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SOME ASPECTS OF MODULES OVER A RING AND ITS COLORINGS
K. C. Chowdhury and Prohelika Das*
Department of Mathematics, Gauhati University, Guwahati-781014, Assam, India
E-mail: [email protected], [email protected]
(Received on: 24-08-11; Accepted on: 11-09-11)
________________________________________________________________________________________________
ABSTRACT
I
n this paper we investigate some graph theoretic aspects of modules, in particular coloring of its vertices. In our discussion especially we have dealt here the cases of finite dimensional modules and in some cases some sort of finiteness conditions on its annihilators. Results obtained here are basically on its finite cliques and chromatic numbers.Key words: Annihilators, Nil-radical, Goldie ring, Goldie module,
f
-clique,f
-chromatic number.AMS Subject Classification2000:16D10, 16D80, 16Y30, 16Y60, 15N40, 16P60, 05C15.
________________________________________________________________________________________________ 1. INTRODUCTION
Here we investigate some graph theoretic aspects related to coloring of elements of modules over a ring introducing the notion of adjacency in between its elements. In an additive algebraic structure, the notion of a product is not well acceptable. In-stead, of course, there may arise such an operation with the help of another structure equipped with two operations, one of them bearing the nature of so-called product. And the same may be obtained when we be able to give an external composition to the preceding algebraic structure with the help of the later one. If
M
is with such an additive structure andA
is theother one with operation ‘•’, at least bearing the semi-group character such that we have the map :M
×
A
→
M
with(
m
,
a
)
→
m
⋅
a
( we will write it as just ma), then for a mapf
:
M
→
A
, it is possible to define a product'
•
f'
such that fora
,
b
∈
A
,
a
•
fb
=
a
⋅
f
( )
b
( or justaf
( )
b
). The system(
M
,
+,
•
f)
is now our sought structure for having a system with the chosen
M
with a pseudo product•
f . And this motivatesus to define the notion of so-called adjacency between two elements in the chosen algebraic structure, in spite of absence of such an explicit product operation beforehand. And such an arrangement may help one to make his stage ready for investigation of the adjacency character of elements in the said algebraic paired structure (with one operation only). For such an algebraic structure our expected graph is the triplet
(
V
,
E
,
f
)
withV
as the set of vertices-theelements of
M
,
E
-the set of edges where fora
,
b
(
∈
M
)
, “a
is f-adjacent tob
”ifa
•
fb
=
0
( or ‘a and b are f-adjacent’) .The pseudo product described here may coincide with the product available in
R
whenM
coincides with the ringR
with respect to some definite mapf
( in particular the identity map) . The technique explored here elegantly appears as an effective one for introducing the notion of coloring in case of the module in discussion.It is observed here some interesting and elegant connections between finiteness of the chromatic number of such a graph and the notion of a so-called Goldie module [4] which reads as a
module
M
over a ringR
where,(1)
M
is finite dimensional(2)
R
Satisfies the ascending chain condition (acc.) for annihilators of subsets ofM
inR
.i.e. any collection of annihilators of subsets of
M
inR
satisfies the maximal condition.First we give some interesting facts revealing the interrelation between such a module and the corresponding
f
-algebraic triplet, when the latter structure appears as a result of an attachment of respective order preserving map
f
. ________________________________________________________________________________________________Page: 1723-1733
" # $ % # % & '
In this context we would like to refer Chartrand et al [3] and Chowdhury [5], [9] for graph and near-ring theoretic pre-requisites. Moreover we refer the works of Beck [1], Bruijn et-al [2] for coloring of rings.
It is to be mentioned that the results due to A.W. Goldie on the structure of semi-prime rings [7], [8] seem to be still relevant due to its elegancy.
If
M
is a right module overR
(denotedM
R) and iff
:
M
→
R
is anR
-homomorphism, then the triple(
M
,
+
,
•
f)
wherem
i•
fm
j=
m
if
( )
m
j is a ring. We call it an h-ring denoteM
f .Unless otherwise specified,through out this paper
M
(orM
R ) will mean a right module overR
andf
is anR
-homomorphism fromM
toR
.A module
M
R is an f- color- module if the f-chromatic number [§ 3][ denotedχ
(
M
f)
] of the corresponding h-ringf
M
is finite .The main results of this paper are dealt here from two main aspects viz. h-ring and that of coloring of module such as:A sub-module of the module appears as a right ideal of the corresponding h-ring structure of the same. The h-ring
structure of a module
M
R gives rise to the h-ring structure of the quotient ofM
modulo an ideal contained in thekernel of the map induced by the preceding map
f
.M
R is a right Goldie module if and only if the corresponding h- ring is right Goldie. Prime character of a sub-module modulo the kernel of the homomorphism leads to the prime character of the image sub-module of the ring as a module over itself .Pseudo product defined with the help of just a mapf
from the moduleM
R to the ringR
gives rise to an abelian near-ring structure. A group structure is sufficientto make it into a right near ring with respect to the pseudo- product defined. Occurrence of infinite number of
f
-rightfinite elements in a module
M
R is a sufficient condition for having an infinitef
-clique in it. An infinitef
-clique in an h-ring helps to get such an induced clique in the quotient modulo the kernel and conversely .The existence of aninfinite
f
-clique in a module is a necessary condition for containing a nilpotent element in the h-ringM
f .A finite dimensional module turns out to be a right Goldie h- ring if it is with only finitef
-cliques. An h-ring originated from afinite dimensional
f
-color module is a right Goldie ring .Thef
-chromatic number of the h-ring never exceeds thei
-chromatic number of the attached ringR
ii.e.R
(In the sense of Beck [1]). In case of anf
-color-moduleM
R, theh-ring
M
f modulo right annihilator of any subset ofM
is aψ
-color-module, (ψ
is induced byf
).2. EXAMPLES AND OBSERVATIONS
The following examples justify how different types of f-maps helps one to get various types of algebraic structures such as right near ring ,left nearing, semi ring, semi-near ring etc from some given once.
Example: 1 Consider the module
Z
[ ]
x
over the ringZ
. Definef
:
Z
[ ]
x
→
Z
by= =
=
ni i n
i i
i
x
a
a
f
0 0
, ,
then
(
Z
[ ]
x
,
+
,
•
f)
is a ring. HenceZ
[ ]
x
is anh-ring.Example: 2
Z
30[ ]
x
is an additive abelian group of polynomials overZ
30 .Then(
Z
30[ ]
x
,
+
,
)
is a right nearing where’ ’is defined as the composition of mappings .ThenI
6[ ]
x
is an additive subgroup ofZ
30[ ]
x
where{
0
,
6
,
12
,
18
,
24
}
6
=
I
.LetN
=(
Z
30[ ]
x
,
+
,
)
andG
=(
I
6[ ]
x
,
+
)
.NowG
is anN
-subgroup ofN
. DefineN
G
→
:
φ
byφ
( )
g
=
2
g
.Then(
G
,
+,
•
φ)
is a right near-ring .ThusG
is aφ
-right near-ring.Example: 3 Consider the semi group
( )
G
,
⋅
whereG
=
1 1
1 1 , 0 1
1 0 , 1 0
0 1 , 0 0
0 0
.
Let =
0 0
0 0
0
A , =
1 0
0 1
1
A , =
0 1
1 0
2
A , =
1 1
1 1
3
Page: 1723-1733 Here
And
(
Z
2,
+
,
⋅
)
is a ring. We definef
:
G
→
Z
2 byf
( )
A
=( )
a
11 whereA
=
( )
a
ij .Here
•
fis right distributive but not left distributive. Hence(
G
,
⋅,
•
f)
is a semi near-ring (right)Thus
G
isf
-semi near-ring (right).Note:
(1) If we define
f
:
G
→
Z
2 byf
( )
A
=det
( )
A
whereA
=
( )
a
ij then(
G
,
⋅,
•
f)
is a semi near-ring (right).(2) If we define
f
:
G
→
Z
2 byf
( )
A
=traceA
orf
( )
A
=a
ij whereA
=
( )
a
ij .Then(
G
,
⋅,
•
f)
is a semi-ring.[Here
traceA
=0 anda
ij=0 asa
ij∈
Z
2 ]Example: 4 Let
R
be a ring andM
= a b c d∈Rd c
b a
, , ,
| .Then
M
is a module overR
.Definef
:
M
→
R
by
f
( )
A
=
traceA
.Then'
•
f'
is both left and right distributive .Thus(
M
,
+,
•
f)
is a ring. ThusM
is an h-ring.Example: 5 Let
R
be a ring .ThenR
is a module over itself. Consider a mapf
:
R
→
R
defined asf
( )
x
=
2
x
. Then'
•
f'
is both left and right distributive. Thus(
R
,
+,
•
f)
is a ring. HenceR
is an h-ring.Note: In a given ring we can insert a number of rings.
Example: 6 Consider the group
G
=
{
0
,
a
,
b
}
under the addition defined by the following table.+ 0 a b 0 0 a b a a b 0 b b 0 a
And let the set N = M
( )
G = α |α :G→
map G .We defineφ
:
G
→
N
by. 0 a b
( )
0
α
1φ
=
0 0 a( )
α
2φ
a
=
0 a 0( )
α
3φ
b
=
a 0 0Then only two colors are needed to color the vertices of
(
G
,
+
,
•
φ)
. Thusχ
(
G
,
+
,
•
φ)
is 2. Ifφ
:
G
→
N
, defined by. 0 a b
( )
0
α
1φ
=
0 0 0( )
α
2φ
a
=
a a a( )
α
3φ
b
=
b b b.
0
A
A
1A
2A
30
A
A
0A
0A
0A
01
A
A
0A
1A
2A
32
A
A
0A
2A
1A
33
Page: 1723-1733
" # $ % # % & )
Then
(
G
,
+
,
•
φ)
is a left near-ring .Only one color is needed to color the vertices of(
G
,
+
,
•
φ)
.Thus(
φ)
χ
G
,
+
,
•
is 1.Example: 7 We consider
R
=
Z
6=
{
0
,
1
,
2
,
3
,
4
,
5
}
.f
:
R
→
R
byf
( )
x
=
2
x
.Then(
R
,
+,
•
f)
is a ring. We needonly three colors to color the ring
(
R
,
+
,
•
f)
.Thusχ
(
R
f)
=
3
.If we defineg
:
R
→
R
byg
( )
x
=
3
x
, then onlyfour colors are needed to color the ring
(
R
,
+,
•
g)
.Thusχ
(
R
g)
=
4
.If we consider the identity mapi
:
R
→
R
, weneed three colors to color the ring
(
R
,
+,
•
i)
.Thusχ
(
R
i)
=
3
.3. PRELIMINARIES
Definitions: The graph of the module
M
is the triplet(
V
,
E
,
f
)
where the elements of the moduleM
is the setV
of vertices,E
is the set of edges andf
is anR
-homomorphism from a moduleM
Rto the moduleR
R.Anelement
x
(
∈
M
)
isf
-adjacent toy
ifx
•
fy
=
0
or we call it “x
andy
are f-adjacent ’’(clearly such a graph isa directed one ) .Two elements “
x
andy
aref
- adjacent to each other” ifx
•
fy
=
0
=
y
•
fx
. Ifx
andy
arenot distinct then
(
x
,
x
)
is anf
- loop .A subsetC
(finite / infinite) ofM
is anf
-clique if any two elements ofC
aref
-adjacent to each other. Thus pseudo product of any two distinct element ofC
vanishes. The minimum numbers of colors which can be assigned to the elements ofM
so that no two f- adjacent elements have same color is thef
-chromatic (denotedχ
(
M
f)
) number ofM
. A moduleM
is an f-color module if thef
- chromatic number of thecorresponding h- ring
M
f is finite.If
χ
(
M
f)
=
n
, whatever be the choice of theR
-homomorphismf
(≠
0
)
, then n is the chromatic number of the moduleM
denotedχ
( )
M
=
n
One may interestingly note here that chromatic number of a ring, what Beck has insisted [1] need not be unique. The
χ
( )
R
in the sense what Beck has meant is nothing but ourχ
( )
R
i wherei
:
R
→
R
is the identity homomorphism.A module
M
R is said to be prime if for any sub-moduleN
R ofM
RAnn
(
M
R)
=
Ann
(
N
R)
. TheM
divisor ofR
is
Z
(
M
)
=
{
r
∈
R
|
mr
=
0
,
for
some
non
zero
m
∈
M
}
.Associated prime ofM
Is( )
M
{
P
P
Ann
( )
S
S
M
}
Ass
=
|
=
i,
i⊆
WhereAnn
( )
S
i is a prime ideal ofR
. An elementx
inM
is f-left-finite(f-right- finite) if
M
•
fx
(x
•
fM
) is finite. Nil radical of a ringR
is the intersection of all prime ideals ofR
.Aring
R
is reduced if nil-radicalJ
=
(
0
)
. It is to be noted that in case of a non-commutative ringR
, for everyR
rR
R
r
∈
,
=
thenR
is a division ring. On the other hand, one can say in case of a division ringR
,aR
=
R
for allR
a
∈
. More generally one would like to note as Dheena [6] has introduced the notion of a Duo-Near-ring (sub-commutative) which may be considered as analogous to what has been mentioned above. This justifiably motivates us as it is seen in a case of a near-ring [6] to give the notion of the left (right) sub-commutativity in a ringR
is as follows. A ringR
is left-sub commutative if fora
,
b
∈
R
we haved
∈
R
such thatab
=
da
(right sub- commutative if fora
,
b
∈
R
we havec
∈
R
such thatab
=
bc
) . The ringR
is sub-commutative, if fora
,
b
∈
R
we haveR
d
c
,
∈
such thatab
=
bc
=
da
.The number of elements in a set is denoted by # here.Lemma: 3.1 If
M
is a module overR
andf
:
M
→
R
is anR
-homomorphism, then(
M
,
+
,
•
f)
where( )
j i j fi
m
m
f
m
m
•
=
is a ring.Note:
Page: 1723-1733
(2) Normally such an h-ring is not commutative. It is easily observed that in case of a PID
D
iff
:
D
→
D
is aD
-homomorphism with (say)f
( )
x
=
mx
,
(
m
∈
D
)
, thenD
f is commutative. It happens to be true for any suchf
.(3) If even the ring
R
does not contain unity 1, yet whenM
is anR
-module,M
f may contain its unity. Followingexplanation justifies what we have meant.
Let
R
=
{
(
2
m
,
2
n
)
/
m
,
n
∈
Z
}
.Then(
R
,
+
,
⋅
)
is a commutative ring and is without unity such that for(
2
m
,
2
n
) (
,
2
a
,
2
b
)
∈
R
,(
2
m
,
2
n
) (
+
2
a
,
2
b
)
=
(
2
(
m
+
a
) (
,
2
n
+
b
)
)
and(
2
m
,
2
n
) (
⋅
2
a
,
2
b
) (
=
2
ma
,
4
nb
)
. Now(
Z
,
+
)
is a module overR
with the mapZ
×
R
→
Z
where(
)
m
Z
m
2
α
,
2
β
=
α
∈
It is easy to see that form
,
n
∈
Z
and(
2
,
2
n
)
∈
R
,m
(
2
,
2
n
)
=
m
.i.e.
R
has no unity, but(
2
,
2
n
)
=
e
∈
R
is such thatme
=
m
∀
m
∈
Z
.Thuse
acts as a right unity for the moduleZ
over the ringR
.For anyn
∈
Z
it is true. Nowf
:
Z
→
R
withf
( ) (
m
=
2
m
,
0
)
is an -homomorphism. Andfor 1∈Z, we have
m
•
f1
=
mf
( )
1
=
m
( )
2
,
0
=
m
∀
m
∈
Z
.Thus 1∈Z acts as the unity in( )
Z
f //(4) When
f
=
I
-the identity map and the attached ring is commutative then the h-ringM
f is commutative.Lemma 3.2: Let
M
be a module over a ringR
andf
:
M
→
R
is anR
-homomorphism. IfN
R is a sub-module ofR
M
thenG
is a right ideal ofM
f .Proof: Here for
n
1,
n
2∈
N
,n
1+
n
2∈
N
.And for,n
∈
N
andm
∈
M
,n
•
fm
=nf
( )
m
∈
N
.ThusN
is aright ideal of
M
f .Note: It is not safe to claim that for
N
- a right ideal ofM
f , we should get the corresponding additive group(
N
,
+
)
asa sub-module of
M
R However the following result reveals that our claim become true obviously iff
is onto. For,N
n
n
N
n
n
1,
2∈
R,
1+
2∈
And,n
∈
N
,
r
∈
R
givesnr
=
nf
( )
m
=
n
•
fm
∈
N
.Thus(
N
,
+
)
is a sub-moduleof
M
R .Lemma 3.3: Let
M
be a module over a ringR
andf
:
M
→
R
is anR
-homomorphism. Then for any subset(
)
M
S
≠
φ
⊆
,S
•
fM
is a sub-moduleM
RThe following lemma follows immediately from the ring structure of
M
f makingN
M is a (right)
f
M module.
Lemma 3.4: Let
N
R be a sub-module ofM
R.ThenN
M is a (right)
f
M
-module.Lemma 3.5 (a): Let
N
Rbe a finite sub-module of the moduleM
R.ThenAnnx x
N: is a finite
R
-module.[
N
:
x
={
r
∈
R
|
xr
∈
N
}
].Lemma 3.5(b): Let
N
Rbe a finite sub-module ofM
R .Then)
(
:
x
r
x
N
f
M
is finite with respect to the ring
f
N
. [N
f:
x
=
{
m
∈
M
|
x
•
fm
∈
N
}
].Page: 1723-1733
" # $ % # % & *
(
) ( )
{
m
∈
M
|
x
+
N
f
m
=
N
}
={
m
∈
M
|
(
xf
( )
m
+
N
)
=
N
}
={
m
∈
M
|
xf
( )
m
∈
N
}
={
m
∈
M
|
x
•
fm
∈
N
}
=N
:
x
.Now the mapr
M(
x
N
)
x
fr
Mf(
x
N
)
f
+
→
•
+
:
φ
Defined by
φ
( )
α
=
x
•
fα
is an epimorphism and( )
r
( )
x
f
M
=
φ
ker
.Therefore
(
)
)
(
)
(
N
x
r
x
x
r
N
x
r
f f f M f M M+
•
≅
+
.Now
x
r
(
x
N
)
f M f
+
•
)}
(
|
{
x
m
m
r
x
N
f
M
f
∈
+
•
=
xf
( )
m
m
r
x
N
N
f
M
+
⊆
∈
=
{
|
(
)}
[Since gives
m
∈
N
:
x
.Thusx
•
fm
∈
N
i.e.xf
( )
m
∈
N
] Therefore the result follows sinceN
is finite //Lemma 3.6: Let the module
M
R be with an infinite numbers off
-right-finite elements. ThenM
contains an infinitef
-clique.Proof: Let
x
1,
x
2,...
be differentf
-right-finite elements inM
. Then the elementsx
1•
fx
2,...,
x
1•
fx
nbelongto the finite right ideal
x
1•
fM
.Now for some infinite subsequence an of {2, 3… n…} we havex
1.
fx
a1 =x
1.
fx
a2=……..Consider the sequence
x
a1,
x
a2,...
and repeat the procedure. Continuing in this way we construct asubsequence
y
1,
y
2,....,
y
n,...
of the sequencex
1,
x
2,...
such thaty
i•
fy
j=
y
i•
fy
k wherei
,
j
>
k
.In thissubsequence
1
2 1
1
x
,
y
x
ay
=
=
…..etc. Putz
ij=
y
i−
y
j.Nowz
ij•
fz
kr=
z
ijf
( )
z
kr =(
y
i−
y
j)
f
(
y
k−
y
r)
=
(
y
i−
y
j)
(
f
( )
y
k−
f
( )
y
r)
=y
if
( )
y
k−
y
if
( )
y
r−
y
jf
( )
y
k+
y
jf
( )
y
r =0.We shall now construct an infinitef
-cliqueofWe consider
z
1,2•
fz
3,4=
z
1,2•
fz
3,5=0.Since,z
1,2≠
z
3,5, at least one ofz
3,4andz
3,5 is different Fromz
1,2. Iffor instance
z
1,2≠
z
3,5 then{
z
1,2,
z
3,5}
is anf
-clique with two elements. We observe thatz
6,7,
z
6,8,
z
6,9 aredifferent and if for instance
z
6,9∉
{
z
1,2,
z
3,5}
then{
z
1,2,
z
3,5,
z
6,9}
is an f- clique with three elements. Continuingin this way we get an infinite
f
-clique ofM
.Note: The above result holds in case of a module
M
with an infinite number off
-left -finite elements too. The following lemma is also easily follows from what have been described in itself.Lemma: 3.7 Let be a left ideal of
R
. And(
Ann
MI
=
)
N
(
⊆
Ker
( )
f
)
is a sub-module ofM
. Then, ψN
M is an
h-ring for the
ψ
induced by where RN M
→
:
ψ is such that
ψ
(
m
+
N
)
=
f
(
m
)
.Lemma: 3.8 LetN=Ker
( )
f be a finite sub-module of the moduleM
R. Then the moduleM
contains an infinitef
-clique if and only ifN
M contains an infinite clique where
ψ
is induced byf
withψ
(
m
+
N
)
=
f
( )
m
.Proof: Let
C
be an infinitef
-clique ofM
.Then we will show thatC
=
{
c
+
N
|
c
∈
C
}
is a ψ-clique of N M.Nowfor
c
i+
N
,
c
j+
N
∈
C
,(
c
i+
N
)
•
ψ(
c
j+
N
)
=(
c
i+
N
)
ψ
(
c
j+
N
)
=(ci+N)f( )
cj =c
if
( )
c
j+
N
=0+N =0
. Similarly(
c
j+
N
)
•
ψ(
c
i+
N
)
=
0
∀
i
≠
j
. ThusC
=
{
c
+
N
|
c
∈
C
}
is a ψ-clique ofN M .And
)
(
)
(
c
i+
N
≠
c
j+
N
,
(
i
≠
j
)
asN
=
Ker
(
f
)
. Conversely, let{ }
=1∞
i i
c
be an infinite ψ-clique ofN
M .Hence,
N
c
c
i•
f j∈
fori
≠
j
.Therefore the set of products{
}
j i j f ic
c
≠•
is a finite set. Now we can construct anPage: 1723-1733 4. MAIN RESULTS
The main results are here presented as follows.
4.1: Characterizations of f-chromatic number A module
M
R(orRM
)
is azero moduleifM
=
0
Theorem: 4.1.1
χ
(
M
f)
=
1
if and only ifM
is a zero module overR
.Proof: Assume
χ
(
M
f)
=
1
.Case I: Suppose,
M
≠
0
andf
=
0
.Then there is anm
i≠
0
∈
M
.Letm
j∈
M
be another element ofM
.Then
m
i•
fm
j=
m
if
( )
m
j=
m
i⋅
0
=
0
,i
≠
j
. Thusm
i,
m
j are f-adjacent, a contradiction toχ
(
M
f)
=
1
.Case II: Assume that
M
= 0 andf
≠
0
. This case does not arise [sincef
is anR
-homomorphism]Case III: Assume that
M
≠
0
andf
≠
0
. Letm
i≠
0
∈
M
. Nowm
i•
f0
=
m
if
(
0
)
=
m
i.
0
=
0
givesm
i,
0
are
f
-adjacent - a contradiction toχ
(
M
f)
=
1
.Thus,M
=
0
andf
=
0
. HenceM
is a zero module. Converselyassume
M
is a zero module .Then(
0
,
0
)
is anf
-loop. Thus only one color is sufficient to color the vertex of themodule
M
.Thusχ
(
M
f)
=
1
.Note:
(1) In case of a graph
(
R
,
E
,
0
)
,χ
( )
R
0 is the order of the ring i.e.0
( )
R
(2)
M
(≠
0
)
is a module over a ringR
with unity. Andf
:
M
→
R
is anyR
-homomorphism. Then( )
≤
≤
χ
M
f2
# M.(3) If
χ
( )
R
f=
k
, for all(
0
)
∧
≠
f
, then we say thatk
is the chromatic number ofR
denoted asχ
( )
R
. For afield
F
,χ
( )
F
f=
2
, for all(
0
)
∧
≠
f
as we have only one suchf
viz: the identity map.(4) It is to be noted that the chromatic number of a ring
R
as discussed in [1] appears as a very restricted one. It is not difficult to see that in case of the ring of integer modulo n, when n is other than prime, thef
-chromatic number variesfor different
R
-homomorphismf
.The problem may be considered as an open one to investigate under what condition one may expect the existence of
( )
R
χ
Proposition: 4.1.2 Let
p
1,
p
2,....,
p
k,
q
1,....,
q
r be different primes and1 2 1
2 1 2 2
1
...
.
...
11 + +
=
k mrr m
n k n
q
q
p
p
N
and letf
:
Z
N→
Z
be a homomorphism such thatf
( )
m
= k, wherek
is the remainder whenm
is divided byN
.Then
χ
(
Z
N)
f=clique(
Z
N)
f=1 1
1
1
...
.
...
11 k + mr+
r m
n k n
q
q
p
p
+ rProof: Let y0 =
1 1
1
1
...
.
...
1
1 k + mr+
r m
n k n
q
q
p
p
.Thenf
( )
y
0=
y
0.Consider the ideal=
•
fα
N
Z
{
z
i•
fα
|
z
i∈
Z
N}
[y0 = f(y0)= f( )
α
, say].Now
(
z
i•
fα
)
•
f(
z
j•
fα
)
=(
z
if
(
α
)
)
•
f(
z
jf
(
α
)
)
=z
if
(
α
)
f
(
z
j)
f
(
α
)
=z
if
(
z
j)
f
(
α
)
f
(
α
)
===
0 0
)
(
)
(
z
f
y
y
f
Page: 1723-1733
" # $ % # % & !
(
zj•fα
)
•f(
zi •fα
)
=0 .ThusZN •fα
is anf
-clique, whose cardinality isr
k m
r m n k n
q
q
p
p
1...
.
1...
11 Then the
set C=ZN •f
α
{
y1•fα
,...,yn•fα
}
is anf
-clique of(
Z
N)
fcontainings
p
p
q
q
r
r
k m
r m n k n
+
=
1...
.
1...
1 1
numbers of elements. Hence clique
(
Z
N)
f≥
s
. In order to showχ(
Z
N)
f≤
s
, we attach a distinct color to each ofthe elements of the
f
-cliqueC
. Furthermore letx
i•
fα
=
x
if
( )
α
= f( )
α
p N
i
n i
, where
i
n i i
p N
x = ,
1
≤
i
≤
k
.Thenα
fx
1•
,x
2•
fα
,
….,x
k•
fα
are also elements ofC
.[Sincex
if
( )
α
•
fx
jf
( )
α
=0. And hence have beenequipped with a color. Let
C
( )
y
denote the color of an elementy
and color the remaining elements of(
Z
N)
fasfollows. Pickx∉ZN •f
α
. If knk np
p
1...
1 divides
x
define,C
( ) (
x
=
C
y
j•
fα
)
, where .If
p
1n1...
p
knkdoes not dividesx
define,C
( ) (
x
=
C
x
j•
fα
)
, where j = min{i | nii
p x}.It is easily seen that this
coloring attaches different colors to f-adjacent vertices. Thus
χ
(
(
Z
N)
f)
≤
s
Henceχ
(
(
Z
N)
f)
=
s
.This is as an example of an h-ring where
f
-chromatic number coincides with clique of the h-ring.Theorem: 4.1.3 The
f
-chromatic number of an h-ringM
f with respect to the simple graph of a left sub-commutative ring
R
never exceedsi
-chromatic number ofR
iwherei
is the identity homomorphism.Proof: It can be shown that for every
f
-clique of the moduleM
there corresponds ani
-cliqueinR
. Next we showifclique
R
i is finite then cliqueM
f is also finite. Suppose thatC
=
{
m
1,
m
2,...
}
⊆
M
be an infinitef
-cliqueofM
. Consider the subsetC
=
{
f
( ) ( )
m
1,
f
m
2,...
.
}
ofR
.Now
f
( )
m
if
( )
m
j=
f
(
m
if
( )
m
j)
=
f
(
m
i•
fm
j)
=
f
( )
0
=
0
givesC
is ani
-clique ofR
which is infinite, acontradiction. Thus clique
M
f<∝
.Now letC
=
{
r
1,
r
2,...
}
⊆
R
is an infinitei
-clique ofR
. Then consider{
mr
mr
}
M
C
=
1,
2,...
⊆
.Sincemr
i•
fmr
j=
mr
if
( )
mr
j =mr
if
( )
m
r
j=mrr
ir
j =mr
0
=
0
[∀
i
≠
j
,
forsome
r
∈
R
].ThereforeC
is anf
-clique ofM
.Thus we getχ
( )
M
f≤
χ
( )
R
i .Note: However if
M
is a module over a zero ringR
thenM
itself is anf
-clique here, and sinceχ
( )
R
=
1
for zero ringR
, thereforeχ
( )
R
≤
χ
(
M
f)
.Thus this inequality does not hold ifM
is a module over a zero ringR
.Theorem: 4.1.4 Let
M
be a module over a right- sub commutative ringR
. If the h-ringM
f contains a nilpotentelement, which is not
f
-right- finite, thenM
f contains an infinitef
-clique.Theorem: 4.1.5 Let
M
be anf
-color module over a right sub- commutative ringR
andS
be any subset ofM
.Then
( )
S rM
f
M
is a
ψ
- color modulewhereψ
is induced byf
.Proof: Let
{
}
( )
S
r
M
m
m
f
M n
⊆
,....,
1 is a
ψ
-clique of( )
S
r
M
f
M
Page: 1723-1733
Now,
s
•
m
s
∈
S
m
j∈
M
finitei j f
i
|
,
is anf
- clique ofS
•
fM
. Clearly, clique( )
S
r
M
f
M
≤ clique
S
•
fM
.Now every
f
- clique of S•f M is also anf
-clique ofM
f as S•f M is a sub- ring ofM
f.SinceM
isf
-colormodule therefore clique
M
f <∝ which gives cliqueS
•
fM
is finite .Thus clique( )
S rM
f
M
is finite .Thus,
( )
S
r
M
f
M
is a
ψ
-color module.//4.2: Inheritance of Goldie Characters
Theorem: 4.2.1 Let
M
be a module overR
.IfM
satisfies the acc. on annihilators of subsets ofM
inR
thenM
fhas the acc. on right annihilators of its subsets.
Proof: We consider an ascending chain of right annihilators say,
⊆
)
(
S
1r
f
M
r
Mf(
S
2)
⊆
r
Mf(
S
3)
⊆
…. whereS
i⊆
M
,
i
=
1
,
2
,...
we claimr
Mf(
S
k)
=
r
Mf(
S
k+1)
=
…. forsome
k
∈
Z
+. Now for every ascending chain of right annihilators say,r
(
S
1)
⊆
f
M
r
Mf(
S
2)
⊆
r
Mf(
S
3)
⊆
….,where
S
i⊆
M
,
i
=
1
,
2
,...
we get a corresponding ascending chain such asAnn
R( )
S
1⊆
Ann
R( )
S
2⊆
...
...And since
M
satisfies the acc. on annihilators of subsets ofM
inR
, we have at
∈
Z
+ such that( )
t=
R
S
Ann
Ann
R(
S
t+1)
=
...
Now we claimr
M( )
S
t=
f
r
Mf(
S
t+1)
=
r
Mf(
S
t+2)
=
....
Suppose
α
∈
r
Mf(
S
t+1)
andα
∉
r
Mf( )
S
t .NowS
t+1•
fα
=
0
andS
t•
fα
≠
0
and so
S
t+1f
( )
α
=
0
and( )
α
≠
0
f
S
t giving therebyf
( )
α
∈
Ann
R(
S
t+1)
andf
( )
α
∉
Ann
R( )
S
t , a Contradiction .Thus rMf( )
St =r
Mf( )
S
t+1 .Hence our claim.//
Theorem: 4.2.2 Let
M
be a module overR
. IfM
is finite dimensional then the corresponding h-ringM
f is alsofinite dimensional.
Proof: Suppose
M
fis not finite dimensional. IfA
is a right ideal of the ringM
f , thenA
•
fM
=
Af
( )
M
is asub-module of
M
R. [Lemma3.3]. Also for right idealA
1,
A
2 ofM
fwithA
1A
2=
0
we have,
A
1f
( )
M
A
2f
( )
M
⊆
A
1A
2=
0
.Thus,A
1⊕
A
2⊕
...
, an infinite direct sum of right ideals off
M
gives rise toA
1f
( )
M
⊕
A
2f
( )
M
⊕
...
,an infinite direct sum of sub-modules ofM
R, a contradiction.4.3. f-color modules and Goldie rings
In this section we explore few ideas to convert an
f
-color-module into a Goldie ring. Here the notion of a prime module plays an important role in the way .In fact the Goldie character of an algebraic structure declares the finiteness of the chromatic number of the corresponding graph of the algebraic structure and vice-versa. The notion of the chromatic number of an arbitrary graph is accountable for what we have attempted to introduce that of a directed-clique, which would appear as a useful tool for study the color property of a non commutative algebraic structure.A finite subset
C
=
{
a
,
b
,....,
d
}
is a directed-clique if for a particular labeled description ofC
viz.{
a
b
d
}
C
=
,
,....,
=
{
x
1,
x
2,....,
x
n}
say, we havex
i⋅
x
j=
0
for alli
<
j
and it is to be noted thatC
will be aPage: 1723-1733
" # $ % # % & !
a directed-clique and such a countably infinite set is a clique if for each
n
∈
N
and for each above type of labeled description ofX
is a directed- clique.Note:
(1) Such an infinite directed-clique may coincide with our ordinary clique if the same is a finite directed-clique for all its finite subsets with all possible permutations. If
S
is a finite subset of T-an infinite directed-clique and each of all possible permutations ofS
is a directed-clique thenT
is a clique.(2) The problem of coloring of elements of such a directed-
f
- clique may be related with an infinitef
-clique which has been described in above and one may expect to get more interesting resultsTheorem: 4.3.1
M
be a finite dimensional module over a right sub- commutative ringR
and Mf is without infinitedirected
f
- Clique. Then Mf is right Goldie ring ifM
fis reduced.Proof: Since
M
Ris a finite dimensional module,so isM
f[Theorem: 4.2.2.].Now we consider one strictly ascendingchain of right annihilators of subsets of
M
, sayr
( )
S
1⊂
f
M
r
Mf( )
S
2⊂
r
Mf( )
S
3⊂
...
which is not stationary .Let( )
i\
M i
r
S
x
f
∈
r
M(
S
i−1)
f ,
i
=
2
,
3
,....
x
i∈
r
Mf( )
S
i andx
i∉
r
Mf(
S
i−1)
.ThenSi •f xi =0 andS
i−1•
fx
i≠
0
Consider the elements
y
n=
s
n−1•
fx
n=
s
n−1f
(
x
n)
,n 2. Theny
i=
s
i−1•
fx
i ,y
j=
s
j−1•
fx
j.Now fori
>
j
,r
( )
S
j⊂
r
( )
S
i .Thereforex
j∈
r
(
s
i−1)
.i.e.S
i−1•
fx
j=
0
.y
iy
j=
0
. Nowz
n=
y
i−nfor alln
. And ify
i=
y
j , theny
i2=
y
j2=
0
and is possible only wheny
i=
0
=
y
j asM
f is with zero nil-radical .Now since( )
S! ⊂r
r
( )
S
2⊂
…..is not stationary therefore{
z
n}
n=1αis an infinite directed- f-clique ofM
f , a contradiction .ThusM
fis right Goldie.//Here we get a very fascinating corollary, which may be called as a sufficient condition for an h-ring of being partially Goldie, which reads as:
Corollary: 4.3.2 (a)
M
is a module over a right sub-commutative ringR
. IfM
fis a reduced ring and is withoutinfinite directed
f
-Clique, thenM
f has the acc. on right annihilators of subsetsM
in ringMf.Corollary: 4.3.2(b) Let
M
be a finite dimensional module over a ringR
such that f( )
M is commutative and letf
M
be without infinitef
- Clique. ThenM
f is right Goldie ring if nil- radicalof Mfis zero.Corollary: 4.3.2(c) Let
R
be a finite dimensional right sub-commutative ring which is without infinite directed-clique.Then
R
is right Goldie ring if nil- radical ofR
is zero.Theorem: 4.3.3 Let
M
be af
-color module over a right sub- commutative ringR
whereM
f is reducedthen
( )
( )
P
M Ass P
M Z
∈
= .
Proof: Let
r
∈
Z
( )
M
. Thenmr
=
0
,
m
≠
0
∈
M
givesr
∈
Ann
( )
m
.Thusr
∈
Ann
( )
S
i for someSi ≠0 ,( )
SiAnn is a maximal ideal [Corollary 4.4.2 (a)]. It can be shown that
Ann
( )
S
i is a prime ideal.Hence
( )
P
M Ass P
r
∈
∈ .Thus
( )
( )
P
M Ass P
M Z
∈
⊆ .Conversely let
x
P
x
P
MAss P
∈
∈
∈ ( )
, for some
P
∈
Ass
( )
M
gives( )
S
iAnn
x
∈
.HereP
=
Ann
( )
S
i,
S
i≠
0
.ThusS
ix
i=
0
.This givess
ix
i=
0
[for somes
i≠
0
].Thus( )
M
Z
x
∈
giving thereby( )
( )
P
M Ass P
M Z
∈
Page: 1723-1733 ACKNOWLEDGEMENT
Authors like to offer their thanks to UGC for their financial help rendered for the work through Major Research Project Scheme.
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[3] Chartrand, G at-el Introduction to graph theory. Tata Mc .Graw Hill.
[4] Chowdhury, K. C.: Goldie M –groups, J, Australian Math .Soc (A), 51 (1991), 237-246.
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[6] Dheena, P: On Strongly regular near-rings, J. Indian Math. Soc. 49(1987), 201- 208
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