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GENERALIZED DERIVATION MODULO THE IDEAL
OF ALL COMPACT OPERATORS
SALAH MECHERI and AHMED BACHIR
Received 3 December 1999
We give some results concerning the orthogonality of the range and the kernel of a gener-alized derivation modulo the ideal of all compact operators.
2000 Mathematics Subject Classification: 47B47, 47A30, 47B20, 47B10.
1. Introduction. Letᏸ(Ᏼ)be the algebra of all bounded operators acting on a com-plex Hilbert spaceᏴ. ForAandBinᏸ(Ᏼ), letδA,Bdenote the operator onᏸ(Ᏼ)defined byδA,B(X)=AX−XB. IfA=B, thenδA is called the inner derivation induced byA. In [1, Theorem 1.7], Anderson showed that ifAis normal and commutes withT then, for allX∈ᏸ(Ᏼ),
T−(AX−XA)≥ T. (1.1)
In [4], we generalized this inequality, we showed that if the pair (A,B) has the Putnam-Fuglede’s property (in particular ifAandB are normal operators) andAT=
T B, then for allX∈ᏸ(Ᏼ),
T−(AX−XB)≥ T. (1.2)
The related inequality (1.1) was obtained by Maher [3, Theorem 3.2] who showed that, ifA is normal andAT =T A, whereT ∈Cp, thenT−(AX−XA)p≥ Tp for all
X∈ᏸ(Ᏼ), whereCpis the von Neumann-Schatten class, 1≤p <∞, and·pits norm. Here we show that Maher’s result is also true in the case whereCpis replaced by(Ᏼ), the ideal of all compact operators with·∞its norm. Which allows to generalize these results, we prove that if the pair(A,B)has(PF)(Ᏼ), the Putnam-Fuglede’s property in (Ᏼ), andAT=T B, whereT∈(Ᏼ), thenT−(AX−XB)∞≥ T∞for allX∈ᏸ(Ᏼ).
2. Normal derivations. In this section, we investigate on the orthogonality of the range and the kernel of a normal derivation modulo the ideal of all compact operators. We recall that the pair(A,B)has the property(PF)(Ᏼ) ifAT =T B, whereT∈(Ᏼ) impliesA∗T=T B∗. Before proving this result we need the following lemmas.
Proof. Letλ1,λ2,...,λnbe eigenvalues of the diagonal operatorN. Then, the op-eratorNcan be written under the following matrix form:
λ1 0 ··· 0
0 λ2 ...
..
. . .. 0
0 ··· 0 λn
. (2.1)
According to the following decomposition ofᏴ:
Ᏼ=
n
i=1
ker N−λj. (2.2)
Let|δij|and |Xij|be the matrix representations ofS andXaccording to the above decomposition ofᏴ. Then
NX−XN= λi−λjXij. (2.3)
SinceS∈ {N}(the commutant ofN), we getS
ij=0 fori≠j. Consequently
NX−XN+S=
S11 ∗ ∗ ∗ ∗ S22 ∗ ∗
∗ ∗ ∗ ∗
∗ ∗ ∗ Snn
. (2.4)
Here∗stands for some entry.
AsδN(X)+S∈(Ᏼ), soS∈(Ᏼ)and the result of Gohberg and Kre˘ın [2] guarantee thatδN(X)+S∞≥ S∞.
Lemma2.2. LetN∈ᏸ(Ᏼ)be a normal operator and letᏴ1=Vectλ∈Cker(N−λ). IfS∈ {N}and there existsX∈ᏸ(Ᏼ)such thatδN(X)+S∈(Ᏼ), thenᏴ1reducesS and the restrictionS|Ᏼ⊥1=0.
Proof. SinceNis a normal operator,Ᏼ1reducesNand the restrictionN|Ᏼ1is a diagonal operator, then the Putnam-Fuglede’s theorem guarantees that S∗ ∈ {N}. Hence,Ᏼ1reducesS. Let
N=
N1 0
0 N2
, S=
S1 0
0 S2
, X=
X11 X12 X21 X22
(2.5)
on Ᏼ=Ᏼ1⊕Ᏼ2, where Ᏼ2 =Ᏼ⊥1. The hypothesis δN(X)+S ∈(Ᏼ)would imply
thatδN2(X22)+S2∈(Ᏼ). The result of Anderson [1] (applied to the Calkin algebra ᏸ(Ᏼ2)\(Ᏼ2)) guarantees that S2∈(Ᏼ). Since the normal operatorN2is without
eigenvalues and the selfadjoint operatorS∗
2S2is compact and belongs to the
Theorem 2.3. LetN∈ᏸ(Ᏼ)be a normal operator,S ∈ {N}, andX∈ᏸ(Ᏼ). If
δN(X)+S∈(Ᏼ), thenS∈(Ᏼ)and
δN(X)+S∞≥ S∞. (2.6)
Proof. SinceδN(X)+S∈(Ᏼ), it follows fromLemma 2.2that
N=
N1 0
0 N2
, S=
S1 0
0 S2
(2.7)
onᏴ=Ᏼ1⊕Ᏼ⊥1, whereᏴ1=Vectλ∈Cker(N−λ). If
X=
X11 X12 X21 X22
(2.8)
onᏴ=Ᏼ1⊕Ᏼ⊥1, then
δN(X)+S=
δN1 X11
+S1 ∗
∗ ∗
. (2.9)
SinceδN(X)+S ∈(Ᏼ), it results that δN1(X11)+S1∈(Ᏼ). As N is a diagonal operator andS1∈ {N1}, it follows fromLemma 2.1thatS1is compact and
δN 1 X11
+S1∞≥S1∞. (2.10)
Consequently,Sis compact and
δN(X)+S∞≥δN 1 X11
+S1∞≥S1∞= S∞. (2.11)
Corollary2.4. LetN,M,S∈ᏸ(Ᏼ)such thatNandMare normal operators and NS=SM. IfX∈ᏸ(Ᏼ)such thatδN,M(X)+S∈(Ᏼ), thenS∈(Ᏼ)and
δN,M(X)+S
∞≥ S∞. (2.12)
Proof. Consider the operatorsL,T, andY defined onᏴ=Ᏼ⊕Ᏼby
L=
N 0
0 M
, S=
0 S
0 0
, Y=
0 X
0 0
, (2.13)
thenLis normal,T∈ {L}and
δL(Y )+T=
0 δN,M(X)+S
0 0
. (2.14)
ThenTheorem 2.3would imply thatT is compact and
δL(Y )+T
consequently,Sis compact and
δN,M(X)+S
∞≥ S∞. (2.16)
3. Generalized derivations. In this section, we generalize the above results to a large class of operators. We show that if the pair(A,B)has the property(PF)(Ᏼ), and
AS=SBsuch thatδN,M(X)+S∈(Ᏼ), thenS∈(Ᏼ)and
δA,B(X)+S
∞≥ S∞, ∀x∈ᏸ(Ᏼ). (3.1)
Before proving this result, we need the following lemma.
Lemma3.1. LetA,B∈ᏸ(Ᏼ). The following statements are equivalent: (1) the pair(A,B)has the property(PF)(Ᏼ);
(2) ifAT =T B, whereT ∈(Ᏼ), then R(T )reduces A, ker(T )⊥ reduces B, and A|R(T )andB|ker(T )⊥ are normal operators.
Proof. (1)⇒(2). Since (Ᏼ) is a bilateral ideal andT ∈(Ᏼ), thenAT ∈(Ᏼ). Hence, asAT=T Band(A,B)satisfies(PF)(Ᏼ),A∗T=T B∗andR(T ), and ker(T )⊥are reducing subspaces for A and B, respectively. Since A(AT ) = (AT )B implies
A∗(AT )=(AT )B∗ by (PF)(Ᏼ), and the identityA∗T = T B∗ implies that A∗AT =
AA∗T, thus we see thatA|
R(T )is normal. Clearly,(B∗,A∗)satisfies(PF)(Ᏼ)andB∗T∗=
T∗A∗. Therefore, it follows from the above argument thatB∗|
R(T∗)=B|ker(T )⊥is nor-mal.
(2)⇒(1). LetT ∈(Ᏼ)such thatAT =T B. Taking the two decompositions of Ᏼ, Ᏼ1=Ᏼ=R(T )⊕R(T )⊥andᏴ2=Ᏼ=ker(T )⊥⊕kerT. Then we can writeAandBon Ᏼ1intoᏴ2, respectively,
A=
A1 0
0 A2
, B=
B1 0
0 B2
, (3.2)
whereA1andB1are normal operators. Also we can writeTandXonᏴ2intoᏴ1
T=
T1 0
0 0
, X=
X1 X2 X3 X4
. (3.3)
It follows from AT =T B that A1T1=T1B1. Since A1and B1 are normal operators,
then, by applying the Fuglede-Putnam’s theorem, we obtain A∗
1T1= T1B1∗, that is, A∗T=T B∗.
Theorem3.2. LetA,B∈ᏸ(Ᏼ)satisfying(PF)(Ᏼ) andAS=SB. IfX∈ᏸ(Ᏼ)such thatδA,B(X)+S∈(Ᏼ), thenS∈(Ᏼ)and
δA,B(X)+S
Proof. Since the pair(A,B)satisfies the property(PF)(Ᏼ), it follows byLemma 3.1 thatR(S)reducesA, ker(S)⊥reducesB, andA|
R(S)andB|ker(S)⊥are normal operators. LetᏴ1=R(S)⊕R(S)⊥andᏴ2=ker(S)⊥⊕kerS. Then
A=
A1 0
0 A2
, B=
B1 0
0 B2
,
S=
S1 0
0 0
, X=
X1 X2 X3 X4
.
(3.5)
It follows from
AS−SB=
A1S1−S1B1 0
0 0
=0 (3.6)
thatA1S1=S1B1and we have
S−(AX−XB)
∞=
S1− A1X1−X1B1
∗
∗ ∗
∞. (3.7)
SinceA1andB1are two normal operators, then it results fromCorollary 2.4thatS1
is compact and
S1− A1X1−X1B1∞≥S1∞, (3.8)
so
S−(AX−XB)∞≥S1− A1X1−X1B1
∞≥S1∞= S∞. (3.9)
Corollary3.3. LetA,B∈ᏸ(Ᏼ)satisfying(PF)(Ᏼ)andAS=SB. IfX∈ᏸ(Ᏼ)such thatδA,B(X)+S∈(Ᏼ), thenS∈(Ᏼ)and
S+AX−XB∞≥ S∞ (3.10)
in each of the following cases:
(1) ifA,B∈ᏸ(Ᏼ)such thatAx ≥ x ≥ Bxfor allx∈Ᏼ; (2) ifAis invertible andBsuch thatA−1B ≤1.
Proof. (1) The result of Tong [5, Lemma 1] guarantees that the above condition implies that for all T ∈ker(δA,B|(Ᏼ)), R(T )reducesA, ker(T )⊥ reducesB, and
A|R(T )andB|ker(T )⊥ are unitary operators. Hence, it results fromLemma 3.1that the pair(A,B)has the property(PF)(Ᏼ)and the result holds byTheorem 3.2.
Inequality (3.10) holds in particular ifA=Bis isometric; in other words,Ax = x
for allx∈Ᏼ.
References
[1] J. H. Anderson,On normal derivations, Proc. Amer. Math. Soc.38(1973), 135–140. [2] I. C. Gohberg and M. G. Kre˘ın,Introduction to the Theory of Linear Nonselfadjoint Operators,
Translations of Mathematical Monographs, vol. 18, American Mathematical Society, Rhode Island, 1969.
[3] P. J. Maher,Commutator approximants, Proc. Amer. Math. Soc.115(1992), no. 4, 995– 1000.
[4] S. Mecheri,On minimizingS−(AX−XB)pp, Serdica Math. J.26(2000), no. 2, 119–126. [5] Y. S. Tong,Kernels of generalized derivations, Acta Sci. Math. (Szeged)54(1990), no. 1-2,
159–169.
Salah Mecheri: Department of Mathematics, College of Science, King Saud
Univer-sity, P.O. Box2455, Riyadh11451, Saudi Arabia
E-mail address:[email protected]
Ahmed Bachir: University of Mostaganem, Exacte Sciences Institute, BP227,27000 Mostaganem, Algeria