Part I Part II Part III Part IV Part - V. Part - VI. DPP No. _____ Home Assignment : Home Assignment : Home Assignment : Home Assignment : Home Assignment : Home Assignment :
Signature HOD Signature Faculty
DAILY LECTURE SHEET : ACADEMIC SESSION 2008-09
Title/Sub title of the Topic : ____________________________________________________________ Lecture No. of the particular topic : _____________________________________Cumulative Lecture No. ______ Contents to be discussed :
DPP No. _______ Home Assignments : ________________________________________________________ _________________________________________________________________________________________________ Theory Contents to be Covered in the Lecture : Assignments to be given after the Lecture :
Discussion : 2 Lecture
Batch : R
Binomial Theorem for positive index Theorem + basic properties
General term, middle term
Coefficient of xk in (ax + b)n
Num greatest coefficient Num greatest term
Remainder
1
LECTURE – 1 1. Expand the following binomials :
(i) (x – 3)5 [ Ans. x5 – 15x4 + 90x3 – 270x2 + 405x – 243 ]
(ii) (2x – y)5 [ Ans. 32x5 – 80x4y + 80x3y2 – 40x2y3 + 10xy4 – y5 ]
2. Find
(i) 28th term of (5x + 8y)30 [ Ans.
! 3 ! 27 ! 30 (5x)3 . (8y)27] (ii) 7th term of 9 x 2 5 5 x 4 [Ans. 3 x 10500 ]
3. Find middle term of (i)
14 2 2 x 1 & (ii) 9 3 6 a a 3 [Ans. (i) 16 429 x14, (ii) 8 189 a17, 16 21 a19]
4. Find the term independent of x in
9 2 x 3 1 x 2 3 [Ans. 18 7 ]
D5. Find the coefficients of x32 & x–17 in
15 3 4 x 1 x [Ans. 1365, –1365]
6. Find the coefficient of x–1 in (1 + 3x2 + x4)
8 x 1 1 [Ans. 232]
7. Find the numerically greatest coefficient in the expansion of (3x – 2)21 [ Ans. T 9 ]
8. Find the algebracally greatest and least coefficient in the expansion of (2 – 5x)48
[ Ans. T35 , T36 ]
9. Find the greatest term in the expansion of (7 – 5x)11 where x =
3 2 [Ans. T4 = 9 440 × 78 × 53]
D10. Find numerically greatest term in the expansion of (3 – 5x)15 when x =
5 1
. [ Ans. T3, T4 ] 11. If n is a positive integer, show that
(i) 9n + 7 is divisible by 8.
D(ii) 32n+1 + 2n+2 is divisible by 7
D(iii) 62n – 35n – 1 is divisible by 1225.
12. What is the remainder when 599 is divided by 13 [Ans. 8]
Part I Part II Part III Part IV Part - V. Part - VI. DPP No. _____ Home Assignment : Home Assignment : Home Assignment : Home Assignment : Home Assignment : Home Assignment :
Signature HOD Signature Faculty
DAILY LECTURE SHEET : ACADEMIC SESSION 2008-09
Title/Sub title of the Topic : ____________________________________________________________ Lecture No. of the particular topic : _____________________________________Cumulative Lecture No. ______ Contents to be discussed :
DPP No. _______ Home Assignments : ________________________________________________________ _________________________________________________________________________________________________ Theory Contents to be Covered in the Lecture : Assignments to be given after the Lecture :
Discussion : 2 Lecture
Batch : R
Sum of series involves binomial coefficient upper index is constant
(i) By proper substitution (ii)
tk =
tn k (iii) By reduction r nC r = n n–1C r–1 (iv) Calculus
Cr ,
rCr ,
(1)Cr ,
1Cr r 1 ,
r 2 C r ... 2 (A + B)n Binomial TheoremLECTURE – 2
1. If n is +ve integer, prove that the integral part of (7 + 4 3 )n is an odd number..
D2. If n is +ve integer, prove that the integeral part of (7 + 2 5 )2n + 1 is an even number..
D3. If (7 + 4 3 )n = , where is a +ve integer and is a proper fraction, then prove that
(1–) () = 1
4. Show that the integer just above ( 3 +1)2n is divisible by 2n + 1 for all n N,
5. If (1 + x)n = C
0 + C1x + C2x
2 + ...+ C nx
n, then show that
(i) C0 + C1 + C2 + ...+Cn = 2n (ii) C0 + C2 + C4 + ... = 2n–1 D(iii) C1 + C3 + C5 + ... = 2n–1 (iv) C0 + 3C1 + 32C 2 + ... = 4 n. 6. If (1 + x)n = C 0 + C1x + C2x 2 + ...+ C nx
n, then show that
(i) C1 + 2C2 + 3.C3 + ... + nCn = n.2n–1
(ii) C0 + 2C1 + 3.C2 + ... + (n+1) . Cn = 2n–1(n+2)
(iii) C0 + 3C1 + 5C2 + ... + (2n+1) . Cn = 2n(n+1)
D(iv) a.C0 + (a – b).C1 _ (a – 2b)C2 + ...+(a – nb).Cn = 2n–1 (2a – nb)
(v) C0 – 22.C 1 + 3 2 C 2 + ...+ (–1) n (n+1)2 .C n = 0, n > 2. D(vi) a2.C 0 – (a – 1) 2.C 1 + (a – 2) 2.C 2 – (a – 3) 2.C 3 + ...+ (–1) n (a – n)2.C n = 0. (vii) 1 n 1 2 1 n C ... 3 C 2 C C 1 n n 2 1 0 (viii) 1 n 1 ... 4 C 3 C 2 C C 1 2 3 0 (ix)
n 0 r r r 2 n 1 ) 2 r )( 1 r ( C . ) 1 ( . (x)
n 0 r r 1 2 r Cr = 1 n 1 ) 3 n ( 2n .Part I Part II Part III Part IV Part - V. Part - VI. DPP No. _____ Home Assignment : Home Assignment : Home Assignment : Home Assignment : Home Assignment : Home Assignment :
Signature HOD Signature Faculty
DAILY LECTURE SHEET : ACADEMIC SESSION 2008-09
Title/Sub title of the Topic : ____________________________________________________________ Lecture No. of the particular topic : _____________________________________Cumulative Lecture No. ______ Contents to be discussed :
DPP No. _______ Home Assignments : ________________________________________________________ _________________________________________________________________________________________________ Theory Contents to be Covered in the Lecture : Assignments to be given after the Lecture :
Discussion : 2 Lecture
Batch : R
3
Problem of double sigma Product of binomial coefficient Upper index is variable (i) nC r + nC r + 1 = n+1C r+1
(ii) Using binomial theorem for negative index
LECTURE – 3 1. (i) nC n + n+1C n+ n+2C n+ ...+ n+kC n = n+kC n+1 . (ii) mC 1 + m+1C 2 + m+2C 3 + ... + m+n–1C n = nC 1 + n+1C 2 + n+2C 2 + ...+ n+m–1C m. 2. Prove that If (1 + x)n = C 0 + C1x + C2x 2 +...+ C nx n, (i) C02 + C 1 2 + ... + C n 2 = )! n ( ! ) n 2 ( (ii) C0C1 + C1C2+ ... + Cn–1 Cn =
)! 1 n ( )! 1 n ( ! n 2 (iii) C0Cn + C1 . Cn–1+ ... + Cn C0 = 2 ) ! n ( )! n 2 ( D(iv)
n 0 r 3 r r 3)! -(n 3)! (n ! n 2 C C . (v) mC r. nC 0 + mC r–1. nC 1 + mC r–2. nC 2 + ...+ mC 1. nC r–1 + mC 0. nC r = m+nC r ,where m,n,r are positive integers and r < m, r < n. D(vi) C0.2nC
n – C1. 2n–2C
n + C2. 2n–4C
n – ... = 2n, where Cr stands for nC r. 3. Evaluate :
n 0 m m 0 p p m m nC . C Ans. 3n 4. If (1 + x)n = C 0 + C1x + C2x 2 + ...+ C nx n, prove that (i)
(ij)nCj nCi = n.22n D(ii) (Ci + Cj)2 = (n – 1).2nC n + 2 2n 0 i < j n, D5. If (1 + x)n = C 0 + C1x + C2x 2 + ...+ C nx n, show that i.j.CiCj=n2 { 1 n 2 n 2 3 n 2 . C 2 1 2 } 0 i < j n. D6. Prove that If (1 + x)n = C 0 + C1x + C2x 2 +...+ C nx n, (i) 2 2 n 2 2 2 1 2 0 ] ! 1) [(n ! ) 1 n 2 ( 1 n C ... 3 C 2 C C (ii) C12 – 2.C 2 2 + 3.C 3 2 – ...– 2n.C2 2n = (–1) n–1.n.Cn where Cr stands for 2nC r. (iii)
n 0 r n 2 n 2 2 2 r n . C C ) r n ( r , where C r stands for nC r. (iv) C0– C1 + C2 – ...+ (–1)m–1.C m–1 = (–1) m–1 ! ) 1 m ( ) 1 m n )...( 2 n )( 1 n ( where Cr stands for nCr. D7. If (1 + x)n = C 0 + C1x + C2x 2 + ...+ C nx n, show that
n 0 r r 2 j i C 1 2 n C j C i , 0 i < j n.Part I Part II Part III Part IV Part - V. Part - VI. DPP No. _____ Home Assignment : Home Assignment : Home Assignment : Home Assignment : Home Assignment : Home Assignment :
Signature HOD Signature Faculty
DAILY LECTURE SHEET : ACADEMIC SESSION 2008-09
Title/Sub title of the Topic : ____________________________________________________________ Lecture No. of the particular topic : _____________________________________Cumulative Lecture No. ______ Contents to be discussed :
DPP No. _______ Home Assignments : ________________________________________________________ _________________________________________________________________________________________________ Theory Contents to be Covered in the Lecture : Assignments to be given after the Lecture :
Discussion : 2 Lecture
Batch : R
Binomial theorem for negative and fractional index
Multinomial theorem
Binomial Theorem
LECTURE – 4 1. Write the expansion of
(i) (1 – x)–1 (ii) (1 – x)–2 (iii) (1 – x)–n
2. Find the general term in the expansion of (2–3x2)–2/3 [Ans.
r 3 2 2 ! r ) 1 r 3 ...( 8 . 5 . 2 2 x2r]
D3. Find the no. of term in the expansion of (a + b + c + d + e + f)n. [Ans. n+5c n]
D4. Find the coeff. of a3.b4.c7 in the expansion of (bc + ca + ab)8. [Ans. 280]
5. Find the coefficient of x3 y4 z2 in the expansion of (2x – 3y + 4z)9. Ans.
! 2 ! 4 ! 3 ! 9 23 34 42
6. Find the coefficient of x4 in (1 + x – 2x2)7 Ans. 14
D7. The sum of rational terms in
3 6
105 3