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Vol. 3, No. 5, 2010, 881-898

ISSN 1307-5543 – www.ejpam.com

Tensor Product Semi-Groups

Roshdi Khalil

1,∗

, R. Al-Mirbati

2

, and D. Drissi

3

1Department of Mathematics, University of Jordan, Amman-Jordan 2Gulf University for Science and Technology, Kuwait

3Department of Mathematics, Kuwait University, Kuwait

Abstract. LetX andY be Banach spaces andL(X,Y)be the space of all bounded linear operators from

X toY.IfX=Y we writeL(X)forL(X,Y). LetXY be the tensor product ofX andY, andXαY be the completion ofXYwith respect to a uniform cross normα. In this paper, we present an extension of the Hille-Yosida Theorem to tensor product semigroups.

2000 Mathematics Subject Classifications: Primary 47D03 , Secondary 47D99

Key Words and Phrases: Semigroups of operators, Tensor product

1. Introduction

One parameter semigroups of operators have been a useful tool in the study of the so-called abstract Cauchy problem. Such a problem states as follows: LetAbe a linear operator on a Banach spaceX, find a continuously differentiable functionT(.,x)from[0,∞)into the domain of Asuch that T satisfies the differential equation d

d tT(t,x) = AT(t,x), (t ≥ 0),

T(0,x) = x, for allxDom(A). So much work has been done on one parameter semigroups of operators as well as its relation to the abstract Cauchy problem. For more on such topics we refer to[3, 4, 9].

We begin recalling some standard definitions. Let X be a Banach space and L(X) be the space of bounded linear operators onX. By a one parameter semigroup of operators onX we mean a mapT :[0,)L(X)such that

(i) T(0) =I, the identity operator onX.

(ii) T(s+t) =T(s)T(t)for alls,t≥0, the semigroup property. ∗Corresponding author.

Email address:roshdiju.edu.jo(R. Khalil)

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R. Khalil, R. Al-Mirbati, D. Drissi Eur. J. Pure Appl. Math,3(2010), 881-898 882

The linear operatorAwhose domainD(A)is given by

D(A) =

xX: lim

t→0+

T(t)xx

t exists

such that

Ax= lim

t→0+

T(t)xx

t =

d+

d t (T(t)x)|t=0 forx∈D(A)

is called the infinitesimal generator of the semigroup(T(t))t0. The generatorAis always a closed, densely defined operator. It is well known that, whenAis a densely defined linear op-erator with non empty resolvent set, then the abstract Cauchy problem has a unique solution, for all xin the domain ofA, if and only ifAgenerates a strongly continuous semigroup. (Pazy,

[9, 10], Goldstein,[3]).

There are many important results on one parameter semigroups of operators. We mention two of such results:

I. Characterization of the infinitesimal generator of a semigroup.

II. “Hille-Yosida Theorem”: The norm of the resolvent operatorRλ(A)of the infinitesimal generator of aC0 semigroup tends to zero at infinity. More precisely,Rλ(A) M

λω for

largeλ, which is known as the Hille-Yosida Inequality.

In this paper, we introduce what we call a tensor product semigroup. We show that every tensor product semigroup is a two parameter semigroup. We study the relation between a tensor product semigroup and its components. As not every two parameter semigroup on Xα Y defines a T.P.S., we present a condition under which a two parameter semigroup be a T.P.S. We show that the operatorA1⊗I+IA2, is the infinitesimal generator of aC0 T.P.S., where A1,A2 generate the semigroup components of the T.P.S. . Equality ofA1⊗I+IA2 andA1I+IA2 is proved as well.

Throughout this paper,X⊗∨Y(X⊗∧Y) denote the completion of the injective (the projective) tensor products ofX andY . IfPandQare elements inL(X)andL(Y)respectively, thenPQ denotes the tensor product operator on XY. Further, we write Xα Y to denote either one of the tensor products (the projective or the injective). For more details on tensor product spaces and tensor product of operators, we refer the reader to[8].

2. Tensor Product Semigroups

Definition 1. Let X,Y be Banach spaces, and(T(s))s0,(S(t))t0 be one parameter families of operators in L(X),L(Y)respectively. The family(T(s)⊗S(t))s,t0 is called atensor product semigroup, (abbreviatedT.P.S.) on the Banach space Xα Y if

1. T(0)⊗S(0) =IXY,

2. T(s1+s2)⊗S(t1+t2) = T(s1)⊗S(t1)

T(s2)⊗S(t2)

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This is equivalent to

T(0)α S(0) =I

XαY and T(s1+s2)

α

S(t1+t2) =



T(s1)α S(t1)

‹ 

T(s2)αS(t2)

‹

.

Thus the family



T(s)α S(t)

‹

s,t≥0

is a T.P.S. defined on the complete space Xα Y. For short, we will write (T(s)S(t))s,t0 for



T(s)α S(t)

‹

s,t≥0 , and I for each of IXY, and I

XαY. It should be remarked that if we knowT(s)⊗S(t)onXY, then we knowT(s)

α

S(t) onXα Y.

One can define aT.P.S.(T(s)S(t))s,t0, to beuniformly continuousonXα Y if Lim

(s,t)→(0+,0+)kT(s)⊗S(t)−IIk=0, and to bestrongly continuousonX

α

Y(C0)if

Lim

(s,t)→(0+,0+)

T(s)α S(t)zz

=0

for allzXα Y.

One can easily see that the limit in (2) can be replaced by Lim

(s,t)→(0+,0+)

(T(s)S(t)) xyxy=0,

for allxX,yY. The proof is a consequence of the following

Lemma 1. Let X , Y be Banach spaces andαbe a uniform crossnorm on XY . If

AiBiz−(AB)z→0as i→ ∞, for all zXY and none of the sequences Ai, Bi has a subsequence that converges to zero pointwise, then AiBi

i is uniformly bonded.

More-over, each of Aii, Biiis uniformly bounded.

Proof. For a fixed 0 6= x0 ∈ X one can see that each vector in the space

x0

Y is of the form x0y for some yY. Therefore, x0Y is a Banach space. Since

AiBiz(AB)zi→∞,0 for everyzx0Y, then AiBiis a pointwise bounded sequence of bounded operators on the Banach spacex0

Y. Which implies by the Uniform Boundedness Principle that



AiBi|

[x0]⊗Y ‹

i

is uniformly bounded. That is

AiBi

|[x0]⊗Y

c for alli. But

AiBi|

[x0]⊗Y

= sup

yY

kx0⊗yk=1

AiBi x0⊗y

= sup

yY

kyk= 1

kx0k

AiBi

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R. Khalil, R. Al-Mirbati, D. Drissi Eur. J. Pure Appl. Math,3(2010), 881-898 884

= sup

yY

kyk=1

Aix0⊗Biy

= sup

yY

kyk=1

Aix0

Biy

.

Thus sup

i

     supyY

kyk=1

Aix0

Biy

   

≤c. In other words Aix0

Biy

cfor allifor all yY.

Under the assumption thatAix0 does not converge to zero, we obtain that Bi

is uniformly bounded on Y. Repeating the same approach and choosing 06= y0Y, one can show that

Aiis uniformly bounded onX. The lemma is then completely proved. One can easily prove the following result.

Lemma 2. Let X,Y be Banach spaces and (T(s))s0,(S(t))t0, be one parameter families of operators in L(X),L(Y)respectively. Then the following are equivalent:

a. T(s)is a one parameter semigroup on X .

b. T(s)I is a one parameter semigroup on Xα Y .

c. IT(s)is a one parameter semigroup on Yα X .

The following Lemma is essential for Theorem 1. Its proof is different from the proof in

[7].

Lemma 3. Let X,Y be Banach spaces, α any crossnorm on XY . Let a,cX,b,dY be nonzero vectors. If ab=cd, then there exists a nonzero scalarβsuch a=βc,b= 1

βd.

Proof. Let x∗∈X∗. Then x∗(a)b= x∗(c)d. In particular, this holds for an x∗satisfying that x∗(c) =kck. That is, xk∗(a)

ck b= d. It is clear that x

(a) is not zero. Choose x∗(a)

kck =β.

Then aβcb=0. Thus, xaβcb=0 for all x∗∈X∗. Choosingx∗∈X∗, such that xaβc=aβccompletes the proof.

Theorem 1. Let X,Y be Banach spaces,(T(s))s0,(S(t))t0one parameter families of operators in L(X),L(Y)respectively. Then the family T(s)⊗S(t) is a T.P.S. on Xα Y if and only if there is a unique06= β ∈R, and unique one parameter semigroups €Tb(s

s≥0,

€ b

S(t

t≥0 on X,Y respectively, such that

βT(s) =Tb(s)and 1

βS(t) =bS(t)for all s,t ≥0.

Proof. If β = 1 then (T(s))s0,(S(t))t0 define one parameter semigroups. Therefore, from Lemma 3, each ofT(s)⊗IandIS(t)is a one parameter semigroup onXα Y. Conse-quently,

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is a T.P.S. onXα Y.

Ifβ 6=1, then T(s),S(t) are not semigroups of operators sinceT(0) = β1I 6= I even though, T(s)S(t)is a T.P.S.

To show necessity, let T(s)⊗S(t)be a T.P.S. onXα Y. then T(0)⊗S(0) =II, and by Lemma 3, there exists 06=γRsuch thatT(0) =γI, andS(0) = 1

γI. Define the familiesTb(s)

andbS(t) fromR+2 into L 

Xα Y

‹

so that Tb(s) = 1

γT(s)andSb(t) =γS(t),s,t ≥0. Clearly, b

T(s)bS(t) is the T.P.S. T(s)S(t). Moreover, Tb(s),bS(t) are one parameter semigroups on X,Y respectively. Indeed, Tb(0) = 1

γT(0) = I andSb(0) =γS(0) =I. To show the semigroup

property forTb(s), lets1,s2∈R+

2

and letxX. Then for any 06= yY we have

bT(s1+s2)xTb(s1)Tb(s2)x

= 1 y

€Tb(s1+s2)xTb(s1)Tb(s2)xŠ⊗ y

= 1 y

€€Tb(s1+s2)⊗I

Š

−€Tb(s1)Tb(s2)⊗I

ŠŠ

xy

= 1 y

€Tb(s1+s2)⊗bS(0+0)Š−€Tb(s1)Tb(s2)⊗Sb(0)Sb(0)Š xy

=

”€Tb(s1+s2)⊗Sb(0+0)Š−€Tb(s1)⊗bS(0)Š €Tb(s2)⊗Sb(0)Š— xy

y

= 1 y

T(s1+s2)⊗S(0+0)− T(s1)⊗S(0) T(s2)⊗S(0) xy.

Therefore bT(s1 +s2) = Tb(s1)Tb(s2). Similarly, €bS(t

t≥0 satisfies the semigroup property. HenceTb(s)andSb(t)are one parameter semigroups onX,Y respectively.

The proof of Theorem 1 shows that if(T(s))s0,(S(t))t0, are one parameter semigroups onX,Y respectively, then the family(T(s)S(t))s,t0is a T.P.S. onXα Y.

As for the continuity of tensor product semigroups it is not difficult to see

Lemma 4. Let X,Y be Banach spaces,(T(s))s0,(S(t))t0, one parameter families of operators in L(X),L(Y)respectively. If T(s)S(t)is a T.P.S. andTb(s),bS(t)are as in Theorem 1, then the following are equivalent

a. T(s)⊗S(t)is uniformly (strongly) continuous.

b. Tb(s)I and ISb(t)are uniformly (strongly) continuous.

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R. Khalil, R. Al-Mirbati, D. Drissi Eur. J. Pure Appl. Math,3(2010), 881-898 886

Now, if(T(s))s0,(S(t))t0, are one parameter families of operators in L(X), L(Y)respectively and T(s)⊗S(t)is a T.P.S., then:

If T(s)⊗S(t)is uniformly (strongly) continuous, then the map F(s,t) :R+2 = [0,∞)×[0,∞)→ L



Xα Y

‹

defined by F(s,t)→T(s)⊗S(t) is continuous in the uniform (strong) operator topology. Further, F(s,t) is uniformly (strongly) continuous if and only if it is separately uniformly (strongly) continuous.

The proof of the following proposition is straight forward, and will be omitted.

Proposition 1. Let L(s,t)be a 2-parameter semigroup on the Banach space Xα Y , such that L(s, 0) xy = f(s)xy for all xX,yY,

L(0,t) xy = xg(t)y for all xX,yY, where f,g are any functions on X,Y respectively. Then

1. f(s)s0, and g(t)t0 are one parameter semigroups on X,Y respectively.

2. L(s,t) is uniformly (strongly) continuous if and only if each of the one parameter semi-groups L(s, 0)and L(0,t)is uniformly (strongly) continuous.

It follows from the definition of a two-parameter semigroup[7], we observe that a T.P.S. (T(s)S(t))s,t0 defines a two-parameter semigroup (L(s,t))s,t0 = L(s,t) = T(s)S(t). Note that L(s,t) =L(s, 0)L(0,t), where L(s, 0) =T(s)⊗S(0) =T(s)⊗I and

L(0,t) =T(0)⊗S(t) =IS(t).

3. The Infinitesimal Generator of a T.P.S.

Let (T(s)⊗S(t))s,t0 be a C0 T.P.S. on Xα Y and A1, A2 be the infinitesimal genera-tors of the one parameter C0 semigroups €Tb(ss0Sb(tt0 on X,Y respectively, where

€ b

T(s

s≥0,

€ b

S(t

t≥0are as in Theorem 1. Remark 1. Let us recall the followings.

1. Let X be a normed space and A be a linear operator, A: D(T) ⊆ XX . A subspace Z of the domain D(A) is called a core for A if Z is dense in D(A) for the graph norm kAkA:=kxk+kAxk. [2]

2. A function G :R+2 →Xα Y , is said to be differentiable at (0, 0) if there exists a linear transformationL:R+2→X α Y such that

lim (s,t)(0+,0+)

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In other words,

G(s,t)−G(0, 0) =L (s,t) +R(s,t), where

lim (s,t)→(0+,0+)

kR(s,t)k k(s,t)k =0.

3. The transformation Labove, if it exists, is unique, and it is called the derivative of G at

(0, 0).

4. For a fixed zXα Y , if G(s,t)z= (T(·)S(··))z, then (2) becomes



T(s)α S(t)

‹

zz=L (s,t)z+R(s,t)z, and (2) comes to

lim (s,t)→(0+,0+)

kR(s,t)zk k(s,t)k =0, for all z where (2) holds.

5. If it is shown that for any z satisfying (4), one has the same L(·,··) in (4), then one can consider the derivative as the linear transformation fromR+2 → L



Xα Y

‹

, where

Xα Y

‹

is the space of linear (not necessarily bounded) operators on Xα Y , in the

following sense:

For all z such that (4) holds, there is a linear transformationLb : R+2 → L 

Xα Y

‹

,

where(s,t)7→bL(s,t)such thatLb(s,t)z=L(s,t)z.

6. In case of item 5 holds, if moreover,Lis of the form L1,L2then for any(s,t)R+2the

domain ofLb(s,t)isD sL1+tL2, the domain of sL1+tL2 which isD L1

∩D L2

.

Definition 2. Let(T(s)⊗S(t))s,t0 be a T.P.S. on Xα Y . Theinfinitesimal generator A of (T(s)S(t))s,t0is defined as follows

D(A) =

§

zXα Y :



T(s)α S(t)

‹

z is differentiable at (0, 0)

ª

, Az = D



T(s)⊗α S(t)

‹

z|(s,t)=(0,0) for z∈D(A),

whereD(A)is the domain of A, and D



T(s)α S(t)

‹

z|(s,t)=(0,0) is the derivative of T(s)α S(t)z as a function of two variables at(s,t) = (0, 0).

Lemma 5. A1I xy =

s (T(s)⊗S(t)) xy

|(s,t)=(0,0), and IA2

xy =

∂t (T(s)⊗S(t)) xy

|(s,t)=(0,0) for all x ∈ D(A1), y ∈ D(A2), where A1 and A2 are the

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R. Khalil, R. Al-Mirbati, D. Drissi Eur. J. Pure Appl. Math,3(2010), 881-898 888

Proof. Let x∈D(A1), y∈D(A2). Then

∂s T(s)⊗S(t) xy

|(s,t)=(0,0) = hLim0+

(T(h)⊗S(0)) xy−(T(0)⊗S(0)) xy h

= Lim

h→0+

T(h) I

h x

y

=

Lim

h→0+

T(h)I

h x

y= A1xy.

Similarly forIA2.

Now, Let



T(s)α I

‹

s≥0,

(T(s))s0be one parameterC0semigroups on the Banach spaces Xα Y,X with infinitesimal generatorsA,A1respectively. Then, one can easily see:

a. D(A1)⊗Y is a subspace ofD(A). b. D(A1)⊗Y is dense inX

α

Y. c. D(A1)⊗Y is invariant underT(s)

α

I. d. D(A1)⊗Y is a core forA.

Lemma 6. Suppose that(T(s))s0,(S(t))t0are one parameter C0semigroups on the Banach spaces X,Y with infinitesimal generators A1, A2 respectively. Then A1⊗I and IA2 are the infinitesimal generators of the one parameter C0 semigroups



T(s)⊗α I

‹

s≥0 ,



IαS(t)

‹

t≥0 respectively on Xα Y .

Proof. First letz= xy, for some xy ∈D(A1)⊗Y. IfAis the infinitesimal generator of



T(s)⊗α I

‹

s≥0

, then Az= A1Iz. This means thatA|D(

A1)⊗Y =A1⊗I. In other words,

Ais an extension ofA1I from the subspaceD(A1)⊗Y to the domainD(A)ofA. Being the infinitesimal generator of a one parameter C0 semigroup,Ais closed[9]. ThusAis a closed extension ofA1I. ButA1I is closable[6]. Since the closure of an operator is its smallest closed extension, thenAA1I A1I. On the other hand, by[6],A1I is the maximal extension ofA1⊗I. Therefore AA1⊗I. Hence A= A1⊗I. Similarly, one can show that IA2generates



Iα S(t)

‹

t≥0 .

Theorem 2. The infinitesimal generator of a C0 T.P.S.(T(s)⊗S(t))s,t≥0 is the linear transfor-mation L : R+2 → L



Xα Y

‹

, (a,b)7−→€€A1I,IA2Š(a,b)Š = €aA1I+bIA2Š, where A1, A2are the infinitesimal generators of the one parameter C0semigroups

€ b

T(s

s≥0,

€ b

S(t

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Proof. First, we should notice that L(a,b) xy = aA1I,bIA2 xy for all x ∈D A1,y ∈D A2. Now, Let(T(s)S(t))s,t0be aC0 T.P.S.,Aits infinitesimal genera-tor and letz∈D(A). That is,zXα Y such that



T(s)αS(t)

‹

zis differentiable at(0, 0). ThusD



T(s)⊗α S(t)

‹

z

‹

|(s,t)=(0,0)

exists. In other words, there existz1,z2 inXα Y such that lim

(s,t)→(0+,0+)

k{(T(s)⊗S(t))−T(0)⊗S(0)}zsz1−tz2k

k(s,t)k =0. In particular, choose (s,t) to be (s, 0)where

s→0+. Then lim

s→0+

k{(T(s)S(0))T(0)S(0)}zsz1k

s =0. Therefore,

lim

s→0+

¦€Tb(s)⊗IŠ−II©zsz1

s =slim→0+

¦€ b

T(s)IŠ−II©

s zz1

=0.

From Lemma 6, z1 = €A1IŠz, where A1 generates the C0 semigroup €Tb(ss0. Sim-ilarly, one can show that z2 = €IA2Šz. Since z was arbitrarily chosen in D(A), this shows that D(A) is a subspace of Xα Y. Further, D(A) A1IŠ∩D€IA2Š. Now

letz∈D€A1IŠ∩D€IA2Šands,t>0. Set

J(s,t) = (T(s)⊗S(t))−(T(0)⊗S(0))−€A1I,IA2Š s t

. Then

kJ(s,t)zk =



T(s)⊗αS(t)

‹

(z)−(z) −€sA1⊗I

Š

(z)€t IA2

Š

(z)

≤  b

T(s)⊗α I

‹ 

Iα bS(t)

‹

(z)

−Tb(s)⊗α I

‹

(z)−€t IA2Š(z)

+  b

T(s)⊗α I

‹

(z)−(z)−€sA1IŠ(z)

t  b

T(s)⊗α I

‹ Iα

⊗bS(t) ‹

(z) 

IαI

‹ (z)

t

!

−€IA2Š(z)

+s   Tb(s)

α

IIα I s

 

(z)€A1⊗I

Š

(z)

.

Divide both sides byk(s,t)k=ps2+t2 to get kJ(s,t)zk

k(s,t)kψs,t

 b

T(s)α I

‹ 1

t



IαSb(t)



Iα I

‹‹

−€IA2

Š

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R. Khalil, R. Al-Mirbati, D. Drissi Eur. J. Pure Appl. Math,3(2010), 881-898 890

+φs,t

1

s

 b

T(s)α IIα I

‹

−€A1IŠ(z)

,

whereψs,t= p t

s2+t2,φs,t=

s

p

s2+t2. Butψs,t≤1,φs,t≤1 for alls,t >0. Therefore,

kJ(s,t)zk k(s,t)k



b

T(s)α I

‹ 1

t



Iα bS(t)



Iα I

‹‹

−€IA2Š(z)

+

1

s

 b

T(s)⊗α IIα I

‹

−€A1IŠ(z)

,

As (s,t) → 0+, 0+, the second norm in the right hand side converges to zero, whereas the first norm converges to zero by Lemma 6, the strong continuity of

 b

T(s)α I

‹

s≥0, and the uniform boundedness principle. Therefore, kJk((ss,,tt))kzk →0 as(s,t)(0+, 0+). Now, define

L:R+2→ L(XαY)by(L(s,t))z=€€A1⊗I,IA2

Š s

t

Š

zfor everyz∈D€€A1IŠ s

t

Š

D€€IA2Š stŠ=D€€A1IŠŠ∩D€€IA2ŠŠ. Then D(T(s)S(t)) |

(s,t)=(0,0)

= (A1I,IA2), as a linear transformation fromR+2 toL(Xα Y) is the derivative of the C0 T.P.S.(T(s)⊗S(t))s,t≥0 at(0, 0). Hence the linear transformation

L=€A1I,IA2Šis the infinitesimal generator of theC0 T.P.S.(T(s)S(t))s,t0.

Remark 2. One can show that for any nonzero (a,b) ∈R+2, D A1⊗D A2 is a core for

€

A1I,IA2Š a

b

.

1. In general, if A,B are closable, or even, closed linear operators on the Banach space X , then A+B need not be closed. But, Theorem 1.1 in[5]ensures that aA1⊗I+b,IA2, a,b6=0 is closable. Moreover, its closure is aA1I+bIA2.

2. Since the restriction ofL(a,b)to XY is defined by

L(a,b) xy= aA1I+bIA2 xy= A1I+IA2

a

b

xy,

for all x ∈D A1,y ∈D A2, and since XY is dense in Xα Y , it is enough to study

T(s)⊗S(t)instead of its extension T(s)⊗α S(t), and A1I+IA2 a

b

instead of its

closure€A1⊗I,IA2

Š a

b

.

From now on, the infinitesimal generator of(T(s)S(t))s,t0will be denoted by

€

A1I,IA2Š.

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The proof follows from general functional analysis arguments and will be omitted. Lemma 8. If(T(s)⊗S(t))s,tois a C0 T.P.S. on Xα Y , then for every(a,b)∈R+2, the family (T(as)⊗S(bs))sois a one parameter C0semigroup on the Banach space Xα Y .

Proof. LetQ(h) =T(ah)S(bh). ThenQ(0) =I, whereI is the identity onXY, and Q(h1+h2) = T ah1S bh1 T ah2S bh2

= Q(h1)Q(h2).

Put bh=t,ah=s. Since

h→0+if and only ifs=ah→0+if and only if t=bh→0+,

then the functionQ(h) =T(s)S(t)converges toIash→0+in the strong operator topology. Lemma 9. Let 0 6= (a,b) R+2. Then the infinitesimal generator of the one parameter C0 semigroup(T(as)S(bs))sois the linear operator

aA1I+b,IA2.

Proof. The generator of the one parameter semigroup(T(as)⊗S(bs))sois given by d+

ds (T(as)⊗S(bs))|s=0 =

d+

ds (T(as)⊗I) (IS(bs))|s=0

= d

+

ds

€ b

T(as)IŠ €I⊗bS(bs

|s=0.

Being the derivative of a function of one variable ats=0, the derivative is

‚

d+ ds

€ b

T(as)IŠ

|s=0 Œ

€

IbS(0)Š+€Tb(0)IŠ

‚

d+ ds

€

ISb(bs

|s=0 Œ

= a

‚

d+ d(as)

€ b

T(as)⊗IŠ

|s=0 Œ

(II) + (II)b

‚

d+ d(as)

€

I⊗bS(bs

|s=0 Œ

(1)

and this is justaA1⊗I+b,IA2.

Corollary 1. The linear operator aA1⊗I+b,IA2 is closed and densely defined.

Corollary 2. For every 0 6= (a,b) R+2 the linear operator aA1I+ b,IA2 is closable, densely defined and its closure is aA1I+b,IA2.

Proof. Being closable is proved in[6]. Since

D aA1I+b,IA2

= D A1YX⊗D ,A2

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R. Khalil, R. Al-Mirbati, D. Drissi Eur. J. Pure Appl. Math,3(2010), 881-898 892

and since A1,A2 are densely defined in X, Y respectively, one can show that the subspace

D A1⊗D ,A2is dense inXY, which is in turn dense inXα Y. ThusaA1I+b,IA2 is densely defined onXα Y. So

€

aA1I+b,IA2Š xy= aA1I+b,IA2 xy, for all xy∈D A1⊗D ,A2. That is

€

aA1I+b,IA2Š

|(XY)∩D(aA1⊗I+b,IA2)=aA1⊗I+b,IA2.

Therefore,B=aA1I+b,IA2is an extension ofA=aA1I+b,IA2from the subspace

D A1⊗D ,A2

toD(B). From Corollary 1,Bis a closed extension ofA. SinceAis closable, and the closure is the smallest closed extension, AB. On the other hand, Ais closable, and the closure of a closable operator is its maximal extension. Thus BA. Hence A= B completes the proof of the corollary.

Corollary 3. Let(T(s)⊗S(t))s,t0be a C0T.P.S. on Xα Y , with infinitesimal generator

€

A1I,IA2Šand06= (a,b)R+2. Then the infinitesimal generator of the one parameter C0 semigroup(T(as)⊗S(bs))sois the linear operator aA1⊗I+b,IA2=a A1⊗I

+b IA2

.

As a consequence of Corollary 3, we obtain Nagel’s result[1, Proposition, Sec. 3.7]. Corollary 4. The infinitesimal generator of the one parameter C0 T.P.S. (T(t)⊗S(t))t≥0, is (A1I) + (IA2)defined on the coreD A1D A2of the generator.

Proof. From Corollary 3 the operator

a A1I+b, IA2=a A1I+b IA2 generates(T(at)S(bt))t0. As a particular case take(a,b) = (1, 1). Then

A1I+ IA2

is the infinitesimal generator of the one parameter C0 semigroup (T(t)⊗S(t))t≥0. But A1I+ IA2 is defined onD A1⊗D A2, which is a core for the infinitesimal gen-erator A1I+ IA2

Definition 3. Let(T(s))s0and(S(t))t0be one parameter C0semigroups on the Banach spaces X and Y respectively. For u= (a,b)∈R+2, thealmost directional derivativea.Duof

T(s)⊗S(t)at(0, 0)is defined by

D ‚

a.Du



T(s)α S(t)

‹

|(s,t)=(0,0)

Œ

=

  zX

α

Y : lim

h→0+

T(ah)⊗α S(bh)zz

h exists

(13)

and

‚ a.Du



T(s)⊗α S(t)

‹

| (s,t)=(0,0)

Œ

z= lim

h→0+

(T(ah)α S(,bh))zz h

It follows from the definition that the almost directional derivativea.Du 

T(s)α S(t)

‹

|(s,t)=(0,0)

is the infinitesimal generator of the one parameterC0semigroup(T(at)⊗S(,bt))t0. Further, foru= (a,b)∈R+2,a.Du(T(s)⊗αS(t)) |

(s,t)=(0,0)

aA1I+bIA2Š=a A1I+b IA2. Also, since∇(T(s)S(t)) =

∂sT(s)⊗S(t)i+

∂tT(s)⊗S(t)j, then foru= (a,b)∈R

+2

a.Du(T(s)⊗α S(t)) | (s,t)=(0,0)

=∇T(s)⊗S(t) |

(s,t)=(0,0)

.u.

Theorem 3. Let(T(t))t0 and(S(t))t0 be one parameter C0semigroups on Banach spaces X and Y with infinitesimal generators A1 and A2respectively. Then

D(T(s)S(t))

a b

xy= A1I,IA2

a b

(T(s)S(t)) xy (2) for all(a,b)∈R+2, all x∈D A1and y∈D A2.

Proof. Let(a,b)R+2, x ∈D A1, and y∈D A2. ThenD(T(s)S(t))as a function of two variables is given by

(D(T(s)⊗S(t)))

a

b

xy

=

∂s(T(s)⊗S(t)),

∂t (T(s)⊗S(t)) a

b

xy

=

a∂

∂s(T(s)⊗S(t)) +b

∂t (T(s)⊗S(t))

xy

=

ad(T(s)⊗I)

ds (IS(t)) +b

d(IS(t))

d t (T(s)⊗I)

xy. Then, by Lemma 2-c, Theorem 2 and Lemma 6 we have

(D(T(s)S(t)))

a

b

xy

= a”€A1IŠ(T(s)IxS(t)y

+b”€,IA2Š(IS(t))— T(s)xy

= a A1I T(s)xS(t)y+b ,IA2 T(s)xS(t)y = A1I,IA2

a

b

(T(s)⊗S(t)) xy. which is (2).

As in the classical case, one can show the existence of constants ω≥0 and M ≥1 such that

T(s)⊗α S(t)

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R. Khalil, R. Al-Mirbati, D. Drissi Eur. J. Pure Appl. Math,3(2010), 881-898 894

4. The Hille-YosidaTheorem for T.P.S’.

Definition 4. Let X and Y be Banach spaces and A be a linear transformation that mapsR+2

intoL



Xα Y

‹

given by A= (A1⊗I,IA2), where A1, ,A2 are linear operators on X and Y respectively, satisfying:

a. For any(a,b)R+2

A

a

b

xy= (aA1I,+bIA2) xy,

x ∈D A1, y∈D A2.

b. A is the infinitesimal generator of a C0 T.P.S.(T(s)⊗S(t))s,t0.

Then we call the linear transformation B= (A1⊗I,IA2)thepseudo-infinitesimal generator of(T(s)⊗S(t))s,t0.

We should remark that uniqueness of the closure of a linear operator, and uniqueness of the infinitesimal generator of a T.P.S. imply that the pseudo-infinitesimal generator of a T.P.S. is unique.

Now, we are ready to prove one of the main results of this section (A Hille-Yosida Theorem for T.P.S.’).

Theorem 4. Let X,Y be Banach spaces. A linear transformation A fromR+2 intoL 

Xα Y

‹

is the pseudo-infinitesimal generator of a C0T.P.S.(T(s)⊗S(t))s,t0on Xα Y satisfying

kT(s)⊗S(t)k ≤ M eω(s+t), for all s,t ≥0, for some constants M ≥1,ω≥0, if and only if the followings hold

(i) €A 01Š xy= A1xy, and€A 10Š xy=xA2y,x ∈D A1, y∈D A2 for some linear operators A1,A2 (not necessarily bounded) on X,Y respectively.

(ii) A1,A2in part (i) are closed and densely defined on X,Y respectively. (iii) ρ(Ai)contains(ω,∞), i=1, 2, and for everyλ > ω

(Ai)

n

(λMωi )n,n=1, 2, 3, . . . , for some Mi≥1,i=1, 2.

Proof. Let the conditions (i), (ii) and (iii) hold. From (ii), (iii) and Theorem 1.7 in

[1] A1,A2 are the infinitesimal generators of one parameter C0 semigroups say (T(s))s0, (S(t))t0on X,Y respectively, satisfying

kT(s)k ≤M1eωs for alls≥0, and kS(t)k ≤M2eωt for allt≥0. By Theorem 1(T(s)S(t))s,t0is aC0T.P.S. onX

α

(15)

M1M2(s+t)

= M eω(s+t), for alls,t ≥0.

By Theorem 2, the transformation A1I,IA2 is the pseudo-infinitesimal generator of T(s)S(t). Let(a,b)R+2, xD A1, yD A2. Then

A1⊗I,IA2

a

b

xy= aA1⊗I+bIA2

xy, which is by (i),

aA

0

1

+bA

1

0

xy=

A

a

b

xy. ThereforeA a

b

coincides with A1I,IA2 a

b

onD A1⊗D A2for every(a,b)∈R+2, thus their closures coincide.

But the transformation mapping (a,b) R+2 into A ab= A1I,IA2 ab is the in-finitesimal generator of(T(s)⊗S(t))s,t0(See Theorem 2, and Corollary 2). In other words, A abis the pseudo-infinitesimal generator of(T(s)S(t)).

Conversely, letAbe as in the statement. SinceT(s)S(t)is aC0 T.P.S., then by Theorem 1 there exist uniqueβ 6=0, and unique one parameterC0 semigroups€Tb(s

s≥0,

€ b

S(t

t≥0 onX,Y respectively, such that (1) holds. LetA1,A2 be their generators. Then by Theorem 2, A1,A2satisfy (i) and (ii). By Theorem 2 and Corollary 2, the transformation

(a,b)7→ A1I,IA2

a

b

A1I,IA2Š a b

is the infinitesimal generator ofTb(s)⊗Sb(t). ButTb(s)⊗bS(t) =T(s)⊗S(t). Thus A1I,IA2 is the pseudo-infinitesimal generator ofT(s)⊗S(t).

Uniqueness of the pseudo-infinitesimal generator, implies that the linear transformation A1I,IA2=A. That isA ab= A1I,IA2 abfor all(a,b)inR+2. In particular, for (a,b) = (0, 1), and(a,b) = (1, 0). Hence (i) is fulfilled.

Theorem 5. Let X,Y be Banach spaces, and(T(s)S(t))s,t0be a C0T.P.S. on the Banach space Xα Y with infinitesimal generator A= (A1⊗I,IA2). Ifλρ

€

(A1⊗I,IA2) ab

Š

, where

(a,b)∈R+2, andλ >(a+b)max

i=1,2 ω(Ai)

, where0< ω(Ai)∈ρ(Ai), for i=1, 2, then

(A1⊗I, ,IA2)

a

b

xy=

∞ Z

0

eλt(T(at)S(bt)) xyd t. (3)

Proof. Let xX, yY,(a,b)R+2, andλbe as given. Define

R(λ) xy=

∞ Z

0

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R. Khalil, R. Al-Mirbati, D. Drissi Eur. J. Pure Appl. Math,3(2010), 881-898 896

Since the map t 7→(T(at)⊗S(bt)) xyis continuous andλ >(a+b)max

i=1,2 ω(Ai)

, the integral exists as an improper Riemann integral and defines a bounded linear operator on XY. Further, forh>0

T(ah)S(bh)II

h R(λ) xy

= 1 h ∞ Z 0

eλt(T(a(t+h)⊗S(b(t+h)) xy−(T(at)⊗S(bt)) xyd t

= 1 h       ∞ R h

eλ(th)(T(at)⊗S(bt)) xyd t

−R∞ 0

eλt(T(at)S(bt)) xy,d t

      = e λh h ∞ Z h

eλt(T(at)⊗S(bt)) xyd t−1 h

∞ Z

0

eλt(T(at)⊗S(bt)) xy,d t

= e

λh1

h

∞ Z

0

eλt(T(at)S(bt)) xyd te

λh

h

h

Z

0

eλt(T(at)S(bt)) xyd t.

Taking the limit of both sides ash→0+yields

(A1I,IA2)

a

b

R(λ) xy=λR(λ) xyxy. This implies that

R(λ) xyD

(A1I,IA2)

a

b

for allxy XY,

and

λII−(A1I,IA2)

a

b

R(λ) =II onXY. Now, for xy∈D€(A1I,IA2) baŠ⊆D€(A1I,IA2) abŠwe have

R(λ)

(A1I,IA2)

a

b

x y

=

∞ Z

0

eλt(T(at)⊗S(bt))

(A1I,IA2)

a

b

xy,

d t = ∞ Z 0

eλt€A1⊗I,IA2

Š a b

(17)

by Theorem 3. Since(A1I,IA2) abis closed by Corollary 2, it follows that the right-hand side of (3) is

€

A1I, ,IA2Š a b

Z∞

0

eλt(T(at)⊗S(bt)) xyd t

= (A1⊗I,IA2)

a

b

R(λ) xy.

Hence,

R(λ)

λI

(A1I,IA2)

a

b

xy= xy, for allxy ∈D€(A1⊗I,IA2) ab

Š

∩(XY). Since by Corollary 1 the domain

D€(A1⊗I,IA2) ab

Š

is dense inXα Y, then

R(λ)

λI−(A1⊗I,IA2)

a

b

=I,

where Iis the identity map onXα Y.

References

[1] W. Arendt, Grabosch, A. Greiner, G., Groh, U., Lotz, H. P., Moustakas, U., Nagel, R., Neubrander, F., and Schlotterbeck, U. One Parameter Semigroups of Positive Operators (edited by R. Nagel). Lecture Notes in Mathematics, 1184. Springer-Verlag. 1986.

[2] K.J. Engel, and R. Nagel. One Parameter Semigroups for Linear Evolution Equations. New York: Springer-Verlag. 2000.

[3] J. Goldstein. Semigroups of Linear Operators and Applications. New York: Oxford Uni-versity Press. 1985.

[4] E. Hille, and R. S. Phillips. Functional Analysis and Semigroups. Rhode Island: Amer. Math. Soc. Colloq. Publi. 31, Providence. 1957.

[5] T. Ichinose. On the spectra of tensor products of linear operators in Banach spaces. J. Reine Angew. Math., (244): 119 - 153 .1970.

[6] T. Ichinose. Operators on tensor product of Banach spaces. Transactions of The American Mathematical Socociety, 1(70): 197 - 219. 1972.

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[8] W. A. Light, and E. W. Cheney. Approximation theory in tensor product spaces, Lecture notes in maths., 1169. Springer-Verlag .1985.

[9] A. Pazy. Semigroups of Linear Operators and Applications to Partial Differential Equa-tions, Lecture notes, University of Maryland. 1974.

References

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