We say a graph is (π‘, π, π)-colorable if π (πΊ) may be partitioned into π independent sets 01, 02, . . . , 0π and π sets π‘1, π‘2, . . . , π‘π whose induced graphs have maximum degree less
than or equal to π‘. We consider the case π‘ = 1 with π independent sets 11, 12, . . . , 1π,
given π > 1 and π > 0.
If a vertex is colored β1β, then it belongs to some color class 1π; similarly if a
vertex is colored β0β, then it belongs to some color class 0π. A 1-class refers to some
Theorem 3.3.1. Given π > 1 and π > 0, if mad(πΊ) < 43π + π, then πΊ is (1, π, π)- colorable.
For a given relaxation (1, π, π), for a vertex π£ β πΊ define β(π£) = π(π£) β (π + π). Then π£ is
β small if π(π£) = π + π, i.e. if β(π£) = 0.
β medium if π + π < π(π£) < 2π + π, i.e. if 0 < β(π£) < π. In particular, we say π£ is an β-medium vertex.
β large if 2π + π β€ π(π£) < 2π + 2π, i.e. if π β€ β(π£) < π + π. In particular, we say π£ is an β-large vertex.
β huge if π(π£) β₯ 2π + 2π, i.e. if β(π£) β₯ π + π. Let πΊ be a minimum counterexample.
We iteratively construct the vertex subset πΉ β π (πΊ). Let πΉ0 be all huge ver-
tices in πΊ. For a given πΉπ, let a vertex in πΉπ be called flagged. We define βspecial
configurationsβ of πΉπ.
Definition 3.3.2. Given a non-empty vertex set π»π β π (πΊ) disjoint from a flagged
vertex set πΉπ, π»π is a special configuration of πΉπ if for every π£ β π»π
(i) π£ has at least max{π β β(π£), 0} flagged neighbors, and
(ii) π£ has degree at least π + π β β(π£) in the induced subgraph πΊ[π»πβͺ πΉπ].
If there exists some special configuration π»π of πΉπ, let πΉπ+1 = πΉπ βͺ π»π. π»π is
non-empty and disjoint from πΉπ, hence π»πβ πΉπ ΜΈ= β : since πΊ is finite, the above
iteration must terminate. Hence let πΉ := πΉπ, where πΉπ is the final possible iteration
of some sequence πΉπ. Note that πΉ0 β πΉ1 β . . . β πΉπ.
Alternately, we may define πΉ as follows. We consider a collection of vertex subsets π, such that π β π if and only if πΉ0 β π through some sequence of the above iteration.
3.3.1
Characterizing the minimum counter example.
Let a vertex be saturated if it is colored 0π or if it is colored 1π and has exactly one
neighbor colored 1π. In some coloring π, let a vertex π£ be recolorable if there exists
some π* such that π(π’) = π*(π’) if and only if π’ ΜΈ= π£. A partial coloring is a coloring excluding exactly one vertex in πΊ.
Lemma 3.3.3. Every vertex π£ β πΊ is at least small, i.e. πΏ(πΊ) β₯ π + π.
Consider a partial coloring π(πΊ β π£). If π cannot be extended to π£, then π (π£) must saturate π + π colors: π£ has at least π + π neighbors.
Given some neighbor π’ of a vertex π£, we say π’ is uniquely colored on π (π£) if π(π’) is unique on π (π£).
Lemma 3.3.4. Consider any non-huge vertex π£ β πΊ and a partial coloring π(πΊ β π£). Then π£ has at least π + π β β(π£) uniquely saturated neighbors, at least max{π β β(π£), 0} of which are uniquely 1-saturated.
We note that π(π£) = π + π + β(π£). Suppose that π£ has π < π + π β β(π£) uniquely colored neighbors. If π cannot be extended to π£, then every color class must be represented on π (π£), hence π + π β π classes are not unique on π (π£). Hence, π£ has at least two neighbors of each of π + π β π classes: π(π£) β₯ 2(π + π β π) + π = 2π + 2π β π > π + π + β(π£), a contradiction. π£ has at least π + π β β(π£) uniquely colored neighbors, each of which must be saturated if π cannot be extended to π£.
Similarly, let π£ be medium or small, hence π β β(π£) > 0. Suppose that π£ has π < π β β(π£) uniquely colored 1-colored neighbors. Every 1-class must be represented on π (π£), hence π β π 1-classes are not unique on π (π£). π£ has at least two neighbors of each of πβπ 1-classes and at least π 0-colored neighbors, hence π(π£) β₯ 2(πβπ)+π+π = 2π + π β π > π + π + β(π£), a contradiction. π£ has at least π β β(π£) uniquely 1-colored neighbors, each of which must also be saturated.
Given a flagged vertex set πΉ , we call a partial coloring π minimum if the number of unflagged 1-saturated vertices is minimum on the set of all partial colorings {π(πΊβπ£) : π£ β π (πΊ) β πΉ }.
Lemma 3.3.5. Every vertex is flagged in πΉ .
Let π» be the set of all unflagged vertices with minimum partial colorings. The following must be true for every π£ β π»:
(i) π£ has at least max{π β β(π£), 0} flagged neighbors.
If π£ is large, then π β β(π£) < 0. Suppose π£ is medium and has fewer than π β β(π£) flagged neighbors. Consider any minimum partial coloring π(πΊ β π£). By Lemma 3.3.4, π£ has at least π β β(π£) uniquely 1-saturated neighbors. Hence, π£ must have at least one uniquely 1-saturated neighbor π’ that is unflagged. Un- color π’ and color π£ with π(π’) to produce the coloring πβ²(πΊ β π’). π£ is unsaturated and no other vertices have been saturated, since π(π’) is unique on π (π£): πβ² has
fewer 1-saturated vertices than π, hence π is not minimum, a contradiction. (ii) π£ has at least π + π β β(π£) neighbors in the induced graph πΊ[π» βͺ πΉ ].
If π£ is unflagged, then π£ is non-huge. By Lemma 3.3.4, π£ has at least π + π β β uniquely saturated neighbors. Consider any such neighbor π€, and assume that π€ is unflagged. Uncolor π€ and color π£ with π(π€) to produce the coloring πβ²(πΊβπ€).
π£ is not 1-saturated and no other vertices have been 1-saturated, since π(π€) is unique on π (π£). πβ² has no more 1-saturated vertices than π, hence πβ² is minimum
as well: π€ β π».
Hence π» is a special configuration of πΉ . If πΉ βͺ π» ΜΈ= πΉ , then πΉ is not maximal, a contradiction. π» and πΉ are disjoint, hence π» = β . There are no unflagged vertices.
3.3.2
Discharging
For a vertex π£ β πΊ, define charge π(π£) as follows:
π(π£) = 3π(π£) β 4π β 3π
R1 if π£ β πΉ0, give charge 1 to each π’ β π (π£) β πΉ0.
R2 if π£ β πΉπβπΉπβ1for some π > 0, then give charge 1 to each vertex π’ β π (π£)βπΉπ.
Let π»π = πΉπ+1β πΉπ for π β₯ 0. By Lemma 3.3.5, πΉ = π (πΊ). Since πΉπβ1 β πΉπ, πΉ
is partitioned by {π»π}πβͺ {πΉ0}. We consider the vertices in each partition separately.
For every π£ β πΉ0, π£ is huge. By R1 π£ gives charge 1 to every neighbor:
π*(π£) = 3π(π£) β 4π β 3π β π(π£) = 2π(π£) β 4π β 3π β₯ 2(2π + 2π) β 4π β 3π > 0
given π(π£) β₯ 2(π + π) and π > 0. π*[πΉ0] > 0.
We consider the total charge of each partition π»π. By R2, we note that every
neighbor in πΉπ gives charge 1 to π»π, and that π»π gives charge 1 to every neighbor
not in πΉπ+1. π»π comprises a special configuration, hence for any π£ β π»π,
β π£ is non-huge,
β π£ has at least max{π β β(π£), 0} neighbors in πΉπ, and
β π£ has at least π + π β β(π£) neighbors in π»πβͺ πΉπ = πΉπ+1, i.e. π£ has at most 2β
neighbors not in πΉπ+1.
Hence for any π£ β π»π, we consider the following cases:
β π£ is small or medium: π£ has at least π β β(π£) flagged neighbors in πΉπ. Then
π*(π£) β₯ 3(π + π + β(π£)) β 4π β 3π + (π β β(π£)) β 2β = 0.
β π£ is large: noting that β(π£) β₯ π,
π*(π£) β₯ 3(π + π + β(π£)) β 4π β 3π β 2β(π£) = β(π£) β π β₯ 0.
Since {π»π}π βͺ {πΉ0} partition π (πΊ), π*[π (πΊ)] = βοΈππ*[π»π] + π*[πΉ0] β₯ 0. But
charge is conserved, hence π[π (πΊ)] = π*[π (πΊ)] β₯ 0, and
βοΈ π£βπ (πΊ) π(π£) = βοΈ π£βπ (πΊ) (3 Γ π(π£) β 4π β 3π) β₯ 0, and hence 1 3π(πΊ) βοΈ π£βπ (πΊ) π(π£) = Β―π(πΊ) β(οΈ 4 3π + π )οΈ β₯ 0.
We find that mad(πΊ) β₯ Β―π(πΊ) β₯ 43π + π, a contradiction with our choice of πΊ.
Finally, we note that if a graph is (1, π, π)-colorable, then it is certainly (π‘, π, π)- colorable, for π‘ β₯ 1. Hence Theorem 3.3.1 holds for the fully general (π‘, π, π)-coloring case, although it is not always an improvement of the previous lower bound in (1.2).
Chapter 4
Conclusion
For the special (1, 1, 0)-coloring case, we demonstrate the bounds
32
3 β€ π < 4 13
40, (4.1)
where π is the maximum number such that for all πΊ with mad(πΊ) β€ π, πΊ is (1, 1, 0)- colorable. Moreover, for a coloring with π β₯ 2 improper classes and π β₯ 1 proper classes, we demonstrate a lower bound
4
3π + π β€ π, (4.2)
where π is again the maximum number such that for all πΊ with mad(πΊ) β€ π, πΊ is colorable with π improper classes and π proper classes.
We note that for the case of (1, π, π)-colorings (here denoting π β₯ 2 1-improper classes and π β₯ 1 proper classes), (4.2) is an improvement over the existing bound in
(1.5): for π β₯ 2, π + 2 + ππ π + 1 > 3 π((π + 2)(π + 1) + ππ) > 3π(π + 1) 1 3π > π(π + 1) (π + 2)(π + 1) + ππ 4 3π + π > π + π + π(π + 1) (π + 2)(π + 1) + ππ,
hence for colorings with mixed 1-improper and proper classes, our result improves the previously existing result in [7].
4.1
Future work
Often work supporting the lower bound develops structure that can inform efforts to- ward improving the upper bound. Our upper bound for the special (1, 1, 0)-coloring case suggest significant room for improvement: ideally, rather than employing struc- tures developed for simpler colorings, we might produce color-forcing graphs βde- signedβ for (1, 1, 0)-colorings. Our work with the lower bound presents novel structure that could inform a sparse non-colorable graph, or family of graphs.
Moreover, we have yet to seriously explore constructions for a generalized upper bound. The structure employed in the proof of the generalized lower bound suggests improvements for an upper bound in the general case, which would complement our completed efforts.
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