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Volume 2010, Article ID 368169,15pages doi:10.1155/2010/368169

Research Article

Positive Solutions of Singular Complementary

Lidstone Boundary Value Problems

Ravi P. Agarwal,

1

Donal O’Regan,

2

and Svatoslav Stan ˇek

3 1Department of Mathematical Sciences, Florida Institute of Technology, Melbourne,

FL 32901-6975, USA

2Department of Mathematics, National University of Ireland, Galway, Ireland

3Department of Mathematical Analysis, Faculty of Science, Palack´y University, Tˇr. 17. listopadu 12,

771 46 Olomouc, Czech Republic

Correspondence should be addressed to Ravi P. Agarwal,[email protected]

Received 7 October 2010; Accepted 21 November 2010

Academic Editor: Irena Rach ˚unkov´a

Copyrightq2010 Ravi P. Agarwal et al. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.

We investigate the existence of positive solutions of singular problem−1mx2m1 ft, x, . . . ,

x2m,x0 0,x2i−10 x2i−1T 0, 1im. Here,m1 and the Carath´eodory function

ft, x0, . . . , x2mmay be singular in all its space variablesx0, . . . , x2m. The results are proved by regularization and sequential techniques. In limit processes, the Vitali convergence theorem is used.

1. Introduction

LetTbe a positive constant,J 0, TandÊ− −∞,0,Ê 0,∞,Ê0 Ê\{0}. We consider

the singular complementary Lidstone boundary value problem

−1mx2m1t ft, xt, . . . , x2mt, m≥1, 1.1

x0 0, x2i−10 x2i−1T 0, 1≤im, 1.2

wherefsatisfies the local Carath´eodory function onJ× Df ∈CarJ× Dwith

D

⎧ ⎪ ⎪ ⎪ ⎨ ⎪ ⎪ ⎪ ⎩ Ê

2

×Ê0×Ê− ×Ê0×Ê × · · · ×Ê×Ê0

4k−1

ifm2k−1,

Ê

2

×Ê0×Ê− ×Ê0×Ê × · · · ×Ê−×Ê0

4k1

(2)

The functionft, x0, . . . , x2mis positive and may be singular at the value zero of all its space

variablesx0, . . . , x2m.

Leti∈ {0,1, . . . ,2m}. We say thatf is singular at the value zero of its space variablexiif

for a.e.tJand allxj, 0≤j≤2m,j /isuch thatx0, . . . , xi, . . . , x2m∈ D, the relation

lim

xi→0ft, x0, . . . , xi, . . . , x2m ∞ 1.4

holds.

A functionxAC2mJ i.e.,xhas absolutely continuous 2mth derivative on Jis

a positive solution of problem 1.1, 1.2if xt > 0 for t ∈ 0, T, x satisfies the boundary conditions1.2and1.1holds a.e. onJ.

The regular complementary Lidstone problem

−1mx2m1t ht, xt, . . . , xqt, m≥1, qfixed, 0≤q≤2m,

x0 α0, x2i−10 αi, x2i−11 βi, 1≤im

1.5

was discussed in1. Here,h:0,1×Êq1 → Êis continuous at least in the interior of the

domain of interest. Existence and uniqueness criteria for problem 1.5 are proved by the

complementary Lidstone interpolating polynomial of degree 2m. No contributions exist, as far as we know, concerning the existence of positive solutions of singular complementary Lidstone problems.

We observe that differential equations in complementary Lidstone problems as well as derivatives in boundary conditions are odd orders, in contrast to the Lidstone problem

−1mx2mt pt, xt, . . . , xrt, m≥1, r fixed, 0≤r ≤2m−1,

x2i0 a

i, x2i1 bi, 1≤im−1,

1.6

where the differential equation and derivatives in the boundary conditions are even orders. Forai bi 0 1 ≤ im−1, regular Lidstone problems were discussed in 2–9, while

singular ones in10–15.

The aim of this paper is to give the conditions on the functionf in1.1which gua-rantee that the singular problem1.1,1.2has a solution. The existence results are proved by regularization and sequential techniques, and in limit processes, the Vitali convergence theorem16,17is applied.

Throughout the paper,x∞ max{|xt| : tJ}and xCn nk0xk,n ≥ 1

stands for the norm in C0J and CnJ, respectively. L1J denotes the set of functions

Lebesgueintegrable onJand measMthe Lebesgue measure ofM ⊂J.

We work with the following conditions on the functionfin1.1.

H1f ∈CarJ× Dand there existsa∈0,∞such that

aft, x0, . . . , x2m, 1.7

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H2For a.e.tJand for allx0, . . . , x2m∈ D, the inequality

ft, x0, . . . , x2mh ⎛ ⎝t,2m

j0

xj⎞⎠2m j0

ωjxj 1.8

is fulfilled, whereh∈ CarJ×0,∞is positive and nondecreasing in the second variable,ωj:Ê → Êis nonincreasing, 0≤j ≤2m,

lim sup

v→ ∞ 1 v

T

0

ht, Kvdt <1, K

⎧ ⎪ ⎨ ⎪ ⎩

T2m11

T−1 if T /1,

2m1 if T 1,

1

0 ω2j

s2ds <,

1

0

ω2j1sds <∞ if 0≤jm−1,

1

0

ω2msds <∞.

1.9

The paper is organized as follows. In Section2, we construct a sequence of auxiliary regular differential equations associated with 1.1. Section 3 is devoted to the study of auxiliary regular complementary Lidstone problems. We show that the solvability of these problems is reduced to the existence of a fixed point of an operatorH. The existence of a fixed

point ofHis proved by a fixed point theorem of cone compression type according to

Guo-Krasnosel’skii18,19. The properties of solutions to auxiliary problems are also investigated here. In Section4, applying the results of Section3, the existence of a positive solution of the singular problem1.1,1.2is proved.

2. Regularization

Let mbe from1.1. For n ∈ Æ, define χn, ϕn, τn,mC

0

Ê, Ên ⊂ Ê, andDn ⊂ Ê

2m1 by

the formulas

χnu ⎧ ⎪ ⎨ ⎪ ⎩

u foru≥ 1

n, 1

n foru < 1 n,

ϕnu ⎧ ⎪ ⎨ ⎪ ⎩

−1n foru >−1 n,

u foru≤ −1

n,

τn,m ⎧ ⎨ ⎩

χn ifm2k−1,

ϕn ifm2k,

Ên

−∞,−1

n

1 n,

,

DnÊ

2×

Ên×Ê×Ên×Ê× · · · ×Ê×Ên

2m1

.

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Letf∈CarJ× D. Chosen∈Æand put

f

nt, x0, x1, x2, x3, x4, . . . , x2m−1, x2m

ft, χnx0, χnx1, x2, ϕnx3, x4, . . . , τn,mx2m−1, x2m

2.2

fort, x0, x1, x2, x3, x4, . . . , x2m−1, x2mJ× Dn. Now, define an auxiliary functionfnby means

of the following recurrence formulas:

fn,0t, x0, x1, . . . , x2m fnt, x0, x1, . . . , x2m fort, x0, x1, . . . , x2mJ× Dn,

fn,it, x0, x1, . . . , x2m

⎧ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎨ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎩

fn,i−1t, x0, x1, . . . , x2m if|x2i| ≥

1 n, n

2

fn,i−1

t, x0, . . . , x2i−1,n1, x2i1, . . . , x2m

x2i1n

fn,i−1

t, x0, . . . , x2i−1,−1n, x2i1, . . . , x2m

x2i− 1n

if|x2i|< 1 n,

2.3

for 1≤im, and

fnt, x0, x1, . . . , x2m fn,mt, x0, x1, . . . , x2m fort, x0, x1, . . . , x2mJ×Ê

2m1. 2.4

Then, under conditionH1,fn∈CarJ×Ê

2m1and

afnt, x0, x1, . . . , x2m for a.e. t∈J and allx0, x1, . . . , x2m∈Ê

2m1. 2.5

ConditionH2gives

fnt, x0, x1, . . . , x2mh

t,2m12m j0

xj⎞⎠2m j0

ωjxjωj1,

for a.e. t∈J and allx0, x1, . . . , x2m∈Ê

2m1

0 ,

2.6

fnt, x0, x1, . . . , x2mh

t,2m12m j0

xj⎞⎠2m j0

ωj

1 n

,

for a.e. t∈J and allx0, x1, . . . , x2m∈Ê

2m1.

2.7

We investigate the regular differential equation

−1mx2m1t f

n

t, xt, . . . , x2mt. 2.8

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3. Auxiliary Regular Problems

Letj∈Æ and denote byGjt, sthe Green function of the problem

x2jt 0, x2i0 x2iT 0, 0ij1. 3.1

Then,

G1t, s

⎧ ⎪ ⎪ ⎨ ⎪ ⎪ ⎩

s

TtT for 0≤stT, t

TsT for 0≤tsT.

3.2

By2,3,20, the Green functionGjcan be expressed as

Gjt, s T

0

G1t, τGj−1τ, sdτ, j >1, 3.3

and it is known thatsee, e.g.,3,20

−1jGjt, s>0 fort, s∈0, T×0, T, j≥1. 3.4

Lemma 3.1see10, Lemmas 2.1 and 2.3. Fort, sJ×Jandj∈Æ, the inequalities

−1jGjt, sT

2j−3

6j−1 sTs, 3.5

−1jGjt, sT

2j−5

30j−1tsTtTs 3.6

hold.

LetγL1Jand letuAC2m−1Jbe a solution of the dierential equation

−1mu2mt γt, 3.7

satisfying the Lidstone boundary conditions

u2i0 u2iT 0, 0im1. 3.8

It follows from the definition of the Green functionGjthat

−1ju2jt −1mj

T

0

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It is easy to check thatxAC2mJis a solution of problem2.8,1.2if and only ifx0 0, and its derivativexis a solution of a problem involving the functional differential equation

−1mu2mt fn

t,

t

0

usds, ut, . . . , u2m−1t

3.10

and the Lidstone boundary conditions3.8. From3.9 forj0, we see thatuAC2m−1J is a solution of problem3.10,3.8exactly if it is a solution of the equation

ut −1m

T

0

Gmt, sfn

s,

s

0

dτ, us, . . . , u2m−1sds, 3.11

in the setC2m−1J. Consequently,xis a solution of problem2.8,1.2if and only if it is a solution of the equation

xt −1m

t

0

T

0

Gms, τfn

τ, xτ, . . . , x2mτ

ds, 3.12

in the setC2mJ. It means thatxis a solution of problem2.8,1.2ifxis a fixed point of the

operatorH:C2mJ C2mJdefined as

Hxt −1m

t

0

T

0

Gms, τfn

τ, xτ, . . . , x2mτ

ds. 3.13

We prove the existence of a fixed point of H by the following fixed point result of cone

compression type according to Guo-Krasnosel’skiisee, e.g.,18,19.

Lemma 3.2. LetX be a Banach space, and letPX be a cone inX. LetΩ1,Ω2be bounded open balls ofX centered at the origin withΩ1 ⊂Ω2. Suppose thatF:P ∩Ω2\Ω1 → P is completely continuous operator such that

Fxx forxPΩ1, Fxx forxPΩ2 3.14

holds. Then,Fhas a fixed point inP∩Ω2\Ω1.

We are now in the position to prove that problem2.8,1.2has a solution.

Lemma 3.3. Let (H1) and (H2) hold. Then, problem2.8,1.2has a solution.

Proof. Let the operatorH:C2mJ C2mJbe given in3.13, and let

P xC2mJ:xt0 for tJ. 3.15

Then,P is a cone inC2mJand since1mG

mt, s>0 fort, s∈0, T×0, Tby3.4and

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operator follows fromfn∈CarJ×Ê

2m1, from Lebesgue dominated convergence theorem, and from the Arzel`a-Ascoli theorem.

ChoosexPand putyt HxtfortJ. Then,cf.2.5

−1my2m1t fn

t, xt, . . . , x2mta >0 for a.e. tJ. 3.16

Sincey0 0 andy2i−10 y2i−1T 0 for 1im, the equalityyjξ

j 0 holds with

someξjJfor 0≤j ≤2m. We now use the equalityy2mξ2m 0 and have

y2mt

t

ξ2m

y2m1sds

a|tξ2m| fortJ. 3.17

Hence,y2m

∞≥aT/2, and so

HxC2m > aT

2 . 3.18

Next, we deduce from the relation

y2mt

t

ξ2m

fn

s, xs, . . . , x2msds

T

0 fn

s, xs, . . . , x2msds 3.19

and from2.7that

y2mtT 0

hs,2m1xC2mdsT

2m

j0 ωj

1 n

fortJ. 3.20

Therefore,

y2m

∞≤

T

0

hs,2m1xC2mdsV, 3.21

whereV T2jm0ωj1/n. Sinceyjξj 0 for 0≤j≤2m, we have

yj ∞≤T

2mjy2m

, 0≤j≤2m. 3.22

The last inequality together with3.21gives

yC2m Ky2m

∞≤K

T

0

hs,2m1xC2mdsV

, 3.23

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xP, inequalities3.18and

HxC2mK T

0

hs,2m1xC2mdsV

3.24

hold. ByH2, there existsC >0 such that

1 v

T

0

hs,2m1KvdsV

≤1 ∀vC

K, 3.25

and therefore,

K

T

0

hs,2m1vdsV

vvC. 3.26

Let

Ω1

xC2mJ:x

C2m < aT

2 , Ω2

xC2mJ:x

C2m < C . 3.27

Then, it follows from3.18,3.24, and3.26that

HxC2mxC2m forxPΩ1, HxC2mxC2m forxPΩ2. 3.28

The conclusion now follows from Lemma3.2forXC2mJandFH.

The properties of solutions to problem2.8,1.2are collected in the following lemma.

Lemma 3.4. Let (H1) and (H2) be satisfied. Letxnbe a solution of problem2.8,1.2. Then, for all

n∈Æ, the following assertions hold:

i −1jxn2j1t>0fort∈0, T,0≤jm−1, and−1mxn2m1tafor a.e.tJ,

iixnis increasing onJ, and for0≤jm−1,−1jxn2j2is decreasing onJ, and there is a uniqueξj,n∈0, Tsuch thatxn2j2ξj,n 0,

iiithere exists a positive constantAsuch that

x2m

n tA|tξm−1,n|,

x2j2

n tAtξj,n2 if 0≤jm−2,

x2j1

n tAtTt if0≤jm−1,

xntAt2,

3.29

fortJ,

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Proof. Let us choose an arbitraryn∈Æ. By2.5,

−1mxn2m1t fnt, xnt, . . . , xn2mta for a.e. t∈J, 3.30

and it follows from the definition of the Green functionGjthat the equality

−1jxn2j1t −1mj T

0

Gmjt, sfn

s, xns, . . . , xn2ms

ds 3.31

holds fortJ and 0 ≤ jm−1. Now, using 1.2,3.4,3.30, and 3.31, we see that assertioniis true. Hence,−1jxn2j2is decreasing onJfor 0≤jm−1 andxnis increasing

on this interval. Due toxn2i−10 xn2i−1T 0 for 1≤im, there exists a uniqueξj,n∈0, T

such thatun2j2ξj,n 0 for 0≤jm−1. Consequently, assertioniiholds.

Next, in view of2.5,3.6, and3.31,

x2j1

n tT

2mj−5a

30mj−1 tTt

T

0

sTsds

T2mj−2a

6·30mj−1tTt fortJ, 0≤jm−1.

3.32

Since

x2j2

n t t

ξj,n

x2j3

n sds 3.33

and, by13, Lemma 6.2,

t

ξj,n

sTsdsT

6

tξj,n2, 3.34

we have

x2j2

n tT

2mj−3a

36·30mj−2

tξj,n2 fortJ, 0≤jm−2. 3.35

Furthermore,

x2m

n t

t

ξm−1,n

fn

s, xns, . . . , xn2ms

(10)

andcf.3.32forj0

xnt t

0 x

nsds≥ T

2m−2a

6·30m−1

t

0

sTsds

T2m−2a

36·30m−1t

23T2t T2m−1a 36·30m−1t

2 fortJ,

3.37

sincexn>0 on0, Tby assertionii. Let

Aa·min

!

1, A1, A2, T2m−1 36·30m−1

"

, 3.38

where

A1min

!

T2mj−2

6·30mj−1 : 0≤jm−1

"

,

A2min

!

T2mj−3

36·30mj−2 : 0≤jm−2

"

.

3.39

Then estimate3.29follows from relations3.32–3.37.

It remains to prove the boundedness of the sequence{xn}inC2mJ. We use estimate

3.29, the properties ofωjgiven inH2, and the inequality

tTt≥ ⎧ ⎪ ⎪ ⎨ ⎪ ⎪ ⎩

T

2t for 0< t

T 2, T

2Tt for T

2 < t < T

3.40

and have

T

0

ω2mxn2ms

ds≤ T

0

ω2mA|sξm−1,n|ds

A1

m1,n

0

ω2msds

ATξm1,n

0

ω2msds

< A2

AT

0

ω2msds, T

0

ω2j2xn2j2s

ds≤ T

0 ω2j2

Asξj,n2

ds

√1

A

ATξj,n

−√Aξj,n

ω2j2

(11)

< √2

A

AT

0

ω2j2

s2ds for 0jm2,

T

0

ω2j1xn2j1s

ds≤ T

0

ω2j1AsTsds

<

T/2

0 ω2j1

ATs 2 ds T T/2 ω2j1

ATTs

2

ds

< AT4

AT2/4

0

ω2j1sds for 0≤jm−1,

T

0

ω0|xns|ds≤ T

0

ω0As2ds 1

A

AT

0

ω0s2ds.

3.41

In particular,

T

0

ω2mxn2ms

ds < A2

AT

0

ω2msds,

T

0

ω2j2xn2j2s

ds < √2

A

AT

0

ω2j2

s2ds for 0jm2,

T

0

ω2j1xn2j1s

ds < AT4

AT2/4

0

ω2j1sds for 0≤jm−1,

T

0

ω0|xns|ds≤ √1

A

AT

0

ω0s2ds,

3.42

for alln∈Æ. Now, from the above estimates, from2.6and fromx

2m

n ξm−1,n 0 for some

ξm−1,n∈0, T, which is proved inii, we get

x2m

n t

t

ξm−1,n

fn

s, xns, . . . , xn2ms dsT 0 fn

s, xns, . . . , xn2ms ds ≤ T 0 h

s,2m12m j0

xnjs

ds2m j0

T

0

ωjxnjs

ωj1 ds < T 0 h

s,2m12m j0

xnj

⎞ ⎠ds Λ,

(12)

where

Λ A2

AT

0

ω2msds√2

A

m−2

j0

AT

0

ω2j2

s2ds

AT4 m−1

j0

AT2/4

0

ω2j1sds 1

A

AT

0

ω0s2dsT2m

j0 ωj1.

3.44

Notice thatΛ<∞byH2. Consequently,

x2m

n < T

0 h

s,2m12m j0

xnj

ds Λ fornÆ. 3.45

SincexnjT2mjx2m

n ∞for 0≤j ≤2m, which follows from the fact thatxnjvanishes

inJby1.2and assertionii, inequality3.45yields

x2m

n < T

0

hs,2m1Kxn2m

ds Λ forn∈Æ, 3.46

whereKis fromH2. Due to the condition

lim sup

v→ ∞ 1 v

T

0

ht, Kvdv <1 3.47

inH2, there exists a positive constantSsuch that for allvSthe inequality

T

0

ht,2m1Kvdt Λ≤v 3.48

is fulfilled. The last inequality together with estimate3.46givesxn2m < Sforn ∈ Æ.

Consequently,xnj< T2mjSfor 0j2n,n

Æ, and assertionivfollows.

The following result gives the important property of {fnt, xnt, . . . , xn2mt} for

applying the Vitali convergent theorem in the proof of Theorem4.1.

Lemma 3.5. Let (H1) and (H2) hold. Letxnbe a solution of problem2.8,1.2. Then, the sequence

fn

t, xnt, . . . , xn2mt

L1J 3.49

is uniformly integrable on J, that is, for each ε > 0, there exists δ > 0 such that ifM ⊂ J and measM< δ, then

Mfn

t, xnt, . . . , xn2mt

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Proof. By Lemma3.4iv, there existsS > 0 such that forn∈ Æ, the inequalityxn C2m < S

holds. Now, we conclude from2.5and2.6, from the properties ofhandωjgiven inH2,

and finally from3.29that forjJandn∈Æ, the estimate

afn

t, xnt, . . . , xn2mt

ht,2m1S ω0At2

m−1

j0

ω2j1AtTt

m−2

j0 ω2j2

Atξj,n2

ω2mA|tξm−1,n|

m

j0 ωj1

3.51

is fulfilled, whereAis a positive constant. Since the functionsht,2m1S,ω0At2, and ω2j1AtTt 0 ≤ jm−1 belong to the setL1J by assumption H2, in order to prove that{fnt, xnt, . . . , xn2mt}is uniformly integrable onJ, it suffices to show that the

sequences

{ω2mA|tξm−1,n|},

ω2j2

Atξj,n2

, 0≤jm−2 3.52

are uniformly integrable onJ. Due to#01ω2msds <∞and#01ω2js2ds <∞for 1≤jm−1

byH2, this fact follows from13, Criterion 11.10withbAandr1,2.

4. The Main Result

The following theorem is the existence result for the singular problem1.1,1.2.

Theorem 4.1. Let (H1) and (H2) hold. Then, problem 1.1, 1.2 has a positive solution xAC2mJand

xt>0 fort∈0, T, −1jx2j1t>0 fort∈0, T, 0≤jm−1. 4.1

Proof. Lemma 3.3guarantees that problem 2.8, 1.2 has a solution xn. Consider the

se-quence{xn}. By Lemma3.4,{xn}is bounded inC2mJ,

−1jxn2j1t>0 fort∈0, T, 0≤jm−1, 4.2

andxnfulfils estimate3.29, whereAis a positive constant andξj,n ∈ 0, T. Furthermore,

the sequence {fnt, xnt, . . . , xn2mt} is uniformly integrable on J by Lemma 3.5, and

therefore, we deduce from the equality−1mxn2m1t fnt, xnt, . . . , xn2mtfor a.e.tJ

that{xn2m} is equicontinuous onJ. Now, by the Arzel`a-Ascoli theorem and the Bolzano-Weierstrass theorem, we may assume without loss of generality that{xn}is convergent in C2mJand{ξ

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0≤jm−1. ThenxC2mJandxsatisfies the boundary conditions1.2. Lettingn → ∞ in3.29and4.2, we getfortJ

x2mtA|tξ

m−1|, x2j2tA

tξj2 if 0≤jm−2

−1jx2j1tAtTt if 0≤jm−1, xtAt2.

4.3

Keeping in mind the definition offn, we conclude from4.3that

lim

n→ ∞fn

t, xnt, . . . , xn2mt

ft, xt, . . . , x2mt for a.e. tJ. 4.4

Then, by the Vitali theorem,ft, xt, . . . , x2mtL1Jand

lim

n→ ∞

t

0 fn

s, xns, . . . , xn2ms

ds

t

0

fs, xs, . . . , x2msds fortJ. 4.5

Lettingn → ∞in the equality

x2m

n t xn2m0 t

0 fn

s, xns, . . . , xn2ms

ds, 4.6

we get

x2mt x2m0 t

0

fs, xs, . . . , x2msds fortJ. 4.7

As a result,xAC2mJandxis a solution of1.1. Consequently,xis a positive solution of problem1.1,1.2and inequality4.1follows from4.3.

Example 4.2. Consider problem1.1,1.2with

ft, x0, . . . , x2m pt

2m

k0

akt|xk|αk bkt |xk|βk

4.8

onJ×D, wherep, akL1J,bkLJ that is,bkis essentially bounded and measurable on

Jare nonnegative,pta >0 for a.e.tJ. Ifαk∈0,1for 0≤k ≤2mandβ2k ∈0,1/2, β2m, β2k1∈0,1for 0≤km−1, then, by Theorem4.1, the problem has a positive solution xAC2mJsatisfying inequality4.1.

Acknowledgment

(15)

References

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References

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