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(1) Equation of Lines in 3D

(a) Vector equations 𝒓 = π’“πŸŽ+ 𝒕𝒗

Where 𝒗 is a vector parallel to the line 𝑳.

(b) Parametric equations

If 𝒗 =< 𝒂, 𝒃, 𝒄 > and π’“πŸŽ=< π’™πŸŽ , π’šπŸŽ ,π’›πŸŽ >

𝒙 = π’™πŸŽ+ 𝒂𝒕 , π’š = π’šπŸŽ+ 𝒃𝒕, 𝒛 = π’›πŸŽ+ 𝒄𝒕 .

(c) Symmetric Equations

π’™βˆ’π’™πŸŽ

𝒂

=

π’šβˆ’π’šπŸŽ

𝒃

=

π’›βˆ’π’›πŸŽ

𝒄 .

Example 1 :

Solution :

(2) Equation of a Line Segment

(3) Skew Lines

Example 2 :

(2)

(3) Equation of a plane

(a) Vector Equation of the Plane : 𝒏 βˆ™ (𝒓 βˆ’ π’“πŸŽ) = 𝟎 ,

Where 𝒏 is a normal vector to plane and 𝒓 βˆ’ π’“πŸŽ is a vector lies on the plane.

(b) Scalar Equation of the Plane thought the point π‘·πŸŽ(π’™πŸŽ, π’šπŸŽ, π’›πŸŽ) :

𝒂(𝒙 βˆ’ 𝒙

𝟎

) + 𝒃(π’š βˆ’ π’š

𝟎

) + 𝒄(𝒛 βˆ’ 𝒛

𝟎

) = 𝟎

Example 2 :

Find an equation of the plane through the point (2, 4, βˆ’1) with normal vector 𝑛 =< 2, 3, 4 >. Find the intercepts and sketch the plane. Solution:

Example 3 :

(3)

Example 4 :

Solution:

Example 5 :

Solution:

(4)

Solution:

(5) Distance from a Point to a Line

(5)

(6) Distance between two Lines

Find the distance between the two lines π‘³πŸ through point π‘·πŸ

parallel to vector π’—πŸ and π‘³πŸ through point π‘·πŸ parallel to vector π’—πŸ.

Solution :

(6)

Example 6 :

Classify the Quadric surface π’™πŸ+ πŸπ’›πŸβˆ’ πŸ”π’™ βˆ’ πŸ”π’š + 𝟏𝟎 = 𝟎 .

Solution :

(8) The derivative 𝒓′(𝒕) of a vector function 𝒓(𝒕) is defined as

(9) Unit Tangent Vector

(7)

Example 7 :

Solution :

(10) Arc-Length

The Arc-length of a space curve has the vector equation

𝒓(𝒕) =< 𝒇(𝒕), π’ˆ(𝒕), 𝒉(𝒕) >, 𝒂 ≀ 𝒕 ≀ 𝒃

𝑳 = ∫ √[𝒇𝒃 β€²(𝒕)]𝟐+ [π’ˆβ€²(𝒕)]𝟐+ [𝒉′(𝒕)]𝟐 𝒂

𝒅𝒕

= ∫ √[𝒅𝒙 𝒅𝒕]

𝟐

+ [π’…π’š 𝒅𝒕]

𝟐

+ [𝒅𝒛 𝒅𝒕]

𝟐 𝒃

𝒂 𝒅𝒕

Example 8 :

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(11) Exercises Parallel Lines

1) Is the line through (βˆ’πŸ’, βˆ’πŸ”, 𝟏) and (βˆ’πŸ, 𝟎, βˆ’πŸ‘)parallel to the line through (𝟏𝟎, πŸπŸ–, πŸ’) and (πŸ“, πŸ‘, πŸπŸ’) ?

Point of Intersection of Lines

2) Determine whether the lines π‘³πŸand π‘³πŸare parallel, skew, or

intersecting. If they intersect, find the point of intersection

π‘³πŸ : 𝒙 = πŸ“ βˆ’ πŸπŸπ’•, π’š = πŸ‘ + πŸ—π’• , 𝒛 = 𝟏 βˆ’ πŸ‘π’•

and π‘³πŸ : 𝒙 = πŸ‘ + πŸ–π’”, π’š = βˆ’πŸ”π’” , 𝒛 = πŸ• + πŸπ’” .

3) Determine whether the lines π‘³πŸand π‘³πŸare parallel, skew, or

intersecting. If they intersect, find the point of intersection.

π‘³πŸβˆΆ π’™βˆ’πŸπŸ =π’šβˆ’πŸ‘βˆ’πŸ =π’›βˆ’πŸβˆ’πŸ‘ and π‘³πŸ ∢ π’™βˆ’πŸ‘πŸ =π’š+πŸ’πŸ‘ =π’›βˆ’πŸβˆ’πŸ• .

Equation of a Plane

4) Find an equation of the plane through the point (πŸ“, πŸ‘, πŸ“) and with normal vector πŸπ’Š + 𝒋 βˆ’ π’Œ.

5) Find an equation of the plane through the point (𝟐, πŸ’, πŸ”) and parallel to the plane 𝒛 = 𝒙 + π’š.

6) Find an equation of the plane through the points (𝟎, 𝟏, 𝟏), (𝟏, 𝟎, 𝟏) and (𝟏, 𝟏, 𝟎) .

7) Find an equation of the plane through the point (𝟏,𝟏𝟐,πŸπŸ‘) and parallel to the plane 𝒙 + π’š + 𝒛 = 𝟎.

8) Find an equation of the plane that passes through the line of intersection of the planes 𝒙 βˆ’ 𝒛 = 𝟏 and π’š + πŸπ’› = πŸ‘ and is perpendicular to the plane 𝒙 + π’š βˆ’ πŸπ’› = 𝟏 .

Intersection Point of a Line and a Plane

9) Find the point at which the line intersects the given plane

𝒙 = 𝟏 + πŸπ’•, π’š = πŸ’π’•, 𝒛 = 𝟐 βˆ’ πŸ‘π’• ; 𝒙 + πŸπ’š βˆ’ 𝒛 + 𝟏 = 𝟎 .

10) Where does the line through (𝟏, 𝟎, 𝟏) and(πŸ’, βˆ’πŸ, 𝟐) intersect the plane 𝒙 + π’š + 𝒛 = πŸ” ?

11) Find the distance from the point (𝟏, βˆ’πŸ, πŸ’) to the given plane

πŸ‘π’™ + πŸπ’š + πŸ”π’› = πŸ“ .

12) Find the distance from the point (βˆ’πŸ”, πŸ‘, πŸ“) to the plane

𝒙 βˆ’ πŸπ’š βˆ’ πŸ’π’› = πŸ– .

13) Find the distance between the parallel planes

πŸπ’™ βˆ’ πŸ‘π’š + 𝒛 = πŸ’ 𝐚𝐧𝐝 πŸ’π’™ βˆ’ πŸ”π’š + πŸπ’› = πŸ‘ .

14) Find the distance between the parallel planes

πŸ”π’› = πŸ’π’š βˆ’ πŸπ’™ 𝒂𝒏𝒅 πŸ—π’› = 𝟏 βˆ’ πŸ‘π’™ + πŸ”π’š .

15) Show that the distance between the parallel planes

𝒂𝒙 + π’ƒπ’š + 𝒄𝒛 + π’…πŸ= 𝟎 and 𝒂𝒙 + π’ƒπ’š + 𝒄𝒛 + π’…πŸ= 𝟎 is

𝑫 = |π’…πŸβˆ’ π’…πŸ| βˆšπ’‚πŸ+ π’ƒπŸ+ π’„πŸ

Distance Between Two Skew Lines

16) Find the distance between the skew lines with parametric Equations

𝒙 = 𝟏 + 𝒕 , π’š = 𝟏 + πŸ”π’• , 𝒛 = πŸπ’• , and 𝒙 = 𝟏 + πŸπ’” , π’š = πŸ“ + πŸπŸ“π’” ,

𝒛 = βˆ’πŸ + πŸ”π’” .

17) Let π‘³πŸ be the line through the points (𝟏, 𝟐, πŸ”) and (𝟐, πŸ’, πŸ–). Let π‘³πŸ be

the line of intersection of the planes π…πŸ and π…πŸ , where π…πŸ is the

(9)

(πŸ‘, 𝟐, βˆ’πŸ) , (𝟎, 𝟎, 𝟏) and (𝟏, 𝟐, 𝟏). Calculate the distance between π‘³πŸ

and π‘³πŸ .

Identify Quadric Surfaces

18) Sketch and identify the surface π’™πŸ = π’šπŸ+ πŸ’π’›πŸ .

19) Sketch and identify the surface πŸπŸ“π’™πŸ+ πŸ’π’šπŸ+ π’›πŸ = 𝟏𝟎𝟎 .

20) Sketch and identify the surface πŸ’π’™πŸ+ πŸ’πŸ—π’šπŸ+ π’›πŸ= 𝟎 .

(For Q21-23)Reduce the equation to one of the standard forms, classify the surface, and sketch it.

21) πŸ’π’™πŸβˆ’ π’š + πŸπ’›πŸ = 𝟎 .

22) πŸ’π’™πŸ+ π’šπŸ+ πŸ’π’›πŸβˆ’ πŸ’π’š βˆ’ πŸπŸ’π’› + πŸ‘πŸ” = 𝟎 .

23) π’™πŸβˆ’ π’šπŸ+ π’›πŸβˆ’ πŸπ’™ + πŸπ’š + πŸ’π’› + 𝟐 = 𝟎 .

24) Sketch the region bounded by the paraboloids 𝒛 = π’™πŸ+ π’šπŸ and

𝒛 = 𝟐 βˆ’ π’™πŸβˆ’ π’šπŸ .

25) Show that the curve of intersection of the surfaces

π’™πŸ+ πŸπ’šπŸβˆ’ π’›πŸ+ πŸ‘π’™ = 𝟏 and πŸπ’™πŸ+ πŸ’π’šπŸβˆ’ πŸπ’›πŸβˆ’ πŸ“π’š = 𝟎 lies in a plane.

26) Sketch the curve with the vector equation 𝒓(𝒕) =< π’”π’Šπ’π’•, 𝒕 >. Indicate with an arrow the direction in which increases.

27) Sketch the curve with the vector equation

𝒓(𝒕) =< π’”π’Šπ’π…π’•, 𝒕, 𝒄𝒐𝒔𝝅𝒕 >.

Indicate with an arrow the direction in which increases.

28) Sketch the curve with the vector equation

𝒓(𝒕) =< 𝟏, 𝒄𝒐𝒔𝒕, πŸπ’”π’Šπ’π’• >.

Indicate with an arrow the direction in which increases.

29) Sketch the curve with the vector equation 𝒓(𝒕) = π’•πŸπ’Š + 𝒕𝒋 + πŸπ’Œ. Indicate with an arrow the direction in which increases.

30) Sketch the curve with the vector equation

𝒓(𝒕) = 𝒄𝒐𝒔𝒕 π’Š βˆ’ 𝒄𝒐𝒔𝒕 𝒋 + π’”π’Šπ’π’• π’Œ.

Indicate with an arrow the direction in which increases.

31) Show that the curve with parametric equations 𝒙 = 𝒕𝒄𝒐𝒔𝒕 ,

π’š = 𝒕 π’”π’Šπ’π’• , 𝒛 = 𝒕 lies on the cone π’›πŸ= π’™πŸ+ π’šπŸ , and use this fact to help sketch the curve.

32) At what points does the helix 𝒓(𝒕) =< π’”π’Šπ’π’•, 𝒄𝒐𝒔𝒕, 𝒕 > intersect the sphere π’™πŸ+ π’šπŸ+ π’›πŸ= πŸ“ ?

33) Show that the curve with parametric equations

𝒙 = π’•πŸ, π’š = 𝟏 βˆ’ πŸ‘π’• , 𝒛 = 𝟏 + π’•πŸ‘

passes through the points (𝟏, πŸ’, 𝟎) and (πŸ—, βˆ’πŸ–, πŸπŸ–) but not through the point (πŸ’, πŸ•, βˆ’πŸ”).

34) Find a vector function that represents the curve of intersection of the surfaces :

the cylinder π’™πŸ+ π’šπŸ = πŸ’ and the surface 𝒛 = π’™π’š.

35) Find a vector function that represents the curve of intersection of the cone

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36) Find a vector function that represents the curve of intersection of the paraboloid 𝒛 = πŸ’π’™πŸ+ π’šπŸ and the parabolic cylinder π’š = π’™πŸ.

37) Find a vector function that represents the curve of intersection of the hyperboloid 𝒛 = π’™πŸβˆ’ π’šπŸ and the cylinder π’™πŸ+ π’šπŸ = 𝟏.

38) Try to sketch by hand the curve of intersection of the circular cylinder π’™πŸ+ π’šπŸ = πŸ’ and the parabolic cylinder 𝒛 = π’™πŸ. Then find parametric equations for this curve and use these equations and a computer to graph the curve.

Applications

39) If two objects travel through space along two different curves, it’s often important to know whether they will collide. (Will a missile hit its moving target? Will two aircraft collide?) The curves might intersect, but we need to know whether the objects are in the same position at the same time. Suppose the trajectories of two particles are given by the vector functions

π’“πŸ(𝒕) =< π’•πŸ, πŸ•π’• βˆ’ 𝟏𝟐, π’•πŸ>

and π’“πŸ(𝒕) =< πŸ’π’• βˆ’ πŸ‘, π’•πŸ, πŸ“π’• βˆ’ πŸ” > for 𝒕 β‰₯ 𝟎.

Do the particles collide?

40) Two particles travel along the space curves π’“πŸ(𝒕) =< 𝒕, π’•πŸ, π’•πŸ‘ >

and π’“πŸ(𝒕) =< 𝟏 + πŸπ’•, 𝟏 + πŸ”π’•, 𝟏 + πŸπŸ’π’• > .

Do the particles collide? Do their paths intersect?

Tangent Vectors and Tangent Lines

41) (a) Make a large sketch of the curve described by the vector function 𝒓(𝒕) =< π’•πŸ, 𝒕 >, 𝟎 ≀ 𝒕 ≀ 𝟐, and draw the vectors

𝒓(𝟏), 𝒓(𝟏. 𝟏), and 𝒓(𝟏. 𝟏) βˆ’ 𝒓(𝟏).

(b) Draw the vector 𝒓′(𝒕) starting at (𝟏, 𝟏), and compare it with the vector 𝒓(𝟏.𝟏)βˆ’π’“(𝟏)𝟎.𝟏 . Explain why these vectors are so close to each other in length and direction.

42) (a) Sketch the plane curve with the vector equation

𝒓(𝒕) =< 𝒕 βˆ’ 𝟐, π’•πŸ+ 𝟏 > , 𝒕 = βˆ’πŸ.

(b) Find 𝒓′(𝒕) .

(c) Sketch the position vector 𝒓(𝒕) and the tangent vector

𝒓′(𝒕) for 𝒕 = βˆ’πŸ.

43) Find the unit tangent vector at the point with the given value of the parameter .

(a) 𝒓(𝒕) =< π’•πŸ‘+ πŸ‘π’•, π’•πŸ+ 𝟏, πŸ‘π’• + πŸ’ >, 𝒕 = 𝟏 .

(b) 𝒓(𝒕) = π’”π’Šπ’πŸπ’• π’Š + π’„π’π’”πŸπ’• 𝒋 + π’•π’‚π’πŸπ’• π’Œ, 𝒕 =π…πŸ’ .

44) Find parametric equations for the tangent line to the curve with the given parametric equations at the specified point.

(a) 𝒙 = 𝟏 + πŸβˆšπ’• , π’š = π’•πŸ‘βˆ’ 𝒕 , 𝒛 = π’•πŸ‘+ 𝒕 ; (πŸ‘, 𝟎, 𝟐) ,

(b) 𝒙 = βˆšπ’•πŸ+ πŸ‘ , π’š = 𝒍𝒏(π’•πŸ+ πŸ‘) , 𝒛 = 𝒕 ; (𝟐, π’π’πŸ’, 𝟏) .

45) Find parametric equations for the tangent line to the curve with the given parametric equations at the specified point. Illustrate by graphing both the curve and the tangent line on a common screen.

(a) 𝒙 = 𝒕 , π’š = π’†βˆ’π’• , 𝒛 = πŸπ’• βˆ’ π’•πŸ ; (𝟎, 𝟏, 𝟎) ,

(b) 𝒙 = πŸπ’„π’π’”π’• , π’š = πŸπ’”π’Šπ’π’• , 𝒛 = πŸ’π’„π’π’”πŸπ’• ; (βˆšπŸ‘, 𝟏, 𝟐) ,

References

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