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Volume 2008, Article ID 384910,16pages doi:10.1155/2008/384910

Research Article

On Singular Solutions of Linear Functional

Differential Equations with Negative Coefficients

Vita Pylypenko1and Andr ´as Ront ´o2

1National Technical University of Ukraine “Kyiv Polytechnic Institute”,

Faculty of Physics and Mathematics, 37 Peremohy Avenue, 03 056 Kyiv, Ukraine

2Institute of Mathematics, Academy of Sciences of Czech Republic, ˇZiˇzkova 22, 61662 Brno, Czech Republic

Correspondence should be addressed to Andr´as Ront ´o,[email protected]

Received 26 May 2008; Accepted 1 September 2008

Recommended by Alberto Cabada

The problem on solutions with specified growth for linear functional differential equations with negative coefficients is treated by using two-sided monotone iterations. New theorems on the existence and localisation of such solutions are established.

Copyrightq2008 V. Pylypenko and A. Ront ´o. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.

1. Problem setting and introduction

In this paper, we are concerned with the problem on the existence and localisation of solutions of singular linear functional differential equations. The class of equations under examination comprises, in particular, the differential equation with argument deviations

ut

n

k0

pktu

ωkt

ft, ta, b, 1.1

considered together with the additional condition

sup

ta,b

htut<, 1.2

whereh:a, b→Ris a certain given continuous nondecreasing function such thatht>0 forta, band

lim

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The argument deviations in1.1are given by arbitrary Lebesgue measurable functionsωk,

k 0,1, . . . , n, transforming the intervala, bto itselfthis setting does not lead one to any loss of generality, see, e.g., 1.

We are interested in conditions guaranteeing the existence of solutions with property 1.2in the case where the coefficients of1.1are nonpositive.

The class of solutions of1.1determined by condition 1.2includes, in particular, those possessing the property

lim

tahtut c, 1.4

wherec∈R. Problem1.1,1.4withhsatisfying1.3is referred to as the singular Cauchy problem 2. It is reduced, in a natural way, to the classical regular Cauchy problem ifhis equal identically to a nonzero constant. Regular and singular Cauchy problems for various classes of functional differential equations are treated, in particular, in 2–11; a problem on regular solutions possessing properties of type1.4is studied in 12.

By asolutionof problem1.1,1.2we mean a locally absolutely continuous function

u : a, b→Rsuch that huL1a, b,Rwhich satisfies 1.1almost everywhere on the intervala, band possesses property1.2. One says that a functionu :a, b→Rislocally absolutely continuousif its restrictionu|aε,bto the interval aε, bis absolutely continuous for anyε∈0, ba.

A solution of 1.1, 1.2 may have a nonintegrable singularity at the point a. For example, the functionut λt−4,t 0,1for any realλ andε 0,is a solution of the homogeneous problem

ut −4 t3u

t1/2, t0,1,

sup

ξ∈0,1

ξ4εuξ< 1.5

in the sense of the above definition. It should be noted that the property of the uniqueness of a solution is not typical for such problems; in other words, the resonance usually takes place.

2. Notation

The following notation is used throughout the paper. 1R: −∞,∞.

2If−∞< a < b <∞andAa, bis a measurable set, thenL1A,Ris the Banach space of all the Lebesgue integrable functionsu:A→Rwith the standard norm

L1A,Ru−→

A

utdt. 2.1

3Ba, b,Ris the Banach space of all the bounded functionsu:a, b→Rwith the standard norm

Ba, b,Ru−→ sup

ta,b

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4L1; loca, b,R is the set of functions u : a, b→R such that u|aε,bL1 a

ε, b,Rfor anyε∈0, ba.

5ACloca, b,R is the set of all the locally absolutely continuous functions u : a, b→R.

6ACloc;ha, b,R is the set of all the locally absolutely continuous functions u :

a, b→Rsuch thathuL1a, b,Rand supta,bht|ut|<.

3. Existence of solutions with restricted growth

Without significant loss of generality we can assume that the functionh:a, b→Rinvolved in1.2has the following properties.

The function h:a, b−→0,∞is absolutely continuous and nondecreasing,

and the relation lim

taht 0 holds.

3.1

The following statement on problem1.1,1.2is true.

Theorem 3.1. Lethin condition1.2possess properties3.1, the functionsωk,k0,1, . . . , n, are

Lebesgue measurable, and let the functionspkL1; loca, b,R,k0,1, . . . , n, be such that

pkt≤0, ta, b, k0,1, . . . , n, 3.2

max

k0,1,...,n

b

a

hs hωks

pksds <. 3.3

Moreover, let there exist a nonnegative functionϕACloc;ha, b,Rsuch that

ϕt

n

k0

pktϕ

ωkt

, ta, b. 3.4

Then for an arbitrary u0 ∈ ACloc;ha, b,R and any function f : a, b→R from

L1; loca, b,Rpossessing the property

hfL1

a, b,R 3.5

and satisfying the estimate

ϕt

n

k0

pktϕ

ωkt

ftu0t

n

k0

pktu0

ωkt

≤0, ta, b, 3.6

problem1.1,1.2has a solutionu:a, b→Rsuch that

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Remark 3.2. The set of functions f satisfying inequalities 3.6 is nonempty because ϕ is assumed to possess property3.4. Of course, it makes sense to consider only thoseϕwhich do not satisfy the corresponding homogeneous equation.

The next corollary deals with the case where the solution in question is bounded from below.

Corollary 3.3. Assume thathin condition1.2possesses properties3.1and the functionspk

L1; loca, b,R, k 0,1, . . . , n, satisfy 3.2 and 3.3. Moreover, let the functional differential

inequality3.4have a nonnegative solutionϕACloc;ha, b,R.

Then for an arbitrary realλand any functionf:a, b→RfromL1; loca, b,Rpossessing

property3.5and satisfying the estimate

ϕt

n

k0

pktϕ

ωkt

ft λ

n

k0

pkt≤0, ta, b, 3.8

problem1.1,1.2has a solutionu:a, b→Rsuch that

0≤utλϕt, ta, b. 3.9

For concrete classes of weight functionsh,Theorem 3.1allows one to obtain efficient results concerning the existence, localisation, and approximate construction of solutions of 1.1possessing property1.2. Let us consider the problem on the existence of solutions of 1.1possessing the property

sup

ta,b

taγut<, 3.10

whereγis a given positive constant.

Corollary 3.4. Let the functions pkL1; loca, b,R, k 0,1, . . . , n, be nonpositive almost

everywhere ona, b. Moreover, let

max

k0,1,...,n

b

a

sa ωksa

γ

pksds <. 3.11

Then for arbitrary functionu0 ∈ ACloc;ha, b,R, number δ ∈ 0, γ, and functionf :

a, b→RfromL1; loca, b,Rpossessing the properties3.5and

γδtaγδ−1−

n

k0

pkt

ωkta

γδ

ftu0t

n

k0

pktu0

ωkt

≤0, ta, b,

3.12

problem1.1,1.2has a solutionu:a, b→Rsuch that

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Remark 3.5. Under condition 3.11, the coefficient pk, k 0,1, . . . , n, may have a

nonin-tegrable singularity at the point a if the corresponding argument deviation ωk has the

property

ess inf

ta,b

ta ωkta

0 3.14

and, in particular, if ess infta,bωkt> a.

In particular, in the case of the problem on finding solutions of the equation

ut

n

k0

pktu

tβkft, t∈0,1, 3.15

satisfying the additional condition

sup

t∈0,1

tγut<, 3.16

whereγ >0,βk≥0,k0,1, . . . , n, we have the following.

Corollary 3.6. Let the functions pkL1; loc0,1,R, k 0,1, . . . , n, be nonpositive almost

everywhere on0,1and let the relation

n

k0 1

0

t1−βkγp

ktdt <∞ 3.17

be satisfied. Moreover, assume that there exists someδ∈0, γsuch that

ess sup

t∈0,1

n

k0

pkttγδ1−βk1≤γδ. 3.18

Then for an arbitrary u0 ∈ ACloc;h0,1,R and any function f : 0,1→R from

L1;loc0,1,Rpossessing the properties

hfL1

0,1,R,

γδtγδ−1−

n

k0

pkttβkγδftu0t

n

k0

pktu0

tβk0, t∈0,1, 3.19

problem3.15,3.16has a solutionu:0,1→Rsuch that

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Remark 3.7. Under the conditions ofCorollary 3.6, the coefficientpk,k 0,1, . . . , n, of3.15

may be nonintegrable if the corresponding exponentβksatisfies the inequalities 0< βk <1,

that is, if there is an advance of argument in thekth term.

The statements formulated above are consequences of the general theorem which will be established inSection 4.

4. A general theorem

Let us consider the functional differential equation

ut lut ft, ta, b, 4.1

wherel:ACloca, b,RnL1; loca, b,Rnis a linear operator andfL1; loca, b,Rnis a given locally integrable function. Assuming implicitly conditions3.1on the functionh, we pose the problem on finding solutions of4.1possessing property1.2.

Definition 4.1. An operator l : ACloca, b,RnL1; loca, b,Rn is said to be pointwise

negativeiflut≤0 for a.e.ta, bwhenever infta,but≥0 andhuL1a, b,Rn. The following theorem holds.

Theorem 4.2. Let the operator l : ACloca, b,RnL1; loca, b,Rn in 4.1 be pointwise

negative such that

hl

1

h

L1

a, b,R. 4.2

Furthermore, let there exist some nonnegative absolutely continuous functiong:a, b→Rsuch that

h

g

h

L1

a, b,R, 4.3

and almost everywhere ona, b,

ht2l

g

h

tgthtgtht, ta, b. 4.4

Then for an arbitraryu0 ∈ACloc;ha, b,Rand any functionf:a, b→RfromL1; loca,

b,Rpossessing the properties3.5and

gthtgtht

ht2 −l

g

h

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problem4.1,1.2has at least one solutionu:a, b→Rsuch that

0≤utu0t

gt

ht, ta, b. 4.6

It should be noted that the solution of problem4.1,1.2, the existence of which is stated in Theorem 4.2, can be found approximately by using a convergent monotone two-sided iteration procedure. Moreover, besides4.6, the solution indicated admits the estimate

gthtgtht

ht2 ≤u

tu

0t≤0, ta, b. 4.7

5. Auxiliary statements

In the sequel, we need an abstract theorem on operators in partially ordered normed spaces 13, Theorem 4.1. In order to state it, we first formulate definitions. We use 13as the main referencesee also 14,15.

5.1. General notions

Let E,· be a normed space overRand letK be a cone 13in E, that is, a nonempty closed subset of Epossessing the properties K ∩−K {0} and α12KK for all {α1, α2} ⊂ 0,∞. A coneKgenerates a natural partial ordering ofE. As usual, we will write

uKvandvKuif and only ifvuK.

Definition 5.1see 13. A sequence{uk|k≥0} ⊂Eis said to beorder-boundedif there exists

somevEsuch thatukKvfor anyk≥0. A sequence{uk|k≥0} ⊂Eis said to bemonotone

ifukKuk1for anyk≥0.

Definition 5.2see 13. A coneKEis said to beregularif every order-bounded monotone

sequence converges inE.

Definition 5.3 see 13. Given a cone KE, a functionall : E→Ris said to be positive

with respect toKiflu≥ 0 for anyuK0. A positive functionall :E→Ris calledstrictly

nondecreasingon the coneKif

lim

n→ ∞l

u1u2. . .un

∞ 5.1

for any sequenceunK,n1,2, . . ., possessing the property infn≥1un>0.

A linear functionall:E→Ris said to beuniformly positiveonKif there exists a certain

λ∈0,∞such that

lxλxxK. 5.2

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Definition 5.4see 13. One says that an operatorT :EEismonotonewith respect toK

ifTuKTvfor anyuandvfromEsuch thatuKv.

Theorem 5.5see 13. LetT :EEbe a monotone and continuous operator. Let there exist some elements{u0, v0} ⊂Esuch thatu0Kv0and, moreover,

Tu0Ku0, 5.3

Tv0Kv0. 5.4

Moreover, assume that the coneKis regular. Then the operatorT has at least one fixed pointusuch thatu0KuKv0.

Remark 5.6. The assertion of Theorem 5.5is established in 13under the assumption that

TKK. The positivity ofT, however, is not used in the proof.

5.2. The spaceACloc;ha, b,R

We assume that the functionhinvolved in the nonlocal condition1.2possesses properties 3.1.

Lemma 5.7. The setACloc;ha, b,Ris a Banach space with respect to the norm

ACloc;h

a, b,Ru−→ u:

b

a

hsusds sup

ξa,b

hξuξ. 5.5

Proof. Let us assume that{um :m≥ 1}is a Cauchy sequence in the spaceACloc;ha, b,R.

Then, in view of5.5, the sequence{hum:m≥1}is a Cauchy sequence inL1a, b,Rand, therefore, there exists some Lebesgue integrable functionv:a, b→Rsuch that

lim

m→∞ b

a

hsumsvsds0. 5.6

According to the definition of the setACloc;ha, b,R, every functionhum:a, b→R,m

1,2, . . ., is bounded in a neighbourhood of the pointa, whence, in view of the assumption, we find that the sequence{hum:m≥1}is a Cauchy sequence in the complete spaceBa, b,R.

Therefore, one can specify a bounded functionw:a, b→Rsuch that

lim

m→∞tmax∈ a,bhsumsws0. 5.7

Let us put

u: w

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fix an arbitraryδ∈0, ba, and construct the sequence of functions

zm,δ :−

b

hsumsus

dshbumbub

haδumaδuaδ

, m1,2, . . . .

5.9

Since the numberδis positive, we see from assumption3.1thath/hL1 aδ, b,R, whence, in view of5.7and the Lebesgue dominated convergence theorem, we obtain

lim

m→∞

b

hsumsus

ds0. 5.10

By virtue of assumption 3.1, ht/0 for a < tb. It then follows from 5.7 that limm→∞umt utfor anyta, b. By virtue of5.10, this yields

lim

m→∞zm,δ 0

δ∈0, ba. 5.11

On the other hand, it follows immediately from5.9that

zm,δ

b

hs us hsumsdshb ub haδuaδ, 5.12

whence, in view of5.6,

b

vsds

b

hs usdshb ubhaδ uaδ 5.13

for any 0< δ < ba. Recalling thatvL1a, b,RandhuBa, b,R, using the relation −∞ < limδ→0abδvsds abvsds < ∞, and passing to the limit asδ→0 in5.13, we

find that

b

a

hs usds

b

a

vsdshb ub− lim

ξahξ 5.14

and, in particular,huL1a, b,R.

It follows from5.13that the functionsvandusatisfy the relation

htut

b

t

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Moreover, the producthuhas a derivative almost every where ona, b. Indeed, it follows

from5.14that, for almost everyta, band anyηat, bt,

1

η

htη utηht ut−1 η

b

vs hsusds

b

t

vs hs usds

1

η

t

vs hs usds.

5.16

Therefore, limη→01/ηhtηutηht ut vt ht ut,which means that

htutvt ht ut 5.17

for a.e.ta, b. Relation5.17implies, in particular, thatuexists almost everywhere on a, band, moreover,

ht ut vt 5.18

for a.e.ta, b. Using5.5and5.18, we get

umu

b

a

hsumsusds sup ξa,b

hξumξ−→0 5.19

asm→ ∞, that is, the sequence{um:m≥1}converges touinACloc;ha, b,R.

Lemma 5.8. The set

K:

uACloc;h

a, b,R: inf

ta,but≥0,ess supta,b u

t0 5.20

is a regular cone in the spaceACloc;ha, b,R.

Proof. The set 5.20is obviously closed, and the axioms of a cone see5.1 are verified

directly. If a monotonous strictly nondecreasing functional is defined on the coneK, then the coneKis regularsee, e.g., 13, Theorem 1.11. In our case, the functional

ϕu:−

b

a

hsusds sup

ξa,b

hξuξ uACloc;h

a, b,R 5.21

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Lemma 5.9. If the operatorland functionhsatisfy condition4.2andhis nondecreasing, then

sup

ta,b

ht

b

t

l

1

h

sds <. 5.22

Proof. Property5.22is a consequence of the estimate

ht

b

t

l

1

h

sds

b

t

hsl

1

h

sds, 5.23

which is valid for anyta, bbecausehis nondecreasing.

5.3. The operatorT

Let us fix a certain locally integrable functionf :a, b→Rwith properties3.5and put

Tut:ub

b

t

lus fsds, ta, b, 5.24

for anyufromACloc;ha, b,R.

Lemma 5.10. Iflis pointwise negative and3.1holds, then

1T is a well-defined mapping fromACloc;ha, b,RtoACloc;ha, b,R;

2T is continuous with respect to norm5.5;

3T is monotone with respect to cone5.20.

Proof. 1Letube an arbitrary function fromACloc;ha, b,R. Then there exists a constant

μu>0 such that

utμu

ht, 5.25

and hence

μu

ht≤ −utututμu

ht, ta, b. 5.26

Relation5.26, due to the pointwise negativityseeDefinition 4.1and linearity ofl, yields

l

μu

h

tl− |u|tlutl|u|tl

μ

u

h

t, 5.27

μul

1

h

t≥ −l|u|tlutl|u|tμul

1

h

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Thus, we have the estimate

lutμul1

h

t, ta, b, 5.29

and therefore, due to assumption4.2,

lim

ta b

t

hslusds <. 5.30

Sincef is assumed to satisfy3.5, this guarantees that the function hw, wherew : Tu, belongs toL1a, b,R.

Furthermore, using condition3.5and arguing similarly to the proof ofLemma 5.9, we find that

sup

ta,b

ht

b

t

fsds <. 5.31

Then, by virtue of3.1and5.27,

sup

ta,bht

Tut sup

ta,bht ub

b

t

lus fsds

hbub sup

ta,b

ht

b

t

lusfsds

hbub μusup ta,b

ht

b t l 1 h

tds sup

ta,b

ht

b

t

fsds,

5.32

whence, in view of assumptions 3.1, 4.2, 5.31 and Lemma 5.9, it follows that supta,bht|Tut| <.Thus, T is well defined and maps the space ACloc;ha, b,R

into itself.

2The continuity ofTfollows from the properties ofl. Indeed, letuandvbe arbitrary functions fromACloc;ha, b,Rand letε ∈0,∞be given. According to5.5and5.24,

in view of the linearity ofl, we have

TvTu

b

a

htlvutdt sup

ta,b

htvbub

b

t

lvusds

b

a

htlvutdt sup

ta,b

htvbub sup

ta,b

ht

b

t

lvusds.

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Sinceuandvbelong toACloc;ha, b,R, it follows that

βu,v

htvtutβu,v

ht, ta, b, 5.34

whereβu,v : supta,bht|vtut| <.By assumption,l is pointwise negative, and

therefore

lvut≤ −βu,vl

1

h

t, ta, b. 5.35

By virtue of condition4.2, it follows from5.35that

b

a

htlvutdtβu,vC, 5.36

whereC:−abhtl1/htdt <∞note thatCis positive.

Due toLemma 5.9, assumption4.2ensures the validity of relation5.22. Using5.22 and 5.36, taking estimate5.23from the proof of Lemma 5.9into account, and arguing analogously, we obtain

sup

ta,bht b

t

lvusds≤ sup

ta,b b

t

hslvusds

≤ sup

ta,b b

t

hslvusdsβu,vC.

5.37

Sincevuβu,v, we see from5.33,5.36, and5.37 thatTvTu < ε whenever

vu < ε12C−1. This, in view of the arbitrariness ofε, proves the continuity of the mappingT.

3Letuandvbe arbitrary elements ofACloc;ha, b,Rsuch thatvKuwith respect

to cone5.20, that is,

−1ivituit0, ta, b, i0,1. 5.38

Sincelis assumed to be pointwise negative, in view of5.38, we have

TvtTut vbub

b

t

lvusds≥0, ta, b,

TvtTut lvut≤0, ta, b,

5.39

which means thatTvKTu.

Lemma 5.11. A functionu:a, b→RfromACloc;ha, b,Ris a solution of problem4.1,1.2

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Proof. To obtain this assertion, it is sufficient to take into account5.24and the definition of the setACloc;ha, b,R.

6. Proofs

Let us now turn to the proofs of the statements formulated in Sections3and4.

6.1. Proof ofTheorem 3.1

It is clear that1.1can be represented in the form of4.1, where the operatorlis defined by the equality

lut

n

k0

pktu

ωkt

, ta, b. 6.1

Since the functionspkL1; loca, b,R,k 0,1, . . . , n are nonpositive, it follows that the operatorlis pointwise negative. Moreover, in view of property3.3, the operatorlsatisfies condition4.2. Furthermore, a nonnegative functionϕACloc;ha, b,Rcan be written in

the form

ϕ g

h, 6.2

wheregis a nonnegative absolutely continuous function ona, b. Then it follows from3.4 and3.6that inequalities4.4and4.5are true.

Thus, all the conditions ofTheorem 4.2hold, and therefore problem1.1,1.2has a solutionu:a, b→Rbelonging toACloc;ha, b,Rand satisfying estimate3.9.

6.2. Proof ofCorollary 3.3

The statement is an immediate consequence ofTheorem 3.1withu0t:λ,ta, b.

6.3. Proof ofCorollary 3.4

It is sufficient to applyTheorem 3.1in the case wherehhas the formht t,ta, b,

withγ > 0, and the functionϕ is given by the formulaϕt taγδ,ta, b, where δ∈0, γ.

6.4. Proof ofCorollary 3.6

It is sufficient to applyCorollary 3.4 with a 0, b 1, and ωkt tβk,t ∈ 0,1, k

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6.5. Proof ofTheorem 4.2

We are going to use Theorem 5.5. Lemmas 5.7 and 5.8guarantee that the set K given by 5.20is a regular cone in the Banach spaceACloc;ha, b,R. ByLemma 5.10, the operatorT :

ACloc;ha, b,R→ACloc;ha, b,Rdefined by formula5.24is continuous and monotone

with respect to the coneK. Therefore, in order to be able to applyTheorem 5.5, we need to specify a pair of elements u0 and v0 inACloc;ha, b,Rsuch that u0Kv0 and5.3,5.4 hold.

Let us putv0:u0ϕ, where

ϕ: g

h 6.3

andu0is the function from the formulation of the theorem. Note thatϕACloc;ha, b,R

in view of assumption 4.3 and the absolute continuity ofg. Moreover, −1iϕit 0,

ta, b,i 0,1, because, by assumption,g is a nonnegative function and the functional differential inequality4.4is satisfied. Hence,ϕK.

The functions indicated satisfy relations5.3and5.4with respect to cone5.20, that is,

−1iTu

0

itui 0 t

≥0, ta, b, i0,1, 6.4

−1iTv

0

itvi

0 t

≤0, ta, b, i0,1. 6.5

Indeed, it follows immediately from5.24that relations6.4and6.5withi1 are satisfied if and only if

u0tϕt lu0

t lϕt≥ −ft≥ −u0t lu0

t, ta, b. 6.6

Therefore, it suffices to notice that6.6holds in view of4.5and6.3, whereas relations 6.4and6.5withi0 are obtained from6.6by integrating fromta, btob.

In view of4.4, the function6.3satisfies the functional differential inequality

ϕtlϕt, ta, b, 6.7

and hence the set of functionsfACloc;ha, b,Rsatisfying condition6.6is nonempty.

ApplyingTheorem 5.5and usingLemma 5.11, we complete the proof ofTheorem 4.2.

Acknowledgments

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References

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