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Permutation and Combination Important Points

In document Maths for jee (Page 189-193)

* Fundamental Principle of counting

:-If an event can occur in m ways and corresponding to each way another event can occur in p ways and corresponding to them, a third event can occur in r ways, then the total number of occurances of the events is mpr.

* Factorial :- The Product of first n natural numbres is known as Factorial. It is denoted by n! or

 n!n.(n 1).(n 2)...3.2.1

 n! n.(n 1)! n(n 1)(n    2)!

 0! 1

* Permutations (Arrangements)

:- A Permutation is an arrangement in a definite order of a number of distinct objects taking some or all at a time.

 The number of linear permutations of n different objects taking r at a time where 1 r n r, nN, is denoted by nP .r

 If repetitions of objects is not allowed and arrangement is linear, the arrangements also called a linear Permutation.

nP = n ( nr 1)(n 2)....( n r 1)

n r n!

P =

(nr)!  n Pr n ( n1 )P( r1 )

nPn n !nP1 nnP2 n ( n 1)

 Number of permutations of n distinct objects taken r at a time with repetitions allowed is n .r

* Permutations when some of the objects are identical (alike or one kind)

:-If P objects are alike, 1 P objects are alike different from earlier ones...., 2 P objects are alike differentK from earlier ones and nP1P2....PKthen the number of are permutations of n things is

1 2 K

n!

P !P !....P !

* Circular Permutation

:-The number of ways of arranging n different objects on a circle is called the number of circular

permutations of n objects.

 The number of circular permutations of n different things is (n 1)!

 In circular permutation, anti-clockwise and clockwise order of arrangements are considered as distinct permutations .

 If anti-clockwise and clockwise order of arrangements are not distinct then the number of circular permutations of n distinct items are (n 1)!

2

 Ex. 1 : The number of permutations of 5 persons seated around the round table is (5-1) ! = 4! . Because with respect to the table, the clockwise and anti-clockwise arrangements are distinct.

 Ex. 2 : Arrangements of beads, necklace, arrangements of flowers in a garland etc., then the number of circular permutations of n distinct items is (n 1)!

2

 The number of all permutations of n different objects taken r at a time, when a particular object is to be always included in each arrangement is r.n 1 Pr 1

 The number of all permutations of n different objects taken r at a time, when a particular object is never taken in each arrangement is n1 Pr

 Number of all permutations of n different objects taken r at a time in which two specified objects always occur together is 2 !( r 1). n2Pr 2

Combination (selection) :- The number of ways of selecting r things out of n different things is called r combination number of n things and is denoted by

n

 The product of n consecutive integers is divisible by n!

 The number of ways of selecting one or more items from a group of n distinct items is 2n 1

 The number of ways of selecting none, one or more items from a group of n distinct items is 2n

 The number of ways of selecting r items out of n identical items is 1.

 The number of ways of selecting one or more (at least one ) items out of n identical items is n.

 The number of ways of selecting none, one or more items out of n identical items is n+1.

(Here 1 is added for the case in no item is selected from the set of n identical items.)

 The number of ways of selecting none, m items of one kind, n items of another kind and p items of another kind out of m+n+p items is (m+1) (n+1) (p+1).

 The number of ways of selecting at least one (one or more) items from a collection of m items of one kind, n items of another kind and p items of another kind is (m+1) (n+1) (p+1) -1.

(Here -1 is used for rejecting that one case in which no item is selected.)

 The number of ways of selecting at least one (one or more) item of each kind from a collection of m items of one kind, n items of another kind and p items of another kind is mnp.

 The total number of ways of selecting one or more items from p identical items of one kind, q identical items of another kind, r identical items of another kind and n different items is

(p 1) (q 1) (r 1) 2n 1

    

 The number of ways in which a selection of at least one item can be made from a collection of n distinct items and m identical items is 2 (m 1) 1n  

(here -1 is used for rejecting that one case in which no item is selected)

 Number of ways in which m+n+p items can be divided into unequal groups containing m, n and p items is m n 1 m n 1 n p p

(m n p )!

C . C . C

m !n !p !

   

 Number of ways to distribute m+n+p items among 3 persons in the group containing m, n and p items is

(m n p)!

m!n!p! 3!

  

(Here 3! Is for arranging the things in between 3 persons as no two persons are alike)

 The number of ways in which mn different items can be divided equally into m groups, each containing n objects and the order of the groups is not important, is m

(m n)! 1 ( n !) m!

 

 The number of ways in which mn different items can be distributed equally among m different persons is m

(m n)!

( n!)

 The number of diagonals of n sided convex polygon is nC2- n = n(n 3), n 3 2

 

 There are n points in the plane such that no three of them are in the same straight line, then the number of lines that can be formed by joining them is nC2

 There are n points in the plane such that no three of them are in the same straight line, then the number of triangles that can be formed by joining them is nC3

 There are n points in the plane such that no three of them are in the same straight line except m of them which are in same straight line then the number of lines that can be formed by joining them is nC2m C21

 There are n points in the plane such that no three of them are in the same straight line except m of them which are in same straight line, then the number of triangles that can be formed by joining them is nC3mC3

 If n points lie on a circle then the number of straight lines formed by joining them isnC2

 If n points lie on a circle then the number of triangles formed by joining them is nC3

 If n points lie on a circle then the number of quadrilateral formed by joining them is nC4

In document Maths for jee (Page 189-193)

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