R E S E A R C H
Open Access
Some generalizations of operator
inequalities for positive linear maps
Jianming Xue
1*and Xingkai Hu
2*Correspondence: [email protected] 1Oxbridge College, Kunming
University of Science and Technology, Kunming, Yunnan 650106, P.R. China
Full list of author information is available at the end of the article
Abstract
In this paper, we generalize some operator inequalities for positive linear maps due to Lin (Stud. Math. 215:187-194, 2013) and Zhang (Banach J. Math. Anal. 9:166-172, 2015).
MSC: 47A63; 47A30
Keywords: operator inequalities; Kantorovich inequalities; positive linear maps
1 Introduction
Throughout this paper, letM,M,m,mbe scalars,Ibe the identity operator, andB(H) be the set of all bounded linear operators on a Hilbert space (H,·,·). The operator norm is denoted by · . We writeA≥ if the operatorAis positive. IfA–B≥, then we say thatA≥B. ForA,B> , we use the following notation:
A∇μB= ( –μ)A+μB,AμB=A
(A–BA–)μA, where≤μ≤.
Whenμ= we writeA∇BandABfor brevity forA∇
BandA B, respectively; see
Kubo and Ando [].
A linear mapis positive if(A)≥ wheneverA≥. It is said to be unital if(I) =I. We say thatis -positive if whenever the × operator matrixBA B∗C
is positive, then so is(B(A)∗)(C)(B).
Let <m≤A,B≤Mandbe positive unital linear map. Lin [], Theorem ., proved the following reversed operator AM-GM inequalities:
A+B
≤K(h)(AB), (.)
A+B
≤K(h)(A) (B), (.)
whereK(h) =(h+)h withh=Mm is the Kantorovich constant.
Can the inequalities (.) and (.) be improved? Lin [], Conjecture ., conjectured
that the constantK(h) can be replaced by the Specht ratioS(h) = h
h– elogh
h–
in (.) and (.),
which remains as an open question.
Zhang [], Theorem ., generalized (.) and (.) whenp≥:
p
A+B
≤(K(M+m))p
Mpmp
p(AB), (.)
p
A+B
≤(K(M+m))p
Mpmp
(A) (B)p. (.)
We will present some operator inequalities which are generalizations of (.), (.), (.), and (.) in the next section.
Bhatia and Davis [] proved that if <m≤A≤MandXandYare two partial isometries onHwhose final spaces are orthogonal to each other. Then for every -positive unital linear map,
X∗AYY∗AY–Y∗AX≤
M–m M+m
X∗AX. (.)
Lin [], Conjecture ., conjectured that the following inequality could be true:
X∗AYY∗AY–Y∗AXX∗AX–≤
M–m M+m
.
Recently, Fu and He [], Theorem , proved
X∗AYY∗AY–Y∗AXX∗AX–≤
M–m M+m
M+
m
. (.)
We will get a stronger result than (.).
2 Main results
We begin this section with the following lemmas.
Lemma [] Let A,B> .Then the following norm inequality holds:
AB ≤
A+B
. (.)
Lemma [] Let A> .Then for every positive unital linear map,
A–≥–(A). (.)
Lemma [] Let A,B> .Then,for≤r<∞,
Ar+Br≤(A+B)r. (.)
Lemma ([], Theorem ) Suppose that two operators A,B and positive real numbers m,m,M,Msatisfy either of the following conditions:
() <m≤A≤m<M≤B≤M, () <m≤B≤m<M≤A≤M.
Then
A∇μB≥Kr
hAμB
Theorem Let <m≤A≤m<M≤B≤M.Then A+B
+MmK
h(AB)–≤M+m, (.)
where K(h) =(hh+) with h=M
m.
Proof It is easy to see that
(M–A)(m–A)A
–≤,
then
MmA
–
+
A
≤
M+m
.
Similarly,
MmB
–
+
B
≤
M+m
.
Summing up the above two inequalities, we get
A+B
+Mm
A–+B–
≤M+m.
By (AB)–=A–B–and Lemma , we have
A+B
+MmK
h(AB)–= A+B
+MmK
hA–B– ≤A+B
+Mm
A–+B–
≤M+m.
This completes the proof.
Theorem Let <m≤A≤m<M≤B≤M.Then for every positive unital linear map
,
A+B
≤K(h)
K(h)
(AB) (.)
and
A+B
≤K(h)
K(h)
(A) (B), (.)
where K(h) =(h+)h,K(h) = (hh+),h=Mm,and h=M
Proof The inequality (.) is equivalent to
A+B
–(AB)≤ K(h)
K(h)
. (.)
Compute
A+B
MmKh–(AB)
≤
A+B
+MmKh–(AB)
(by (.))
≤
A+B
+MmKh(AB)–
(by (.))
=
A+B
+MmK
h(AB)–
≤
(M+m)
(by (.))
=
(M+m)
.
That is,
A+B
–(AB)≤ (M+m)
MmK(h)
= K(h)
K(h)
.
Thus, (.) holds. The proof of (.) is similar, we omit the details.
This completes the proof.
Remark Because of KK(h(h)) <K(h), inequalities (.) and (.) are refinements of (.) and (.), respectively.
Theorem Let <m≤A≤m<M≤B≤M and≤p<∞.Then for every positive unital linear map,
p
A+B
≤
K(h)(M+m)
K(h)Mm
p
p(AB) (.)
and
p
A+B
≤
K(h)(M+m)
K(h)Mm
p
(A) (B)p, (.)
where K(h) =(h+)h,K(h) = (hh+),h=Mm,and h=Mm.
Proof By the operator reverse monotonicity of inequality (.), we have
–(AB)≤L–
A+B
, (.)
whereL= K(h)
Compute p
A+B
Mpmp–p(AB)
≤
Lpp
A+B
+
Mm
L
p
–p(AB)
(by (.))
≤
L
A+B
+M
m
L
–(AB) p
(by (.))
≤
L
A+B
+LMm–
A+B
p (by (.))
≤
LM+mp (by [], (.)). That is,
p
A+B
–p(AB)≤
L(M+m)
Mm
p
=
K(h)(M+m)
K(h)Mm
p
.
Thus, (.) holds. By inequality (.), the proof of (.) is similar, we omit the details.
This completes the proof.
Remark SinceK(h) > , inequalities (.) and (.) are sharper than (.) and (.), respectively.
Theorem Let <m≤A≤M and let X,Y be two isometries onHwhose final spaces are orthogonal to each other.Then for every-positive unital linear map,
X∗AYY∗AY–Y∗AXX∗AX–≤(M–m)
Mm . (.)
Proof Since X is isometric and < m ≤ A ≤ M, m ≤ (X∗AX) ≤ M and M ≤
(X∗AX)–≤ m.
Compute
M–m M+m
MmX∗AYY∗AY–Y∗AXX∗AX–
≤
X∗AYY∗AY–Y∗AX+
M–m M+m
MmX∗AX–
(by (.))
≤
MM–+mmX∗AX+
M–m M+m
MmX∗AX–
(by (.))
≤
M–m M+m
(M+m).
Hence,
X∗AYY∗AY–Y∗AXX∗AX–≤(M–m)
Mm .
Remark Since <m≤M,
M–m M+m
M+
m
≥
M–m M+m
M m ≥
M–m M+m
(M+m)
Mm =
(M–m)
Mm .
Thus, (.) is tighter than (.).
Competing interests
The authors declare that they have no competing interests.
Authors’ contributions
All authors contributed equally to the writing of this paper. All authors read and approved the final manuscript.
Author details
1Oxbridge College, Kunming University of Science and Technology, Kunming, Yunnan 650106, P.R. China.2Faculty of
Science, Kunming University of Science and Technology, Kunming, Yunnan 650500, P.R. China.
Acknowledgements
The authors wish to express their heartfelt thanks to the referees for their detailed and helpful suggestions for revising the manuscript. This research was supported by Scientific Research Fund of Yunnan Provincial Education Department (No. 2014C206Y).
Received: 9 October 2015 Accepted: 15 January 2016 References
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