Chapter 4
The Problem Solving Process
■
Ryan’s Roofing charges $50 plus $30 per hour
for emergency roof repair. A homeowner’s bill
was $860 after the last storm. How long did
Ryan’s Roofing spend working on the job?
Strategy
Problem 1 on WorksheetFixed Charge + Hourly Charge = Bill
Guess:
20 hours
$50
Let x = # of hours worked
50 + 30(
x
) = 860
x
=
27 hours
Example
Problem 4 on Worksheet■
Evelyn paid $89.25, including 5% tax, for her
Mechanics and Materials
textbook. How
much did the book cost (before taxes)?
Selling Price + Sales Tax = Total Price
Guess: $80
$80 + .05($80) = __________
$84
x + .05x = 89.25
Example
Problem 2 on Worksheet■
Jesse’s test scores in DC and AC Fundamentals
so far are; 73, 75, 89,and 91.
■
What is the lowest score he can get on the next
Example
Problem 3 on Worksheet■
The second angle of an architect’s triangle is
three times as large as the first. The third
angle is 30° more than the first.
❑
Find the measure of each angle.
Angle 1 + Angle 2 + Angle 3 = 180°
A1 A2
A3
Since the second and third angles are
described in terms of first angle, let’s use the variable a to represent the first angle…
a
+
3
a
+
a
+ 30 = 180
5
a +
30 = 180
a = 30°
Angle 1 = _____
Angle 2 = _____
Angle 3 = _____
Practice
■
Complete worksheet:
■
#5 – 11
■
Write a “hybrid” equation first.
■Diagram if applicable.
■
Make a guess to help write the final
Notes/Worksheet
■ 5.) A computer repair and consulting business charges in-home
visits based on the following rate schedule: $35 plus $28.50 per hour. If a customer has several issues/problems to be solved and they only have $200 to spend, what is the most amount of time (in hours) the computer technician can stay at the customer’s house?
Fixed Amount + Hourly Amount = Customer’s Bill
$35 + Hourly Amount = $200
Notes/Worksheet
■ 6.) The world’s oldest groom was 19 years older than his bride.
Together their ages totaled 187 years. How old were the bride and groom? (Reference Guinness World Records, Millennium Edition)
Groom + Bride = 187
b
Observation: The groom is described in terms of the
bride.
So let the variable be “b” for bride.
+
Notes/Worksheet
■ 7.) Jake paid $63.75 for multi-meter during a 15% off sale. What
was the regular price of the multi-meter?
Meter – Discount = 63.75
Guess: Meter cost$70 originally.
Replace 70 with a variable.
70
–
70(.15)
=
59.50
Notes/Worksheet
■ 8.) David did a bike ride around the outer edge of the state of
Wyoming (which is shaped like a rectangle) and accumulated a
distance of 1280 miles. The width of Wyoming is 90 miles less than the length. Determine the width and length of Wyoming.
2(Length) + 2(Width) = 1280
2L
+
2(L – 90)
= 1280
2L + 2L – 180 = 1280
L
Notes/Worksheet
■
9.) Nate’s investment in K-mart stock fell 38% to
$25,560. How much money did Nate lose?
Investment – Loss = 25,560
Guess: Investmentwas $30,000
Replace $30,000 with a variable (
x
).30,000
–
30,000(.38)
=
18,600
Notes/Worksheet
■
10.) The Iditarod sled-dog race extends for 1049 miles
from Anchorage to Nome. If John is twice as far from
Anchorage as from Nome, how far does John have left to
go?
Dist. to Anch. + Dist. to Nome = 1049
2
n
+
n
= 1049
Nome ∙
Anchorage ∙ Position ∙
n
milesNotes/Worksheet
■
11.) Ray has an old tractor that he will put in a
neighbor’s upcoming auction. If he wants to pocket
$3200 minimum for the tractor, how much will it have to
sell for at auction so that he gets his price? The
auctioneer receives a 7% commission on all items sold.
Selling Price – Commission = 3200
Guess: Selling price of $3,500.
Replace $3,500 with a variable (x).
3500
–
3500(.07)
=
3255
HOMEWORK
Homework Problems
■
Question 1
■Question 2
■Question 3
■Question 4
■Question 5
■Question 6
1.) Homework
■ When three resistors are connected in series, their resistances are
added to produce a total resistance of 970 Ω. One of them has a resistance of 530 Ω, and the others have resistance levels equal to each other. Find the resistance levels of the other two resistors.
Resistor 1 + Resistor 2 + Resistor 3 = 970
530
Menu
R
2.) Homework
■ A power supply has 2 printed circuit boards that contain a combined
total of 222 components. One board has 6 more than twice the
number of components on the other board. How many components are in each board?
Board 1 + Board 2 = 222
B
Since the board with more
components is described based upon the board with fewer
components, let B = board with the fewer amt. of components.
Menu
2 + 6
3.) Homework
■ An architect determines that if she reduces the dimensions of a
square room by 2 ft. on each side, the perimeter will be 56 ft. What is the length of the original room, before the reduction?
4(length of side) = 56
4(s – 2) = 56
Reduced Floor Plan
s – 2
4.) Homework
■ The sum of two currents is 200 mA, and the larger current is 30 mA
more than the smaller current. Determine the value of the smaller current.
Current 1 + Current 2 = 200
(C + 30) + C = 200
Since the larger current is
described based upon the smaller current, let c = smaller current.
5.) Homework
■ Some resistors cost $0.12 each, while others cost $1.08 each.
Sixty-five resistors cost a total of $22.20. How many of each resistor was purchased?
x + y =
65
x =
65 –
y
.12(65 –
y
) + 1.08
y
= 22.20
Menu
Number of Cheaper Resistors = x
Number of More Expensive Resistors = y
Quantity: # of Cheap + # of Expensive = 65 Quantity: x + y = 65
5.) Homework
■ Some resistors cost $0.12 each, while others cost $1.08 each.
Sixty-five resistors cost a total of $22.20. How many of each resistor was purchased?
Quantity Cost Total Cost
Cheaper Resistor More Expensive Resistor Total
x
y
x + y =
65
$0.12
$1.08
-.12
x
1.08
y
$22.20
x =
65 –
y
.12(65 –
y
)
.12(65 –
.12
x
+ 1.08
y
) + 1.08
y
= 22.20
y
= 22.20
Two variables…cannot solve.
6.) Homework
■ A company plans to issue 24,500 shares of two different kinds of
stocks, which will have a combined value of $800,000. One of the stocks is worth $100 per share and the other stock is worth $25 per share. How many of each stock will be issued?
x + y =
24,500
x =
24,500 –
y
25(24,500 –
y
) + 100
y
= 800,000
Menu
Amount of $25 stocks issued = x
Amount of $100 stocks issued = y
Quantity: Amt. $25 stock + Amt. of $100 stock = 24,500 Quantity: x + y = 24,500
6.) Homework
■ A company plans to issue 24,500 shares of two different kinds of
stocks, which will have a combined value of $800,000. One of the stocks is worth $100 per share and the other stock is worth $25 per share. How many of each stock will be issued?
Quantity Cost Total Cost
Cheaper Stock More Expensive Stock Total
x
y
x + y =
24500
$25
$100
-25
x
100
y
$800,000
x =
24500 –
y
25(24500 –
y
)
25(24500 –
y
) + 100
y
= 800,000
7.) Homework
■ Three different oil storage tanks have a combined capacity of 4,400
gallons. The largest tank holds three times as much as the smallest tank, and twice as much as the other tank. What is the capacity of each tank?
Tank 1+ Tank 2 + Tank 3 = 4,400
Since the smaller tanks are described with reference to the largest tank, let t = size of largest tank.
8.) Homework
■ According to Kirchhoff’s current law, the sum of the currents into a
node equals the current out of the node. The current out of a node is 650 mA and three currents go into it. The largest current is twice the smallest and 100 mA more than the other current. Determine all three currents.
Current 1 + Current 2 + Current 3 = 650
C
Since the two of the currents are described in reference to the largest current, let c = largest current.
C
C - 100
+
+
= 650
9.) Homework
■ A person pays $4800 in state and federal income taxes in a year.
The federal income tax is five times as great as the state income tax. How much does the person pay on each of these income taxes?
State Tax + Federal Tax = 4800
S
Since the federal tax is described in reference to the state tax, let s = state tax paid.
S
5
+
= 4400
10.) Homework
■ A walkway 3 meters wide is constructed along the outside of a
square courtyard. If the perimeter of the courtyard is 320 meters, what is the perimeter of the square formed by the outer edge of the walkway?
4(length of side) = 320
4s = 320
Courtyard
s
s = 80 m
80
+ 3 + 3
80
86
4(86) = Perimeter of outer edge
344 m = Perimeter of outer edge
11.) Homework
■ Two stock investments totaled $15,000. One stock led to a 40%
gain, but the other stock resulted in a 10% loss. If the net result is a profit of $2,000, how much was invested in each stock.
x + y =
15,000
x =
15,000 –
y
.40(15,000 –
y
) – .10
y
= 2,000
Menu
Amount invested in gaining stock = x
Amount invested in losing stock = y
Investment: x + y = $15,000
11.) Homework
■ Two stock investments totaled $15,000. One stock led to a 40%
gain, but the other stock resulted in a 10% loss. If the net result is a profit of $2000, how much was invested in each stock.
Amt. Invested Gain/Loss % Gain/Loss $
Stock that Gained Stock that Lost Total
x
y
x + y =
15000
40%
-10%
-.40
x
–.10
y
$2,200
x =
15000 –
y
.40(15000 –
y
)
.40(15000 –
y
) – .10
y
= 2,200
Example 1
Washington Textbook, page 135 Ex. 3■
Several 6-volt and 12-volt batteries are arranged so that
their individual voltages combine to provide a power
supply of 84-volts.
■
How many of each type are present if the total number of
batteries is 10?
Qty6v x 6-volts + Qty12v x 12-volts = 84-volts
Total Voltage from the 6v batteries + Total Voltage from the 12v batteries = 84 volts
Example 2
Washington Textbook, page 135 Ex. 4■
A machinist made 132 items, some of which were
hubs with the rest being threaded rods.
❑
He made 12 more hubs than threaded rods.
❑How many of each kind of item did he make?
Distance, Rate, Time
■
Formula relating these components:
❑
Distance = Rate x Time
Example 3
Rate Problem■
A car travels at 40 mi/h for 2 hours along a road.
■
A second car starts on the same route 2 hours later,
traveling at 60 mi/h.
■
How many hours will it take for the faster car to
overtake the slower one?
Example 3
Rate Problem (Continued)Distance
slower car= Distance
faster carD = RT
Example 4
Rate Problem■
A space shuttle is sent to “capture” an
orbiting satellite 6,000 km ahead of it’s
current position.
■
The satellite travels at 27,000 km/h and the
shuttle travels at 29,500 km/h.
Example 4
Rate Problem (continued)27,000 km/h 29,500 km/h
6,000 km
X
D = RT
Mixture Problems
IntroCement: 20% sand
Cement: 30% sand
Cement: 27% sand
+
=
200 lbs of cement 467 lbs of cement
667 lbs of cement
Mixture Problem
Sample #1■
On hand is 100 g of solder that is 50% tin.
■
How many grams of 10% tin solder must be mixed to
end up with solder that is 25% tin?
Solder: 50% tin
Solder: 10% tin
Solder: 25% tin
+
=
Practice
■
Worksheet: Mixture Problems
Example 2
of 8■
The houses on the south side of Elm Street
are consecutive even numbers. Wanda and
Larry are next door neighbors and the sum of
their house numbers is 794. Determine their
house numbers.
Wanda’s House # + Larry’s House # = 794
Example 3
of 8■
The top of the John Hancock Building is a rectangle
whose length is 60 ft more than the width. The
perimeter is 520 ft.
❑
Find the width and length.
❑
Find the area of the rectangle.
width + length + width + length = perimeter
Bird’s eye view from above
2(width) + 2(length) = perimeter
Since length is being compared towidth, let the width be the variable (unknown).
Example 5
of 8■
A taxi ride costs $1.90 plus $1.60 for each
mile traveled. If $18 is budgeted for a taxi
ride, how far can you travel?
Fixed Amount + Amt. Based on Miles Driven = Total Charge
Guess: 10 miles
Example 6
of 8■
Sarah’s investment in Jet Blue stock grew
28% to $448. How much did she invest?
Original Investment + Gain in Value = Current Price
Guess: $400
Example 7
of 8■
Lincoln’s 1863 Gettysburg Address refers to
the year 1776 as “four score and seven years
ago”. Determine what length of time is a
“score”.
Example 8
of 8■