R E S E A R C H
Open Access
Asymptotic properties of solutions of
third-order nonlinear neutral dynamic
equations
Tuncay Candan
**Correspondence:
[email protected] Department of Mathematics, Faculty of Art and Science, Ni ˘gde University, Ni ˘gde, 51200, Turkey
Abstract
The purpose of this article is to give oscillation criteria for the third-order neutral dynamic equation (r2(t)[(r1(t)[y(t) +p(t)y(
τ
(t))])]γ)+f(t,y(δ
(t))) = 0, whereγ
≥1 is a ratio of odd positive integers withr1(t),r2(t), andp(t) are positive real-valued rd-continuous functions defined onT. We give new results for the third-order neutral dynamic equations and an example to illustrate the importance of our results.Keywords: oscillation; dynamic equations; time scales; neutral equations
1 Introduction
In the present article, we are concerned with oscillations of the third-order nonlinear neu-tral dynamic equation
r(t)
r(t)
y(t) +p(t)yτ(t)γ+ft,yδ(t)= ()
on a time scaleT. Throughout this paper it is assumed thatγ ≥ is a ratio of odd positive integers,τ(t) :T→Tandδ(t) :T→Rare rd-continuous functions such thatτ(t)≤t,
δ(t)≤t,limt→∞δ(t) =limt→∞τ(t) =∞andδ(t) > is rd-continuous,r(t),r(t) andp(t) are positive real valued rd-continuous functions defined onT, ≤p(t)≤p< is increas-ing. We define the time scale interval [t,∞)Tby [t,∞)T= [t,∞)∩T. Furthermore, f :T×R→Ris a continuous function such thatuf(t,u) > for allu= and there exists a rd-continuous positive functionq(t) defined onTsuch that|f(t,u)| ≥q(t)|uγ|.
We use throughout this paper the following notations for convenience and for shorten-ing the equations:
x(t) =y(t) +p(t)yτ(t), x[]=rx
,
x[]=r
x[]γ, x[]=x[].
()
A nontrivial functiony(t) is said to be a solution of () ifx∈Crd[ty,∞),rx∈Crd[ty,∞) andx[]∈Crd[ty,∞) forty≥tandy(t) satisfies equation () forty≥t. A solution of () which is nontrivial for all largetis said to be oscillatory if it is neither eventually positive nor eventually negative. Otherwise, it is called nonoscillatory.
Recently, there has been many important research activity on the oscillatory behavior of dynamic equations. For example, on second-order dynamic equations, Saker [], and
Agarwalet al.[], Saker [], Hassan [] and Candan [, ] considered the following non-linear dynamic equations:
r(t)y(t) +p(t)y(t–τ)γ+ft,y(t–δ)= ,
r(t)y(t) +p(t)yτ(t)γ+ft,yδ(t)= ,
r(t)x(t)γ+p(t)xγ(t) = ,
and
r(t)y(t) +p(t)yτ(t)γ+ d
c
ft,yθ(t,ξ)ξ= ,
respectively, and they gave sufficient conditions which guarantee that every solution of the equation oscillates. Moreover, there are also some papers on third-order dynamic equa-tions. For instance, Erbeet al.[] considered the third-order nonlinear dynamic equation
c(t)a(t)x(t)+q(t)fx(t)= .
Later, Erbeet al.[] considered the third-order nonlinear dynamic equation
x(t) +p(t)x(t) =
by giving Hille and Nehari type criteria. Then, Hassan [] studied the third-order nonlin-ear dynamic equation
a(t)r(t)x(t)γ+ft,xτ(t)= .
Lastly, Wang and Xu [] studied asymptotic properties of a certain third-order dynamic equation,
r(t)
r(t)x(t)
γ
+q(t)fx(t)= .
As we see from all the above, our equation, a neutral dynamic equation, is more general than other third-order dynamic equations and therefore it is very important. For some other important articles on oscillations of second-order nonlinear neutral delay dynamic equation on time scales and oscillations of third-order neutral differential equations, we refer the reader to the papers [, ], and [], respectively. We give [, ] as references for books on the time scale calculus.
2 Main results
Lemma Assume that y is an eventually positive solution of()and
∞
t t r(t)
=∞,
∞
t
r(t)
γ
t=∞. ()
Then,there is a t∈[t,∞)Tsuch that either
or
(ii) x(t) > , x(t) < , x[](t) > , t∈[t,∞)T.
Proof Assume thaty(t) > fort≥tand thereforey(τ(t)) > andy(δ(t)) > fort≥t>t. Consequently,x(t) > , eventually. Using () in () and the fact that|f(t,u)| ≥q(t)|uγ|, we obtain
x[](t) +q(t)yδ(t)γ ≤, t∈[t,∞)T. ()
Hence, we conclude that x[](t) is a strictly decreasing function on [t
,∞)T. We claim
thatx[](t) > on [t
,∞)T. If not, then there exists at∈[t,∞)Tsuch thatx[](t) < on
[t,∞)T. Then, there exist a negative constantcandt∈[t,∞)Tsuch that
x[](t)≤c< , t∈[t,∞)T
and it follows that
x[](t)≤
c r(t)
γ
. ()
Integrating () fromttotand using (), we obtain
r(t)x(t)≤r(t)x(t) +c
γ t
t
r(s)
γ
s,
which implies thatr(t)x(t)→–∞ast→ ∞. Therefore, there exists at∈[t,∞)Tsuch
that
r(t)x(t)≤r(t)x(t) < , t∈[t,∞)T. ()
Dividing both sides of () byr(t) and integrating fromttot, we obtain
x(t) –x(t)≤r(t)x(t) t
t
r(s)
s.
Hence, we see from () thatx(t)→–∞ast→ ∞, which contradicts the fact thatx(t) > , and thereforex[](t) > fort∈[t
,∞)T. As a result ofx[](t) > fort∈[t,∞)Tit follows
thatr(t)x(t) < on [t,∞)T orr(t)x(t) > on [t,∞)T, which completes the proof.
Lemma Let y be an eventually positive solution of().Assume that Case(i)of Lemma holds.Then,there exists a t∈[t,∞)Tsuch that
x(t)≥r(t,t) r(t)
x[](t)γ, t∈[t
where r(t,t) = tt s (r(s))
γ and
x(t)≥r(t,t)
x[](t)γ, t∈[t
,∞)T,
where r(t,t) = ttrr(s(,st))s.
Proof Sincex[](t) is strictly decreasing on [t
,∞)T, we have
r(t)x(t)≥r(t)x(t) –r(t)x(t)
= t
t
[x[](s)]γ
(r(s))
γ
s,
it follows that
x(t)≥[x [](t)]γ
r(t) t
t s (r(s))
γ
or
x(t)≥r(t,t) r(t)
x[](t)
γ, t∈[t
,∞)T. ()
Similarly, integrating () fromttot, we obtain
x(t)≥x[](t)γ t
t
r(s,t) r(s)
s
or
x(t)≥r(t,t)
x[](t)γ, t∈[t
,∞)T.
This completes the proof.
Lemma Let y be an eventually positive solution of().Assume that Case(ii)of Lemma holds.If
∞
t
r(t)
∞
t
r(s)
∞
s
q(u)u /γ
st=∞, ()
thenlimt→∞y(t) = .
Proof Since Case (ii) of Lemma is satisfied,
lim
t→∞x(t) =l≥.
We claim thatlimt→∞x(t) = . Assume thatl> . Then for any> , we havel<x(t) <l+
for sufficiently larget≥t. Choose <<l(–pp). On the other hand, since
we have
y(t)≥x(t) –pxτ(t)
>l–p(l+)
=k(l+)
>kx(t), t≥t≥t,
wherek=l–pl+(l+) > . Then,
yδ(t)γ ≥kγxδ(t)γ, t≥t≥t. ()
Substituting () into (), we obtain
x[](t)≤–q(t)kγxδ(t)γ, t≥t. ()
Integrating () fromtto∞, we get
x[](t)≥kγ
∞
t
q(s)xδ(s)γs, t≥t
or usingx(δ(t)) >l,
x[](t)≥kl
r(t)
∞
t
q(s)s /γ
, t≥t. ()
Integrating () fromtto∞and dividing both sides byr(t), we have
–x(t)≥ kl r(t)
∞
t
r(u)
∞
u
q(s)s /γ
u, t≥t. ()
Integrating () fromtto∞, we obtain
x(t)≥kl
∞
t
r(t)
∞
t
r(s)
∞
s
q(u)u /γ
st,
which contradicts () and thereforel= . By making use of ≤y(t)≤x(t), we conclude
thatlimt→∞y(t) = .
Theorem . Assume thatδ(σ(t)) =σ(δ(t)).Furthermore,suppose that(), (),and
∞
t
Q(s)s=∞, ()
where Q(s) =q(s)( –p)γ, hold. Then, every solution y(t) of ()is either oscillatory on [t,∞)Torlimt→∞y(t) = .
the case wheny(t) is negative the proof is similar. As we see from Lemma we have two cases to consider. First we assume thatx(t) satisfies Case (i) in Lemma . Then, by using () we see that
y(t)≥x(t) –p(t)xτ(t)≥( –p)x(t), t≥t≥t
or
yδ(t)γ ≥( –p)γxδ(t)γ, t≥t≥t. ()
Substituting () into (), we obtain
x[](t)≤–q(t)( –p)γxδ(t)γ = –Q(t)xδ(t)γ, t≥t
. ()
Furthermore, using Pötzche’s chain rule, we find
xδ(t)γ
=γ
hxδ(t)σ+ ( –h)xδ(t)γ–xδ(t)dh
≥γ
hxδ(t)+ ( –h)xδ(t)γ–xδ(t)dh
=γxδ(t)γ–xδ(t)δ(t) > . ()
Define the function
z(t) = x [](t)
(x(δ(t)))γ, t≥t. ()
It is easy to see thatz(t) > . Taking the derivative ofz(t), we see that
z(t) = x [](t)
(x(δ(t)))γ +
x[](t)σ
(x(δ(t)))γ
= x [](t)
(x(δ(t)))γ –
x[](t)σ ((x(δ(t))) γ)
(x(δσ(t)))γ(x(δ(t)))γ. ()
Substituting () into () and using (), respectively, we have
z(t)≤–Q(t) –x[](t)σ ((x(δ(t))) γ)
(x(δσ(t)))γ(x(δ(t)))γ
≤–Q(t) –x[](t)σγ(x(δ(t)))
γ–x(δ(t))δ(t)
(x(δσ(t)))γ(x(δ(t)))γ
= –Q(t) –γx[](t)σ x
(δ(t))δ(t)
(x(δσ(t)))γx(δ(t))
≤–Q(t) –γx[](t)σx
(δ(t))δ(t)
Using () in () and the fact thatx[](t) is strictly decreasing, we obtain from ()
Finally, integrating () fromttot, we get
z(t) –z(t)≤
which contradicts (). When Case (ii) holds, we can conclude from Lemma that
limt→∞y(t) = .
Theorem . Suppose that(), ()hold andδ(σ(t)) =σ(δ(t)).Furthermore,assume that there exists a positive rd-continuous-differentiable functionα(t)such that
lim sup
Proof Suppose to the contrary thaty(t) is nonoscillatory solution of (). We assume that y(t) > fort≥t, theny(τ(t)) > andy(δ(t)) > fort≥t>t. We first consider thatx(t) satisfies Case (i) in Lemma . We proceed as in the proof of Theorem ., and we obtain (). Let us define the function
z(t) =α(t) x [](t)
(x(δ(t)))γ, t≥t. ()
It is clear thatz(t) > . Taking the derivative ofz(t), we see that
Substituting () into (), we obtain
By making use of the inequality
λABλ––Aλ≤(λ– )Bλ, λ> ,A,B≥ ()
Integrating both sides of () fromttotthen yields
t continuous-partial derivativeHs(t,s) onD
with respect to the second variable.
where C(t,s) =max{,Hs(t,s) +H(t,s)(α(s))+
ασ(s) }.Then every solution y(t)of()is either oscil-latory on [t,∞)Torlimt→∞y(t) = .
Proof Assume thaty(t) is a nonoscillatory solution of (). Definez(t) as in (). We proceed as in the proof of Theorem . to obtain (). Multiplying both sides of () byH(t,s), integrating with respect tosfromttot, we get
t
Then, using the inequality () in (), we have t
When Case (ii) holds, we can conclude from Lemma thatlimt→∞y(t) = .
Example . Consider the following third-order neutral nonlinear dynamic equation:
t
t
y(t) +
y
t
+ ty
t
= , t∈[t,∞)T,t> , ()
where γ = ,r(t) =t, r(t) =r(t) =t p(t) = ,τ(t) =δ(t) = t, andq(t) = t–. We can verify that all conditions of Theorem . are satisfied, therefore every solution of () is oscillatory orlimt→∞y(t) = . In fact,y(t) =t–is a solution of ().
Competing interests
The author declares that they have no competing interests.
Received: 11 September 2013 Accepted: 6 January 2014 Published:27 Jan 2014
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Cite this article as:Candan:Asymptotic properties of solutions of third-order nonlinear neutral dynamic equations.