VOL. 17 NO. 3 (1994) 441-446
REGULAR
MEASURES
AND NORMAL LATTICES
CARMEN VLAD
Department
of MathematicsPace University/NYC
campusPace
Plaza, New York,NY
10038-1502(Received
August
26, 1992and in revised formDecember 27,1992)
ABSTRACT. In
this paper, we investigateM(2,)
in case2. is anormal lattice of subsets ofX
and weextend the results to
1,
2’2-lattices
ofsubsets ofX
such that2.1
C2-2
and2,1
separates2.2.
We
define the outer measures/P
and#"
which prove very useful in proving some of theabove results.
KEY
WORDS AND PHRASES.
Normallattice,
outer measure, separation. 1991AMS
SUBJECT CLASSIFICATION CODES.
28.1.
INTRODUCTION.
Let
X
bean abstract set and 2. alattice ofsubsets ofX.
If 2_is a normal lattice, then in previous papers consequences pertaining toI(2,)-the
set of non-trivial finitely additive zero-one valuedmeasureson.A(2,),
thealgebra
generated by2. have beeninvestigated.In
thefirst part ofthis paper, weextend these results toM(2,),
theset ofnon-trivial,
non-negativefiniteandfinitelyadditivemeasures on.A(2,).
We
extendtheseconsiderations to1,2.2-lattices ofsubsets of
X
such that2-1
C2- and2-1
separates 2-2.Iftt(5
M()
then an auxiliary finitelysubadditive outermeasure/t is associated with itand proves veryuseful in proving someofthe aboveresults. Thisalong
with anotheroutermeasure#"
isconsidered in detail in the secondpartof the paper.It
isshownthatalthough/t
mightnotbea
regular
finitely subadditive outermeasure, it is still truethat an arbitrary setE
CX
is/P-measurable ifand only if it splits justX
additively.We
note that ifu
51(2,)
thenu
isclearly
regular,
butthisneednot be thecasefor#(5M(2,).
We
begin with some standardbackground
material(see
also[1]
and[5])
for the reader’sconvenience.
Some
relatedmaterialcanbe found in[2], [3],
and[4].
2.
BACKGROUND AND NOTATIONS.
Let
X
bean abstract set and 2. alatticeofsubsets ofX.
It
is assumedthatO,X
(52-. Thelattice is called normal if for any
LI,L
(52, withL
NL
0 there existLa,
L
(52, withi C
i,
5 Ci
andi
fLt
0(where
prime denotescomplement).
is almostcountably
compactif#E
IR(2’
)
implies#EI().
a-smoothon/,if forallsequences
{L,}
of sets of withL,O, #(L,,)-O.
a-smooth onA(/,)iffor all sequences
{A,}
of sets ofA(/,)
with A,$O,#(A,,)-O.
/--regular
ifforanyA
A(/’), it(A)= sup{/a(L)/L
CA,L
We
denote byMn(/’)
the set of /--regular measures ofM(/,);
M(/’)
the set of a-smooth measures on/,ofM(/,); M(/’)
the set ofa-smoothmeasuresonA(/-)of M(/’); M(/,)
the setof/--regular
measuresofIn
addition,I(/-),In(/,),I(/,),I(/’)
andI(/’)
are the subsets of thecorresponding M’s
which consist ofthe non-trivialzero-onevaluedmeasures.
Finally, for
/-1
C/-2
tWOlattices of subsets ofX, /-1
separates/-2
ifA,B
2. and AflB
0 implies there existC, D /’1
suchthatA
CC, B
CD
andC
f3D
0.3.
NORMAL
LATTICES.
THEOIM
1.Let
2. be normal and let#M(/,), r,Mn(/,
with#<u
on and#(X)
u(X).
Thenu(L’)=
sup{p("
),"
CL’,L,"
/,}.
PROOF.
Let
L/, and >0. SinceuMR(/,),
there existsAcLt,
A2.
such thatu(L
)
<
t,(A).
Since/,isnormal,
there existB,
C
/’such thatA
CB
CC
CL
t.
Hence,
u(A) <_
u(B’)
<_
#(B’)
<_ #(C)
<_ u(C) <
u(L’)
and then
u(L’)-
#(C)
<
u(L’)-
t,(A)
<
,
i.e.,u(L’)
<
#(C)
+
e, e arbitrary small.Therefore,
r,(L’)
sup{#(
),"
CL’,"
/,}.
DEFINITION
1.Let
gM(/,)
and define#’(E)=
inf{
#(L:),E
C0
L,,
L,
/,,E
CX.}
t=l
inf{g(L’),E
CL’,L
/’}.
THEOIM
2.Suppose
2. is normal and let #M(/,),t
MR(
with #<
t, on and#(X)
t,(X).
Then#_<
t, t/=#’
on/’.PROOF.
IfA
,#(A)_<
#(L’)
for allA
CL’,L
/,. Therefore#(A)_<
#’(A)=
inf
A
CL
t,
i.e.,#<
#
on/,.For
tMR(/,
wehave for anyA
/,:t,(A)
inf
{t,(Lt)/A
CL’,L
}
i.e.,
t,r,’
on /,. #<
t, on 2. and#(X)=
(X)implies
#_>
t, on2.’.
Hence
t,’(A)=
inft,(L’)
< inf#(L’)=
#’(A),A
CL’,
i.e., t/<#’
on/,.To
show that’
#’
on/,,
suppose thatt,’
# #’
on /-. Then thereexistsL
/,such thatt,(L)
<
#’(L).
Since t,MR(I.),
there existsA
,L
CA’
suchthat
t,(A’)-
<
t,(L)=
t,’(L).
2. being
normal,
there existC,D
/" such thatL
cC
CD
CA
and#’(L)
<
#(C’)
<
#(C’)
< #(D).
But
#(D)
< t,(D) _<
(A’)
<
t/(L)
+
<
#’(L)
+
_< #(D)
+
e, contradiction.THEOREM
3.Let
be normal and let #M(),
t,MR(Z
with # <t, on and#(X)
t,(X).
Thent,M(/,’).
PROOF. Let
L,
t;,L,
/,. Sincet,MR(Z)
and#M()
with #<
t, on,
t,(L’)
sup#(
),
CL’;L,
/,. Given e>
0, there exist.
CL$,,
/’ such thatt,(L$)<
#(.)+.
May
assume,
and since,
CLt,
it follows,,
t;. Since #M(),#(,)<,
all n_> N(e).
Hence
t(L,)
<
foralln_> N(),
i.e.,M(’).
TH:EOIM
4.Suppose Z
is normal and let /M(/,),t,l,t,
EMR(/’)
with t<
t, on/,,
#
_<
t,on/,and#(X)= l(X)= t,(Z).
Then h t%PROOF.
By
Theorem 2,Hencev
l=u2=ItTHEOREM
5.Let
2.be almost countably compactandlet/
EMn(2.).
Then I EPROOF.
Suppose
#M(Z).
Then there existsA,
O,A,
6Z
withit(A,)@0.
SinceMn(Z’),
there existsB,
Z,A,
ZB
andO+,(A,)
u(B).
May
assumeB
0 alln andB,
hence{B}
has the finite intersectionproperty. Therefore thereexistsA
In(Z
)
such thatA(B)=I
all n. SinceA,
zB
it followsA(A,)=I
all n.But
A,
0; thenA
contradictionsince
Z
isalmost countably compact.THEOM
6.Let
Z
CZ
and supposethatZ
separatesZ.
Let
Mn(Z)
andconsidertheextension u6
Mn().
Then:(a)
uisZ-regular
on(b)
If.
M(Z,)
thenuM.(Z).
(c)
vis unique.PROOE.
(a)
Define#,(L)= inf
(L),
L
CL,L
,L
.
For
yL
DL
we havev(L)
inf #(L)=
#,(L),
hence u #, on.
Suppose
thatu(L)
<
u,(L)
for someL
fiZ.
Sinceu
Mn(),
thereexistsL
,
L
CL)
such thatu()
<
u(L)+
e.By
separation, thereexistLa,L1
such thatLcL1,LCI
andLL,=O.
ThenLCL]CL;CL
du(L)
<
u(L])
#(L1)
<
u(L)
<
#,(L)+
e, e arbitrary small.It
follows#(L,) < #,(L).
But
L
CL]
implies#,(L)
#(L),
contradiction.Hence
wemusthaveu #,on oru #. on()
Let
L
e ti,
L
t
0.(L)=
..(L)=
.v{(L.),L.
c
,L.
e t}.
Si.L,
CL,
may assumeL,
0. Given e>
0, there existsL,
CL
such thatu(L)-e
<
#(L,).
u
M()implies
#(,)0,
henceu(L)0,
i.e.,uM,().
(c)
Suppose
for#M(1)
therearetwoextensionsu,u
M(Z).
By
(a)
u,,u,
eZ;-regular
on,
i.e.,()
.
.(),
c
L,]
e Z, e
.
(L)
u(L,),L,
c
L,L,
,,L
Hence
u;(L)= u(L)
dthen u]u
on whichimpliesu,
u
onZ.
THEOM
7.Let
C and suppose1
sepates
.
Let
#M(Z1),u
fiM(Z)
with# u on
;
d#(X)=
u(X).
Consider the extensions vM(Z),v/A(;)=
U dMa(),
A/’(a)
u. ThenvA
on.
PROOF.
Let
L
,
bitry. SinceA
isZ-regular,
given e>
0,
there existsL
C such thatA()<
A(L)+
e.By
sepation, there existsLI,a
,
such thatL
CL;,
,
c
]
a
L
]
.
Thfo,
hL
CL1C
Ca
(L)
/a(z)(L])
u(L)
u(L;)
u(L)
/A(I)(L;)
(L)
<
(L)
+
e d u on,;
e bitry smM1 impliesv(L)
A(L).
L
bitraryin shows that v5
onTEOM
8.Let
Z
benormM
dMmost
countably
compact. ThenM()
CM,().
PROOF.
Lt
e M.(Z).
The.e
M.(t’)
o.t’
a
.(X)
p(X).
n
d p
M,()
since isMmost
countably
compact.But
pM,()
d UMn()
d p on,
therefore, Z
beingnormM
itfollows#M,(Z).
4.
SOME
FITELY
SUBADDIT OUTER
MEASUS.
DEFITION
2. #definedon(X)
isafinitelysubadditive outermeasureif:(a)
#isnondecreing;
(b)
.(
0
E,) <
(,),
fo .yE,,...
.
X;
()
,()
o
Clearly,
#t,
asdefinedin Section 3,isafinitelysubadditiveoutermeasure.Let
fu,
be the set of all/it-measurable
sets, whereE
is measurable with respect to it iffor any ,4 CX,
#(A)
’(A
a
)
+
,’(a
E’)
if andonly
if/(A)
>/t(A
CE)
+
IL(A
CE
)
for allA
.
THEOREM
9.E
C:fu’
PROOF.
(a)
IfE
CYu"
then the relationclearlyholds.(b)
Let
/3be arbitraryinX,
B
CAt,
A
.
We
have:p(A’)
g’(A’) >_/’(A’
NE)
+/’(A’
CE’) _>/’(B
fE)
+
p’(B
NE’),
by assumption and
/r
being monotone. Since this is true for anyB
CAt,
A
,
it followsI(B) >#(Bf]E)+I(BVE).
By
the definition ofpr
as an outer measure, we have forB
(BNE)U(BVE’):t’(B)
<_
I’(BNE)+ p’(BE’).
Therefore,p’(B)
I’(BNE)+ I’(Br]E’),
B
arbitraryinX,
i.e.,E
f,,.
DEFINITION
3.Let
/M()
and define the inner measureI,(E)=supp(L),
L
CE,L
,E
CX.
THEOREM
10. Thefollowingstatementsare true:(a)
/(X) =/,(L)
+
I’(L’),L
.
(b)
(X) =/,(L’)
+/’(L)
PROOF.
Clear.DEFINITION
4.Let
/Ma(),E
CX
and defineI"(E)=
inf,
I(L:),E
CJ
L:,L,
.
--1
Let
f,.,,
be the set ofp-measurable
sets, whereE
is measurable withrespect
toif
for anyA
CXt"(A)
I"(A
fE)
+
I"(A
fE’).
THEOREM
11./
isanoutermeasure.PROOF. Clear.
THEOREM
12.E
f,,,
ifandonly
if#’(A)
>_
I’(A
fE)
+
i(At
E
)
for allA
.
PROOF.
(a)
IfE
f,,,,
thenclearly/"(A’)
>/"(A’
E)
+
g"(A’
fE’)
forA
.
(b)
Let
B
be arbitraryset inX
andletBC
J
L,L,
alli. Then,since/’_</on
’,
wehave
/(L,)
>
/"(L[)
>
[/"(L
gE) +/"(U,
E’)]
’,
#"(L
fE)
+
,=I --s=l ,=I
#"(L
E’)
>/"(
L
fE)
+/"(
L
fE’) >/z"(B
E)
+
#"(B
NE’).
s=l s=l ,=1
wm os
fo.n
z.z
c
g’..
tefo,"(Z)
..f
,(g’.)
>
,"(
)
+
,"(
’)
=d i.=1 =1
B
wasarbitraryinX
itfollowsE
f,,,.
THEOREM
13.Let/
M(),E
CX.E
:f,,
iff/,(E)
=/’(E).
PROOF.
Suppose
E
’,,.
Then/(X)
#’(E’)
+/’(E).
By
Theorem 10,/(X)
=/,(E’)
+/’(E),
so we have#’(E’)=#,(E’).
Hence
t(X)-I’(E’)=I(X)-I,(E’)
and then/,(E)
=/’(E).
Conversely, suppose#,(E)=/z’(E).
Then,
given>
0, there existsL
,L
CE
and
#(/,)+
>
#(E).
Also,
be definition of#’,
there exists such that,’D
E
D/,
and#(]_,’)
</’(E)
+
.
Now,
letA’
/.’.
Then#’(A’
fE)
_</’(A’
’)
=/(A’)
+/(,’)
I(A’U,’)
<_
#(A’)
+
#’(E)
+
-
#(A’U[,)
<_
I(A’)
+
Iz([,)
+
+
I(A’U[,)
I(A’
[,) +
.
Now
E’
C/,’,
+
e+
p(A’
N,’)
p(A’)
+
e, arbitrary.Therefore,
t,’(A’
C?E)
+
t,’(A’
NE’)
<_ p(A’)
p’(At),A’ e
-’,
i.e.,E
e
’,,,.
THEOREM
14.Let
pEM()
and definep"(E)
as above. Then(,)
,,"(.)
,(.\")
(b)
I<Id’n.
PROOF.
(a)
If"(X)
p(X),
thereexistsL,
EZ,z
1,2, such thatX-
L
and#(L)<
(X).
ButI,(L
lirap(L)>
hm#(
0
Lt,),
0
L
and0
Lt,
t
and,=1 t=l t=l =1
L
?
L’,
X.Therefore,
since,
e M,(Z)we
have lira#(
0
L.)=
It(X),
contradiction.=1 *=l =l
(b)
Suppose
thereexistsL
e
such thatp(L)
>
"(L).
Then<_
,"(L)+
,(L’)
<
,(L)
+
#(L’)
p(X)which contradictspart(a)
of the theorem.REFERENCES
1.
ALEXANDROFF, A.D.,
Additive set functions in abstract spaces,Mat.
Sb.(N.S.)
8(50)
(1940),
307-34S.2.
BACHMAN,
G.
&
SULTAN, A.,
Regular
lattice measures: mappings and spaces,Pac. J.
Math.67
(2)
(1976),
291-321.3.
EID, G.,
On
normal lattices and Wallmanspaces,Internat.
J.
Math. and Math. Sci. 13(1)
(1990),
31-38.4.
SZETO, M.,
On
separation oflattices,Internat.
J.
Math. and Math. Sci. 14(2)
(1991),
325-338.