A ~ & Aa.vc Aa\tc.
corollary 8 (note that the hypothesis that the states are pure is not
used in the first part of their proof)). Hence and cOg* are not
disjoint. I
We now investigate some properties of states on the C*-algebra
A
. Before presenting the main results we prove some lemmas.(10.3) Lemma. Every element A of a;A may be written
uniquely in the form A = X + Y for some X €
A Î
and some Y € L(P). Define a mapping 7t :A
— ^ lT(P) by tc (A) = Y whenever A = X + Ywith X Ê and Y L(P). Then (L^ , % ) is a representation of
A
.
Proof. If T € AM^nlTfP) then T commutes with every
Ut
so^ Ut TUt = T .
Hence
A t n l“(P) ~ {o}
and the uniqueness of the expression for eachA
now follows. By (9.18) is an ideal inA
and it is noweasily verified that iz is a representation. I
- (10.4) Lemma. Let f,gcL^ If <f!Ep(R)g> = 0 for all Borel sets R
then there are disjoint Borel sets S, and in with
Ep(S| )f = f and Ep(S;i)g = g.
Proof. Since and
E
q are unitarily equivalent we mayprove the result with
B
q,
replacingEp
. Suppose- {x6 IR” :
u(x) > o }
then= 4,«- = o
so =
o
(almost everywhere). A similar argument shows(almost everywhere) so
u = o
(almost everywhere). Repeating thisprocedure with
u
replaced by the imaginary part of f we deducethat f g = O' (almost everywhere). Hence f W = o or = o for
almost all ac e Let S, »
{=c; f(^)
t* o } and 5% - 3o}
then £Q(5,)f = f , (Sa)g = 5 and Si o Sj has measure zero. The resultfollows from this. *
(10.5) Definition. For each unit vector f in we denote
by the state on
A
defined bya^TCA) = JÏ%<(4flAUtf> (VA <44). (This is a state by (9.2).)
(10.6) Theorem. Let f and g be unit vectors in l\/R'^)
then the states and on
A
are disjoint if and only ifthere are disjoint Borel sets S, and Sj, with
Ep(S, )f = f and Ep (S_2)g = g.
Proof. Let tv be the representation of A defined in
(10.3) then it follows from the definition of A t that <v^(A) = <fi7T(A)f)>
and OJj(A) = < 3 I
for all A ^ A , Note that ir(A) - A whenever A & L*(P) and Tr(A) = o if A e A^.
<-F I ir(£p(R)) 3 > = < F l E p ( R )5> o
for some R and it follows that co* and
ccÇ
are not disjoint (4.3). Conversely suppose £/»(s,)f = and £/>(Sa)^ = 5 whereS,
andSx
are disjoint. Since 7t(a54) =Lt^(P)
it follows that the range of £p/S, ) is invariant under Tc(/\H) and we shall denote by tt, thecorresponding subrepresentation of tt. Similarly let
Ttx^
be thesubrepresentation corresponding to the range of £"p (Sa). Let & be
the von Neumann algebra generated by TT(^$4) then
£, =
lF(P)
= <8^ and henceEp(.s,)
and are equal to their owncentral supports in . Since S, and 5% are disjoint, )
and
Ep(Sx)
are orthogonal and it follows that andFx
are disjoint (Dixmier (1977) pll5; see also p375 for further details of central supports).To' complete the proof it is now sufficient to show that the canonical cyclic representations associated with
cop
and oj* are unitarily equivalent to subrepresentations of tt, andFx
. Let M be the closure of the linear manifold {%(A)f ; A€/>s4 j = {Af ■Then
M
is invariant under it(A)
andM
is contained in the range ofEp(St) ,
LetiZo
be the corresponding subrepresentation ofx,
then
co“ (A) = <(f 1 7Ttf(A)-r ]>
and f is clearly a cyclic vector for
~Fo
• Hence tTo is unitarily equivalent to the canonical cyclic representation associated with (Bratteli and Robinson (1979) p56), A similar argument showsthat the canonical cyclic representation associated with is
(10,7) Corollary. Let f be a unit vector in L^ and let S I be a Borel set with
Ep(S)f 0 ^ Ep(S)f
then
=* 11
£p(S)f
Jl cOg +1} £p(st-f Ij
where 3 — llEp(s)f 11"* £p(s)f and L = 'Ep(S) f . Thus each cj™ is a mixture of two disjoint states.
Proof. By the theorem
co^
and are disjoint and ifA
then A ^ so •(uTCA) = *2^ <f|ufAu+f>
Jt L < Ep(s)f j Ut A Ut Ep(s)f > + < E p (s /f I u^A Ut £p(s)^f >
/l£p(s)f 11^ cu” (A)
+ IIEp(S)^ftcJ>uiA)
I States of the form (J* (f e L^) may be generalised to give states which are limits of states described by density operators.(10.8) Theorem. Let W be a density operator on L*" , then
the formula
C U ( A ) = titc o Ty ( W U ^A U t )
defines a state
co
onA .
. If A = x+Y where X ^A t
and Ye 1*(P) thenw ( A ) = Ty(>AJy)
In particular
cJ>
vanishes on oW* ,Proof. Let A s ^ then A = X+Y for some Xe
A t
and some ye 1*(P). Then for every f€t
we haveLet ; y £ M } be an orthonormal basis for
it
consisting ofeigenvectors of W and for each
f-eN
let ay be the eigenvalue »associated with fy . Since IE #y =
I
it follows that%
(if K-ff I
exists and also thata, (2 2 L < fK u fx l4 f» > ) = o
since the above sum is uniform by the Weierstrass M-test (Apostol (1974) p223). Hence
GO ( A ) = Z <( fy I W uf AUt >
S a , < f. |Y f,> - Tf ( w y )
so
Ct
3 is well defined and co (A) = l>{wy). Clearly w is linearand co(z) = = I.
Finally since is an ideal in
A
(9.18) we haveCO (A^A) = w ( x * x + x * y + y * x + y * y ) Ty (wy*y)
^ o
so CO is a state on ^4. I
(10.9) Definition. For each density operator W on L^ we
denote by co" the state on
A
defined in (10.8), A stateco
on xfl will be called normal if there is a density operator W on L^ with(10.10) Corollary. If W is a density operator on L then CcC is not a normal state on
A
.Proof. By way of contradiction suppose there is a density