Paper Code: UN415
5. (A) The average of X and Y = 108 So, X + Y2 = 108 ⇒ X + Y = 108×2 = 216 →(1) 300% X = Y i.e., Y = 3X X + Y = 216 ⇒ X + 3X = 216 ⇒ 4X = 216 ⇒ X = 216 4 = 54
The required difference = Y X = 3X X = 2X = 2×54 = 108
6. (D) Ratio of sides of a triangle is 3 : 4 : 5 The longest side = 15 cm
= 5 units
∴ 1 unit = 15 cm= 3cm5 Hence, 3 units = 9 cm and 4 units = 12 cm
Therefore, perimeter of the triangle = (9 + 12 + 15) cm
5×9×10 = 450 = P.
∴ 10P + 100 = 450×10 + 100 = 4500 + 100 = 4600
9. (D) Actual : 14.36×23 = 330.28 Addition : 14.36 + 23 = 37.36
The difference between his answer and the actual answer
= 330.28 37.36 = 292.92 10. (A) 10 11 3 1 5 7 9 2 8 6 4
∴ 11 more such basic shapes fill up the given box.
11. (B) Length (l), Breadth (b)
⇒ P = 2(l+ b) units
When length and breadth are doubled, l→2lb→2b
Then P = 2(2l + 2b) = 2×[2(l + b)] = 2×P
i.e., perimeter is doubled.
12. (D) The missing digit according to the given expansion is 7.
13. (B) H.C.F. of 11, 33 and 88 is 11. L.C.M. of 11, 33 and 88 is 11×3×8 = 11×24 = H.C.F.×24
14. (D) 0.3 ÷ 0.3×3 = 1×3 = 3
15. (C) The sum of the three angles in a triangle is 180o or 2 right angles.
16. (B) Area of square = 144 cm2
⇒ Side = 144 cm = 12 cm
division (D), multiplication (M), addition (A) and subtraction (S) have to be performed in order.
18. (A) The product of factors in the prime factorisation of a number
= (2 × 2 × 2) × (3 × 3 × 3 × 3) × 5
∴ The number = The product of the given prime factors = 3240
19. (A) Part of the book read =3 5
∴ Part of the book left to be read
3 2 = 1 =
5 5 −
No. of pages left to be read = 80
∴ 2
5 part = 80
∴ No. of pages in the book
5 =80×2 = 40 5×
= 200
20. (C) Let the third number be 100. Required % =120 100= 80
150×
21. (C) 684 > 68.4 > 6.84 > 0.684
∴ R > Q > S > P
22. (B) A radius of a circle joins its centre to a point on it.
23. (D) Volume of 4 similar cubes of side 5 cm = 4×5×5×5 cm3 = 500 cm3
24. (C) 909000 ÷ 9090 = 159 ?
100 = 159 ?
6.63 + 0.13 = 6.76 The value of R is 6.76 + 0.13 = 6.89 ∴ P + Q R = 6.63 + 6.76 6.89 = 6.50 = 6.5 27. (B) 25 →48 1 48 2 = 24 5 → ÷ 5 = 24 5 = 120 5 × 3of 120 = 3 120 5 5 ∴ × = 3×24 = 72 28. (A) Speed = 45 km/h Time = 36 minutes = 36 hr60 Distance = Speed×Time
× 36
= 45 60 = 27 km
29. (B) Six hundred one thousand and five hundred = 601500
30. (B) After 10 hours, the time would be 2 oclock.
In 12 hours, the hour hand moves through 360o.
∴ For 10 hours, the hour hand moves through 36012o ×10 = 300o
31. (B) Score of Pavan = 76 = 45 of score of Prateek 4 76 5 → 5 76 5 5 → × 4 32. (C) 33. (C) 25% of 50 = 25 50 100× = 12.5 250% of 20 =250 20 100× = 50
∴ The required difference = 50 12.5 = 37.5 34. (C) 3 3, 6, N 2 1, 2, 1, 1, N ! N $ Given that LCM of 3, 6, x is 18, ∴ LCM = 3 2× × 6N= 18, x = 18. 35. (A) From the given figure,
AOB = COB COA
∠ ∠ − ∠ = 134o 90o = 44o 36. (C) 453.07 = 400 + 50 + 3 + 1007 = 400 + 50 + 3 + 0.07 Required difference = 50 0.07 = 49.93 37. (B) 2 × 25 × 2 = 104 , 5 × 52 × 5 = 25 ,10 7 × 25 × 2 = 104 9 × 5 2 × 5 = 45 ,10 7 ×2 × 55 = 3510 ⇒ 4 <14 25 35 45< < < 10 10 10 10 10
Hence 1410 ⎛⎜⎝i.e.,75⎞⎟⎠ lies between
⎛ ⎞
The factors of 108: , 2, ! , 4, 6, 9
12, 18, 2%, 36, 54, 108
The highest common factor of 81 and 108 is 27.
∴ p + 3 = 27 p = 24.
40. (C) 23 weeks = 7 × 23 days = 161 days
⇒ 23 weeks 16 days = (161 16) days = 145 days
= (140 + 5) days = ((7 × 20) + 5) days = 20 weeks 5 days 41. (C) A : B = 4 : 3
Height of B = 37 (Total height) = 1 2⋅ m Total height = 7 1.2 m× 3 = 2.8 m ∴ Height of A = 4 2.8 m× 7 = 1.6 m 42. (A) 1 Kg = 1000 gm; 1 l = 1000 ml; 1 km = 1000 m (i) 604 g × 100 = 60400 g = 60.4 kg (ii) 415 ml × 10 = 4150 ml = 41.5 l (iii) 0.25 km × 100 = 25 km = 25000 m (iv) 1.12 l × 10 = 11.2 l = (11.2 × 1000) ml × = 100% 12 = 50% 44. (A) 9103 −415 − 93 21 =10 5 − × − 93 (21 2) 93 42 = 10 = 10 51 1 = = 5 10 10 45. (D) 9.801 × 100 = 980.1 5. 243 × 10 = 52.43 96.4 × 1000 = 96400 28.474 × 100 = 2847.4
∴ Option (D) is the true statement.
General Science
46. (D) The winged seed of drum stick get dispersed by the wind.
47. (D) Parrot-lungs, Fish-gills, Earthworm-skin. Cockroach breathe through tiny holes called spiracles. It does not use gills. 48. (B) A ribcage is formed by the fusion of
curved bones. It protects the heart and the lungs.
49. (C) Fishing rod belong to III class lever. FEL. It is class III lever.
50. (A) Carbon dioxide is released when oxygen gas is used up in the burning of things and during respiration.
51. (B) The cup of icecream that is taken out from the refrigerator is in solid state when it is left on the table for few hours get melted and changed to liquid state. When the liquid form of icecream when again put back to the refrigerator change to solid.
develops or forms into stem and leaves grows up and the early roots called radicle grows down.
57. (A) In the water cycle water vapour get cooled and turn into a liquid.
58. (B) An x-ray gives the fracture details to the doctor.
59. (B) Light-weight, small and dry seeds are dispersed by wind.
60. (B) Elbow and knee joints are called hinge joints and the joints at shoulder and pelvis are called ball and socket joints. 61. (A) Diseases that can spread from one person
to another are called infectious or communicable diseases.
62. (D) Carelessness is the major cause of most accidents.
63. (B) In the given lfigure X is liquid Y is solid and Z is gas.
64. (B) Insects have jointed appendages and has no bones.
65. (A) Brinjal plant is a herb with taproot and wheat is herb with fibrous root system. 66. (B) Tadpole breathe through gills. A tapole is
a fish like and breathe through gills. 67. (D) Beans grows well during winter. Winter
crops are called rabi crops.
68. (C) The given animal tern migrates to warmer places.
69. (A) Lava cools to form igneous rocks. 70. (A) The chemical formula of water is H2O. 71. (A) White blood cells helps us to fight
against disease causing germs like viruses and bacteria.
72. (C) A football, that rolls for some distance and then stop on its own is due to frictional force. Frictional force opposes the movement of ball.
73. (B,C) Miles, metres and light years are used to measure distances and length.
is I order lever.
If load lies between fulcrum and effort it is II order lever.
If effort lies between load and fulcum it is III order lever.
76. (C) Earthworm and frog breathe through moist skin.
77. (A) Ball and socket joint enables us to swing our arms.
78. (A) Part A in the given figure represents nitrogen. About 78% of nitrogen is present in the air.
79. (C) There are 3 types of levers.
80. (D) A freely falling body when thrown up into the air come back to the earth is due to gravitational force.
81. (B) Fossils are found in sedimentary rocks. 82. (B) Heat, light and electricity are all forms of
energy.
83. (A) A mango tree is a producer.
84. (C) With respect to brightness venus is ranked third in the solar system. 85. (B) In the given figure the parts lebelled in
flower (1) as ovary (2) as petal (3) as stamen and (4) as sepal.
86. (A) A bat and a bird are flying animals and so the bird has wings and the bat also has modified wings.
87. (C) A hard shell protects tortoise from its predators.
88. (B) Citrus fruits like orange and lemon are rich in vitamin C.
89. (B) The moon reflects the light of the sun at night.
Solutions for Class : 5 Mathematics 1. (A) 7.8 + 2.460 – 0.09 = R 7.8 + 2.4 60 – 0.09 = R 7.8 + 24 600 – 0.09 = R 7.8 + 0.04 – 0.09 = R 7.84 – 0.09 = R R = 7.75
Rounding off R to 1 decimal place, we get 7.8.
2. (D) The unit shape in the given tessellation is .
3. (D) A solid figure with 6 square faces is a cube.
4. (B)
1 0 0 0 0 0 0
TM M H.Th T.Th Th H T O
0
In the numeral for 10 millions, 1 is followed by 7 zeroes. 5. (D) 3 2145 11 143 13 5 715
UNIFIED COUNCIL
UNIFIED COUNCIL
A n I S O 9 0 0 1 : 2008 C e r t i f i e d O r g a n i s a t i o nNATIONAL LEVEL SCIENCE TALENT SEARCH EXAMINATION
Paper Code: UN 418
7. (A) Total marks = 75 + 25 = 100 Required ratio =75 : 100 = 3 : 4 8. (A) On cross multiplication,
we get 9 8 15 16 72 240 9 15 < 16 8
9. (D) List all the prime numbers between 17 and 41. Then, find the value of p and q. 17, 19, 23, 28, 31, 37, 41.
p = 23, q = 37
q – p = 37 – 23 = 14 10. (D) 100 – 7 1 + 5
According to DMAS, as multiplication has to be carried out before addition and subtraction, the given expression can be written as 100 – (7 1) + 5.
11. (C) No. of cubes in solid A = 8 No. of cubes in solid B = 19
19 – 8 = 11 more cubes must be added to solid A to make it solid B.
12. (B) The sum of the lengths of two sides of a triangle is greater than its third side. 13. (A) 7 is the first digit of the decimal part of
15. (A) + = + 10 5 2 10 10 10 7 4 + 5 8 4 = = = 10 10 5
The missing number is 5.
16. (C) The prime numbers between 50 and 100 are 53, 59, 61, 67, 71, 73, 79, 83, 89 and 97, which are 10 in number.
17. (C) The figure in option (C) is a trapezium which has only one pair of parallel lines. 18. (C) The area of a square = 144 sq. m
i.e., side side = 144 sq. m = (12 12) sq. m
The side of the square = 12 m
19. (C) The required fraction is 35 seconds =35= 7
1 minute 60 12
20. (A) The L.C.M. of co-primes is their product. 21. (C) 792 650 = (800 – 8) 650
= 800 650 – 8 650
The value of the product of the missing numbers is 8 650 = 5200
22. (B) The sum of the three angles in a triangle is 180o. o o o BAC = 180 (90 + 21 ) = 180o – 111o = 69o 23. (A) P = 12 12 12 m3 = 1728 cu. m Q = 8 6 4 m3 = 192 cu. m
Clearly, P is greater than Q. 24. (B) 5 thousandths = 5 1000 =0.005 = 10 100 100 = 10 50% of 10 50 = 100 10 = 5 Since 10 > 5, 10% of 100 > 50% of 10.
27. (D) Chord MN and QR pass through the centre O of the circle. So, they are diameters.
28. (B) The product of a fraction and its reciprocal is 1.
29. (D) Factors of 36 are 1 , 2 , 3 , 4 , 6 , 9, 12 , 18, 36.
Factors of 24 are 1 , 2 , 3 , 4 , 6 , 8, 12 , 24.
Common factors of 36 and 24 are 1, 2, 3, 4, 6, 12.
P is the 2-digit common factor of 36 and 24.
P = 12
Q is a factor and multiple of 28, which is 28. P + Q = 12 + 28 = 40 30. (B) Q = 2 R Q Q = R = 1 R = 1 Q = 2 31. (C) Area of rectangle = 42 m2 Length = 7 m Breadth = 42 7 = 6 m
= 5 12 + 10 4 12 + 4 = 16 notes
Hence, the number of 10 notes is 4. 34. (B) The lines perpendicular to AE are AB and
DE.
35. (C) 12 4 3 12 2 6 125 ;3 3 9 ;1 6 6
Decending order is 9 , 6 , 5
12 12 12 The required order is , ,1
4
3 5
2 12. 36. (B) Area of X = 8 units2
Area of Y = 11 units2
Their differnce = (11 – 8) unit2 = 3 units2 37. (B) Oranges in Box A = 5984
Oranges in Box B = 5984 + 1250 = 7234 Oranges removed from Box B = 2365 Oranges left in Box B = 7234 – 2635
= 4599
38. (D) The given numbers are factors of 63. 63 = 1 63
3 21 7 9
Hence, the missing factor is 63.
39. (B) Point ‘B’ should be joined to Q to get B
= 86o
40. (D) Age of Tara = Age of Dev Age of Jai = 3 Dev’s agee Given, total age = 60
Tara’s age + Dev’s age + Jai’s age = 60 Dev’s age + Dev’s age + 3(Dev’s age)
Given,
= 2 2
3= 24
6 = 24
= 24 6 = 442. (D) Amount with Tanish = 633
More amount needed to buy 9 pens = 18
Amount needed to buy 9 pens = (63 + 18)
= 81
Hence, cost of 1 pen = 819 9 43. (B) 29 = 30 – 1 = 10 + 10 + (10 – 1)
= XXIX
No. of match sticks needed = 7
44. (A) Co-prime numbers have no common factor other than 1. So, their H.C.F is 1.
45. (D) TL L T.Th Th H T O 7 1 6 8 4 5 9 5 6 3 5 0 8 2 0 9 5 3 3 8 7 1
In 7653231, 5 is in the ten thousands place and hence has the greatest value.
General Science
46. (C) The given fruit is of castor. It has hooks which get stuck to the skin of animals and get dispersed.
47. (D) Ribcage protects the lungs and heart. 48. (A) Igneous rocks that are formed due to
53. (B) The food items given in the figure are sources of mainly carbohydrates. 54. (B) Cotyledon supplies food to the
developing embryo.
55. (B) Gneiss is formed by the metamorphosis of granite.
56. (D) The life cycle is
Seedseedlingsaplingplant. 57. (B) Brain is the controlling centre of the body. 58. (B) The amount of water vapour is present in
air is called humidity.
59. (B) A fulcrum is the fixed point of a lever. 60. (C) Salt is separated from salt water by
evaporation.
61. (D) Overgrazing grass by like cattle cause soil erosion as most of the small plants are removed. Small grass like plants help to conserve soil.
62. (D) Ice is lighter than water.
63. (C) Ginger is the stem part of the plant. A stem has nodes and internodes on it. 64. (C) A grasshopper can camouflage itself in the grass to protect itself from the predator.
65. (C) Water can dissolve many substances, hence it is known as a universal solvent. 66. (C) Sweet potato is a modified fibrous root. It grows from the root part of the plant. 67. (C) The automatic responses of the body to
an event is called a reflex action. 68. (A) The person who goes into space is called
an astronaut.
69. (A) Lever in which the fulcrum is located between the load and the effort is I class lever.
70. (D) Animals move or migrate to escape harsh weather, insearch of food and to reach their breeding grounds.
72. (D) Corn is a fibre food.
73. (D) The arragement of veins on a leaf are is called venation. In dicots the venation is reticulate and in monocots it is parallel. 74. (A) The thigh bone is the longest bone in our
body.
75. (B) Lunar eclipse occurs on a full moonday. 76. (B) The camel is called the ship of the
desert.
77. (B) Cholera spreads through contaminated water.
78. (B) When the moon comes between the sun and the earth, it blocks the sun and this causes a solar eclipse.
79. (B) Open terrace is not a safe place to fly kites.
80. (A) Frog is an egg laying that breathe through lungs when it is on land. In the given diagram ‘Y’ represents frog.
81. (C) In desert plants stem is modified in the form of fleshy leaves that helps them to make food.
82. (A) Berry seeds are dispersed by birds. 83. (A) Bones and joints are parts of the skeletal
system.
84. (A) Rice is rich in carbohydrates. Carbohydrates are energy giving foods. 85. (C) A ramp is an inclined plane.
86. (C) Fish is rich in proteins. Proteins are body building foods.
87. (D) Goitre is a deficiency disease.
88. (C) The moon is our nearest neighbour in space.
89. (D) Plastic is non-biodegradable substance which on burying in wet ground remains the same even after several years. 90. (D) Whale, Snake and fish are vertebrates.
Solutions for Class : 5 Mathematics 1. (A) 5 2025 9 81 9 5 405 2025 = 5 5 9 9 = A A B B Therefore, A = 5 and B = 9. 2. (C) 3, 1 4, 25, ? , 47 4 5 6 8 3 9 17 39 = , , , , 4 5 6 8 +6 +8 +10 +12 +1 +1 +1 +1
The missing fraction is 17 + 10
6 + 1 27 = = 7 6 3 7. 3. (A) 28.5 7 – 27 3 – 29 3 = 31.5 oC
4. (A) Area is the amount of surface occupied by
an object. 5. (C) ML = 1000 + 50 = 1050 LX = 50 + 10 = 60 CLV = 100 + 50 + 5 = 155 XL = 50 – 10 = 40