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10 Tail Weight Measures: Hazard Rate Function and Mean Excess Loss Function

In this section with classify the tail weight of a distribution based on the hazard rate function and the mean excess loss function.

Classification Based on the Hazard Rate Function

Another way to classify the tail weight of a distribution is by using the hazard rate function:

h(x) = f (x)

S(x) = F0(x)

1 − F (x) = − d

dx[ln S(x)] = −S0(x) S(x).

By the existence of moments, the Pareto distribution is considered heavy-tailed. Its hazard rate function is

h(x) = f (x) S(x) = α

x + θ.

Note that h0(x) = −(x+θ)α 2 < 0 so that h(x) is nonincreasing. Thus, it makes sense to say that a distribution is considered to be heavy-tailed if the hazard rate function is nonincreasing. Likewise, the random variable X with pdf f (x) = xe−x for x > 0 and 0 otherwise has a light-tailed distribution according to the existence of moments (See Problem9.1). Its hazrad function is h(x) = x+1x which is a nondecreasing function. Hence, a nondecreasing hazard rate function is an indication of a light-tailed distribution.

Example 10.1

Let X be a random variable with survival function f (x) = x12 if x ≥ 1 and 0 otherwise. Based on the hazard rate function of the distribution, decide whether the distribution is heavy-tailed or light-tailed.

Solution.

The hazard rate function is

h(x) = −S0(x)

S(x) = −−2

x3 1 x2

= 2 x. Hence, for x ≥ 1,

h0(x) = −2 x2 < 0

which shows that h(x) is decreasing. We conclude that the distribution of X is heavy-tailed

Remark 10.1

Under this definition, a constant hazard function can be called both non-increasing and nondecreasing. We will refer to distributions with constant hazard function as medium-tailed distribution. Thus, the exponential random variable which was classified as light-tailed in Example9.1, will be referred to as a medium-tailed distribution.

The next result provides a criterion for testing tail weight based on the probability density function.

Theorem 10.1

If for a fixed y ≥ 0, the function f (x+y)f (x) is nonincreasing (resp. nondecreas-ing) in x then the hazard rate function is nondecreasing (resp. nonincreas-ing).

Thus, if f (x+y)f (x) is nondecreasing in x for a fixed y, then h(x) is a nonincreas-ing in x. Likewise, if f (x+y)f (x) is nonincreasing in x for a fixed y, then h(x) is a nondecreasing in x

Example 10.2

Using the above theorem, show that the Gamma distribution with parame-ters θ > 0 and 0 < α < 1 is heavy-tailed.

for 0 < α < 1. Thus, the hazard rate function is nonincreasing and the distribution is heavy-tailed

Next, the hazard rate function can be used to compare the tail weight of two

distributions. For example, if X and Y are two distributions with increasing (resp. decreasing) hazard rate functions, the distributions of X has a lighter (resp. heavier) tail than the distribution of Y if hX(x) is increasing (resp.

decreasing) at a faster rate than hY(x) for a large value of the argument.

Example 10.3

Let X be the Pareto distribution with α = 2 and θ = 150 and Y be the Pareto distribution with α = 3 and θ = 150. Compare the tail weight of these distributions using

(a) the relative tail weight measure;

(b) the hazard rate measure.

Compare your results in (a) and (b).

Solution.

(a) Note that both distributions are heavy-tailed using the hazard rate anal-ysis. However, h0Y(x) = −(x+150)2 2 < h0X(x) = −(x+150)1 2 so that hY(x) de-creases at a faster rate than hX(x). Thus, X has a lighter tail than X.

(b) Using the relative tail weight, we find

x→∞lim fX(x)

fY(x) = lim

x→∞

2(150)2

x + 150)2 ·(x + 150)4 3(150)4 = ∞.

Hence, X has a heavier tail than Y which is different from the result in (a)!

Remark 10.2

Note that the Gamma distribution is light-tailed for all α > 0 and θ > 0 by the existence of moments analysis. However, the Gamma distribution is heavy-tailed for 0 < α < 1 by the hazard rate analysis. Thus, the concept of light/heavy right tailed is somewhat vague in this case.

Classification Based on the Mean Excess Loss Function

A fourth measure of tail weight is the mean excess loss function as introduced in Section 5. For a loss random variable X, the expected amount by which loss exceeds x, given that it does exceed x is

e(x) = eX(x) = E[X − x|X > x] = E(X) − E(X ∧ x) 1 − F (x) .

In the context of life contingency models (See [3]), if X is the random variable representing the age at death and if T (x) is the continuous random variable

representing time until death of someone now alive at age x then e(x) is denoted by ˚e(x) = E[T (x)] = E[X − x|X > x]. In words, for a newborm alive at age x, ˚e(x) is the average additional number of years until death from age x, given that an individual has survived to age x. We call ˚e(x) the complete expectation of life or the residual mean lifetime.

Viewed as a function of x, an increasing mean excess loss function is an indication of a heavy-tailed distribution. On the other hand, a decreasing mean excess loss function indicates a light-tailed distribution.

Next, we establish a relationship between e(x) and the hazard rate function.

We have

But one of the characteristics of the hazard rate function is that it can generate the survival function:

SX(x) = e

Rx 0 h(t)dt. Hence, we can write

e(x) = increasing function of x (and therefore e(x) is increasing) then the hazard rate function is decreasing and consequently the distribution is heavy-tailed.

Likewise, if the SXS(x+y)

X(x) is a decreasing function of x (and therefore e(x) is decreasing) then the hazard rate function is increasing and consequently the distribution is light-tailed.

Example 10.4

Let X be a random variable with pdf f (x) = 2xe−x2 for x > 0 and 0 otherwise. Show that the distribution is light-tailed by showing SXS(x+y)

X(x) is a decreasing function of x.

Solution.

We have SX(x) =R

x 2te−t2dt = e−x2. Thus, for a fixed y > 0, we have SX(x + y)

SX(x) = e−2xy− y2

whose derivative with respect to x is d

dx

 SX(x + y) SX(x)



= −2ye−2xy−y2 < 0.

That is, SXS(x+y)

X(x) is a decreasing function of x

Practice Problems

Problem 10.1

Show that the Gamma distribution with parameters θ > 0 and α > 1 is light-tailed.

Problem 10.2

Show that the Gamma distribution with parameters θ > 0 and α = 1 is medium-tailed.

Problem 10.3

Let X be the Weibull distribution with probability density function f (x) =

τ xτ −1e(xθ)τ

θτ . Using hazard rate analysis, show that the distribution is heavy-tailed for 0 < τ < 1 and light-heavy-tailed for τ > 1.

Problem 10.4

Let X be a random variable with pdf f (x) = 2xe−x2 for x > 0 and 0 otherwise. Determine the tail weight of this distributions using Theorem 10.1.

Problem 10.5

Using Theorem 10.1, show that the Pareto distribution is heavy-tailed.

Problem 10.6

Show that the hazard rate function of the Gamma distribution approaches

1

θ as x → ∞.

Problem 10.7

Show that limx→∞e(x) = limx→∞ 1 h(x). Problem 10.8

Find limx→∞e(x) where X is the Gamma distribution.

Problem 10.9

Let X be the Gamma distribution with 0 < α < 1 and θ > 0. Show that e(x) increases from αθ to θ.

Problem 10.10

Let X be the Gamma distribution with α > 1 and θ > 0. Show that e(x) decreases from αθ to θ.

Problem 10.11

Find limx→∞e(x) where X is the Pareto distribution with parameters α and θ and conclude that the distribution is heavy-tailed.

Problem 10.12

Let X be a random variable with pdf f (x) = (1+x)1 2 for x > 0 and 0 other-wise. Find an expression of limx→∞e(x).