Reference
Calculation
Output
Area of concrete
Area of concrete in compression Area of tension reinforcement
Minimum area of tension reinforcement
Length of that part of member traversed by shear failure plane b With (breath) or effective width of section
c Cover to outer diameter d Effective depth of section
Basic force used in defining compressive forces Basic force used in defining tie forces
Characteristic strength of concrete
Estimated design service stress in the tension reinforcement Characteristic strength of reinforcement
G Shear modulus
H Maximum horizontal force Horizontal force in x direction Horizontal force in y direction h Overall depth
KEL Knife edge load L Critical perimeter
Dimension of element on x direction Dimension of element on y direction Dimension of element on z direction M Design ultimate resistance moment
Moment on x axis Moment on y axis Moment on z axis q Surcharge load r Internal radius of bend SLS Serviceability limit state T Traction force
t Thickness of the element ULS Ultimate limit state
V Shear force due to design ultimate loads or design ultimate value of a concentrated load
v Design shear stress
vc Design shear stress in concrete x Neutral axis depth
x' Distance from Y axis to the centroid of an element
y' Distance from X axis to the centroid of an element
z Lever arm
z' Distance from X - Y plane to point where the considered resultant force acting
Coefficient, variously defined, as appropriate Strain in tension reinforcement
Nominal range of movement Soil friction angle, or diameter Active earth pressure Unit weight of soil Partial load factor Partial load factor
Doc. No.
DESIGN UNIT
Designed
Ac Acc As As min av Fc Ft fcu fs fy Hx Hy lx ly lz Mx My Mz
D
E
C
Date
β
¿
sδ
φ
σ
aγ
γ
fLγ
f3EPC DIVISION
Checked
Date
CENTRAL ENGINEERING CONSULTANCY BUREAU (CECB)
Job Code
Page
Reference
Calculation
Output
D
E
C
Doc. No.
DESIGN UNIT
Designed
EPC DIVISION
Checked
Date
CENTRAL ENGINEERING CONSULTANCY BUREAU (CECB)
Job Code
Page
Reference
Calculation
Output
D
E
C
Doc. No.
DESIGN UNIT
Designed
EPC DIVISION
Checked
Date
CENTRAL ENGINEERING CONSULTANCY BUREAU (CECB)
Job Code
Page
Reference
Calculation
Output
D
E
C
Doc. No.
DESIGN UNIT
Designed
EPC DIVISION
Checked
Date
CENTRAL ENGINEERING CONSULTANCY BUREAU (CECB)
Job Code
Page
Reference
Calculation
Output
D
E
C
Doc. No.
DESIGN UNIT
Designed
EPC DIVISION
Checked
Date
CENTRAL ENGINEERING CONSULTANCY BUREAU (CECB)
Job Code
Page
D
E
C
Reference
Calculation
Output
Design of Box Culvert
Figure 01 Dimentional Properties
h = 1.2 m
l = 1.5 m
Soil Cover , H = 7.2 m
Safe Bearing Pressure = 150 kN/m2
Section Thickness
= 0.2 m ( hw , h = span/(10 ~15))Main R/F
=12
mmCover to R/F
=45
mmGrade of Concrete
=25
N/mm2 Properties of Soilγc
=24
kN/m3 γs = 20 kN/m3γw
=9.81
kN/m3 Φ' = 25 1 - Permanent Loads 1.1 Dead LoadsThe nominal dead doad consist of the weight of the materials and the part of the structure
Structural Unit Weight of Concrete shall be taken as 24 kN/m3
Engineering Becouse of the arching of soil, check whether the depth above culvert is Design in > 3 x width of culvert ( in which case limit depth to 3 x width )
preactice
(Roger - Depth of cover (H) = 7.2
m
westbrook) 3 x width = 3 x
1.6
(page-94) = 4.8 m 3 x width<
= 7.2 m SoDepth limited to
=
4.8 m
Surcharge on Roof
Surcharge Presure (qr) = 4.8 x 20 qr = 96 kN/m2Soil
Engineering
Casses of conduit installation consider as Ditch Conduit
(Spangler &
Ditch Conduit
Handy)
A ditch conduit is defined as one which is instaled in a relatively narrow
ditch dug in passive or undisturbed soil and wich is then covered with earth backfill.Ceylon Electricity Board
Doc. No.
Dam Safety
Designed
S.M.P
31.05.2010Environmental &
Checked
Date
o
C
E
B
Date
Y hs hw Ground Level hs hw A B D C H l h XCivil Structure Maintanance
Job Code
Page
1
Reference
Calculation
Output
Maximum load on ditch condition
Depth of cover = 7.2 m
Surcharge on Roof
Surcharge Presure (qr) , (qr) = Cd = =K
=
-
coedicient of friction between fill material
and side of ditch
K
-
Active Lateral earth pressure coeficient -Horizontal width of ditch at top of conduit
γ-
Unit weight (wet density) of filling materialH
- Height of fill above top of conduiteCd - Load coeficient for ditch condition
So, K = Bd = 3.60 m, Consider 1m length of Roof slab
= 0.406 = = 0.466 2.K.µ'.(H/Bd) = 0.76 Cd = 1.403 (qr) = (qr) =
101.0
kN/m2Structural 1.2 Horizontal Earth Pressure Engineering
Design in If the backfill properties are known, preactice If wall friction is to be ignored (δ = 0 ) (Roger
-westbrook) = 1-sin Φ' = 0.58
(page-94) = ( 1-sin Φ' ) / ( 1+sin Φ' ) = 0.41
q max
=
γ.Ka.h
=
20 x
0.41 x
9.1
= 73.87 kN/m2
=
20 x
0.41 x
1.9
= 15.42
kN/m2
q
=
q
=
58.44 kN/m2
Ceylon Electricity Board
Doc. No.
Dam Safety
Designed
S.M.P
31.05.2010C
E
B
Cd.γ.Bd21-e
-2Kµ'
(H/Bd) 2.K.µ' µ' tan φ'1-sin φ
1+sin φ µ' Bd1-sin φ
1+sin φ µ' tan φ' Cd.γ.Bd2 K0 Kaq
epq
max- q
epC
E
B
Date
Environmental &
Checked
Date
Civil Structure Maintanance
Job Code
Page
1
Reference
Calculation
Output
AASHTO 2 - Vertical Live Loads 3.7.1
For Fill Depths H ≥ 8 feet (2400 mm) and Culvert Clear Span Length,
The effect of live load is neglected in design when the depth of fill is more than
8 feet
3 - Hydrostatic Pressure (Internal)
= C.h
=
9.81 x
1.7
= 16.68
kN/m2
4 - Analysis Reinforced Concrete Constant K = h{
hs}
3 = 1.21 Designers l Manual k1 = K+1 = 2.21 (ref-5.1) k3 = K+3 = 4.21 k5 = 2K+3 = 5.43 k7 = 2K+7 = 9.43 k8 = 3K+8 = 11.644.1 Load Case -01 Testing Condition
4.1.1
Hydrostatic Pressure-(Internal)
Reinforced=
=
Concrete60.k1.k3
Designers=
0.99 kN.m/m
Manual (ref-5.1)=
= Ma. K8
k7
= 1.22kN.m/m
4.1.2
Flexure due to weight of wall
Wall weight ( G ) = hw.γ.h
q1 = 2.G
= 10.20kN/m2
= 8.2 kN/ml.hw
Reinforced Concrete=
=
Designers12.k1.k3
Manual=
0.22 kN.m/m
(ref-5.1)=
= Ma. K5
K
=
-0.97 kN.m/m
4.1.3
Flexure due to weight of Roof
q = hs.γc = 4.8
kN/m2
Doc. No.
C
E
B
q
ip hwM
AM
Bq
ip.h
2.K.k7
M
CM
DM
AM
Bq1.l
2.K
M
CM
D A B D C qip q = qip B.M.D Pressures A B D C q1 G G B.M.D PressuresDam Safety
Designed
S.M.P
31.05.2010Environmental &
Checked
Date
Civil Structure Maintanance
Job Code
Page
2
Reference
Calculation
Output
=
=
=
=
12.k1
=
-0.35 kN.m/m
Addition of moment for Load case 01Position
γf
Walls
Roofγf
Total uls
A and B
0.99
1.4
1.38
0.22
-0.35 -0.14 1.4 -0.19 1.19 C and D1.22
1.4
1.70
-0.97
-0.35 -1.32 1.4 -1.85 -0.150.99
1.4
1.38
0.22
**
1.04 1.4 1.45 2.83 0.821.22
1.4
1.70
**
**
2.35 1.4 3.29 5.001.53
0.82*
1.4
-2.88
-0.38
-0.35 -0.73 1.4 -1.02 -3.90-2.06
Table - 01 Fixed end mement of the wall for Hydrostatic load= W.L = W.L
15 10
= 1.61 kN.m/m = 2.41 kN.m/m
Maximum (-ve) moment = W.L
(Where x is 0.45L from C) 23.3
= -1.0 kN.m/m
* Calculation of moment at mid span of walls done by aproximatly by adding moment transferred to mid span from FEM to the Maximum negative meoment occurred at 0.45L after moment distribution
** Moment at mid span of the wall is calculated by considering full bending Calculation of midspan moment due to wall load
Niutral axis depth from A = 0.26 m
4.2 Load Case -02 Culvert empty and trench filled
Lateral soil pressurees giving rise to flexture in the structure
4.2.1 Reinforced Concrete
=
=
Designers60.k1.k3
Manual= -0.91 kN.m/m
(ref-5.1)=
=
k7
= -1.13kN.m/m
C
E
B
Date
M
AM
BM
CM
Dq.l
2Hydrost-atic
uls-
Mb
Walls + Roofuls-
Mb
Roof mid-Span Base mid-Span Walls middle MA MC"q"is the rectanguler pressure and "q
ep"is the triangular pressure
Trianguler Pressure,q
epM
AM
Bq
ep.h
2.K.k7
M
CM
DM
A. K8
A B D C qep qep B.M.D Pressures A B D C q = q1 B.M.D PressuresDoc. No.
Dam Safety
Designed
S.M.P
31.05.2010Environmental &
Checked
Date
Civil Structure Maintanance
Job Code
Page
3
Reference
Calculation
Output
4.2.2
Surcharge on walls,q
=
=
=
Reinforced
=
Concrete
12.k1
Designers
= -7.72 kN.m/m
Manual 4.2.3
Surcharge on Roof ,qr
(ref-5.1)
=
=
=
=
12.k1
=
-7.45 kN.m/m
Addition of moment for Load Case 2
Posotion q γf Total U.L.S.
A and B -0.91 -7.72 -0.14 -7.45 -16.22 1.4 -22.70 C and D -1.13 -7.72 -1.32 -7.45 -17.62 1.4 -24.66 Roof mid-Span -0.91 -7.72 1.04 17.29 9.70 1.4 13.58 -1.13 -7.72 2.35 17.29 10.80 1.4 15.12 Walls middle
*
**
-0.73 -7.45 6.65 1.4 9.31 1.43 13.39 = W.L = W.L 15 10 = 1.49 kN.m/m = 2.23 kN.m/mMaximum (-ve) moment = W.L
(Where x is 0.45L from C) 23.3
= -1.0 kN.m/m
4.2 Load Case -03
4.2.1
This is load case 02 + Hydrostatic load from Load case 01
Posotion Total (U.L.S.)
A and B -16.22 0.99 -15.23 -22.70 1.38 -21.32 C and D -17.62 1.22 -16.40 -24.66 1.70 -22.96 Roof mid-Span 9.70 0.99 10.69 13.58 1.38 14.96 10.80 1.22 12.02 15.12 1.70 16.83 Walls middle 6.65 -2.06 4.59 9.31 -2.88 6.43
C
E
B
Date
M
AM
BM
CM
Dq.h
2.K
M
AM
BM
CM
Dq.l
2q
ep Roof(Walls & LC-1) Surcharg -e (Roof) (Survice)TotalBase mid-Span
Fixed end mement of the wall due to qep
MA MC
L.C.02
(Service) (Service)Hydrost. (Service)Total (U.L.S.)L.C.02 Hydrost. (U.L.S.)
Base mid-Span A B D C B.M.D Pressures Pressures A B D C B.M.D
Doc. No.
Dam Safety
Designed
S.M.P
31.05.2010Environmental &
Checked
Date
Civil Structure Maintanance
Job Code
Page
4
Reference
Calculation
Output
5 - Check on ground safe bearing pressure
5.1 Load Case -01
Hydrostatic Pressure = 16.68 kN/m2
Weight of walls = 10.20 kN/m2
Weight of Roof + Floor = 9.60 kN/m2
Total Pressure = 36.48 kN/m2
Total Pressure < 150
kN/m2
hence ok5.2 Load Case -02
Weight of walls = 10.20 kN/m2
Weight of Roof + Floor = 9.60 kN/m2
Surcharge on Roof = 96.00 kN/m2
Total Pressure = 115.80 kN/m2
Total Pressure < 150
kN/m2
hence ok5.3 Load Case -03
Weight of walls = 10.20 kN/m2
Weight of Roof + Floor = 9.60 kN/m2
Surcharge on Roof = 96.00 kN/m2
Hydrostatic Pressure = 16.68 kN/m2
Total Pressure = 122.28 kN/m2
Total Pressure < 150
kN/m2
hence ok6 - U.L.S. of Flexture
Maximum Moments kN.m/m
Member Hogging Sagging
Roof -22.70 (L.C-01) 14.96 (L.C-03) Walls -24.66 (L.C-02) 9.31 (L.C-02) Base -24.66 (L.C-02) 16.83 (L.C-03) i - Slabs Maximum Moment = 24.15 kN.m/m
C
E
B
Date
Doc. No.
Dam Safety
Designed
S.M.P
31.05.2010Environmental &
Checked
Date
Civil Structure Maintanance
Job Code
Page
5
Reference
Calculation
Output
6 -
Design Calculation for Box Culvert
6.1 U.L.S. of Flexture
Analysis was carried out for several load cases of various loading arrangements to find out the maximum effect on the Box culvert Diameter of main reinforcement = 12
mm
Diameter of secondary reinforcement = 12mm
Section Thickness
= 200 mm
Maximum Bending Moment
=
24.15 kN.m/mAssume severe environment condition, for driving rain
Cover = 45
mm
Effective depth, d = 200 - 45- 6 d = 149 mm=
149 mm k = 2 = =0.044
< 0.16 Hence no compression r/f is requiredM = equation 1
z = equation 5 from these two equations z = z = = 141.41 < 0.950 d Take Z as 0.95d Z = 0.95 d = 0.95 x 149 = 142
mm
6.1.1 Design of main reinforcement =
= =
= 426 426
Use T 12 @
250
( As = 452 =452
Minimum area of main rainforcement for slabs
= 100x452/(1000x149) = 0.30 ###0.13 Main r/f
T 12 @ 250
Hence o.k
6.2 Design for Shear Reinforcement
Check shear in U.L.S. on roof and floor slabs
Take Load case 02
Shear across support
=
( 115.80 - Wt of Base x γf )
=
109.08 kN/m2
C
E
B
Date
M / (bd2f cu) (24.15x106 /(1000x1492x25) (0.87fy)Asz (1 - 1.1fyAs/ fcubd) d d (0.5+(0.25-k/0.9)1/2 d [0.5+(0.25-0.044/0.9)1/2 As M / 0.87fyz 24.15 x106 / 0.87x460x142 A s reqmm
2/m
mm2/mmm
2/m
A
s pro mm2/m 100As / badTherefore shear in the support =
109.08 x 1.2 /2
=
65.45 kN/m
Doc. No.
Dam Safety
Designed
S.M.P
31.05.2010Environmental &
Checked
Date
Civil Structure Maintanance
Job Code
Page
6
Reference
Calculation
Output
Design shear force, V design = 65.45 kN/m Effective depth, d = 149
mm
Tension steel across shear plane = Y12 -250 c/c
100 As/bd =
100 x 452
1000x149
=
0.30
BS 8110 Effective depth=
149 mm
Part 01=
table 3.1=
0.54
Design shear stress v = V/bd = = 0.44
v
<
vc
Hence o.k6.3 Check in U.L.S. on the ability of the wall to trasmit the axial loads Bs 8110 Treat as a column with bending at right angle to wall
3.9.3.6.2
Check h/hw
=
1.7 /
0.2
3.4.4.1
=
8.5 <
12
hence column is short
BS 8110 indicates that the effect of the axial load may be ignored if this force does
hence
0.1.fcu.(C.S.A)
=
0.1 x
30 x
200
= 600 kN/m
Ultimate Load /m/Wall = 1/2( 96.0 x 1.7 x 1.4 + 0.2 x 1.7 x 24x1.4 ) = 120 kN/m < 600 kN/m
hence o.k.
The above calculation assumes that the wall is cosidered as reignfoced and not mass concrete
vertical R/F provided = Y 12 @ 200 2 Layers
so Area = 1131.0 mm2
Percentage of Concrete area = 1131.0 x 100 1000 x 149 = 0.76 % > 0.4 % This is > Minimum of 0.4% hence o.k.
C
E
B
Date
v
c0.79x{(100As/bd)
1/3.(400/d)
1/4/1.25
(65.45x103)/(1000x149) N/mm2Doc. No.
Dam Safety
Designed
S.M.P
31.05.2010Environmental &
Checked
Date
Civil Structure Maintanance
Job Code
Page
7
Reference
Calculation
Output
C
E
B
Doc. No.
Dam Safety
Designed
S.M.P
31.05.2010Environmental &
Checked
Date
Civil Structure Maintanance