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MAXIMUM MODULUS OF POLYNOMIALS HAVING SOME ZEROS AT ORIGIN Roshan Lal

Department of Mathematics V.S.K.C. Govt. P.G. College Dakpathar

Vikasnagar, Dehradun Uttarakhand, India-246162

Abstract: Let be a polynomial of degree

n

. Concerning the estimate for the maximum

modulus of a polynomial on the circle , in terms of its degree and the maximum modulus on the unit circle, we have several well known results for the case R1and

r

1

respectively. In this paper, we have obtained bounds for the maximum modulus of polynomials having some zeros in the interior of a circle of radiusR1. Our result improves as well as generalizes the bounds obtained by other authors for the same class of polynomials.

Key Words: Polynomials, Inequalities, Complex domain, zeros. 2000 AMS Subject Classification: 30A10, 30C10, 30C15.

1. INTRODUCTION AND STATEMENT OF RESULTS

Let be a polynomial of degree

n

. Concerning the estimate for the maximum

modulus of a polynomial on the circle , in terms of its degree and the maximum modulus on the unit circle, we have the following well known results.

Theorem A If is a polynomial of degree n, then for every R1,

max

(

)

max

(

)

1

z

p

R

z

p

z n R

z

 . (1.1.)

The result is best possible and extremal polynomial is

p

(

z

)

z

n,

 

0

being a complex number.

Inequality (1.1.) is a simple deduction from the maximum modulus principle (for reference see [7] or [6]).

n

j

j j

z

a

z

p

0

)

(

0

,

R

R

z

n

j

j j

z

a

z

p

0

)

(

0

,

R

R

z

(2)

Theorem B. If is a polynomial of degree n, then for r1,

max

(

)

max

(

)

1

p

z

r

z

p

z n r

z

 . (1.2.)

The result is best possible and extremal polynomial is ,

 

0

being a complex number.

Inequality (1.2.) is due to Zarantonello and Varga [9].

Theorem C. If is a polynomial of degree n, having no zeros in , then for

r

1

,

max

(

)

2

1

)

(

max

1

z

p

r

z

p

z n r

z

 

. (1.3.)

The result is best possible and equality in inequality (1.3) holds for

n

z

z

p

 

2

1

)

(

.

The inequality (1.1) is due to Ankeny and Rivlin [1] and inequality (1.3) is due to Rivlin [8]. For the case

0

1

, we have the following result due to Aziz [2].

Theorem D. Let

n j

j j

z

a

z

p

0

)

(

be a polynomial of degree n, which does not vanish in

. Then for

0

1

max

(

)

1

)

(

max

1

z

p

k

k

z

p

z n

z

 . (1.4)

The result is sharp and equality in (1.4) is attained for

p

(

z

)

c

(

ze

i

k

)

n

,

c

(

0

)

C

and

R

.

The following result is due to Jain [5].

Theorem E. If be a polynomial of degree n, having all its zeros in

z

k

,

k

1

, then for

2

k

R

k

,

)

(

z

p

n

z

z

p

(

)

)

(

z

p

z

1

1

,

k

k

z

(3)

max

(

)

1

)

(

max

1

z

p

k

k

R

R

z

p

z s

R

z

. (1.5)

where s(<n) is the order of a possible zero of p(z) at origin.

In this paper, we prove the following generalization of Theorem E by involving the coefficients of the

polynomial

n j

j j

z

a

z

p

0

)

(

. In fact we prove the following

Theorem 1. Let

n j

j j

z

a

z

p

0

)

(

be a polynomial of degree n, having all its zeros in

1

,

k

k

z

, then for

k

R

k

2,

,

)

(

min

)

1

(

)

(

)

(

)

)

(

)(

1

(

)

(

max

)

1

(

)

)(

(

2

)

)(

(

)

(

max

1 2

1 1

1 1

2 1

1 1

2 1

z

p

a

R

R

k

R

a

s

n

R

s

n

a

a

R

k

R

z

p

a

R

a

s

n

R

k

R

a

R

a

s

n

R

k

R

R

z

p

k z n s

n s

n n

n n

s n s

s

z n

s n n

s n

n s n n

s n s

n s R

z

  

 

 

 

 

  

 









(1.6)

where s is the order of a possible zero of p(z) at the origin .

2. LEMMAS.

For the proof of the above theorems, we need the following lemmas.

Lemma 2.1. If

n

a

z

z

p

0

)

(

is a polynomial of degree n, having no zeros in ,

then

max

(

)

2

)

1

(

)

(

'

max

1 1 2 0

2

1 2 0

1

k

n

a

k

a

p

z

a

k

a

n

n

z

p

z

z

. (2.1)

The above lemma is due to Govil, Rahman and Schmeisser [4]. The above lemma is due to Dewan, Singh and Yadav [3]. Lemma 2.2. If

 

 

 

n

a

z

z

p

0

has no zeros in , then

1

,

k

k

z

1

,

k

k

(4)

.

)

(

min

2

)

1

(

)

)

(

max

2

)

1

(

)

(

'

max

1 2 0

2

1 0 2

1 1 2 0

2

1 2 0

1

z

p

a

k

a

n

k

a

a

n

k

n

z

p

a

k

a

n

k

a

k

a

n

n

z

p

k z n

z z

 

 

(2.2)

Lemma 2.3.If

n j

j j

z

a

z

p

0

)

(

is a polynomial of degree n having all its zeros in

z

k

,

k

0

,

then for

r

k

R

, we have

 

min

 

.

max

2

max

z 1

2 2

2 0 2

1 0 1

z 1

2 2

2 0

1 2 0

2 2 1

z

z

p

R

r

a

k

R

r

k

r

a

n

k

a

r

a

n

r

R

r

R

r

a

k

R

r

k

r

a

n

a

k

a

n

k

r

r

z

p

k n

n n

n n

n n n

R n n n

n n r

 

 





(2.3) Proof of Lemma 2.3. Since

p

(z

)

does not vanish in

z

k

,

k

1

, the polynomial

)

(

)

(

z

p

rz

T

does not vanish in

,

1

r

k

r

k

z

, therefore applying Lemma 2.2 to

T

(z

)

, we get

)

(

min

2

)

1

(

)

)

(

max

2

)

1

(

)

)

(

'

max

1 2 2

0 2 2

1 0

2

1 1

2 2

0 2 2

1 2 2

0

1

z

T

a

r

r

k

a

n

r

k

a

r

a

n

r

k

n

z

T

a

r

r

k

a

n

r

k

a

r

r

k

a

n

n

z

T

r k z n

z z

 

 









(5)

)

(

min

2

)

(

)

)

(

max

2

)

(

)

)

(

'

max

1 2 0

2 2

1 0

2

1 1

2 0

2 2

1 2 0

rz

p

a

r

k

a

n

k

r

a

r

a

n

k

r

n

z

p

a

r

k

a

n

k

r

a

k

r

a

n

r

n

rz

p

r

r k z n

n

z r

z

 

 









which is equivalent to

.

)

,

(

2

)

(

)

)

,

(

2

)

(

)

)

(

'

max

1 2 0

2 2

1 0

2 1

1 2 0

2 2

1 2 0

k

p

m

a

r

k

a

n

k

r

a

r

a

n

k

r

n

r

p

M

a

r

k

a

n

k

r

a

k

r

a

n

n

z

p

n n r

z









  

(2.4)

Again as

p

'

(

z

)

is a polynomial of degree

n

1

, by maximum modulus principle [6, p. 158, problem III 269], we have

,

)

,

'

(

)

,

'

(

1

1 

n

n

r

r

p

M

t

t

p

M

for

t

r

(2.5) Combining inequalities (2.4) and (2.5), we have

.

)

,

(

2

)

(

)

)

,

(

2

)

(

)

)

(

'

max

1 2 0

2 2

1 0

2 1

1 2 0

2 2

1 2 0

1 1









  

 

k

p

m

a

r

k

a

n

k

r

a

r

a

n

k

r

r

p

M

a

r

k

a

n

k

r

a

k

r

a

n

r

t

n

z

p

n n n

n

(6)

.

)

,

(

2

)

(

)

)

,

(

2

)

(

)

)

,

(

2

)

(

)

)

,

(

2

)

(

)

)

(

'

)

(

)

(Re

1 2 0

2 2

1 0

2 1

1 2 0

2 2

1 2 0

1

1 2 0

2 2

1 0

2 1

1 2 0

2 2

1 2 0

1 1

















  

  

k

p

m

a

r

k

a

n

k

r

a

r

a

n

k

r

r

p

M

a

r

k

a

n

k

r

a

k

r

a

n

r

r

R

dt

k

p

m

a

r

k

a

n

k

r

a

r

a

n

k

r

r

p

M

a

r

k

a

n

k

r

a

k

r

a

n

r

t

n

dt

te

p

re

p

p

n n n

n n R

r

n n n

n

R

r

i i

i  

This is equivalent to

.

)

,

(

2

)

(

)

)

,

(

}

2

)

{(

]

)[

(

]

2

)

[(

,

1 2 0

2 2

1 0

2

1 2 0

2 2 1

1 2 0

1 2 0

2 2 1

k

p

m

a

r

k

a

n

k

r

a

r

a

n

k

r

R

r

p

M

a

r

k

a

n

k

r

r

a

k

r

a

n

r

R

a

r

k

a

n

k

r

r

R

p

M

n n n

n

n n n





  

From which the proof of Lemma 2.3 follows.

3. PROOF OF THE MAIN THEOREM

Proof of the Theorem 1. The polynomial

p

 

z

of degree n has all its zeros in

z

k

,

k

1

, with s-fold zeros at the origin, implies that the polynomial

q

(

z

)

z

n

p

(

1

/

z

)

is of degree (n-s) and has all its zeros in

1

,

1

1

k

k

z

.

On applying Lemma 2.3 to the polynomial

q

(z

)

with , we obtain for

k

r

k

1

1

2

,

1

(7)

1

min

(

)

1

1

1

)

(

1

)

)

)((

1

(

)

(

max

1

1

1

1

)

(

1

2

)

(

1

)

(

max

1 1 2 2 2 2 1 1 1 1 2 2 2 1 2 2 2 1

z

p

r

a

k

r

k

r

a

s

n

k

a

r

a

s

n

r

r

z

q

r

a

k

r

k

r

a

s

n

a

r

k

a

s

n

k

r

r

z

q

k z s n n s n n s n n n s n s n z s n n s n n n s n n s n r z                     

or equivalently

for

1

2

1

.

k

r

k

The above inequality is equivalent to









 

                   

z

p

z

k

r

a

k

r

r

a

s

n

a

r

a

s

n

r

k

r

z

p

r

k

a

k

r

r

a

s

n

a

k

r

a

s

n

k

r

r

z

p

z

n k z s n n s n n n n s n s n s n z s n n s n n n n s n n r z

1

min

1

1

)

(

)

)

)((

1

(

)

(

max

1

1

)

(

2

)

(

1

1

max

1 2 1 2 2 1 2 1 1 2 1 2 2 1 2 2 2 1

1

min

(

)

(8)

for

1

2

1

.

k

r

k

Now replacing r by R

1

we get from inequality (3.1)

)

(

min

1

1

1

1

1

1

)

(

)

(

1

1

)

(

max

1

1

1

1

1

)

(

2

)

(

1

1

)

(

max

2 1 2

2

1 2

1

1 2

1 2

2

1 2

2 2 1

z

p

k

R

k

a

R

k

R

a

s

n

R

a

a

s

n

R

k

R

z

p

R

k

a

R

k

R

a

s

n

a

R

k

a

s

n

k

R

R

z

p

k z n s n n

s n n

n n s

n s

n s

z s

n n

s n n

n n

s

R z

 

 

 

  

 

 

 

 

 

for

k

R

k

2. The above inequality on simplification reduces to

,

)

(

min

)

1

(

)

(

)

(

)

)

(

)(

1

(

)

(

max

)

1

(

)

)(

(

2

)

)(

(

)

(

max

1 2

1 1

1 1

2 1

1 1

2 1

z

p

a

R

R

k

R

a

s

n

R

s

n

a

a

R

k

R

z

p

a

R

a

s

n

R

k

R

a

R

a

s

n

R

k

R

R

z

p

k z n s

n s

n n

n n

s n s

s

z n

s n n

s n

n s n n

s n s

n s R

z

  

 

 

 

 

  

 









for

k

R

k

2. This completes the proof of Theorem 1.

(9)

References

1 N.C. Ankeny and T.J.Rivlin, On a Theorem of S. Bernstein, Pacific J. Maths. , 5 (1955), 249-252.

2 A. Aziz, Growth of polynomials whose zeros are within or outside a circle, Bull. Austral. Math. Soc., 35 (1987), 247-250.

3 K.K.Dewan, Harish Singh and R.S.Yadav, Inequalities concerning polynomials having zeros in closed interior of a circle, Indian J. Pure and Appl. Math., 32 (5) (2001), 759-763.

4 N.K.Govil, Q.I.Rahman and G.Schmeisser, On the derivative of a polynomial, Illinois J. Math., 23 (1979), 319-329.

5 V.K.Jain, On polynomials having zeros in closed exterior or interior of a circle, Indian J. Pure Appl. Math., 30 (1999), 153-159.

6 G. Polya and G.

Szeg

o

, “Problems and Theorems in Analysis” Vol-1, Springler- Verlag, Berlin, 1972.

7 M.Riesz,

U

ber

enin Satz der Herrn Serge Bernstein, Acta Math., 40 (1918), 337-347. 8 T.J.Rivlin, On the maximum modulus of polynomials, Amer. Math. Monthly, 67 (1960),

251-253.

References

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