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LEAK OFF TEST DATA 3650 PSI with 11 ppg mud

In document 73236775 3 Well Control Exercises (Page 56-74)

1. What is the total capacity of the drill string? a) 288 bbls

b) 162 bbls c) 335 bbls d) 456 bbls

2. Calculate the total annular capacity with the pipe on bottom? a) 722 bbls

b) 443 bbls c) 987 bbls d) 323 bbls

3. What is the surface to bit time with the pump running at 40 spm? a) 61 minutes

b) 25 minutes c) 87 minutes d) 54 minutes

4. Calculate bit to surface time (bottoms up) at 40 spm? a) 155 minutes

b) 234 minutes c) 60.3 minutes d) 123 minutes

5. What kill mud is required to balance formation pressure? a) 13.3 ppg

b) 13.0 ppg c) 12.4 ppg d) 16.0 ppg

6. The ICP (initial circulating pressure) at 40 spm will be approximately? a) 1680 psi

b) 770 psi c) 2130 psi d) 1200 psi

7. The FCP (final circulating pressure) at 40 spm will be approximately? a) approximately 1800 psi

b) approximately 1050 psi c) approximately 1500 psi d) approximately 1290 psi

8. After reaching FCP it is decided to increase the pump speed to 50 spm. What would happen to BHP if the drill pipe pressure is held constant at the original FCP value?

a) increase by about 590 psi b) decrease by about 590 psi

c) remain constant because drill pipe pressure was not changed d) increase by about 500 psi

9. What is formation pressure based on the shut in data? a) 10,823 psi

b) 6800 psi c) 7800 psi d) 6240 psi

10.What is the ECD on bottom while drilling? a) 12.73 ppg

b) 15.54 ppg c) 16.03 ppg d) 16.52 ppg

11.What would be the circulating pressure while drilling if the pump was decreased to 60 spm?

a) 2240 psi b) 2800 psi c) 2100 psi d) 1860 psi

12.At 75 spm what is the annular velocity around the drill collars? a) 412 ft/min

b) 210 ft/min c) 506 ft/min d) 300 ft/min

13.What is the maximum allowable mud weight? a) 17.5 ppg

b) 16.0 ppg c) 18.0 ppg

14.What is the approximate length of the influx? a) 1027 ft

b) 850 ft c) 653 ft d) 342 ft

15.The gradient of the influx is about? a) 0.115 psi/ft

b) 0.320 psi/ft c) 0.465 psi/ft d) 0.433 psi/ft

16.How many strokes to go from ICP to FCP? a) 1282 stks

b) 1363 stks c) 1680 stks d) 2461 stks

17.Calculate the MAASP? a) 2620 psi

b) 2524 psi c) 2368 psi d) 1356 psi

18.Not following the the correct pressure schedule, the BHP could be high or low causing losses or another influx.

a) True b) False

19.What is the capacity of the choke line: a) 15 bbls

b) 12 bbls c) 23 bbls d) 28 bbls

20.How many strokes are required to displace the riser – annulus a) 7034 strokes

b) 4882 strokes c) 3453 strokes d) 1234 strokes

21.If the well had been shut in with 0 psi on the drill pipe pressure and no float in the string and a SICP of 300 psi, what mud weight would have required to kill the well?

a) 12.9 ppg b) 12.4 ppg c) 14.5 ppg d) 15.5 ppg

Answer the following gauge questions as the well is killed using the Drillers method. 1 00 200 3 00 400 5 00 600 70 0 80 0 90 0 1000 1 100 1200 1300 1400 15 00 160 0 1700 1 800 1900 10 0 200 300 4 00 5 00 6 00 700 800 900 10 00 1100 1 200 13 00 14 00 1 500 1600 1 700 18 00 1 900 O P EN P O S IT IO NC H O KE C LO S E P S I P S I T O TA L S TR O K E S D R ILL P IP E P R E S S U R E P U M P S P E E D C A S IN G P R E S S U R E 1 20 4 0 1 6 80 5 9 0

22.The kill operation has started. This is what the choke control console shows. What should you do?

a) open the choke a little b) close the choke a little

c) nothing everything looks alright d) Possible plugged nozzle

e) Possible choke plugging

1 00 2 00 300 40 0 5 00 60 0 70 0 800 900100 01 100 120 0 130 0 140 0 1500 16 00 170 0 1800 1 900 100 2 00 300 40 0 5 00 60 0 70 0 800 900100 011 00 120 0 130 0 1400 1 500 160 0 170 0 1 800 1 900 O P E N P O S ITIO NC H O K E C LO S E P S I P S I TO T A L S TR O K E S D R IL LP IP E P R E S S U R E P U M P S P E E D C A S IN G P R E S S U R E 40 1620 500 700

23.Pit room calls up to confirm a .5 bbl rise in the level. What should you do? a) open the choke a little

b) close the choke a little c) increase the pump speed d) decrease the pump speed e) nothing everything looks alright

100 200 300 400 500 600 700 8 00 900 1000 1100 1200 1 300 1400 1500 1600 1700 1800 1900 100 200 300 400 500 600 700 800 900 1000 1100 1200 1300 1400 1500 1600 1700 1800 1900 O PEN PO SITIO NC H O K E C LO S E P S I P S I TO TA L S TR O K ES D R ILLP IPE PR E SS U R E PU M P S PE E D CA S IN G PR E SS U R E 4 0 4 5 5 0 1 6 80 1 4 80

24.The pit levels are still reported to be increasing slightly. This is what you see on the panel.

a) open the choke a little b) close the choke a little c) possible choke washout d) possible choke plugging

e) nothing everything looks alright

100 200 300 400 500 600 70 0 8 00 90 0 1000 11 00 1200 1 300 140 0 1500 1600 1 70 0 1800 1 900 100 200 300 400 50 0 600 700 800 900 1000 1100 12 00 1300 1400 15 00 1600 1700 180 0 1900 OP EN PO SITIONC H O KE CL OSE PSI P SI TO TAL STRO K ES

DR ILLPIPE PRE SSU RE

P UM P SPE ED

CASIN G PRESS UR E

40 5600

25.Experienced a sudden increase in casing pressure over the last 100 strokes. Gas is venting and pit levels are reported to be falling. What are you going to do now?

a) open the choke a little b) close the choke a little c) possible nozzle plugging d) possible choke plugging

e) nothing everything looks alright

100 200 300 400 500 600 700 800 900 1000 1100 1200 1300 1400 1500 1600 1700 1800 1900 100 200 300 400 500 600 700 800 900 1000 1100 1200 1300 1400 1500 1600 1700 1800 1900

OPEN POSITIONCHOKE CLOSE

P S I P S I T O T A L S T R O K E S D R IL L P IP E P R E S S U R E P U M P S P E E D C A S IN G P R E S S U R E 4 0 1 6 80 6 2 2 0 1 40

26.Not hearing anymore gas. How are things going? a) open the choke a little

b) close the choke a little c) casing pressure should be 0 d) possible choke wash out e) good everything looks alright

1 00 200 3 00 400 500 600 70 0 80 0 90 0 1000 1 100 120 0 1300 1400 1 500 160 0 1700 1 800 1900 1 00 200 30 0 400 5 00 600 700 80 0 900 10 00 110 0 1 200 13 00 14 00 150 0 1600 1 700 18 00 1 900 O P E N P O S IT IO NC H O K E C LO S E P S I P S I T O TA L S TR O K E S D R ILL P IP E P R E S S U R E P U M P S P E E D C A S IN G P R E S S U R E 0 0 70 0 6300 7 00

27.Shut back in. What should you do? a) Check MW = 13.3 ppg

b) Check MW = 16 ppg c) Reset stroke counter d) Bleed off pressure to 0

e) nothing everything looks alright

100 200 300 400 500 600 70 0 800 900 1000 1100 1 200 1300 1400 1500 16 00 1700 1800 1900 100 200 300 400 500 600 700 800 900 1000 1100 120 0 1 300 1400 1500 1600 170 0 1800 1900 O P EN PO SITIO NCH O K E C LO S E P S I P S I TO TA L S TR O K ES D R ILLP IP E P RE S SU R E P U M P S PE E D C AS IN G P R ES SU R E 4 0 0 0 0 0 1 7 80 2 3 6

28.Got the pump to kill speed and have just reset the stroke counters having pumped the surface line. What should you do?

a) open the choke a little b) close the choke a little c) increase the pump speed d) decrease the pump speed e) nothing everything looks alright

100 200 300 400 500 600 70 0 8 00 90 0 1000 11 00 1200 1 300 140 0 1500 1600 1 70 0 1800 1 900 100 200 300 400 50 0 600 700 800 900 1000 1100 12 00 1300 1400 15 00 1600 1700 180 0 1900 OP EN PO SITIONC H O KE CL OSE PSI P SI TO TAL STR O K ES

DR ILLPIPE PRE SSU RE

P UM P SPE ED

CASIN G PRESS UR E

40 250

29.Pump room is on the phone saying pit levels are OK. What are you going to do now?

a) open the choke a little b) close the choke a little c) possible nozzle plugged d) possible choke plugged

e) nothing everything looks alright

100 200 300 400 500 600 700 800 900 1000 11001200 1300 1400 1500 1600 1700 1800 1900 100 200 300 400 500 600 700 800 900 1000 11001200 1300 1400 1500 1600 1700 1800 1900

OPEN POSITIONCHOKE CLOSE

P S I P S I T O T A L S T R O K E S D R IL L P IP E P R E S S U R E P U M P S P E E D C A S IN G P R E S S U R E 4 0 1 4 30 9 8 0 1 40

30.Drill pipe pressure is falling but casing pressure stay constant. How are things going?

a) open the choke a little b) close the choke a little c) increase the pump speed d) possible choke wash out e) good everything looks alright

1 00 200 3 00 400 5 00 600 70 0 80 0 90 010001 100 1200 1300 1400 15 00 160 0 1700 1 800 1900 10 0 200 300 4 00 5 00 6 00 700 800 90010 001100 1 200 13 00 14 00 1 500 1600 1 700 18 00 1 900 O P E N P O S IT IO NC H O K E C LO S E P S I P S I T O TA L S TR O K E S D R ILL P IP E P R E S S U R E P U M P S P E E D C A S IN G P R E S S U R E 0 0 2 20 17 20 7 0 0

31.Had to shut in because of a pump. What do you thing? a) Drill pipe pressure is too low

b) Casing pressure is too high c) Drill pipe pressure is too high d) Casing pressure is too low e) Everything looks alright

100 200 300 400 500 600 70 0 800 900 1000 1100 1 200 1300 1400 1500 16 00 1700 1800 1900 100 200 300 400 500 600 700 800 900 1000 1100 120 0 1 300 1400 1500 1600 170 0 1800 1900 O P EN PO SITIO NCH O K E C LO S E P S I P S I TO TA L S TR O K ES D R ILLP IP E P RE S SU R E P U M P S PE E D C AS IN G P R ES SU R E 4 0 2 4 8 0 1 0 50 1 3 0

32.Back up to kill speed. Company man wants to know how things are going. What do you tell him?

a) open the choke a little b) close the choke a little c) possible choke plugging d) possible nozzle plugging

EXERCISE # 9

1. A driller needs to close in a flowing well with drill pipe in a subsea BOP stack. He

Pushes the “Annular Close” button and the pilot light changes, but all gauges and the flow meter remain static. What is his best option?

a) Change pod and try again.

b) Call and wait for the subsea engineer.

c) Send assistant driller to manually operate the 4-ways valve on the Hydraulic Control Manifold to close the annular.

d) Close the lower annular preventer.

2. While drilling, an alarm goes off indicating low accumulator pressure and the flow meter Indicates a rapid loss of fluid. The best course of action is:

a) Stop drilling and shut the well in. b) Stop drilling and call subsea engineer.

c) Stop drilling and put all function in block one at a time until the flow stops. d) None of the above.

3. When a function is operated, which of the following is true? a) SPM valve will operate in both pods.

b) SPM valve will operate only on the active pod.

c) The SPM valve will operate after the function is complete.

4. How much time is allowed for subsea ram type preventer to close in API RP53? a) 30 seconds

b) 45 seconds c) 60 seconds d) 50 seconds

5. From which position in the hydraulic circuit is readback pressure taken? a) Upstream of the regulator in the pod?

b) The regulator itself?

c) Down stream of the regulator in the pod?

6. What is the principal reason for fitting ram locking devices such as wedgelocks or Poslocks to a subsea stack?

a) To give additional force when closing in, thus reducing delay times.

b) To lock the ram in the closed position and maintain the shear rams locked during disconnect.

c) To lock the BOP stack to the well head and lock the lower Marine Riser Package to the BOP stack.

7. The subsea hydraulic BOP control system is divided into a Control System and a Pilot System. Which two statements are true with respect to the Pilot System?

a) The fluid in the Pilot System flows continuously while a function on the BOP takes place.

b) The Pilot System dumps fluid to the sea at every operation of BOP functions. c) The Pilot System controls the position of all shuttle valves on the BOP stack directly.

d) The Pilot system is a closed dead-end system.

e) Pilot fluid consists of potable water, water-soluble concentrate and glycol. 8. Which two statements are true with respect to shuttle valves on a subsea stack?

a) The shuttle valves automatically seal any hydraulic leaks in the selected pod. b) The shuttle valves prevent communication between the selected system and the redundant system.

c) The shuttle valves are pilots operated.

d) The shuttle valves allow the retrieval of a malfunctioning pod without losing hydraulic BOP control.

9. What is the purpose of the "Memory Function" on electric control panels?

a) Memory Function indicates a malfunction by giving permanent light on the alarm panel after an alarm has been acknowledged and the audible alarm has stopped. b) Memory Function reminds the driller to add anti-freeze fluid when the temperature drops below a set level.

c) Memory Function indicates the previous position before “Block position” of three position functions.

d) Memory Function reminds the driller to engage Wedge Locks before hanging off. 10. Which of the following statements is true regarding to the use of “manipulator” type 4-

Ways valve used in subsea hydraulic BOP control systems.

a) If the valve is shifted to the center or “block” position, pressure will be vented from the line previously pressurised.

b) If the valve is shifted to the center or “block” position, pressure will be trapped in the line previously pressurised.

12. What is the purpose of sub-sea stack mounted bottles?

a) to minimize the time to operate any BOP function b) to maximize the time to operate any BOP function c) to minimize the time to operate annular type preventer d) to optimize the time to operate ram type preventer

The drillers BOP panel has gauges for pilot and readback pressure for the manifold and annular pressure. Answer true or false to the following statements:

13. Pilot pressure and readback pressure should normally be the same. a) true

b) false

14. Read back pressure is mesured at the output from the sub sea regulator a) true

b) false

15. Pilot pressure is measured at the out put of the surface regulator a) true

b) false

Answer true or false in each case to measure Choke Line Friction Loss (CLFL): 16. You can pump down the choke line taking return up the riser.

a) true b) false

17. You need to know the length of the choke line. a) true

b) false

18. You can pump down the drill string taking returns through the riser and then close the annular and take returns through the choke line.

a) true b) false

19. While pumping down the choke line at 150 gpm taking returns through the riser with 9 ppg mud in 750 feet water with 60 feet air gap, a stand pipe pressure of 65 psi was recorded. Estimate CLFL:

a) 30 psi b) 65 psi c) 351 psi d) 143 psi

20. What would be the new CLFL if the mud weight is increased to 13.5 ppg (use data from Q-19) a) 65 psi b) 97.5 psi c) 132 psi d) 234 psi

21. While pumping down the drill string and up the riser, a circulating pressure of 375 psi was recorded.

The annular was closed and returns taken through a wide open choke, circulating pressure was now 600 psi. What are the CLFL?

a) 375 psi b) 975 psi c) 600 psi d) 225 psi

22. Calculate the Maximum Allowable Mud Weight with the following data: Hole size 17 ½”,

Air gap is 80 ft,

Water depth is 220 ft, Casing shoe is 600 ft RKB, Sea water is .455 psi/ft, Overburden is .65 psi/‟ft, APL is 10 psi a) 8.77 ppg b) 9.45 ppg c) 10.7 ppg d) 11.7 ppg

23. A semi is in 650 ft of water (.445 psi/ft) drilling without a riser. Air gap is 60 ft and TD / TVD is 1350 ft RKB. What is the BHP during connections?

a) 450 psi b) 474 psi c) 550 psi d) 574 psi

Air gap

24. What surface volume would 2 bbl of gas trapped in a sub sea BOP at 1900 ft water depth have if released and allowed to migrate through the riser filled with 12.9 ppg mud?

a) 45 bbls b) 93 bbls c) 157 bbls d) 173 bbls

25. A semi is drilling top hole with a riser and diverter installed connected to 30” casing.

Air gap is 70 ft, water depth is 1523 ft, sea water is .465 psi/ft, TVD / TD is 2250 ft RKB and MW is 9.7 ppg.

What would be the reduction in BHP if the riser were lost or removed? a) 30 psi

b) 65 psi c) 95 psi

d) no reduction

26. hat increase in mud weight is required to offset this? a) 1.34 ppg

b) 1.67 ppg c) 2.23 ppg d) 2.78 ppg

Air gap

27. The recommended response time for sub sea BOP is:

Rams to close in less than: seconds

Annular should not exceed: seconds

Time to unlatch LMRP should not exceed: seconds

28. How can gas trapped in a subsea BOP be safely circulated out?

29. By how much would BHP change if a well was inadvertently opened before displacing riser to kill mud?

MW=10.4 ppg KMW=10.9 ppg water depth=1342 ft

a) 0 psi b) 35 psi c) 65 psi d) 90 psi

30. How many (.115bbl/st) strokes will it take to displace a 16” x 5” riser/drillpipe

annulus (200 ft long)? a) 290 strokes b) 390 strokes c) 490 strokes d) 190 strokes

31. The following drawing shows components of a subsea hydraulic control system. Each component has a number. Place the number next to the component in the list provided.

Using the schematic diagram of a hydraulic valve, answer the following question:

32. How many positions can the valve be placed in: a. 2

b. 3 c. 4 d. 8

33. How many active ports does the valve have? a. 2

b. 3 c. 4 d. 8

34. Can the valve be operated by: a. manual function only b. remote function only c. air operated only

d. manual or remote function 35. What is the name of this valve?

a. Terminator b. Selector c. Manipulator

36. In the center or block position, the valve vents fluid lines to tank.

a. True b. false

In document 73236775 3 Well Control Exercises (Page 56-74)

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