
u t x
=
t
t
−β −f
ξ
* ( 2)
p
k p m
N
β = − + +
1 1 ( 2) 1
( ) ( )
p p
p m k p
f
ξ
a bξ
− − + − − + = − 1 2 1
( ( 2) 1) / ( p )( p)p , ( 2) 1 0
b= m+k p− − k − p − m+k p− − >
1/
[ ( )] p
x t
ξ = τ −
τ
( )
t
=
t
α1ln
α2t
12
( 2) 1
,
( ( ( 2) ) )
( 2) 1
1
( ( ( 2) ) )
k p m p k p m N p
k p m p k p m N p
k=2 m=2 p=3
m=4 p=3 k=2
k=4 p=3 m=2
k=1 m=2 p=3
As we can see from the figures, for large times and a critical value of parameter
β
* , the solutions of the problem infinitely close to each other, which leads tolocalization.
4. Conclusions
As we see the asymptotic of the solution to problem (1)-(2) for the critical parameter changes its asymptotic for . Proofs of the proposal based on principle of comparison solutions. The resulting asymptotic of the solutions were used as an initial approximation for numerical computation. As we now the final propagation velocity is a natural effect inherent in nonlinear processes. In all numerical experiments we got this effect. As a numerical experiment showed, founded asymptotic is a good initial approximation. The numerical results are in good agreement with the physics of this process.
We are currently investigating the convergence of schemes (24), (19) and the asymptotic stability of a solution (30).
In[32] authors study the homogeneous Dirichlet problem for the following doubly nonlinear equation posed in a bounded domain in with homogeneous boundary conditions and with non-negative and integrable data for the degenerate case m(p-1)>1 and the quasilinear case
m(p-1)=1
is p-Laplacian operator, p>1, m>0.
They established the following long time asymptotic of the solution and gives rates
where α, β are positive parameters and h a real valued function satisfying a certain ODE.
The founded long time asymptotic of the solution (3.3.1) can be used for this problem with the additional absorption part for the critical parameter in case m=1, k=m.
In addition, the equation (17) can be obtained by multiplying the equation (15) on and integrating over the interval . Kind of such an equation may be get using work [33].
At there is a special case. In this case function looks like following
All this suggest that parameter is very sensitive to parameters k, p, m. Besides at the asymptotic of the solution will also change, which as in the
β
t
→ +∞
N
R
0
( , )
( , ), for 0 and
,
(0, )
( ),
for ,
( , )
0,
for
0 and
.
m
t p
u t x
u
t x
t
x
u
x
u x
x
u t x
t
x
= ∆
>
∈Ω
=
∈Ω
=
>
∈∂Ω
2
: div(| |p )
pw w w
−
∆ = ∇ ∇
( , )
(
)
( ),
| | (
)
,
u t x
= +
t
s
−αh r
r
=
x t
+
s
−ββ
1
N
ξ
−(0, )
ξ
( 2) 1
k p− + =m
( )
f
ξ
1
2 1 1
( ) exp( ( ) )
p
p p p p
f ξ = − k − p −ξ −
β
( 2) 1
critical case, can discover new effects, properties, estimates.
For the equation with variable density which is given below, the critical value of parameter is also found. With it helps search the asymptotic of the solution with critical parameter possible.
The search for new effects of a variable density problem for a critical value of parameter is a very important and interesting study. It expands the possibilities of applied application of this study and this equation a more generalized case of problem (1) - (2).
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β
(
1 2)
*0
, (0, ) ( ),
p
l m k l
N
u
x u u u x u
t
u x u x x R
β
−
− ∂ = ∇ − ∇ ∇ − −
∂
= ∈
*
2
1 1 1
( )
( , ) ( , ( ))
( ) / ( ), , ,
( 2) / ( 2)
p k
s s m
p l
u t x w t x
w w w
w w
t
N l
x p x p l s p N l l p
p l
p l
k p p s k p
N l
β
ϕ
ϕ ϕ
ϕ ϕ ϕ
ϕ
β
−
− − −
−
∗ =
∂ ∂ ∂ ∂
= −
∂ ∂ ∂ ∂
−
= − = > <
− −
= − + = − +
−
β
1 t
u = ∆ +u u+α
2
( p ) ( , , , )
t
u =div ∇u − ∇ +u f ∇u u x t
2
( p )
t
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m
t p