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The diagonal embedding

In document Habilthesis.pdf (Page 158-161)

In this section, we will prove Theorem6.1.1. Let X be a smooth projective surface over C

and 2≤n∈ N. We denote byδ:X → Xn the diagonal embedding. We want to show that

the composition

F:Db(X)−−→triv DbSn(X)−→δ∗ DbSn(Xn) is a Pn−1-functor. Here,S

nis considered to act trivially on X andtriv:Db(X)→DbSn(X)is

the functor which equips each object with the trivial linearisation. The right adjoint ofF is

given by the composition

R:DbSn(Xn)−→δ! DbSn(X) ( )

Sn

−−−−→Db(X)

of the usual right adjoint of the push-forward (see [LH09, Proposition 28.8] for equivari- ant Grothendieck duality for regular embeddings) and the functor of taking invariants. The approach is to compute the compositionδ!δ

∗ rst. Then taking Sn-invariants gives the com-

positionRF.

We consider the standard representation % of Sn as the quotient of the permutation representation Cn by the one-dimensional invariant subspace. The normal bundle sequence

0→TX →TXn|X →N →0, whereN :=Nδ=NX/Xn, is of the form

where the mapTX →TX⊕nis the diagonal embedding. When consideringTXn|X as aSn-sheaf

equipped with the natural linearisation it is given by TX ⊗Cn where Cn is the permutation

representation. Thus, as aSn-sheaf, the normal bundle N equals TX ⊗%. We also see that

the normal bundle sequence splits using e.g. the splitting

TX⊗Cn→TX , (v1, . . . , vn)7→

1

n(v1+· · ·+vn).

Theorem 6.3.1 ([AC12, Theorem 1.4]). Letι:Z ,→M be a regular embedding of codimension csuch that the normal bundle sequence splits. Then there is an isomorphism

ι∗ι∗( )'( )⊗ c M i=0 ∧iN∨ Z/M[i] (6.7) of endofunctors of Db(Z).

Recall that the right-adjoint ι! of ι∗ is given by ι!( ) = ι∗( )⊗ι!OM and ι!OM =

∧c:onderivedN

ι[−c]; see [Har66, Corollary III 7.3].

Corollary 6.3.2. Under the same assumptions, there is an isomorphism ι!ι∗( ) ' ( )⊗

Lc

i=0∧iNZ/M[−i]

.

Proof. Apply the tensor product withι!OM ' ∧cNZ/M[−c]on both sides of (6.7).

In the case thatι=δ from above this yields the isomorphism of functors

δ!δ∗( )'( )⊗ 2(n−1) M i=0 ∧i(T X⊗%)[−i] . (6.8)

Lemma 6.3.3. Letι:Z ,→M be as in Theorem6.3.1and letε:=ει∗:ι∗ι!→idbe the counit of adjunction. For0≤i, j≤c with i+j≤c, the component

( )⊗ ∧iNZ/M⊗ ∧jNZ/M[−(i+j)]→( )⊗ ∧i+jNZ/M[−(i+j)]

of the morphismι!ει∗:ι!ι∗ι!ι∗ →ι!ι∗ is given by the wedge pairing.

Proof. ForE ∈Db(M) the objectι!E can be identied with HomM(ι∗OZ, E), the latter con-

sidered as an object inDb(Z). Under this identication the counit mapε: HomM(ι∗OZ, E)→

E is given by the evaluation ϕ 7→ ϕ(1); see [Har66, Section III.6]. Corollary 6.3.2 says in particular that ι!ι∗(B) ' B ⊗OZ ι

!ι

∗(OZ) for B ∈ Db(Z). This gives the identications

ι!ι∗B ' HomM(ι∗OZ, ι∗OZ)⊗OZB and

ι!ι∗ι!ι∗B ' HomM(ι∗OZ, ι∗OZ)⊗OZHomM(ι∗OZ, ι∗OZ)⊗OZB .

Under these identications, the component

ExtiM(ι∗OZ, ι∗OZ)⊗OZExt

j

M(ι∗OZ, ι∗OZ)⊗OZ B→ Ext i+j

M (ι∗OZ, ι∗OZ)⊗OZB

of the monad multiplication equals the Yoneda product. The Yoneda product corresponds to the wedge product under the isomorphismExti

M(OZ,OZ)' ∧iNZ/M; see [LH09, Proposition

Lemma 6.3.4 ([Sca09a, Lemma B.5]). Let V be a two-dimensional vector space with a basis

consisting of vectorsu andv. Then the space of invariants[∧i(V %)]Sn is one-dimensional

if 0≤i≤2(n−1)is even and zero if it is odd. In the even casei= 2`the space of invariants

is spanned by the image of the vector ω`, where ω =

n X

i=1

uei∧vei∈ ∧2(V ⊗Cn),

under the projection induced by the quotient Cn%.

Corollary 6.3.5. For a vector bundle E on X of rank two and 0 ≤ ` ≤ n−1 there is an isomorphism of line bundles[∧2`(E%)]Sn '(2E)⊗`.

Proof. The isomorphism is given by composing the morphism (∧2E)⊗` → ∧2`(ECn) , x

1⊗ · · · ⊗x` 7→

X

1≤i1<···<i`≤n

x1ei1 ∧ · · · ∧x`ei`

with the projection induced by the quotient Cn%.

We setD:= ( )⊗ ∧2T

X[−2]'Mω∨

X[−2]'S

−1

X as the inverse of the Serre functor on X.

Corollary 6.3.6. There is the isomorphism of functors RF 'id⊕D⊕D2⊕ · · · ⊕Dn−1.

Proof. We have RF = ( )Snδ!δ

∗triv. The assertion follows by formula (6.8) and Corollary 6.3.5.

Lemma 6.3.7. The functor F fulls condition (ii) of a Pn−1-functor with cotwistD=SX−1.

Proof. All the components cij:DDi−1 = Di → Dj of the morphism (6.3) are induced by

morphisms between the FourierMukai kernels. The FM kernel of Di = SX−i is ι∗ω−Xi[−2i] withι:X →X×X being the diagonal embedding. Fori < j we have

Hom(ι∗ωX−i[−2i], ι∗ω−Xj[−2j]) = Ext2(i−j)(ι∗ωX−i, ι∗ωX−j) = 0

hencecij = 0. The generatorsω` from Lemma 6.3.4 are mapped to each other by the wedge

product. For i = 1, . . . , n−1 the components cii: DDi−1 → Di are given by the wedge

product; see Lemma6.3.3. Hence, they are isomorphisms. Lemma 6.3.8. There is an isomorphismSXnF Dn−1 'F SX.

Proof. For E ∈Db(X) there are natural isomorphisms

SXnF Dn−1(E)'ωXn[2n]⊗δ(E ⊗ω−(n−1) X [−2(n−1)])'ω n X ⊗δ∗(E ⊗ω −(n−1) X )[2] 'δ∗(E ⊗ωX[2])'F SX(E)

where the second-to-last isomorphism is the projection formula.

All this together shows Theorem 6.1.1. This means that F = δ∗triv is indeed a Pn−1- functor with P-cotwistD=SX−1.

6.4 Composition with the BridgelandKingReidHaiman equiv-

In document Habilthesis.pdf (Page 158-161)