Volume 2008, Article ID 732193,18pages doi:10.1155/2008/732193
Research Article
Weak and Strong Convergence Theorems of
an Implicit Iteration Process for a Countable
Family of Nonexpansive Mappings
Kittikorn Nakprasit,1Weerayuth Nilsrakoo,2and Satit Saejung1
1Department of Mathematics, Khon Kaen University, Khon Kaen 40002, Thailand 2Department of Mathematics, Statistics and Computer, Ubon Rajathanee University,
Ubon Ratchathani 34190, Thailand
Correspondence should be addressed to Satit Saejung,[email protected]
Received 22 July 2008; Accepted 18 November 2008
Recommended by Anthony Lau
Using the implicit iteration and the hybrid method in mathematical programming, we prove weak and strong convergence theorems for finding common fixed points of a countable family of nonexpansive mappings in a real Hilbert space. Our results include many convergence theorems by Xu and Ori2001and Zhang and Su2007as special cases. We also apply our method to find a common element to the set of fixed points of a nonexpansive mapping and the set of solutions of an equilibrium problem. Finally, we propose an iteration to obtain convergence theorems for a continuous monotone mapping.
Copyrightq2008 Kittikorn Nakprasit et al. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.
1. Introduction
LetHbe a real Hilbert space with inner product·,·and norm·,and letCbe a nonempty subset ofH. A mappingT :C → His said to benonexpansiveif
Tx−Ty ≤ x−y ∀x, y∈C. 1.1
We denote byFTthe set of all fixed points ofT. IfCis bounded closed convex andT is a nonexpansive mapping ofCinto itself, thenFTis nonemptysee1. We writexn → x
xn x, resp.if {xn} converges strongly weakly, resp. to x. There are many methods
x1α1x01−α1T1x1,
x2α2x11−α2T2x2, ..
.
xNαNxN−1
1−αNTNxN,
xN1αN1xN1−αN1
T1xN1
.. .
1.2
where{αn}is a sequence in0,1. The iteration above can be written in the following compact form:
xnαnxn−1
1−αnTnxn, n≥1, 1.3
whereTn≡TnmodN,here the mod Nfunction takes values in{1,2, . . . , N}.They proved that
this process converges weakly to a common fixed point of{Ti}Ni1. Recently, to obtain a strong convergence theorem, Zhang and Su 3 modify iteration processes 1.3 by the implicit hybrid method for a finite family of nonexpansive mappings{Ti}Ni1: an initial pointx0∈C,
x0∈Cis arbitrary,
ynαnxn1−αnTnzn,
znβnyn1−βnTnyn,
Cnz∈C:yn−z≤xn−z,
Qnz∈C:xn−z, x0−xn≥0,
xn1PCn∩Qnx0, n0,1,2, . . . ,
1.4
whereTn≡TnmodN, {αn}and{βn}are real sequences in0,1withαn<1.
In this paper, we establish weak and strong convergence theorems for finding common fixed points of a countable family of nonexpansive mappings in a real Hilbert space. Our results include many convergence theorems by 2, Theorems 2 and 3, Theorems 2.4 as special cases. The new iteration introduced in this paper is applied to find a common element to the set of fixed points of a nonexpansive mapping and the set of solutions of an equilibrium problem. We also propose an iteration to obtain convergence theorems for a continuous monotone mapping.
2. Preliminaries
LetHbe a real Hilbert space. Then,
x−y2x2− y2−2x−y, y, 2.1
λx 1−λy2λx2 1−λy2−λ1−λx−y2 2.2
1Opial’s condition4, that is, for any sequence{xn}withxn x, the inequality
lim inf
n→ ∞ xn−x<lim infn→ ∞ xn−y 2.3
holds for everyy∈Hwithy /x.
2The Kadec-Klee property 1, that is, for any sequence {xn} with xn x and xn → xtogether impliesxn−x → 0.
LetCbe a nonempty closed convex subset ofH. Then, for anyx∈H, there exists the nearest pointPCxinCsuch that
x−PCx≤ x−y ∀y∈C. 2.4
Such a mapping, PC is called the metric projection of H onto C. We know that PC is
nonexpansive. Furthermore, forx∈Handz∈C,
zPCx iffx−z, z−y ≥0∀y∈C. 2.5
Lemma 2.1see5, Lemma 1. Suppose that{an}and{bn}are two sequences of nonnegative real numbers such that
an1≤anbn ∀n≥1, 2.6
and ∞n1bn<∞, thenlimn→ ∞anexists. In particular, iflim infn→ ∞an0, thenlimn→ ∞an0.
Lemma 2.2see6, Lemma 2.2. Suppose that{an}and{bn}are two sequences of nonnegative real numbers such that ∞n1an∞and ∞n1anbn<∞. Then,lim infn→ ∞bn0.
Lemma 2.3see7, Lemma 3.2. LetCbe a nonempty closed convex subset of a real Hilbert space
H. Let{xn}be a sequence inHsuch that
xn1−y≤xn−y ∀y∈C, n∈N. 2.7
Then, the sequence{PCxn}converges strongly to somez∈C.
To deal with a family of mappings, the following conditions are introduced. LetCbe a subset of a Banach space, let{Tn}andTbe families of mappings ofCwith ∞n1FTn
FT/∅, whereFTis the set of all common fixed points of all mappings inT.
a{Tn}is said to satisfy the AKTT-condition8if for each bounded subsetBofC,
∞
n1
supTn1z−Tnz:z∈B<∞. 2.8
b{Tn}is said to satisfy the NST-conditionIwithT9if for each bounded sequence
{zn}inC,
lim
n→ ∞zn−Tnzn0 implies limn→ ∞zn−Tzn0 ∀T ∈ T. 2.9
c{Tn}is said to satisfy the NST-conditionII 9if for each bounded sequence{zn} inC,
lim
n→ ∞zn1−Tnzn0 implies limn→ ∞zn−Tmzn0 ∀m∈N. 2.10
Inspired by conditions above, we introduce the following one.
d{Tn}is said to satisfy the NST∗-condition withTif for each bounded sequence{zn} inC,
lim
n→ ∞zn−Tnzn0, nlim→ ∞zn−zn10 2.11
imply that limn→ ∞zn−Tzn 0 for allT ∈ T. In particular, ifT {T}, then we simply say that{Tn}satisfies the NST∗-condition withT.
Remark 2.4. iIf {Tn}satisfies the NST-conditionIwith T, then {Tn} satisfies the NST∗ -condition withT.
iiIf{Tn}satisfies the NST-conditionII, then{Tn}satisfies the NST∗-condition with
{Tn}.
Lemma 2.5 see8, Lemma 3.2. LetCbe a nonempty closed subset of a Banach space, and let {Tn}be a family of mappings ofCinto itself which satisfies the AKTT-condition, then there exists a mappingT :C → Csuch that
Tx lim
n→ ∞Tnx ∀x∈C, 2.12
andlimn→ ∞sup{Tz−Tnz:z∈B}0for each bounded subsetBofC.
Lemma 2.6. LetCbe a nonempty closed subset of a Banach space, and let{Tn}be a family of mappings ofCinto itself which satisfies AKTT-condition and∞n1FTn/∅. LetTbe the mapping fromCinto itself defined byTz limn→ ∞Tnzfor allz ∈ Cand suppose thatFT ∞n1FTn. Then,{Tn}
satisfies the NST-condition (I) withT. This implies that{Tn}satisfies the NST∗-condition withT. Proof. Let {zn} be a bounded sequence in Csuch that limn→ ∞zn−Tnzn 0.We apply
Lemma 2.5to get
zn−Tzn≤zn−TnznTnzn−Tzn
≤zn−TnznsupTnz−Tz:z∈zn−→0.
2.13
Hence, we obtain that{Tn}satisfies the NST-conditionIwithT. This completes the proof.
Lemma 2.7. Let C be a nonempty subset of a Banach space, and let {Tn}Nn1 be a finite family of nonexpansive mappings of Cinto itself with a common fixed point. Then,{Tn} satisfies NST∗ -condition withT{T1, T2, . . . , TN}, whereTn≡TnmodN.
Proof. Let{zn}be a bounded sequence inCsuch that lim
Obviously, it is easy to see that limn→ ∞zni−zn0 for eachi1,2, . . . , N. Consequently,
zn−Tnizn≤zn−znizni−TnizniTnizni−Tnizn
≤2zn−znizni−Tnizni−→0 asn−→ ∞.
2.15
This implies that limn→ ∞zn−Tmzn0 for eachm1,2, . . . , N. This completes the proof.
Remark 2.8. There are families of mappings{Tn}andTsuch that
1{Tn}satisfies the NST∗-condition withT;
2{Tn}fails the NST-conditionIwithTand the NST-conditionII.
The following example shows that the NST∗-condition withTis strictly weaker than NST-conditionIwithTand the NST-conditionII.
Example 2.9. LetH:R2andC: 0,1×0,1. DefineT1, T2:C → Cas follows:
T1x, y x,1−y, T2x, y 1−x, y 2.16
for allx, y∈C. Hence,T1andT2are nonexpansive mappings with
FT1∩FT2
0,1×
1 2
∩
1 2
×0,1
1 2,
1 2
/
∅. 2.17
LetTnTnmod 2. ByLemma 2.7, we have{Tn}satisfies NST∗-condition with{T1, T2}.
a{Tn}fails the NST-condition Iwith T {T1, T2}. In fact, letz2n−1 1,1/2and z2n 1/2,1for alln∈N. Then,z2n−1 ∈FT2n−1 FT1andz2n∈FT2n FT2.
In particular,zn−Tnzn ≡0. Clearly,
zn−T1zn0, zn−T2zn0. 2.18
Hence,{Tn}fails the NST-conditionIwith{T1, T2}.
b{Tn} fails the NST-condition II. To this end, let z4n−3 1/4,1/4, z4n−2
1/4,3/4, z4n−1 3/4,3/4, andz4n 3/4,1/4for all n ∈ N. Then,zn1 − Tnzn ≡0. But,
zn−T1zn0, zn−T2zn0. 2.19
Hence,{Tn}fails the NST-conditionII.
Lemma 2.10see10. LetCbe a nonempty closed convex subset of a strictly convex Banach space,
SandTbe two nonexpansive mappings ofCinto itself with a common fixed point, and0< β <1. Let
Ube a mapping defined by
UTβI 1−βS, 2.20
whereIis the identity mapping. Then,Uis a nonexpansive mapping fromCinto itself andFU
Lemma 2.11. LetCbe a nonempty closed convex subset of a strictly convex Banach space. Let{Tn} andTbe two families of nonexpansive mappings fromCinto itself such that∞n1FTn FT/∅, and suppose that{Tn} satisfies the NST∗-condition withT. Let {Un} be a family of nonexpansive mappings fromCinto itself defined by
UnTnβnI1−βnTn 2.21
for alln ∈N, whereI is the identity mapping, and{βn}is a sequence ina,1for somea ∈0,1. Then,{Un}satisfies the NST∗-condition withT.
Proof. ByLemma 2.10, we haveFUn FTnfor alln∈Nand so,
∞
n1
FUnFT/∅. 2.22
Let{zn}be a bounded sequence inCsuch that
lim
n→ ∞zn−Unzn0, nlim→ ∞zn1−zn0. 2.23
Since
zn−Tnzn≤zn−UnznTn
βnzn1−βnTnzn−Tnzn ≤zn−Unzn1−βnzn−Tnzn
≤zn−Unzn 1−azn−Tnzn,
2.24
it follows that
zn−Tnzn≤ 1
azn−Unzn−→0. 2.25
Since{Tn}satisfies the NST∗-condition withT, we have
lim
n→ ∞zn−Tzn0 ∀T ∈ T. 2.26
Hence, we obtain that{Un}satisfies the NST∗-condition withT. This completes the proof.
3. Weak convergence theorems
Lemma 3.1. LetCbe a nonempty closed convex subset of a real Hilbert spaceH. Let{Tn}be a family of nonexpansive mappings fromCinto itself with a common fixed point. Let{xn}be a sequence inC defined byx0∈Cand
xnαnxn−1
1−αnTnxn 3.1
for alln∈N, where{αn}is a sequence in0,1. Then,
ilimn→ ∞xn−pexists for eachp∈∞n1FTn;
Proof. Observe that ifCis a nonempty closed convex subset of a real Hilbert space Hand
T : C → C is a nonexpansive mapping, then for everyu ∈ C, α ∈ 0,1, the mapping
SSα,T:C → Cdefined by
Sxαu 1−αTx x∈C 3.2
is a1−α-contraction, that is, for allx, y∈C,
Sx−Sy 1−αTx−Ty ≤1−αx−y. 3.3
Consequently,Shas a unique fixed pointx∗∈C. Thus, there exists a uniquex∗∈C, that is,
x∗αu 1−αTx∗. 3.4
This implies that the implicit iteration scheme 3.1 is well defined. To seei, we letp ∈ ∞
n1FTn. It follows from2.2that
xn−p2 α
nxn−1−p
1−αnTnxn−p2
αnxn−1−p2
1−αnTnxn−p2−αn1−αnxn−1−Tnxn2
≤αnxn−1−p2
1−αnxn−p2−αn1−αnxn−1−Tnxn2.
3.5
Sinceαn>0, we have
xn−p2≤x
n−1−p2−
1−αnxn−1−Tnxn2. 3.6
In particular,
xn−p≤xn−1−p. 3.7
So, limn→ ∞xn−pexists. Furthermore, from3.6, we have
1−αnxn−1−Tnxn2≤xn−1−p2−xn−p2. 3.8
Summing from 1 tomand tending to infinity form, we haveii. This completes the proof.
Theorem 3.2. LetCbe a nonempty closed convex subset of a real Hilbert space H. Let {Tn}and T be two families of nonexpansive mappings fromCinto itself such that∞n1FTn FT/∅, and suppose that{Tn}satisfies the NST∗-condition withT. Then, the sequence{xn}inCdefined by
3.1, where{αn}is a sequence in0, bfor someb∈0,1, converges weakly tow∈FT. Moreover,
limn→ ∞PFTxnw.
Proof. It follows fromLemma 3.1ithat{xn}is bounded. ByLemma 3.1iiandαn ≤ b, we have
∞
n1
xn−1−Tnxn2 <∞.
It follows that limn→ ∞xn−1−Tnxn0.From3.1, we immediately have
lim
n→ ∞xn−Tnxnnlim→ ∞αnxn−1−Tnxn0, 3.10
and so,
lim
n→ ∞xn−xn−10. 3.11
Since{Tn}satisfies the NST∗-condition withT, we have
lim
n→ ∞xn−Txn0 ∀T ∈ T. 3.12
We now extract a subsequence{xni}of{xn}such thatxni w. So, by the demiclosedness
principle,w ∈FT. To prove thatxn w, suppose that there exists another subsequence {xmj}of{xn}such thatxmj w/w. So, we havew ∈FT. It follows fromLemma 3.1i
and Opial’s condition that
lim
n→ ∞xn−wilim→ ∞xni−w<ilim→ ∞xni−w
lim
j→ ∞xmj−w
< lim
j→ ∞xmj−w
lim
n→ ∞xn−w,
3.13
arriving at a contradiction. Hence,xn w ∈ FT.Finally, we prove that limn→ ∞zn w,
wherezn PFTxn for eachn ∈ N. By3.7andLemma 2.3, there isw0 ∈ FTsuch that
zn → w0.FromznPFTxnandw∈FT, we have
xn−zn, zn−w≥0 ∀n∈N. 3.14
It follows fromzn → w0andxn wthat
w−w0, w0−w≥0, 3.15
and thenw0w.This completes the proof.
UsingTheorem 3.2andLemma 2.7, we have the following result.
Corollary 3.3see2, Theorem 2. LetCbe a nonempty closed convex subset of a real Hilbert spaceH,and let{Tn}Nn1be a finite family of nonexpansive mappings ofCinto itself with a common fixed point. Then, the sequence{xn}inCdefined by1.3, where{αn}is a sequence in0, bfor some
b∈0,1, converges weakly towlimn→ ∞PN
n1FTnxn.
In the presence of the stronger condition than NST∗-condition withT, we are able to weaken the restriction on{αn}.
Theorem 3.4. Let Cbe a nonempty closed convex subset of a real Hilbert space H, and let{Tn} be a family of nonexpansive mappings of C into itself which satisfies the AKTT-condition and
∞
n1FTn/∅. LetTbe the mapping fromCinto itself defined byTzlimn→ ∞Tnzfor allz∈C,and
Proof. By Lemmas2.2and3.1iiand n∞11−αn ∞, we have
lim inf
n→ ∞ xn−1−Tnxn0, 3.16
and hence,
lim inf
n→ ∞ xn−Tnxnlim infn→ ∞ αnxn−1−Tnxn0. 3.17
Next, we prove that the limit limn→ ∞xn−Tnxnexists. Since{xn}is bounded, it follows from
AKTT-condition that
∞
n1
supTnz−Tn−1z:z∈xn<∞. 3.18
Notice that
xn−xn−1
1−αnxn−1−Tnxn
≤1−αnxn−1−Tn−1xn−1Tn−1xn−1−Tn−1xnTn−1xn−Tnxn
≤1−αnxn−1−Tn−1xn−1
1−αnxn−1−xn
1−αnsupTnz−Tn−1z:z∈xn,
3.19
so we have
αnxn−xn−1≤
1−αnxn−1−Tn−1xn−1
1−αnsupTnz−Tn−1z:z∈xn.
3.20
It follows that
xn−Tnxn αn
1−αn
xn−xn−1
≤xn−1−Tn−1xn−1supTnz−Tn−1z:z∈xn.
3.21
ByLemma 2.1and3.18, we have limn→ ∞xn−Tnxnexists. Thus, we have
lim
n→ ∞xn−Tnxn0. 3.22
From the definition ofT, we haveT is nonexpansive. ByLemma 2.6, we have{Tn}satisfies the NST∗-condition withT. As in the proof ofTheorem 3.2,{xn}converges weakly to w
limn→ ∞PFTxn.
Remark 3.5. Since the NST∗-condition is implied by the AKTT-condition,Theorem 3.4still holds under the same condition of{αn}as inTheorem 3.2.
Corollary 3.6. LetCbe a nonempty closed convex subset of a real Hilbert spaceH. Let{αn}be a sequence in0,1with ∞n11−αn ∞. Let{βkn}be a family of positive real numbers with indices
n, k∈Nwithk≤nsuch that
i nk1βkn1for everyn∈N;
iilimn→ ∞βkn>0for everyk∈N;
iii ∞n1 nk1|βkn1−βkn|<∞.
Let {Sk} be a family of nonexpansive mappings from C into itself with a common fixed point. Then, the sequence {xn} in C defined by 3.1, where Tn ≡ nk1βknSk, converges weakly to
wlimn→ ∞P∞
k1FSkxn.
4. Strong convergence theorems
We next use the hybrid method from mathematical programming to obtain several strong convergence theorems.
Theorem 4.1. LetCbe a nonempty closed convex subset of a real Hilbert spaceH. Let{Tn}andT be two families of nonexpansive mappings fromCinto itself such that∞n1FTn FT/∅,and suppose that{Tn}satisfies the NST∗-condition withT. Let{xn}be a sequence inCdefined as follows:
x0∈Cis arbitrary,
ynαnxn1−αnTnyn,
Cnz∈C:yn−z≤xn−z,
Qnz∈C:xn−z, x0−xn≥0,
xn1PCn∩Qnx0, n0,1,2, . . . ,
4.1
where{αn}is a sequence in0, bfor someb∈0,1. Then,{xn}converges strongly toPFTx0. Proof. We first prove thatCn andQn are closed and convex for eachn ∈N∪ {0}. From the definitions ofCnandQn, it is obvious thatCnis closed andQnis closed and convex for each
n∈N∪ {0}. We prove thatCnis convex. Sinceyn−z ≤ xn−zis equivalent to
yn−xn2
2yn−xn, xn−z≤0, 4.2
by2.1it follows thatCnis convex. Next, we show that
FT⊂Cn ∀n∈N∪ {0}. 4.3
Letp∈FTandn∈N∪ {0}.Since
yn−pαnxn
1−αnTnyn−p ≤αnxn−p1−αnTnyn−p ≤αnxn−p1−αnyn−p,
it follows that
yn−p≤xn−p, 4.5
and hence,p∈Cn. Therefore, we obtain4.3. Now, we show that
FT⊂Qn ∀n∈N∪ {0}. 4.6
We prove this by induction. Forn0, we haveFT⊂CQ0. Suppose thatFT⊂Qn. Then, ∅/FT⊂Cn∩Qnand there exists a unique elementxn1 ∈Cn∩Qnsuch thatxn1PCn∩Qnx0.
Then,
xn1−z, x0−xn1
≥0 4.7
for eachz∈Cn∩Qn. In particular,
xn1−p, x0−xn1
≥0 4.8
for eachp∈FT. It follows thatFT⊂Qn1,and hence4.6holds. Therefore,
FT⊂Cn∩Qn ∀n∈N∪ {0}. 4.9
This implies that{xn}is well defined. It follows from the definition ofQn thatxn PQnx0,
that is,
xn−x0≤z−x0 ∀z∈Qn and all n∈N∪ {0}. 4.10
In particular,
xn−x0≤z−x0 ∀z∈FTand all n∈N∪ {0}. 4.11
On the other hand, fromxn1PCn∩Qnx0∈Qn, we have
xn−x0≤xn1−x0 ∀n∈N∪ {0}. 4.12
Therefore,{xn−x0}is nondecreasing and bounded. So, limn→ ∞xn−x0exists. This implies
that{xn}is bounded. Sincexn1 PCn∩Qnx0∈Qn, we have
xn−xn1, x0−xn≥0. 4.13
It follows from2.1that
xn1−xn2x
n1−x0
−xn−x02
xn1−x02−xn−x02−2xn1−xn, xn−x0 ≤xn1−x02−xn−x02
4.14
for alln∈N∪ {0}.This implies that
lim
Sincexn1∈Cn, we have
yn−xn≤yn−xn1xn−xn1
≤2xn−xn1−→0.
4.16
It follows fromαn≤b <1 that
xn−Tnxn≤xn−TnynTnyn−Tnxn
≤xn−Tnynyn−xn
1
1−αn
yn−xnyn−xn
≤ 1
1−byn−xnyn−xn−→0.
4.17
Since{Tn}satisfies the NST∗-condition withT, we have
lim
n→ ∞xn−Txn0 ∀T ∈ T. 4.18
Finally, we show thatxn → w, wherew PFTx0. Since{xn} is bounded, let{xnk} be a
subsequence of{xn}such thatxnk w. SinceI−T is demiclosed and by using4.18, we
havew∈FT. By4.11, we have
xn−x0≤w−x0. 4.19
It follows fromwPFTx0and the lower semicontinuity of the norm that
w−x0≤w−x0≤lim inf
k→ ∞ xnk−x0≤lim supk→ ∞ xnk −x0≤w−x0. 4.20
Thus, we obtain that limk→ ∞xnk−x0w−x0w−x0. Using the Kadec-Klee property ofH, we obtain that limk→ ∞xnk w w.Since{xnk}is an arbitrary subsequence of{xn},
we can conclude that the whole sequence{xn}converges strongly toPFTx0.
UsingTheorem 4.1and Lemmas2.7and2.11, we have the following result.
Corollary 4.2see3, Theorem 2.4. LetCbe a nonempty closed convex subset of a real Hilbert spaceH,and let{Tn}Nn1be a finite family of nonexpansive mappings ofCinto itself with a common fixed point. Then, the sequence{xn}inCdefined by1.4, where{αn}is a sequence in0, afor some
a∈0,1,and{βn}is a sequence inb,1for someb∈0,1, converges strongly toPN
n1FTnx0. 5. Applications
5.1. Equilibrium problems
LetCbe a nonempty closed convex subset of a real Hilbert spaceH. Letfbe a bifunction of
C×CintoR, whereRis the set of real numbers. The equilibrium problem forf:C×C → R is to findx∈Csuch that
The set of solutions of 5.1 is denoted by EPf. Numerous problems in physics, optimization, and economics are reduced to find a solution of 5.1. Some methods have been proposed to solve the equilibrium problem11–17. In 2005, Combettes and Hirstoaga
12introduced an iterative scheme of finding the best approximation to the initial data when EPfis nonempty, and they also proved a strong convergence theorem.
For solving the equilibrium problem, let us assume that the bifunctionf satisfies the following conditionssee11.
A1fx, x 0 for allx∈C;
A2fis monotone, that is,fx, y fy, x≤0 for anyx, y∈C;
A3fis upper-hemicontinuous, that is, for eachx, y, z∈C,
lim sup
t→0 f
tz 1−tx, y≤fx, y; 5.2
A4fx,·is convex and lower semicontinuous for eachx∈C.
The following lemma is shown in11, Corollary 1and12, Lemma 2.12.
Lemma 5.1. LetCbe a nonempty closed convex subset of a real Hilbert spaceH, letfbe a bifunction fromC×CintoRsatisfies (A1)–(A4), and letr >0andx∈H. Then, there exists a uniquex∗∈C such that
fx∗, y 1
r
y−x∗, x∗−x≥0 ∀y∈C. 5.3
Moreover, letTr be a mapping ofHintoCdefined by
Trx x∗ ∀x∈H. 5.4
Then, the following conditions hold:
iTr is firmly nonexpansive, that is, for anyx, y∈H,
Trx−Try2≤ x−y2−T
rx−x−Try−y2; 5.5
iiFTr EPf;
iiiEPfis closed and convex.
Lemma 5.2. Let C be a nonempty closed convex subset of a real Hilbert space H. Let S be a nonexpansive mapping of Cinto H, and letT be a firmly nonexpansive mapping fromH into C such thatFS∩FT/∅. Then,STis a nonexpansive mapping fromHinto itself and
FST FS∩FT. 5.6
Proof. SinceTis firmly nonexpansive, there exists a nonexpansive mappingUsuch thatT
1/2IUandFU FT. As in the proof ofLemma 2.10, the conclusion holds.
Theorem 5.3. Let C be a nonempty closed convex subset of a real Hilbert space H. Let f be a bifunction fromC×CintoRsatisfying (A1)–(A4), and letSbe a nonexpansive mapping ofCintoH such thatFS∩EPf/∅. Let{xn}and{un}be two sequences generated byx0∈Hand
fun, y r1 n
y−un, un−xn≥0 ∀y∈C,
xnαnxn−1
1−αnSun
5.7
for alln ∈ N, where{αn}is a sequence in0,1with ∞n11−αn ∞,and {rn}is a sequence in0,∞withlim infn→ ∞rn > 0and ∞n1|rn1 −rn| < ∞. Then,{xn}converges weakly tow ∈ FS∩EPf. Moreover,limn→ ∞PFS∩EPfxnw.
Proof. It is noted that the iteration scheme is well defined. As in the proof of14, Theorem 16, it follows from lim infn→ ∞rn>0 and ∞n1|rn1−rn|<∞that
∞
n1
supTrn1z−Trnz:z∈B
<∞ 5.8
for any bounded subsetBofH. Moreover, byLemma 2.5, the mappingT defined by
Tx lim
n→ ∞Trnx ∀x∈H 5.9
satisfies
FT ∞
n1
FTrnEPf. 5.10
It is easy to see thatT is a firmly nonexpansive mapping ofHintoC. WriteTn ≡STrn then,
byLemma 5.2, we haveTnis a nonexpansive mapping fromHinto itself, and
FTnFSTrnFS∩FTrnFS∩EPf FST 5.11
for alln∈Nand so,
∞
n1
FTn FST FS∩EPf. 5.12
SinceSis nonexpansive,5.8and5.9, we have
∞
n1
supTn1z−Tnz:z∈B<∞ 5.13
for any bounded subsetBofH,and
STxS
lim
n→ ∞Trnx
lim
n→ ∞STrnxnlim→ ∞Tnx ∀x∈H. 5.14
Similarly, we have the following strong convergence theorem. We safely suppress the proof.
Theorem 5.4. Let C be a nonempty closed convex subset of a real Hilbert space H. Let f be a bifunction fromC×CintoRsatisfying (A1)–(A4), and letSbe a nonexpansive mapping ofCintoH such thatFS∩EPf/∅. Let{xn}and{un}be two sequences generated byx0∈Hand
fun, yr1 n
y−un, un−yn≥0 ∀y∈C,
ynαnxn−1
1−αnSun,
Cnz∈C:yn−z≤xn−z,
Qnz∈C:xn−z, x0−xn≥0,
xn1PCn∩Qnx0, n0,1,2, . . . ,
5.15
where {αn} is a sequence in 0, a for some a ∈ 0,1, and {rn} is a sequence in 0,∞ with
lim infn→ ∞rn>0and n∞1|rn1−rn|<∞. Then,{xn}converges strongly toPFS∩EPfx0.
5.2. Convergence theorem for monotone mappings
LetHbe a real Hilbert space, andCbe a nonempty closed convex subset ofH. LetA:C → H be a mapping. The classical variational inequality is to findx∈Csuch that
Ax, y−x ≥0 ∀y∈C. 5.16
The set of solutions of classical variational inequality is denoted by VIPC, A. The variational inequality has been extensively studied in the literaturessee7,18–23and the references therein. We recall that a mappingA:C → His said to be
amonotone if
Au−Av, u−v ≥0 ∀u, v∈C; 5.17
bα-inverse-strongly monotone if there exists a constantα >0 such that
Au−Av, u−v ≥αAu−Av2 ∀u, v∈C; 5.18
cr-strongly monotone if there exists a constantr >0 such that
Au−Av, u−v ≥ru−v2 ∀u, v∈C; 5.19
drelaxedγ, r-cocoercive if there exist constantsγ,r >0 such that
Au−Av, u−v ≥ −γAu−Av2ru−v2 ∀u, v∈C; 5.20
eμ-Lipschitzian if there exists a constantμ >0 such that
Remark 5.5. 1Everyα-inverse-strongly monotone mapping is monotone and 1/α -Lipschit-zian.
2Everyr-strongly monotone is monotone.
3 Every relaxed γ, r-cocoercive and μ-Lipschitzian mapping with γμ2 ≤ r is
monotone.
Lemma 5.6. Let C be a nonempty closed convex subset of a real Hilbert space H. Let A be a continuous monotone mapping ofCintoH. Define a bifunctionf :C×C → Ras follows:
fx, y Ax, y−x ∀x, y∈C. 5.22
Then,
i[14, Lemma 19]fsatisfies (A1)–(A4) and VIPC, A EPf;
ii[14, Lemma 20] Ifx∈H, u∈C,andr >0, then
fu, y 1ry−u, u−x ≥0 ∀y∈C⇐⇒uPCx−rAu. 5.23
UsingTheorem 5.3andLemma 5.6, we haveTheorem 5.7.
Theorem 5.7. Let C be a nonempty closed convex subset of a real Hilbert space H. Let A be a continuous monotone mapping ofC,and letS be a nonexpansive mapping of Cinto H such that
FS∩VIPC, A/∅. Let{xn}and{un}be sequences generated byx0 ∈Hand
unPCxn−rnAun,
xnαnxn−1
1−αnSun
5.24
for alln ∈ N, where{αn}is a sequence in0,1with ∞n11−αn ∞,and {rn}is a sequence
in0,∞withlim infn→ ∞rn > 0and ∞n1|rn1 −rn| < ∞. Then,{xn}converges weakly tow ∈
FS∩VIPC, A. Moreover,limn→ ∞PFS∩VIPC,Axnw.
UsingTheorem 5.4andLemma 5.6, we also haveTheorem 5.8.
Theorem 5.8. Let C be a nonempty closed convex subset of a real Hilbert space H. Let A be a continuous monotone mapping ofC,and letS be a nonexpansive mapping of Cinto H such that
FS∩VIPC, A/∅. Let{xn}and{un}be sequences generated byx0 ∈Hand
unPCyn−rnAun,
ynαnxn−1
1−αnSun,
Cnz∈C:yn−z≤xn−z,
Qnz∈C:xn−z, x0−xn≥0,
xn1PCn∩Qnx0, n0,1,2, . . . ,
5.25
where {αn} is a sequence in 0, a for some a ∈ 0,1, and {rn} is a sequence in 0,∞ with
Remark 5.9. 1 By Remark 5.5, we obtain a strong convergence theorem for α -inverse-strongly monotone mappings,r-strongly monotone and continuous mappings and relaxed
γ, r-cocoercive andμ-Lipschitzian mappings withγμ2≤r.
2Some weak and strong convergence theorems for monotone Lipschitzian mappings were established by several authors 7, 18–23. However, there is a monotone continuous mapping which is not Lipschitziansee14, Remark 23. Therefore, Theorems5.7and5.8
provide a new convergence theorem for a wider class of mappings.
Acknowledgments
The authors would like to thank the referee for comments which improve the manuscript. Satit Saejung was supported by the Commission on Higher Education and the Thailand Research Fund under Grant MRG5180146.
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