doi:10.1155/2010/714891
Research Article
Strictly Increasing Solutions of Nonautonomous
Difference Equations Arising in Hydrodynamics
Luk ´a ˇs Rach ˚unek and Irena Rach ˚unkov ´a
Department of Mathematics, Faculty of Science, Palack´y University, tˇr. 17. listopadu 12, 77146 Olomouc, Czech Republic
Correspondence should be addressed to Irena Rach ˚unkov´a,[email protected]
Received 19 December 2009; Revised 14 February 2010; Accepted 10 March 2010
Academic Editor: A ˘gacik Zafer
Copyrightq2010 L. Rach ˚unek and I. Rach ˚unkov´a. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.
The paper provides conditions sufficient for the existence of strictly increasing solutions of the second-order nonautonomous difference equationxn1 xn n/n12xn−xn− 1 h2fxn,n∈N, whereh > 0 is a parameter andfis Lipschitz continuous and has three real zerosL0 <0< L. In particular we prove that for each sufficiently smallh > 0 there exists a solution{xn}∞n0such that{xn}∞n1is increasing,x0 x1 ∈L0,0,and limn→ ∞xn> L.
The problem is motivated by some models arising in hydrodynamics.
1. Formulation of Problem
We will investigate the following second-order non-autonomous difference equation
xn1 xn
n
n1
2
xn−xn−1 h2fxn, n∈N, 1.1
wherefis supposed to fulfil
L0<0< L, f ∈LiplocL0,∞, fL0 f0 fL 0, 1.2
xfx<0 forx∈L0, L\ {0}, fx≥0 forx∈L,∞, 1.3
∃B∈L0,0such that
L
Bfzdz0.
Let us note thatf ∈ LiplocL0,∞means that for eachL0, A ⊂ L0,∞there existsKA >0 such that|fx−fy| ≤ KA|x−y|for allx, y ∈L0, A . A simple example of a functionf
satisfying1.2–1.4isfx cx−L0xx−L, wherecis a positive constant.
A sequence{xn}∞n0which satisfies1.1is called a solution of1.1. For each values
B, B1∈L0,∞there exists a unique solution{xn}∞n0of1.1satisfying the initial conditions
x0 B, x1 B1. 1.5
Then{xn}∞n0is called a solution of problem1.1,1.5.
In 1 we have shown that 1.1 is a discretization of differential equations which generalize some models arising in hydrodynamics or in the nonlinear field theory; see2–
6 . Increasing solutions of 1.1,1.5withB B1 ∈L0,0has a fundamental role in these
models. Therefore, in1 , we have described the set of all solutions of problem1.1,1.6, where
x0 B, x1 B, B∈L0,0. 1.6
In this paper, using1 , we will prove that for each sufficiently smallh >0 there exists at least oneB∈L0,0such that the corresponding solution of problem1.1,1.6fulfils
x0 x1, lim
n→ ∞xn> L, {xn} ∞
n1 is increasing. 1.7
Note that an autonomous case of 1.1 was studied in 7 . We would like to point out that recently there has been a huge interest in studying the existence of monotonous and nontrivial solutions of nonlinear difference equations. For papers during last three years see, for example,8–22 . A lot of other interesting references can be found therein.
2. Four Types of Solutions
Here we present some results of1 which we need in next sections. In particular, we will use the following definitions and lemmas.
Definition 2.1. Let{xn}∞n0be a solution of problem1.1,1.6such that
{xn}∞n1 is increasing, nlim→ ∞xn 0. 2.1
Then{xn}∞n0is called a damped solution.
Definition 2.2. Let{xn}∞n0be a solution of problem1.1,1.6which fulfils
{xn}∞
n1 is increasing, nlim→ ∞xn L. 2.2
Definition 2.3. Let {xn}∞n0 be a solution of problem 1.1,1.6. Assume that there exists
b∈N, such that{xn}bn11is increasing and
xb≤L < xb1. 2.3
Then{xn}∞n0is called an escape solution.
Definition 2.4. Let {xn}∞n0 be a solution of problem 1.1,1.6. Assume that there exists
b∈N,b >1, such that{xn}bn1is increasing and
0< xb< L, xb1≤xb. 2.4
Then{xn}∞n0is called a non-monotonous solution.
Lemma 2.5see1 on four types of solutions. Let{xn}∞n0be a solution of problem1.1, 1.6. Then{xn}∞n0is just one of the following four types:
I{xn}∞n0is an escape solution; II{xn}∞n0is a homoclinic solution; III{xn}∞n0is a damped solution;
IV{xn}∞n0is a non-monotonous solution.
Lemma 2.6see1 estimates of solutions. Let{xn}∞n0be a solution of problem1.1,1.6. Then there exists a maximalb∈N∪ {∞}satisfying
xn∈B, L forn1, . . . , b, ifb∈N,
xn∈B, L forn∈N, ifb∞. 2.5
Further, ifb >1, then moreover
{xn}bn1 is increasing, 2.6
Δxn< hL−2L0M0h2M0 2.7
forn1, . . . , b−1ifb∈N, and forn∈Nifb∞, where
M0max fx :x∈L0, L
. 2.8
In 1 we have proved that the set consisting of damped and non-monotonous solutions of problem 1.1, 1.6 is nonempty for each sufficiently small h > 0. This is contained in the next lemma.
InSection 4of this paper we prove that also the set of escape solutions of problem 1.1,1.6is nonempty for each sufficiently smallh >0. Note that in our next paper23 we prove this assertion for the set of homoclinic solutions.
3. Properties of Solutions
Now, we provide other properties of solutions important in the investigation of escape solutions.
Lemma 3.1. Let {xn}∞n0 be an escape solution of problem 1.1, 1.6. Then {xn}∞n1 is increasing.
Proof. Due to1.1,{xn}∞n0fulfils
Δxn
n
n1
2
Δxn−1 h2fxn, n∈N. 3.1
According to Definition 2.3 there existsb ∈ N, such that{xn}bn11 is increasing and 2.3
holds. By 1.3 we get fxb 1 ≥ 0. Consequently, by 3.1 and 2.3, Δxb 1 ≥ b12/b22Δxb>0 andfxb2≥0. SimilarlyΔxbj≥bj2/b1j2Δxb
j−1and
Δxbj≥
b
1
b1j
2
Δxb, j∈N. 3.2
This yields that{xn}∞n1is increasing.
Lemma 3.2. Assume thatfx 0forx > L. Choose an arbitrary >0. LetB1, B2∈L0,0and let
{xn}∞
n0and{yn}∞n0be a solution of problem1.1,1.6withBB1andBB2, respectively.
LetKLbe the Lipschitz constant forfonL0, L . Then
xn−yn ≤ |B1−B2|e2KL
, 3.3
Δxn−hΔyn ≤ |B1−B2|KLe2KL, 3.4
wheren∈N,n≤/h.
Proof. By3.1we have
j12Δxj−j2Δxj−1h2j2fxj, j∈N. 3.5
Summing it forj1, . . . , k, we get by1.6
Δxk h2 1
k12 k
j1
Summing it again fork1, . . . , n−1, we get
From this and by using summation by parts we easily obtain
xn−yn ≤ |B1−B2|h2n−1
Moreover, if the sequence {γk}∞k1 is unbounded, then there exists ∈ N such that the solution
{xn}∞n0of problem1.1,1.6withBB∈L0, Bis an escape solution.
Proof. Chooseh0>0 such that
h0
L−2L0M0h20M0<|C|. 4.2
Fork∈Ndenote by{xkn}∞n0a solution of problem1.1,1.6withBBk. The existence of
bkis guaranteed byLemma 2.6. ByLemma 2.5,{xkn}∞n0is just one of the typesI–IV, and
ifh∈0, h0 , then the monotonicity of{xkn}bkn0yields a uniqueγk ∈N,γk < bk, satisfying
4.1.
Forh∈0, h0, consider the sequence{γk}∞k1 and assume that it is unbounded. Then
we have
lim
k→ ∞γk∞ 4.3
otherwise we take a subsequence.Assume on the contrary that for anyk ∈N,{xkn}∞n0 is not an escape solution. Choosek ∈N. If{xkn}∞n0is damped, then byDefinition 2.1, we
havebk∞and
xkbk: lim
k→ ∞xkn 0, Δxkbk:klim→ ∞Δxkn 0. 4.4
If{xkn}∞n0is homoclinic, then byDefinition 2.2, we havebk∞and
xkbk: lim
k→ ∞xkn L, Δxkbk:klim→ ∞Δxkn 0. 4.5
If{xkn}∞n0is non-monotonous, then byDefinition 2.4, we havebk<∞and
xkbk∈0, L, Δxkbk≤0. 4.6
To summarize if{xkn}∞n0is not an escape solution, then by4.4,4.5, and4.6, we have
xkbk∈0, L, Δxkbk≤0. 4.7
SinceΔxk0 0, there existsγk∈Nsatisfying
Lettingk → ∞, we obtain, by4.3, that limk→ ∞Δxkγk ∞, contrary to4.17. Therefore an escape solution{xn}∞n0of problem1.1,1.6withBB∈L0, Bmust exist.
Now, we are in a position to prove the next main result.
Theorem 4.2On the existence of escape solutions. There existsh∗ > 0such that for anyh ∈ 0, h∗ the initial value problem1.1,1.6has an escape solution for someB∈L0, B.
Proof. We have the following steps.
Step 1. Let us define
fx
⎧ ⎨ ⎩
fx forx≤L,
0 forx > L,
4.23
and consider an auxiliary equation
xn1 xn
n
n1
2
xn−xn−1 h2fxn, n∈N. 4.24
Leth∗ > 0 be the constant ofLemma 4.1for problem4.24,1.6. Chooseh ∈ 0, h∗ ,C ∈ L0, Band letKLbe the Lipschitz constant forfonL0,∞. Consider a sequence{Bk}∞k1 ⊂
L0, Csuch that limk→ ∞BkL0. Then, for eachm∈Nthere existskm∈Nsuch that
|Bkm −L0|< e−m
2KL
C−L0. 4.25
Letx00 x0n L0 forn ∈ N. Then the sequence{x0n}∞n0 is the unique solution of
problem4.24,1.6withB L0. Let{xkn}∞n0 be a solution of problem4.24,1.6with
BBk,k∈N, and let{γk}∞k1be the sequence corresponding to{xkn}∞n0byLemma 4.1. We
prove that{γk}∞k1is unbounded. According toLemma 3.2, for eachm∈N,
|xkmn−x0n| ≤ |Bkm−L0|em
2KL
, n≤ m
h. 4.26
Consequently,4.25and4.26give
|xkmn−x0n| ≤C−L0, n≤ mh, 4.27
and hence
xkmn≤C, n≤ mh. 4.28
Therefore
which yields that{γk}∞k1 is unbounded. By Lemma 4.1, the auxiliary initial value problem
4.24, 1.6 has an escape solution for some B B ∈ L0,B. Denote this solution by
{xn}∞n0.
Step 2. ByDefinition 2.3, there existsb∈Nsuch that
{xn}b1
n1 is increasing, xb≤L <xb1. 4.30
Now, consider the solution{xn}∞n0of our original problem1.1,1.6withB B. Due
to4.23,xn xn forn 0,1, . . . , b1. Using4.30and Definition 2.3, we get that
{xn}∞n0is an escape solution of problem1.1,1.6.
Acknowledgments
The paper was supported by the Council of Czech Government MSM 6198959214. The authors thank the referees for valuable comments.
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