R E S E A R C H A R T I C L E
Open Access
A new order-preserving average function on
a quotient space of strictly monotone
functions and its applications
Yasuo Nakasuji
1*and Sin-Ei Takahasi
2*Correspondence:
1The Open University of Japan,
Chiba, 261-8586, Japan Full list of author information is available at the end of the article
Abstract
We introduce an order in a quotient space of strictly monotone continuous functions on a real interval and show that a new average function on this quotient space is order-preserving. We also apply this new order-preserving function to derive a finite form of Jensen type inequality with negative weights.
MSC: Primary 39B62; secondary 26B25; 26A51
Keywords: Jensen’s inequality; strictly monotone function; order-preserving average function
1 Introduction and main results
This is meant as a continuation of our paper [] related to Jensen’s inequality []. The reader should refer to the recent paper of József [] on Jensen’s inequality. Further the paper is related to the notion of quasi-arithmetic means, so the reader should refer to the recent paper of Janusz [].
LetIbe a finite closed interval [m,M] onRandC(I) the space of all continuous real-valued functions defined onI. Moreover, letC+
sm(I) (resp.C–sm(I)) be the set of all functions
inC(I) which are strictly monotone increasing (resp. decreasing) onI. Put
Csm(I) =Csm+ (I)∪Csm– (I).
ThenCsm(I) is equal to the space of all strictly monotone continuous functions onI. For
anyϕ,ψ ∈Csm(I), we writeϕ∼=ψ if there exist two numbersa,b∈Rsuch thatϕ(x) =
aψ(x) +b for allx∈I. Then it is clear that∼= is an equivalence relation inCsm(I). Let
˜
Csm(I) be the quotient space ofCsm(I) by∼= and we denote byϕ˜the coset ofϕ∈Csm(I).
We introduce an orderinC˜sm(I) in the next section (see Theorem ).
Let (,μ) be a probability space andfa function inL(,μ) such thatf(ω)∈Ifor almost
allω∈. Then we see thatϕ◦f ∈L(,μ) for all ϕ∈C
sm(I) becauseϕ is a bounded
continuous function andμis a finite measure. Put
Mϕ(f) =ϕ–
ϕ◦f dμ
for eachϕ ∈Csm(I). Then [, Theorem ] which gives a new interpretation of Jensen’s
inequality is restated as ϕ˜ ˜ψ ⇒Mϕ(f)≤Mψ(f). In this paper, we give a new
order-preserving average functionN[I,f]on the quotient spaceC˜sm(I), according to this idea. We
also apply this functionN[I,f]to derive a finite form of Jensen type inequality with negative
weights.
Letϕbe an arbitrary function ofCsm(I). Sinceϕ(I) is an interval ofRandμis a
proba-bility measure on, it follows that
ϕ(m) +ϕ(M) –
ϕ◦f dμ∈ϕ(I),
and hence we have
ϕ–
ϕ(m) +ϕ(M) –
ϕ◦f dμ
∈I.
Note that a simple computation implies that ifϕ,ψ∈Csm(I) satisfyϕ˜=ψ˜, then
ϕ–
ϕ(m) +ϕ(M) –
ϕ◦f dμ
=ψ–
ψ(m) +ψ(M) –
ψ◦f dμ
holds. Then denote byN[I,f](ϕ˜) the above value.
In this case, our main result can be stated as follows.
Theorem N[I,f]is an order-preserving real-valued function on the quotient spaceC˜sm(I)
with order,that is,ϕ˜ ˜ψ⇒N[I,f](ϕ˜)≤N[I,f](ψ˜).
The above theorem easily implies the following result, which is a finite form of Jensen type inequality with negative weights.
Corollary Letϕ,ψ∈Csm(I)withϕ˜ ˜ψand t, . . . ,tn∈Rwith
n
i=ti= , <t,tn< ,
and t, . . . ,tn–< .Then
ϕ–
n
i=
tiϕ(xi)
≤ψ–
n
i=
tiψ(xi)
holds for all x, . . . ,xn∈I with x≤x, . . . ,xn–≤xn. Finally, we give concrete examples of Corollary .
2 An order in the quotient spaceC˜sm(I)
Let us start with the following two lemmas.
Lemma Letϕ∈Csm(I).Then:
(i) ϕis increasing and convex onIif and only ifϕ–is increasing and concave onϕ(I). (ii) ϕis increasing and concave onIif and only ifϕ–is increasing and convex onϕ(I). (iii) ϕis decreasing and convex onIif and only ifϕ–is decreasing and convex onϕ(I).
Proof Straightforward.
Lemma
(i) Ifϕis a convex function onIandψ is an increasing convex function onϕ(I),then ψ◦ϕis convex onI.
(ii) Ifϕis a convex function onIandψ is a decreasing concave function onϕ(I),then ψ◦ϕis concave onI.
(iii) Ifϕis a concave function onIandψ is an increasing concave function onϕ(I),then ψ◦ϕis concave onI.
(iv) Ifϕis a concave function onIandψ is a decreasing convex function onϕ(I),then ψ◦ϕis convex onI.
Proof Straightforward.
For anyϕ,ψ∈Csm(I), we writeϕψif any of the following four conditions holds:
(i) ϕ,ψ∈C+
sm(I)andϕ◦ψ–is concave onψ(I).
(ii) ϕ∈Csm– (I),ψ∈Csm+ (I)andϕ◦ψ–is convex onψ(I). (iii) ϕ,ψ∈C–
sm(I)andϕ◦ψ–is convex onψ(I).
(iv) ϕ∈C+
sm(I),ψ∈C–sm(I)andϕ◦ψ–is concave onψ(I).
Remark Lemma guarantees that the aboveϕψ is a restatement of the concepts ap-pearing in [, Lemma ].
Lemma Letϕ,ϕ,ψ,ψ ∈Csm(I).Ifϕ∼=ϕ,ψ∼=ψ,andϕψ,thenϕ ψ .
Proof Assume thatϕ∼=ϕ,ψ∼=ψ, andϕψ. Then we must showϕ ψ. Sinceϕ∼=ϕ, ψ∼=ψ, we can writeϕ andψ as follows:
ϕ =aϕ+b and ψ =cψ+d
for somea,b,c,d∈R. Then we havea= andc= . Put
ζ(x) =ax+b and η(x) =cx+d
for eachx∈R. In the case ofϕ,ψ∈C+sm(I) anda,c> , we find thatϕ◦ψ–is concave on ψ(I) becauseϕψ. Thenζ◦ϕ◦ψ–is increasing and concave onψ(I) from Lemma -(iii)
and henceϕ ◦ψ–=ζ◦ϕ◦ψ–◦η–is also concave onψ(I) from Lemma -(iii). However,
sinceϕ,ψ ∈C+
sm(I), we obtainϕ ψ as required. Moreover, we can easily see thatϕ
ψ holds in the other cases:
ϕ∈C+
sm(I),ψ∈C–sm(I),a> ,c>
, . . . ,
ϕ∈Csm– (I),ψ∈C–sm(I),a< ,c< .
For anyϕ˜,ψ˜ ∈ ˜Csm(I), we writeϕ˜ ˜ψ by the same notation ifϕψ holds. This is well
defined by Lemma . In this case, we have the following.
Proof We show the theorem by dividing into three steps. (I) It is evident thatsatisfies the reflexivity.
(II) Assume thatϕ˜ ˜ψandψ˜ ˜ϕ. Thenϕψ andψϕhold. In the case ofϕ,ψ∈
C+
sm(I), we find thatϕ◦ψ–is concave onψ(I) andψ◦ϕ–is concave onϕ(I). Sinceψ◦ϕ–
is increasing and concave onϕ(I), it follows from Lemma -(ii) thatϕ◦ψ–= (ψ◦ϕ–)–
is convex onψ(I). Thereforeϕ◦ψ–is affine onψ(I) and henceϕ∼=ψ, that is,ϕ˜=ψ˜. By the same method, we can easily see thatϕ˜=ψ˜ holds in the other three cases:
ϕ∈Csm+ (I),ψ∈Csm– (I), ϕ∈C–sm(I),ψ∈Csm+ (I) and ϕ,ψ∈C–sm(I).
Thereforesatisfies the symmetry law.
(III) Assume thatϕ˜ ˜ψandψ˜ ˜λ. Thenϕψandψλhold. In the case ofϕ,ψ,λ∈
C+
sm(I), we find thatϕ◦ψ–is increasing and concave onψ(I) andψ◦λ–is concave on
λ(I). Then it follows from Lemma -(iii) thatϕ◦λ–= (ϕ◦ψ–)◦(ψ◦λ–) is concave on λ(I), and henceϕλ, that is,ϕ˜ ˜λholds. By the same method, we can easily see that
˜
ϕ ˜λholds in the other seven cases:
ϕ∈Csm+ (I),ψ∈C+sm(I),λ∈Csm– (I), . . . , ϕ∈Csm– (I),ψ∈C–sm(I),λ∈Csm– (I).
Thereforesatisfies the transitive law.
3 Proofs of Theorem 1 and Corollary 1
Letϕbe an arbitrary function ofCsm(I). Then an easy observation implies that
(–ϕ)–(y) =ϕ–(–y) ()
for ally∈–ϕ(I) and that
N[I,f](–ϕ) =N[I,f](ϕ˜). ()
Lemma Let ϕ∈Csm(I).If eitherϕ is increasing and concave on I or decreasing and
convex on I,then
N[I,f](ϕ˜)≤
ϕ–◦ϕ(m) +ϕ(M) –ϕ◦fdμ≤m+M–
f dμ
holds.If eitherϕ is increasing and convex on I or decreasing and concave on I,then the above inequalities are reversed.
Proof (I) Suppose thatϕis increasing and concave onI. Thenϕ–is increasing and convex onϕ(I) by Lemma -(ii), and hence the first inequality in Lemma follows from Jensen’s inequality. Put
for eachx∈I. Then it follows from Lemma -(i) thatϕ is a convex function onI such thatϕ (m) =ϕ (M) =m+M. Therefore we have
ϕ–ϕ(m) +ϕ(M) –ϕf(ω)≤m+M–f(ω) ()
for almost allω∈. By integrating () with respect toω, we obtain the second inequality in Lemma . We next suppose thatϕis decreasing and convex onI. Then –ϕis increasing and concave onI. Therefore the desired inequality follows from (), (), and the above argument.
(II) Suppose thatϕis increasing and convex onI. Thenϕ–is increasing and concave on ϕ(I) by Lemma -(i), and hence the first inequality in Lemma is reversed from Jensen’s inequality. Also sinceϕ is concave onIby Lemma -(iii), it follows that the second in-equality in Lemma is reversed from a consideration in (I). Similarly for the decreasing
and concave case.
Proof of Theorem Letϕ˜,ψ˜ ∈ ˜Csm(I) withϕ˜ ˜ψ, whereϕ,ψ∈Csm(I).
(I-i) In the case ofϕ,ψ∈C+
sm(I), we find thatϕ◦ψ–is increasing and concave onψ(I) =
[ψ(m),ψ(M)] becauseϕψ. Therefore we have from Lemma
ψN[I,f](ϕ˜)
=ψ◦ϕ–ϕ(m) +ϕ(M) –
ϕ◦f dμ
=ϕ◦ψ––ϕ◦ψ–ψ(m)+ϕ◦ψ–ψ(M)– ϕ◦ψ–◦(ψ◦f)dμ
=N[ψ(I),ψ◦f]
ϕ◦ψ–
≤ψ(m) +ψ(M) –
ψ◦f dμ
=ψN[I,f](ψ˜)
,
so we obtainN[I,f](ϕ˜)≤N[I,f](ψ˜) sinceψis strictly increasing onI.
(I-ii) In the case ofϕ∈Csm– (I) andψ∈Csm+ (I), we find thatϕ◦ψ–is decreasing and convex onψ(I) because ϕψ. Then –ϕ,ψ ∈C+
sm(I) and (–ϕ)◦ψ– is increasing and
concave onψ(I). Therefore we have from (I-i) and ()
N[I,f](ϕ˜) =N[I,f](–ϕ)≤N[I,f](ψ˜).
(I-iii) In the case ofϕ,ψ∈C–
sm(I), we find thatϕ◦ψ–is increasing and convex onψ(I)
becauseϕψ. Thenϕ∈C–
sm(I), –ψ∈C+sm(I), andϕ◦(–ψ)–is decreasing and convex
on –ψ(I) by (). Therefore we have from (I-ii) and ()
N[I,f](ϕ˜)≤N[I,f](–ψ) =N[I,f](ψ˜).
(I-iv) In the case ofϕ∈C+
sm(I) andψ∈Csm– (I), we find thatϕ◦ψ–is decreasing and
con-cave onψ(I) becauseϕψ. Then –ϕ,ψ∈C–
onψ(I). Therefore we have from (I-iii) and ()
N[I,f](ϕ˜) =N[I,f](–ϕ)≤N[I,f](ψ˜).
This completes the proof.
Remark Letϕ,ψ∈Csm(I). We see from Theorem and Lemma thatψϕand then
N[I,f](ϕ˜)≥N[I,f](ψ˜) if any of the following four conditions holds:
(v) ϕ,ψ∈Csm+ (I)andϕ◦ψ–is convex onψ(I). (vi) ϕ∈C–
sm(I),ψ∈Csm+ (I), andϕ◦ψ–is concave onψ(I).
(vii) ϕ,ψ∈C–
sm(I)andϕ◦ψ–is concave onψ(I).
(viii) ϕ∈C+
sm(I),ψ∈Csm– (I), andϕ◦ψ–is convex onψ(I).
Throughout the remainder of the paper, we assume that=Iandf(x) =xfor allx∈I.
Proof of Corollary Letϕ,ψ∈Csm(I) withϕψandt, . . . ,tn∈Rwith
n
i=ti= , <t,
tn< andt, . . . ,tn–< . Letx, . . . ,xn∈Ibe such thatx≤x, . . . ,xn–≤xn. Puts= –
t,s= –t, . . . ,sn–= –tn–,sn= –tn. Then we have
n
i=si= ands, . . . ,sn> . So μ≡sδx+· · ·+snδxn
is a probability measure onI, whereδxdenotes the Dirac measure atx∈I. Taking [x,xn] instead ofIin Theorem , we obtain
ϕ–
ϕ(x) +ϕ(xn) – n
i=
siϕ(xi)
≤ψ–
ψ(x) +ψ(xn) – n
i=
siψ(xi)
,
which implies the desired inequality
ϕ–
n
i=
tiϕ(xi)
≤ψ–
n
i=
tiψ(xi)
.
This completes the proof.
Remark Letϕ, ψ be in Csm(I) such that any of (v), (vi), (vii), and (viii) holds. Then
ψ ϕholds from Lemma . Therefore ift, . . . ,tn∈Rwith
n
i=ti= , <t,tn< , and
t, . . . ,tn–< , then
ϕ–
n
i=
tiϕ(xi)
≥ψ–
n
i=
tiψ(xi)
holds from Corollary .
Example Putϕ(x) =logxandψ(x) =xfor each positive numberx> . Then Corollary easily implies that
n
i=
xti i ≤
n
i=
holds for allt, . . . ,tn∈Rwith
n
i=ti= , <t,tn< , and t, . . . ,tn–< , and all
pos-itive numbersx, . . . ,xnwithx≤x, . . . ,xn–≤xn. This is a geometric-arithmetic mean inequality with negative weights.
Example Putϕ(x) =
xandψ(x) =logxfor each positive numberx> . Then Corollary easily implies that
n
i=
ti
xi
–
≤ n
i=
xti i
holds for allt, . . . ,tn∈Rwith
n
i=ti= , <t,tn< , andt, . . . ,tn–< , and all positive
numbersx, . . . ,xnwithx≤x, . . . ,xn–≤xn. This is a harmonic-geometric mean inequal-ity with negative weights.
Competing interests
The authors declare that they have no competing interests.
Authors’ contributions
All authors contributed equally to this paper. All authors read and approved the final manuscript.
Author details
1The Open University of Japan, Chiba, 261-8586, Japan.2Toho University, Funabashi, 273-0866, Japan.
Acknowledgements
The authors are grateful to the referees for careful reading of the paper and for helpful suggestions and comments. The second author is partially supported by Grant-in-Aid for Scientific Research, Japan Society for the Promotion of Science.
Received: 23 June 2014 Accepted: 21 October 2014 Published:06 Nov 2014 References
1. Nakasuji, Y, Kumahara, K, Takahasi, S-E: A new interpretation of Jensen’s inequality and geometric properties of
ϕ-means. J. Inequal. Appl.2011, 48 (2011)
2. Jensen, J: Sur les fonctions convexes et les inégalités entre les valeurs moyennes. Acta Math.30, 175-193 (1906) 3. József, S: On global bounds for generalized Jensen’s inequality. Ann. Funct. Anal.4(1), 18-24 (2013)
4. Janusz, M: Generalized weighted quasi-arithmetic means and the Kolmogorov-Nagumo theorem. Colloq. Math.
133(1), 35-49 (2013)
10.1186/1029-242X-2014-450