R E S E A R C H
Open Access
Fixed points of
(
ψ
,
φ
)
contractions on
rectangular metric spaces
˙Inci M Erhan
1*, Erdal Karapınar
1and Tanja Sekuli´c
2*Correspondence: [email protected] 1Department of Mathematics, Atilim University, Incek, Ankara 06836, Turkey
Full list of author information is available at the end of the article
Abstract
Existence and uniqueness of fixed points of a general class of (ψ,
φ) contractive
mappings on complete rectangular metric spaces are discussed. One of the theorems is a generalization of a fixed point theorem recently introduced by Lakzian and Samet. Fixed points of (ψ,φ) contractions under conditions involving rational expressions are
also investigated. Several particular cases and applications as well as an illustrative example are given.MSC: 46T99; 47H10; 54H25
Keywords: rectangular metric spaces; fixed point theorem; Hausdorff spaces
1 Introduction and preliminaries
Fixed point theory has been one of the most rapidly developing fields in analysis during the last few decades. Wide application potential of this theory has accelerated the research activities which resulted in an enormous increase in publications [–]. In a large class of studies the classical concept of a metric space has been generalized in different directions by partly changing the conditions of the metric. Among these generalizations, one can mention the partial metric spaces introduced by Matthews [, ] (see also [, , –]), and rectangular metric spaces defined by Branciari [].
Branciari defined a rectangular metric space (RMS) by replacing the sum at the right-hand side of the triangle inequality by a three-term expression. He also proved an analog of the Banach Contraction Principle. The intriguing nature of these spaces has attracted attention, and fixed points theorems for various contractions on rectangular metric spaces have been established (see,e.g., [–]).
In Boyd and Wong [] defined a class of contractive mappings calledφ contrac-tions. In , Alber and Guerre-Delabriere [] generalized this concept by introducing weakφcontraction. A self-mappingT on a metric space (X,d) is said to be weakφ con-tractive if there exists a mapφ: [, +∞) –→[, +∞) withφ() = andφ(t) > for allt> such that
d(Tx,Ty)≤d(x,y) –φd(x,y), (.)
for allx,y∈X. Contractions of this type have been studied by many authors (see,e.g., [, ]). The larger class of (ψ,φ) weakly contractive mappings has also been a subject of interest (see,e.g., [, –]).
In a recent paper, Lakzian and Samet [] stated and proved a fixed point theorem for the (ψ,φ) weakly contractive mappings on complete rectangular metric spaces. They also provided interesting examples as particular cases of such mappings. In this paper, we gen-eralize the result of Lakzian and Samet [] and, in addition, investigate maps satisfying rational type contractive conditions. We also give applications and an example.
We state some basic definitions and notations to be used throughout this paper. Rect-angular metric spaces are defined as follows.
Definition ([]) LetXbe a nonempty set and letd:X×X–→[,∞] satisfy the fol-lowing conditions for allx,y∈Xand all distinctu,v∈Xeach of which is different fromx
andy.
(RM) d(x,y) = if and only ifx=y,
(RM) d(x,y) =d(y,x), (.)
(RM) d(x,y)≤d(x,u) +d(u,v) +d(v,y).
Then the mapdis called a rectangular metric and the pair (X,d) is called a rectangular metric space.
The concepts of convergence, Cauchy sequence and completeness in a RMS are defined below.
Definition
() A sequence{xn}in a RMS(X,d)is RMS convergent to a limitxif and only if
d(xn,x)→asn→ ∞.
() A sequence{xn}in a RMS(X,d)is RMS Cauchy if and only if for everyε> there exists a positive integerN(ε)such thatd(xn,xm) <εfor alln>m>N(ε).
() A RMS(X,d)is called complete if every RMS Cauchy sequence inXis RMS convergent.
We also use the following modified notations of Lakzian and Samet [].
Letdenote the set of all continuous functionsψ: [, +∞)→[, +∞) for whichψ(t) = if and only ift= . Nondecreasing functions which belong to the classare also known as altering distance functions (see []).
In their paper, Lakzian and Samet [] stated the following fixed point theorem.
Theorem Let(X,d)be a Hausdorff and complete RMS and let T:X→X be a self-map satisfying
ψd(Tx,Ty)≤ψd(x,y)–φd(x,y)
for all x,y∈X andψ,φ∈, whereψ is nondecreasing. Then T has a unique fixed point in X.
2 Main results and applications
We present our main results in this section. First, we state the following fixed point theo-rem.
Theorem Let(X,d)be a Hausdorff and complete RMS and let T:X→X be a self-map satisfying
ψd(Tx,Ty)≤ψM(x,y)–φM(x,y)+Lm(x,y) (.)
for all x,y∈X andψ,φ∈, where L> , the functionψis nondecreasing and M(x,y) =maxd(x,y),d(x,Tx),d(y,Ty),
m(x,y) =mind(x,Tx),d(y,Ty),d(x,Ty),d(y,Tx).
(.)
Then T has a unique fixed point in X.
Proof First, we prove the existence part. Letx∈Xbe an arbitrary point. Define the
se-quence{xn} ⊂Xas
xn=Txn–, n= , , , . . . .
Assume thatxn=xn+=Txnfor alln≥. Substitutex=xn–andy=xnin (.) and note that
m(xn–,xn) =min
d(xn–,xn),d(xn,xn+),d(xn–,xn+),d(xn,xn)
= .
Then we obtain,
ψd(Txn–,Txn)
=ψd(xn,xn+)
≤ψM(xn–,xn)
–φM(xn–,xn)
+Lm(xn–,xn)
=ψM(xn–,xn)
–φM(xn–,xn)
, (.)
where
M(xn–,xn) =max
d(xn–,xn),d(xn–,xn),d(xn,xn+)
=maxd(xn–,xn),d(xn,xn+)
.
IfM(xn–,xn) =d(xn,xn+), then we have
ψd(xn,xn+)
≤ψd(xn,xn+)
–φd(xn,xn+)
,
which impliesφ(d(xn,xn+)) = , and henced(xn,xn+) = . Thenxn=xn+=Txn, which contradicts the initial assumption. Therefore, we must haveM(xn–,xn) =d(xn–,xn), that is,
ψd(xn,xn+)
≤ψd(xn–,xn)
–φd(xn–,xn)
≤ψd(xn–,xn)
Sinceψis nondecreasing, thend(xn,xn+)≤d(xn–,xn) for alln≥, that is, the sequence
{d(xn,xn+)}is decreasing and positive. Hence, it converges to a positive number, says> .
Taking limit asn→ ∞in (.), we obtain
ψ(s)≤ψ(s) –φ(s),
which leads toφ(s) = and hence tos= . Thus, lim
n→∞d(xn,xn+) = . (.)
Next, we will show thatT has a periodic point, that is, there exist a positive integerp
and a pointz∈Xsuch thatz=Tpz. Assume the contrary, that is,Thas no periodic point. Then, all elements of the sequence{xn}are distinct,i.e.,xn=xmfor alln=m. Suppose also that{xn}is not a RMS Cauchy sequence. Therefore, there existsε> for which one can find subsequences{xn(i)}and{xm(i)}of{xn}withn(i) >m(i) >isuch that
d(xm(i),xn(i))≥ε, (.)
wheren(i) is the smallest integer satisfying (.), that is,
d(xm(i),xn(i)–) <ε. (.)
We apply the rectangular inequality (RM) and use (.) and (.) to obtain
ε≤d(xm(i),xn(i))
≤d(xm(i),xn(i)–) +d(xn(i)–,xn(i)–) +d(xn(i)–,xn(i))
≤ε+d(xn(i)–,xn(i)–) +d(xn(i)–,xn(i)). (.)
Taking limit asi→ ∞in (.) and using (.), we get
lim
i→∞d(xn(i),xm(i)) =ε. (.)
Employing the rectangular inequality (RM) once again, we write the following inequali-ties:
d(xn(i),xm(i))≤d(xn(i),xn(i)–) +d(xn(i)–,xm(i)–) +d(xm(i)–,xm(i)),
d(xn(i)–,xm(i)–)≤d(xn(i)–,xn(i)) +d(xn(i),xm(i)) +d(xm(i),xm(i)–),
(.)
from which we obtain
ε≤ lim
i→∞d(xn(i)–,xm(i)–)≤ε, (.)
using (.) and (.); and therefore,
lim
Now we substitutex=xn(i)–andy=xm(i)–in (.), which yields
ψd(Txn(i)–,Txm(i)–)
=ψd(xn(i),xm(i))
≤ψM(xn(i)–,xm(i)–)
–φM(xn(i)–,xm(i)–)
+Lm(xn(i)–,xm(i)–), (.)
where
M(xn(i)–,xm(i)–) =max
d(xn(i)–,xm(i)–),d(xn(i)–,xn(i)),d(xm(i)–,xm(i)
,
m(xn(i)–,xm(i)–) =min
d(xn(i)–,xn(i)),d(xm(i)–,xm(i)),d(xn(i)–,xm(i)),d(xm(i)–,xn(i)
.
Clearly, asi→ ∞we haveM(xn(i)–,xm(i)–)→max{ε, , }=εandm(xn(i)–,xm(i)–)→
due to (.) and (.). Then lettingi→ ∞in (.), we get
≤ψ(ε)≤ψ(ε) –φ(ε) + , (.)
which impliesφ(ε) = , and henceε= . This contradicts the assumption that{xn}is not RMS Cauchy, thus,{xn}must be RMS Cauchy. Since (X,d) is complete, then{xn}converges to a limit, sayu∈X. Letx=xnandy=uin (.). This gives
ψd(Txn,Tu)
≤ψM(xn,u)
–φM(xn,u)
+Lm(xn,u), (.)
with
M(xn,u) =max
d(xn,u),d(xn,Txn),d(u,Tu)
,
m(xn,u) =min
d(xn,Txn),d(u,Tu),d(xn,Tu),d(u,Txn)
.
Note thatm(xn,u)→ asn→ ∞. IfM(xn,u) =d(xn,u) orM(xn,u) =d(xn,xn+), then we
haveM(xn,u)→ asn→ ∞, due to (.) and the fact that the sequence{xn}converges tou. Regarding the continuity ofψandφ, we have
≤ψ
lim
n→∞d(Txn,Tu)
≤ lim n→∞
ψM(xn,u)
–φM(xn,u)
+Lm(xn,u) = .
Hence,limn→∞d(Txn,Tu) = , that is, in either case, we end up withxn+=Txn→Tu. SinceXis Hausdorff, we deduce thatu=Tu. If, on the other hand,M(xn,u) =d(u,Tu) passing to limit asn→ ∞in (.), we getφ(M(u,Tu)) = , henced(u,Tu) = , that is
u=Tu. This result contradicts the assumption thatT has no periodic points. Therefore,
T has a periodic point, that is,z=Tpzfor somez∈Xand a positive integerp.
Ifp= , thenz=Tz, sozis a fixed point ofT. Letp> . We claim that the fixed point of
T isTp–z. Suppose the contrary, that is,Tp–z=T(Tp–z). Thend(Tp–z,Tpx) > and so isφ(d(Tp–z,Tpx)). Lettingx=Tp–zandy=Tpzin (.), we have
ψd(z,Tz)=ψdTpz,Tp+z
where
MTp–z,Tpz=maxdTp–z,Tpz,dTp–z,Tpz,dTpz,Tp+z,
mTp–z,Tpz=mindTp–z,Tpz,dTpz,Tp+z,dTp–z,Tp+z,dTpz,Tpz= .
ForM(Tp–z,Tpz) =d(Tpz,Tp+z), (.) becomes
ψd(z,Tz)=ψdTpz,Tp+z≤ψdTpz,Tp+z–φdTpz,Tp+z.
Thus, we getφ(d(Tpz,Tp+z)) = and henced(Tpz,Tp+z) =d(z,Tz) = , which is not
pos-sible sincep> . If, on the other hand,M(Tp–z,Tpz) =d(Tp–z,Tpz), then (.) turns into
ψd(z,Tz)=ψdTpz,Tp+z≤ψdTp–z,Tpz–φdTp–z,Tpz
<ψdTp–z,Tpz, (.)
and taking into account the fact thatψis nondecreasing, we deduce
d(z,Tz) <dTp–z,Tpz.
Now we writex=Tp–zandy=Tp–zin (.) and get
ψdTp–z,Tpz≤ψMTp–z,Tp–z–φMTp–z,Tp–z
+LmTp–z,Tp–z, (.)
where
MTp–z,Tp–z=maxdTp–z,Tp–z,dTp–z,Tp–z,dTp–z,Tpz,
mTp–z,Tp–z=mindTp–z,Tp–z,dTp–z,Tpz,
dTp–z,Tpz,dTp–z,Tp–z= .
ForM(Tp–z,Tp–z) =d(Tp–z,Tpz), we obtain
ψdTp–z,Tpz≤ψdTp–z,Tpz–φdTp–z,Tpz,
which is possible only ifφ(d(Tp–z,Tpz)) = and hence,d(Tp–z,Tpz) = . However, we assumed thatd(Tp–z,Tpz) > . Thus, we must haveM(Tp–z,Tp–z) =d(Tp–z,Tp–z), so
that
ψdTp–z,Tpz≤ψdTp–z,Tp–z–φdTp–z,Tp–z
≤ψdTp–z,Tp–z, (.)
We continue in this way and end up with the inequality
<d(z,Tz) =dTpz,Tp+z<dTp–z,Tpz≤dTp–z,Tp–z≤ · · · ≤d(z,Tz),
which yieldsd(z,Tz) <d(z,Tz). Therefore, the assumptiond(Tp–z,Tpx) > is wrong, that is,d(Tp–z,Tpx) = andTp–zis the fixed point ofT.
Finally, to prove the uniqueness, we assume thatT has two distinct fixed points, sayz
andw. Then lettingx=zandy=win (.), we have
ψd(z,w)=ψd(Tz,Tw)≤ψM(z,w)–φM(z,w)+Lm(z,w), (.)
where
M(z,w) =maxd(z,w),d(z,Tz),d(w,Tw)=d(z,w),
m(z,w) =mind(z,Tz),d(w,Tw),d(w,Tz),d(z,Tw)= .
Thus, we have
ψd(z,w)≤ψd(z,w)–φd(z,w), (.)
implyingφ(d(z,w)) = , and henced(z,w) = , which completes the proof of the
unique-ness.
It is worth mentioning that the Theorem . given in [] is a particular case of Theo-rem . We next give some consequences of TheoTheo-rem .
Corollary Let(X,d)be a Hausdorff and complete RMS and let T:X→X be a self-map satisfying
ψd(Tx,Ty)≤ψM(x,y)–φM(x,y) (.)
for all x,y∈X andψ,φ∈, where the functionψis nondecreasing and
M(x,y) =maxd(x,y),d(x,Tx),d(y,Ty). (.)
Then T has a unique fixed point in X.
Proof Observe that
ψd(Tx,Ty)≤ψM(x,y)–φM(x,y)
≤ψM(x,y)–φM(x,y)
+Lmind(x,Tx),d(y,Ty),d(x,Ty),d(y,Tx)
Corollary Let(X,d)be a Hausdorff and complete RMS and let T:X→X be a self-map satisfying
d(Tx,Ty)≤kmaxd(x,y),d(x,Tx),d(y,Ty) (.)
for all x,y∈X and some≤k< . Then T has a unique fixed point in X.
Proof Letψ(t) =tandφ(t) = ( –k)t. Then by Corollary ,T has a unique fixed point.
Corollary Let(X,d)be a Hausdorff and complete RMS and let T:X→X be a self-map satisfying
d(Tx,Ty)≤kd(x,y) +d(x,Tx) +d(y,Ty)
+Lmind(x,Tx),d(y,Ty),d(x,Ty),d(y,Tx) (.)
for all x,y∈X and some≤k<and L> . Then T has a unique fixed point in X.
Proof Obviously,
kd(x,y) +d(x,Tx) +d(y,Ty) +Lmind(x,Tx),d(y,Ty),d(x,Ty),d(y,Tx)
≤kmaxd(x,y),d(x,Tx),d(y,Ty)+Lmind(x,Tx),d(y,Ty),d(x,Ty),d(y,Tx).
Letψ(t) =tandφ(t) = ( – k)t. Then by Theorem ,Thas a unique fixed point. Our next corollary is concerned with weakφcontractions.
Corollary Let(X,d)be a Hausdorff and complete RMS and let T:X→X be a self-map satisfying
d(Tx,Ty)≤M(x,y) –φM(x,y)+Lm(x,y) (.)
for all x,y∈X, where
M(x,y) =maxd(x,y),d(x,Tx),d(y,Ty),
m(x,y) =mind(x,Tx),d(y,Ty),d(x,Ty),d(y,Tx).
Then T has a unique fixed point in X.
Proof Letψ(t) =t. Then by Theorem ,Thas a unique fixed point. As the second result, we state the following existence and uniqueness theorem under conditions involving rational expressions.
Theorem Let(X,d)be a Hausdorff and complete RMS and let T:X→X be a self-map satisfying
for all x,y∈X andψ,φ∈, whereψis nondecreasing and
M(x,y) =max
d(x,y),d(y,Ty) +d(x,Tx) +d(x,y)
. (.)
Then T has a unique fixed point in X.
Proof Letx∈Xbe an arbitrary point. Define the sequence{xn} ⊂Xas
xn=Txn–, n= , , , . . . .
Assume thatxn=xn+=Txnfor alln≥. Substitutingx=xn–andy=xn in (.), we obtain
ψd(Txn–,Txn)
=ψd(xn,xn+)
≤ψM(xn–,xn)
–φM(xn–,xn)
, (.)
where
M(xn–,xn) =max
d(xn–,xn),d(xn,Txn)
+d(xn–,Txn–)
+d(xn–,xn)
=maxd(xn–,xn),d(xn,xn+)
.
For the rest of the proof, one can follow the same steps as in the proof of Theorem .
Settingψ(t) =tandφ(t) = ( –k)t, we obtain the following particular result.
Corollary Let(X,d)be a Hausdorff and complete RMS and let T:X→X be a self-map satisfying
d(Tx,Ty)≤kmax
d(x,y),d(y,Ty) +d(x,Tx) +d(x,y)
(.)
for all x,y∈X and some k∈[, ). Then T has a unique fixed point in X.
We also generalize the applications of Theorem . in [] given by Lakzian and Samet. Letbe the set of functionsf: [, +∞)→[, +∞) such that
() f is Lebesgue integrable on each compact subset of[, +∞); () εf(t)dt> for everyε> .
For this class of functions, we can state the following results.
Theorem Let(X,d)be a Hausdorff and complete RMS and let T:X→X be a self-map satisfying
d(Tx,Ty)
f(t)dt≤
M(x,y)
f(t)dt– M(x,y)
g(t)dt+Lm(x,y) (.)
m(x,y) =mind(x,Tx),d(y,Ty),d(x,Ty),d(y,Tx).
Then T has a unique fixed point in X.
Proof Letψ(t) =tf(u)duandφ(t) =tg(u)du. Thenψ andφ are functions in, and moreover, the functionψ is nondecreasing. By Theorem ,T has a unique fixed point.
Corollary Let(X,d)be a Hausdorff and complete RMS and let T:X→X be a self-map satisfying
d(Tx,Ty)
f(u)du≤k
M(x,y)
f(u)du+Lm(x,y) (.)
for all x,y∈X and f ∈and some≤k< , L> , where M(x,y) =maxd(x,y),d(x,Tx),d(y,Ty),
m(x,y) =mind(x,Tx),d(y,Ty),d(x,Ty),d(y,Tx).
Then T has a unique fixed point in X.
Proof Letg(t) = ( –k)f(t). Then by Theorem ,T has a unique fixed point.
Theorem Let(X,d)be a Hausdorff and complete RMS and let T:X→X be a self-map satisfying
d(Tx,Ty)
f(t)dt≤
M(x,y)
f(t)dt– M(x,y)
g(t)dt (.)
for all x,y∈X and f,g∈, where
M(x,y) =max
d(x,y),d(y,Ty) +d(x,Tx) +d(x,y)
.
Then T has a unique fixed point in X.
Proof Letψ(t) =tf(u)duandφ(t) =tg(u)du. Thenψ andφ are functions in, and moreover, the functionψ is nondecreasing. By Theorem ,Thas a unique fixed point. Finally, we give an illustrative example of (ψ,φ) contraction defined on a generalized metric space.
Example LetX=A∪B, whereA={,,,}andB= [, ]. Define the generalized metricdonXas follows:
d , =d ,
= ., d
, =d , = ., d , =d ,
= ., d
and
d(x,y) =|x–y| ifx,y∈Borx∈A,y∈Borx∈B,y∈A.
It is clear thatddoes not satisfy the triangle inequality onA. Indeed,
. =d
, ≥d , +d , = ..
Notice that (RM) holds, sodis a rectangular metric. LetT:X→Xbe defined as
Tx= ⎧ ⎪ ⎪ ⎨ ⎪ ⎪ ⎩
ifx∈[, ],
ifx∈ { , , },
ifx= .
Define ψ(t) =tandφ(t) =t. Then T satisfies the conditions of Theorem and has a unique fixed point onX,i.e.,x=.
Competing interests
The authors declare that they have no competing interests.
Authors’ contributions
All authors read and approved the final manuscript.
Author details
1Department of Mathematics, Atilim University, Incek, Ankara 06836, Turkey.2Higher Technical School of Professional Studies in Zrenjanin, University of Novi Sad, Djordja Stratimirovica 23, Zrenjanin, Serbia.
Acknowledgements
Tanja Sekuli´c is thankful to the Ministry of Science and Technological Development of Republic Serbia.
Received: 14 March 2012 Accepted: 21 August 2012 Published: 4 September 2012 References
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