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Proof of lemma 2.1. That q(· |X)is an element of L1(µ)for each realization of X. That it is also a random variable (i.e., a measurable map) follows easily from separability of L1(µ).22 To show thatEq(· |X) = f, we must

Proof of theorem 2.1. Regarding consistency, let P be ergodic, let(Xt)t0 be P-Markov and let Xψ. Define Q(x) := q(· |x) − f, which is a mea-surable function from X to L1(µ). Note thatEQ(X) = 0 by lemma 2.1.

We need to show that

nlimkfn− fk = lim

Our proof is an extention of that for the IID Banach space LLN, as given in Bosq (2000, thm. 2.4). To begin, fix e > 0 and choose a partition{Bj} of L1(µ)such that each Bjhas diameter less than e. For any L1(µ)-valued random variable Y, we let LJY :=Jj=1bj1{Y ∈ Bj}. We use the following fact, a proof of which can be found in Bosq (2000, pp. 27-28):

JN with EkQ(X) −LJQ(X)k < 2e (30) Our first claim is that

nlim

22See, in particular, Bosq (2000, lemma 1.2).

To establish (31), we can use the real ergodic law (8) to obtain

almost surely, where the last equality follows immediately from the defi-nition ofE. Thus (31) is established.

Returning to (29), we have Using real-valued ergodicity again, as well as (31), we get

lim sup

Since e is arbitrary, the proof of (29) is now done.

Regarding the asymptotic normality result, this follows immediately from the Hilbert space CLT of Stachurski (2009, theorem 3.1), where x7→ q(· |x) corresponds to T0in that theorem. The only point that needs checking vis-a-vis that CLT is thatEq(· |X) = f, and this has already been verified in lemma 2.1.

Proof of theorem 4.1. We make use of the following fact: By the Markov property, for our state process(Xt)t0and integrable h : XR we have

Eth(Xt+k) = Pkh(Xt)

where Et is expectation conditional on σ(X0, . . . , Xt), and Pk is the k-th iterate of the mapping h 7→ Ph. For convenience, let ¯h := h−R

hdψ for any h : XR. By the Markov chain CLT for V-uniformly ergodic kernels (Meyn and Tweedie, 1993, p 411), if g : XR with g2≤V, then

n1/2

n t=1

¯g(Xt) → N(0, v)

in distribution, where

v =:E ¯g2(X1) +2

t2

E ¯g(X1)¯g(Xt) (32)

Here(Xt)t0is a stationary version of the process (1). Regarding the stan-dard Monte Carlo estimator Enτ, it now follows that

n1/2(Enτ− Z

τdψ) = n1/2

n t=1

¯τ(Xt) → N(0, v1) where v1is given by

v1 =:E ¯τ2(X1) +2

t2

E ¯τ(X1)¯τ(Xt) (33)

Regarding the look-ahead estimator, we claim that n1/2(En−R

τdψ) → N(0, v2), where

v2 =: E ¯2(X1) +2

t2

E ¯(X1)¯ (Xt) (34)

To show this, observe that n1/2(En

Z

τdψ) =n1/2(En− Z

Pτdψ) = n1/2

n t=1

¯ (Xt)

where the second equality follows from (20).

Now note that P is also ˆV-UE, where ˆV := λV+L. To see this, observe that the drift inequality (17) holds with ˆV in place of V, because P is V-UE, and hence

P ˆV =λPV+L≤λ(λV+L) +L=λ ˆV+L

Second, the sublevel sets{Vˆα}are P-small, because the sublevel sets V are P-small, and

{Vˆα} = {λV+L≤α} = {V ≤ (α−L)} Thus the CLT claim for n1/2(En−R

τdψ)will hold if we can show that ()2V. Using Jensen’s inequality, τˆ 2 ≤V and the drift condition (17),

()22 ≤PV ≤λV+L =: ˆV

It remains only to show that v2 ≤ v1. To see this, consider first the term E ¯2(X1). Writing ψτ forR

τdψ and using Jensen’s inequality for con-ditional expectations, we obtain

E((X1) −ψτ)2 =E(E1(τ(X2) −ψτ))2

EE1(τ(X2) −ψτ)2

=E(τ(X2) −ψτ)2 =E(τ(X1) −ψτ)2

where the last step is by stationarity. In other words,E ¯2(X1) ≤E ¯τ2(X1). To complete the proof that v2 ≤ v1, then, it is sufficient to show that the autocovariance terms in v1and v2are equal. That is, for any t ≥2,

E((X1) −ψτ)((Xt) −ψτ) =E(τ(X1) −ψτ)(τ(Xt) −ψτ) To see this, observe that

E((X1) −ψτ)((Xt) −ψτ) = E(E1τ(X2) −ψτ)(Etτ(Xt+1) −ψτ)

=EE1Et(τ(X2) −ψτ)(τ(Xt+1) −ψτ)

=E(τ(X2) −ψτ)(τ(Xt+1) −ψτ)

=E(τ(X1) −ψτ)(τ(Xt) −ψτ) The proof is done.

Proof of Theorem 5.1. Unbiasedness of the estimator fTn is equivalent to the claim thatEqT1(· |XT1) = fT. The proof is almost identical to that for f given in the proof of lemma 2.1, and hence is omitted. Regarding consis-tency, the Banach-space law of large numbers (cf., e.g., Bosq, 2000, Theo-rem 2.4) implies that if(Ui)i1is anIIDsequence in L1(µ)with expectation

which is consistency result that we seek.

Finally, consider the issue of asymptotic normality. From Bosq (2000, the-orem 2.7), we can deduce that if(Ui)i1 is an IIDsequence in L2(µ) such

converges in distribution to a centered Gaussian on L2(µ). Once again we take Ui = qT1(· |XiT1), where (XiT1)i1 IIDψT1. From the condition in Theorem 5.1 we have

Z

converges in distribution to a centered Gaussian on L2(µ).

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