Introduction
•The invention of the transistor was the beginning of a technological revolution that is still continuing.
•All of the complex electronic devices and systems today are an outgrowth of early developments in semiconductor transistors.
•Two basic types of transistors are the bipolar junction transistor (BJT), and the field-effect transistor (FET).
•The BJT is used in two broad areas
•as a linear amplifier to boost or amplify an electrical signal,
•as an electronic switch.
•The term bipolar refers to the use of both holes and electrons as current carriers in the transistor structure.
BJT Structure
The BJT has three regions called the emitter, base, and collector. Between the regions are two pn junctions as indicated. B (base) C (collector) n p n Base-Collecto r junction Base-Emitter junction B 3 C p n p E (emitter) npn E pnp
The base is a thin lightly doped region compared to the
heavily doped emitter and
moderately doped collector regions.
BJT Structure
BJT Operation
In normal operation, the base-emitter (BE) is forward- biased and the base-collector (BC) is reverse-biased.
npn – + – + BC reverse- biased BE forward-biased
For the npn type shown, the collector is more positive than the base, which is more positive than the emitter.
6
+
C n
–
E n
B p
–
+
BJT Operation
In normal operation, the base-emitter (BE) is forward- biased and the base-collector (BC) is reverse-biased.
For the pnp type, the voltages are reversed to maintain the forward-reverse bias. – + + – BC reverse- biased + – BE forward-biased – + pnp 7
C p
E p
B n
BJT Operation (npn)
Direction of electron flow:
8
IE = IC + IB
B
C
E
BJT Operation (npn)
•The heavily doped n-type emitter region has a very high density of conduction-band (free) electrons.
•These free electrons easily diffuse through the forward- biased BE junction into the lightly doped and very thin p-type base region.
•The lightly doped p-type base has a low density of holes, which are the majority carriers.
•A small percentage of the total number of free electrons injected into the base region recombine with holes and move as valence electrons through the base region, forming small base electron current.
•When the electrons that have recombined with holes as valence electrons leave the crystalline structure of the base, they become free electrons in the metallic base lead and produce the external base current.
BJT Operation (npn)
10
•Most of the free electrons that have entered the base do not recombine with holes because the base is very thin (no enough holes).
•As the free electrons move toward the reverse-biased BC junction, they are swept across into the collector region by the attraction of the positive collector supply voltage.
•The free electrons move through the collector region, into the external circuit forming collector current, and then return into the emitter region along with the base current (IE = IC + IB).
•The emitter current is slightly greater than the collector current because of the small base current that splits off from the total current injected into the base region from the emitter (IE = IC +
BJT Currents
11
IE I
E
I
B
I
C IC
I B n p n p n p – +
The direction of conventional current is in the direction of the arrow on the emitter terminal.
The emitter current is the sum of the collector current and the small base current. That is, IE = IC + IB.
+ – – + I C I B + – +
IE IE
DC Bias Circuits (Common Emitter)
DC Beta (βDC) and DC Alpha (αDC)
13
The dc current gain of a transistor is the ratio of the dc collector current (IC) to the dc base current (IB) and is designated dc beta (βDC).
Typical values of βDC range from less than 20 to 200 or higher.
The ratio of the dc collector current (IC) to the dc emitter current (IE) is the dc
alpha (αDC).
The alpha is a less-used parameter than beta in transistor circuits.
Typically, values of α
DC range from 0.95 to 0.99 or greater, but αDC is
always less than 1. The reason is that I
C is always slightly less than IE by the amount of IB
(I
DC Beta (βDC) and DC Alpha (αDC)
14
Example:
If IE = 100 mA and IB = 1 mA, then
IC = IE – IB = 100 – 1 = 99 mA and
Current & Voltage Analysis
15
IB: dc base current
IE: dc emitter current
IC: dc collector current
KCL: IE = IC + IB
VBE: dc voltage at base with respect to emitter
VCB: dc voltage at collector with respect to base
VCE: dc voltage at collector with respect
to emitter KVL: VCE = VCB + VBE
VBB forward-biases the BE junction, and VCC reverse-biases the BC junction. When BE is forward-biased, it is like a forward-biased diode and has a
Current & Voltage Analysis
16
VBE = 0.7 V
VCE = VCC – IC RC
VCB = VCE – VBE
VRB = VBB – VBE
VRB = IB RB
IB = (VBB – VBE ) / RB
VRC = IC RC
IB RB = VBB – VBE
VCE = VCC – VRC
> 0
Operation of BJTs
BJT will operates in one of following four regions:
1. Cutoff region (digital circuit/switching)
•
When I
B=0, BEJ is RB and BCJ is RB
2. Linear / Active region (Amplifier)
•
BEJ is FB and BCJ is RB
3. Saturation region (digital circuit/switching)
•
BEJ is FB and BCJ is also FB
4. Breakdown region (never recommended)
Linear / Active Region
Cut off Region
Saturation Region
The collector characteristic curve shows the relationship of the three transistor currents.
BJT Characteristics
22
I
C Breakdown
The curve shown is for a fixed base current. The first region is
CE
the saturation region. As V
is
B
C
A
0 0.7 V V
CE(max) VCE Saturation region Active region region
increased, IC increases until B.
Then it flattens in the region between points B and C, which is the active region.
After C, is the breakdown region.
BJT Characteristics
Consider point A on the characteristic curve:
•Assume that VBB is set to produce a certain value of IB and VCC is zero.
•For this condition, both the BE junction and the BC junction are forward- biased, because the base is at approximately 0.7 V while the emitter and the collector are at 0 V.
•IB is through the BE junction, because of the low impedance path to ground and, therefore, IC is zero.
•When both junctions are forward-biased, the transistor is in the saturation region of its operation.
Consider the portion of the curve between points A and B:
•Saturation is the state of a BJT in which IC has reached a maximum and is independent of IB (IC ≠ βDC IB). IB is constant, but IC is increasing.
•When VCC is increased, VCE increases as IC increases.
•IC increases as VCC is increased because VCE remains less than 0.7 V due to the forward-biased BC junction.
VCE = VCB + VBE = negative + 0.7 < 0.7 and IC = (VCC – VCE) / RC
BJT Characteristics
Consider the portion of the curve between points B and C:
•Ideally, when VCE exceeds 0.7 V, the BC junction becomes reverse-biased and the transistor goes into the active, or linear, region of its operation.
•Once the BC junction is reverse-biased, IC levels off and remains
essentially constant for a given value of IB as VCE continues to increase.
•Actually, IC increases very slightly as VCE increases due to widening of the BC depletion region.
•This results in fewer holes for recombination in the base region which effectively causes a slight increase in βDC.
•For this portion of the characteristic curve, the value of IC is determined only by the relationship IC = βDC IB.
Consider the portion of the curve to the right of point C:
•When VCE reaches a sufficiently high voltage, the reverse-biased BC junction goes into breakdown; and IC increases rapidly.
•A transistor should never be operated in this breakdown region.
BJT Characteristics
It can be read from the curves. The value of βDC is nearly the same wherever it is read.
BJT Characteristics
•A family of collector characteristic curves is produced when
IC versus VCE is plotted for several values of IB.
•When IB = 0, the transistor is in the cutoff region although there is a very small collector leakage current.
•Cutoff is the non-conducting state of a transistor.
•The amount of collector leakage current for IB = 0 is exaggerated on the graph for illustration.
Cutoff
In a BJT, cutoff is the condition in which there is no base current (IB = 0), which results in only an extremely small leakage current (ICEO ≈ 0) in the collector circuit (due mainly to thermally produced carriers). For practical work, this current is assumed to be zero.
In cutoff, neither the BE junction, nor the BC junction are forward- biased.
The subscript CEO represents
collector-to-emitter with the base open.
Saturation
In a BJT, saturation is the condition in which there is maximum IC. The saturation current is determined by the external circuit (VCC and RC in this case) because the CE voltage is minimum (VCE ≈ 0.2 V). VCE = VCC –IC RC
In saturation, an increase of IB has no effect on the collector circuit
and C DC B
the relation I = β I is no longer valid.
Saturation
31
•When the BE junction becomes forward-biased and IB is increased, IC also increases (IC = βDC IB) and VCE
decreases as a result of more drop across R
C, VCE = VCC –
IC RC
•When VCE reaches its saturation value, VCE(sat), the BC junction becomes forward-biased and IC can increase no further, even with a continued increase in IB.
DC Load Line
32
the transistor. It is drawn by connecting the
saturation
The DC load line represents the circuit that is external to
and cutoff points.
The transistor characteristic curves are shown superimposed on the load line.
The DC Operating Point
For a transistor circuit to amplify it must be properly biased with dc voltages.
The dc operating point between saturation and cutoff is called the Q-point.
The goal is to set the Q-point such that that it does not go into saturation or cutoff when an a ac signal is applied.
DC Load Line
35
What is the saturation current for the circuit? Assume VCE = 0.2 V in
saturation.
+
+
VCC
– 15
V V BB 3 V – R C R B
βDC = 200 220 kΩ 3.3 kΩ C(sat) I = V CC
RC 3.3 kΩ − 0.2 V
= 15 V − 0.2 V = 4.48 mA
B
Is the transistor saturated? I = 3.0 V − 0.7 V = 10.45 μA
220 kΩ
IC = β IB = 200 (10.45 μA) = 2.09 mA
(repeated)
BJT As An Amplifier
A BJT amplifies AC signals by converting some of the DC power from the power supplies to AC signal power.
An ac signal at the input is superimposed in the dc bias by
capacitive coupling.
The output ac signal is inverted and rides on a dc level of VCE.
BJT As Switch
A BJT can be used as a switching device in digital circuits to turn on or off current to a load. As a switch, the transistor is normally in either cutoff (load is OFF) or saturation (load is ON).
IC
V
CE
IB = 0 Cutoff
0 V
CE(sat) VCC
I
C(sat)
Saturation
In cutoff, the transistor
looks like an open switch.
In saturation, the transistor
looks like a closed switch.
R B 0 V R C I C =
0 +V CC R C C E +V CC
IB = 0 –
+ R
B
A Sample of Common Transistor Packages
Voltage-Divider Bias
• Voltage-divider bias is the most widely used type of bias circuit. Up to this point a separate dc source, VBB, was used to bias the base-emitter junction because it could be varied independently of VCC and it helped to illustrate transistor operation.
• A more practical bias method is to use VCC as the single bias source. To simplify the schematic, the battery symbol is omitted and replaced by a line termination circle with a voltage indicator (VCC) as shown.