Applied Mathematics Letters 22 (2009) 1803–1809
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Applied Mathematics Letters
journal homepage:www.elsevier.com/locate/aml
On a result of Flett for Cesáro matrices
Dansheng Yu
Department of Mathematics, Hangzhou Normal University, Hangzhou Zhejiang 310036, China
a r t i c l e i n f o
Article history:
Received 21 April 2008
Received in revised form 17 June 2009 Accepted 17 June 2009
Keywords:
Cesáro matrix Conservative matrix Absolute summability
a b s t r a c t
Let snbe the partial sums of the seriesP∞
n=0an.We consider the sufficient conditions for a matrix T=(tnk)such that
∞
X
n=1
αn|sn−sn−1|k< ∞
implies
∞
X
n=1
βn|tn−tn−1|s< ∞
where{αn}and{βn}are two given positive sequences and k,s > 0, and{tn}is the T - transformation of{sn}.Our results extend the related results of Flett [T.M. Flett, On an extension of absolute summability and some theorems of Littlewood and Paley, Proc.
London Math. Soc. 7 (1957) 113–141] and Savas and Sevli [E. Savaş, H. Sevli, On extension of a result of Flett for Cesáro matrices, Appl. Math. Lett. 20 (2007) 476–478].
© 2009 Elsevier Ltd. All rights reserved.
Let snbe the partial sums of the series
P
∞n=0an. The Cesáro means of order
α
of the seriesP
∞n=0anare defined by
σ
nα:=
1Aαn
n
X
j=0
Aα−n−j1sj
,
n=
0,
1, . . . ,
whereAαn
:=
0(
n+ α +
1)
0
(α +
1)
0(
n+
1) ,
n=
0,
1, . . . .
Let
(
C, α)
, the Cesáro matrix of orderα
, be the lower triangular matrix Aα−n−ν1/
Aαn.
Flett [1] introduced the concept of absolute summability of order k. A seriesP
∞n=0anis said to be summable
|
C, α|
k,
k≥
1, α > −
1, if∞
X
n=1
nk−1
σ
nα−1− σ
nαk
< ∞.
Das [2] defined a matrix T
:=
tnjto be absolutely kth-power conservative for k
≥
1, denoted by T∈
B(
Ak)
, that is, if{
sn}
satisfies∞
X
n=1
nk−1
|
sn−
sn−1|
k< ∞,
(1)E-mail address:danshengyu@yahoo.com.cn.
0893-9659/$ – see front matter©2009 Elsevier Ltd. All rights reserved.
doi:10.1016/j.aml.2009.06.023
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then
∞
X
n=1
nk−1
|
tn−
tn−1|
k< ∞,
(2)where tn
=
n
X
j=0
tnjsj
.
Flett [1] established the following inclusion theorem for
|
C, α|
k. If the seriesP
∞n=0an is summable
|
C, α|
k, it is also summable|
C, α|
rfor each r≥
k≥
1, α > −
1, β > α +
1k−
1r. Especially, a series
P
∞n=0anwhich is
|
C, α|
ksummable is also|
C, β|
ksummable for k≥
1, β > α > −
1.
If one sets
α =
0, from the above inclusion result, we have Theorem A. Let k≥
1, then(
C, β) ∈
B(
Ak) (
k≥
1)
forβ ≥
0.
Recently, Savaş and Şevli [3] claimed thatTheorem Aholds for all
β > −
1.
However, in their proof (see P. 477, [3]), they said that Applying Hölder’s inequality, we have∞
X
n=1
1 n
τ
nβk
=
∞
X
n=1
1 n
1 Aβn
n
X
v=1
Aβ−n−v1
v
avk
≤
∞
X
n=1
1 n
Aβn k nX
v=1
Aβ−n−v1
v
k|
av|
kn
X
v=1
Aβ−n−v1
!
k−1.
(3)Unfortunately,(3)is not true when
−
1< β <
0. In fact, take a1=
1,
a2=
a3= · · · =
0, then the middle term of(3)equals∞
X
n=1
1 n
Aβ−n−11 Aβn
k
>
Aβ−1 0
Aβ1
!
k=
1(β +
1)
k,
while the right-hand side of(3)is∞
X
n=1
Aβ−n−11 n
Aβn k Aβn−
Aβ−n 1k−1<
Aβ−1 0
Aβ1 kAβ1
−
Aβ−1 1 k−1=
1(β +
1)
k,
where we used the following facts:Aβ−n−11
<
0,
Aβ−n 1<
0 and Aβn>
0,
n≥
2, −
1< β <
0.
Since(3)plays an essential role, their proof of the result is not true. The correctness ofTheorem Afor
−
1< β <
0 need to be further verified. In spite of this, Savaş and Şevli [3] have given a simple proof ofTheorem Aby adopting some new ideas.Motivated byTheorem A, a natural problem is that what are the sufficient conditions for T such that
∞
X
n=1
α
n|
sn−
sn−1|
k< ∞
(4)implies that
∞
X
n=1
β
n|
tn−
tn−1|
s< ∞
(5)where
{ α
n}
and{ β
n}
are two given positive sequences and k,
s>
0?The object of this note is to answer the above problem by establishing the followingTheorem 1. We also prove few corollaries(1)–(4)on absolute Cesáro summability andCorollary 5on absolute Riesz summability.
Theorem 1. Let
{ α
n}
and{ β
n}
be positive sequences and k>
0,
s≥
1. Assume that T:=
tnjis a lower triangular matrix satisfying
P
nj=0tnj
=
1 for any n≥
0. If∞
X
n=i
β
n nX
v=1
e
tnvv
!
s−1e
tni=
O i1−kα
i,
i=
1,
2, . . . ,
(6)and
(
i|
si−
si−1| )
s−k=
O(
1) ,
(7)where
e
tni:=
n
X
j=i
tnj
−
n−1
X
j=i
tn−1,j
,
0≤
i≤
n−
1,
tnn
,
i=
n,
then(4)implies(5).
Proof. Since (set s−1
:=
0)tn
=
n
X
j=0
tnjsj
=
n
X
j=0
tnj
j
X
i=0
(
si−
si−1)
!
=
n
X
i=0
(
si−
si−1) X
nj=i
tnj
! ,
thentn
−
tn−1=
n
X
i=0
(
si−
si−1)
n
X
j=i
tnj
!
−
n−1
X
i=0
(
si−
si−1)
n−1
X
j=i
tn−1,j
!
=
n
X
i=0
e
tni(
si−
si−1) =
n
X
i=1
e
tni(
si−
si−1) ,
where in the last inequality, we used the fact that
e
tn0=
0, which follows fromP
nj=0tnj
=
1 and the definition ofe
tn0.
By Hölder’s inequality,(6)and(7), we have∞
X
n=1
β
n|
tn−
tn−1|
s=
∞
X
n=1
β
nn
X
i=1
e
tni(
si−
si−1)
s
≤
∞
X
n=1
β
n nX
i=1
e
tni i!
s−1 nX
i=1
e
tnii is
|
si−
si−1|
s!
=
O(
1)
∞
X
n=1
β
n nX
i=1
e
tni i!
s−1 nX
i=1
e
tni ik−1|
si−
si−1|
k!
=
O(
1)
∞
X
i=1
ik−1
|
si−
si−1|
k
∞
X
n=i
β
n nX
v=1
e
tnvv
!
s−1e
tni
=
O(
1)
∞
X
i=1
α
i|
si−
si−1|
k.
Theorem 1is proved.
A non-negative sequence
{
an}
is said to be almost decreasing, if there is a positive constant K such that an≥
Kamholds for all n
≤
m, and it is said to be quasi-β
-power decreasing with some real numberβ
, if nβanis almost decreasing.
It should be noted that every decreasing sequence is an almost decreasing sequence, and every almost decreasing sequence is a quasi-
β
-power decreasing sequence for any non-positive indexβ
, but the converse is not true.The following properties of Aαnare well known (see [4], P.77):
Lemma 1. (i) Aαnis positive for
α > −
1, increasing (as a function of n) forα >
0 and decreasing for−
1< α <
0;
and A0n=
1 for all n.
(ii) Aαn
=
0(α+nα1) 1
+
O 1n.
We give some applications ofTheorem 1now.
Corollary 1. Let T be the Cesáro matrix of order
α ≥
0 and k>
0,
s≥
1. Assume that{ β
n}
is a positive sequence such that n1−sβ
nis quasi-
ε
-power decreasing for someε > −
1.
If (7)holds, then(4)implies(5)withα
n=
nk−sβ
n.
Proof. Lettnj
:=
Aα−1 n−j
Aαn
,
j=
0,
1, . . . ,
n.
It is clear thatn
X
j=0
tnj
=
1 Aαnn
X
j=0
Aα−n−j1
=
1.
For 0
≤
i≤
n−
1, a direct calculation yieldse
tni=
1 Aαnn
X
j=i
Aα−n−j1
−
1 Aαn−1n
X
j=i
Aα−n−11−j
=
1 Aαnn−i
X
j=0
Aα−j 1
−
1 Aαn−1n−1−i
X
j=0
Aα−j 1
=
Aαn−i
Aαn
−
Aαn−1−i
Aαn−1
=
i nAα−n−i1
Aαn
,
(8)and
e
tnn=
Aα−1 0
Aαn
=
1Aαn
.
(9)By(8)and(9)andLemma 1, we have
n
X
v=1
e
tnvv =
1nAαn
n
X
v=1
Aα−n−v1
=
1 nAαnn
X
v=0
Aα−n−v1
−
Aα−1 n
nAαn
=
O 1 n.
(10)Since
n1−sβ
nis quasi-
ε
-power decreasing for someε > −
1, by(10), we have∞
X
n=i
β
n nX
v=1
e
tnvv
!
s−1e
tni=
O(
1)
∞
X
n=i
n1−s
β
ne
tni=
O(
1)
∞
X
n=i
n1−s+ε
β
ne
tni nε=
O i2−s+εβ
i∞
X
n=i
Aα−n−i1 n1+εAαn
.
Therefore, byLemma 1and the conditionε > −
1, we have∞
X
n=i
β
n nX
v=1
e
tnvv
!
s−1e
tni=
O i2−s+εβ
i 1i1+εAαi
2i
X
n=i
Aα−n−i1
+
∞
X
n=2i+1
Aα−n−i1 n1+εAαn
!
=
O i2−s+εβ
i 1i1+εAαi
i
X
n=0
Aα−n 1
+
∞
X
n=2i+1
(
n−
i)
α−1 n1+ε+α!
=
O i2−s+εβ
i i−1−ε+
∞
X
n=2i+1
n−2−ε
!
=
O i1−sβ
i=
O i1−kα
i.
Therefore, we obtainCorollary 1by applyingTheorem 1.Let
β
n=
nδk+k−1logγn,
n≥
1,
k>
0,
s≥
1. Ifδ <
1+ks−k,
then there is anε
such that−
1< ε < −δ
k−
k+
s. Thus, by noting that nε n1−sβ
n=
nε−(−δk−k+s)logγn, we see thatn1−s
β
nis quasi-
ε
-power decreasing forγ ∈
R.
Now, applying Corollary 1, we haveCorollary 2. Let T be the Cesáro matrix of order
α ≥
0, and let k>
0,
s≥
1 andγ ∈
R. Ifδ <
1+sk−kand(7)holds, then∞
X
n=1
nδk+2k−s−1logγn
|
sn−
sn−1|
k< ∞
implies
∞
X
n=1
nδk+k−1logγn
σ
nα− σ
nα−1s
< ∞, α ≥
0.
In particular (by taking s
=
k), ifδ <
1k, then∞
X
n=1
nδk+k−1logγn
|
sn−
sn−1|
k< ∞
implies
∞
X
n=1
nδk+k−1logγn
σ
nα− σ
nα−1k
< ∞, α ≥
0.
Remark 1. By taking s
=
k, δ = γ =
0 inCorollary 2, we obtainTheorem A.Corollary 3. Let T be the Cesáro matrix of order
−
1< α <
0 and k>
0,
s≥
1. Assume that{ β
n}
is a positive sequence such thatn(1+α)(1−s)
β
nis quasi-
ε
-power decreasing for someε > −
1.
If (7)holds, then(4)implies(5)withα
n=
nk−(1+α)sβ
n.
Proof. When−
1< α <
0, it is clear that Aα−n 1<
0 for n=
1,
2, . . . ,
and Aα−0 1=
1. ByLemma 1,(8)and(9), we getn
X
v=1
e
tnvv =
1nAαn
n−1
X
v=1
Aα−n−v1
+
Aα−1 0
nAαn
=
1 nAαnn
X
v=0
Aα−n−v1
−
Aα−n 1−
Aα−0 1+
1 nAαn=
1 nAαn Aαn−
Aα−n 1−
Aα−0 1+
1 nAαn
=
O 1 n1+α,
(11)2i
X
n=i+1
Aα−n−i1
=
2i
X
n=i+1
Aα−n−i1
=
i
X
n=0
Aα−n 1
−
Aα−0 1=
Aαi−
Aα−0 1=
O(
1) ,
(12)and
∞
X
n=2i+1
Aα−n−i1
n1+εAαn
=
O(
1)
∞
X
n=2i+1
(
n−
i)
α−1 n1+ε+α=
O(
1)
∞
X
n=2i+1
n−2−ε
=
O i−1−ε(13)
for
ε > −
1. Combining(11)–(13)and noting thatn(1+α)(1−s)
β
nis quasi-
ε
-power decreasing withε > −
1, we have∞
X
n=i
β
n nX
v=1
e
tnvv
!
s−1e
tni=
O(
1)
∞
X
n=i
n(1+α)(1−s)
β
ne
tni=
O(
i)
∞
X
n=i
n(1+α)(1−s)
β
nAα−n−i1 nAαn
=
Oi1+(1+α)(1−s)
β
i1 iAαi
+
O(
i)
∞
X
n=i+1
n(1+α)(1−s)
β
nAα−n−i1 nAαn
=
Oi1+(1+α)(1−s)
β
i1 iAαi
+
O(
i)
∞
X
n=i+1
n(1+α)(1−s)+
β
nAα−n−i1 n1+Aαn
=
O i1−(1+α)sβ
i+
O i1+(1+α)(1−s)+εβ
i∞
X
n=i+1
Aα−n−i1 n1+εAαn
=
O i1−(1+α)sβ
i+
O i1+(1+α)(1−s)+β
i2i
X
n=i+1
Aα−n−i1 n1++α
+
O i1+(1+α)(1−s)+εβ
i∞
X
n=2i+1
Aα−n−i1
n1+εAαn (byLemma 1again)
=
O i1−(1+α)sβ
i+
O i(1+α)(1−s)−αβ
i2i
X
n=i+1
Aα−n−i1
+
O i1+(1+α)(1−s)+εβ
i∞
X
n=2i+1
Aα−n−i1 n1+εAαn
=
O i1−(1+α)sβ
i+
O i(1+α)(1−s)β
i=
O i1−(1+α)sβ
i=
O i1−kα
i.
Therefore, we obtainCorollary 3byTheorem 1.Similar to the deduction ofCorollary 2, we have the following corollary ofCorollary 3:
Corollary 4. Let T be the Cesáro matrix of order
−
1< α <
0 and let k>
0,
s≥
1 andγ ∈
R.
Ifδ <
2+(1+α)(ks−1)−kand(7) holds, then∞
X
n=1
nδk+2k−(1+α)s−1logγn
|
sn−
sn−1|
k< ∞
implies
∞
X
n=1
nδk+k−1logγn
σ
nα− σ
nα−1s
< ∞, α ≥
0.
In particular (by taking s
=
k), ifδ <
αk−kα+1,
then∞
X
n=1
nδk+k−αk−1logγn
|
sn−
sn−1|
k< ∞
implies
∞
X
n=1
nδk+k−1logγn
σ
nα− σ
nα−1k
< ∞, α ≥
0.
Corollary 5. Let s
=
k≥
1, δ ∈
R, {
pn}
be a positive sequence, such that Pn= P
nn=0pi
→ ∞
as n→ ∞ ,
andn
X
i=1
Pi
i
=
O(
Pn) ,
(14)∞
X
n=i
Pn pn δk+k−spn PnPn−1
=
O Pi pi δk+k−s1 Pi−1
!
.
(15)If (7)is satisfied, then(4)implies(5)with
α
n=
nk−1 Pn pn δk+k−s, β
n=
Pn pn δk+k−1. Proof. Let
tnj
:=
pjPn
,
j=
0,
1, . . . ,
n,
thenP
nj=0tnj
=
1 for any n≥
0. Direct calculations yielde
tni=
n
X
j=i
tnj
−
n−1
X
j=i
tn−1,j
=
pn Pn+
1 Pn−
1Pn−1
n−1X
j=i
pj
=
pnPi−1 PnPn−1,
1≤
i≤
n−
1,
(16)and
e
tn0=
0, e
tnn=
pnPn
.
(17)Therefore, by(14), we have
n
X
v=1
e
tnvv =
pnPnPn−1 n
X
v=1
Pv−1
v =
O pn Pn.
Now, by(15), we have∞
X
n=i
β
n nX
v=1
e
tnvv
!
s−1e
tni=
O∞
X
n=i
Pn pn δk+k−1 pn Pn s−1pnPi−1
PnPn−1
!
=
O(
Pi−1)
∞
X
n=i
Pn pn δk+k−spn PnPn−1
=
O Pi pi δk+k−s! ,
which completes the proof ofCorollary 5.Remark 2. If
δ =
0,
s=
k,
(15)can be deduced from the facts that Pn→ ∞
as n→ ∞
, and PpnnPn−1
=
1Pn−1
−
1Pn
.
Remark 3. If{
pn}
, in addition, satisfies npn≈
Pn, thenα
ninCorollary 5becomes nδk+k−1when s=
k.
Acknowledgements
The author is grateful to the referees for their careful reading and kind suggestions which improved the presentation of the paper. The research is supported by Research Project of Hangzhou Normal University.
References
[1] T.M. Flett, On an extension of absolute summability and some theorems of Littlewood and Paley, Proc. London Math. Soc. 7 (1957) 113–141.
[2] G. Das, A tauberian theorem for absolute summability, Proc. Cambridge Philos. Soc. 67 (1970) 321–326.
[3] E. Savaş, H. Sevli, On extension of a result of Flett for Cesáro matrices, Appl. Math. Lett. 20 (2007) 476–478.
[4] A. Zygmund, Trigonometric Series, Cambridge Univ. Press, Cambridge, 1977.