• No results found

Argument estimates of certain multivalent functions involving a linear operator

N/A
N/A
Protected

Academic year: 2020

Share "Argument estimates of certain multivalent functions involving a linear operator"

Copied!
15
0
0

Loading.... (view fulltext now)

Full text

(1)

http://ijmms.hindawi.com © Hindawi Publishing Corp.

ARGUMENT ESTIMATES OF CERTAIN MULTIVALENT

FUNCTIONS INVOLVING A LINEAR OPERATOR

NAK EUN CHO, J. PATEL, and G. P. MOHAPATRA

Received 28 December 2001

The purpose of this paper is to derive some argument properties of certain multivalent functions in the open unit disk involving a linear operator. We also investigate their integral preserving property in a sector.

2OOO Mathematics Subject Classification: 30C45.

1. Introduction. LetᏭpdenote the class of functions of the form

f (z)=zp+

n=1

an+pzn+p p∈N= {1,2, . . .} (1.1)

which are analytic in the open unit diskᐁ= {z:|z|<1}. A functionf∈pis said to bep-valently starlike of orderαinᐁ, if it satisfies

Re

zf(z) f (z)

> α (0≤α < p; z∈). (1.2)

We denote this class by᏿∗p(α). A functionf∈pis said to bep-valently convex of orderαinᐁ, if it satisfies

Re

1+zf(z) f(z)

> α (0≤α < p;z∈). (1.3)

The class ofp-valently convex functions of orderαis denoted by᏷p(α). It follows from (1.2) and (1.3) that

f∈p(α)⇐⇒ zf

p p(α). (1.4)

Further, a functionf∈pis said to bep-valently close-to-convex of orderβand type α, if there exists a functiong∈

p(α)such that

Re

zf(z) g(z)

> β (0≤α, β < p;z∈). (1.5)

It is well known (see [10]) that everyp-valently close-to-convex function isp-valent inᐁ.

For arbitrary fixed real numbersAandB (−1≤B < A≤1), letᏼ(A, B)denote the class of functions of the form

(2)

which are analytic inᐁand satisfies the condition

φ(z)≺11++AzBz (z∈), (1.7)

where the symbolstands for subordination. The classᏼ(A, B)was introduced and studied by Janowski [8].

We note that a functionφ∈(A, B), if and only if

φ(z)−11ABB2

< A−B

1−B2 (B1, z∈), Reφ(z)>1−A

2 (B= −1, z∈).

(1.8)

For a function f Ꮽ, given by (1.1), the generalized Bernardi-Libera-Livingston integral operatorF [1] is defined by

F (z)=γ+p

z

0t

γ−1f (t) dt

=zp+

n=1 γ+p

γ+p+nan+pz

n+p (γ >p; z). (1.9)

It readily follows from (1.9) that

f∈pF∈p. (1.10)

Let

φp(a, c;z)=

n=0 (a)n (c)n

zn+p (c≠0,−1,−2, . . .; z∈), (1.11)

and we define a linear operatorLp(a, c)onᏭpby

Lp(a, c)f (z)=φp(a, c;z)∗f (z) (z∈), (1.12)

where(x)n=Γ(n+x)/Γ(x)and the symbolis the Hadamard product or convolu-tion. Clearly,Lp(a, c)mapsᏭp into itself. Further,Lp(a, a) is the identity operator and

Lp(a, c)=Lp(a, b)Lp(b, c)=Lp(b, c)Lp(a, b) (b, c≠0,−1,−2, . . .). (1.13)

Thus, ifa≠0,−1,−2, . . . ,thenLp(a, c)has an inverseLp(c, a). We also observe that forf∈p,

Lp(p+1, p)f (z)= zf(z)

p , Lp(µ+p,1)f (z)=D

µ+p−1f (z), (1.14)

(3)

L(a, c)introduced by Carlson and Shaffer [3] in their systemic investigation of certain classes of starlike, convex, and prestarlike hypergeometric functions.

In the present paper, we give some argument properties of certain class of analytic functions inᏭp involving the linear operatorLp(a, c). An application of a certain integral operator is also considered. The results obtained here, besides extending the works of Bulboac˘a [2], Chichra [4], Cho et al. [5], Fukui et al. [6], Libera [9], Nunokawa [13], and Sakaguchi [16], it yields a number of new results.

2. Main results. To establish our main results, we need the following lemmas.

Lemma2.1[11]. Leth(z)be convex (univalent) inand letψ(z)be analytic inwithRe{ψ(z)} ≥0. Ifφ(z)is analytic inandφ(0)=ψ(0), then

φ(z)+ψ(z)zφ(z)≺h(z) (z∈) (2.1)

implies

φ(z)≺h(z) (z∈). (2.2)

Lemma2.2[12]. Letφ(z)be analytic in,φ(0)=1, φ(z)≠0inand suppose that there exists a pointz0such that

argφ(z)<π 2η

|z|<z0, argφ

z0= π 2η,

(2.3)

whereη >0. Then

z0φ

z0

φz0

=ikη, (2.4)

where

k≥12

d+1d

whenargφz0

2η,

k≤ −12

d+1d

when argφz0

= −π2η,

(2.5)

where

φz01/η= ±id (d >0). (2.6) We now derive the following theorem.

Theorem2.3. Leta >0,1B < A1,fp, and suppose thatgpsatisfies

Lp(a+1, c)g(z) Lp(a, c)g(z)

1+Az

1+Bz (z∈). (2.7)

If

arg

(1−λ)Lp(a, c)f (z) Lp(a, c)g(z)+

λLp(a+1, c)f (z) Lp(a+1, c)g(z)−

β

2δ (λ≥0; 0≤β <1; 0< δ≤1; z∈),

(4)

then

arg

Lp(a, c)f (z) Lp(a, c)g(z)−

β

2η (z∈), (2.9)

whereη (0< η≤1)is the solution of the equation

δ=

      

η+π2tan−1

ληsin(π /2)1−t(A, B)

a(1+A)/(1+B)+ληcos(π /2)1−t(A, B)

, forB1,

η, forB= −1,

(2.10)

when

t(A, B)=π2sin1 AB

1−AB

. (2.11)

Proof. Let

Lp(a, c)f (z) Lp(a, c)g(z)=

β+(1−β)φ(z). (2.12)

Thenφ(z)is analytic inᐁwithφ(0)=1. On differentiating both sides of (2.12) and using the identity

zLp(a, c)f (z)=aLp(a+1, c)f (z)−(a−p)Lp(a, c)f (z) (2.13)

in the resulting equation, we deduce that

(1−λ)Lp(a, c)f (z) Lp(a, c)g(z)+

λLp(a+1, c)f (z) Lp(a+1, c)g(z)−

β=(1−β)

φ(z)+λzφ(z) ar (z)

, (2.14)

where

r (z)=Lp(a+1, c)g(z) Lp(a, c)g(z)

. (2.15)

If we let

r (z)=ρe(π θ/2)i, (2.16)

then from (2.7) followed by (1.8), it follows that

1−A 1−B < ρ <

1+A 1+B,

−t(A, B) < θ < t(A, B) forB1,

(2.17)

whent(A, B)is given by (2.11), and

1−A

2 < ρ <∞,

1< θ <1 forB= −1.

(5)

Leth(z)be the function which maps onto the angular domain{w:|arg{w}|< (π /2)δ}

withh(0)=1. ApplyingLemma 2.1for thish(z)withψ(z)=λ/(ar (z)), we see that Reφ(z) >0 inᐁand henceφ(z)≠0 inᐁ.

If there exists a point z0 ᐁ such that conditions (2.3) are satisfied, then by

Lemma 2.2we obtain (2.4) under restrictions (2.5) and (2.6).

At first, suppose thatp(z0)1/η=id (d >0). For the caseB1, we obtain

arg

(1−λ)Lp(a, c)f

z0

Lp(a, c)g

z0

+λLp(a+1, c)f

z0

Lp(a+1, c)g

z0 −β

=argφz0+arg

1+ λ arz0

z0φ

z0

φz0

2η+arg

1+iηkλe− (π θ/2)i

ρa

2η+tan1

ληksin(π /2)(1−θ) ρa+ληkcos(π /2)(1−θ)

≥π2η+tan1

ληsin(π /2)1−t(A, B)

a(1+A)/(1+B)+ληcos(π /2)1−t(A, B)

≥π

2δ,

(2.19)

whereδandt(A, B)are given by (2.10) and (2.11), respectively. Similarly, for the case B= −1, we have

arg

(1−λ)Lp(a, c)f

z0 Lp(a, c)gz0+

λLp(a+1, c)f

z0 Lp(a+1, c)gz0

β

≥π2η. (2.20)

This is a contradiction to the assumption of our theorem.

Next, suppose thatφ(z0)1/η= −id (d >0). For the caseB1, applying the same method as above, we have

arg

(1−λ)Lp(a, c)f

z0 Lp(a, c)gz0+

λLp(a+1, c)f

z0 Lp(a+1, c)gz0

β

≤ −π2η−tan−1

ληsin(π /2)1−t(A, B)

a(1+A)/(1+B)+ληcos(π /2)1−t(A, B)

≤ −π

2δ,

(2.21)

whereδandt(A, B)are given by (2.10) and (2.11), respectively and for the caseB= −1, we have

arg

(1−λ)Lp(a, c)f

z0 Lp(a, c)gz0+

λLp(a+1, c)f

z0 Lp(a+1, c)gz0

β

≤ −π2η (2.22)

(6)

Remark2.4. Fora=c=p,A=1,B= −1, andλ=1,Theorem 2.3is the recent result obtained by Nunokawa [13].

Takinga=µ+p (µ >−p), c=1, A=1, andB=0 inTheorem 2.3, we have the following corollary.

Corollary2.5. Iff∈psatisfies

arg

(1−λ)D

µ+p−1f (z) Dµ+p−1g(z)

Dµ+pf (z) Dµ+pg(z)−β

2δ (λ≥0; 0< δ≤1; 0≤β <1;z∈)

(2.23)

for someg∈psatisfying the condition

DDµµ++pp−g(z)1g(z)1

< α (0< α≤1; z∈), (2.24)

then

arg

Dµ+p−1f (z) Dµ+p−1g(z)

2η (z∈), (2.25)

whereη (0< η≤1)is the solution of the equation

δ=η+π2tan1

ληsinπ /2sin1α (µ+p)(1+α)+ληcosπ /2sin1α

. (2.26)

LettingB→A (A <1)andg(z)=zpinTheorem 2.3, we get the following corollary.

Corollary2.6. Iffpsatisfies

arg

(1−λ)Lp(a, c)f (z) zp

Lp(a+1, c)f (z)

zp −β

2δ (a >0; λ≥0; 0≤β <1; 0< δ≤1; z∈),

(2.27)

then

arg

Lp(a, c)f (z) zp −β

<

π

2η (z∈), (2.28)

whereη (0< η≤1)is the solution of the equation

δ=η+π2tan1 λη

a

. (2.29)

Corollary2.7. Under the hypothesis ofCorollary 2.6, we have argH(z)−β<π

(7)

where the functionH(z)is defined inby

H(z)= z

0

Lp(a, c)f (t)

tp dt (2.31)

andη (0< η≤1)is the solution of (2.29).

Remark2.8. Takinga=c=p,λ=1, andβ=0 inCorollary 2.6, a=c=p and β=0 inCorollary 2.7, we get the corresponding results obtained by Cho et al. [5].

SettingA=1−(2α/p) (0≤α < p),B= −1, andδ=1 inTheorem 2.3, we have the following corollary.

Corollary2.9. Leta >0,fp, andgp(α). If

Re

(1−λ)Lp(a, c)f (z) Lp(a, c)g(z)+

λLp(a+1, c)f (z) Lp(a+1, c)g(z)

> β (λ≥0; 0≤β <1;z∈), (2.32)

then

Re

Lp(a, c)f (z) Lp(a, c)g(z)

> β (z∈). (2.33)

Remark2.10. Fora=c=p=1 andα=0,Corollary 2.9is the result by Bulboac˘a [2]. If we puta=c=p=1,β=0, andg(z)=zinCorollary 2.9, then we have the result due to Chichra [4]. Further, takinga=c=p,λ=1, andα=β=0 inCorollary 2.9, we get the corresponding results of Libera [9] and Sakaguchi [16].

Theorem2.11. Iff∈psatisfies

arg

Lp(a, c)f (z) zp −β

2δ (0≤β <1; 0< δ≤1; z∈), (2.34)

then arg

(γ+p)0ztγ−1Lp(a, c)f (t) dt

zγ+p −β

<

π

2η (0< γ+p; z∈), (2.35)

whereη (0< η≤1)is the solution of the equation

δ=η+π2tan1

η γ+p

. (2.36)

Proof. Consider the functionφ(z)defined inby

(γ+p)0ztγ−1Lp(a, c)f (t) dt

zγ+p =β+(1−β)φ(z). (2.37)

Thenφ(z) is analytic inᐁ with φ(0)=1. Differentiating both sides of (2.37) and simplifying, we get

Lp(a, c)f (z)

zp −β=(1−β)

φ(z)+zφ (z)

γ+p

. (2.38)

(8)

Takinga=p+1,c=p,β=ρ/p, andδ=1 inTheorem 2.11, we have the following corollary.

Corollary2.12. Iffpsatisfies

Re f(z)

zp−1

> ρ (0≤ρ < p; z∈), (2.39)

then

arg

(γ+p)0ztγ−1f(t) dt

zγ+p −ρ

<

π

2η (z∈), (2.40)

whereη (0< η≤1)is the solution of the equation

η+2 πtan

−1 η γ+p

=1. (2.41)

Theorem2.13. Iffpsatisfies

arg

Lp(a+1, c)f (z) Lp(a, c)f (z)

a−p−γ a

2δ (a >0; p+γ >0; 0< δ≤1;z∈), (2.42)

then

arg

L

p(a, c)f (z) z

0tγ−1Lp(a, c)f (t) dt

<

π

2η (z∈), (2.43)

whereη (0< η≤1)is the solution of (2.36).

Proof. Our proof ofTheorem 2.13is much akin to that ofTheorem 2.3. Indeed, in place of (2.37), we define the functionφ(z)by

φ(z)= zγLp(a, c)f (z) (γ+p)0ztγ−1Lp(a, c)f (t) dt

(z∈), (2.44)

and applyLemma 2.1(withψ(z)=1/(γ+p)) as before. We choose to skip the details involved.

Settinga=c=pandδ=1 inTheorem 2.13, we obtain the following corollary.

Corollary2.14. Iffpsatisfies

Re

zf(z) f (z)

>−γ (γ+p >0; z∈), (2.45)

then

arg

f (z) z

0tγ−1f (t) dt

2η (z∈), (2.46)

whereη (0< η≤1)is the solution of (2.41).

(9)

Corollary2.15. Iff∈psatisfies

Re

1+zff(z)(z)

>−γ (γ+p >0;z∈), (2.47)

then

arg

zf(z) f (z)−(γ/zγ)z

0tγ−1f (t) dt

<

π

2η (z∈), (2.48)

whereη (0< η≤1)is the solution of (2.41).

By settingγ=0 inCorollary 2.15, we have the following corollary.

Corollary2.16. Iff∈p(0), then

arg

zf(z)

f (z)

2η (z∈), (2.49)

whereη (0< η≤1)is the solution of the equation:

η+π2tan−1 η

p

=1. (2.50)

Similarly, we have the following theorem.

Theorem2.17. Iffpsatisfies

arg

Lp(a+1, c)f (z) Lp(a, c)f (z)

β

<

π

2δ (a >0; 0≤β <1; 0< δ≤1;z∈), (2.51)

then

arg

Lp(a, c)f (z) zp

<

π

2η (z∈), (2.52)

whereη (0< η≤1)is the solution of the equation

δ= 2 πtan

1 η (1−β)a

. (2.53)

Theorem2.18. Letfpand suppose that

B < A≤B+p(1−B)

a (a >0; 1≤B < A≤1). (2.54)

If arg

(1−λ)Lp(a+1, c)f (z) Lp(a, c)g(z) +

λ

Lp(a+1, c)f (z)

Lp(a, c)g(z) −β

2δ (λ≥0; 0≤β <1; 0< δ≤1; z∈),

(10)

for someg∈psatisfying

Lp(a+1, c)g(z) Lp(a, c)g(z)

1+Az

1+Bz (z∈), (2.56)

then

arg

Lp(a+1, c)f (z) Lp(a, c)g(z)

β

2η (z∈), (2.57)

whereη (0< η≤1)is the solution of the equation

δ=

      

η+2 πtan

1 ληsin(π /2)

1−t(A, B)

p(1+B)+a(A−B)/(1+B)+ληcos(π /2)1−t(A, B)

, forB1,

η, forB=−1,

(2.58)

when

t(A, B)=π2sin1

a(A−B) p1−B2aB(AB)

. (2.59)

Proof. Let

Lp(a+1, c)f (z) Lp(a, c)g(z) =

β+(1−β)φ(z), r (z)=Lp(a+1, c)g(z) Lp(a, c)g(z)

, (2.60)

we have

(1−λ)Lp(a+1, c)f (z) Lp(a, c)g(z) +

λ

Lp(a+1, c)f (z)

Lp(a+1, c)g(z)

−β=(1−β)

φ(z)+ λzφ (z)

ar (z)+p−a

.

(2.61)

The remaining part of the proof ofTheorem 2.18is similar to that ofTheorem 2.3. So we omit the details.

Puta=c=p,λ=1,A=α/p, andB=0 inTheorem 2.18, we have the following corollary.

Corollary2.19. Iff∈psatisfies

arg

zf(z) g(z) −β

<

π

2δ (0≤β < p; 0< δ≤1; z∈), (2.62)

for someg∈psatisfying the condition

zg(z)

g(z) −p

(11)

then

arg

zf(z)

g(z) −β

2η (z∈), (2.64)

whereη (0< η≤1)is the solution of the equation

δ=η+π2tan−1

ηsinπ /2sin1(α/p) p+α+ηcosπ /2sin−1(α/p)

. (2.65)

Lemma2.20. Let

α=ξ+ ξ γ+p+aξ

0≤(a−1)/a < ξ < α <1 (2.66)

and the functionG(z)be defined by

G(z)=γz+γp z

0

tγ−1g(t) dt g∈p

(2.67)

forγ > (aξ2+(p+1a)ξp)/(1ξ). Ifg

psatisfies

Lp(a+1, c)g(z) Lp(a, c)g(z)

1< α (z∈), (2.68)

then

Lp(a+1, c)G(z) Lp(a, c)G(z)

1< ξ (z∈). (2.69)

Proof. Defining the functionw(z)by

Lp(a+1, c)G(z) Lp(a, c)G(z) =

1+ξw(z), (2.70)

we see thatw(z)is analytic inᐁwithw(0)=0. Now, using the identities

zLp(a, c)G(z)=aLp(a+1, c)G(z)−(a−p)Lp(a, c)G(z), (2.71)

zLp(a, c)G(z)

=+p)L

p(a, c)g(z)−γLp(a, c)G(z) (2.72)

in (2.70), we get

Lp(a, c)G(z) Lp(a, c)g(z)=

γ+p

γ+p+aξw(z). (2.73)

Making use of the logarithmic differentiation of both sides of (2.73) and using identity (2.71) for bothg(z)andf (z)in the resulting equation, we deduce that

Lp(a+1, c)g(z) Lp(a, c)g(z)

1=ξw(z)+ zw (z)

γ+p+aξw(z)

(12)

We assume that there exists a pointz0ᐁsuch that max|z|<|z0||w(z)| = |w(z0)| =1. Then by Jack’s lemma [7], we havez0w(z0)=kw(z0) (k≥1). Letw(z0)=eiθ, and apply this result tow(z)atz0ᐁ, we get

Lp(a+1, c)gz0 Lp(a, c)g

z0

11+ k γ+p+aξeiθ

(γ+p+k)2+2aξ(γ+p+k)cosθ+(aξ)2 (γ+p)2+2aξ(γ+p)cosθ+(aξ)2

1/2 .

(2.75)

Since the right side of (2.75) is decreasing for 0≤θ <2πandγ >{aξ2+(p+1a)ξ p}/(1−ξ), we obtain

Lp(a+1, c)gz0 Lp(a, c)gz0

1≤ξ(γ+p+1+aξ)

γ+p+aξ , (2.76)

which contradicts our hypothesis and hence we get

w(z)=ξ1LpL(a+1, c)G(z)

p(a, c)G(z)

1<1 (z∈). (2.77)

This completes the proof ofLemma 2.20.

Remark2.21. We note that fora=c=p=1,Lemma 2.20yields the correspond-ing result obtained by Fukui et al. [6].

Theorem 2.22. Letα be as given in (2.66) andγ >max{(aξ2+(p+1a)ξ p)/(1−ξ), aξ−p}. Iff∈psatisfies

arg

Lp(a+1, c)f (z) Lp(a, c)g(z)

β

2δ (0≤β <1; 0< δ≤1; z∈), (2.78)

for somef∈psatisfying condition (2.68), then

arg

Lp(a+1, c)F (z) Lp(a, c)G(z)

β

2η (z∈), (2.79)

where the functionF (z)andG(z)are defined forγ∗by (1.9) and (2.67), respectively andη (0< η≤1)is the solution of the equation

δ=η+2 πtan

−1

ηsinπ /2sin−1aξ/γ∗+p γ∗+p+aξ+ηcosπ /2sin−1aξ/γ∗+p

. (2.80)

Proof. Consider the functionφ(z)defined inby

Lp(a+1, c)F (z) Lp(a, c)G(z) =

(13)

Thenφ(z)is analytic inᐁwithφ(0)=1. Taking logarithmic differentiation on both sides of (2.81) and using identity (2.71) in the resulting equation, we get

zLp(a+1, c)F (z) Lp(a+1, c)F (z) =

p−a+aLp(a+1, c)G(z) Lp(a, c)G(z) +

(1−β) zφ(z)

β+(1−β)φ(z). (2.82)

From the definition ofF (z), we have

γ∗+pLp(a, c)f (z)=a

Lp(a+1, c)F (z) +γL

p(a+1, c)F (z). (2.83)

Again, from (2.71) and (2.72), it follows that

γ∗+pLp(a+1, c)g(z)=zLp(a+1, c)G(z)+

p+γ∗−aLp(a, c)G(z). (2.84)

Thus, by using (2.83) and (2.84) followed by (2.82), we obtain

Lp(a+1, c)f (z) Lp(a, c)g(z)

β=(1−β)

φ(z)+ zφ(z) ar (z)+γ∗+p−a

, (2.85)

wherer (z)=Lp(a+1, c)G(z)/Lp(a, c)G(z). By usingLemma 2.20, we have

r (z)≺1+ξz (z∈), (2.86)

whereξis given by (2.66). Letting

ar (z)+γ∗+p−a=ρeiπ θ/2 (2.87)

and using the techniques ofTheorem 2.3, the remaining part of the proof ofTheorem 2.22follows.

Remark2.23. We easily find the following:

γ >                     

aξ−p, ifa−1

a < ξ < 2a−1

2a ,

2(a−p)−1

2 , ifξ=

2a−1 2a ,

2+(p+1a)ξp 1−ξ , if

2a−1

2a < ξ <1.

(2.88)

Takinga=c=pinTheorem 2.22, we get the following corollary.

Corollary2.24. Let

(14)

whereγ∗>max{(pξ2+ξp)/(1ξ), p(ξ1)}. Iff

psatisfies

arg

zf(z)

g(z) −β

2δ (0≤β < p; 0< δ≤1; z∈) (2.90)

for someg∈psatisfying the condition

zgg(z)(z)−p< pα (z∈), (2.91)

then

arg

zF(z)

G(z) −β

<

π

2 (z∈), (2.92)

whereη (0< η≤1)is the solution of the equation

δ=η+ 2 πtan

−1

ηsinπ /2sin−1pξ/γ∗+p γ∗+p(1+ξ)+ηcosπ /2sin−1pξ/γ∗+p

. (2.93)

Acknowledgment. This work was supported by Korea Research Foundation Grant KRF-2001-015-DP0013.

References

[1] S. D. Bernardi,Convex and starlike univalent functions, Trans. Amer. Math. Soc. 135 (1969), 429–446.

[2] T. Bulboac˘a,Differential subordinations by convex functions, Mathematica (Cluj)29(52) (1987), no. 2, 105–113.

[3] B. C. Carlson and D. B. Shaffer,Starlike and prestarlike hypergeometric functions, SIAM J. Math. Anal.15(1984), no. 4, 737–745.

[4] P. N. Chichra,New subclasses of the class of close-to-convex functions, Proc. Amer. Math. Soc.62(1976), no. 1, 37–43.

[5] N. E. Cho, J. A. Kim, I. H. Kim, and S. H. Lee,Angular estimations of certain multivalent

functions, Math. Japon.49(1999), no. 2, 269–275.

[6] S. Fukui, J. A. Kim, and H. M. Srivastava,On certain subclass of univalent functions by

some integral operators, Math. Japon.50(1999), no. 3, 359–370.

[7] I. S. Jack,Functions starlike and convex of orderα, J. London Math. Soc. (2)3(1971), 469–474.

[8] W. Janowski,Some extremal problems for certain families of analytic functions. I, Bull. Acad. Polon. Sci. Sér. Sci. Math. Astronom. Phys.21(1973), 17–25.

[9] R. J. Libera,Some classes of regular univalent functions, Proc. Amer. Math. Soc.16(1965), 755–758.

[10] A. E. Livingston,p-valent close-to-convex functions, Trans. Amer. Math. Soc.115(1965), 161–179.

[11] S. S. Miller and P. T. Mocanu,Differential subordinations and inequalities in the complex

plane, J. Differential Equations67(1987), no. 2, 199–211.

[12] M. Nunokawa,On the order of strongly starlikeness of strongly convex functions, Proc. Japan Acad. Ser. A Math. Sci.69(1993), no. 7, 234–237.

[13] ,On some angular estimates of analytic functions, Math. Japon.41(1995), no. 2,

447–452.

(15)

[15] H. Saitoh and M. Nunokawa,On certain subclasses of analytic functions involving a linear

operator, S¯urikaisekikenky¯usho K¯oky¯uroku963(1996), 97–109.

[16] K. Sakaguchi,On a certain univalent mapping, J. Math. Soc. Japan11(1959), 72–75.

Nak Eun Cho: Division of Mathematical Sciences, Pukyong National University,

Pusan608-737, Korea

E-mail address:[email protected]

J. Patel: Department of Mathematics, Utkal University, Vani Vihar, Bhubaneswar 751 004, India

E-mail address:[email protected]

G. P. Mohapatra: Silicon Institute of Technology, Near Infocity, Patia,

Bhubaneswar751035, India

References

Related documents

In this dissertation the writer analyses the emergency response system focusing on the contingency planning for dangerous goods incidents as an integral part of whole environmental

The study is crucial in unearthing psychosocial effects faced by War Victims among Freedom Fighters (MAU MAU) Those experiences are of great interest to the

Intermittent versus continuous renal replacement therapy for acute kidney injury patients admitted to the intensive care unit: results of a randomized clinical trial.. Nephrol

Microsoft Word thesis 18 3 3 doc Planning of Mega Projects Influence of Execution Planning on Project Performance Author T Slootman Planning of Mega Projects Influence of Execution

From the above conducted prospective observa- tional study we conclude that bronchoscopy is an important tool for both diagnostic and therapeutic purpose in

As compared to other studies conducted ac- cording to the same methodology, it was demonstrated that tansy aqueous extracts are characteristic for a high deterrent activity in

Background: Negative Pressure Wound Therapy (NPWT) or Vacuum Assisted Closure (VAC) is a method used to cover large wounds, decubitus ulcers and open fractures which cannot be

Methods: A cross-sectional study was conducted, adopting the Morisky eight-item Medication Adherence Scale (MMAS) for the assessment of medication adherence and using the