Figure3-14depictsasimplelowsideswitch.WhenRB0ishigh,
Q1isforwardbiasedintoconductionandcurrentflowsthroughthe
load.Let’sworkthroughafewdesignconcernswiththissimple
circuit.Wewillassumetheloadisa100ohmresistorandVis12
volts.Hence,thecurrentbeingswitchedis120mA.We’lltreatthe
currentthroughthiscircuitasaconstantandignorethevoltagedrop
acrosstheswitchingdevicetosimplifyourcalculations.Sinceour
switchcircuitswilloperatewithavoltagedropofwellunder0.5V,
oursimplificationswillnotintroduceappreciableerror.
Voltagerating—WhenRB0islow,Q1appearsasanopencir-cuitandthushasthefullloadsupplyvoltageVacrossit.Ina
transistordatasheet,themaximumvoltagethatmaysafelybeappliedinthismodeisVCEOormaximum
collectortoemittervoltage,baseopen.Ourparticulardevice,a2N4401isratedfor40VVCEO.Itshould
besafetouseituptoabout25volts,applyingareasonablesafetymargintotheratedvalue.Our12V
switchingexamplewillbewellwithinQ1’sratings.
Leakagecurrent—Whenthe2N4401iscutoff—thatis,thebasevoltageislessthanabout0.4V,someleak-agecurrent,ICEX,willstillflowthroughthedevice’scollector.ICEXisratednottoexceed0.1µAinthe
2N4401,anegligiblevalueinthecontextofourcircuits.
Saturationvoltage—Whenthebasedriveissufficienttosaturateabipolartransistor,thevoltagedropbe-tweenthecollectorandemitterisapproximatelyaconstant,referredtoindatasheetsasVCE(SAT),0.4V
fora2N4401atcurrentlevelsnear100mA.
Collectorcurrentanddevicepowerdissipation—The2N4401hasamaximumcontinuouscollectorcurrent
ratingof600mA,andamaximumpowerdissipationratingof625mWatroomtemperature(25°C).The
saturatedcollectorvoltage,VCE(SAT)is400mVat150mAand750mVat500mA.Thethermalresistance
junctiontoambientRθJAis200°C/wattandthemaximumjunctionoperatingtemperatureis+150°C.
We’llassumeadequatebasedrivetosaturateQ1,henceweexpectthecollectorvoltageat120mAtobe400
mVorless.We’llalsoassumeQ1istobeoncontinuously—continuouslyinthiscontextmeanslongenough
forthermalequilibriumtobereached,amatterofafewsecondsfora2N4401sizedevice.Hence:
Thedevicedissipationwillbe120mA×400mV,or48mW.
Thejunctiontemperatureriseoverambientwillthusbe200°C/watt×0.048watts,or9.6°C.As-sumingtheambientairtemperatureis120°F(49°C),themaximumjunctiontemperaturewillthus
be48°+9.6°=57.6°C.
Todeterminecasetemperature,weusethethermalresistancejunctiontocaseRθJCspecification,83.3°C/
watt.Thecasewillthusbeat83.3°C/watt×0.048watts,or4°Caboveambienttemperature.Ourdesignthus
iswellwithinthesafeoperatingparametersofthe2N4401.
Ifthe2N4401isbeingcycledoffandonatarapidrate,thedutycyclewillenterintocertainoftheseratings.
Forexample,supposethe2N4401isdrivingamultiplexedLEDdisplay,onfor2msandofffor8ms,fora
dutycycleof0.20.TheaveragepowerdissipationofQ1willthusbe20%ofthepeakpowerandthepermis-siblepeakpowerdissipationlimitmaybeasmuchasfivetimesthecontinuousvalue.Ofcourse,forthis
averagingeffecttowork,theontimemustbeshortcomparedwiththetimeittakesforthedevicetoreach
thermalequilibrium.
Figure 3-14: 2N4401 NPN low side
switch.
Basecurrentdrive—Asaroughapproximation,wemayregardQ1asacurrentoperatedswitch—thatis,for
everymilliampereofcurrentwewishtobesunkbyQ1’scollector,wemustinjectintothebaseacertain
currentlevel.(Thisisahighlysimplifiedapproximationofsemiconductoroperation,butadequatefor
ourpurpose.)TheratioofcollectorcurrenttobasecurrentisknownashFEor“DCcurrentgain.”The
DCcurrentgainvariesfromdevicetypetodevicetype,isnotwellcontrolledfromexampletoexample
ofthesamedevicetypeand,finally,varieswithcurrentevenforaparticulartransistor.2N4401devices,
forexample,haveanhFEthatvariesfrom20to300,dependingonthecollectorcurrent.
Ifwearenotconcernedwithswitchingtime,orpowerminimization,thesimplestdesignapproachistoas-sumetheworstcasehFEanddesignaccordingly.Tosink120mA,forexample,sincetheminimumspecified
hFEat100mAis100,thetargetbasecurrentshouldbe1.2mA.However,wenotethatatboth500mAand
10mAcollectorcurrents,theminimumhFEdropsto40.Hence,asamatterofperhapsexcessivecaution,and
toensureQ1isdrivenwellintosaturation,wewilldesignforhFEof40,representing3mAbasecurrent.
Thebasetoemitterjunctionvoltage,VBE,fora2N4401isspecifiedat750mVforabasecurrentof15mAand
collectorcurrentof150mA,sowewillusethisvalueincalculatingthebaseresistor,R2.(Sincethebaseto
emitterjunctionismodeledasaforwardbiasedsilicondiode,700mVisacommonlyusedroughestimatefor
thebasetoemittervoltageoverawiderangeofbasecurrentsforallsiliconbipolarjunctiontransistors.)R2’s
value(neglectingthePIC’sapproximately85ohmseriesresistancewhensourcingcurrent)isthus:
R V V
SwitchingSpeed—We’vealludedtoQ1’sswitchingspeed
concernsseveraltimesinourdesign.Ifweareswitching
anLED,orrelayorsteppermotor,theseproblemsare
unlikelytoconcernus.However,therearetimeswhereit
iscriticaltoswitchaloadasfastaspossible.Figure3-15
showswhathappenswhenveryshortswitchingintervals
areusedinthecircuitofFigure3-14.RB0emitsafastrise
andfall200nswidepulseandQ1turnsonwithlessthan
20nsdelay.However,whenRB0goeslow,Q1exhibits
nearly500nsturnoffdelay.Theturn-offdelayresults
fromthe“storedcharge”effect,whereexcessminority
carrierchargeisstoredinthebaseregionofthetransistor
junctionstructureandmustberemovedbeforethetransis-torturnsoffandcollectorcurrentceases.Weassumethat
anyonedesirousofswitchingspeedsinthesub-microsec-ondrangeknowsaboutstoredchargesandthemitigatingtechniquestodealwiththeproblem.
OnefinalpointshouldbenotedwiththebipolartransistordesignofFigure3-14—thevoltageVbeing
switchedisimmaterial.Ofcourse,Q1mustberatedtowithstandthevoltage,butwithasuitabletransis-tor,thecircuitofFigure3-14couldswitch500voltsaseasilyasitswitches5volts.Thecurrentrequiredto
saturateorcutoffQ1isnotaffectedbythevoltageitswitches.
SmallN-ChannelMOSFETSwitch
Attheriskofconsiderableoversimplification,Q1inFigure3-14maybethoughtofasacurrentcontrolled
switch;currentinjectedintothebasecausesthecollectortobepulledclosetogroundpotential.Thereis
asimilarvoltagecontrolledswitch,theMOSFET,wherebyvoltageappliedtothedevice’sgatecausesthe
drainvoltagetobepulledclosetothesource,orgroundpotentialinalowsideswitch.
Figure3-15:2N4401switchingtimeIbase=6
mA,Ic=40mA;Ch1:PICpintobasedrive;Ch2:
2N4401collector.
Figure3-16:2N7000NPNLowSideSwitch.
Figure3-17:2N7000predictedon-resistance
variationwithgatevoltageanddraincurrent.
Figure 3-18: 2N7000 driven by PIC turn-on/
turn-offspeedCh1:PICoutput;Ch2:2N7000
drain.
Figure3-16istheMOSFETcounterpartofFigure3-14.A2N7000MOSFETcom-paresfavorablywiththe2N4401inthemaximumpermissiblevoltage,witha60V
rating.However,the2N7000isratedat200mAmaximumcontinuouscurrentand500
mAmaximumpulsedcurrentwithatotaldevicemaximumdissipationof400mW.
Let’slookattheareasofdifferencebetweentheMOSFETand
NPNbipolartransistor.
Whensaturated,aMOSFETactslikealowvalueresistor
betweenthedrainandsource,referredtoRDS(ON) ,withthecor-respondingvoltagebetweenthedrainandsourcedetermined
bytheproductofthedraincurrentIDandRDS(ON).Recallthat
inthe2N4401,thecorrespondingvoltageVCE(SAT) isapproxi-matelyaconstantvalueoverawidecurrentrange.
TherelationshipbetweenRDS(ON) andthegatevoltageis,asil-lustratedinFigure3-17,complex.Thepointtobetakenaway
fromFigure3-17isthatsincewecandriveQ1’sgateonlyto
+5voltswithahighonanoutputpin,weexitthesaturation
regionwithonlymodestdraincurrent.
Let’srunthroughthesame120mAsinkdesignwedidforthe
2N4401.We’vealreadydeterminedthatthe2N7000meets
ouropencircuitvoltagerequirementsandthat120mAis
lessthanthemaximumpermissiblecontinuousdraincurrent.
Withagatedriveof+5Vand120mAdraincurrent,Figure
3-17showsRDS(ON)willbeabout3.2ohms.SinceVDSisthe
IRdropacrossRDS(ON),wemaycalculateitas0.120A×3.2
ohms,or0.38volts,verysimilartoour2N4401NPNbipolar
transistordesign.
ThepowerdissipatedinQ1equalsID×VDS,or0.38volts×
0.120mAor46mW,almostidenticalinvaluewiththe48
mWwefoundforthe2N4401bipolarswitchandwellwithin
thedeviceratings.The2N7000’sthermalresistancejunction
toambientRθJAis312.5°C/wattandthemaximumjunction
operatingtemperatureis+150°C.Thetemperatureriseat
thecasewillthusbe312.5°C/watt×0.046watt,or14.4°C.
Assumingtheambientairtemperatureis120ºF(49°C),the
maximumjunctiontemperaturewillthusbe48°C+14.4°C=
62.4°C,allquiteacceptablevalues.
Ifweweretorepeatthisseriesofcalculationsfor,saya
400mAload,wewillfindRDS(ON)is3.6ohms,VDSis1.44
VandQ1’sdissipationis576mW,welloverthemaximum
permissiblevaluefora2N7000.Theproblemisthat5Vis
inadequategatevoltagetofullyturntheMOSFETat400mA.
Whenlookingatnanosecondswitchingwitha2N4401,we
foundsignificantturn-offproblemsduetostoredcharge.AsFigure3-18shows,boththeturnonandturn
offtimesfora2N7000arequiterespectable.But,acloseexaminationoftheleadingedgeofthePICoutput
foreshadowsthemaindifficultyofdrivingMOSFETs,gatecharge.Thesmallplateauorkinkintherisetime
ofthePICoutputreflectsthefactthatthegateofaMOSFETbehaveslikeanonlinearcapacitiveloadtoits
drivingcircuitry.Accordingly,theswitchingtimeperformanceisdefinedbytheabilityofthedrivingPIC
tochangethegatevoltage.The2N7000’sgate,assuminga5Vgatedriveand120mAload,looksapproxi-matelylikea200pFcapacitor.WewillexamineMOSFETgatedrivingproblemswhenwelookatahigher
powerdevice,theIRF510.Fornow,wesimplynotethataPICiscapableofdirectlydrivinga2N7000to
quiterespectableswitchingspeeds.
HighPowerBipolarLowSideSwitching
Boththe2N4401and2N7000arelowpowerdevices,goodforcon-tinuouscurrentsofafewtenthsofanampereatmost.Supposewe
wishtoswitchanampereortwowithabipolartransistor.
Inmostinstances,wewillnotbeabletobuildahighpowerswitch
bysimplyreplacingthe2N4401withahighpowerdevice,asthe25
mAorsomaximumcurrentoutputofahighPICpinisn’tenough
basedrivetoreliablysaturateasimplebipolarpowertransistor.
ConsiderFigure3-19.TheTIP31’smaximumcurrentratingis3.0
A,butatthisleveltheminimumguaranteedhFEisonly10,so300
mAbasedrivewouldberequiredforsaturation.Evenat1.5amperes
collectorcurrentthePICisshortofachievingfullsatura-tionwiththemaximumpossiblePICoutputcurrentasits
basedrive(This,ofcourse,wouldrequirehFEtobeatleast
60.).Figure3-20showstheVCEis920mV,insteadofthe
expected300mVshownintheTIP31’sdatasheetfor1.5A
collectorcurrent.
ADarlingtontransistorsolvesourbasedriveproblem.As
reflectedinFigure3-21,aDarlingtontransistorusesone
transistorasaemitterfollowercurrentboostertodrivethe
baseofthesecondtransistor.TheDarlingtonconfigura-tionmayusetwoseparatedevicesor,asinthecaseofthe
TIP120,thedrivertransistormaybeintegratedontothe
samedieasthepowertransistor.ThecompositehFEofthe
DarlingtonpairisapproximatelytheproductofthehFE ofthetwotransistors.Sincethedrivertransistordoesn’t
handlehighcurrents,itshFEmaybeverylarge,thusensuringa
compositehFEinthethousands.Foracollectorcurrentof1A,the
TIP120’shFEisapproximately3300,permittingcollectorsaturation
withabasecurrentofaslittleas300µA.
Sofar,sogood.TheTIP120isratedat60VVCE,5Amaximum
collectorcurrentICand65wattsdissipation,withanappropriate
heatsink.ThepricetobepaidfortheextrahFE,though,isfound
inthesaturationvoltage,VCE(SAT).ForanICof3A,VCE(SAT)is2.0V
whileat5A,VCE(SAT)is4.0V.AquickglanceinFigure3-21reveals
whyVCE(SAT)issopoor.ThedrivertransistorreliesuponVCE(SAT)as
itssourceofcurrenttosupplybasedrivetotheoutputtransistor.
Figure3-19:Highcurrentswitchingwith
TIP31.
Figure 3-20: TIP31 at 1.5A IC Ch1: Base Ch2:
collector.
Figure 3-21: Switching with TIP120
Darlington.
Recallthatthebaseoftheoutputtransistor’sbasemustbe
atabout0.7Vaboveitsemitterbeforebasecurrentflows.
And,thedrivertransistoritselfintroducesanother0.4Vor
sominimumvoltagedropevenifitissaturated.Hence,if
VCE(SAT)dropsbelow1.1V,thedrivertransistornolonger
cansupplybasecurrenttotheoutputstage.
Anotherareaweexpecttoseeaperformanceproblemwith
theDarlingtonisturnofftimeaspowertransistorsare
slowerthanthesmallswitchingdeviceswehavelookedat
sofar.Figure3-22confirmsourpessimism,astheTIP120’s
turnofftimeisnearlytwomicroseconds.However,we
shouldrememberthatformanyapplications,2µsturnoff
timeismorethanadequate.
CalculatingthebaseseriesresistorRbase,andtheother
parametersfollowtheapproachusedforthe2N4401andwon’tberepeated.However,attentionmustbe
paidtoproperheatsinkselectionforpowerdevices.AlthoughtheTIP120isratedat65wattsdissipation,
thatvaluepresumesanadequateheatsink.Absentaheatsink,itsratingisonly2watts.Operatingwithouta
heatsink,incontinuousoperation,aTIP120shouldnotsinkmorethan1Aorso—andeventhatispushingit.
HighPowerMOSFETLowSideSwitching IRF510Switch
Justastherearehighpowerrelativesofthe2N4401,the2N7000hasmanybigbrothersaswell.We’ll
quicklyexamineoneoftheoriginalpowerMOSFETsbutthenturnourattentiontoanewpowerMOSFET
devicethatsolvesmanyoftheshortfallsofearlierdevices.
TheIRF510isoneoftheearliestinexpensivepowerMOSFETsandisstillinproduction.It’sratedat100V
VDS,maximumIDof5.6Aandapowerdissipationof43watts,assumingproperheatsinking.Itissupplied
inaTO220package.RDS(ON) isunder1ohmatroomtemperature.(Moderndevicesareinthetensofmil-liohmrange,butwe’llstickwiththeIRF510toillustratethepointongatevoltageconcerns.)
WhenwesubstitutetheIRF510forthe2N7000,asshowninFigure3-23againwearelimitedto5Vgate
drive.IfweconsulttheRDS(ON)versusgatevoltageandcurrentplotofFigure3-24,weseethatfor5VVGSand
Figure3-22:TIP120turnofftimeCh1:PICoutput;
Ch2:TIP120collector.
Figure3-23:LowsideswitchingwithIRF510. Figure 3-24: IRF510 predicted on-resistance
variationwithgatevoltageanddraincurrent.
1AID,weexpectRDS(ON)tobeabout0.5ohm.But,supposewewishtosink3.0Aofcurrentrepresenting,saya
12voltsupplyanda4ohmload,wellwithintheIRF510’sratings.AsFigure3-24shows,theminimumVGSto
obtainsaturationat3Aexceeds5V.Ifallwehavetodrive
thegateisthe+5VhighfromourPIC,RDS(ON)willbemany
ohmsindicatingtheIRF510isoutofsaturationandoperat-inginthelinearregion.Infact,undertheseconditionswith
VGS=5VwewillfindVDSapproximately6.2VandID1.4A.
TheIRF510willdissipate8.6wattsanditsRDSis4.4ohms.
IfweexpectedtheIRF510toactasasaturatedswitch,with
anRDS(ON)ofafewtenthsofanohm,wewillbeinfora
surprise.And,ifourdesigndidn’tuseaheatsinkbecauseit
wasn’tnecessarywithalowRDS(ON),we’llhaveanevengreater
surpriseastheIRF510destroysitselffromoverheating.
Finally,roundingoutthedifficultiesindrivinganIRF510
directlyfromaPIC,weseetheexpectedturnonproblem.
Figure3-25showsnearly750µsturnondelay.
IPS021Switch
ManysuppliershaveaddressedtheshortcomingsseenwhenweexaminedtheIRF510.We’lllookatone
particulardevice,InternationalRectifier’sIPS021intelligentpowerMOSFETswitchwhichisratedat50V
VDSandhasseveralinterestingfeatures:
• Logiclevelinputwithbuilt-involtagemultiplierandlevel
convertertoensuresaturationoftheswitchingMOSFET;
• RDS(ON)0.125ohmsorlessatroomtemperatureand5V
input;
• Over-temperatureprotectedwithautomaticshutdown;
• Over-currentprotected,at5.5Anominal;
• Built-insnubbingprotectionforinductiveloads.
TheIPS021issuppliedinaTO-220packageandhasthesame
pinconnectionastheIRF510.Inalmostallcasesitcanbe
directlysubstitutedforanIRF510withlittleornochangein
circuitdesignorphysicallayout.AsshowninFigure3-26,
isconnectedinthesamefashion.InternationalRectifier
recommendsaseriesresistorof500ohmsto5Kohms
betweenthedrivingpinandtheinputpinoftheIPS021,
althoughitmaynotbenecessaryinallcases.
What’snottolikeabouttheIPS021?Themainissueis
switchingspeed,withturn-onandturn-offspeedsinthe
severalmicrosecondrange.Formanypurposes,wherea
fewmicrosecondsofturn-onorturn-offtimeisimmaterial,
theIPS021isagoodchoice.Figure3-27showsexcellent
performanceinswitching1.5AinthecircuitofFigure3-26.
Theseriesresistanceof240milliohmscomputedfrom
Figure3-27includeswiringandplugboardcomponentsas
wellastheIPS021’sRDS(ON).
Figure3-25:PICOutput;Ch2:IRF510Drain.
Figure3-26:LowsideswitchingwithIPS021
intelligentpowerswitch.
Figure 3-27: IPS021 Switching 1.5A Ch1: PIC
Output;Ch2:IPS021Drain.
HighSideSwitching SmallPNPSwitch
Figure3-28depictsasimplehighsideswitch.WhenRB0is
low,Q1isforwardbiasedintoconductionandcurrentflows
throughtheload.Let’sworkthroughafewdesignconcerns
withthissimplecircuit.Wewillassumetheloadisa47ohm
resistorandVis2volts.Hence,thecurrentbeingswitchedis
approximately45mA.
Wecalculatethebaseresistorandpowerdissipationexactlyas
foralowsideswitch,butwemustbecarefultoselectthecorrect
voltagesources.The2N4403hFEat–2VVCEand–150mAICis
specifiedataminimumof100.Wewillwishthebiascurrentto
beatleast450µA.(InaPNPtransistor,thecollectorisnega-tivewithrespecttotheemitter;hencethesignofthevoltages
andcurrentsarereversedfromtheNPNcase.)When
conducting,thebasebiassource(RB0)isat0voltsandthe
emitterisatVvolts(2.0Vinourdesignexample)positive.
Henceinourexamplethevoltagetodrivethebasecurrentis
2.0V.Wewillusethestandard700mVassumptionforQ1’s
base-emitterjunctionvoltagedropandwe’llignoreRB0’s
base-emitterjunctionvoltagedropandwe’llignoreRB0’s