Universal Gravitation & Field Strength
• Newton’s Law of Universal Gravitation is:
• And we learned last year that the force of gravity on the Earth can be calculated by:
Example Problem
Now what if it was dropped on the Moon?
• Moon’s mass is 7.35x1022 kg & radius is
1.74x103 km
Gravitational Field Strength
• That acceleration due to the gravitational field is also known as the field strength • The gravitational field strength at a
certain point is the force per unit mass
experienced by a small point mass, m, at that point.
• It has units of N•kg-1
2
r
M
G
Gravitational Field Lines
• The field lines show the direction of the force. For a spherical mass they become more dense closer to the mass (and
Gravitational Field close to the Earth
• Close to the Earth’s surface, we can
assume that the field lines are parallel and the field is uniform.
Adding Field Forces
• Since the field is a vector, we can add the field strengths of multiple masses
• What is the field strength at point “A” • Calculate the field strength at point “B”
• Calculate the field strength at “A” if the big mass were changed to a 100kg mass
B A
2.5m 2.5m
1m
1000kg
Gravitational Potential Energy
• If you lift a mass up from the ground, you increase its potential energy: PE = mgh • If PE = mgh, the “gh” part just describes
the location of the object: which gravity field and how far from it
• We call that location in the gravity field its “gravitational potential” : (V)
• V tells how much PE a mass would have there
Moving masses in potentials
If a mass is moved from a position with
potential V1 to a position with potential V2, work = m(V2 – V1) = mΔV
V1
Examples: • What is the potential at “A”?
• If a body is moved to point “B”, what is the change in potential?
• How much work is done moving 2kg A to B? • Potential difference
between C & D?
• Potential difference between A & E?
Field and equipotentials
• Equipotentials are always perpendicular to field lines.
Diagrams of equipotential lines give us information about the gravitational field in much the same way as contour
Equipotential surfaces/lines
• Work done = ∆V x mass
• Work done also equals force x distance ∆Vm=mgh
h
V
Contour Lines on Maps
The contour lines on a map show how steep the slope is.
When they are closer together, the slope is steeper.
In our equation, that would mean the ∆h is smaller and the gradient (slope) is greater.
h
V
How did we calculate Potential
Energy?
• GPE = mgh
• So higher means more potential energy, right?
• What if we went really high?
GPE in space?
• In space, h→∞.
– Do we therefore have infinite potential energy? – I think not!
• The old way we calculated GPE is really only a way to simply determine the change
in GPE near the surface of the Earth • We need a way to state an absolute
potential energy.
Gravitational potential energy
Gravitational potential energy at a point is defined as the work done to move a
Gravitational potential energy
Gravitational potential energy at a point is defined as the work done to move a
mass from infinity to that point.
M
m
I’ve come from infinity!
Gravitational potential energy
Gravitational potential energy at a point is defined as the work done to move a
mass from infinity to that point.
M
m
I’ve come from infinity!
R
Work done = force x distance
The force however is changing as the
Gravitational potential energy
M
m
I’ve come from infinity!
R
W =
R
Fdr
R
GMmdr
r2
= =
[ ]
GMmr
R
= GMm
R
Gravitational potential energy
Gravitational potential energy at a point is defined as the work done to move a
mass from infinity to that point.
E
p= -GMm
r
Gravitational Potential
It follows that the Gravitational potential
at a point is the work done per unit mass
on a small point mass moving from infinity to that point. It is given by
V = -GM
r
Note the difference between gravitational potential energy (J) and
Gravitational potential (J.kg-1)
Let’s do some examples:
• The moon’s mass is 7.4x1022 kg and the Earth’s
mass is 6.0x1024 kg. The average distance to the moon is 3.8x108 m. If you travel in a 2000kg
rocket:
• Calculate the gravitational potential when you’re 1.0x107 m from the moon.
• Calculate the rocket’s PE at that point.
1 6 7 22 11 8 24 11 10 6 . 1 10 1 10 4 . 7 10 67 . 6 10 7 . 3 10 6 10 67 .
6
kg J x x x x x x x V r GM r GM V A m m E E A J x x x m V
Escape speed
Imagine throwing a ball into the air
Escape speed
It falls to the ground (Doh!)
Escape speed
What happens if you throw harder?
Escape speed
It goes higher and takes longer to return.
Escape speed
It goes higher and takes longer to return.
Ouch!
Escape speed
The kinetic energy of the ball changes to gravitational potential energy as the ball rises. This in turn turns back into kinetic energy as the ball falls again.
Escape speed
How fast would you have to throw the ball so that it doesn’t come back? (i.e. goes to “infinity” or escapes the gravitational field of the earth)
Escape speed
At “infinity”, its gravitational energy is given by :
and PE=0 when r=∞
Loss of KE = gain in PE
© Simon Porter 2007
r GMm PE
Escape speed
For the Earth:
I can’t throw that fast!
© Simon Porter 2007
Energy of an orbiting body • As a body orbits, it has KE from its
movement and PE due to its position • We know:
• Setting gravity force = centripetal force:
2
2 1
& KE mv
r GMm
PE
Energy of an orbiting body • Total energy = PE + KE so:
• The orbit of a high satellite is less negative, so requires more energy